Sequential Logic
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Transcript of Sequential Logic
모바일컴퓨팅특강 2
강의순서강의순서 Latch FlipFlop
Active-high Clock & asynchronous Clear Active-low Clock & asynchronous Clear Active-high Clock & asynchronous Preset Active-high Clock & asynchronous Clear & Preset
Shift Register Counter
4 bits Universal Counter : 74161 Modulo 16 Up counter Modulo 16 Down counter Modulo 16 Up Down counter 0-14 hold Up counter
모바일컴퓨팅특강 4
SR LatchSR Latch
Most simple “storage element”.
Qnext = (R + Q’current)’
Q’next = (S + Qcurrent)’
In1 In2 Out0 0 10 1 01 0 01 1 0
NOR
S R Q
0 0 No change0 1 0 (reset)1 0 1 (set)
Function Table
Storing
모바일컴퓨팅특강 5
SR latches are sequentialSR latches are sequential
For inputs SR = 00, the next value of Q depends on the current value of Q.
So the same inputs can yield different outputs.
This is different from the combinational logics.
I nputs Current NextS R Q Q’ Q Q’
0 0 0 1 0 10 0 1 0 1 0
0 1 0 1 0 10 1 1 0 0 11 0 0 1 1 01 0 1 0 1 0
S R Q
0 0 No change0 1 0 (reset)1 0 1 (set)
모바일컴퓨팅특강 8
What about SR = 11?What about SR = 11?
Both Qnext and Q’next will become 0.
If we then make S = 0 and R = 0 together,
Qnext = (0 + 0)’ = 1Q’next = (0 + 0)’ = 1
But these new values go back into the NOR gates, and in the next step we get:
Qnext = (0 + 1)’ = 0Q’next = (0 + 1)’ = 0
The logic enters an infinite loop, where Q and Q’ cycle between 0 and 1 forever. (Unstable)
This is actually the worst case, so we have to avoid setting SR=11.
Qnext = (R + Q’current)’Q’next = (S + Qcurrent)’
0
0
0
0
0
0
1
1
모바일컴퓨팅특강 9
An SR latch with a control An SR latch with a control inputinput(Gated SR latch)(Gated SR latch)
The dotted blue box is the S’R’ latch from the previous slide. The additional NAND gates are simply used to generate the corr
ect inputs for the S’R’ latch. The control input acts just like an enable.
C S R S’ R’ Q
0 x x 1 1 No change1 0 0 1 1 No change1 0 1 1 0 0 (reset)1 1 0 0 1 1 (set)1 1 1 0 0 Avoid!
모바일컴퓨팅특강 10
D latch (Gated D latch)D latch (Gated D latch)
D latch is based on an S’R’ latch. The additional gates generate the S’ and R’ signals, based on inputs D (“data”) and C (“control”).
When C = 0, S’ and R’ are both 1, so the state Q does not change.
When C = 1, the latch output Q will equal the input D. Single input for both set and reset
Also, this latch has no “bad” input combinations to avoid. Any of the four possible assignments to C and D are valid.
C D Q
0 x No change1 0 01 1 1
모바일컴퓨팅특강 13
D latch simulation with D latch simulation with PrimitivePrimitive Insert the
symbol latch
모바일컴퓨팅특강 16
The D flip-flop : Edge The D flip-flop : Edge triggeringtriggering
• The D flip-flop is said to be “edge triggered” since the output Q only changes on the rising edge (positive edge) of the clock signal
DLatch
D1
C
Q1
Q’
DLatch
D2
C
Q2
Q2’
D
C
Q
모바일컴퓨팅특강 17
Timing Diagram for a D flip-Timing Diagram for a D flip-flopflop
C
D
Q
Q1
shift
shift
Positive Edge Triggering
모바일컴퓨팅특강 18
Direct inputsDirect inputs
Most flip-flops provide direct, or asynchronous, inputs that immediately sets or clears the state.
