MDTNC_C5
of 35
Transcript of MDTNC_C5
-
7/24/2019 MDTNC_C5
1/35
Chng 5: Mch lc
Th.S. NguynThanh Tun
Bmn Vinthng (B3)[email protected]
1
-
7/24/2019 MDTNC_C5
2/35
Ni dung
Phn loimchlctheo linh kin. Thng(RLC) Tch cc(RC & OpAmp)
Phn loimchlctheo pngtns Mchlcthng thp. Mchlcthng cao.
Mchlcthng di. Mchlcchndi.
ThitkmchlcButterword.
2
-
7/24/2019 MDTNC_C5
3/35
Phn loi mch lc
3
-
7/24/2019 MDTNC_C5
4/35
Mch lc thng thp th ng
4
-
7/24/2019 MDTNC_C5
5/35
Mch lc thng thp tch cc
5
-
7/24/2019 MDTNC_C5
6/35
6
-
7/24/2019 MDTNC_C5
7/35
7
-
7/24/2019 MDTNC_C5
8/35
Mch lc thng thp tch cc (tt)
Sallen & Key 2
8
-
7/24/2019 MDTNC_C5
9/35
Sallen & Key 3
9
-
7/24/2019 MDTNC_C5
10/35
Mch lc thng cao th ng
10
-
7/24/2019 MDTNC_C5
11/35
Mch lc thng cao tch cc
11
-
7/24/2019 MDTNC_C5
12/35
Mch lc thng cao tch cc (tt)
12
-
7/24/2019 MDTNC_C5
13/35
Mch lc thng di th ng
13
-
7/24/2019 MDTNC_C5
14/35
Mch lc thng di tch cc
14
-
7/24/2019 MDTNC_C5
15/35
dc b lc ghp lin tng
15
-
7/24/2019 MDTNC_C5
16/35
16
-
7/24/2019 MDTNC_C5
17/35
Tiu chun ti u
Di thng phng cc iButterworth
Khong dch chuyn di thng-di chn nhTschebyscheff
Pha tuyn tnhBessel
17
-
7/24/2019 MDTNC_C5
18/35
Thit k b lc Butterworth
18
-
7/24/2019 MDTNC_C5
19/35
Thit k b lc Butterworth (tt)
19
-
7/24/2019 MDTNC_C5
20/35
Thit k b lc Butterworth (tt)
20
-
7/24/2019 MDTNC_C5
21/35
21
-
7/24/2019 MDTNC_C5
22/35
22
-
7/24/2019 MDTNC_C5
23/35
23
-
7/24/2019 MDTNC_C5
24/35
Lc thng cao
Thay s bi 1/s
Thay R bi C v ngc li
24
-
7/24/2019 MDTNC_C5
25/35
Lc thng di
Thay s bi
Ni tip lc thng thp vi lc thng cao
25
-
7/24/2019 MDTNC_C5
26/35
-
7/24/2019 MDTNC_C5
27/35
27
-
7/24/2019 MDTNC_C5
28/35
B lc chn di
Thay s bi
28
-
7/24/2019 MDTNC_C5
29/35
-
7/24/2019 MDTNC_C5
30/35
Mch lc chn di Wien-Robison
30
-
7/24/2019 MDTNC_C5
31/35
Mch lc ton di
31
-
7/24/2019 MDTNC_C5
32/35
32
-
7/24/2019 MDTNC_C5
33/35
Bi tp 1
V 1 s mch dng cc Op-Amp l tng, in tr v tin (xc nh gi tr cc linh kin) mch c dng lc thngthp Butterworth bc 3 vi tn s ct (-3dB) l 1KHz v liln nht l 10, bit rng hm truyn tng qut ca mch lc
thng thp Butterworth bc 3 chun ha vi tn s ct 1rad/sc dng: G0/(1+s)(1+s+s^2).
33
A0= 1 + R4/R3
-
7/24/2019 MDTNC_C5
34/35
Bi tp 2
34
-
7/24/2019 MDTNC_C5
35/35
Bi tp 3
a) Trong trnghpR1 = 1K, R2 = 2K, R3 = R4 = 12K, C1 = C2 =F, tnh tnsct(-3dB) camchlctrn?
b) V1 smchv xc nhgi trcc linh kinmchc dnglcthng thpButterworthbc2 vitnsct(-3dB) l 1KHz v liln
nhtl 10,bitrnghm truyncamchlcthng thpButterworthbc2 chunha vitnsct1rad/s c dng: G0/ )
35
A0= 1 + R4/R3
