SA 606 -P.M.I.S

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    layout must be planned after keeping in mind their particular

    requirements. The position of employees, that is, whether they remain

    stationary or moving, also influences the layout. Employee facilities

    such as health, locker rooms, public facilities and related services also

    influence the layout significantly.

    Machinery:-

    The type of product, the volume of its production, the type

    of process and management policy determines the size and type of the

    machinery to be installed which, in turn, influences the plant layout.

    Production is the combination and manipulation of men, materials and

    machines. Before laying out a plant, it is necessary to determine

    which of these elements are to be stationary or fixed as to location in

    the plant and which will be mobile during the process of production.

    2. State the function of production management. (Same as 4).

    Nov-06

    Repeated Question: - (1)3. Explain the importance of systems approach to production

    management.

    October/Novmeber-024. Define production management. List important areas of it. State the

    function of any one area.

    Ans. Production Management:-

    It refers to the application of management principles to the

    production function in a factory. In other words, production management

    involves application of planning, organizing, directing and controlling to the

    production process.

    The important areas of it are as follows:

    i. Improving the volume of production.

    ii. Reducing the rejection rate.

    iii. Minimizing re-work rate.iv. Maintaining the delivery schedules.

    v. Controlling the idle machine and manpower hours.

    vi. Establishing/updating/improving/setting industrial

    engineering norms.

    vii. Updating processes and procedures.

    viii. Maintaining accuracy and timelines of MIS.

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    ix. Decreasing machine set-up time.

    x. Controlling overtime.

    xi. Good house-keeping.

    xii. Checking absenteeism, thefts/pilferage and misconduct.

    xiii. Eliminating the accidents.

    xiv. Effective grievance handling.

    xv.Efficient training and team building.

    xvi. Minimizing inventory and achieving better yields.

    xvii.Enhancing the customer satisfaction.

    xviii. Total Quality Management (TQM).

    xix. Business Process Re-engineering (BPRE).

    xx. Automation.

    5. Compare the batch production and mass production.Ans.

    Batch Production/ Unit Production Mass Production

    a). In this type, the product is

    produces in the same batches.

    a). In this type of production, the

    production is continues throughout.

    b). Same type of product is repeated

    for many time in the industries.

    b). Once the machine is set-up, there

    is no need to adjust it for a long time

    period.

    c). If the design of product or

    measurement will change there willbe accordingly changes in set-up and

    instruction.

    c). Once the production instruction is

    given, the work is going straight andsystematically.

    d). As per time variation, lots of

    changes implement in machine and

    method.

    d). Raw material storage is

    compulsory in this type of

    production otherwise production will

    stop.

    e). The new product will be dispatch

    in the market within certain batches.

    e).Examples: Electronic industry,

    watch industry, Bearing industry,

    Electrical goods industry.

    f). Examples: medicine industry,shoes industry, furniture,

    Automobiles, Imitation item.

    f).Apart from this process industry isalso a type of Mass Production. It

    also includes chemical and food

    products such as cement, sugar, food

    products, fertilizer, petrochemicals.

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    6. State the application of job shop production. Also state its merits and

    demerits.

    Ans.

    Number of jobs produced: 01 to 05 only.

    In this production method, a production is as per the customer order.

    At the time period there will be variety in the product.

    As per customer order specification, set up and instruction will be

    changed.

    No requirement of stock storage in this type of production.

    Production is done as per customer order.

    Examples: ship building, casting industries, aircraft industries,

    machine tool manufacturing, process industry equipment.

    Advantages:

    a) Getting more information regarding new technology.

    b) No requirement of inventory control so the cost is reducing.

    c) Skill of worker is increasing.

    Disadvantages:

    a) There are lots of difficulties due to not awareness about new

    technology

    b) A special skilled worker is required.

    c) For every new product a worker has to give special training.

    7. Differentiate between data and information. Also state various types

    of data.8. State and explain features of DBMS.

    Topis-2

    June/July-089. State the type of time series analysis. Explain ay one in brief.

