1ESC_590.Ch_2&13.Redox_Rxns.09[1]
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Transcript of 1ESC_590.Ch_2&13.Redox_Rxns.09[1]
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EVSC 590
Oxidation -Reduction (Redox)
Soil Microbiology:
An Exploratory ApproachChapter 2 and 13
Pages 17-18 and 163-165
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Redox Reactions
An Oxidation-Reduction (redox) reaction is
a chemical reaction in which electrons aretransferred completely from one species to
another.
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Redox Reactions
The chemical species which loses electrons
in this transfer process is called oxidized
whereas the one receiving electrons is
called reduced.
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Oxidation is the loss of electrons and
Reduction is the gain of electrons.
All chemical elements can accept or donate
electrons under appropriate conditions.
Redox Reactions
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Redox Reactions
Oxidation and Reduction always occur
together because a substance can only
donate electrons if another substance canaccept it.
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Redox Reactions
The chemical conditions of soils and nature
limit the number of elements involved in
natural electron exchange.
Many inorganic chemical reactions and
virtually all biological reactions of C, N,and S are oxidation-reduction (redox)
reactions
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Redox Potentials
The redox reaction below has two half
cells
H2+ 1/2O2 H20 Eq. 1an oxidation
H2 2H+ + 2e- Eq. 2and a reduction
1/2 O2 + 2H+ +2e- H20 Eq. 3
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Redox Potentials
The tendency of reactions to occur is based
on the relative tendencies of reactions 2 and
3 to proceed in the directions indicated.
This tendency is determined by the
electromotive force or potential(E) of the
reaction.
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Redox Potentials
The electromotive force for a half reactionis determined by measuring the electricpotential generated relative to a referenceelectrode(normally a hydrogen electrode).
By convention, the H electrode is assigned ahalf reaction potential (Eh) of 0.00v under
standard state conditions, i.e.H+ (1M) + e- 1/2H2 (1atm) Eh
o=0.00V
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Redox Potentials
The Eho is corrected to pH 7 and designated
Eho to reflect metabolic activity at neutral
conditions.
To facilitate comparisons, half reactions arewritten as reductions and the sign of the
corresponding electrical potential isadjusted accordingly.
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Redox Couples
In redox couples oxidized form is always
placed on the left.
e.g. 2H +/H2 or O2/ H2O
H+ and O2 are the oxidized forms
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Redox Couples
When constructing complete oxidation
reduction reactions from constituent half
reactions, the reduced substance of a redoxcouple whose reduction potential is the
more negative donates electron to the
oxidized substance whose potential is more
positive.
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Redox Potentials
The standardized values are referred to as
reduction potentials , for example,
2H+ + 2e- H2 Eo= -0.42V Eq.41/2 O2 + 2H
++2e-H20 Eo=+0.82V Eq.5
Since Eq 4 is more negative than Eq 5, Eq 5has a greater tendency to proceed as written.
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FREE ENERGY
For the reaction; H2 +1/2 O2H20
Eo = +0.82 (-0.42) = +1.2
Go = -(2) (23.1) (1.24)
= -239 KJ mol-1 ofH20 produced
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FREE ENERGY
One very useful measure of metabolic
reaction is the free energy change also
known as the Gibbs free energy.
Gro is the intrinsic energy contained in a
given substance.
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FREE ENERGY
For a reaction X Y, the free energychange DGo is the difference between the
free energy of the product Y and thereactant X
DGo = Gy -Gx
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FREE ENERGY
Negative DG = Exergonic,
Positive DG = Endogonic,
Zero DG = Equlibrium
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FREE ENERGY
DGo for redox reaction can be calculated
using the following equation.
