Sach Bai Tap Trac Nghiem Hoa Huu Co 11

8/7/2019 Sach Bai Tap Trac Nghiem Hoa Huu Co 11

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NGUYN MINH TUNGio vin trng THPT Chuyn Hng Vng

BI TP TRC NGHIM

HO HU C 11

Mi kin ng gp ca thy c v cc em hc sinh xin gi ti a chEmail : [email protected] xin trn thnh cm n!

Dy v hc Ha hc, http://ngocbinh.webdayhoc.net


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MC LCTrang

Phn 1: Bi tp 2 - 62

Chuyn 1 : i cng ho hu c 2

Chuyn 2 : Hirocacbon no 10

Chuyn 3 : Hirocacbon khng no 16

Chuyn 4 : Hirocacbon thm - Ngun hirocacbon 29thin nhin

Chuyn 5 : Dn xut halogen - Phenol - Ancol 35

Chuyn 6 : Anehit - Xeton - Axitcacboxylic 49

Phn 2 : p n 63- 65



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Phn 1: Bi tp

CHUYN 1 : I CNG HA HC HU C

Cu 1: Thnh phn cc nguyn t trong hp cht hu c

A. nht thit phi c cacbon, thng c H, hay gp O, N sau nhalogen, S, P...B. gm c C, H v cc nguyn t khc.C.bao gm tt c cc nguyn t trong bng tun hon.D. thng c C, H hay gp O, N, sau n halogen, S, P.

Cu 2: c im chung ca cc phn t hp cht hu c l1) Thnh phn nguyn t ch yu l C v H.2) C th cha nguyn t khc nh Cl, N, P, O.3) Lin kt ha hc ch yu l lin kt cng ho tr.4) Lin kt ho hc ch yu l lin kt ion.5) D bay hi, kh chy.6) Phn ng ho hc xy ra nhanh.

Nhm cc ng l:A. 4, 5, 6. B. 1, 2, 3. C. 1, 3, 5. D. 2, 4, 6.

Cu 3: Cu to ho hc lA. s lng lin kt gia cc nguyn t trong phn t.B. cc loi lin kt gia cc nguyn t trong phn t.C. th t lin kt gia cc nguyn t trong phn t.D.bn cht lin kt gia cc nguyn t trong phn t.

Cu 4: Pht biu no sau c dng nh ngha cng thc n gin nhtca hp cht hu c ?A. Cng thc n gin nht l cng thc biu th s nguyn t ca mi nguyn t trong phn t.B. Cng thc n gin nht l cng thc biu th t l ti gin v s nguyn t ca cc nguyn

t trong phn t.C. Cng thc n gin nht l cng thc biu th t l phn trm s mol ca mi nguyn ttrong phn t.

D. Cng thc n gin nht l cng thc biu th t l s nguyn t C v H c trong phn t.Cu 5: Cho cht axetilen (C2H2) v benzen (C6H6), hy chn nhn xt ng trong cc nhn xt sau :

A. Hai cht ging nhau v cng thc phn t v khc nhau v cng thc n gin nht.B. Hai cht khc nhau v cng thc phn t v ging nhau v cng thc n gin nht.C. Hai cht khc nhau v cng thc phn t v khc nhau v cng thc n gin nht.D. Hai cht c cng cng thc phn t v cng cng thc n gin nht.

Cu 6: c im chung ca cc cacbocation v cacbanion l:A. km bn v c kh nng phn ng rt km.

B. chng u rt bn vng v c kh nng phn ng cao.C. c th d dng tch c ra khi hn hp phn ng.D. km bn v c kh nng phn ng cao.

Cu 7: Phn ng ha hc ca cc hp cht hu c c c im l:A. thng xy ra rt nhanh v cho mt sn phm duy nht.B. thng xy ra chm, khng hon ton, khng theo mt hng nht nh.C. thng xy ra rt nhanh, khng hon ton, khng theo mt hng nht nh.D. thng xy ra rt chm, nhng hon ton, khng theo mt hng xc nh.

Cu 8: Pht biu no sau y l sai ?A. Lin kt ha hc ch yu trong hp cht hu c l lin kt cng ha tr.B. Cc cht c cu to v tnh cht tng t nhau nhng v thnh phn phn t khc nhau mt

hay nhiu nhm -CH2- l ng ng ca nhau.C. Cc cht c cng khi lng phn t l ng phn ca nhau.D. Lin kt ba gm hai lin kt v mt lin kt .

Cu 9: Kt lun no sau y l ng ?Dy v hc Ha hc, http://ngocbinh.webdayhoc.net


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A. Cc nguyn t trong phn t hp cht hu c lin kt vi nhau khng theo mt th t nht nh.B. Cc cht c thnh phn phn t hn km nhau mt hay nhiu nhm -CH2-, do tnh cht

ha hc khc nhau l nhng cht ng ng.C. Cc cht c cng cng thc phn t nhng khc nhau v cng thc cu to c gi l cc

cht ng ng ca nhau.D. Cc cht khc nhau c cng cng thc phn t c gi l cc cht ng phn ca nhau.

Cu 10: Hin tng cc cht c cu to v tnh cht ho hc tng t nhau, chng ch hn kmnhau mt hay nhiu nhm metylen (-CH2-) c gi l hin tng

A. ng phn. B. ng v. C. ng ng. D. ng khi.Cu 11: Hp cht cha mt lin kt trong phn t thuc loi hp cht

A. khng no. B. mch h. C. thm. D. no hoc khng no.Cu 12: Hp cht hu c c phn loi nh sau:

A. Hirocacbon v hp cht hu c c nhm chc.B. Hirocacbon v dn xut ca hirocacbon.C. Hirocacbon no, khng no, thm v dn xut ca hirocacbon.D. Tt c u ng.

Cu 13: Pht biu khng chnh xc l:A. Tnh cht ca cc cht ph thuc vo thnh phn phn t v cu to ha hc.B. Cc cht c cng khi lng phn t l ng phn ca nhau.C. Cc cht l ng phn ca nhau th c cng cng thc phn t.D. S xen ph trc to thnh lin kt , s xen ph bn to thnh lin kt .

Cu 14: Nung mt hp cht hu c X vi lng d cht oxi ha CuO ngi ta thy thot ra khCO2, hi H2O v kh N2. Chn kt lun chnh xc nht trong cc kt lun sau :

A. X chc chn cha C, H, N v c th c hoc khng c oxi.B. X l hp cht ca 3 nguyn t C, H, N.C. Cht X chc chn c cha C, H, c th c N.D. X l hp cht ca 4 nguyn t C, H, N, O.

Cu 15: Cho hn hp cc ankan sau : pentan (si 36o

C), heptan (si 98o

C), octan (si 126o

C),nonan (si 151oC). C th tch ring cc cht bng cch no sau y ?A. Kt tinh. B. Chng ct C. Thng hoa. D. Chit.

Cu 16: Cc cht trong nhm cht no di y u l dn xut ca hirocacbon ?A. CH2Cl2, CH2Br-CH2Br, NaCl, CH3Br, CH3CH2Br.B. CH2Cl2, CH2Br-CH2Br, CH3Br, CH2=CHCOOH, CH3CH2OH.C. CH2Br-CH2Br, CH2=CHBr, CH3Br, CH3CH3.D. HgCl2, CH2Br-CH2Br, CH2=CHBr, CH3CH2Br.

Cu 17: Cho cc cht : C6H5OH (X) ; C6H5CH2OH (Y) ; HOC6H4OH (Z) ; C6H5CH2CH2OH (T).Cc cht ng ng ca nhau l:

A. Y, T. B. X, Z, T. C. X, Z. D. Y, Z.

Cu 18: Trong nhng dy cht sau y, dy no c cc cht l ng phn ca nhau ?A. C2H5OH, CH3OCH3. B. CH3OCH3, CH3CHO.C. CH3CH2CH2OH, C2H5OH. D. C4H10, C6H6.

Cu 19: Cc cht hu c n chc Z1, Z2, Z3 c CTPT tng ng l CH2O, CH2O2, C2H4O2. Chngthuc cc dy ng ng khc nhau. Cng thc cu to ca Z3 l

A. CH3COOCH3. B. HOCH2CHO. C. CH3COOH. D. CH3OCHO.Cu 20: Nhng cht no sau y l ng phn hnh hc ca nhau ?

A. (I), (II). B. (I), (III). C. (II), (III). D. (I), (II), (III).Cu 21: Cho cc cht sau : CH2=CHCCH (1) ; CH2=CHCl (2) ; CH3CH=C(CH3)2 (3) ;



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CH3CH=CHCH=CH2 (4) ; CH2=CHCH=CH2 (5) ; CH3CH=CHBr (6).Cht no sau y c ng phn hnh hc ?

A. 2, 4, 5, 6. B. 4, 6. C. 2, 4, 6. D. 1, 3, 4.Cu 22: Hp cht hu c no sau y khng c ng phn cis-trans ?

A. 1,2-icloeten. B. 2-metyl pent-2-en. C. but-2-en. D. pent-2-en.Cu 23: Hp cht (CH3)2C=CHC(CH3)2CH=CHBr c danh php IUPAC l

A. 1-brom-3,5-trimetylhexa-1,4-ien. B. 3,3,5-trimetylhexa-1,4-ien-1-brom.C. 2,4,4-trimetylhexa-2,5-ien-6-brom. D. 1-brom-3,3,5-trimetylhexa-1,4-ien.

Cu 24: Hp cht (CH3)2C=CH-C(CH3)3 c danh php IUPAC l:A. 2,2,4- trimetylpent-3-en. B. 2,4-trimetylpent-2-en.C. 2,4,4-trimetylpent-2-en. D. 2,4-trimetylpent-3-en.

Cu 25: Hp cht CH2=CHC(CH3)2CH2CH(OH)CH3 c danh php IUPAC l:A. 1,3,3-trimetylpent-4-en-1-ol. B. 3,3,5-trimetylpent-1-en-5-ol.C. 4,4-imetylhex-5-en-2-ol. D. 3,3-imetylhex-1-en-5-ol.

Cu 26: Cho cng thc cu to sau : CH3CH(OH)CH=C(Cl)CHO. S oxi ha ca cc nguyn tcacbon tnh t phi sang tri c gi tr ln lt l:

A. +1 ; +1 ; -1 ; 0 ; -3. B. +1 ; -1 ; -1 ; 0 ; -3.C. +1 ; +1 ; 0 ; -1 ; +3. D. +1 ; -1 ; 0 ; -1 ; +3.

Cu 27: Trong cng thc CxHyOzNt tng s lin kt v vng l:A. (2x-y + t+2)/2. B.(2x-y + t+2). C.(2x-y - t+2)/2. D.(2x-y + z + t+2)/2.

Cu 28: a.Vitamin A cng thc phn t C20H30O, c cha 1 vng 6 cnh v khng c cha lin ktba. S lin kt i trong phn t vitamin A l

A. 7. B. 6. C. 5. D. 4.b.Licopen, cng thc phn t C40H56 l cht mu trong qu c chua, ch cha lin kt i v linkt n trong phn t. Hiro ha hon ton licopen c hirocacbon C40H82. Vy licopen c

A. 1 vng; 12 ni i. B. 1 vng; 5 ni i.C. 4 vng; 5 ni i. D. mch h; 13 ni i.

Cu 29: Metol C10H20O v menton C10H18O chng u c trong tinh du bc h. Bit phn t metolkhng c ni i, cn phn t menton c 1 ni i. Vy kt lun no sau y l ng ?A. Metol v menton u c cu to vng.B. Metol c cu to vng, menton c cu to mch h.C. Metol v menton u c cu to mch h.D. Metol c cu to mch h, menton c cu to vng.

Cu 30: Trong hp cht CxHyOz th y lun lun chn v y 2x+2 l do:A. a 0 (a l tng s lin kt v vng trong phn t).B. z 0 (mi nguyn t oxi to c 2 lin kt).C. mi nguyn t cacbon ch to c 4 lin kt.D. cacbon v oxi u c ha tr l nhng s chn.

Cu 31: Tng s lin kt v vng ng vi cng thc C5H9O2Cl l:A. 0. B. 1. C. 2. D. 3.

Cu 32: Tng s lin kt v vng ng vi cng thc C5H12O2 l:A. 0. B. 1. C. 2. D. 3.

Cu 33: Cng thc tng qut ca dn xut iclo mch h c cha mt lin kt ba trong phn t lA. CnH2n-2Cl2. B. CnH2n-4Cl2. C. CnH2nCl2. D. CnH2n-6Cl2.

Cu 34: Cng thc tng qut ca dn xut ibrom khng no mch h cha a lin kt lA. CnH2n+2-2aBr2. B. CnH2n-2aBr2. C. CnH2n-2-2aBr2. D. CnH2n+2+2aBr2.

Cu 35: Hp cht hu c c cng thc tng qut CnH2n+2O2 thuc loiA. ancol hoc ete no, mch h, hai chc. B. anehit hoc xeton no, mch h, hai chc.

C. axit hoc este no, n chc, mch h. D. hiroxicacbonyl no, mch h.Cu 36: Ancol no mch h c cng thc tng qut chnh xc nht lA. R(OH)m. B. CnH2n+2Om. C. CnH2n+1OH. D. CnH2n+2-m(OH)m.

Cu 37: Cng thc tng qut ca anehit n chc mch h c 1 lin kt i C=C l:



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A. CnH2n+1CHO. B. CnH2nCHO. C. CnH2n-1CHO. D. CnH2n-3CHO.Cu 38: Anehit mch h c cng thc tng qut CnH2n-2O thuc loi

A. anehit n chc no.B. anehit n chc cha mt lin kt i trong gc hirocacbon.C. anehit n chc cha hai lin kt trong gc hirocacbon.D. anehit n chc cha ba lin kt trong gc hirocacbon.

Cu 39: Cng thc tng qut ca ancol n chc mch h c 2 ni i trong gc hirocacbon lA. CnH2n-4O. B. CnH2n-2O. C. CnH2nO. D. CnH2n+2O.

Cu 40: Anehit mch h CnH2n 4O2 c s lng lin kt trong gc hirocacbon l:A. 0. B. 1. C. 2. D. 3.

Cu 41: Cng thc phn t tng qut ca axit hai chc mch h cha mt lin kt i trong gchirocacbon l:

A. CnH2n-4O4. B. CnH2n-2O4. C. CnH2n-6O4. D. CnH2nO4.Cu 42: Axit mch h CnH2n 4O2 c s lng lin kt trong gc hirocacbon l:

A. 0. B. 1. C. 2. D. 3.Cu 43: Tng s lin kt v vng trong phn t axit benzoic l:

A. 3. B. 4. C. 5. D. 6.Cu 44: S lng ng phn ng vi cng thc phn t C6H14A. 6. B. 7. C. 4. D. 5.

Cu 45: S lng ng phn mch h ng vi cng thc phn t C5H10 l:A. 2. B. 3. C. 6. D. 5.

Cu 46: S lng ng phn cu to ng vi cng thc phn t C5H10 l:A. 7. B. 8. C. 9. D. 10.

Cu 47: S lng ng phn mch h ng vi cng thc phn t C5H8 l:A. 7. B. 8. C. 9. D. 10.

Cu 48: S lng ng phn cha vng benzen ng vi cng thc phn t C9H12 l:A. 7. B. 8. C. 9. D. 10.

Cu 49: S lng ng phn cha vng benzen ng vi cng thc phn t C9H10 l:A. 7. B. 8. C. 9. D. 6.

Cu 50: S lng ng phn ng vi cng thc phn t C3H5Br3 l:A. 3. B. 4. C. 5. D. 6.

Cu 51: S lng ng phn ng vi cng thc phn t C3H5Cl l:A. 3. B. 4. C. 5. D. 6.

Cu 52: Hp cht C4H10O c s ng phn ancol v tng s ng phn l:A. 7 v 4. B. 4 v 7. C. 8 v 8. D. 10 v 10.

Cu 53: S lng ng phn mch h ng vi cng thc phn t C3H6O l:A. 2. B. 3. C. 4. D. 5.

Cu 54: S lng ng phn mch h ng vi cng thc phn t C4H6O2 tc dng c viNaHCO3 l:

A. 2. B. 3. C. 4. D. 5.Cu 55: S lng ng phn ng vi cng thc phn t C4H11N l:

A. 7. B. 8. C. 9. D. 10.Cu 56: Mt hp cht hu c X c khi lng phn t l 26. em t X ch thu c CO2 v H2O.CTPT ca X l:

A. C2H6. B. C2H4. C. C2H2. D. CH2O.Cu 57: Mt hp cht hu c A c M = 74. t chy A bng oxi thu c kh CO2 v H2O. C baonhiu cng thc phn t ph hp vi A?

A. 4. B. 2. C. 3. D. A.1.

Cu 58: Mt hp cht hu c A c t khi so vi khng kh bng bng 2. t chy hon ton Abng kh O2 thu c CO2 v H2O. C bao nhiu cng thc phn t ph hp vi A ?A. 2. B. A. 1. C. 3. D. 4.