    10. State the various methods to fit a trend line in forecasting. Explain

    any one.

    11.The past date about sales of an item are as follows:

    Months Jan-05 Feb-05 Mar-05 April-05 May-05 June-05Sales

    Volume

    (in lacs)

    25 28 16 19 21 23

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    i. If 3 months moving average is used to forecast the next

    months demand, calculate the forecast of sales in the month of

    July-05.

    ii. Calculate a weighted three months moving average for the

    month of July-05, where the weights are 0.5 for the least

    month, 0.3 and 0.2 for the other months respectively.

    Ans. a). Three months simple moving average:

    21F

    3

    63F

    3

    232119F

    3

    DDDF

    nextmonth

    nextmonth

    nextmonth

    JuneMayAprilnextmonth

    =

    =

    ++=

    ++=

    b).Three months weighted moving average:

    6.21F

    )192.0()213.0()235.0(F

    D)2.0(D)3.0(D)5.0(F

    nextmonth

    nextmonth

    AprilMayJunenextmonth

    =++=

    ++=

    Nov-0612.Explain noise in demand. Explain independent verses dependent

    demand.

    Ans.

    Independent Demand:

    Demand for a material that is independent of the demands for

    other materials. For example, demands for end products are independent

    of demand for parts, raw material or components as their demands are

    determined, by customers outside the organization.

    Dependent Demand:

    Demand for a raw material, part or a component, that is

    dependent on the demand doe the end product in which these materials

    are used.

    13.Explain Mean Absolute Deviation (MAD) and Bias with respect to

    forecasting error.

    Ans.

    Mean Absolute Deviation (MAD):-

    A forecast error measure that is the average

    forecast error without regard to direction, calculated as the

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    sum of absolute value of forecast error for all periods divided

    by the total number of periods evaluated.

    For each period (l), you find the difference between

    the forecasted demand and the actual demand. If your forecast

    was perfect actual demand equals the forecasted demand, and

    the forecast error is zero. As forecasting continues, the forecast

    error is recorded and accumulated, period by period.

    Notice that MAD is an average of the absolute value

    of forecast error; errors are measured without regard to sign

    Mad expresses the magnitude but not the direction

    error. This measure of absolute values is called absolute

    deviation.

    BIAS:-

    A forecast error measure that is the average of

    forecast error with regard to direction and shows any tendencyconsistently to over or under forecast; calculated as the sum of

    actual forecast error for all periods divided by the total

    number of periods evaluated.

    Unlike MAD, BIAS indicates the directional

    tendency of forecast errors. If fewer forecasts repeatedly

    overestimate actual demand BIAS will have a positive value

    consistent under estimates will be indicated by a negative

    value.

    14.With suitable illustration, explain computer aided inventory system.October/Novmeber-0215.The past data about the absenteeism of workers in machine shop are

    as under:

    Months Aug.-

    01

    Sept.-

    01

    Oct.-

    01

    Nov.-

    01

    Dec.-

    01

    Jan.-

    02

    Feb.-

    02

    Mar.-

    02

    Numbers

    of

    workers

    remained

    absent

    18 24 32 35 31 27 21 20

    i. If three month moving average is used to forecast the next

    months absenteeism. Calculate the forecast of absenteeism in

    the month of April-02.

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    ii. Calculate a weighted three moving average for April-02,

    where the weights are 0.55 for the least month, 0.35 and 0.10

    for other months respectively.

    iii. Compare the simple moving average and weighted moving

    average methods.