DGo = -nFDEo
N = # of electrons transferred
F = Faradays constant (96.5KJV-1 mol-1)
= 23.1 V-1 mol-1
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FREE ENERGY
DEo= difference in reduction potentials for
the two half reactions comprising the
combined reaction. For the reaction; H2 + 1/2 O2 H20DEo = +0.82 (-0.42) = +1.2
DGo = -(2) (23.1) (1.24)
= -239 KJ mol-1 of H20 produced
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FREE ENERGY
For the reaction
Ox + mH+ + ne Red DGr = DGro + RTln(Red)/(Ox)(H+)m
DGro= -nFEo
DGr= -nFE
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Nerst Equation
Nernst Equation relates activities of to Eh
-nFE = -nFEo + RT ln(Red)/(Ox)(H+)m
Eh= Eho- RT/nFln(red)/(Ox) - mRT/nF lnH+
Reduces to Eh = 2.303RT/F x pe
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Concept of pe
Just as pH is based on moles L-1, redox
potential can also be expressed in terms of
pe (-log of electron activity) which iscompatible with units of moles per liter.
In this way, electrons can be treated as other
reactants and products so that both can beexpressed by a single equilibrium constant.
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Concept of pe
pe = -log (e-)
It measures the relative tendency of a
solution to accept electrons.
Reducing solutions have low pe and tend to
donate electrons to species placed in thesolution.
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Concept of pe
Oxidizing solutions have high pe and tend
to accept electrons from species placed in
the solution. Large values of pe favor the existence of
electron- poor (i.e) oxidized species just as
large values of pH favor the existence ofproton poor species (i.e bases)
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Concept of pe
Small values of pe favor electron- rich, or
reduced, species, just as small values of pH
favor proton rich species, acids.
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Concept of pe
Unlike pH, however, pe can take on
negative values.
The largest pe value is +13.0 and the
smallest is near -6.0.
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pe vs Eh
Eh (millivolts) = 59.2pe
Eh (Volts) = 0.059 pe
e.g. For (CO2/ CH2O), -0.43V
pe = 0.059 x0. 43 =
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Table 1. Redox Pairs Arranged in Order from the
Strongest Reductants to the Strongest Oxidantsa
(Paul and Clark, 1989).
Redox Pair pe Eh (volts)
CO2/CH2O -7.3 -0.43
SO4
2-/H2S -3.7 -0.22
NO3-/N2 7.11 0.42
MnO2/Mn2+ 8.1 0.48
NO3-/N2 12.4 0.74
Fe3+/Fe2+ 12.9 0.761/2 O2/H2O 13.9 0.82
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Concept of pe
In soils the pe range can be divided into 3
parts that corresponds to:
1) oxic soils (pe > + 7 at pH 7)
2) Sub oxic soils (2 < pe < + 7 pe at pH 7)
3) Anoxic soils ( pe < + 2 at pH 7)
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pe + pH
Most soil systems consist of aqueous
environments in which the dissociation of
water into H2(g) or O2(g) imposes redoxlimit on soils
On the reduced side the redox limit is given
by the reaction;H+ + e- 1/2 H2 g Rxn.1
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pe + pH
H+ + e- 1/2 H2 g K = (H2)g
1/2/(H+) (e-) ,
K = 1, thus log K = 0
or log K = 1/2 log H2 (g) - log (H+) - log(e-)
At H2
=1 atm, pe + pH = O
This represents the most reduced equilibrium
conditions in natural aqueous environments.
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pe + pH
On the oxidized side the redox limit is given
by the reaction
H+
+ e-
+ 1/4 O2(g) = 1/2 H2O Rxn.2K =1/2 H2O /(H
+)(e-)(O2)1/4 =1020.78.
Log K =Log (H+) -log(e-) 1/4 log O2(g)
= 20.78
pe + pH = 20.78 + 1/4 O2(g)
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pe + pH
Thus when O2 is 1 atm,
pe + pH = 20.78.
This represents the most oxidized
equilibrium conditions in natural aqueousenvironments
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pe + pH
When the redox limits of natural aqueous
environments defined by reactions 1 and 2
are plotted we get a graph which is knownas a pE-pH diagram, and shows the domain
of electron and proton activity that has been
observed in soil environment worldwide.
Both pe and pH are needed to specify the
redox status of aqueous systems.
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Redox in soils
This pe range can be divided into 3 parts
that corresponds to:
1) Oxic soils (pE > + 7 ) at pH 7
2) Sub-oxic soils (2 < pE < + 7 ) at pH 7
3) Anoxic soils (pE < + 2 ) at pH 7