The below is a D flip-flop with active-low direct inputs.S’ R’ C D Q
0 0 x x Avoid!0 1 x x 1 (set)1 0 x x 0 (reset)
1 1 0 x No change1 1 1 0 0 (reset)1 1 1 1 1 (set)
Direct inputs to set or reset the flip-flop
S’R’ = 11 for “normal” operation of the D flip-flop
모바일컴퓨팅특강 21
FlipFlop FlipFlop with active-high Clock &with active-high Clock & asynchronous Clear asynchronous Clear
library ieee;use ieee.std_logic_1164.all;entity dff_1 is port( d, clk, nclr : in std_logic; q : out std_logic );end dff_1 ;architecture a of dff_1 isbegin
process(nclr,clk)begin if( nclr='0') then
q <='0'; elsif(clk'event and clk='1') then
q <= d; end if;end process;
end a;
모바일컴퓨팅특강 22
FlipFlop FlipFlop with active- low Clock &with active- low Clock & asynchronous Clear asynchronous Clear
library ieee;use ieee.std_logic_1164.all;entity dff_fall_1 is port( d, clk, nclr : in std_logic; q : out std_logic );end dff_fall_1 ;architecture a of dff_fall_1 isbegin
process(nclr,clk)begin if( nclr='0') then
q <='0'; elsif(clk'event and clk=‘0') then
q <= d; end if;end process;
end a;
모바일컴퓨팅특강 23
FlipFlop FlipFlop with active-high Clock &with active-high Clock & asynchronous Preset asynchronous Preset
library ieee;use ieee.std_logic_1164.all;entity dff_ preset_1 is port( d, clk, npre : in std_logic; q : out std_logic );end dff_ preset_1 ;architecture a of dff_ preset_1 isbegin
process(npre,clk)begin if( npre='0') then
q <=‘1'; elsif(clk'event and clk=‘1') then
q <= d; end if;end process;
end a;
모바일컴퓨팅특강 24
FlipFlop FlipFlop with active-high Clock &with active-high Clock & asynchronous Clear & Preset asynchronous Clear & Presetlibrary ieee; use ieee.std_logic_1164.all;entity dff_ presetclr_1 is port( d, clk, npre,nclr : in std_logic; q : out std_logic );end dff_ presetclr_1 ;architecture a of dff_ presetclr_1 isbegin
process(npre, nclr, clk)begin if( npre='0') then
q <=‘1'; elsif( nclr='0') then
q <=‘0'; elsif(clk'event and clk=‘1') then
q <= d; end if;end process;
end a;
모바일컴퓨팅특강 25
Shift RegisterShift Registerlibrary ieee; use ieee.std_logic_1164.all;use ieee.std_logic_unsigned.all;
entity shiftreg is port( d, clk,nclr : in std_logic; qa,qb : out std_logic );end shiftreg;
architecture a of shiftreg issignal tqa,tqb : std_logic;
beginprocess(nclr,clk)begin if( nclr='0') then
tqa <='0'; tqb <='0';
elsif(clk'event and clk='1') thentqa <= d; tqb <= tqa;
end if;end process;qa<=tqa; qb<=tqb;
end a;
모바일컴퓨팅특강 26
library ieee; use ieee.std_logic_1164.all; use ieee.std_logic_unsigned.all;entity cnt161_4bits is port( d3,d2,d1,d0 : in std_logic; nld,ent,enp : in std_logic; clk,nclr : in std_logic; q3,q2,q1,q0 : out std_logic; rco : out std_logic);end cnt161_4bits;architecture a of cnt161_4bits is
signal q : std_logic_vector( 3 downto 0);begin
process(nclr,clk)variable d : std_logic_vector(3 downto 0);begin
