sec5_4ea
Transcript of sec5_4ea
?dimYhi je A\UfjYh 4 MYl]Ym 798
Review exercises
62 1---- 4 < ---!-- - _ then 1---- _ < 4 . ---!--. 4 . 2 ., 4 2
3///_>34
{9}
L*/MI. -&5 2. u < --2- 3. I I and 13; -13 and -II
1+ r 7774 5. $1r * s'$1r * s' 6. $r * .4'$r * I(4+ 2$r * /'$r * I(
5 _Therefore 2-mches represents 21 feet.
8
4 8_>3'.>.
3 3
3 I 8-&4< ,&,4 . 2 . 3
Let v < the number of liters of gasoline
to travel 1,428 kilometers.
8 liters v litersThen -- < ---and
84 km 1,428 kmv / 84 < 8 . 1,428
51r < 11,424
11,424v < ,, < 13684
Therefore at the same rate of gasoline consumption, it would take
136 liters to travel 1,428 kilometers.
Let 2 < the length of the enlargement.
10 in. 2 in.Then -- < ,, and 8 . 2 < 10« 36
8 in. 36 in .
82 : 360
2 = _36_0= 458
I 5-GA2-8 8
21v < ,& 7 < 10
8
Therefore the enlargement will be 45 inches long.
5 .Let v < the number of feet represented by 28mches.
I . 5 .7c- 17c- 1 5
Then -- = -- and -& v = I . 2-I ft v ft 8 8
so
76.
68.
82.
Therefore we have the ratio 32 or 32:33
9 3655.
~= 4"&then 36 . v = 9 . 5
36G < 45
5
13. 1, to ~ is written ~ = 1-- 1---= 1,6 3 2 6 2 4
3
Therefore we have the ratio 2. or 5:44
. 4.2 42 217. 4.2 to 2.1 is written - < , < ,
2.1 21 I
so we have the ratio 2-or 2:1F
27. Since there are 3 . 12 = 36 inches in 3 feet, we have
15 inches to 36 inches written -!1 < 2- or 5: 1236 12
. . 300 miles 30 miles36. 300 miles to 10 gallons IS written ---- < ,,,+
10 gallons I gallon
which we state as 30 miles per gallon.
output 375 1506+IB:*+**:*:*
Input 425 17
~ h . I . 15There ore t e mechafilca efficiency IS I7Cutting speed of tool steel = 20 ft/min = ~44. -------- ---Cutting speed of cast iron 45 ft/min 9
C 42 ft-Ib53. - < ,,, < 7 ft-Ib per sec
F 6 sec
Solutions to trial exercise problems
3 8 39. 8 to - is written - or 8:-
4 3 4
4
8 4 32but - = 8 . - = -
3334
169. 36 grams of hydrogen 71. 390 73. 6,826- ohms
330. 40.
75. 75 losses 77. v = -lRches W = - Inches7 & 7
79. 3,240 holes 81. 270 minutes < 4+ hours 83. 2+ quarts
45 5v>.>.36 4
954
59, 6: 15 = r75) then 15 . r < 6 . 8
15x < 48
48 16r:*:*
15 5
7. All real numbers except -I and I
3. All real numbers except 9
:/ \4v\;x/w3
4n . 114.--
6n * F
9/ 4_]
24/ *$r * s'
6, All real numbers except -4
2. All real numbers except -72
4. All real numbers except --3
612-° 5__2v\,\4
v,8G-7
10.--v,8
35. All real numbers except -
5
and 3
A\YfjYh 4 hYl]Ym
1. All real numbers except 0
536
056:15 = -: 8
5
Therefore
Therefore