Cu 59: Hp cht X c thnh phn % v khi lng : C (85,8%) v H (14,2%). Hp cht X l



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A. C3H8. B. C4H10. C. C4H8. D. kt qu khc.Cu 60: Hp cht X c %C = 54,54% ; %H = 9,1%, cn li l oxi. Khi lng phn t ca X bng88. CTPT ca X l:

A. C4H10O. B. C5H12O. C. C4H10O2. D. C4H8O2.Cu 61: Phn tch hp cht hu c X thy c 3 phn khi lng cacbon li c 1 phn khi lnghiro, 7 phn khi lng nit v 8 phn lu hunh. Trong CTPT ca X ch c 1 nguyn t S, vyCTPT ca X l

A. CH4NS. B. C2H2N2S. C. C2H6NS. D. CH4N2S.Cu 62: a.Hp cht X c CTGN l CH3O. CTPT no sau y ng vi X ?

A. C3H9O3. B. C2H6O2. C. C2H6O. D. CH3O.b.Cng thc thc nghim ca cht hu c c dng (CH3Cl)n th cng thc phn t ca hp cht

lA. CH3Cl. B. C2H6Cl2. C. C2H5Cl. D. C3H9Cl3.

Cu 63: Mt hp cht hu c gm C, H, O ; trong cacbon chim 61,22% v khi lng. Cngthc phn t ca hp cht l:

A. C3H6O2. B. C2H2O3. C. C5H6O2. D. C4H10O.Cu 64: Cht hu c X c M = 123 v khi lng C, H, O v N trong phn t theo th t t l vi72 : 5 : 32 : 14. CTPT ca X l:

A. C6H14O2N. B. C6H6ON2. C. C6H12ON. D. C6H5O2N.Cu 65: t chy hon ton 0,6 gam hp cht hu c X ri cho sn phm chy qua bnh ng dungdch Ca(OH)2 d thy c 2 gam kt ta v khi lng bnh tng thm 1,24 gam. T khi ca X sovi H2 bng 15. CTPT ca X l:

A. C2H6O. B. CH2O. C. C2H4O. D. CH2O2.Cu 66: Khi t 1 lt kh X cn 6 lt O2 thu c 4 lt CO2 v 5 lt hi H2O (cc th tch kh o cng iu kin nhit , p sut). CTPT ca X l:

A. C4H10O. B. C4H8O2. C. C4H10O2. D. C3H8O.Cu 67: t chy hon ton 3 gam hp cht hu c X thu c 4,4 gam CO2 v 1,8 gam H2O. Bit

t khi ca X so vi He (MHe

= 4) l 7,5. CTPT ca X l:A. CH2O2. B. C2H6. C. C2H4O. D. CH2O.Cu 68: t chy 1 lt hi hirocacbon vi mt th tch khng kh (lng d). Hn hp kh thuc sau khi hi H2O ngng t c th tch l 18,5 lt, cho qua dung dch KOH d cn 16,5 lt, chohn hp kh i qua ng ng photpho d th cn li 16 lt. Xc nh CTPT ca hp cht trn bitcc th tch kh o cng iu kin nhit , p sut v O2 chim 1/5 khng kh, cn li l N2.

A. C2H6. B. C2H4. C. C3H8. D. C2H2.Cu 69: t 0,15 mol mt hp cht hu c thu c 6,72 lt CO2 (ktc) v 5,4 gam H2O. Mt khct 1 th tch hi cht cn 2,5 th tch O2. Cc th tch o cng iu kin nhit , p sut.CTPT ca hp cht l:

A. C2H6O2. B. C2H6O. C. C2H4O2. D. C2H4O.

Cu 70: t chy hon ton mt hp cht hu c X (C, H, N) bng lng khng kh va (gm1/5 th tch O2, cn li l N2) c kh CO2 , H2O v N2. Cho ton b sn phm chy qua bnh ngdung dch Ba(OH)2 d thy c 39,4 gam kt ta, khi lng dung dch gim i 24,3 gam. Kh thotra khi bnh c th tch 34,72 lt (ktc). Bit

2OXd < 2. CTPT ca X l:

A. C2H7N. B. C2H8N. C. C2H7N2. D. C2H4N2.Cu 71: Oxi ha hon ton 4,02 gam mt hp cht hu c X ch thu c 3,18 gam Na2CO3 v0,672 lt kh CO2. CTGN ca X l:

A. CO2Na. B. CO2Na2. C. C3O2Na. D. C2O2Na.Cu 72: t chy hon ton mt hirocacbon trong 0,5 lt hn hp ca n vi CO 2 bng 2,5 lt O2thu c 3,4 lt kh. Hn hp ny sau khi ngng t ht hi nc cn 1,8 lt, tip tc cho hn hp kh

cn li qua dung dch kim d th cn li 0,5 lt kh. Cc th tch c o cng iu kin nhit ,p sut. CTPT ca hirocacbon l:A. C4H10. B. C3H8. C. C4H8. D. C3H6.



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Cu 73: t chy hon ton 1,605 gam hp cht hu c A thu c 4,62 gam CO2 ; 1,215 gam H2Ov 168 ml N2 (ktc). T khi hi ca A so vi khng kh khng vt qu 4. Cng thc phn t caA l:

A. C5H5N. B. C6H9N. C. C7H9N. D. C6H7N.Cu 74: Oxi ha hon ton 6,15 gam hp cht hu c X thu c 2,25 gam H2O ; 6,72 lt CO2 v0,56 lt N2 (kc). Phn trm khi lng ca C, H, N v O trong X ln lt l:

A. 58,5% ; 4,1% ; 11,4% ; 26%. B. 48,9% ; 15,8% ; 35,3% ; 0%.C. 49,5% ; 9,8% ; 15,5% ; 25,2%. D. 59,1 % ; 17,4% ; 23,5% ; 0%.

Cu 75: Phn tch 0,31gam hp cht hu c X ch cha C, H, N to thnh 0,44 gam CO2. Mt khc,nu phn tch 0,31 gam X ton b N trong X chuyn thnh NH3 ri dn NH3 va to thnh vo100 ml dung dch H2SO4 0,4M th phn axit d c trung ha bi 50 ml dung dch NaOH 1,4M.Bit 1 lt hi cht X (ktc) nng 1,38 gam. CTPT ca X l:

A. CH5N. B. C2H5N2. C. C2H5N. D. CH6N.Cu 76: t chy 200 ml hi mt hp cht hu c X cha C, H, O trong 900 ml O2, th tch hnhp kh thu c l 1,3 lt. Sau khi ngng t hi nc ch cn 700 ml. Tip theo cho qua dung dchKOH d ch cn 100 ml kh bay ra. Cc th tch kh o cng iu kin nhit , p sut. CTPTca Y l:

A. C3H6O. B. C3H8O2. C. C3H8O. D. C3H6O2.Cu 77: Phn tch 1,5 gam cht hu c X thu c 1,76 gam CO2 ; 0,9 gam H2O v 112 ml N2 o 0oC v 2 atm. Nu ha hi cng 1,5 gam cht Z 127o C v 1,64 atm ngi ta thu c 0,4 lt khcht Z. CTPT ca X l:

A. C2H5ON. B. C6H5ON2. C. C2H5O2N. D. C2H6O2N.Cu 78: t chy hon ton mt th tch hi hp cht hu c A cn 10 th tch oxi (o cng iukin nhit v p sut), sn phm thu c ch gm CO2 v H2O vi mCO2 : mH2O = 44 : 9. BitMA < 150. A c cng thc phn t l:

A. C4H6O. B. C8H8O. C. C8H8. D. C2H2.Cu 79: Cho 400 ml mt hn hp gm nit v mt hirocacbon vo 900 ml oxi (d) ri t. Th

tch hn hp thu c sau khi t l 1,4 lt. Sau khi cho nc ngng t cn 800 ml hn hp, ngita cho li qua dung dch KOH thy cn 400 ml kh. Cc th tch kh u o cng iu kin nhit, p sut. Cng thc phn t ca cht hu c l:

A. C3H8. B. C2H4. C. C2H2. D. C2H6.Cu 80: t chy 0,282 gam hp cht hu c X, cho sn phm i qua cc bnh ng CaCl2 khan vKOH d. Thy bnh ng CaCl2 tng thm 0,194 gam cn bnh ng KOH tng thm 0,8 gam. Mtkhc nu t chy 0,186 gam cht X th thu c 22,4 ml kh N2 ( ktc). Bit rng hp cht X chcha mt nguyn t nit. Cng thc phn t ca hp cht X l:

A. C6H6N2. B. C6H7N. C. C6H9N. D. C5H7N.Cu 81: t chy hon ton hp cht hu c cha C, H, Cl sinh ra 0,22 gam CO2, 0,09 gam H2O.Mt khc khi xc nh clo trong hp cht bng dung dch AgNO3 ngi ta thu c 1,435 gam

AgCl. T khi hi ca hp cht so vi hiro bng 42,5. Cng thc phn t ca hp cht l:A. CH3Cl. B. C2H5Cl. C. CH2Cl2. D. C2H4Cl2.Cu 82: t chy hon ton 0,4524 gam hp cht A sinh ra 0,3318 gam CO2 v 0,2714 gam H2O.un nng 0,3682 gam cht A vi vi ti xt chuyn tt c nit trong A thnh amoniac, ri dnkh NH3 vo 20 ml dung dch H2SO4 0,5 M. trung ho axit cn d sau khi tc dng vi NH3 cndng 7,7 ml dung dch NaOH 1M. Bit MA= 60. Cng thc phn t ca A l:

A. CH4ON2. B. C2H7N. C. C3H9N. D. CH4ON.Cu 83*: t chy hon ton 0,01 mol cht hu c X cn va 0,616 lt O2. Sau th nghim thuc hn hp sn phm Y gm : CO2, N2 v hi H2O. Lm lnh ngng t hi H2O ch cn 0,56lt hn hp kh Z (c t khi hi vi H2 l 20,4). Bit th tch cc kh u o ktc. Cng thc phnt X l:

A. C2H5ON. B. C2H5O2N. C. C2H7O2N. D. A hoc C.Cu 84: X l mt ancol no, mch h. t chy 0,05 mol X cn 4 gam oxi. X c cng thc l:

A. C3H5(OH)3. B. C3H6(OH)2. C. C2H4(OH)2. D. C4H8(OH)2.



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Cu 85: Khi t chy hon ton mt amin n chc X, thu c 16,80 lt kh CO2 ; 2,80 lt N2 (ccth tch o ktc) v 20,25 gam H2O. CTPT ca X l:

A. C4H9N. B. C3H7N. C. C2H7N. D. C3H9N.Cu 86: t chy hon ton m gam mt amin X bng lng khng kh va thu c17,6 gam CO2, 12,6 gam H2O v 69,44 lt N2 (ktc). Gi thit khng kh ch gm N2 v O2trong oxi chim 20% th tch khng kh. X c cng thc l:

A. C2H5NH2. B. C3H7NH2. C. CH3NH2. D. C4H9NH2.Cu 87: Trong mt bnh kn cha hi este no n chc h A v mt lng O2 gp i lng O2 cnthit t chy ht A nhit 140oC v p sut 0,8 atm. t chy hon ton A ri a v nhit ban u, p sut trong bnh lc ny l 0,95 atm. A c cng thc phn t l:

A. C2H4O2. B. C3H6O2. C. C4H8O2. D. C5H10O2.Cu 88: t chy hon ton 0,12 mol cht hu c X mch h cn dng 10,08 lt kh O2 (ktc). Dnton b sn phm chy (gm CO2, H2O v N2) qua bnh ng dung dch Ba(OH)2 d, thy khilng bnh tng 23,4 gam v c 70,92 gam kt ta. Kh thot ra khi bnh c th tch 1,344 lt(ktc). Cng thc phn t ca X l:

A. C2H5O2N. B. C3H5O2N. C. C3H7O2N. D. C2H7O2N.Cu 89: t chy hon ton 0,1 mol cht X cn 6,16 lt kh O2 (ktc), thu c 13,44 lt (ktc) hnhp CO2, N2 v hi nc. Sau khi ngng t ht hi nc, cn li 5,6 lt kh (ktc) c t khi so vihiro l 20,4. Cng thc phn t ca X l:

A. C2H7O2N. B. C3H7O2N. C. C3H9O2N. D. C4H9N.Cu 90: t chy hon ton 0,1 mol mt ancol mch h ba ln cha mt lin kt ba trong gchirocacbon thu c 0,6 mol CO2. Cng thc phn t ca ancol l:

A. C6H14O3. B. C6H12O3. C. C6H10O3. D. C6H8O3.Cu 91: t chy hon ton 1,18 gam cht Y (CxHyN) bng mt lng khng kh va . Dn ton

b hn hp kh sau phn ng vo bnh ng dung dch Ca(OH)2 d, thu c 6 gam kt ta v c9,632 lt kh (ktc) duy nht thot ra khi bnh. Bit khng kh cha 20% oxi v 80% nit v thtch. Cng thc phn t ca Y l:

A. C2H7N. B. C3H9N. C. C4H11N. D. C4H9N.Cu 92: Phn tch 1,47 gam cht hu c Y (C, H, O) bng CuO th thu c 2,156 gam CO 2 vlng CuO gim 1,568 gam. CTGN ca Y l:

A. CH3O. B. CH2O. C. C2H3O. D. C2H3O2.Cu 93: t chy hon ton mt hp cht hu c n chc X thu c sn phm chy ch gmCO2 v H2O vi t l khi lng tng ng l 44 : 27. Cng thc phn t ca X l:

A. C2H6. B. C2H6O. C. C2H6O2. D. C2H4O.Cu 94: Mt hp cht hu c Y khi t chy thu c CO2 v H2O c s mol bng nhau v lngoxi cn dng bng 4 ln s mol ca Y. Cng thc phn t ca Y l:

A. C2H6O. B. C4H8O. C. C3H6O. D. C3H6O2.Cu 95: t chy hon ton 0,2 mol mt axit cacboxylic no 2 ln thu c 1,2 mol CO2. Cng thc

phn t ca axit l: A. C6H14O4. B. C6H12O4. C. C6H10O4. D. C6H8O4.Cu 96: t chy hon ton 5,8 gam mt hp cht hu c n chc X cn 8,96 lt kh O2 (ktc),thu c CO2 v H2O c s mol bng nhau. CTGN ca X l:

A. C2H4O. B. C3H6O. C. C4H8O. D. C5H10O.Cu 97: t chy hon ton 0,2 mol hirocacbon X. Hp th ton b sn phm chy vo nc vitrong c 20 gam kt ta. Lc b kt ta ri un nng phn nc lc li c 10 gam kt ta na.Vy X khng th l:

A. C2H6. B. C2H4. C. CH4. D. C2H2.Cu 98: Hn hp X gm mt s hirocacbon l ng ng k tip. Tng khi lng phn t cacc hirocacbon trong A l 252, trong khi lng phn t ca hirocacbon nng nht bng2 ln

khi lng phn t ca hirocacbon nh nht. Cng thc phn t ca hirocacbon nh nht v slng hirocacbon trong X l:

A. C3H6 v 4. B. C2H4 v 5. C. C3H8 v 4. D. C2H6 v 5.



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Cu 99: t chy hon ton 5,80 gam cht X thu c 2,65 gam Na 2CO3 ; 2,26 gam H2O v 12,10gam CO2. Cng thc phn t ca X l:

A. C6H5O2Na. B. C6H5ONa. C. C7H7O2Na. D. C7H7ONa.Cu 100: t chy hon ton 1,88 gam hp cht hu c Z (cha C, H, O) cn 1,904 lt kh O 2(ktc), thu c CO2 v H2O vi t l mol tng ng l 4 : 3. Cng thc phn t ca Z l:

A. C4H6O2. B. C8H12O4. C. C4H6O3. D. C8H12O5.

CHUYN 2 : HIROCACBON NO



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Cu 1: Hp cht hu c X c tn gi l: 2-clo-3-metylpentan. Cng thc cu to ca X l:A. CH3CH2CH(Cl)CH(CH3)2. B. CH3CH(Cl)CH(CH3)CH2CH3.C. CH3CH2CH(CH3)CH2CH2Cl. D. CH3CH(Cl)CH3CH(CH3)CH3.

Cu 2: C bao nhiu ng phn cu to c cng thc phn t C5H12 ?

A. 3 ng phn. B. 4 ng phn. C. 5 ng phn. D. 6 ng phnCu 3: C bao nhiu ng phn cu to c cng thc phn t C6H14 ?A. 3 ng phn. B. 4 ng phn. C. 5 ng phn. D. 6 ng phn

Cu 4: C bao nhiu ng phn cu to c cng thc phn t C4H9Cl ?A. 3 ng phn. B. 4 ng phn. C. 5 ng phn. D. 6 ng phn.

Cu 5: C bao nhiu ng phn cu to c cng thc phn t C5H11Cl ?A. 6 ng phn. B. 7 ng phn. C. 5 ng phn. D. 8 ng phn.

