Powerpoint Templates

Post on 12-Jan-2016

70 views 0 download

description

PONDASI DANGKAL MEKANIKA TANAH II YULVI ZAIKA. Powerpoint Templates. KEDALAMAN TANAH KERAS BEBAN YANG DITAHAN BIAYA YANG TERSEDIA PENGARUH-PENGARUH LAIN. SYARAT- SYARAT PEMILIHAN PONDASI. Lapisan Tanah Keras. PONDASI TELAPAK. property line. property line. P1. P2. P 1. P2. - PowerPoint PPT Presentation

Transcript of Powerpoint Templates

Powerpoint TemplatesPage 1

Powerpoint Templates

PONDASI DANGKAL

MEKANIKA TANAH IIYULVI ZAIKA

Powerpoint TemplatesPage 2

SYARAT- SYARAT PEMILIHAN PONDASI1. KEDALAMAN TANAH KERAS

2. BEBAN YANG DITAHAN

3. BIAYA YANG TERSEDIA

4. PENGARUH-PENGARUH LAIN

Powerpoint TemplatesPage 3

PONDASI TELAPAK

Lapisan Tanah Keras

Powerpoint TemplatesPage 4

Combined footing

2 footings close

to each other

P1 close to property

line and P2 > P1

property line

P1 P2

If P2/P1 < 1/2, use strap combined footing

property line

If 1/2 < P2/P1 < 1

use trapezoidal footing

property line

P1 P2

Powerpoint TemplatesPage 5

BENTUK PONDASI TELAPAK

Powerpoint TemplatesPage 6

Powerpoint TemplatesPage 7

PONDASI TELAPAK MENERUS/ LAJUR

Powerpoint TemplatesPage 8

Powerpoint TemplatesPage 9

Powerpoint TemplatesPage 10

PONDASI RAKIT

Powerpoint TemplatesPage 11

PONDASI RAKIT

Powerpoint TemplatesPage 12

Powerpoint TemplatesPage 13

PONDASI RAKIT

Powerpoint TemplatesPage 14

Powerpoint TemplatesPage 15

SYARAT PONDASI DANGKAL

Kedalaman tanah pondasi kurang atau sama dengan lebarnya atau kedalaman (Terzaghi, 1943).

Teori lain, kedalaman pondasi dangkal 3-4 kali lebar pondasi.

Pondasi setempat harus memenuhi syarat-syarat:

1. Stabilitas, aman terhadap keruntuhan geser

2. deformasi harus lebih kecil dari yang diizinkan.

Lapisan Tanah Keras

Df

B

Powerpoint TemplatesPage 16

METODA PELAKSANAAN

Powerpoint TemplatesPage 17

KERUNTUHAN PADA PONDASI DANGKALPADA TANAH PASIR PADAT DAN LEMPUNG KAKU

B

Powerpoint TemplatesPage 18

MODEL KERUNTUHAN GESER

» keruntuhan umum geser» pasir padat Dr>67%

» lempung kaku NSPT >12

» Koruntuhan lokal» pasir atau

» pasir kelempungan» kurang padat (medium)

» 30%<Dr<67%

» Keruntuhan penetrasi » Pasir lepas

» Dr< 30%

Beban/luas

Penurunan

qu

Beban/luas

Penurunan

qu1

qu

Beban/luas

Penurunan

qu1

qu qu

Permukaan runtuh

Permukaan runtuh

Permukaan runtuh

(a)

(b)

(c)

Powerpoint TemplatesPage 19

MODEL KERUNTUHAN BERDASARKAN RELATIF DENSITY

Powerpoint TemplatesPage 20

Terzaghi Assumptions

• 1.    Soil under footing is homogeneous and isotropic  • 2. Soil surface is horizontally• 3. The base of footing is rough, to prevent the shear displacement.• 4      The foot is shallow foundation, i.e. the depth of foundation is less than

the width of foot…

• Df      ≤        B• 3.     Shear strength above the level of the base of footing is negligible.

c = 0 above ( F.L ).• 4.     Consider only the surcharge which produced as uniform pressure     •    q = »DF at foundation level.

• 5.      The load on foundation is vertical and uniform.• 6.     The foot is long strip footing (pondasi lajur, B/L » 0). • 7. » = »

Powerpoint TemplatesPage 21

Shear failure happened on many stages

• I) Stage I: The soil in the elastic case and behave as the part of foundation it still that, and by increasing the load performed the region I which called active zone.

