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º∞§∞π√ 3Ô · άκρα Β, Γ της έδρας και βρήκε ότι ΑΒ = 3 m, ΑΓ = 4 m, ενώ έχουμε ότι ΒΓ = 5 m. Ο Μιχάλης, αντίστοιχα,
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