    Ans. a).Three month moving average:

    67.22F

    3

    68F

    3

    202127F

    3

    DDDF

    nextmonth

    nextmonth

    nextmonth

    MarchFebJannextmonth

    =

    =

    ++=

    ++=

    b). Three month weighted moving average:

    20.24F

    )2010.0()2135.0()2755.0(F

    )D10.0()D35.0()D55.0(F

    nextmonth

    nextmonth

    MarchFebJannextmonth

    =++=

    ++=

    16.Acme engineering is planning to set a new work shop for the

    following 6 jobs. The details of required machining hours and other

    information are produced in the following table:

    Job Machining hours/Job Quantity per

    yearCenterlathe

    CNCLathe

    Drilling Grinding

    A 0.50 0.50 0.10 0.80 2000

    B 0.60 - 0.50 0.20 800

    C 0.10 0.60 - - 6000

    D 0.80 1.20 0.50 0.50 500

    E 1.00 - - 0.20 200

    F 0.30 0.10 0.60 - 100

    Assume following data:

    i. Utilization factor for each machine = 0.85ii. Average efficiency of output on each machine = 0.80

    iii. Number of hours which can be scheduled for each machine

    is 6000 per year.

    Estimate the number of machine of each type.

    Ans.

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    Job Center

    lathe

    CNC lathe Drilling

    machine

    Grinding

    machine

    Quantit

    y per

    year

    A1000

    5.02000

    ==

    1000

    5.02000

    ==

    200

    10.02000

    ==

    1600

    80.02000

    == 2000

    B480

    6.0800

    == -

    400

    50.0800

    ==

    160

    20.0800

    == 800

    C600

    10.06000

    ==

    3600

    60.06000

    == - - 6000

    D

    400

    80.0500

    ==

    600

    20.1500

    ==

    250

    50.0500

    ==

    250

    50.0500

    == 500

    E200

    10.0200

    == - -

    40

    20.0200

    == 200

    F30

    30.0100

    ==

    10

    10.0100

    ==

    60

    60.0100

    == - 100

    Total

    Hours

    2710 5210 910 2050 -

    Actual machining hours for Center Lathe:

    hrs3986

    29.3985

    )80.085.0(

    2710

    =

    =

    No. of Center Lathe:

    1

    66.0

    6000

    3986

    =

    =

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    Actual machining hours for CNC Lathe:

    hrs7662

    76.7661

    )80.085.0(

    5210

    =

    =

    No. of CNC Lathe:

    2

    277.1

    6000

    7662

    =

    =

    Actual machining hours for Drilling machine:

    133924.1338

    )80.085.0(

    910

    =

    =

    No. of Drilling Machine:

    1

    22.0

    6000

    1339

    =

    =

    Actual machining hours for Grinding machine:

    3015

    71.3014

    )80.085.0(2050

    =

    =

    No. of Grinding Machine:

    1

    50.0

    6000

    3015

    =

    =

    Topis-3

    June/July-0817.State the goals of Aggregate Production Planning. Also how the

    interrelations of aggregate production planning with major activities

    of production systems.

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    18.M/s. Pankaj Engineering is planning to establish a new workshop for

    its following additional five jobs. The details of required machining

    hours and other information are given in the table below:

    Job Machining hours Quantity

    per yearCapstanLathe BoringM/c Radialdrill Surfacegrinder Universal

    milling

    M/c

    A 0.4 0.6 - - 0.4 1100

    B 0.3 - 0.7 - 0.3 550

    C 0.5 0.3 0.4 0.4 - 750

    D - - 0.4 0.3 0.5 450

    E 0.7 0.6 - 0.4 - 600

    Take following data:

    i. Utilization factor for each machine is 0.8ii. Average efficiency of output on each = 0.75

    iii. Number of hours which can be scheduled on each machine

    is 4800 per year.

    Estimate the number of machine required of each type.

    Ans.

    Jo

    b

    Machining hours/job Quantit

    y per

    year

    Capstan

    Lathe

    Bring m/c Radial

    Drill

    Surface

    Grinder

    Universal

    millingm/c

    A

    440

    4.01100

    ==

    660

    6.01100

    == - -

    440

    4.01100

    == 1100

    B165

    3.0550

    == -

    385

    7.0550

    == -

    165

    3.0550

    == 550

    C375

    5.0750

    ==

    225

    3.0750

    ==

    300

    4.0750

    ==

    300

    4.0750

    == - 750

    D - -180

    4.0450

    ==

    135

    3.0450

    ==

    225

    5.0450

    == 450

    E420

    7.0600

    ==

    360

    6.0600

    == -

    240

    4.0600

    == - 600

    T

    ot

    al

    h

    o

    1400 1245 865 675 830 -

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    ur

    s

    Actual machining hours for Capstan Lathe:

    2334

    33.2333

    )75.08.0(1400

    =

    =

    No. of Capstan Lathe:

    1

    49.0

    4800

    2334

    =

    =

    Actual machining hours for Boring Machine:

    2075

    )75.08.0(

    1245

    =

    =

    No. of Boring machine:

    1

    43.0

    4800

    2075

    =

    =

    Actual machining hours for Radial drill:

    1442

    67.1441

    )75.08.0(

    865

    =

    =

    No. of Radial drill:

    1

    30.0

    4800

    1442

    =

    =

    Actual machining hours for Surface grinder:

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    1125

    )75.08.0(

    675

    =

    =

    No. of surface grinder:

    1

    23.0

    48001125

    =

    =

    Actual machining hours for Universal milling machine:

    1384

    33.1383

    )75.08.0(

    830

    =

    =

    No. of universal milling m/c:

    1

    28.0

    4800

    1384

    =

    =

    Nov-0619. M/s. Reynolds Pen Industries manufactures gold plate ball point

    pens. The company wants to make an accurate demand forecast

    based on the following information:Month Number of pens

    Forecasting Sales Actual Sales

    January 760 800

    February 750 780

    March 760 700

    April 760 700

    May 900 820

    June 1060 1300

    July 1020 1030August 890 870

    September 920 1200

    October 950 980

    November 1020 980

    December 1500 1700

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    Forecast the demand for next month, based on the above

    information, using.

    a) Three month simple moving average.

    b) Six month simple moving average.

    c) Four month weighted moving average using weights of 0.1, 0.2,

    0.3 and 0.4 for the month of December, October and

    September respectively.

    d) Exponential smoothing using =0.4

    Ans. a).Three months simple average:

    1220F

    33600F

    3

    1700980980F

    3

    DDDF

    nextmonth

    nextmonth

    nextmonth

    DecNovCctnextmonth

    =

    =

    ++=

    ++=

    b). Six months simple moving average:

    1127F

    7.1126F

    6

    6760F

    6

    170098098012008701030F

    6

    DDDDDDF

    nextmonth

    nextmonth

    nextmonth

    nextmonth

    DecNovOctSeptAugJuly

    nextmonth

    =

    =

    +++++=

    +++++=

    c). Four month moving average:

    1140F

    )12004.0()9803.0()9802.0()17001.0(F

    D)4.0(D)3.0(D)2.0(D)1.0(F

    nextmonth

    nextmonth

    SeptOctNovDecnextmonth

    =+++=+++=

    d). Exponential Smoothing:

    1580F

    )1500)(4.01()1700(4.0F

    )F)(1()D(F

    nextmonth

    nextmonth

    DecDecnextmonth

    =+=+=

    October/Novmeber-02

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    20.Unique engineering has 8 jobs on hand today. Job consists milling

    and drilling operations. The time estimates for the job are as follows.

    (in minutes)

    Job 1 2 3 4 5 6 7 8

    Milling 35 15 35 10 12 10 16 8Drilling 15 55 65 15 18 20 22 5

    Sequence them so as to complete all the jobs in minimum time.

    Calculate this minimum time. Johnsons rule is to be used for this

    case.

    Ans.

    In M/c-1 and M/c-2 minimum time for Job 8 for M/c-2 so taken Job 8

    last.

    8

    Compare the other than Job 8 minimum time for Job 4 for M/c-1 so taken

    Job 4 in first.

    4 8

    Compare the other than Job 4 minimum time for Job 6 for M/c-1 so taken

    Job 6 at second position.

    4 6 8

    Compare the other than Job 6 minimum time for Job 5 for M/c-1 so takeJob 5 at third position.

    4 6 5 8

    Compare the other than Job 5 minimum time for Job 2 for M/c-1 so take

    Job 2 at third position.

