Tekanan Tanah

7/24/2019 Tekanan Tanah

1/13

Ka = 109

121 x sin ( 121 - 8 )1 + sin ( 12 + 8 ) x sin ( 12

sin ( 121 - 8 ) x sin ( 0

Ka =0.9452690049

0.733985 x 0.9201944 1 +0.34215 x 0.207994 2

0.92019 x 0.856729

Ka =0.9452690049

0.675409 x 1.691172756

Ka = 0.9452690049

1.1422329788

Ka = 0.8275623471

Kp = 129

121 x sin ( 121 + 8 ) 1 +sin ( 12 + 8 ) x sin ( 12

sin ( 121 + 22 ) x sin ( 0

0.7765753414

Kp = 0.733985 x 0.7765753 1 +0.34215 x 0.207994 2

0.60101 x 0.856729

Kp =0.7765753414

0.569995 x 1.881746705

Kp =0.7765753414

1.0725854434

Kp = 0.7240218914

sin2

sin2

sin2

sin2

2

2

2

sin().sin(

)sin().sin(1)sin(.sin

)(sin

+

++

=

Pa

Pp=sin

2(+ )

sin2 . sin(+)[1+sin(+). sin(+)sin(+). sin(+) ]

2

[

][

[

][ ][


2/13


3/13

Pa = 0.5 x 1.63 x 2.5 2x 0.827562

= 4.21539571

Pah = pa x cos 23

= 4.215 x 0.920442

= 3.88002603

pav = pa x sin 23

= 4.215 x 0.391

= 1.64771325

- 0 ) 2

+ 121 )

Pp = 0.5 x 1.63 x 1 2x 0.724022

= 0.59007784

Pph = Pp x cos 23

= 0.59 x 0.920442

= 0.54313226

ppv = Pp x sin 23

= 0.59 x 0.391

= 0.23064954

+ 0 ) 2

+ 121 ) = 3.88 x 0.833 + 1.00 x 0.333333

= 3.56668836

Foakto K"a#anan t"ha$ap %&'in

=14.52

= 4.07080228863.5666883582

Foakto K"a#anan t"ha$ap %"s"

Pa=1

2H2ka

Pp=1

2H

2Kp

Mo=Pah .(H3)+Pp .(D

3)

FS= Mr Mo

FS

( V) tan(2

3)+

2

3cB+Pp


4/13

Fs =8.148 0.14059814 + 3.3 = 0.590078

3.2899481883

Fs =

5.0689645418

3.2899481883

Fs = 1.5407429697 1.5

FS=

( V) tan(23 )+2

3cB+Pp

PahPP


5/13

*o P &as

1 2 0.5 1

2 2 0.5 1

3 2 0.5 1

4 2 0.5 1

5 2 0.5 1

= 1.3

3.201562

0.624695

= 14.519 -

8.1477132

-0.3443

= 8.1477(

2

= 4.0739 x

= 8.2812

, = 1.63

= 0.815

= 2

= 1.3115

= 1 0667

Pav =

Pv =

/at&

e=

B

2

Mr Mo

V

q max=

VB

[1

+

6e

B

]x

qu=cNc Fcd Fci+qNq Fqd

q=Dx

B'=B2e

Fcd=1+0 .4B '

D

Fqd=1+2 tan (1sin )2


6/13

1

aa $&k&n =

= 2.5 9.28

= 29.107Fs= 3.5149

Fd=

Fci=F

qi=(1

o

90o)

2

Fi=(1

o

o)2

o= tan1 (Pa cos

V )

qu=cNc Fcd Fci+qNq F

x x(


7/13

"at o#"n

1.3 1 1.30

1.3 1 1.30

1.3 1.5 1.95

1.3 2 2.60

1.3 2.5 3.251.6477 2.5 4.12 1.233758

8.1477 14.52

0.833333

1.028132

3.57

24

12.065523

)2

2.0328

0.5

- 0.688508

= 2.049194

=

"nan#o#"n

t =

r Mo

V

+

ci+qNq Fqd Fqi+1

2B ' N Fd Fi

x

(1sin )2 DB


8/13

= 0.555191

= 0.831136

= 4.2153957

8.1477133

= 0.5173716

= 22.94

2.049 0.555 + 0.815 2.97 1.067 0.555 +

3 k"

tan-1

tan-1

o

0o)

2

)2

cos

V )

Fci+qNq Fqd Fqi+1

2B ' N Fd Fi

x x x x) )(


9/13


10/13

0.5 1.63 1.311 1.44 1 0.831136x x xx )(


11/13

Perkuatan tebing pasangan bronjong

Gambar Diagram gaya perkuatan tebing pasangan bronjong

Data : Berat isi batu kali = 2 t#3

Porositas = 0.35

Berat bersih = (1 0,35) x 2

= 1.3 t#3 Berat isi tanah = 0.00 t#3

= 39.417

$ = 1.17

h = 4 #

= 15

ata an ip"o'"h ai apoan a/oatoia#

t#3

3,0

Pp0,5

G1

G2

G3

G4

G5

1,5

B = 2 m


12/13

$ =

1 +

= $ x (1 + )

= x 1 +=

2sin(.sin

=

Pa

Pa0,5

0,5

0,50,5

0,5

Pah

Pav


13/13

2

2

sin().sin(

)sin().sin(1)

)(sin

+

++

Tekanan Tanah

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