--,, 2 20132 2013
, .
3 kW
3 kW3 kW
1 kW
1 kW
20C0C
Q = A U (T )
0 5 10 15 20
10 kW
5 kW
0
.
= 0 C = 20 C
050
100
150
200
250
300
350
400
450
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
(C)
:
2070
1-3
050
100
150
200
250
300
350
400
450
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
0
2
4
6
8
10
12
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
X =
x =
(C)
.
(k
W)
0200
400
600
800
1000
1200
1400
1600
1800
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
(C)
kW
h
K
0 5 10 15 20
20 kW
10 kW
0
.
50%
kW
h
K
0 5 10 15 20
20 kW
10 kW
0
.
0 5 10 15 20
20 kW
10 kW
0
.
0 5 10 15 20
200 kW
100 kW
0
.
, 1975
(%)
(%)
:Vd
ZVe
rein
igun
gde
rde
utsc
hen
Zent
ralh
eizu
ngsw
irts
chaf
t
3 kW
3 kW3 kW
1 kW
20C00CC
Q = A U (T )= 10 kW
7070CC
1,5 kW
1,5 kW1,5 kW
0,5 kW
20C1010CC
Q = A U (T ) = 5 kW
5050CC
70C = 60
50C = 40
= 10C
0C
back
C
C
70C
:
CH4 + 2O2 CO2 + 2H2O + HU
10,0 kWh/m3
:
CH4 + 2O2 CO2 + 2H2O + HO
11,6 kWh/m3
100%
uo
c
= 9,2 kWh / 10,0 kWh = 92% = 10,7 kWh / 10,0 kWh = 107%
150
100
50
C
45C
80C
.
(kW
h /
K)
0 5 10 15 20
110%
105%
100%
95%
45C
65C
.
(kW
h /
K)
0 5 10 15 20
110%
105%
100%
95%
45C
80C
0 5 10 15 20
95%94%93%92%91%90%89%
, 1975
(%)
(%)
:Vd
ZVe
rein
igun
gde
rde
utsc
hen
Zent
ralh
eizu
ngsw
irts
chaf
t
0 5 10 15 20
200 kW
100 kW
0
.
110%
100%
90%
80%
70%
60%
-
-
20
5
15
:Vd
ZVe
rein
igun
gde
rde
utsc
hen
Zent
ralh
eizu
ngsw
irts
chaf
t
27%
35%
56%104%12kW
020
40
60
80
100
2
A/B. . .
0-5
D. ,
F. , , . . .
/E/G. .
inverter
-- ..
on/off
ON
100%
ON ON50% ON ON ON25%
0
kW
t
ON
100%
ON ON50% ON ON ON25%
0
rpm / kW
t
ON
on/off
ON
100%
ON50%25%
0
kW
t
t
: COP = Coefficient of Performance = Qc / P
: EER = Energy Efficiency Ratio = Q0 / P
log
p (
) [
MPa
]
h () [kJ/kg]
1
2
4
3pH
pL
Q0
P
Qc
H
TL2
: COP = Coefficient of Performance = Qc / P
: EER = Energy Efficiency Ratio = Q0 / P
log
p (
) [
MPa
]
h () [kJ/kg]
1
2
4
3pH
pL
Qc
Q0
P
H
TL2
: COP = Coefficient of Performance = Qc / P
: EER = Energy Efficiency Ratio = Q0 / P
log
p (
) [
MPa
]
h () [kJ/kg]
1
2
4
3pH
pL
Q0
P
Qc
H
TL2
: COP = Coefficient of Performance = Qc / P
: EER = Energy Efficiency Ratio = Q0 / P
log
p (
) [
MPa
]
h () [kJ/kg]
1
2
4
3pH
pL
Q0
P
Qc
H
TL2
6,0
5,0
4,0
3,0
2,0
COP /
COP
0 C 5 C 10 C 15 C 20 C
6,0
5,0
4,0
3,0
2,0
1,0
0,0
COP /
COP
0 C 5 C 10 C 15 C 20 C
0 C 5 C 10 C 15 C 20 C
20 kW
10 kW
0
/
.
/
.
(kW
h /
K) /
/
0 C 5 C 10 C 15 C 20 C
monoblock
0 C 5 C 10 C 15 C 20 C
20 kW
10 kW
0
COP /
.
/
0
1
2
3
4
5
6
7
0500
1000
1500
2000
2500
3000
3500
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
0
1
2
3
4
5
6
7
/ =
. / COP = .
0 C 5C 10C 15C 20C
(k
Wh)
COP
0200
400
600
800
1000
1200
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
(k
Wh)
SCOP = /
0 C 5C 10C 15C 20C
SCO
P
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
-20C -15C -10C -5C 0C 5C
( )
SCO
P
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
80C 70C 60C 50C
A/ . . 65C
SCO
P /
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
65C 55C 45C
1
3
( )
k
Wh
()
/
0
0.01
0.02
0.03
0.04
0.05
0.06
0.07
65C 55C 45C
1
3
( )
/ RR
+
+
+
0 2
/ /
/
00.10.20.30.40.50.60.70.80.9
1 CO2 (kg/kWh)
0
0.05
0.1
0.15
0.2
0.25
0.3
/
/
(50%)
/
(/kWh)
, .
Top Related