    4 6 5 2 8

    Compare the other than Job 2 minimum time for Job 1 for M/c-2 so take

    Job 1 at second last.

    4 6 5 2 1 8

    Compare the other than Job 1 minimum time for Job 7 for M/c-1 so take

    Job 7 at third position and Job 3 at fourth position.

    4 6 5 2 7 3 1 8

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    Job Milling Drilling

    4 10 15

    6 10 20

    5 12 18

    2 15 557 16 22

    3 35 65

    1 35 15

    8 8 5

    Total 141 215

    Job Milling Drilling Idle time on

    milling

    Idle time on

    drillingTime

    in

    Time

    out

    Time

    in

    Time

    out

    00 00

    4 00 10 10 25 00-00=00 10-00=10

    6 10 20 25 45 10-10=00 25-25=00

    5 20 32 45 63 20-20=00 45-45=00

    2 32 47 63 118 32-32=00 63-63=00

    7 47 63 118 140 47-47=00 118-118=00

    3 63 98 140 205 63-63=00 140-140=00

    1 98 133 205 220 98-98=00 205-205=00

    8 133 141 220 215 133-133=00 220-220=00

    Total 141 215 00 10

    Milling operation time = 141hours

    Drilling operation time = 215hours

    Total time = 215hours

    Idle processing time on milling = 00hours

    Idle processing time on drilling = 10 hours

    OR

    Job waiting to be processed at grinding shop today is as follow.

    Job A B C D E F G

    Time

    remaining

    for due

    date of

    6 10 25 11 9 6 9

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    job (days)

    Time

    needed to

    complete

    the job(days)

    8 12 20 10 8 8 10

    Sequence the jobs at grinding shop based on minimum critical ratio.

    21.Write brief note on Master production schedule (MPS).

    Ans.

    This is the schedule of the quantity and timing of all end

    products to be produced over a specific planning horizon. MPS is

    developed from customers firm orders or from forecast of demand or

    both. It is an input of the MRP system.

    The MPS specifies what end products are to be produced andwhen. The planning horizon should be long enough to cover the

    cumulative lead times of all components must be purchased or

    manufactured to meet the end product requirements.

    22.How material requirement planning (MRP) is useful in production

    management.

    23.Explain Manufacturing resource planning (MRP II).

    Ans. When the capabilities of closed-loop MRP (Material

    Requirement Planning) are extended to integrate financial, accounting,

    personnel, engineering and marketing information along with the

    production planning and control activities of the basic MRP system, the

    resulting broad-based resource-coordination system is known as

    manufacturing resource planning or MRP-II. It is the heart of the

    corporate management information system for many companies, as it

    provides information about inventory investment levels, plant expansion

    needs, and work-force requirements, which is useful for coordinating

    marketing, financial, engineering and manufacturing efforts to achievethe companys overall business plans.

    The projection of what materials and components will be

    purchased and when, can be used to develop purchase commitments and

    a projected purchasing budget. The labour hours projected in the capacity

    requirement plan for each work center can be aggregated to develop

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    personnel needs and labour budgets. The projected on-hand inventory of

    material ca be used to develop inventory budgets.

    24.State scheduling techniques. Explain any one.

    Topis-4

    June/July-0825. State the function of Enterprise Resource Planning (ERP). Also state

    the advantage of ERP.

    OR

    Describe critical Ratio scheduling with a suitable example.

    26. Write a brief note on Master Production schedule. (Same as 21)

    OR

    Discuss the usefulness of Material Requirement Planning inproduction management. (Same as 22)

    27.M/s. Pankaj Industries have six jobs on hand; job consists mainly of

    turning and grinding operations. The time estimates for jobs in

    minutes are as follows:

    Jobs 1 2 3 4 5 6

    Operation

    Turning 26 19 16 29 30 49

    Grinding 10 19 09 24 17 33

    Arrange all jobs in a sequence so as to finish them in a minimum

    possible time. Calculate the minimum time using Johnsons rule.

    Ans.

    In m/c-1 and m/c-2 minimum time for 3 for m/c-2 take Job3 last.