Cu 6: Phn trm khi lng cacbon trong phn t ankan Y bng 83,33%. Cng thc phn t caY l:

A. C2H6. B. C3H8. C. C4H10. D. C5H12.Cu 7: Cng thc n gin nht ca hirocacbon M l CnH2n+1. M thuc dy ng ng no ?

A. ankan. B. khng d kin xc nh.C. ankan hoc xicloankan. D. xicloankan.

Cu 8: a. 2,2,3,3-tetrametylbutan c bao nhiu nguyn t C v H trong phn t ?A. 8C,16H. B. 8C,14H. C. 6C, 12H. D. 8C,18H.

b. Cho ankan c CTCT l: (CH3)2CHCH2C(CH3)3. Tn gi ca ankan l:A. 2,2,4-trimetylpentan. B. 2,4-trimetylpetan.C. 2,4,4-trimetylpentan. D. 2-imetyl-4-metylpentan.

Cu 9: Phn ng c trng ca hirocacbon no lA. Phn ng tch. B. Phn ng th. C. Phn ng cng. D. C A, B v C.

Cu 10: Cho iso-pentan tc dng vi Cl2 theo t l s mol 1 : 1, s sn phm monoclo ti a thuc l:

A. 2. B. 3. C. 5. D. 4.Cu 11: Iso-hexan tc dng vi clo (c chiu sng) c th to ti a bao nhiu dn xut monoclo ?

A. 3. B. 4. C. 5. D. 6Cu 12: Khi cho 2-metylbutan tc dng vi Cl2 theo t l mol 1:1 th to ra sn phm chnh l:

A. 1-clo-2-metylbutan. B. 2-clo-2-metylbutan.C. 2-clo-3-metylbutan. D. 1-clo-3-metylbutan.

Cu 13: Khi clo ha C5H12 vi t l mol 1:1 thu c 3 sn phm th monoclo. Danh php IUPACca ankan l:

A. 2,2-imetylpropan. B. 2-metylbutan. C. pentan. D. 2-imetylpropan.Cu 14: Khi clo ha metan thu c mt sn phm th cha 89,12% clo v khi lng. Cng thc

ca sn phm l:A. CH3Cl. B. CH2Cl2. C. CHCl3. D. CCl4.Cu 15: Cho 4 cht: metan, etan, propan v n-butan. S lng cht to c mt sn phm thmonoclo duy nht l:

A. 1. B. 2. C. 3. D. 4.Cu 16: khi clo ha mt ankan c cng thc phn t C6H14, ngi ta ch thu c 2 sn phm thmonoclo. Danh php IUPAC ca ankan l:

A. 2,2-imetylbutan. B. 2-metylpentan. C. n-hexan. D. 2,3-imetylbutan.Cu 17: Khi clo ha hn hp 2 ankan, ngi ta ch thu c 3 sn phm th monoclo. Tn gi ca2 ankan l:

A. etan v propan. B. propan v iso-butan.

C. iso-butan v n-pentan. D. neo-pentan v etan.

Cu 18: Khi brom ha mt ankan ch thu c mt dn xut monobrom duy nht c t khi hi ivi hiro l 75,5. Tn ca ankan l:



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A. 3,3-imetylhecxan. C. isopentan.B. 2,2-imetylpropan. D. 2,2,3-trimetylpentan

Cu 19: Khi cho ankan X (trong phn t c phn trm khi lng cacbon bng 83,72%) tc dngvi clo theo t l s mol 1:1 (trong iu kin chiu sng) ch thu c 2 dn xut monoclo ng

phn ca nhau. Tn ca X l:A. 3-metylpentan. B. 2,3-imetylbutan. C. 2-metylpropan. D. butan.

Cu 20: Hirocacbon mch h X trong phn t ch cha lin kt v c hai nguyn t cacbon bcba trong mt phn t. t chy hon ton 1 th tch X sinh ra 6 th tch CO 2 ( cng iu kin nhit, p sut). Khi cho X tc dng vi Cl2 (theo t l s mol 1 : 1), s dn xut monoclo ti a sinh ral:

A. 3. B. 4. C. 2. D. 5.Cu 21: Khi tin hnh phn ng th gia ankan X vi kh clo c chiu sng ngi ta thu c hnhp Y ch cha hai cht sn phm. T khi hi ca Y so vi hiro l 35,75. Tn ca X l

A. 2,2-imetylpropan. B. 2-metylbutan. C. pentan. D. etan.Cu 22: Ankan no sau y ch cho 1 sn phm th duy nht khi tc dng vi Cl 2 (as) theo t l mol(1 : 1): CH3CH2CH3 (a), CH4 (b), CH3C(CH3)2CH3 (c), CH3CH3 (d), CH3CH(CH3)CH3(e)

A. (a), (e), (d). B. (b), (c), (d).C. (c), (d), (e). D. (a), (b), (c), (e), (d)

Cu 23: Khi th monoclo mt ankan A ngi ta lun thu c mt sn phm duy nht. Vy A l:A. metan. B. etanC. neo-pentan D. C A, B, C u ng.

Cu 24: Sn phm ca phn ng th clo (1:1, nh sng) vo 2,2- imetyl propan l :(1) CH3C(CH3)2CH2Cl; (2) CH3C(CH2Cl)2CH3 ; (3) CH3ClC(CH3)3A. (1); (2). B. (2); (3). C. (2). D. (1)

Cu 25: C bao nhiu ankan l cht kh iu kin thng khi phn ng vi clo (c nh sng, t lmol 1:1) to ra 2 dn xut monoclo ?

A. 4. B. 2. C. 5. D. 3.

Cu 26: Ankan Y phn ng vi brom to ra 2 dn xut monobrom c t khi hi so vi H2 bng61,5. Tn ca Y l:A. butan. B. propan. C. Iso-butan. D. 2-metylbutan.

Cu 27: t chy mt hn hp gm nhiu hirocacbon trong cng mt dy ng ng nu ta thuc s mol H2O > s mol CO2 th CTPT chung ca dy l:

A. CnHn, n 2. B. CnH2n+2, n 1 (cc gi tr n u nguyn).C. CnH2n-2, n 2. D. Tt c u sai.

Cu 28: t chy cc hirocacbon ca dy ng ng no di y th t l mol H2O : mol CO2gim khi s cacbon tng.

A. ankan. B. anken. C. ankin. D. arenCu 29: Khi t chy ankan thu c H2O v CO2 vi t l tng ng bin i nh sau:

A. tng t 2 n + . B. gim t 2 n 1.C. tng t 1 n 2. D. gim t 1 n 0.Cu 30: Khng th iu ch CH4 bng phn ng no ?

A. Nung mui natri malonat vi vi ti xt.B. Canxicacbua tc dng vi nc.C. Nung natri axetat vi vi ti xt.D. in phn dung dch natri axetat.

Cu 31: Trong phng th nghim c th iu ch metan bng cch no sau y ?A.Nhit phn natri axetat vi vi ti xt. B. Crackinh butanC. T phn ng ca nhm cacbua vi nc. D. A, C.

Cu 32: Thnh phn chnh ca kh thin nhin l:

A. metan. B. etan. C. propan. D. n-butan.Cu 33: Xicloankan (ch c mt vng) A c t khi so vi nit bng 3. A tc dng vi clo c chiusng ch cho mt dn xut monoclo duy nht, xc nh cng thc cu to ca A ?



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A.

CH3

. B. . C.

CH3

CH3 . D.

CH3

CH3

CH3 .

Cu 34: Hai xicloankan M v N u c t khi hi so vi metan bng 5,25. Khi tham gia phn ngth clo (as, t l mol 1:1) M cho 4 sn phm th cn N cho 1 sn phm th. Tn gi ca ccxicloankan N v M l:

A. metyl xiclopentan v imetyl xiclobutan. B. Xiclohexan v metyl xiclopentan.C. Xiclohexan v n-propyl xiclopropan. D. C A, B, C u ng.

Cu 35: (A) l cht no trong phn ng sau y ?A + Br2 Br-CH2-CH2-CH2-Br

A. propan. B. 1-brompropan. C. xiclopopan. D. A v B u ng.Cu 36: Dn hn hp kh A gm propan v xiclopropan i vo dung dch brom s quan st chin tng no sau y :

A. Mu ca dung dch nht dn, khng c kh thot ra.B. Mu ca dung dch nht dn, v c kh thot ra.C. Mu ca dung dch mt hn, khng cn kh thot ra.D. Mu ca dung dch khng i.

Cu 37: Cho hn hp 2 ankan A v B th kh, c t l s mol trong hn hp: nA : nB = 1 : 4. Khilng phn t trung bnh l 52,4. Cng thc phn t ca hai ankan A v B ln lt l:

A. C2H6 v C4H10. B. C5H12 v C6H14. C. C2H6 v C3H8. D. C4H10 v C3H8Cu 38: Khi tin hnh craking 22,4 lt kh C4H10 (ktc) thu c hn hp A gm CH4, C2H6, C2H4,C3H6, C4H8, H2 v C4H10 d. t chy hon ton A thu c x gam CO2 v y gam H2O. Gi tr ca xv y tng ng l:

A. 176 v 180. B. 44 v 18. C. 44 v 72. D. 176 v 90.Cu 39: Craking n-butan thu c 35 mol hn hp A gm H2, CH4, C2H4, C2H6, C3H6, C4H8 v mt

phn butan cha b craking. Gi s ch c cc phn ng to ra cc sn phm trn. Cho A qua bnhnc brom d thy cn li 20 mol kh. Nu t chy hon ton A th thu c x mol CO2.

a.Hiu sut phn ng to hn hp A l:A. 57,14%. B. 75,00%. C. 42,86%. D. 25,00%.b. Gi tr ca x l:

A. 140. B. 70. C. 80. D. 40.Cu 40: Khi crackinh hon ton mt th tch ankan X thu c ba th tch hn hp Y (cc th tchkh o cng iu kin nhit v p sut); t khi ca Y so vi H2 bng 12. Cng thc phn tca X l:

A. C6H14. B. C3H8. C. C4H10. D. C5H12.Cu 41: Khi crackinh hon ton mt ankan X thu c hn hp Y (cc th tch kh o cng iukin nhit v p sut); t khi ca Y so vi H2 bng 29. Cng thc phn t ca X l:

A. C6H14. B. C3H8. C. C4H10. D. C5H12

Cu 42: Craking 8,8 gam propan thu c hn hp A gm H2, CH4, C2H4, C3H6 v mt phnpropan cha b craking. Bit hiu sut phn ng l 90%. Khi lng phn t trung bnh ca A l:A. 39,6. B. 23,16. C. 2,315. D. 3,96.

Cu 43: Craking 40 lt n-butan thu c 56 lt hn hp A gm H2, CH4, C2H4, C2H6, C3H6, C4H8 vmt phn n-butan cha b craking (cc th tch kh o cng iu kin nhit v p sut). Gi sch c cc phn ng to ra cc sn phm trn. Hiu sut phn ng to hn hp A l:

A. 40%. B. 20%. C. 80%. D. 20%.Cu 44: Craking m gam n-butan thu c hp A gm H2, CH4, C2H4, C2H6, C3H6, C4H8 v mt

phn butan cha b craking. t chy hon ton A thu c 9 gam H 2O v 17,6 gam CO2. Gi trca m l

A. 5,8. B. 11,6. C. 2,6. D. 23,2.

Cu 45: t chy hon ton mt th tch kh thin nhin gm metan, etan, propan bng oxi khngkh (trong khng kh, oxi chim 20% th tch), thu c 7,84 lt kh CO2 ( ktc) v 9,9 gam nc.Th tch khng kh ( ktc) nh nht cn dng t chy hon ton lng kh thin nhin trn l

A. 70,0 lt. B. 78,4 lt. C. 84,0 lt. D. 56,0 lt.Dy v hc Ha hc, http://ngocbinh.webdayhoc.net


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Cu 46: t chy mt hn hp hirocacbon ta thu c 2,24 lt CO2 (ktc) v 2,7 gam H2O th thtch O2 tham gia phn ng chy (ktc) l:

A. 5,6 lt. B. 2,8 lt. C. 4,48 lt. D. 3,92 lt.Cu 47: Hn hp kh A gm etan v propan. t chy hn hp A thu c kh CO2 v hi H2Otheo t l th tch 11:15. Thnh phn % theo khi lng ca hn hp l:

A. 18,52% ; 81,48%. B. 45% ; 55%.C. 28,13% ; 71,87%. D. 25% ; 75%.

Cu 48: t chy hon ton mt hirocacbon X thu c 0,11 mol CO2 v 0,132 mol H2O. Khi Xtc dng vi kh clo thu c 4 sn phm monoclo. Tn gi ca X l:

A. 2-metylbutan. B. etan.C. 2,2-imetylpropan. D. 2-metylpropan.

Cu 49: Mt hn hp 2 ankan lin tip trong dy ng ng c t khi hi vi H2 l 24,8.a. Cng thc phn t ca 2 ankan l:

A. C2H6 v C3H8. B. C4H10 v C5H12. C. C3H8 v C4H10. D. Kt qu khcb. Thnh phn phn trm v th tch ca 2 ankan l:

A. 30% v 70%. B. 35% v 65%. C. 60% v 40%. D. 50% v 50%Cu 50: iu kin tiu chun c 1 hn hp kh gm 2 hirocacbon no A v B, t khi hi ca hnhp i vi H2 l 12.

a. Khi lng CO2 v hi H2O sinh ra khi t chy 15,68 lt hn hp ( ktc).A. 24,2 gam v 16,2 gam. B. 48,4 gam v 32,4 gam.C. 40 gam v 30 gam. D. Kt qu khc.

b. Cng thc phn t ca A v B l:A. CH4 v C2H6. B. CH4 v C3H8. C. CH4 v C4H10. D. C A, B v C.

Cu 51: t 10 cm3 mt hirocacbon bng 80 cm3 oxi (ly d). Sn phm thu c sau khi cho hinc ngng t cn 65 cm3 trong c 25 cm3 oxi d. Cc th tch trong cng iu kin. CTPTca hirocacbon l:

A. C4H10. B. C4H6. C. C5H10. D. C3H8

Cu 52: t chy hon ton hn hp X gm hai ankan k tip trong dy ng ng c 24,2 gamCO2 v 12,6 gam H2O. Cng thc phn t 2 ankan l:A. CH4 v C2H6. B. C2H6 v C3H8. C. C3H8 v C4H10. D. C4H10 v C5H12

Cu 53: X l hn hp 2 ankan. t chy ht 10,2 gam X cn 25,76 lt O2 (ktc). Hp th ton b sn phm chy vo nc vi trong d c m gam kt ta.

a. Gi tr m l:A. 30,8 gam. B. 70 gam. C. 55 gam. D. 15 gam

b.Cng thc phn t ca A v B l:A. CH4 v C4H10. B. C2H6 v C4H10. C. C3H8 v C4H10. D. C A, B v C.

Cu 54: Hirocacbon X chy cho th tch hi nc gp 1,2 ln th tch CO2 (o cng k). Khi tcdng vi clo to mt dn xut monoclo duy nht. X c tn l:

A. isobutan. B. propan. C. etan. D. 2,2- imetylpropan.Cu 55: t chy hon ton hn hp X gm 2 hirocacbon l ng ng lin tip, sau phn ng thuc VCO2:VH2O =1:1,6 (o cng k). X gm:

A. CH4 v C2H6. B. C2H4 v C3H6. C. C2H2 v C3H6. D. C3H8 v C4H10.Cu 56: t chy hon ton 0,2 mol hirocacbon X. Hp th ton b sn phm chy vo nc vitrong c 20 gam kt ta. Lc b kt ta ri un nng phn nc lc li c 10 gam kt ta na.Vy X khng th l:

A. C2H6. B. C2H4. C. CH4. D. C2H2Cu 57: n gin ta xem xng l hn hp cc ng phn ca hexan v khng kh gm 80% N2v 20% O2 (theo th tch). T l th tch xng (hi) v khng kh cn ly l bao nhiu xng cchy hon ton trong cc ng c t trong ?

A. 1: 9,5. B. 1: 47,5. C. 1:48. D. 1:50Cu 58: t chy hon ton hn hp hai hirocacbon ng ng c khi lng phn t hn kmnhau 28 vC, ta thu c 4,48 l CO2 (ktc) v 5,4 gam H2O. CTPT ca 2 hirocacbon trn l:



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A. C2H4 v C4H8. B. C2H2 v C4H6. C. C3H4 v C5H8. D. CH4 v C3H8.Cu 59: Cho 224,00 lt metan (ktc) qua h quang c V lt hn hp A (ktc) cha 12% C2H2 ;10% CH4 ; 78%H2 (v th tch). Gi s ch xy ra 2 phn ng:

2CH4C2H2 + 3H2 (1)CH4C + 2H2 (2)

Gi tr ca V l:A. 407,27. B. 448,00. C. 520,18. D. 472,64.

