UACH Bachillerato Lab 3
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Laboratorio 3Cinemática (2)Cinemática (2)
Dr. Willy H. GerberInstituto de FisicaUniversidad Austral
Valdivia, Chile
Objetivos: Comprender y aplicar los conceptos de camino, velocidad y aceleración.
www.gphysics.net – UACH‐Laboratorio‐3‐Version 09.08
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Índice
1. Solución de la tarea2. Experimento repaso conceptos cinética
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Tarea
Solución de la tarea: seleccionar datos
15.0±0.5m 30.0±0.5m7.3±0.2s 14.2±0.2s8.0±0.2s 15.9±0.2s7.6±0.2s 14.7±0.2s7 1±0 2s 14 0±0 2s7.1±0.2s 14.0±0.2s8.3±0.2s 15.4±0.2s
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Tarea
Definir ejes
Eje y: ‐Mínimo 0 [m]
15.0±0.5m 30.0±0.5m
‐Máximo 30 [m]‐ Leyenda: “Distancia recorrida [m]”
15.0 0.5m 30.0 0.5m
7.3±0.2s 14.2±0.2s8.0±0.2s 15.9±0.2s7 6±0 2 14 7±0 27.6±0.2s 14.7±0.2s7.1±0.2s 14.0±0.2s8.3±0.2s 15.4±0.2s
Eje x: ‐Mínimo 7.1 [s] => 6.0 [s]Má i 15 6 [ ] > 16 0 [ ]
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‐Máximo 15.6 [s] => 16.0 [s]‐ Leyenda: “Tiempo transcurrido [s]”
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Tarea
Dibujo de los ejes:
Eje y:Eje y: ‐Mínimo 0 [m]‐Máximo 30 [m]‐ Leyenda: “Distancia recorrida [m]”
Eje x:
39 unidades ‐> 1 unidad = 1 m (usa 30 unidades)
j‐Mínimo 7.1 [s] => 6.0 [s]‐Máximo 15.6 [s] => 16.0 [s]‐ Leyenda: “Tiempo transcurrido [s]”
63 unidades ‐> 6 unidad = 1 s (usa 60 unidades)
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Tarea
Dibujo de los ejes:
Eje y:Eje y: ‐Mínimo 0 [m]‐Máximo 30 [m]‐ Leyenda: “Distancia recorrida [m]”30
Eje x: rrida [m
] 39 unidades ‐> 1 unidad = 1 m (usa 30 unidades)
j‐Mínimo 7.1 [s] => 6.0 [s]‐Máximo 15.6 [s] => 16.0 [s]‐ Leyenda: “Tiempo transcurrido [s]”
ancia recor
Dista 63 unidades ‐> 6 unidad = 1 s (usa 60 unidades)
0
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Tiempo transcurrido [s]6 10 16
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Tarea
Dibujo de los ejes:
15.0±0.5m 30.0±0.5m1 cuadro = 1m
7.3+0.2s
30
7.3±0.2s 14.2±0.2s8.0±0.2s 15.9±0.2s7.6±0.2s 14.7±0.2s7.3s
7.3‐0.2s 7.3+0.2s
7.3+0.2s0.4s
1.0m
rrida [m
]
7.6±0.2s 14.7±0.2s7.1±0.2s 14.0±0.2s8.3±0.2s 15.4±0.2s
15.0+0.5 m
ancia recor
15.0 m
15.0‐0.5 m
15.0±0.5 m
Dista
0
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Tiempo transcurrido [s]6 10 16
1 cuadro = 0.166s
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Tarea
Dibujar puntos y tendencia:
1 cuadro = 1m
30
rrida [m
]
15.0±0.5m 30.0±0.5m7.3±0.2s 14.2±0.2s
ancia recor
8.0±0.2s 15.9±0.2s7.6±0.2s 14.7±0.2s7 1±0 2s 14 0±0 2s
Dista
0
7.1±0.2s 14.0±0.2s8.3±0.2s 15.4±0.2s
www.gphysics.net – UACH‐Laboratorio‐3‐Version 09.08
Tiempo transcurrido [s]6 10 16
1 cuadro = 0.166s
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Tarea
Calcular velocidad media:
1 cuadro = 1m
30
rrida [m
]
20.5 unidades =20.5 m
ancia recor 20.5 m
10 s
Dista
0
www.gphysics.net – UACH‐Laboratorio‐3‐Version 09.08
Tiempo transcurrido [s]6 10 16
1 cuadro = 0.166s
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Tarea
Calcular tiempo de aceleración:
2.0
dad [m
/s]
Velocid
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0.0Tiempo [s] 15.0
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Índice
1. Solución de la tarea2. Experimento repaso conceptos cinética
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Experimento
“Caída” por una pendiente
Cordel para medir posición del carro
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Experimento
Desde abajo…
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Experimento
Desde arriba …
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Experimento
Carro acelerando
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Experimento
Sistema de “frenado amortiguado”
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Experimento
M di ió C i TiMedición: Camino vs Tiempo
ción
[m]
Posi
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Tiempo [s]
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Experimento
1. Calcule la curva Velocidad vs Tiempo
a. Seleccione los tiempos que va a dibujarb. Estudie la escala y determine la equivalencia entre metros y casillerosy q yc. Dibuje la tangente y estime la velocidad en cada punto (que cada persona
en el grupo calcule alguno de los puntos.d. Grafique el resultado
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Experimento
Calculo de las pendientes: seleccionar el punto
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Experimento
Calculo de las pendientes: dibujar tangente
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Experimento
Calculo de las pendientes: dibujar tangente
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Experimento
Calculo de las pendientes: dibujar tangente
Medir en mmMedir en mm,Determinar equivalencia escala con mmCalculo delIdem para
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Experimento
2. Verificar que la curva esta bien armada verificando que el área debajo de la curva velocidad corresponde a el camino recorrido
3 Calcular la curva Aceleración vs Tiempo3. Calcular la curva Aceleración vs Tiempo
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Experimento
4. Cual es el ángulo de declive si la aceleración vertical es g=9.8 m/s2.
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Experimento
Solución
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Solución
M di ió C i TiMedición: Camino vs Tiempo
ción
[m]
Posi
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Tiempo [s]
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Solución
Valores medidos y convertidosy
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Solución
Velocidad
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Solución
Camino calculado y medido
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Solución
Posición calculada y real
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Solución
Aceleración calculadaAceleración calculada
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Solución
Aceleración calculada
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