K THI TUYN SINH CAO NG NM 2011 Mn thi : HO HC; khi A,B - M : 812 Cho bit nguyn t khi (theo vC) ca cc nguyn t H = 1;Li = 7; Be = 9; C = 12; N = 14; O = 16; Na = 23; Mg = 24; Al = 27; S = 32; Cl = 35,5; K = 39; Ca = 40; Cr = 52, Mn = 55; Fe = 56; Cu = 64; Zn = 65; Rb = 85,5;Ag=108; I = 127; Cs = 133; Ba = 137. I. PHN CHUNG CHO TT C TH SINH (40 cu, t cu 1 n cu 40) Cu 1:Cho cc cht : saccaroz, glucoz , frutoz, etyl format , axit fomic v anehit axetic. Trong cc cht trn, s cht va c kh nng tham gia phn ng trng bc va c kh nng phn ng vi Cu(OH)2 iu kin thng lA. 3B. 2C. 4D. 5 Gi : glucoz , frutoz, axit fomic. Andehit axetic khng c v n cn c nhit . Cu 2: Cho m gamhnhp X gm phenolv etanol phn nghon ton vinatri (d), thu c2,24 lt kh H2 (ktc). Mt khc, phn ng hon ton vi m gam X cn 100 ml dung dch NaOH 1M. Gi tr ca m l:A. 7,0B. 14,0C. 10,5D.21,0 Gi : nH2=0.1 mol. A mol phenol, b mol etanol ta c h:]0.5( o + b) = 0.1o = 0.1]o = 0.1b = 0.1m= (0.1)x(94+46)=14g Cu 3: Lnmen dung dch cha 300 gam glucoz thu c 92 gam ancol etylic. Hiu sut qu trnhlnmen to thnh ancol etylic l: A. 60%B. 40%C. 80%D. 54% Gi : C6H12O6 2CO2 + 2C2H5OH 180 92 H= 92.18092.300= 60% Cu 4: Ho tan hon ton hn hp X gm 0,2 mol Fe v 0,2 mol Fe2O3 vo dung dch axit H2SO4 long (d), thu c 2,24 lt kh (ktc) v dung dch Y. Cho lng d dung dch NaOH vo dung dch Y, sau khi phn ng xy ra hon ton thu c m gam kt ta. Gi tr nh nht ca m l: A. 54,0B. 59,1C. 60,8D. 57,4 Gi : nH2=0.1 mol < 0.2 mol cn d Fe do oxit s phn ng trc. Fe + 2Fe3+ 3Fe2+ 0.1 0.20.3 ]0.2 mol Fc3+0.4 mol Fc2+ m= 0.2(107)+0.4(90)=57.4 Cu 5:Cho cc polime : (1) polietilen , (2) poli (metyl metacrylat), (3) polibutaien, (4) polistiren, (5) poli(vinyl axetat) v (6) t nilon-6,6. Trong cc polime trn, cc polime c th b thu phn trong dung dch axit v dung dch kim l: A. (2),(3),(6)B. (2),(5),(6)C. (1),(4),(5)D. (1),(2),(5) Gi : polime c th b thu phn trong dung dch axit v dung dch kim phi l polime trng ngng (2),(5),(6) Cu 6:Pht biu no sau y khng ng? A. Mui AgI khng tan trong nc, mui AgF tan trong nc B. Flo c tnh oxi ho mnh hn clo. C. Trong cc hp cht, ngoi s oxi ho -1, flo v clo cn c s oxi ho +1, +3, +5, +7 D. Dung dch HF ho tan c SiO2 Cu 7:t chy hon ton 17,4 gam hn hp Mg v Al trong kh oxi (d) thu c 30,2 gam hn hp oxit. Th tch kh oxi (ktc) tham gia phn ng l: A. 17,92 ltB. 4,48 ltC. 11,20 ltD. 8,96 lt Gi : V=30.217.432. 22,4 = 8.96 Cu 8:Cho cc cht : KBr, S, SiO2, P, Na3PO4, FeO, Cu v Fe2O3. Trong cc cht trn, s cht c th oxi ho bi dung dch axitH2SO4 c nng l: A. 4B. 5C. 7D. 6 Gi : FeO, C, P, S, KBr (to Br2) Cu 9:Mc phn cccalin kt ho hc trong cc phn t c spxp theo th t gim dn t tri sang phi l: A. HBr, HI, HClB. HI, HBr, HCl C. HCl , HBr, HID. HI, HCl , HBrGi : V m im gim dn t Cl > Br > I lc ht gim dn trong lin kt s phn cc gim dnC Cu 10: phn ng ht vi mt lng hn hp gm hai cht hu c n chc X v Y (Mx < MY) cn va 300 ml dung dch NaOH 1M. Sau khi phn ngxy ra hon ton thu c 24,6 gammui camt axit hu cvm gam mt ancol. t chy hon ton lng ancol trn thu c 4,48 lt CO2 (ktc) v 5,4 gam H2O. Cng thc ca Y l: A. CH3COOC2H5B. CH3COOCH3 C. CH2=CHCOOCH3 D. C2H5COOC2H5 Gi : nNaOH= 0.3 mol= n mui nCO2=0.2 mol v nH2O= 0.3 mol ru no v lp t l ta c : nCnH=0.20.3.2=26 ancol etylicV thu 1 mui