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PHN ICCH S DNG MY TNH FX500MS V FX 570MS

THAO TC VI S PHC TRONG K THUT IN.

I. CCH SDNGMY TNH CASIO FX - 500MS.

- ivimy tnh Casio Fx - 500MS th ta chthchincvicchuyn

iqua ligiacc dngsphc (tm sang i sv tis sang m) cn

victnh ton cng, trnhn chia bngsphcth khng thchinc.

- Numunthchinccc php tnh cng, tr, nhn, chia sphctrn

my tnh Casio Fx - 500MS th ta phi nng cp ln thnh my tnh Casio Fx -

570MS. nng cp ln thnh my tnh Casio Fx - 570MS th ta tham kho

phnsau.

1. Cch chuyn i s phc t dng s m sang dng i s

(Z= r.ej => Z= a + jb).

- nphm ON mmy

=> n r(modul) (argumen) Mn hnh hinktqu: a.

=> ntip Mn hnh hin kt qu:

b.

=> n , Ta c ktqu: a, b.

V d1:ChuynsphcdngsmZ= 2.ej60Sang dngis.

=> n 2 60 Mn hnh hinktqu: a = 1.

=> ntip Mn hnh hin kt qu: b =

1,73.

=> n , Ta c ktqu: a = 1, b = 1,73.

=> Z= 2.ej60

= 1 + j1,73

2. Cch chuyn i s phc t dng i s sang dng s m

(Z= a + jb => Z= r.ej

).

=> n a b Mn hnh hinktqu: r.

=> ntip Mn hnh hinktqu: .

=> n , Ta c ktqu: r,.

V d 2:ChuynsphcdngisZ= 1 + j sang d ngsm

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TrngTrung cpKinh t- KthutHngLam 2

=> n 1 3 Mn hnh hinktqu: r = 2.

=> ntip Mn hnh hinktqu: = 60.

=> n , Ta c ktqu: r = 2, = 60.

=> Z= 1 + j = 2ej60

II. CCH SDNGMY TNH CASIO FX - 570MS.

- My tnh Casio Fx - 570MS c 2 chthchinvisphc,

* Ch COMP: ChthchinvisphcgingnhCasio Fx - 500MS.

* ChCMPLX: Chsphc, chny ta c ththchinc

cc php tnh cngtrnhn chia ivisphc.

- chuynmy tnh sang chsphcta thchinnhsau:

* nON mmy, n (CMPLX), trn mn hnh sxuthinch

CMPLX bo rngmy tnh chuynsang chtnh vicc sphc.

- trn mn hnh hinthn thnghinthmcnhl sphcdngis.

1. Cch chuyn i s phc t dng s m sang dng i s

(Z= r.ej => Z= a + jb).

Cch 1:

- n Mn hnh hinktqu: a.

- n Mn hnh hinktqu: bi.

- n Ta c ktqu: a, bi.

Cch 2: Davo cimmn hnh hin ththnghin thsphcdngi

s.

- n Mn hnh hinktqu: a.

- n Mn hnh hinktqu: bi.

- n Ta c ktqu: a, bi.

V d 4:ChuynsphcdngsmZ = 2.ej60Sang dng is.

- n2 60 Mn hnh hinktqu: a = 1.- n Mn hnh hinktqu: b = 1,732i.

- n Ta c ktqu: a = 1, b = 1,732i.

=> Z= 2.ej60

= 1 + j1,73

2. Cch chuyn i s phc t dng i s sang dng s m

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TrngTrung cpKinh t- KthutHngLam 3

(Z= a + jb => Z = r.ej)

- n Mn hnh hinktqu: r.

- n Mn hnh hinktqu: .

- n Ta c ktqu: r, .V d 5:ChuynsphcdngisZ= 3 + j4 sang dngsm

- n3 4 Mn hnh hinktqu: r = 5.

- n Mn hnh hinktqu: = 53,13.

- n Ta c ktqu: r = 5, = 53,13.