Cu 60: t chy hon ton 2,24 lt hn hp A (ktc) gm CH4, C2H6 v C3H8 thu c V lt khCO2 (ktc) v 7,2 gam H2O. Gi tr ca V l:

A. 5,60. B. 6,72. C. 4,48. D. 2,24.Cu 61: t chy hon ton 6,72 lt hn hp A (ktc) gm CH4, C2H6, C3H8, C2H4 v C3H6, thuc 11,2 lt kh CO2 (ktc) v 12,6 gam H2O. Tng th tch ca C2H4 v C3H6 (ktc) trong hn hpA l:

A. 5,60. B. 3,36. C. 4,48. D. 2,24.Cu 62: t chy hon ton hn hp A gm CH4, C2H2, C3H4, C4H6 thu c x mol CO2 v 18xgam H2O. Phn trm th tch ca CH4 trong A l:

A. 30%. B. 40%. C. 50%. D. 60%.Cu 63: t chy hon ton hn hp kh X gm 2 hirocacbon A v B l ng ng k tip thuc 96,8 gam CO2 v 57,6 gam H2O. Cng thc phn t ca A v B l:

A. CH4 v C2H6. B. C2H6 v C3H8.C. C3H8 v C4H10. D. C4H10 v C5H12

Cu 64: Hn hp kh X gm 2 hirocacbon A v B l ng ng k tip. t chy X vi 64 gamO2 (d) ri dn sn phm thu c qua bnh ng Ca(OH) 2 d thu c 100 gam kt ta. Kh rakhi bnh c th tch 11,2 lt 0oC v 0,4 atm. Cng thc phn t ca A v B l:

A. CH4 v C2H6. B. C2H6 v C3H8.C. C3H8 v C4H10. D. C4H10 v C5H12

Cu 65: Khi t chy hon ton V lt hn hp kh gm CH 4, C2H6, C3H8 (ktc) thu c 44 gam

CO2 v 28,8 gam H2O. Gi tr ca V l:A. 8,96. B. 11,20. C. 13,44. D. 15,68.Cu 66: Khi t chy hon ton 7,84 lt hn hp kh gm CH 4, C2H6, C3H8 (ktc) thu c 16,8 ltkh CO2 (ktc) v x gam H2O. Gi tr ca x l:

A. 6,3. B. 13,5. C. 18,0. D. 19,8.Cu 67: Khi t chy hon ton hn hp 2 ankan l ng ng k tip thu c 7,84 lt kh CO 2(ktc) v 9,0 gam H2O. Cng thc phn t ca 2 ankan l:

A. CH4 v C2H6. B. C2H6 v C3H8. C. C3H8 v C4H10. D. C4H10 v C5H12.Cu 68: Np mt hn hp kh c 20% th tch ankan A v 80% th tch O2 (d) vo kh nhin k.Sau khi cho n ri cho hi nc ngng t nhit ban u th p sut trong kh nhin k gim i2 ln. Thit lp cng thc phn t ca ankan A.

A. CH4. B. C2H6. C. C3H8 . D.C4H10.Cu 69: t chy mt s mol nh nhau cua 3 hirocacbon K, L, M ta thu c lng CO 2 nhnhau v t l s mol nc v CO2 i vi s mol ca K, L, M tng ng l 0,5 : 1 : 1,5. Xc nhCT K, L, M (vit theo th t tng ng):

A. C2H4 , C2H6 , C3H4. B. C3H8 , C3H4 , C2H4.C. C3H4 , C3H6 , C3H8. D. C2H2 , C2H4 , C2H6

Cu 70:Nung m gam hn hp X gm 3 mui natri ca 3 axit no n chc vi NaOH d thu ccht rn D v hn hp Y gm 3 ankan. T khi ca Y so vi H2 l 11,5. Cho D tc dng vi H2SO4d thu c 17,92 lt CO2 (ktc). a. Gi tr ca m l:

A. 42,0. B. 84,8. C. 42,4. D. 71,2.b. Tn gi ca 1 trong 3 ankan thu c l:



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A. metan. B. etan. C. propan. D. butan.

CHUYN 3 : HIROCACBON KHNG NO

BI TP V ANKENCu 1: Anken X c cng thc cu to: CH3CH2C(CH3)=CHCH3.Tn ca X l

A. isohexan. B. 3-metylpent-3-en. C. 3-metylpent-2-en. D. 2-etylbut-2-en.Dy v hc Ha hc, http://ngocbinh.webdayhoc.net


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Cu 2: S ng phn ca C4H8 lA. 7. B. 4. C. 6. D. 5.

Cu 3: Hp cht C5H10 mch h c bao nhiu ng phn cu to ?A. 4. B. 5. C. 6. D. 10.

Cu 4: Hp cht C5H10 c bao nhiu ng phn anken ?A. 4. B. 5. C. 6. D. 7.

Cu 5: Hp cht C5H10 c bao nhiu ng phn cu to ?A. 4. B. 5. C. 6. D. 10.

Cu 6: Ba hirocacbon X, Y, Z l ng ng k tip, khi lng phn t ca Z bng 2 ln khilng phn t ca X. Cc cht X, Y, Z thuc dy ng ng

A. ankin. B. ankan. C. ankaien. D. anken.Cu 7: Anken X c c im: Trong phn t c 8 lin kt xch ma. CTPT ca X l

A. C2H4. B. C4H8. C. C3H6. D. C5H10.Cu 8: Vitamin A cng thc phn t C20H30O, c cha 1 vng 6 cnh v khng c cha lin kt ba.S lin kt i trong phn t vitamin A l

A. 7. B. 6. C. 5. D. 4.Cu 9: Licopen, cng thc phn t C40H56 l cht mu trong qu c chua, ch cha lin kt iv lin kt n trong phn t. Hiro ha hon ton licopen c hirocacbon C40H82. Vy licopenc

A. 1 vng; 12 ni i. B. 1 vng; 5 ni i.C. 4 vng; 5 ni i. D. mch h; 13 ni i.

Cu 10: Cho cc cht sau: 2-metylbut-1-en (1); 3,3-imetylbut-1-en (2); 3-metylpent-1-en (3);3-metylpent-2-en (4); Nhng cht no l ng phn ca nhau ?

A. (3) v (4). B. (1), (2) v (3). C. (1) v (2). D. (2), (3) v (4).Cu 11: Hp cht no sau y c ng phn hnh hc ?

A. 2-metylbut-2-en. B. 2-clo-but-1-en.C. 2,3- iclobut-2-en. D. 2,3- imetylpent-2-en.

Cu 12: Nhng hp cht no sau y c ng phn hnh hc (cis-trans) ?CH3CH=CH2 (I); CH3CH=CHCl (II); CH3CH=C(CH3)2 (III); C2H5C(CH3)=C(CH3)C2H5 (IV);C2H5C(CH3)=CClCH3 (V).

A. (I), (IV), (V). B. (II), (IV), (V). C. (III), (IV). D. (II), III, (IV), (V).Cu 13:Cho cc cht sau: CH2=CHCH2CH2CH=CH2; CH2=CHCH=CHCH2CH3;CH3C(CH3)=CHCH2; CH2=CHCH2CH=CH2; CH3CH2CH=CHCH2CH3; CH3C(CH3)=CHCH2CH3;CH3CH2C(CH3)=C(C2H5)CH(CH3)2; CH3CH=CHCH3.S cht c ng phn hnh hc l:

A. 4. B. 1. C. 2. D. 3.Cu 14: p dng quy tc Maccopnhicop vo trng hp no sau y ?

A. Phn ng cng ca Br2 vi anken i xng.

C. Phn ng cng ca HX vo anken i xng.B. Phn ng trng hp ca anken.D. Phn ng cng ca HX vo anken bt i xng.

Cu 15: Khi cho but-1-en tc dng vi dung dch HBr, theo qui tc Maccopnhicop sn phm nosau y l sn phm chnh ?

A. CH3-CH2-CHBr-CH2Br. C. CH3-CH2-CHBr-CH3.B. CH2Br-CH2-CH2-CH2Br . D. CH3-CH2-CH2-CH2Br.

Cu 16: Anken C4H8 c bao nhiu ng phn khi tc dng vi dung dch HCl ch cho mt snphm hu c duy nht ?

A. 2. B. 1. C. 3. D. 4.Cu 17: Cho cc cht: xiclobutan, 2-metylpropen, but-1-en, cis-but-2-en, 2-metylbut-2-en. Dy

gm cc cht sau khi phn ng vi H2 (d, xc tc Ni, to), cho cng mt sn phm l:A. xiclobutan, cis-but-2-en v but-1-en. B.but-1-en, 2-metylpropen v cis-but-2-en.C. xiclobutan, 2-metylbut-2-en v but-1-en. D. 2-metylpropen, cis -but-2-en v xiclobutan.



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Cu 18: Cho hn hp tt c cc ng phn mch h ca C4H8 tc dng vi H2O (H+,to) thu c tia bao nhiu sn phm cng ?

A. 2. B. 4. C. 6. D. 5Cu 19: C bao nhiu anken th kh (kt) m khi cho mi anken tc dng vi dung dch HClch cho mt sn phm hu c duy nht ?

A. 2. B. 1. C. 3. D. 4.Cu 20: Hirat ha 2 anken ch to thnh 2 ancol (ru). Hai anken l

A. 2-metylpropen v but-1-en (hoc buten-1). B. propen v but-2-en (hoc buten-2).C. eten v but-2-en (hoc buten-2). D. eten v but-1-en (hoc buten-1).

Cu 21: Ankenthch hp iu ch ancolsau y (CH3 CH2)3C-OH lA. 3-etylpent-2-en. B. 3-etylpent-3-en.C. 3-etylpent-1-en. D. 3,3- imetylpent-1-en.

Cu 22: Hirat ha hn hp X gm 2 anken thu c ch thu c 2 ancol. X gmA. CH2=CH2 v CH2=CHCH3. B. CH2=CH2 v CH3CH=CHCH3.C. B hoc D. D. CH3CH=CHCH3 v CH2=CHCH2CH3.

Cu 23: S cp ng phn cu to anken th kh (kt) tho mn iu kin: Khi hirat ho tothnh hn hp gm ba ancol l

A. 6. B. 3. C. 5. D. 4.Cu 24: S cp ng phn anken th kh (kt) tho mn iu kin: Khi hirat ho to thnh hnhp gm ba ancol l:

A. 6. B. 7. C. 5. D. 8.Cu 25: Hp cht X c CTPT C3H6, X tc dng vi dung dch HBr thu c mt sn phm hu cduy nht. Vy X l:

A. propen. B. propan. C. ispropen. D. xicloropan.Cu 26: Hai cht X, Y c CTPT C3H6 vC4H8 v u tc dng c vi nc brom. X, Y l

A. Hai anken hoc xicloankan vng 3 cnh. C. Hai anken hoc xicloankan vng 4 cnh.B. Hai anken hoc hai ankan. D. Hai anken ng ng ca nhau.

Cu 27: C hai ng nghim, mi ng cha 1 ml dung dch brom trong nc c mu vng nht.Thm vo ng th nht 1 ml hexan v ng th hai 1 ml hex-1-en. Lc u c hai ng nghim, sau yn hai ng nghim trong vi pht. Hin tng quan st c l:

A. C s tch lp cc cht lng c hai ng nghim.B. Mu vng nht vn khng i ng nghim th nhtC. ng nghim th hai c hai lp cht lng u khng mu.D. A, B, C u ng.

Cu 28: Trng hp eten, sn phm thu c c cu to l:A. (-CH2=CH2-)n . B. (-CH2-CH2-)n .C. (-CH=CH-)n. D. (-CH3-CH3-)n .

Cu 29: Oxi ho etilen bng dung dch KMnO4 thu c sn phm l:A. MnO2, C2H4(OH)2, KOH. C. K2CO3, H2O, MnO2.

B. C2H5OH, MnO2, KOH. D. C2H4(OH)2, K2CO3, MnO2.Cu 30: X l hn hp gm 2 hirocacbon. t chy X c nCO 2 = nH2O. X c th gmA. 1xicloankan + anken. B. 1ankan + 1ankin.C. 2 anken. D. A hoc B hoc C.

Cu 31: iu ch etilen trong phng th nghim t C2H5OH, (H2SO4 c, 170oC) thng ln ccoxit nh SO2, CO2. Cht dng lm sch etilen l:

A. dd brom d. B. dd NaOH d.C. dd Na2CO3 d. D. dd KMnO4 long d.

Cu 32: Sn phm chnh ca s ehirat ha 2-metylbutan-2-ol l cht no ?A. 3-metylbut-1-en. B. 2-metylbut-1en.C. 3-metylbut-2-en. D. 2-metylbut-2-en.

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Cu 33: Khi tch nc t ru (ancol) 3-metylbutanol-1 (hay 3-metylbutan-1-ol), sn phm chnhthu c l:

A. 2-metylbuten-3 (hay 2-metylbut-3-en). B. 3-metylbuten-2 (hay 3-metylbut-2-en).C. 3-metylbuten-1 (hay 3-metylbut-1-en). D. 2-metylbuten-2 (hay 2-metylbut-2-en).

Cu 34: Hp cht 2-metylbut-2-en l sn phm chnh ca phn ng tch t cht no ?A. 2-brom-2-metylbutan. B. 2-metylbutan -2- ol.C. 3-metylbutan-2- ol. D. Tt c u ng.

Cu 35: Khi lng etilen thu c khi un nng 230 gam ru etylic vi H 2SO4 m c, hiusut phn ng t 40% l:

A. 56 gam. B. 84 gam. C. 196 gam. D. 350 gam.Cu 36: Cho 3,36 lt hn hp etan v etilen (ktc) i chm qua qua dung dch brom d. Sau phnng khi lng bnh brom tng thm 2,8 gam. S mol etan v etilen trong hn hp ln lt l:

A. 0,05 v 0,1. B. 0,1 v 0,05. C. 0,12 v 0,03. D. 0,03 v 0,12.Cu 37: 2,8 gam anken A lm mt mu va dung dch cha 8 gam Br2. Hirat ha A ch thuc mt ancol duy nht. A c tn l:

A. etilen. B. but - 2-en.C. hex- 2-en. D. 2,3-dimetylbut-2-en.

Cu 38: 0,05 mol hirocacbon X lm mt mu va dung dch cha 8 gam brom cho ra sn phmc hm lng brom t 69,56%. Cng thc phn t ca X l:

A. C3H6. B. C4H8. C. C5H10. D. C5H8.Cu 39: Dn t t 8,4 gam hn hp X gm but-1-en v but-2-en li chm qua bnh ng dung dchBr2, khi kt thc phn ng thy c m gam brom phn ng. m c gi tr l:

A. 12 gam. B. 24 gam. C. 36 gam. D. 48 gam.Cu 40: Dn 3,36 lt (ktc) hn hp X gm 2 anken l ng ng k tip vo bnh nc brom d,thy khi lng bnh tng thm 7,7 gam. Thnh phn phn % v th tch ca hai anken l:

A. 25% v 75%. B. 33,33% v 66,67%.C. 40% v 60%. D. 35% v 65%.

Cu 41: Hn hp X gm 2 anken l ng ng lin tip c th tch 4,48 lt ( ktc). Nu cho hnhp X i qua bnh ng nc brom d, khi lng bnh tng ln 9,8 gam. % th tch ca mt trong2 anken l:

A. 50%. B. 40%. C. 70%. D. 80%.Cu 42: Dn 3,36 lt (ktc) hn hp X gm 2 anken l ng ng k tip vo bnh nc brom d,thy khi lng bnh tng thm 7,7 gam. CTPT ca 2 anken l:

A. C2H4 v C3H6. B. C3H6 v C4H8. C. C4H8 v C5H10. D. C5H10 v C6H12.Cu 43: Mt hn hp X c th tch 11,2 lt (ktc), X gm 2 anken ng ng k tip nhau. Khi choX qua nc Br2 d thy khi lng bnh Br2 tng 15,4 gam. Xc nh CTPT v s mol mi ankentrong hn hp X.