    3

    Compare the other than Job3 minimum time for Job1 for m/c-2 so

    taken Job1 second last.

    1 3

    Compare the other than Job1 minimum time for Job5 for m/c-2 so

    taken Job5 third last.

    5 1 3

    Compare the other than Job5 minimum time for Job2 for m/c-1 so

    taken Job2 first.

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    2 5 1 3

    Compare the other than Job2 minimum time for Job4 for m/c-2 so

    taken Job4 at third position and Job 6 at second position.

    2 6 4 5 1 3

    Job Turning Grinding

    2 19 19

    6 49 33

    4 29 24

    5 30 17

    1 26 10

    3 16 09

    Total 169 112

    Job m/c-1

    (turning)

    m/c-2

    (grinding)

    Idle time on

    milling

    Idle time on

    drilling

    Time

    in

    Time

    out

    Time

    in

    Time

    out

    00 00

    2 00 19 19 38 0-0=0 19-0=19

    6 19 68 38 71 19-19=0 38-38=04 68 97 71 95 68-68=0 71-71=0

    5 97 127 95 112 97-97=0 95-95=0

    1 127 153 112 122 127-127=0 112-112=0

    3 153 122 153-153=0 122-122=0

    Total 169 112 00 19

    Turning operation time = 169hrs

    Grinding operation time = 112hrs

    Total time = 169hrsTurning idle time = 00hrs

    Grinding idle time = 19hrs

    Nov-0628. State the goals of Aggregate Production Planning.

    Or

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    Explain the strategies of Aggregate Production Planning.

    29. Explain the meaning and method of Capacity Requirement Planning

    (CRP), taking a suitable case example. Also state importance of CRP.

    October/Novmeber-02

    30.M/s. Sona enterprise is a bearing dealer. They deal almost for 100types and sizes of bearings. They have following data with them. The

    management is interested to have balance stock, inventory, and

    profit online.

    i. Type of bearing (for e.g., ball, needle, roller, etc.....)

    ii. Code (Maximum 10 digits, alpha-numeric).

    iii. Stock.

    iv. Receipts.

    v. Sales.

    vi. Purchase price of each bearing.

    vii. Sales price of each bearing.Prepare following:-

    a) List user input fields, its type, and width.

    b) Data model using bubble chart and tree structure.

    c) System design consideration.

    d) Steps to design system.

    Assume (1). Any one database software.

    (2). Balance stock = Stock + Receipts Sales

    (3). Inventory = Balance stock of each item x purchase price

    of each.(4). Profit = (Sales price of each item purchase price of

    each item) x quantity sold of each item.

    Topis-5

    June/July-0831.Difference between data and information with suitable example.

    32.List the application software available for RDBMS. State the

    features and system requirements for any ONE.

    ORExplain bubble chart.

    33.Define DBMS. Explain its importance in Production Management.

    OR

    List the objectives of database organization. What are the benefits of

    database organization?

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    34.In toolcrib of M/s. Deepti Enterprise, the database of tool issues is

    required to be maintained. Following information is available.

    i. Name of tool.

    ii. Code of tool (assume 10 digit code)

    iii. Date of issue.

    iv. Date of receipts back of tool.

    v. Tool issued to operator (use 6 digit code for operator number)

    Prepare the database for the following:

    a) List the user input fields, its type and width.

    b) System design consideration.

    c) Steps in system design (assume any one suitable database

    software).

    d) Retrieval for the following query:

    1) A specific tool issued to whom?

    2) Which tool is with a specific operator?3) Number of days an operator has kept the tool.

    Ans.

    SQL> Create table assembly(Compo varchar2 (30),Code_compo

    number,issue_date date,assembly_date date, fitter_number number(6))

    If any error occurs then use the below command

    SQL>Ed (and then modify the error)

    SQL>/

    Table Created

    SQL>select* from assembly;

    No rows selected.

