Cong thuc

8
B C I I . β = β C bh B I k I = β C B I I > 5 , 1 2 , 1 ÷ = bh k B C FE I I h = = = π θ θ π 2 0 0 ) ( 2 1 ). ( 1 d u dt t u T U d T d d = π θ θ π 2 0 ) ( 2 1 d i I d d d sd BA P k S S S . 2 2 1 = + = AC ϕ 1 1 1 .I U S = 1 A ϕ = = m i i i I U S 1 2 2 2 0 1 U U k m dm = An ϕ 1 K ϕ KC ϕ Kn ϕ An A A A ϕ ϕ ϕ ϕ > > > > .... 3 2 1 KC A ϕ ϕ > 1 = = = = 2 2 2 45 . 0 2 sin 2 2 1 ) ( 2 1 U U d U d u U d d π θ θ π θ θ π d d d R U I = d tbv I I = 2 2 2 U U m =

description

Cong thuc ctm

Transcript of Cong thuc

  • BC

    II .=

    C

    bhB

    I

    kI =

    C

    B

    I

    I > 5,12,1 =bh

    k

    B

    C

    FE

    I

    I

    h =

    ==

    2

    00

    )(2

    1).(

    1dudttu

    T

    U

    d

    T

    dd

    =

    2

    0

    )(2

    1diI

    dd

    dsdBA

    Pk

    SS

    S .2

    21 =+

    =

    AC

    111 .IUS = 1A

    =

    =m

    i

    ii

    IUS

    1222

    0

    1

    U

    U

    k

    m

    dm

    = An 1K KC

    Kn

    AnAAA

    >>>> ....321

    KCA

    >1

    ==== 222 45.02

    sin22

    1)(

    2

    1UUdUduU

    dd

    d

    d

    d

    R

    U

    I =dtbv

    II = 22 2UU m =

  • 22 9.022

    UUU

    d

    ==

    d

    d

    d

    R

    U

    I =

    2d

    tbv

    I

    I = I 2max 2UU ngV =

    22

    90

    30

    22

    90

    30

    34,263

    )]120sin(sin[2

    6)(

    621

    UUdUUduuU

    o

    o

    o

    o

    o

    mmbad

    ====

    2

    )cos1(2sin2

    2

    1)(

    2

    122

    2

    0

    2

    +=== UdUdUU d

    220 45,02

    UUU

    d

    ==

    )(2

    )cos1(00

    fUUU

    ddd

    =+

    =

    2

    cos19,0

    2

    )cos1(20

    +=

    += UUU

    dd

    1 2

    2

    )cos1(

    2

    )cos1(22sin2

    1)(

    2

    1022

    2

    0

    +=

    +=== ddd UUdUdUU

    20 9,0 UU d =

    3

    )30(.1

    3

    )30(.1

    2

    63

    )]30(.1[2

    23sin2

    2

    1)(

    2

    1

    02

    22

    2

    0

    2

    o

    d

    o

    o

    d

    sCo

    U

    sCo

    U

    scoUdUdUU

    ++=

    ++=

    ++===

    ( 2.24)

  • sCoUdUU

    oo

    o

    d

    .2

    63)(2

    2

    32

    12030

    30

    2 == ++

    +

    (2.25)

    20 34,2. UsCoUU dd == (2.29)

    2

    )60(.1

    2

    )60(.16332

    302

    60

    2

    o

    d

    o

    d

    sCo

    U

    sCo

    UdSinUU

    o

    ++=

    ++==

    +

    (2.30)

    2

    cos19,0

    2

    )cos1(20

    +=

    += UUU

    dd

    ( 2.89)

    d

    d

    d

    R

    U

    I

    =

    ddTtb

    IdII

    ==

    22

    1. ( 2.91)

    ddDtb

    IdII + +

    ==

    0

    . 22

    1 ( 2.92)

    CosUCosUU

    tiadd 20 17,1. ==

    200 17,1 UUU tiadd ==

    )cos1(17,1)cos1( 20 +=+= UUU tiadd

    2

    134,2

    2

    120

    Cos

    U

    Cos

    UU

    Caudd

    +=

    +=

    Chng

    )(2

    2sin

    )2cos1(2

    2)sin2(

    1

    2

    1

    1

    212

    0

    21

    2

    0

    21

    fU

    d

    U

    dUduU

    t

    =+

    =

    ===

    ( 3.67)