A. 0,2 mol C2H4 v 0,3 mol C3H6. B. 0,2 mol C3H6 v 0,2 mol C4H8.

C. 0,4 mol C2H4 v 0,1 mol C3H6. D. 0,3 mol C2H4 v 0,2 mol C3H6.Cu 44: Mt hn hp X gm ankan A v anken B, A c nhiu hn B mt nguyn t cacbon, A vB u th kh ( ktc). Khi cho 6,72 lt kh X (ktc) i qua nc brom d, khi lng bnh bromtng ln 2,8 gam; th tch kh cn li ch bng 2/3 th tch hn hp X ban u. CTPT ca A, B vkhi lng ca hn hp X l:

A. C4H10, C3H6 ; 5,8 gam. B. C3H8, C2H4 ; 5,8 gam.C. C4H10, C3H6 ; 12,8 gam. D. C3H8, C2H4 ; 11,6 gam.

Cu 45: Mt hn hp X gm ankan A v mt anken B c cng s nguyn t C v u th kh ktc. Cho hn hp X i qua nc Br2 d th th tch kh Y cn li bng na th tch X, cn khilng Y bng 15/29 khi lng X. CTPT A, B v thnh phn % theo th tch ca hn hp X l

A. 40% C2H6 v 60% C2H4. B. 50% C3H8v 50% C3H6C. 50% C4H10 v 50% C4H8. D. 50% C2H6 v 50% C2H4



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Cu 46 : Hn hp X gm metan v 1 olefin. Cho 10,8 lt hn hp X qua dung dch brom d thy c1 cht kh bay ra, t chy hon ton kh ny thu c 5,544 gam CO2. Thnh phn % v th tchmetan v olefin trong hn hp X l:

A. 26,13% v 73,87%. B. 36,5% v 63,5%.C. 20% v 80%. D. 73,9% v 26,1%.

Cu 47: Cho 8960 ml (ktc) anken X qua dung dch brom d. Sau phn ng thy khi lng bnhbrom tng 22,4 gam. Bit X c ng phn hnh hc. CTCT ca X l:

A. CH2=CHCH2CH3. B. CH3CH=CHCH3.C. CH3CH=CHCH2CH3. D. (CH3)2C=CH2.

Cu 48: a.Cho hirocacbon X phn ng vi brom (trong dung dch) theo t l mol 1 : 1, thu ccht hu c Y (cha 74,08% Br v khi lng). Khi X phn ng vi HBr th thu c hai sn phmhu c khc nhau. Tn gi ca X l:

A. but-1-en. B. but-2-en. C. Propilen. D. Xiclopropan.b.Hirocacbon X cng HCl theo t l mol 1:1 to sn phm c hm lng clo l 55,04%. X c

cng thc phn t l:A. C4H8. B. C2H4. C. C5H10. D. C3H6.

Cu 49: Hn hp X gm metan v anken, cho 5,6 lt X qua dung dch brom d thy khi lngbnh brom tng 7,28 gam v c 2,688 lt kh bay ra (ktc). CTPT ca anken l:

A. C4H8. B. C5H10. C. C3H6. D. C2H4Cu 50: Dn 3,36 lt (ktc) hn hp X gm 2 anken l vo bnh nc brom d, thy khi lng

bnh tng thm 7,7 gam. CTPT ca 2 anken l:A. C2H4 v C4H8. B. C3H6 v C4H8. C. C4H8 v C5H10. D. A hoc B.

Cu 51: Cho 10 lt hn hp kh (54,6oC; 0,8064 atm) gm 2 olefin li qua bnh dung dch brom dthy khi lng bnh brom tng 16,8 gam. CTPT ca 2 anken l (Bit s C trong cc anken khngvt qu 5)

A. C2H4 v C5H10. B. C3H6 v C5H10. C. C4H8 v C5H10. D. A hoc B.Cu 52: Mt hirocacbon X cng hp vi axit HCl theo t l mol 1:1 to sn phm c thnh phn

khi lng clo l 45,223%. Cng thc phn t ca X l:A. C3H6. B. C4H8. C. C2H4. D. C5H10.Cu 53: Cho hn hp X gm etilen v H2 c t khi so vi H2 bng 4,25. Dn X qua bt niken nungnng (hiu sut phn ng 75%) thu c hn hp Y. T khi ca Y so vi H 2 (cc th tch o cng iu kin) l:

A. 5,23. B. 3,25. C. 5,35. D. 10,46.Cu 54: Cho H2 v 1 olefin c th tch bng nhau qua Niken un nng ta c hn hp A. Bit tkhi hi ca A i vi H2 l 23,2. Hiu sut phn ng hiro ho l 75%. Cng thc phn tolefin l

A. C2H4. B. C3H6. C. C4H8. D. C5H10.Cu 55: Hn hp kh X gm H2 v mt anken c kh nng cng HBr cho sn phm hu c duy

nht. T khi ca X so vi H2 bng 9,1. un nng X c xc tc Ni, sau khi phn ng xy ra honton, thu c hn hp kh Y khng lm mt mu nc brom; t khi ca Y so vi H 2bng 13.Cng thc cu to ca anken l:

A. CH3CH=CHCH3. B. CH2=CHCH2CH3.C. CH2=C(CH3)2. D. CH2=CH2.

Cu 56: Cho hn hp X gm anken v hiro c t khi so vi heli bng 3,33. Cho X i qua btniken nung nng n khi phn ng xy ra hon ton, thu c hn hp Y c t khi so vi heli l 4.CTPT ca X l:

A. C2H4. B. C3H6. C. C4H8. D. C5H10.Cu 57: Hn hp kh X gm H2 v C2H4 c t khi so vi He l 3,75. Dn X qua Ni nung nng, thuc hn hp kh Y c t khi so vi He l 5. Hiu sut ca phn ng hiro ho l:

A. 20%. B. 25%. C. 50%. D. 40%.Cu 58: t chy hon ton a gam hn hp eten, propen, but-2-en cn dng va b lt oxi (ktc) thu c 2,4 mol CO2 v 2,4 mol nc. Gi tr ca b l:



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A. 92,4 lt. B. 94,2 lt. C. 80,64 lt. D. 24,9 lt.Cu 59: t chy hon ton V lt (ktc) hn hp X gm CH 4, C2H4 thu c 0,15 mol CO2 v 0,2mol H2O. Gi tr ca V l:

A. 2,24. B. 3,36. C. 4,48. D. 1,68.Cu 60: t chy hon ton 0,1 mol hm hp gm CH4, C4H10 v C2H4 thu c 0,14 mol CO2 v0,23mol H2O. S mol ca ankan v anken trong hn hp ln lt l:

A. 0,09 v 0,01. B. 0,01 v 0,09. C. 0,08 v 0,02. D. 0,02 v 0,08.Cu 61: Mt hn hp kh gm 1 ankan v 1 anken c cng s nguyn t C trong phn t v ccng s mol. Ly m gam hn hp ny th lm mt mu va 80 gam dung dch 20% Br2 trongdung mi CCl4. t chy hon ton m gam hn hp thu c 0,6 mol CO2. Ankan v anken c cng thc phn t l:

A. C2H6 v C2H4. B. C4H10 v C4H8. C. C3H8 v C3H6. D. C5H12 v C5H10.Cu 62: t chy hon ton 10ml hirocacbon X cn va 60 ml kh oxi, sau phn ng thuc 40 ml kh cacbonic. Bit X lm mt mu dung dch brom v c mch cacbon phn nhnh.CTCT ca X

A. CH2=CHCH2CH3. B. CH2=C(CH3)2.C. CH2=C(CH2)2CH3. D. (CH3)2C=CHCH3.

Cu 63: Cho 0,2 mol hn hp X gm etan, propan v propen qua dung dch brom d, thy khilng bnh brom tng 4,2 gam. Lng kh cn li em t chy hon ton thu c 6,48 gam nc.Vy % th tch etan, propan v propen ln lt l:

A. 30%, 20%, 50%. B. 20%, 50%, 30%.C. 50%, 20%, 30%. D. 20%, 30%, 50%.

Cu 64: Mt hn hp X gm 2 hirocacbon A, B c cng s nguyn t cacbon. A, B ch c th lankan hay anken. t chy 4,48 lt (kc) hn hp X thu c 26,4 gam CO2 v 12,6 gam H2O. Xcnh CTPT v s mol ca A, B trong hn hp X.

A. 0,1 mol C3H8 v 0,1 mol C3H6. B. 0,2 mol C2H6 v 0,2 mol C2H4.C. 0,08 mol C3H8 v 0,12 mol C3H6. D. 0,1 mol C2H6 v 0,2 mol C2H4.

Cu 65: Mt hn hp X gm 1 anken A v 1 ankin B, A v B c cng s nguyn t cacbon. X ckhi lng l 12,4 gam, c th tch l 6,72 lt. Cc th tch kh o ktc. CTPT v s mol A, Btrong hn hp X l:


Cu 66: Mt hn hp A gm 2 hirocacbon X, Y lin tip nhau trong cng dy ng ng. tchy 11,2 lt hn hp X thu c 57,2 gam CO2 v 23,4 gam CO2. CTPT X, Y v khi lng ca X,Y l:

A. 12,6 gam C3H6 v 11,2 gam C4H8. B. 8,6 gam C3H6v 11,2 gam C4H8.C. 5,6 gam C2H4 v 12,6 gam C3H6. D. 2,8 gam C2H4 v 16,8 gam C3H6.

Cu 67: t chy hon ton 0,05 mol mt anken A thu c 4,48 lt CO2 (ktc). Cho A tc dng

vi dung dch HBr ch cho mt sn phm duy nht. CTCT ca A l:A. CH2=CH2. B. (CH3)2C=C(CH3)2. C. CH2=C(CH3)2.D. CH3CH=CHCH3.Cu 68: Hn hp X gm propen l ng ng theo t l th tch 1:1. t 1 th tch hn hp X cn3,75 th tch oxi (cng k). Vy B l:

A. eten. B.propan. C.buten. D.penten.Cu 69: em t chy hon ton 0,1 mol hn hp X gm 2 anken l ng ng k tip nhau thuc CO2 v nc c khi lng hn km nhau 6,76 gam. CTPT ca 2 anken l:

A. C2H4 v C3H6. B. C3H6 v C4H8.C. C4H8 v C5H10. D. C5H10 v C6H12.Cu 70: X, Y, Z l 3 hirocacbon k tip trong dy ng ng, trong MZ = 2MX. t chy honton 0,1 mol Y ri hp th ton b sn phm chy vo 2 lt dung dch Ba(OH)2 0,1M c mtlng kt ta l:

A. 19,7 gam. B. 39,4 gam. C. 59,1 gam. D. 9,85 gam.Cu 71: Chia hn hp gm C3H6, C2H4, C2H2 thnh hai phn u nhau.

Phn 1: t chy hon ton thu c 2,24 lt CO2 (ktc).



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Phn 2: Hiro ho ri t chy ht th th tch CO2 thu c (ktc) l bao nhiu ?A. 1,12 lt. B. 2,24 lt. C. 4,48 lt. D. 3,36 lt.

Cu 72: t chy hon ton 20,0 ml hn hp X gm C3H6, CH4, CO (th tch CO gp hai ln thtch CH4), thu c 24,0 ml CO2(cc th tch kh o cng iu kin nhit v p sut). T khica X so vi kh H2 l:

A. 12,9. B. 25,8. C. 22,2. D. 11,1Cu 73: t chy hon ton 0,1 mol anken X thu c CO 2 v hi nc. Hp th hon ton sn

phm bng 100 gam dung dch NaOH 21,62% thu c dung dch mi trong nng ca NaOHch cn 5%. Cng thc phn t ng ca X l:

A. C2H4. B. C3H6. C. C4H8. D. C5H10.Cu 74: X l hn hp gm hirocacbon A v O2 (t l mol tng ng 1:10). t chy hon ton Xc hn hp Y. Dn Y qua bnh H2SO4 c d c hn Z c t khi so vi hiro l 19. A c cngthc phn t l:

A. C2H6. B. C4H8. C C4H6. D. C3H6.Cu 75: m gam hn hp gm C3H6, C2H4 v C2H2 chy hon ton thu c 4,48 lt kh CO2 (ktc).

Nu hiro ho hon ton m gam hn hp trn ri t chy ht hn hp thu c V lt CO2 (ktc).

Gi tr ca V l:A. 3,36. B. 2,24. C. 4,48. D. 1,12.Cu 76: Dn 1,68 lt hn hp kh X gm hai hirocacbon vo bnh ng dung dch brom (d). Saukhi phn ng xy ra hon ton, c 4 gam brom phn ng v cn li 1,12 lt kh. Nu t chyhon ton 1,68 lt X th sinh ra 2,8 lt kh CO2. Cng thc phn t ca hai hirocacbon l (bit ccth tch kh u o ktc)

A. CH4 v C2H4. B. CH4 v C3H4. C. CH4 v C3H6. D. C2H6 v C3H6.Cu 77: Hn hp X gm C3H8 v C3H6 c t khi so vi hiro l 21,8. t chy ht 5,6 lt X (ktc)th thu c bao nhiu gam CO2 v bao nhiu gam H2O ?

A. 33 gam v 17,1 gam. B. 22 gam v 9,9 gam.C. 13,2 gam v 7,2 gam. D. 33 gam v 21,6 gam.

Cu 78: Hin nay PVC c iu ch theo s sau:C2H4 CH2ClCH2Cl C2H3Cl PVC.Nu hiu sut ton b qu trnh t 80% th lng C2H4 cn dng sn xut 5000 kg PVC l:

A. 280 kg. B. 1792 kg. C. 2800 kg. D. 179,2 kg.Cu 79: Thi 0,25 mol kh etilen qua 125 ml dung dch KMnO4 1M trong mi trng trung tnh(hiu sut 100%) khi lng etylen glicol thu c bng

A. 11,625 gam. B. 23,25 gam. C. 15,5 gam. D. 31 gam.Cu 80: kh hon ton 200 ml dung dch KMnO4 0,2M to thnh cht rn mu nu en cn V ltkh C2H4 ( ktc). Gi tr ti thiu ca V l:

A. 2,240. B. 2,688. C. 4,480. D. 1,344.Cu 81: Ba hirocacbon X, Y, Z k tip nhau trong dy ng ng, trong khi lng phn t Z

gp i khi lng phn t X. t chy 0,1 mol cht Z, sn phm kh hp th hon ton vo dungdch Ca(OH)2 (d), thu c s gam kt ta l:

A. 20. B. 40. C. 30. D. 10.Cu 82: Hn hp X c t khi so vi H2 l 21,2 gm propan, propen v propin. Khi t chy honton 0,1 mol X, tng khi lng ca CO2 v H2O thu c l:

A. 18,60 gam. B. 18,96 gam. C. 20,40 gam. D. 16,80 gam.

Cu 83: X l hn hp C4H8 v O2 (t l mol tng ng 1:10). t chy hon ton X c hn hpY. Dn Y qua bnh H2SO4 c d c hn Z. T khi ca Z so vi hiro l

A.18. B. 19. C. 20. D. 21.Cu 84: Hn hp X gm 2 anken kh phn ng va vi dung dch cha 48 gam brom. Mt khct chy hon ton hn hp X dng ht 24,64 lt O2 (ktc). Cng thc phn t ca 2 anken l:

A. C2H4 v C3H6.B. C2H4 v C4H8. C. C3H6 v C4H8.D. A v B u ng.



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Cu 85: t chy mt s mol nh nhau ca 3 hirocacbon K, L, M ta thu c lng CO 2 nhnhau v t l s mol nc v CO2 i vi s mol ca K, L, M tng ng l 0,5 ; 1 ; 1,5. CTPT caK, L, M (vit theo th t tng ng) l:

A. C2H4, C2H6, C3H4. B. C3H8, C3H4, C2H4.C. C3H4, C3H6, C3H8. D. C2H2, C2H4, C2H6.

BI TP V ANKAIEN -TECPEN - ANKIN

Cu 1: S ng phn thuc loi ankaien ng vi cng thc phn t C5H8 lA. 4. B. 5. C. 6. D. 7.

Cu 2: C5H8 c bao nhiu ng phn ankaien lin hp ?A. 2. B. 3. C. 4. D. 5.

Cu 3: Trong cc hirocacbon sau: propen, but-1-en, but-2-en, penta-1,4- ien, penta-1,3- ienhirocacbon cho c hin tng ng phn cis - trans ?

A.propen, but-1-en. B.penta-1,4-dien, but-1-en.

C.propen, but-2-en. D.but-2-en, penta-1,3- ien.Cu 4: Cng thc phn t ca buta-1,3-ien (ivinyl) v isopren (2-metylbuta-1,3-ien) ln lt lA. C4H6 v C5H10. B. C4H4 v C5H8. C. C4H6 v C5H8. D. C4H8 v C5H10.

Cu 5: Hp cht no trong s cc cht sau c 9 lin kt xch ma v 2 lin kt ?A. Buta-1,3-ien. B. Penta-1,3- ien. C. Stiren. D. Vinyl axetilen.

Cu 6: Hp cht no trong s cc cht sau c 7 lin kt xch ma v 3 lin kt ?A. Buta-1,3-ien. B. Tuloen. C. Stiren. D. Vinyl axetilen.

Cu 7: Cho phn ng gia buta-1,3-ien v HBr -80oC (t l mol 1:1), sn phm chnh ca phnng l

A. CH3CHBrCH=CH2. B. CH3CH=CHCH2Br.C. CH2BrCH2CH=CH2. D. CH3CH=CBrCH3.

Cu 8: Cho phn ng gia buta-1,3-ien v HBr 40oC (t l mol 1:1), sn phm chnh ca phnng l

A. CH3CHBrCH=CH2. B. CH3CH=CHCH2Br.C. CH2BrCH2CH=CH2. D. CH3CH=CBrCH3.

Cu 9: 1 mol buta-1,3-ien c th phn ng ti a vi bao nhiu mol brom ?A. 1 mol. B. 1,5 mol. C. 2 mol. D. 0,5 mol.