d := d3&d2&d1&d0;if( nclr='0') then q <="0000";elsif(clk'event and clk='1') then
if(nld='0') then q <= d;elsif(ent='1' and enp='1') then
q <= q+'1';end if;
end if;end process;q3<=q(3); q2<=q(2); q1<=q(1); q0<=q(0); rco <= ent and q(3) and q(2) and q(1) and q(0);
end a;
74161 은 실제로 가장 널리 사용되는 4 비트
카운터임
74161 은 실제로 가장 널리 사용되는 4 비트
카운터임
4 bits Universal Counter: 741614 bits Universal Counter: 74161
모바일컴퓨팅특강 27
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
entity mod16cnt is
port( clk,nclr : in std_logic;
q3,q2,q1,q0 : out std_logic);
end mod16cnt;
architecture a of mod16cnt is
signal q : std_logic_vector( 3 downto 0);
begin
process(nclr,clk)
begin
if( nclr='0') then q <="0000";
elsif(clk'event and clk='1') then
q <= q+'1';
end if;
end process;
q3<=q(3); q2<=q(2); q1<=q(1); q0<=q(0);
end a;
Modulo 16 Up CounterModulo 16 Up Counter
모바일컴퓨팅특강 28
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
entity mod16dncnt is
port( clk,nclr : in std_logic;
q3,q2,q1,q0 : out std_logic);
end mod16dncnt;
architecture a of mod16dncnt is
signal q : std_logic_vector( 3 downto 0);
begin
process(nclr,clk)
begin
if( nclr='0') then q <="0000";
elsif(clk'event and clk='1') then
q <= q-'1';
end if;
end process;
q3<=q(3); q2<=q(2); q1<=q(1); q0<=q(0);
end a;
Modulo 16 Down CounterModulo 16 Down Counter
모바일컴퓨팅특강 29
Modulo 16 Up Down Modulo 16 Up Down countercounter
library ieee; use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
entity UpDncnt4 is
port( clk,nclr : in std_logic;
UpDn : in std_logic;
q3,q2,q1,q0 : out std_logic);
end UpDncnt4;
architecture a of UpDncnt4 is
signal q : std_logic_vector( 3 downto 0);
begin
process(nclr,clk)
begin
if( nclr='0') then q <="0000";
elsif(clk'event and clk='1') then
if( UpDn='1') then q <= q+'1';
else q <= q-'1';
end if;
end if;
end process;
q3<=q(3); q2<=q(2); q1<=q(1); q0<=q(0);
end a;
1 이면 증가
1 이면 증가
0 이면 감소
0 이면 감소
모바일컴퓨팅특강 30
library ieee; use ieee.std_logic_1164.all;use ieee.std_logic_unsigned.all;entity mod15cnt is port( clk,nclr : in std_logic; q3,q2,q1,q0 : out std_logic);end mod15cnt;architecture a of mod15cnt is
signal q : std_logic_vector( 3 downto 0);begin
process(nclr,clk)begin
if( nclr='0') thenq <="0000";
elsif(clk'event and clk='1') thenif( q="1110") then
q<="0000";else q <= q+'1';end if;
end if;end process;q3<=q(3); q2<=q(2); q1<=q(1); q0<=q(0);
end a;
14에서 0
으로 증가
14에서 0
으로 증가
Modulo 15 Up CounterModulo 15 Up Counter
모바일컴퓨팅특강 31
library ieee; use ieee.std_logic_1164.all;use ieee.std_logic_unsigned.all;entity mod15holdcnt is port( clk,nclr : in std_logic; q3,q2,q1,q0 : out std_logic);end mod15holdcnt;architecture a of mod15holdcnt is
signal q : std_logic_vector( 3 downto 0);
beginprocess(nclr,clk)begin
if( nclr='0') then q <="0000";elsif(clk'event and clk='1') then
if( q=14) then q<=q;else q <= q+'1';end if;
end if;end process;q3<=q(3); q2<=q(2); q1<=q(1); q0<=q(0);
end a;
