sec5_4ea

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Transcript of sec5_4ea

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?dimYhi je A\UfjYh 4 MYl]Ym 798

Review exercises

62 1---- 4 < ---!-- - _ then 1---- _ < 4 . ---!--. 4 . 2 ., 4 2

3///_>34

{9}

L*/MI. -&5 2. u < --2- 3. I I and 13; -13 and -II

1+ r 7774 5. $1r * s'$1r * s' 6. $r * .4'$r * I(4+ 2$r * /'$r * I(

5 _Therefore 2-mches represents 21 feet.

8

4 8_>3'.>.

3 3

3 I 8-&4< ,&,4 . 2 . 3

Let v < the number of liters of gasoline

to travel 1,428 kilometers.

8 liters v litersThen -- < ---and

84 km 1,428 kmv / 84 < 8 . 1,428

51r < 11,424

11,424v < ,, < 13684

Therefore at the same rate of gasoline consumption, it would take

136 liters to travel 1,428 kilometers.

Let 2 < the length of the enlargement.

10 in. 2 in.Then -- < ,, and 8 . 2 < 10« 36

8 in. 36 in .

82 : 360

2 = _36_0= 458

I 5-GA2-8 8

21v < ,& 7 < 10

8

Therefore the enlargement will be 45 inches long.

5 .Let v < the number of feet represented by 28mches.

I . 5 .7c- 17c- 1 5

Then -- = -- and -& v = I . 2-I ft v ft 8 8

so

76.

68.

82.

Therefore we have the ratio 32 or 32:33

9 3655.

~= 4"&then 36 . v = 9 . 5

36G < 45

5

13. 1, to ~ is written ~ = 1-- 1---= 1,6 3 2 6 2 4

3

Therefore we have the ratio 2. or 5:44

. 4.2 42 217. 4.2 to 2.1 is written - < , < ,

2.1 21 I

so we have the ratio 2-or 2:1F

27. Since there are 3 . 12 = 36 inches in 3 feet, we have

15 inches to 36 inches written -!1 < 2- or 5: 1236 12

. . 300 miles 30 miles36. 300 miles to 10 gallons IS written ---- < ,,,+

10 gallons I gallon

which we state as 30 miles per gallon.

output 375 1506+IB:*+**:*:*

Input 425 17

~ h . I . 15There ore t e mechafilca efficiency IS I7Cutting speed of tool steel = 20 ft/min = ~44. -------- ---Cutting speed of cast iron 45 ft/min 9

C 42 ft-Ib53. - < ,,, < 7 ft-Ib per sec

F 6 sec

Solutions to trial exercise problems

3 8 39. 8 to - is written - or 8:-

4 3 4

4

8 4 32but - = 8 . - = -

3334

169. 36 grams of hydrogen 71. 390 73. 6,826- ohms

330. 40.

75. 75 losses 77. v = -lRches W = - Inches7 & 7

79. 3,240 holes 81. 270 minutes < 4+ hours 83. 2+ quarts

45 5v>.>.36 4

954

59, 6: 15 = r75) then 15 . r < 6 . 8

15x < 48

48 16r:*:*

15 5

7. All real numbers except -I and I

3. All real numbers except 9

:/ \4v\;x/w3

4n . 114.--

6n * F

9/ 4_]

24/ *$r * s'

6, All real numbers except -4

2. All real numbers except -72

4. All real numbers except --3

612-° 5__2v\,\4

v,8G-7

10.--v,8

35. All real numbers except -

5

and 3

A\YfjYh 4 hYl]Ym

1. All real numbers except 0

536

056:15 = -: 8

5

Therefore

Therefore