  • )2

    2sin(

    +=P

    P (3.68)

    2sin.PQ = (3.69)

    +==

    )cos1(sin1

    R

    U

    d

    R

    U

    I

    mm

    t

    (3.70)

    2

    2sin

    2sin)(

    1 22

    +== R

    U

    d

    R

    U

    I

    mm (3.71)

    d

    di

    LRLU

    m

    ...sin += ( 3.72)

    tg

    m

    eA

    Z

    U

    i

    += .)sin()( ( 3.73)

    22 )( LRz +=

    R

    L

    arctg

    =

    =

    tg

    m

    e

    z

    U

    i ).sin()sin()(

    tg

    e

    =+ ).sin()sin( (3.74)

    .1

    0

    E

    T

    EEdt

    T

    U

    R

    === (3.1)

  • ==1

    0

    11 )(1

    t

    T

    Idtti

    T

    I

    (3.35)

    t

    L

    UE

    Iti

    t

    += min1 )( (3.29)

    t

    L

    U

    Iti

    t+= max2 )( (3.30)

    ==T

    t

    tD

    Idtti

    T

    I

    1

    )1()(1

    2 (3.36)

    EUU

    DT

    ==

    P

    t

    T

    P

    P = (3.37)

    Ch dng in gin on

    im gii hn gia lin tc v gin on tng ng vi iu kin : I min = 0.

    fL

    E

    I

    tgioihan .2

    )1( = ( 3.38)

    Gi tr in cm gii hn:

    fI

    E

    L

    tgh

    gioihan .2

    )1( = (3.39)

    Khong dn in gii hn:f

    gioihan

    ..21 =

    Trong :t

    R

    L

    =

    Quan h:

    E

    fLI

    E

    U

    t

    t

    .22

    2

    =

    (3.43) Vi:

    dtt

    L

    U

    T

    L

    UE

    T

    dt

    L

    UE

    T

    I

    t t

    ttt

    t

    +

    =

    1 2

    0 0

    1 .11

  • Ngoi vng gii hn l vng dng in lin tc m t bng quan h:

    ttt

    IREU .. = (3.44)

    tT

    II .1

    = (3.56)

    ==1

    t

    LD

    I

    II

    (3.57)

    200

    )1(1

    =

    RIE

    U

    t

    t

    (3.58)

    0

    20

    max 4 RI

    E

    U

    t

    t

    = (3.61)

  • =1

    . 0EU

    t

    (3.68)

    t

    E

    U

    t

    sin4

    (4.24a)

    ).sin(4

    22

    +

    = tXR

    E

    i

    tt

    t

    (4.25a)

    =

    1

    .).sin(2

    1

    t

    mT

    tdtII

    (4.26)

    I =1

    .).sin(2

    1 t

    t

    mD

    tdtII

    (4.27)

    )2ln21(3

    .

    =

    ct

    t

    UR

    TE

    C

    (4.280

    t

    t

    t

    R

    L

    T =

    EdttUU

    Pp 3

    2)(

    2

    1 2

    0

    2 ==

    ( 4.29)

    tSinEtu

    A

    ..3

    2)( = (4.30)

    )120.(.3

    2)( o

    B

    tSinEtu =

    )240.(.3

    2)( o

    C

    tSinEtu =

    o

    o

    UU 5sin2 2= (6.7)

    t

    C

    I

    dtI

    C

    U

    C

    t

    CC ==0

    1 (6.8)

  • 12

    2 TCR

    E

    UU

    C

    == (6.9)

    22

    2 TCR

    E

    UU

    C

    == (6,10)

    ConstI

    R

    E

    I

    CR

    ===

    t

    RC

    E

    dt

    R

    E

    C

    dtI

    C

    UU

    t t

    CCR

    =

    =

    ==

    0 0

    11 (6.11)

    t

    RC

    U

    RC

    U

    ttdU

    RC

    U

    mm

    t

    mR

    cos.sin1

    0

    =

    = (6.12)

    RC

    U

    U

    m

    cd

    =

    t

    RC

    U

    U

    m

    R

    cos=

    21

    C

    B

    I

    I = (6.19)

    B

    V

    B

    IK

    U

    R

    .=

    & &

    tUU

    mRC

    cos)1( =

    dkm

    UU =cos

    m

    dk

    U

    U

    ar cos= (6.1)

    dk

    m

    d

    dd

    U

    U

    U

    UU

    00 cos == ( 6.3)