14에서 정지
14에서 정지
0-14 hold Up Counter0-14 hold Up Counter
모바일컴퓨팅특강 37
State Machine - State Machine - Mealy Mealy MachineMachine
Mealy Machine 현재의 상태 (Current State) 와 현재의 입력 (Inputs) 에
의해 출력이 결정
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
모바일컴퓨팅특강 38
State Machine - State Machine - Moore Moore MachineMachine Moore Machine
현재의 상태 (Current State) 에 의해 출력 (Outputs) 이 결정
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
모바일컴퓨팅특강 39
Mealy Machine – Mealy Machine – VHDL VHDL ExampleExample
S0
S1
0/00
1/00
0/01 1/10
WindowAct / RiseShot, FallShot
입력 / 출력 1, 출력 2
해석
1. WindowAct 신호가 0 에서 1 로 변하는 순간에 RiseShot 을 1 로 만들고 ,
2. WindowAct 신호가 1 에서 0 로 변하는 순간에 FallShot 을 1 로 만들어야함 ..
해석
1. WindowAct 신호가 0 에서 1 로 변하는 순간에 RiseShot 을 1 로 만들고 ,
2. WindowAct 신호가 1 에서 0 로 변하는 순간에 FallShot 을 1 로 만들어야함 ..
모바일컴퓨팅특강 40
Mealy Machine–Mealy Machine–Process 2Process 2 개 개 사용사용
Library ieee; Use ieee.std_logic_1164.all;
ENTITY RiseFallShot IS
PORT( clk : IN STD_LOGIC;
reset : IN STD_LOGIC;
WindowAct : IN STD_LOGIC;
RiseShot, FallShot : OUT STD_LOGIC);
END RiseFallShot;
ARCHITECTURE a OF RiseFallShot ISTYPE STATE_TYPE IS (s0, s1);SIGNAL state: STATE_TYPE;
BEGINPROCESS (clk, reset)BEGIN IF reset = '0' THEN state <= s0; ELSIF clk'EVENT AND clk = '1' THEN CASE state IS
WHEN s0 => IF WindowAct='1' THEN state <= s1; ELSE state <= s0; END IF;
WHEN others => IF WindowAct='0' THEN state <= s0; ELSE state <= s1; END IF;END CASE;
END IF;END PROCESS;
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
같은 부분같은 부분
Entity 문에 입출력이 표시 .Entity 문에 입출력이 표시 .
모바일컴퓨팅특강 41
Mealy Machine–Mealy Machine–Process 2Process 2 개 개 사용사용
PROCESS(state, WindowAct)
BEGIN
if( state= s0 and WindowAct='1') then
RiseShot <='1';
else
RiseShot <='0';
end if;
if( state= s1 and WindowAct='0') then
FallShot <='1';
else
FallShot <='0';
end if;
END PROCESS;
END a;
Combination
Logic F/F
Outputs
Current State
Combination
Logic
Next State
Inputs
같은 부분같은 부분
모바일컴퓨팅특강 42
Mealy Machine–Mealy Machine–Process 3Process 3 개 개 사용사용library ieee;Use ieee.std_logic_1164.all;ENTITY RiseFallShot_v2 IS
PORT(clk : IN STD_LOGIC;reset : IN STD_LOGIC;WindowAct : IN STD_LOGIC;RiseShot, FallShot : OUT STD_LOGIC);
END RiseFallShot_v2;
ARCHITECTURE a OF RiseFallShot_v2 ISTYPE STATE_TYPE IS (s0, s1);SIGNAL State, NextState: STATE_TYPE;
BEGINPROCESS (State, WindowAct)BEGIN
CASE State ISWHEN s0 =>
IF WindowAct='1' THENNextState <= s1;
ELSENextState <= s0;
END IF;WHEN others =>
IF WindowAct='0' THENNextState <= s0;
ELSENextState <= s1;
END IF;END CASE;
END PROCESS;
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
같은 부분같은 부분
Entity 문에 입출력이 표시 .Entity 문에 입출력이 표시 .
모바일컴퓨팅특강 43
Mealy Machine–Mealy Machine–Process 3Process 3 개 개 사용사용
PROCESS(reset,clk)BEGIN
IF reset = '0' THENState <= s0;
ELSIF clk'EVENT AND clk = '1' THENState <= NextState;
END IF;END PROCESS;
PROCESS(State,WindowAct) BEGIN if( State= s0 and WindowAct='1') then RiseShot <='1'; else RiseShot <='0'; end if; if( State= s1 and WindowAct='0') then FallShot <='1'; else FallShot <='0'; end if; END PROCESS;
END a;
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
같은 부분같은 부분
같은 부분같은 부분
모바일컴퓨팅특강 44
Moore Machine – Moore Machine – VHDL VHDL ExampleExample
S0000
S1010
0
01
1
S2101
1
상태출력
입력 : WindowAct
출력 : y(2:0)
해석
1. WindowAct 신호가 0 에서는 상태의 변화가 없으며 , 1 인 구간에서는 상태의 변화가 S0->S1->S2->S0 로 순환한다 .
2. 출력신호 y(2:0) 은 상태가 S0 인 경우 “ 000” 을 S1 인 경우에는 “ 010” 을 S2인 경우에는 “ 101” 을 출력한다 .
