Cong thuc
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Transcript of Cong thuc
-
BC
II .=
C
bhB
I
kI =
C
B
I
I > 5,12,1 =bh
k
B
C
FE
I
I
h =
==
2
00
)(2
1).(
1dudttu
T
U
d
T
dd
=
2
0
)(2
1diI
dd
dsdBA
Pk
SS
S .2
21 =+
=
AC
111 .IUS = 1A
=
=m
i
ii
IUS
1222
0
1
U
U
k
m
dm
= An 1K KC
Kn
AnAAA
>>>> ....321
KCA
>1
==== 222 45.02
sin22
1)(
2
1UUdUduU
dd
d
d
d
R
U
I =dtbv
II = 22 2UU m =
-
22 9.022
UUU
d
==
d
d
d
R
U
I =
2d
tbv
I
I = I 2max 2UU ngV =
22
90
30
22
90
30
34,263
)]120sin(sin[2
6)(
621
UUdUUduuU
o
o
o
o
o
mmbad
====
2
)cos1(2sin2
2
1)(
2
122
2
0
2
+=== UdUdUU d
220 45,02
UUU
d
==
)(2
)cos1(00
fUUU
ddd
=+
=
2
cos19,0
2
)cos1(20
+=
+= UUU
dd
1 2
2
)cos1(
2
)cos1(22sin2
1)(
2
1022
2
0
+=
+=== ddd UUdUdUU
20 9,0 UU d =
3
)30(.1
3
)30(.1
2
63
)]30(.1[2
23sin2
2
1)(
2
1
02
22
2
0
2
o
d
o
o
d
sCo
U
sCo
U
scoUdUdUU
++=
++=
++===
( 2.24)
-
sCoUdUU
oo
o
d
.2
63)(2
2
32
12030
30
2 == ++
+
(2.25)
20 34,2. UsCoUU dd == (2.29)
2
)60(.1
2
)60(.16332
302
60
2
o
d
o
d
sCo
U
sCo
UdSinUU
o
++=
++==
+
(2.30)
2
cos19,0
2
)cos1(20
+=
+= UUU
dd
( 2.89)
d
d
d
R
U
I
=
ddTtb
IdII
==
22
1. ( 2.91)
ddDtb
IdII + +
==
0
. 22
1 ( 2.92)
CosUCosUU
tiadd 20 17,1. ==
200 17,1 UUU tiadd ==
)cos1(17,1)cos1( 20 +=+= UUU tiadd
2
134,2
2
120
Cos
U
Cos
UU
Caudd
+=
+=
Chng
)(2
2sin
)2cos1(2
2)sin2(
1
2
1
1
212
0
21
2
0
21
fU
d
U
dUduU
t
=+
=
===
( 3.67)
-
)2
2sin(
+=P
P (3.68)
2sin.PQ = (3.69)
+==
)cos1(sin1
R
U
d
R
U
I
mm
t
(3.70)
2
2sin
2sin)(
1 22
+== R
U
d
R
U
I
mm (3.71)
d
di
LRLU
m
...sin += ( 3.72)
tg
m
eA
Z
U
i
+= .)sin()( ( 3.73)
22 )( LRz +=
R
L
arctg
=
=
tg
m
e
z
U
i ).sin()sin()(
tg
e
=+ ).sin()sin( (3.74)
.1
0
E
T
EEdt
T
U
R
=== (3.1)
-
==1
0
11 )(1
t
T
Idtti
T
I
(3.35)
t
L
UE
Iti
t
+= min1 )( (3.29)
t
L
U
Iti
t+= max2 )( (3.30)
==T
t
tD
Idtti
T
I
1
)1()(1
2 (3.36)
EUU
DT
==
P
t
T
P
P = (3.37)
Ch dng in gin on
im gii hn gia lin tc v gin on tng ng vi iu kin : I min = 0.
fL
E
I
tgioihan .2
)1( = ( 3.38)
Gi tr in cm gii hn:
fI
E
L
tgh
gioihan .2
)1( = (3.39)
Khong dn in gii hn:f
gioihan
..21 =
Trong :t
R
L
=
Quan h:
E
fLI
E
U
t
t
.22
2
=
(3.43) Vi:
dtt
L
U
T
L
UE
T
dt
L
UE
T
I
t t
ttt
t
+
=
1 2
0 0
1 .11
-
Ngoi vng gii hn l vng dng in lin tc m t bng quan h:
ttt
IREU .. = (3.44)
tT
II .1
= (3.56)
==1
t
LD
I
II
(3.57)
200
)1(1
=
RIE
U
t
t
(3.58)
0
20
max 4 RI
E
U
t
t
= (3.61)
-
=1
. 0EU
t
(3.68)
t
E
U
t
sin4
(4.24a)
).sin(4
22
+
= tXR
E
i
tt
t
(4.25a)
=
1
.).sin(2
1
t
mT
tdtII
(4.26)
I =1
.).sin(2
1 t
t
mD
tdtII
(4.27)
)2ln21(3
.
=
ct
t
UR
TE
C
(4.280
t
t
t
R
L
T =
EdttUU
Pp 3
2)(
2
1 2
0
2 ==
( 4.29)
tSinEtu
A
..3
2)( = (4.30)
)120.(.3
2)( o
B
tSinEtu =
)240.(.3
2)( o
C
tSinEtu =
o
o
UU 5sin2 2= (6.7)
t
C
I
dtI
C
U
C
t
CC ==0
1 (6.8)
-
12
2 TCR
E
UU
C
== (6.9)
22
2 TCR
E
UU
C
== (6,10)
ConstI
R
E
I
CR
===
t
RC
E
dt
R
E
C
dtI
C
UU
t t
CCR
=
=
==
0 0
11 (6.11)
t
RC
U
RC
U
ttdU
RC
U
mm
t
mR
cos.sin1
0
=
= (6.12)
RC
U
U
m
cd
=
t
RC
U
U
m
R
cos=
21
C
B
I
I = (6.19)
B
V
B
IK
U
R
.=
& &
tUU
mRC
cos)1( =
dkm
UU =cos
m
dk
U
U
ar cos= (6.1)
dk
m
d
dd
U
U
U
UU
00 cos == ( 6.3)