Cu 10: Isopren tham gia phn ng vi dung dch Br2 theo t l mol 1:1 to ra ti a bao nhiu snphm ?

A. 4. B. 1. C. 3. D. 2.Cu 11: Isopren tham gia phn ng vi dung dch HBr theo t l mol 1:1 to ra ti a bao nhiu sn

phm cng ?A. 8. B. 5. C. 7. D. 6.

Cu 12: Cht no sau y khng phi l sn phm cng gia dung dch brom v isopren (theo t lmol 1:1) ?

A. CH2BrC(CH3)BrCH=CH2. B. CH2BrC(CH3)=CHCH2Br.C. CH2BrCH=CHCH2CH2Br. D. CH2=C(CH3)CHBrCH2Br.

Cu 13: Ankaien A + brom (dd) CH3C(CH3)BrCH=CHCH2Br. Vy A lA. 2-metylpenta-1,3-ien. B. 2-metylpenta-2,4-ien.C. 4-metylpenta-1,3-ien. D. 2-metylbuta-1,3-ien.

Cu 14: Ankaien B + Cl2 CH2ClC(CH3)=CH-CH2Cl-CH3. Vy A lA. 2-metylpenta-1,3-ien. B. 4-metylpenta-2,4-ien.

C. 2-metylpenta-1,4-ien. D. 4-metylpenta-2,3-ien.Cu 15: Cho 1 Ankaien A + brom(dd) 1,4-ibrom-2-metylbut-2-en. Vy A lA. 2-metylbuta-1,3-ien. C. 3-metylbuta-1,3-ien.B. 2-metylpenta-1,3-ien. D. 3-metylpenta-1,3-ien.



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Cu 16: Trng hp ivinyl to ra cao su Buna c cu to l ?A. (-C2H-CH-CH-CH2-)n. B. (-CH2-CH=CH-CH2-)n.C. (-CH2-CH-CH=CH2-)n. D. (-CH2-CH2-CH2-CH2-)n.

Cu 17: ng trng hp ivinyl v stiren thu c cao su buna-S c cng thc cu to lA. (-CH2-CH=CH-CH2-CH(C6H5)-CH2-)n. B. (-C2H-CH-CH-CH2-CH(C6H5)-CH2-)n.C. (-CH2-CH-CH=CH2- CH(C6H5)-CH2-)n. D. (-CH2-CH2-CH2-CH2- CH(C6H5)-CH2-)n .

Cu 18: ng trng hp ivinyl v acrylonitrin (vinyl xianua) thu c cao su buna-N c cngthc cu to l

A. (-C2H-CH-CH-CH2-CH(CN)-CH2-)n. B. (-CH2-CH2-CH2-CH2- CH(CN)-CH2-)n.C. (-CH2-CH-CH=CH2- CH(CN)-CH2-)n.D. (-CH2-CH=CH-CH2-CH(CN)-CH2-)n .

Cu 19: Trng hp isopren to ra cao su isopren c cu to lA. (-C2H-C(CH3)-CH-CH2-)n . C. (-CH2-C(CH3)-CH=CH2-)n .B. (-CH2-C(CH3)=CH-CH2-)n. D. (-CH2-CH(CH3)-CH2-CH2-)n .

Cu 20: Tn gi ca nhm hirocacbon khng no c cng thc chung l (C5H8)n (n 2) lA. ankaien. B. cao su. C. anlen. D. tecpen.

Cu 21: Caroten (licopen) l sc t mu ca c rt v c chua chn, cng thc phn t cacaroten l

A. C15H25. B. C40H56. C. C10H16. D. C30H50.Cu 22: Oximen c trong tinh du l hng qu, limonen c trong tinh du chanh. Chng c cngcng thc phn t l

A. C15H25. B. C40H56. C. C10H16. D. C30H50.Cu 23: C4H6 c bao nhiu ng phn mch h ?

A. 5. B. 2. C. 3. D. 4.Cu 24: C bao nhiu ankin ng vi cng thc phn t C5H8 ?

A. 1. B. 2. C. 3. D. 4Cu 25: Ankin C4H6 c bao nhiu ng phn cho phn ng th kim loi (phn ng vi dung dchcha AgNO3/NH3)

A. 4. B. 2. C. 1. D. 3.Cu 26: C bao nhiu ng phn ankin C5H8 tc dng c vi dung dch AgNO3/NH3 to kt taA. 3. B. 2. C. 4. D. 1.

Cu 27: Ankin C6H10 c bao nhiu ng phn phn ng vi dung dch AgNO3/NH3 ?A. 3. B. 4. C. 5. D. 6.

Cu 28: Trong phn t ankin X, hiro chim 11,111% khi lng. C bao nhiu ankin ph hpA. 1. B. 2. C. 3. D. 4

Cu 29: Cho ankin X c cng thc cu to sau :Tn ca X l

CH3C C CH CH3

CH3

A. 4-metylpent-2-in. B. 2-metylpent-3-in. C. 4-metylpent-3-in. D. 2-metylpent-4-in.

Cu 30: Cho phn ng : C2H2 + H2O

AA l cht no di yA. CH2=CHOH. B. CH3CHO. C. CH3COOH. D. C2H5OH.

Cu 31: Cho s phn ng sau: CH3-CCH + AgNO3/ NH3 X + NH4NO3X c cng thc cu to l?

A. CH3-CAgCAg. B. CH3-CCAg.C. AgCH2-CCAg. D. A, B, C u c th ng.

Cu 32: Trong s cc hirocacbon mch h sau: C4H10, C4H6, C4H8, C3H4, nhng hirocacbon noc th to kt ta vi dung dch AgNO3/NH3 ?

A. C4H10 ,C4H8. B. C4H6, C3H4. C. Ch c C4H6. D. Ch c C3H4.Cu 33: Hn hp A gm hiro v cc hirocacbon no, cha no. Cho A vo bnh c niken xc tc,

un nng bnh mt thi gian ta thu c hn hp B. Pht biu no sau y sai ?A. t chy hon ton hn hp A cho s mol CO2 v s mol nc lun bng s mol CO2 v

s mol nc khi t chy hon ton hn hp B.



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B. S mol oxi tiu tn t hon ton hn hp A lun bng s mol oxi tiu tn khi t honton hn hp B.

C. S mol A - S mol B = S mol H2 tham gia phn ng.D. Khi lng phn t trung bnh ca hn hp A bng khi lng phn t trung bnh ca hn

hp B.Cu 34: Cht no trong 4 cht di y c th tham gia c 4 phn ng: Phn ng chy trong oxi,

phn ng cng brom, phn ng cng hiro (xc tc Ni, to), phn ng th vi dd AgNO3 /NH3A. etan. B. etilen. C. axetilen. D. xiclopropan.

Cu 35: Cu no sau y sai ?A. Ankin c s ng phn t hn anken tng ng.B. Ankin tng t anken u c ng phn hnh hc.C. Hai ankin u dy khng c ng phn.D. Butin c 2 ng phn v tr nhm chc.

Cu 36: Cho cc phn ng sau:

CH4 + C l21 : 1

askt(1 )

(2) C2H4 + H2 (3) 2 CHCH

(4) 3 CHCH

(5) C2H2 + Ag2O

(6) Propin + H2O

S phn ng l phn ng oxi ho kh l:A. 2. B. 3. C. 4. D. 5.

Cu 37: Cho dy chuyn ho sau: CH4 A B C Cao su buna.Cng thc phn t ca B l

A. C4H6. B. C2H5OH. C. C4H4. D. C4H10.Cu 38: C chui phn ng sau:

N + H2 B D H C l E (spc) KOH

DXc nh N, B, D, E bit rng D l mt hidrocacbon mch h, D ch c 1 ng phn.

A.N : C2H2 ; B : Pd ; D : C2H4 ; E : CH3CH2Cl.B.N : C4H6 ; B : Pd ; D : C4H8 ; E : CH2ClCH2CH2CH3.

C.N : C3H4 ; B : Pd ; D : C3H6 ; E : CH3CHClCH3.D.N : C3H4 ; B : Pd ; D : C3H6 ; E : CHCH2CH2Cl.

Cu 39: Cht no sau y khng iu ch trc tip c axetilen ?A. Ag2C2. B. CH4. C. Al4C3. D. CaC2.

Cu 40: lm sch etilen c ln axetilen ta cho hn hp i qua dd no sau y ?A. dd brom d. B. dd KMnO4 d.C. dd AgNO3 /NH3 d. D. cc cch trn u ng.

Cu 41: nhn bit cc bnh ring bit ng cc kh khng mu sau y: SO2, C2H2, NH3 ta cth dng ho cht no sau y ?

A. Dung dch AgNO3/NH3. B. Dung dch Ca(OH)2C. Qu tm m. D. Dung dch NaOH

Cu 42: X l mt hirocacbon kh ( ktc), mch h. Hiro ho hon ton X thu c hirocacbonno Y c khi lng phn t gp 1,074 ln khi lng phn t X. Cng thc phn t X l

A. C2H2. B. C3H4. C. C4H6. D. C3H6.Cu 43: Cht hu c X c cng thc phn t C6H6 mch thng. Bit 1 mol X tc dng vi AgNO3d trong NH3 to ra 292 gam kt ta. CTCT ca X c th l

A. CH CCCCH2CH3. C. CHCCH2CH=C=CH2.B. CHCCH2CCCH3. D. CHCCH2CH2CCH.

Cu 44: Mt hirocacbon A mch thng c CTPT C6H6. Khi cho A tc dng vi dung dchAgNO3/NH3 d thu c hp cht hu c B c MB - MA=214 vC. Xc nh CTCT ca A ?

A. CHCCH2CH2CCH. B. CH3C CCH2CCH.

C. CHCCH(CH3)CCH. D. CH3CH2CCCCH.Cu 45: A l hirocacbon mch h, th kh (kt), bit A 1 mol A tc dng c ti a 2 mol Br2trong dung dch to ra hp cht B (trong B brom chim 88,88% v khi lng. Vy A c cng thc

phn t l



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A. C5H8. B. C2H2. C. C4H6. D. C3H4.Cu 46: 4 gam mt ankin X c th lm mt mu ti a 100 ml dung dch Br2 2M. CTPT X l

A. C5H8 . B. C2H2. C. C3H4. D. C4H6.Cu 47: X l mt hirocacbon khng no mch h, 1 mol X c th lm mt mu ti a 2 mol bromtrong nc. X c % khi lng H trong phn t l 10%. CTPT X l

A. C2H2. B. C3H4. C. C2H4. D. C4H6.Cu 48: X l hn hp gm 2 hirocacbon mch h (thuc dy ng ng ankin, anken, ankan).Cho 0,3 mol X lm mt mu va 0,5 mol brom. Pht biu no di y ng

A. X c th gm 2 ankan. B. X c th gm2 anken.C. X c th gm1 ankan v 1 anken. D. X c th gm1 anken v mt ankin.

Cu 49: Hn hp X gm 1 ankin th kh v hiro c t khi hi so vi CH 4 l 0,425. Nung nnghn hp X vi xc tc Ni phn ng hon ton thu c hn hp kh Y c t khi hi so vi CH4l 0,8. Cho Y i qua bnh ng dung dch brom d, khi lng bnh tng ln bao nhiu gam ?

A. 8. B. 16. C. 0. D. Khng tnh c.Cu 50: Hn hp A gm C2H2 v H2 c dA/H2 = 5,8. Dn A (ktc) qua bt Ni nung nng cho nkhi cc phn ng xy ra hon ton ta c hn hp B. Phn trm th tch mi kh trong hn hp Av dB/H2 l

A. 40% H2; 60% C2H2; 29. B. 40% H2; 60% C2H2 ; 14,5.C. 60% H2; 40% C2H2 ; 29. D. 60% H2; 40% C2H2 ; 14,5.

Cu 51: Mt hn hp gm etilen v axetilen c th tch 6,72 lt (ktc). Cho hn hp qua dungdch brom d phn ng xy ra hon ton, lng brom phn ng l 64 gam. Phn % v th tchetilen v axetilen ln lt l

A. 66% v 34%. B. 65,66% v 34,34%.C. 66,67% v 33,33%. D. Kt qu khc.

Cu 52: Cho 10 lt hn hp kh CH4 v C2H2 tc dng vi 10 lt H2 (Ni, to). Sau khi phn ng xy rahon ton thu c 16 lt hn hp kh (cc kh u o cng iu kin nhit p sut). Th tchca CH4 v C2H2 trc phn ng l

A. 2 lt v 8 lt. B. 3 lt v 7 lt. C. 8 lt v 2 lt. D. 2,5 lt v 7,5 lt.Cu 53: Cho 28,2 gam hn hp X gm 3 ankin ng ng k tip qua mt lng d H 2 (to, Ni) phn ng xy ra hon ton. Sau phn ng th tch th tch kh H 2 gim 26,88 lt (ktc). CTPT ca 3ankin l

A. C2H2, C3H4, C4H6. B. C3H4, C4H6, C5H8.C. C4H6, C5H8, C6H10. D. C A, B u ng.

Cu 54: Hn hp X gm propin v mt ankin A c t l mol 1:1. Ly 0,3 mol X tc dng vi dungdch AgNO3/NH3 d thu c 46,2 gam kt ta. A l

A. But-1-in. B. But-2-in. C. Axetilen. D. Pent-1-in.Cu 55: Trong bnh kn cha hirocacbon X v hiro. Nung nng bnh n khi phn ng hon tonthu c kh Y duy nht. cng nhit , p sut trong bnh trc khi nung nng gp 3 ln p sut

trong bnh sau khi nung. t chy mt lng Y thu c 8,8 gam CO2 v 5,4 gam nc. Cng thcphn t ca X l

A. C2H2. B. C2H4. C. C4H6. D. C3H4.Cu 56: t chy hon ton mt ankin X th kh thu c H2O v CO2 c tng khi lng l 23gam. Nu cho sn phm chy i qua dung dich Ca(OH)2 d, c 40 gam kt ta. Cng thc phnt ca X l

A. C3H4. B. C2H2. C. C4H6. D. C5H8.Cu 57: t chy hon ton 5,4 gam mt hirocacbon A ri cho sn phm chy i qua bnh 1 ngdd H2SO4 c, d; bnh 2 ng dung dch Ba(OH)2 dthy khi lng bnh 1 tng 5,4 gam; bnh 2tng 17,6 gam. A l cht no trong nhng cht sau ? (A khng tc dng vi dd AgNO3/NH3)

A. But-1-in. B. But-2-in. C. Buta-1,3-ien. D. B hoc C.

Cu 58: Hn hp X gm C2H2 v H2 ly cng s mol. Ly mt lng hn hp X cho i qua chtxc tc thch hp, un nng c hn hp Y gm 4 cht. Dn Y qua bnh ng nc brom thy



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khi lung bnh tng 10,8 gam v thot ra 4,48 lt kh Z (ktc) c t khi so vi H2 l 8. Th tch O2(ktc) cn t chy hon ton hn hp Y l

A. 33,6 lt. B. 22,4 lt. C. 16,8 lt. D. 44,8 lt.Cu 59: Cho 17,92 lt hn hp X gm 3 hirocacbon kh l ankan, anken v ankin ly theo t l mol1:1:2 li qua bnh ng dd AgNO3/NH3 ly d thu c 96 gam kt ta v hn hp kh Y cn li.t chy hon ton hn hp Y thu c 13,44 lt CO2. Bit th tch o ktc. Khi lng ca X l

A. 19,2 gam. B. 1,92 gam. C. 3,84 gam. D. 38,4 gam.Cu 60: Mt hn hp gm 2 ankin khi t chy cho ra 13,2 gam CO2 v 3,6 gam H2O. Tnh khilng brom c th cng vo hn hp trn

A. 16 gam. B. 24 gam. C. 32 gam. D. 4 gam.Cu 61: Cho canxi cacbua k thut (ch cha 80% CaC2 nguyn cht) vo nc d, th thu c3,36 lt kh (ktc). Khi lng canxi cacbua k thut dng l

A. 9,6 gam. B. 4,8 gam C. 4,6 gam. D. 12 gamCu 62: C 20 gam mt mu CaC2 (c ln tp cht tr) tc dng vi nc thu c 7,4 lt khaxetilen (20oC, 740mmHg). Cho rng phn ng xy ra hon ton. tinh khit ca mu CaC2 l

A. 64%. B. 96%. C. 84%. D. 48%.Cu 63: Cho hn hp X gm CH4, C2H4 v C2H2. Ly 8,6 gam X tc dng ht vi dung dch brom(d) th khi lng brom phn ng l 48 gam. Mt khc, nu cho 13,44 lt ( ktc) hn hp kh Xtc dng vi lng d dung dch AgNO3 trong NH3, thu c 36 gam kt ta. Phn trm th tchca CH4 c trong X l

A. 40%. B. 20%. C. 25%. D. 50%.Cu 64: Hn hp kh X gm anken M v ankin N c cng s nguyn t cacbon trong phn t. Hnhp X c khi lng 12,4 gam v th tch 6,72 lt ( ktc). S mol, cng thc phn t ca M v Nln lt l


Cu 65: Trong mt bnh kn cha hirocacbon A th kh (kt) v O 2 (d). Bt tia la in t

chy ht A a hn hp v iu kin ban u trong % th tch ca CO2 v hi nc ln lt l30% v 20%. Cng thc phn t ca A v % th tch ca hirocacbon A trong hn hp lA. C3H4 v 10%. B. C3H4 v 90%. C. C3H8 v 20%. D. C4H6 v 30%.