해석
1. WindowAct 신호가 0 에서는 상태의 변화가 없으며 , 1 인 구간에서는 상태의 변화가 S0->S1->S2->S0 로 순환한다 .
2. 출력신호 y(2:0) 은 상태가 S0 인 경우 “ 000” 을 S1 인 경우에는 “ 010” 을 S2인 경우에는 “ 101” 을 출력한다 .
모바일컴퓨팅특강 45
Moore Machine–Moore Machine–Process 2Process 2 개 개 사용사용
Library ieee; Use ieee.std_logic_1164.all;ENTITY MooreMachine ISPORT( clk : IN STD_LOGIC;
reset : IN STD_LOGIC;WindowAct : IN STD_LOGIC;y : OUT STD_LOGIC_vector(2 downto 0));
END MooreMachine;
ARCHITECTURE a OF MooreMachine ISTYPE STATE_TYPE IS (s0, s1,s2);SIGNAL state: STATE_TYPE;
BEGINPROCESS (clk, reset)BEGIN IF reset = '0' THEN state <= s0; ELSIF clk'EVENT AND clk = '1' THEN CASE state IS
WHEN s0 => IF WindowAct='1' THEN
state <= s1;ELSE
state <= s0; END IF;
WHEN s1 => IF WindowAct='1' THEN
state <= s2;ELSE
state <= s1; END IF;
WHEN others => IF WindowAct='1' THEN
state <= s0;ELSE
state <= s2; END IF;
END CASE; END IF;END PROCESS;
Entity 문에 입출력이 표시 .Entity 문에
입출력이 표시 .
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
같은부분
같은부분
모바일컴퓨팅특강 46
Moore Machine–Moore Machine–Process 2Process 2 개 개 사용사용
PROCESS(state)BEGIN
CASE state ISWHEN s0 =>
y <= "000";WHEN s1 =>
y <= "010";WHEN others =>
y <= "101"; END CASE;END PROCESS;END a;
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
같은 부분같은 부분
모바일컴퓨팅특강 47
Moore Machine–Moore Machine–Process 3Process 3 개 개 사용사용Library ieee;Use ieee.std_logic_1164.all;ENTITY MooreMachine_v3 ISPORT( clk : IN STD_LOGIC;
reset : IN STD_LOGIC;WindowAct : IN STD_LOGIC;y : OUT STD_LOGIC_vector(2 downto 0));
END MooreMachine_v3;
ARCHITECTURE a OF MooreMachine_v3 ISTYPE STATE_TYPE IS (s0, s1,s2);SIGNAL state, NextState: STATE_TYPE;
BEGINPROCESS ( State, WindowAct)BEGIN
CASE State ISWHEN s0 =>
IF WindowAct='1' THENNextState <= s1;
ELSENextState <= s0;
END IF;WHEN s1 =>
IF WindowAct='1' THENNextState <= s2;
ELSENextState <= s1;
END IF;WHEN others =>
IF WindowAct='1' THENNextState <= s0;
ELSENextState <= s2;
END IF;END CASE;
END PROCESS;
Entity 문에 입출력이 표시 .Entity 문에 입출력이 표시 .
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
같은 부분같은 부분
모바일컴퓨팅특강 48
Moore Machine–Moore Machine–Process 3Process 3 개 개 사용사용
PROCESS (clk, reset)BEGIN IF reset = '0' THEN state <= s0; ELSIF clk'EVENT AND clk = '1' THEN
state <= NextState; END IF;END PROCESS;
PROCESS(state)BEGIN
CASE state IS WHEN s0 =>
y <= "000"; WHEN s1 =>
y <= "010"; WHEN others =>
y <= "101"; END CASE;
END PROCESS;END a;
Combination
Logic F/FInputs
Outputs
Current State
Combination
Logic
Next State
같은부분
같은부분
같은 부분
같은 부분