PowerPoint

ABC
AB
AC
BC
F



4 - 3

ABC
ABC
ABC



4-3 3

(2)
(3)

ABCFABC 1 0 F=1 F=0 4 - 4



A
B
C
F

5 8421BCD 3
BCD 4 -7 4 - 5



*
8421BCD1010~1111 4 - 8 4 - 9




4 – 8
Ai Bi C i-1
Si C i+1
0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 0 1 1 0 1 1 1
0 0 1 0 1 0 0 1 1 0 0 1 0 1 1 1

4 – 13

(a) (b)

4 – 18

*
8 8421 8421 8421 8421


*
8421BCD 9 8421BCD 9 “0” 9 0110




9 8421BCD 3
8421BCD 0011 3 4 -22
4-22 8421BCD3
8421BCD 8421BCDB80, B40, B20, B10BCDB8, B4, B2, B1 8421BCD
B(01)








*
11 012…7 4 - 24
4 – 24
4–25
0 1 2 3 4 5 6 7
0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1


10
0 1 2 3 4 5 6 7 8 9
0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 0 1 0 1 0 1 1 0 0 1 1 1 1 0 0 0 1 0 0 1


A B C
0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1
N









BIBI=0
LTBI=1LT=0 DCBA “8”


*
RBI: BI=LT=1RBI=0 DCBA0000 “0”DCBA 0093.2300RBI93.23
RBO“0”RBO=0RBI





“1”

1 0 0 0 0
× D0~D3 D0~D3 D0~D3 D0~D3
0 D0 D1 D2 D3

15
4-51A2A2=0 FF1D0~D3A2=1 FF2, D4~D7

16
4-52A3A200FD0~D3;A3A201 FD4~D7; A3A2 10 FD8~D11A3A211FD12~D15

F
0 1 1 0
D0 D1 D2 D3
4 – 17
A2 A 1 A0
F
Di
0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1
0 0 0 1 0 1 1 1
D0 D1 D2 D3 D4 D5 D6 D7


19 18
4-56 A2A1 DiD0=0,D1=A0, D2=A0, D3=1


F=∑(0 1, 5, 6, 7, 9, 10, 14, 15)
A1A0ABCD 4 -57
4 – 57 20

21 01101001
D0=D3=D5=D6=0 D1=D2=D4=D7=1 01101001 4 - 58
4 – 58

8421BCDD0D1,D2, D3 00 8421BCD011011 2 - 4 A1A0=00Y0=04 - 59


*
A1A0=00DCBA=1001Y0=09A1A0=01DCBA=0111, Y1=0, 7A1A0=10 DCBA=0000, Y2=00A1A0=11DCBA=0011, Y3=0 325/s
3.
4.3.4
1.
AB A>B, A<BA=BABFA>B, FA<BFA=B104-18

0 0 1 0
0 1 0 0
1 0 0 1

*
(1) A3>B3A>BFA>B=1;A3<B3 A<B, FA<B=1
(2) A3=B3A2,B2A2>B2,FA>B=1A2<B2FA<B=1
(3) A2=B2A1, B1
……

(1) “A=B”1“A>B”“A<B”0
(2)
4 – 63

2. “0”()
4-67 B=C=0 0Atpd
4-67 “0”
“1”
“0”
AB=00 F=C
AB=01 F=1
AB=10 F=C
AB=11 F=C
24 F=(A+C)(A+B)(B+C)
AC
A
C

4.4.4
1. ()
F=AC+ABB=C=1F=A+A“1” BCB=C=1 F1 4-69 BC


(b)
(c)
(d)
1
9
74LS138






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