Cu 66: t chy hon ton 1 lt hn hp kh gm C2H2 v hirocacbon X sinh ra 2 lt kh CO2 v 2lt hi H2O (cc th tch kh v hi o trong cng iu kin nhit v p sut). Cng thc phn tca X l

A. C2H4. B. CH4. C. C2H6. D. C3H8.Cu 67: Hn hp X c t khi so vi H2l 21 gm propan, propen v propin. Khi t chy honton 0,1 mol X, tng khi lng ca CO2v H2O thu c l

A. 18,60 gam. B. 18,96 gam. C. 20,40 gam. D. 16,80 gam.Cu 68:Cho s chuyn ha: CH4 C2H2 C2H3Cl PVC. tng hp 250 kg PVC theo

s trn th cn V m3 kh thin nhin ( ktc). Gi tr ca V l (bit CH4chim 80% th tch khthin nhin v hiu sut ca c qu trnh l 50%)

A. 224,0. B. 448,0. C. 286,7. D. 358,4.Cu 69: un nng hn hp kh gm 0,06 mol C2H2v 0,04 mol H2vi xc tc Ni, sau mt thigian thu c hn hp kh Y. Dn ton b hn hp Y li t t qua bnh ng dung dch brom (d)th cn li 0,448 lt hn hp kh Z ( ktc) c t khi so vi O 2l 0,5. Khi lng bnh dung dch

brom tng lA. 1,20 gam. B. 1,04 gam. C. 1,64 gam. D. 1,32 gam.

Cu 70: t chy hon ton m gam hirocacbon th kh, mch h, nng hn khng kh thu c7,04 gam CO2. Sc m gam hirocacbon ny vo nc brom d n khi phn ng hon ton, thy c25,6 gam brom phn ng. Gi tr ca m l

A. 2 gam. B. 4 gam. C. 10 gam D. 2,08 gam



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Cu 71: t chy hon ton m gam hirocacbon th kh, mch h thu c 7,04 gam CO2. Sc mgam hirocacbon ny vo nc brom d n khi phn ng hon ton, thy c 25,6 gam brom phnng. Gi tr ca m l

A. 2 gam. B. 4 gam. C. 2,08 gam. D. A hoc C.Cu 72: Dn V lt ( ktc) hh X gm axetilen v hiro i qua ng s ng bt niken nung nng,thu c kh Y. Dn Y vo lng d AgNO3 trong dd NH3 thu c 12 gam kt ta. Kh i ra khidung dch phn ng va vi 16 gam brom v cn li kh Z. t chy hon ton kh Z c 2,24lt kh CO2 (ktc) v 4,5 gam H2O. Gi tr ca V bng

A. 11,2. B. 13,44. C. 5,60. D. 8,96.Cu 73: Cho 4,48 lt hn hp X (ktc) gm 2 hirocacbon mch h li t t qua bnh cha 1,4 ltdung dch Br2 0,5M. Sau khi p hon ton, s mol Br2 gim i mt na v m bnh tng thm 6,7gam. CTPT ca 2 hirocacbon l

A. C3H4 v C4H8. B. C2H2 v C3H8. C. C2H2 v C4H8. D. C2H2 v C4H6.Cu 74: Dn 1,68 lt hn hp kh X gm hai hirocacbon vo bnh ng dd brom (d). Sau khi

phn ng hon ton, c 4 gam brom phn ng v cn li 1,12 lt kh. Nu t chy hon ton1,68 lt X th sinh ra 2,8 lt kh CO2 (ktc). CTPT ca hai hirocacbon l

A. CH4 v C2H4. B. CH4 v C3H4. C. CH4 v C3H6. D. C2H6v C3H6.Cu 75: t chy hon ton hn hp M gm mt ankan X v mt ankin Y, thu c s mol CO 2

bng s mol H2O. Thnh phn % v s mol ca X v Y trong hn hp M ln lt lA. 35% v 65%. B. 75% v 25%. C. 20% v 80%. D. 50% v 50%.

Cu 76: t chy hon ton 20,0 ml hn hp X gm C3H6, CH4, CO (th tch CO gp hai ln thtch CH4), thu c 24,0 ml CO2 (cc kh o cng iu kin to, p). T khi ca X so vi kh hirol

A. 25,8. B. 12,9. C. 22,2. D. 11,1.Cu 77: Mt hn hp X gm 1 ankan A v 1 ankin B c cng s nguyn t cacbon. Trn X viH2 c hn hp Y. Khi cho Y qua Pt nung nng th thu c kh Z c t khi i vi CO 2

bng 1 (phn ng cng H2 hon ton). Bit rng VX = 6,72 lt v 2HV = 4,48 lt. CTPT v s mol

A, B trong hn hp X l (Cc th tch kh o kc)A. 0,1 mol C2H6 v 0,2 mol C2H2. B. 0,1 mol C3H8 v 0,2 mol C3H4.C. 0,2 mol C2H6 v 0,1 mol C2H2. D. 0,2 mol C3H8 v 0,1 mol C3H4.

Cu 78: Mt hn hp X gm C2H2, C3H6, CH4. t chy hon ton 11t hn hp X thu c 12,6gam H2O. Nu cho 11,2 lt hn hp X (ktc) qua dung dch brom d thy c 100 gam brom phnng. Thnh phn % th tch ca X ln lt l

A. 50%; 25% ; 25%. B. 25% ; 25; 50%.C.16% ; 32; 52%. D. 33,33%; 33,33; 33,33%.

Cu 79: Dn 4,032 lt (ktc) hn hp kh A gm C2H2, C2H4, CH4 ln lt qua bnh 1 cha dung dcAgNO3 trong NH3 ri qua bnh 2 cha dung dch Br2 d trong CCl4. bnh 1 c 7,2 gam kt ta.Khi lng bnh 2 tng thm 1,68 gam. Th tch (ktc) hn hp A ln lt l:

A. 0,672 lt; 1,344 lt; 2,016 lt. B. 0,672 lt; 0,672 lt; 2,688 lt.C. 2,016; 0,896 lt; 1,12 lt. D. 1,344 lt; 2,016 lt; 0,672 lt.

Cu 80: X, Y, Z l 3 hirocacbon th kh trong iu kin thng, khi phn hu mi cht X, Y, Zu to ra C v H2, th tch H2 lun gp 3 ln th tch hirocacbon b phn hu v X, Y, Z khng

phi l dng phn. CTPT ca 3 cht lA. C2H6 ,C3H6 C4H6. B. C2H2 ,C3H4 C4H6. C. CH4 ,C2H4 C3H4. D. CH4 ,C2H6 C3H8.

Cu 81: Hn hp X gm 0,1 mol C2H2; 0,15 mol C2H4 ; 0,2 mol C2H6 v 0,3 mol H2. un nng Xvi bt Ni xc tc 1 thi gian c hn hp Y. t chy hon ton hn hp Y c s gam CO2 vH2O ln lt l

A. 39,6 v 23,4. B. 3,96 v 3,35. C. 39,6 v 46,8. D. 39,6 v 11,6.

Cu 82: Hn hp ban u gm 1 ankin, 1 anken, 1 ankan v H2 vi p sut 4 atm. un nng bnhvi Ni xc tc thc hin phn ng cng sau a bnh v nhit ban u c hn hp Y, psut hn hp Y l 3 atm. T khi hn hp X v Y so vi H2 ln lt l 24 v x. Gi tr ca x l

A. 18. B. 34. C. 24. D. 32.



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Cu 83: Hn hp A gm H2, C3H8, C3H4. Cho t t 12 lt A qua bt Ni xc tc. Sau phn ng c6 lt kh duy nht (cc kh o cng iu kin). T khi hi ca A so vi H2 l

A. 11. B. 22. C. 26. D. 13.Cu 84: un nng hn hp X gm 0,1 mol C3H4 ; 0,2 mol C2H4 ; 0,35 mol H2 vi bt Ni xc tcc hn hp Y. Dn ton b Y qua bnh ng dung dch KMnO4 d, thy thot ra 6,72 l hn hpkh Z (ktc) c t khi so vi H2 l 12. Bnh ng dung dch KMnO4 tng s gam l:

A. 17,2. B. 9,6. C. 7,2. D. 3,1.Cu 85: t chy m gam hn hp C2H6, C3H4, C3H8, C4H10 c 35,2 gam CO2 v 21,6 gam H2O.Gi tr ca m l

A. 14,4. B. 10,8. C. 12. D. 56,8.Cu 86: t chy 1 hirocacbon A c 22,4 lt kh CO2 (ktc) v 27 gam H2O. Th tch O2 (ktc)(l) tham gia phn ng l:

A. 24,8. B. 45,3. C. 39,2. D. 51,2.Cu 87: Mt hn hp X gm 1 ankin v H2 c V = 8,96 lt (kc) v mX = 4,6 gam. Cho hn hp X

i qua Ni nung nng, phn ng hon ton cho ra hn hp kh Y, c t khiX

Yd = 2. S mol H2phn ng; khi lng; CTPT ca ankin l

A. 0,16 mol; 3,6 gam; C2H2. B. 0,2 mol; 4 gam; C3H4.C. 0,2 mol; 4 gam; C2H2. D. 0,3 mol; 2 gam; C3H4.

Cu 88: t chy mt hirocacbon M thu c s mol nc bng s mol CO2 v s mol CO2nh hn hoc bng 5 ln s mol M. Xc nh CTPT v CTCT ca M bit rng M cho kt ta vidung dch AgNO3/NH3.

A. C4H6 v CH3CH2C CH. B. C4H6 v CH2=C=CHCH3.C. C3H4 v CH3C CH. D. C4H6 v CH3C CCH3.



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CHUYN 4 : HIROCACBON THM NGUNHIROCACBON THIN NHIN

Cu 1: Trong phn t benzen, cc nguyn t C u trng thi lai ho :A. sp. B. sp2. C. sp3. D. sp2d.

Cu 2: Trong vng benzen mi nguyn t C dng 1 obitan p cha tham gia lai ho to ra :A. 2 lin kt pi ring l. B. 2 lin kt pi ring l.C. 1 h lin kt pi chung cho 6 C. D. 1 h lin kt xigma chung cho 6 C.

Cu 3: Trong phn t benzen:A. 6 nguyn t H v 6 C u nm trn 1 mt phng.B. 6 nguyn t H nm trn cng 1 mt phng khc vi mt phng ca 6 C.C. Ch c 6 C nm trong cng 1 mt phng.D. Ch c 6 H mm trong cng 1 mt phng.

Cu 4: Cho cc cng thc :

(1)

H

(2) (3)Cu to no l ca benzen ?

A. (1) v (2). B. (1) v (3). C. (2) v (3). D. (1) ; (2) v (3).Cu 5: Dy ng ng ca benzen c cng thc chung l:

A. CnH2n+6 ; n 6. B. CnH2n-6 ; n 3.C. CnH2n-6 ; n 6. D. CnH2n-6 ; n 6.

Cu 6: Cng thc tng qut ca hirocacbon CnH2n+2-2a. i vi stiren, gi tr ca n v a ln lt l:A. 8 v 5. B. 5 v 8. C. 8 v 4. D. 4 v 8.

Cu 7: Cng thc tng qut ca hirocacbon CnH2n+2-2a. i vi naptalen, gi tr ca n v a ln ltl:

A. 10 v 5. B. 10 v 6. C. 10 v 7. D. 10 v 8.Cu 8: Cht no sau y c th cha vng benzen ?

A. C10H16. B. C9H14BrCl. C. C8H6Cl2. D. C7H12.Cu 9: Cht no sau y khng th cha vng benzen ?

A. C8H10. B. C6H8. C. C8H10. D. C9H12.Cu 10: Cho cc cht: C6H5CH3 (1) p-CH3C6H4C2H5 (2)

C6H5C2H3 (3) o-CH3C6H4CH3 (4)Dy gm cc cht l ng ng ca benzen l:

A. (1); (2) v (3). B. (2); (3) v (4).C. (1); (3) v (4). D. (1); (2) v (4).

Cu 11: Cht cu to nh sau c tn gi l g ? CH3

CH3

A. o-xilen. B. m-xilen. C.p-xilen. D. 1,5-imetylbenzen.Cu 12: CH3C6H2C2H5 c tn gi l:

A. etylmetylbenzen. B. metyletylbenzen.C.p-etylmetylbenzen. D. p-metyletylbenzen.

Cu 13: (CH3)2CHC6H5 c tn gi l:A.propylbenzen. B. n-propylbenzen.

C. iso-propylbenzen. D. imetylbenzen.Cu 14: iso-propyl benzen cn gi l:A.Toluen. B. Stiren. C. Cumen. D. Xilen.



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Cu 15: Cu to ca 4-cloetylbenzen l:

A.

C2H5

Cl B.

C2H5

Cl C.

C2H5

Cl

D.

C2H5

Cl

Cu 16: Ankylbenzen l hirocacbon c cha :A. vng benzen. B. gc ankyl v vng benzen.C. gc ankyl v 1 benzen. D. gc ankyl v 1 vng benzen.

Cu 17: Gc C6H5-CH2- v gc C6H5- c tn gi l:A.phenyl v benzyl. B. vinyl v anlyl.C. anlyl v Vinyl. D.benzyl v phenyl.

Cu 18: iu no sau u khng ng kh ni v 2 v tr trn 1 vng benzen ?A. v tr 1, 2 gi l ortho. B. v tr 1,4 gi l para.C. v tr 1,3 gi l meta. D. v tr 1,5 gi l ortho.

Cu 19: Mt ankylbenzen A c cng thc C9H12, cu to c tnh i xng cao. Vy A l:

A. 1,2,3-trimetyl benzen. B. n-propyl benzen.C. iso-propyl benzen. D. 1,3,5-trimetyl benzen.Cu 20: Mt ankylbenzen A (C12H18) cu to c tnh i xng cao. A l:

A. 1,3,5-trietylbenzen. B. 1,2,4-tri etylbenzen.C. 1,2,3-tri metylbenzen. D. 1,2,3,4,5,6-hexaetylbenzen.

Cu 21: C7H8 c s ng phn thm l:A. 1. B. 2. C. 3. D. 4.

Cu 22: ng vi cng thc phn t C8H10 c bao nhiu cu to cha vng benzen ?A. 2. B. 3. C. 4. D. 5.

Cu 23: ng vi cng thc C9H12 c bao nhiu ng phn c cu to cha vng benzen ?A. 6. B. 7. C. 8. D. 9.

Cu 24: S lng ng phn cha vng benzen ng vi cng thc phn t C9H10 lA. 7. B. 8. C. 9. D. 6.Cu 25: A l ng ng ca benzen c cng thc nguyn l: (C3H4)n. Cng thc phn t ca A l:

A. C3H4. B. C6H8. C. C9H12. D. C12H16.Cu 26: Cho cc cht (1) benzen ; (2) toluen; (3) xiclohexan; (4) hex-5-trien; (5) xilen; (6) cumen.Dy gm cc hirocacbon thm l:

A. (1); (2); (3); (4). B. (1); (2); (5; (6).C. (2); (3); (5) ; (6). D. (1); (5); (6); (4).

Cu 27: Hot tnh sinh hc ca benzen, toluen l:A. Gy hi cho sc khe.B. Khng gy hi cho sc khe.

C. Gy nh hng tt cho sc khe.D. Ty thuc vo nhit c th gy hi hoc khng gy hi.

Cu 28: Tnh cht no sau y khng phi ca ankyl benzenA. Khng mu sc. B. Khng mi v.C. Khng tan trong nc. D. Tan nhiu trong cc dung mi hu c.

Cu 29: Phn ng no sau y khng xy ra:A. Benzen + Cl2 (as). B. Benzen + H2 (Ni, p, to).C. Benzen + Br2 (dd). D. Benzen + HNO3 () /H2SO4 ().

Cu 30: Tnh cht no khng phi ca benzen ?A. D th. B. Kh cng.C. Bn vi cht oxi ha. D. Km bn vi cc cht oxi ha.

Cu 31: Cho benzen + Cl2 (as) ta thu c dn xut clo A. Vy A l:A. C6H5Cl. B. p-C6H4Cl2. C. C6H6Cl6. D. m-C6H4Cl2.



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Cu 32: Phn ng chng minh tnh cht no; khng no ca benzen ln lt l:A. th, cng. B. cng, nitro ho.C. chy, cng. D. cng, brom ho.

Cu 33: Tnh cht no khng phi ca benzenA. Tc dng vi Br2 (to, Fe). B. Tc dng vi HNO3 () /H2SO4().C. Tc dng vi dung dch KMnO4. D. Tc dng vi Cl2 (as).