duy nht phi cng gc acid M mui= 24.60.3= 82 CH3COONa A Cu 11:Ho tan hon ton 6,645 gamhn hp mui clorua ca hai kimloi kim thuc hai chuk k tip nhau vonccdungdchX.ChotonbdungdchXtcdnghontonvidungdchAgNO3(d), thuc 18,655 gam kt ta. Hai kim loi kim trn l: A. Na v KB. Rb v CsC. Li v NaD. K v RbnCl= nAgCl= 18.655143.5= 0.13 ]nKl =0.13 mKl = 6.645 4.615 = 2.03Mtb= 2.030.13 =15.61 Li v Na Cu 12: nhn ra ion NO3- trong dung dch Ba(NO3)2, ngi ta un nng nh dung dch vi: A. dung dch H2SO4 longB. kim loi Cu v dung dch Na2SO4 C. kim loi Cu v dung dch H2SO4 longD. kim loi Cu Gi : to kh NO bay ra ha nu ngoi khng kh. Cu 13: Cht no sau y c ng phn hnh hc? A. CH2=CH-CH=CH2B. CH3-CH=CH-CH=CH2 C. CH3-CH=C(CH3)2D. CH2=CH-CH2-CH3

Cu 14: Amino axit Xc dng H2NRCOOH (R l gc hirocacbon). Cho 0,1 mol X phn ng ht vi dung dch HCl (d) thu c dung dch cha 11,15 gam mui. Tn gi ca X l: A. phenylalaninB. alaninC. valinD.glyxin C mX= 11.15 0.1(36.5)=7.5 M=75 R=14 Glyxin Cu 15: Sn phm ch yu trong hn hp thu c khi cho toluen phn ng vi brom theo t l s mol 1:1 (c mt bt st) l A. o-bromtoluen v p-bromtoluenB. benzyl bromua C. p-bromtoluen v m-bromtoluenD. o-bromtoluen v m-bromtoluen Gi : c xc tc bt Fe th vo nhn do toluen c gc CH3- cho in tch th vo ortho v para Cu 16: Cho cn bng ho hc : N2 (k) +3H2 (k) 2NH3 (k)H 0 Cn bng trn chuyn dch theo chiu thun khi: A. tng p sut ca h phn ngB. tng nhit ca h phn ng C. gim p sut ca h phn ngD. thm cht xc tc vo h phn ng Gi : CB theo chiu thun gim s mol kh tng p sutCu 17:Dy gm cc kim loi u c cu to mang tinh th lp phng tm khi l: A. Na, K, Ca, BaB. Li, Na, K, RbC. Li, Na, K , MgD. Na, K, Ca, Be Cu 18:t chyhon tonmt lng hnhp X gm 3 ancol thuc cng dy ng ng thu c 6,72 lt kh CO2 (ktc) v 9,90 gam H2O. Nu un nng cng lng hn hp X nh trn vi H2SO4 c nhit thch hp chuyn ht thnh ete th tng khi lng ete thu c l: A. 6,45 gamB. 5,46 gamC. 7,40 gamD. 4,20 gam Ta c nH2O=0.55, nCO2=0.3 ru no n ru = 0.25 nCtb= 0.3 : 0.25 = 1.2 Mtb= 34.8mete = 0.25(34.8) (0.5x0.25 x18)= 6.45Cu 19:S ancol ng phn cu to ca nhau c cng thc phn t C5H12O, tc dng vi CuO un nng sinh ra xenton l: A. 4B. 2C. 5D. 3 Gi thit to xeton Ru bc II 3 ctct C-C(OH)-C-C-C, C-C-C(OH)-C-C. C-C(C)-C(OH)-C Cu 20: Nung hnhp gm 10,8 gam Alv 16,0 gam Fe2O3 (trong iu kin khng c khng kh), sau khi phn ng xy ra hon ton thu c cht rn Y. Khi lng kim loi trong Y l: A. 5,6 gamB. 22,4 gamC. 11,2 gamD.16,6 gamnAl =0.4, n Fe2O3= 0.1 2Al + Fe2O3 2Fe + 2Al2O3 0.20.10.2 m = (0.2x27) +( 0.2x56) = 16.6 Cu 21:Cng thc ca triolein l: A. (CH3[CH2]16COO)3C3H5 B. (CH3[CH2]7CH=CH[CH2]5COO)3C3H5 C. (CH3[CH2]7CH=CH[CH2]7COO)3C3H5 D. (CH3[CH2]14COO)3C3H5 Cu 22: Trong bng tunhon cc nguyn t ho hc, nguyn t X nhm IIA, nguyn t Y nhm VA. Cng thc ca hp cht to thnh 2 nguyn t trn c dng l: A.X3Y2 B. X2Y3C. X5Y2D. X2Y5 Cu 23:Pht biu no sau y l ng? A. Amino axit l hp cht c tnh lng tnh. B. Trong mi trng kim, ipetit mch h tc dng c vi Cu(OH)2 cho hp cht mu tm. C. Trong mt phn t tetrapeptit mch h c 4 lin kt peptit. D. Cc hp cht peptit km bn trong mi trng baz nhng bn trong mi trng axit Cu 24: ho tan hon ton 6,4 gam hn hp gm kim loi R (ch c ho tr II) v oxit ca n cn va 400 ml dung dch HCl 1M. Kim loi R l: A. BaB. CaC. BeD. Mg Gi : nhh= 0.5 nH+= 0.2 Mtb= 32 R