=> Z= 3 + j4 = 5ej53,13

3. Php cng, trsphc.

a. Php cng 2 s phc.

V d 6: Thchinphp tnh sau: (1 - j2) + (3 + j4) = ?

- n 1 2 3 4

Mn hnh hinktqu: a = 4.

- n Mn hnh hinktqu: b = 2i.

- n Ta c ktqu: a = 4, b = 2i.

* (1 - j2) + (3 + j4) = 4 + j2

V d 7:Thchinphp tnh sau: 2ej60+ (3 + j4) = ?

- n2 60 3 4

Mn hnh hinktqu: a = 4.

- n Mn hnh hinktqu: b = 5,732i.

- n Ta c ktqu: a = 4, b =5,732i.

* 2ej60

+ (3 + j4) = 4 + j5,732

V d 8:Thchinphp tnh sau: 2ej60+ 5ej45= ?

n2 60 5 45 Mn hnh hinktqu: a = 4,53555.

- n Mn hnh hinktqu: b = 5,2675i.- n Ta c ktqu: a = 4,53555; b

=5,2675i.

* 2ej60

+ 5ej45

= 4,5355 +j5,2675

b. Php tr 2 s phc.

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TrngTrung cpKinh t- KthutHngLam 4

- Php trhai sphccngcthchintng tnhtrn chcnthay

vicnnt iviphp cngbngvicn nt iviphp trv phi

dng dumngocn v ngngoc n sau dutr.

3. Php nhn, chia sphc.

a. Php nhn 2 s phc.

V d 9:Thchinphp tnh sau: (1 - j2) x (3 + j4) = ?

- n 1 2 3 4

Mn hnh hinktqu: a = 11.

- n Mn hnh hinktqu: b = - 2 i.

- n Ta c ktqu: a = 11, b = - 2 i.

* (1 - j2) x (3 + j4) = 11 - j2 = 11,18e-j10,3

V d 10:Thchinphp tnh sau: 2ej60

x (3 + j4) = ?

- n2 60 3 4

Mn hnh hinktqu: a = -20,784.

- n Mn hnh hinktqu: b = 12i.

- n Ta c ktqu: a = -20.784, b =12 i.

* 2ej60

x (3 + j4) = -20,784 + j12 = 24ej150

V d 11:Thchinphp tnh sau: 2ej60x 5ej45= ?

n2 60 5 45 Mn hnh hinktqu: a = -2,588.- n Mn hnh hinktqu: b = 9,659i.

- n Ta c ktqu: a = -2,588; b =9,659i.

* 2ej60

x 5ej45

= -2,588 +j9,659 = 10ej105

b. Php chia 2 s phc.

Php trhai sphccngcthchintng tnhtrn chcnthay

vicnnt iviphp nhn bngvicn nt iviphp chia.

III. CCH NNG CPMY TNH CASIO FX 500MS THNH FX570MS

Cch nng cp ny chsdngcho my tnh Casio Fx500MS chnh hng v Dng

cho my c hinch2500000000004khi nngthithp3 phm

v 4 ln nphm .

Cc thao tc chuyninhsau:

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TrngTrung cpKinh t- KthutHngLam 5

Cch 1:

n

n (41 ln) cho nkhi mn hnh hinchData Full

n

n cho nkhi khng thncna.

n (mn hnh hinchData Full)

n

n lnlt(chm) cho nkhi mn hnh chcn con trv mitn ch

qua tri ( ).

ntip

Cch 2:

n

n (41 ln) cho nkhi mn hnh hinchData Full

n

n Cho nkhi khng n cna(scuicng l s4)

n (mn hnh hinchData Full)

n (mn hnh hinchMath Error)

n

Ch :

- Schuynichthnh cng khi ta n ngcc phm theo cc thao tc trn, nu

sai mtthao tc btkth ta phithchinlitu.

- Khi chuynithnh cng my c chcnng nhmy Casio fx570MS thchinvisphc. C mtsmy khi ta nphm hocmy tttth my s

trlimy Casio fx500MS