Bairstow et lavaur effets des sous titres et des consignes de visionnage SFP 2012 Montpellier 0912
MODELO DE BAIRSTOW
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La ecuación es: x 5 + 4 x 4 + x 3 −10 x 2 −4 x + 8 r : 1 s: 1 El Polinomio Factor: x 2 −x−1 a b c (5) 1 1 1 (4) 4 5 6 (3) 1 7 14 (2) -10 2 22 (1) -4 5 41 (0) 8 15 No se necesita. El Polinomio Factor: x 2 + 0.111 x−2.388 a b c (5) 1 1 1 (4) 4 3.889 3.778 (3) 1 2.956 4.924 (2) -10 -1.041 9.590 (1) -4 3.174 13.868 (0) 8 5.161 No se necesita b 0 =−5 b 1 =−15 C 2 ( Δr )+ C 3 ( Δs )=−b 1 C 1 ( Δr )+ C 2 ( Δs )=−b 0 ( Δr )=−1.111 ( Δs )=1.388 r n =1−1.111=−0 . 111 s n =1+1.388= 2.388 b 0 =−3.174 b 1 =−5.161 C 2 ( Δr )+ C 3 ( Δs )=−b 1 C 1 ( Δr )+ C 2 ( Δs )=−b 0 ( Δr )=−0.212 ( Δs )=−0.231 r n =−0.111−0.212=−0.323 s n =2.388−0.231=2 . 157
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Transcript of MODELO DE BAIRSTOW
La ecuación es:
x5+4 x4+x3−10 x2−4 x+8r : 1s: 1
El Polinomio Factor:
x2−x−1a b c
(5) 1 1 1(4) 4 5 6(3) 1 7 14
(2) -10 2 22(1) -4 5 41(0) 8 15 No se necesita.
El Polinomio Factor:
x2+0 .111x−2 .388
a b c(5) 1 1 1(4) 4 3.889 3.778(3) 1 2.956 4.924
(2) -10 -1.041 9.590(1) -4 3.174 13.868(0) 8 5.161 No se necesita
b0=−5b1=−15C2 (Δr )+C3 (Δs)=−b1C1 (Δr )+C2 (Δs)=−b0(Δr )=−1.111(Δs )=1.388rn=1−1 .111=−0.111sn=1+1.388=2 .388
El Polinomio Factor:
x2+0 .323 x−2.157
a b c(5) 1 1 1(4) 4 3.677 3.354(3) 1 1.969 3.042
(2) -10 -2.704 3.548(1) -4 1.120 6.535(0) 8 1.805 No se necesita
El Polinomio Factor:
x2+0 .531x−2.032
a b c(5) 1 1 1(4) 4 3.469 2.938(3) 1 1.189 1.660
(2) -10 -3.582 1.506(1) -4 0.318 2.891(0) 8 0.552 No se necesita
b0=−3 .174b1=−5 .161C2 (Δr )+C3 (Δs)=−b1C1 (Δr )+C2 (Δs)=−b0(Δr )=−0.212(Δs )=−0 .231rn=−0 .111−0.212=−0 .323sn=2.388−0.231=2.157
b0=−1 .120b1=−1.805C2 (Δr )+C3 (Δs)=−b1C1 (Δr )+C2 (Δs)=−b0(Δr )=−0.208(Δs )=−0 .125rn=−0 .323−0 .208=−0 .531sn=2.157−0 .125=2.032
El Polinomio Factor:
x2+0 .703 x−2.123
a b c(5) 1 1 1(4) 4 3.297 2.594(3) 1 0.805 1.104
(2) -10 -3.566 1.164(1) -4 0.215 1.740(0) 8 0.278 No se necesita
El Polinomio Factor:
x2+0 .798 x−2.03
a b c(5) 1 1 1(4) 4 3.202 2.404(3) 1 0.474 0.585
(2) -10 -3.878 0.535(1) -4 0.056 0.816
b0=−0 .318b1=−0 .552C2 (Δr )+C3 (Δs)=−b1C1 (Δr )+C2 (Δs)=−b0(Δr )=−0.172(Δs )=−0 .034rn=−0 .531−0 .172=−0 .703sn=2.157−0 .034=2 .123
b0=−0 .215b1=−0 .278C2 (Δr )+C3 (Δs)=−b1C1 (Δr )+C2 (Δs)=−b0(Δr )=−0.095(Δs )=−0 .093rn=−0 .703−0 .095=−0.798sn=2.123−0.093=2.03
(0) 8 0.082 No se necesita
El Polinomio Factor:
x2+0 .892 x−2.0395
a b c(5) 1 1 1(4) 4 3.108 2.216(3) 1 0.267 0.329
(2) -10 -3.899 0.327(1) -4 0.022 0.401(0) 8 0.028 No se necesita
El Polinomio Factor:
x2+0 .972 x−2.0525
a b c(5) 1 1 1(4) 4 3.028 2.056(3) 1 0.109 0.163
(2) -10 -3.891 0.170(1) -4 0.0057 0.175
b0=−0 .056b1=−0 .082C2 (Δr )+C3 (Δs)=−b1C1 (Δr )+C2 (Δs)=−b0(Δr )=−0.094(Δs )=−0 .0095rn=−0 .798−0 .094=−0 .892sn=2.03−0 .0095=2 .0395
b0=−0 .022b1=−0 .028C2 (Δr )+C3 (Δs)=−b1C1 (Δr )+C2 (Δs)=−b0(Δr )=−0.080(Δs )=0 .013rn=−0 .892−0 .080=−0.972sn=2.0395+0 .013=2.0525
(0) 8 0.0081 No se necesita
bo y b1 tienden a 0.
El Polinomio Factor:
( x5+4 x4+x3−10 x2−4 x+8 )(x2+0 .036 x−1 .040)
=x3+3 .964 x2+1 .897x−5.945
b0=−0 .0057b1=−0 .0081C2 (Δr )+C3 (Δs)=−b1C1 (Δr )+C2 (Δs)=−b0(Δr )=0.936(Δs )=−1 .012rn=−0 .972+0 .936=−0 .036sn=2.0525−1.012=1 .040