Cu 34: Benzen + X etyl benzen. Vy X lA. axetilen. B. etilen. C. etyl clorua. D. etan.

Cu 35: Tnh cht no khngphi ca toluen ?A. Tc dng vi Br2 (to, Fe). B. Tc dng vi Cl2 (as).C. Tc dng vi dung dch KMnO4, to. D. Tc dng vi dung dch Br2.

Cu 36: So vi benzen, toluen + dung dch HNO3()/H2SO4 ():A. D hn, to ra o nitro toluen v p nitro toluen.B. Kh hn, to ra o nitro toluen v p nitro toluen.C. D hn, to ra o nitro toluen v m nitro toluen.D. D hn, to ra m nitro toluen v p nitro toluen.

Cu 37: Toluen + Cl2 (as) xy ra phn ng:A. Cng vo vng benzen. B. Th vo vng benzen, d dng hn.C. Th nhnh, kh khn hn CH4. D. Th nhnh, d dng hn CH4.

Cu 38: 1 mol Toluen + 1 mol Cl2 asA . A l:A. C6H5CH2Cl. B. p-ClC6H4CH3.C. o-ClC6H4CH3. D. B v C u ng.

Cu 39: Tin hnh th nghim cho nitro benzen tc dng vi HNO3 ()/H2SO4 (), nng ta thy:A. Khng c phn ng xy ra.B. Phn ng d hn benzen, u tin v tr meta.C. Phn ng kh hn benzen, u tin v tr meta.D. Phn ng kh hn benzen, u tin v tr ortho.

Cu 40: Khi trn vng benzen c sn nhm th -X, th nhm th hai s u tin th vo v tr o- vp- . Vy -X l nhng nhm th no ?A. -CnH2n+1, -OH, -NH2. B. -OCH3, -NH2, -NO2.C. -CH3, -NH2, -COOH. D. -NO2, -COOH, -SO3H.

Cu 41: Khi trn vng benzen c sn nhm th -X, th nhm th hai s u tin th vo v tr m - .Vy -X l nhng nhm th no ?

A. -CnH2n+1, -OH, -NH2. B. -OCH3, -NH2, -NO2.C. -CH3, -NH2, -COOH. D. -NO2, -COOH, -SO3H.

Cu 42: 1 mol nitrobenzen + 1 mol HNO3 2 4o H SO d

tB + H2O. B l:

A. m-initrobenzen. B. o-initrobenzen.

C. p-initrobenzen. D. B v C u ng.Cu 43: C2H2 A B m-brombenzen. A v B ln lt l:A.benzen ; nitrobenzen. B. benzen,brombenzen.C. nitrobenzen ; benzen. D. nitrobenzen; brombenzen.

Cu 44: Benzen A o-brom-nitrobenzen. Cng thc ca A l:A. nitrobenzen. B. brombenzen.C. aminobenzen. D. o-ibrombenzen.

Cu 45: 1 ankylbenzen A(C9H12),tc dng vi HNO3 c (H2SO4 ) theo t l mol 1:1 to ra 1 dnxut mononitro duy nht . Vy A l:

A. n-propylbenzen. B. p-etyl,metylbenzen.D. iso-propylbenzen D. 1,3,5-trimetylbenzen.

Cu 46: Cho phn ng A/trung hop

1,3,5-trimetylbenzen . A l:A. axetilen. B. metyl axetilen. C. etyl axetilen. D. imetyl axetilen.

Cu 47: Stiren khngphn ng c vi nhng cht no sau y ?Dy v hc Ha hc, http://ngocbinh.webdayhoc.net


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A. dd Br2. B. khng kh H2 ,Ni,to.C. dd KMnO4. D. dd NaOH.

Cu 48: A + 4H2 , ,o Ni p t

etyl xiclohexan. Cu to ca A l:A. C6H5CH2CH3. B. C6H5CH3.C. C6H5CH2CH=CH2. D. C6H5CH=CH2.

Cu 49: Phn ng no sau y khng dng iu ch benzen ?A. tam hp axetilen. B. kh H2 ca xiclohexan.C. kh H2, ng vng n-hexan. D. tam hp etilen.

Cu 50: Phn ng no khng iu ch c toluen ?A. C6H6 + CH3Cl 3 ;

o AlCl t B. kh H2, ng vng benzen

C. kh H2 metylxiclohexan D. tam hp propinCu 51: A ,

oxt t toluen + 4H2. Vy A l:

A. metyl xiclo hexan. B. metyl xiclo hexen. C. n-hexan. D. n-heptan.Cu 52: ng dng no benzen khng c:

A. Lm dung mi. B. Tng hp monome.C. Lm thuc n. D. Dng trc tip lm dc phm.

Cu 53: Thuc n TNT c iu ch trc tip tA.benzen. B. metyl benzen.C. vinyl benzen. D. p-xilen.

Cu 54: phn bit benzen, toluen, stiren ta ch dng 1 thuc th duy nht l:A. Brom (dd). B. Br2 (Fe).C. KMnO4 (dd). D. Br2 (dd) hoc KMnO4(dd).

Cu 55: phn bit c cc cht Hex-1-in, Toluen, Benzen ta dng 1 thuc th duy nht l:A. dd AgNO3/NH3. B. dd Brom. C. dd KMnO4. D. dd HCl.

Cu 56: A l dn xut benzen c cng thc nguyn (CH)n. 1 mol A cng ti a 4 mol H2 hoc 1

mol Br2 (dd). Vy A l:A. etyl benzen. B. metyl benzen. C. vinyl benzen. D. ankyl benzen.Cu 57: a. Mt hn hp X gm 2 aren A, R u c M < 120, t khi ca X i vi C 2H6 l 3,067.CTPT v s ng phn ca A v R l

A. C6H6 (1 ng phn) ; C7H8 (1 ng phn).B. C7H8 (1 ng phn) ; C8H10 (4 ng phn).C. C6H6 (1 ng phn) ; C8H10 (2 ng phn).D. C6H6 (1 ng phn) ; C8H10 (4 ng phn).

b. Mt hp cht hu c c vng benzen c CTGN l C3H2Br v M = 236. Gi tn hp cht nybit rng hp cht ny l sn phm chnh trong phn ng gia C6H6 v Br2 (xc tc Fe)

A. o-hoc p-ibrombenzen. B. o-hoc p-ibromuabenzen.

C. m-ibromuabenzen. D. m-ibrombenzen.Cu 58: Hn hp C6H6 v Cl2 c t l mol 1 : 1,5. Trong iu kin c xc tc bt Fe, t o, hiu sut100%. Sau phn ng thu c cht g ? bao nhiu mol ?

A.1 mol C6H5Cl ; 1 mol HCl ; 1 mol C6H4Cl2.B. 1,5 mol C6H5Cl ; 1,5 mol HCl ; 0,5mol C6H4Cl2.C. 1 mol C6H5Cl ; 1,5 mol HCl ; 0,5 mol C6H4Cl2.D. 0,5 mol C6H5Cl ; 1,5 mol HCl ; 0,5 mol C6H4Cl2.

Cu 59: Cho 100 ml bezen (d = 0,879 g/ml) tc dng vi mt lng va brom lng (xc tc btst, un nng) thu c 80 ml brombenzen (d = 1,495 g/ml). Hiu sut brom ha t l

A. 67,6%. B. 73,49%. C. 85,3%. D. 65,35%

Cu 60: Cho benzen vo 1 l ng Cl2 d ri a ra nh sng. Sau khi phn ng xy ra hon tonthu c 5,82 kg cht sn phm. Tn ca sn phm v khi lng benzen tham gia phn ng l:

A. clobenzen; 1,56 kg. B. hexacloxiclohexan; 1,65 kg.Dy v hc Ha hc, http://ngocbinh.webdayhoc.net


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C. hexacloran; 1,56 kg. D. hexaclobenzen; 6,15 kg.Cu 61: A c cng thc phn t l C8H8, tc dng vi dung dch KMnO4 nhit thng to raancol 2 chc. 1 mol A tc dng ti a vi:

A. 4 mol H2; 1 mol brom. B. 3 mol H2; 1 mol brom.C. 3 mol H2; 3 mol brom. D. 4 mol H2; 4 mol brom.

Cu 62: A l hirocacbon c %C (theo khi lng) l 92,3%. A tc dng vi dung dch brom dcho sn phm c %C (theo khi lng) l 36,36%. Bit MA < 120. Vy A c cng thc phn t l

A. C2H2. B. C4H4. C. C6H6. D. C8H8.Cu 63: Tin hnh trng hp 10,4 gam stiren c hn hp X gm polistiren v stiren (d). Cho Xtc dng vi 200 ml dung dch Br2 0,15M, sau cho dung KI d vo thy xut hin 1,27 gam iot.Hiu sut trng hp stiren l

A. 60%. B. 75%. C. 80%. D. 83,33%.Cu 64: hiro ho etylbenzen ta c stiren; trng hp stiren ta c polistiren vi hiu sutchung 80%. Khi lng etylbenzen cn dng sn xut 10,4 tn polisitren l:

A.13,52 tn. B. 10,6 tn. C. 13,25 tn. D. 8,48 tn.Cu 65: a. t chy hon ton m gam A (CxHy), thu c m gam H2O. Cng thc nguyn ca A l:

A. (CH)n. B. (C2H3)n. C. (C3H4)n. D. (C4H7)n.b.t chy hon ton 1,3 gam A (CxHy) to ra 0,9 gam H2O. Cng thc nguyn ca A l:

A. (CH)n. B. (C2H3)n. C. (C3H4)n. D. (C4H7)n.Cu 66: t chy hon ton hirocacbon X cho CO2 v H2O theo t l mol 1,75 : 1 v th tch. Cho

bay hi hon ton 5,06 gam X thu c mt th tch hi ng bng th tch ca 1,76 gam oxi trongcng iu kin. Nhn xt no sau y l ng i vi X ?

A. X khng lm mt mu dung dch Br2 nhng lm mt mu dung dch KMnO4 un nng.B. X tc dng vi dung dch Br2 to kt ta trng.C. X c th trng hp thnh PS.D. X tan tt trong nc.

Cu 67: t chy hon ton m gam hirocacbon A, thu c m gam H2O. Cng thc phn t ca

A (150 < MA < 170) l:A. C4H6. B. C8H12. C. C16H24. D. C12H18.Cu 68: t chy hon ton 6 gam cht hu c A, ng ng ca benzen thu c 10,08 lt CO 2(ktc). Cng thc phn t ca A l:

A. C9H12. B. C8H10. C. C7H8. D. C10H14.Cu 69: t chy hon ton 0,1 mol CxHy thu c 20,16 lt CO2 (ktc) v 10,8 gam H2O (lng).Cng thc ca CxHy l:

A. C7H8. B. C8H10. C. C10H14. D. C9H12.Cu 70: A (CxHy) l cht lng iu kin thng. t chy A to ra CO 2 v H2O v mCO2 : mH2O =4,9 : 1. Cng thc phn t ca A l:

A. C7H8. B. C6H6. C. C10H14. D. C9H12.

Cu 71: t chy hon ton hi A (CxHy) thu c 8 lt CO2 v cn dng 10,5 lt oxi. Cng thcphn t ca A l:A. C7H8. B. C8H10. C. C10H14. D. C9H12.

Cu 72: Cho a gam cht A (CxHy) chy thu c 13,2 gam CO2 v 3,6 gam H2O. Tam hp A thuc B, mt ng ng ca ankylbenzen. Cng thc phn t ca A v B ln lt l:

A. C3H6 v C9H8. B. C2H2 v C6H6.C. C3H4 v C9H12. D. C9H12 v C3H4.

Cu 73: 1,3 gam cht hu c A chy hon ton thu c 4,4 gam CO2 v 0,9 gam H2O. T khi hica A i vi oxi l d tha mn iu kin 3


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Cu 75: t chy ht m gam 2 ng ng ca benzen A, B thu c 4,05 gam H 2O v 7,728 ltCO2 (ktc). Gi tr ca m v s tng s mol ca A, B l:

A. 4,59 v 0,04. B. 9,18 v 0,08. C. 4,59 v 0,08. D. 9,14 v 0,04.Cu 76: t chy ht 9,18 gam 2 ng ng ca benzen A, B thu c 8,1 gam H 2O v V lt CO2(ktc). Gi tr ca V l:

A. 15,654. B. 15,465. C. 15,546. D. 15,456.Cu 77: t chy ht 2,295 gam 2 ng ng ca benzen A, B thu c 2,025 gam H 2O v CO2.Dn ton b lng CO2 vo 250 ml dung dch NaOH 1M thu c m gam mui. Gi tr ca m vthnh phn ca mui

A. 16,195 (2 mui). B. 16,195 (Na2CO3).C. 7,98 (NaHCO3) D. 10,6 (Na2CO3).

Cu 78: t chy ht 9,18 gam 2 ng ng k tip thuc dy ca benzen A, B thu c H 2O v30,36 gam CO2. Cng thc phn t ca A v B ln lt l:

A. C6H6 ; C7H8. B. C8H10 ; C9H12.C. C7H8 ; C9H12. D. C9H12 ; C10H14.

Cu 79: t 0,13 gam mi cht A v B u cng thu c 0,01 mol CO2 v 0,09 gam H2O. T khihi ca A so vi B l 3; t khi hi ca B so vi H2 l 13. Cng thc ca A v B ln lt l:

A. C2H2 v C6H6. B. C6H6 v C2H2.C. C2H2 v C4H4. D. C6H6 v C8H8.

Cu 80: A, B, C l ba cht hu c c %C, %H (theo khi lng) ln lt l 92,3% v 7,7%, t l khi lng mol tng ng l 1: 2 : 3. T A c th iu ch B hoc C bng mt phn ng. C khnglm mt mu nc brom. t 0,1 mol B ri dn ton b sn phm chy qua bnh ng dung dchnc vi trong d.

a. Khi lng bnh tng hoc gim bao nhiu gam ?A. Tng 21,2 gam. B. Tng 40 gam.C. Gim 18,8 gam. D. Gim 21,2 gam.

b. Khi lng dung dch tng hoc gim bao nhiu gam ?

A. Tng 21,2 gam. B. tng 40 gam.C. gim 18,8 gam. D. gim 21,2 gam.

CHUYN 5 : DN XUT HALOGEN - PHENOL - ANCOLCu 1 : S ng phn ca C4H9Br l

A. 4. B. 2. C. 3. D. 5.



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Cu 2: S ng phn dn xut halogen bc I c CTPT C4H9Cl lA. 2. B. 3. C. 4. D. 5.

Cu 3: S ng phn mch h (k c ng phn hnh hc) ca cht c CTPT l C3H5Br lA. 2. B. 3. C. 4. D. 5.

Cu 4: Mt hp cht hu c Z c % khi lng ca C, H, Cl ln lt l : 14,28% ; 1,19% ; 84,53%.CTPT ca Z l

A. CHCl2. B. C2H2Cl4. C. C2H4Cl2. D. mt kt qu khc.Cu 5: Dn xut halogen khngc ng phn cis-trans lA. CHCl=CHCl. B. CH2=CH-CH2F. C. CH3CH=CBrCH3. D.CH3CH2CH=CHCHClCH3.Cu 6: Danh php IUPAC ca dn xut halogen c cng thc cu to : ClCH2CH(CH3)CHClCH3 l

A. 1,3-iclo-2-metylbutan. B. 2,4-iclo-3-metylbutan.C. 1,3-iclopentan. D. 2,4-iclo-2-metylbutan.

Cu 7: Cho cc cht sau: C6H5CH2Cl ; CH3CHClCH3 ; Br2CHCH3 ; CH2=CHCH2Cl. Tn gi cacc cht trn ln lt l

A.benzyl clorua ; isopropyl clorua ; 1,1-ibrometan ; anlyl clorua.B.benzyl clorua ; 2-clopropan ; 1,2-ibrometan ;1-cloprop-2-en.C.phenyl clorua ; isopropylclorua ; 1,1-ibrometan ; 1-cloprop-2-en.D.benzyl clorua ; n-propyl clorua ; 1,1-ibrometan ; 1-cloprop-2-en.

Cu 8: Cho cc dn xut halogen sau : C2H5F (1) ; C2H5Br (2) ; C2H5I (3) ; C2H5Cl (4) th tgim dn nhit si l

A. (3)>(2)>(4)>(1). B. (1)>(4)>(2)>(3). C. (1)>(2)>(3)>(4). D. (3)>(2)>(1)>(4).Cu 9: Nh dung dch AgNO3 vo ng nghim cha mt t dn xut halogen CH2=CHCH2Cl, lcnh. Hin tng xy ra l

A. Thot ra kh mu vng lc. B. xut hin kt ta trng.C. khng c hin tng. D. xut hin kt ta vng.

Cu 10: a. Sn phm chnh ca phn ng tch HBr ca CH3CH(CH3)CHBrCH3 l

A. 2-metylb

Sach Bai Tap Trac Nghiem Hoa Huu Co 11

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