• II)     Stage II: At this stage the foundation load effect on the active zone and neighboring soil so perform the region which called arc of logarithmic spiral zone.

• III)    Stage III: By increasing the load performed the third part curve in which part the soil became in the passive case it make to resist the failure.

Powerpoint TemplatesPage 22

PROSES TERJADINYA KERUNTUHAN

Powerpoint TemplatesPage 23

Three components produced to resist the failure of soil.

I)  (Pp)γ   = Component produced by the weight of shear zone II,

III.

II)(Pp)c = Component produced by the cohesive stress.

III) (Pp)q = Component produced by the surcharge q.

Pp     =       (Pp)γ +   (Pp)c  +   (Pp)q

Powerpoint TemplatesPage 24

DASAR PENURUNAN RUMUS TERZAGHI

• Kesetimbangan Gaya qu(2b)= -W+ 2Pp+f sin f• W=(1/2)2bg btan =a b2gtanf• f=c DC= c. b/cosf• Pp=(1/2)g (b tan f)2 Kg + c (b tan f)Kc +q(b tan f) Kq• qu =c{tan (f Kc +1)} +q(tan f Kq) + g B/2{(1/2) tan (f Kg. tan -1)}f

Zona aktif

Zona pasif

Zona geser radial

quA B

J

PpPp

W

» »ff

B=2b

»»

Powerpoint TemplatesPage 25

PERSAMAAN DAYA DUKUNG TERZAGHIUNTUK PONDASI LAJUR/ MENERUS

1

2u c qq cN qN BN

245cos2 2

2

a

Nq =

»= e

cot1qNNc =

Powerpoint TemplatesPage 26

TEORI DAYA DUKUNG TERZAGHI (1943)

Daya dukung:

Pondasi lajur

Pondasi bujursangkar

Pondasi lingkaran

Untuk keruntuhan geser lokal:

c’ = 2/3 c dan f’ = 2/3 f

qu

q=gDf

B

Df

45-f/2 45-f/2 45-f/2 45-f/2a aA C

D

EF

H G

J I

1

2u c qq cN qN BN

1.3 0.4u c qq cN qN BN

1.3 0.3u c qq cN qN BN

Powerpoint TemplatesPage 27

GRAFIK FAKTOR DAYA DUKUNG

General shear failureLocal shear failure

Powerpoint TemplatesPage 28

PERBANDINGAN BIDANG RUNTUH

Powerpoint TemplatesPage 29

RUMUS UMUM DAYA DUKUNG PONDASIMEYERHOF (1963)

• Fcs , Fqs , F»s = faktor bentuk

• Fcd , Fqd , F»d = faktor kedalaman

• Fci , Fqi , F»i = faktor inklinasi

1

2u c cs cd ci q qs qd qi s d iq cN F F F qN F F F BN F F F

Powerpoint TemplatesPage 30

FAKTOR PENGARUH MEYERHOF

• F. BENTUK F. KEDALAMAN F. INKLINASI

245tan

1.01

1.01

2.01

2

p

ps

pqs

pcs

K

L

BKF

L

BKF

L

BKF

B

DKF

B

DKF

B

DKF

pd

pqd

pcd

1.01

1.01

2.01

2

2

190

1

o

ci qi

i

F F

F

b

Q

T

R

Powerpoint TemplatesPage 31

Powerpoint TemplatesPage 32

DISTRIBUSI TEGANGAN TANAH AKIBAT TEG. VERTIKAL DAN MOMEN

P

M

Powerpoint TemplatesPage 33

Tegangan kontak akibat beban vertikal dan momen

P

M

P

Me

e = B/6qmaxqmin

e < B/6qmax

qmin

e > B/6qmax

qmin

B

eR

Powerpoint TemplatesPage 34

P

e = B/6qmaxqmin

e < B/6qmax

qmin

e > B/6qmax

qmin

e

Powerpoint TemplatesPage 35

Pondasi Lajur

e

B

B-2e

Powerpoint TemplatesPage 36

Stabilitas Daya Dukung

C

Tegangan kontak : tegangan akibat beban

Menentukan eksentrisitas DPT

XB

eV

MX net

2;