    SQL> insert into assembly(Compo,

    Code_compo,issue_date,assembly_date,fitter_number)values(gear,101,

    07-may-2009,12-may-2009,1001);

    SQL> Select fitter_number,compo from assembly where compo=gear;

    Nov-0635. State the advantages and limitations of Material Requirement

    Planning (MRP).36.Outline the purposes of MRP and explain how an MRP system can

    achieve these purposes.

    37.Explain the role of Master Production schedule and how it relates to

    the other elements of an MRP system.

    38.MRP-II as an integrated system of planning and control: explain.

    October/Novmeber-02

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    Repeated Question: 32 (or)39.Write the short note on Fitting trendline methods.

    40.Write the short note on Production Plans.

    41. Write the short note on Communication Protocols.

    Ans. The term protocols refer to the set of procedures that must be

    followed so that the communicating agent can perform their exchange in an

    orderly manner. The protocol comprises the set of rules for operating a data

    communication system.

    A well-defined protocol is essential for data exchanges. The two

    common types of protocols are:-

    The polling techniques, such as token passing;

    The collisions detect technique, such as carrier sense multiple access

    collision detect.

    42.Write the short note on Information flow in capacity requirementplanning.

    43.Write the short note on Factors influencing productivity and quality

    their effects and way to improve.

    Topis-6

    June/July-08

    Repeated Question: 4144.Explain the importance of a well managed information system in

    improving productivity.45.Explain Decision Support System (DDS) in brief.

    Ans.

    DDS is component of MIS (Management Information System).

    Decision Support System that may help managers extracts essential data

    from other systems and then apply data analysis and decisions procedures to

    the retrieved data to make unstructured decisions is another MIS component.

    DDS often uses mathematical or graphical analysis software to

    help managers deal with questions that cant be answered by the reports

    produced by operational/tactical support systems.46.Explain the features of any information system with a suitable

    example.

    Nov-0647.Sonal Auto Products Ltd. has five jobs that are to be processed

    though two machines sequentially. The processing time for these jobs

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    at both the machines 1 and 2 are given below. What sequence of jobs

    will minimize both total completion time and idle processing time?

    Job timings for two machines:

    Job Machine - 1 Machine - 2

    A 2 4B 7 8

    C 5 6

    D 6 7

    E 3 3

    Ans.

    In m/c-1 and m/c-2 minimum time for Job A for m/c-1 so taken Job A first.

    A

    Compare other than Job A. Minimum time for Job E for m/c-2 so take Job E

    last.

    A E

    Compare other than above Jobs Job C minimum time for m/c-1 so takes it on

    second.

    A C E

    Compare other than above Jobs. Job D has minimum time on m/c-1 so take

    Job D on number 3 position and Job B on number 4 positions.

    A C D B E

    Job M/c-1 M/c-2

    A 2 4

    C 6 6

    D 5 7

    B 7 8

    E 5 3

    Total 25 28

    Job M/c-1 M/c-2 Idle time on

    M/c-1

    Idle time on

    M/c-2Time

    in

    Time

    out

    Time

    in

    Time

    out

    00 00

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    A 00 02 02 06 0-0=00 02-00=02

    C 02 07 06 12 02-02=00 06-06=00

    D 07 13 12 19 07-07=00 12-12=00

    B 13 20 19 27 13-13=00 19-19=00

    E 20 25 27 30 20-20=00 27-27=00Total 25 30 00 02Now M/c-1 processing time = 25hours

    M/c-2 processing time = 30hours

    Total completion time = 30hours

    Idle processing time for m/c-1 = 00hours

    Idle processing time for m/c-2 = 02hours

    48.M/s. Seema enterprise is a well known management consultant who

    specializes in developing management information systems forproduction facilities. Currently, M/s. Seema enterprise has 6 data

    processing jobs, each of which requires flow charting and writing of

    the actual computer program. Seema enterprise wants to complete

    the jobs within 36 hours. Given the following processing times.

    Job Flow Charting Time

    (hrs.)

    Program Writing

    Time (hrs.)

    A 9 1

    B 8 3

    C 5 4D 7 11

    E 6 8

    F 2 9

    Use Johnsons method to determine whether M/s. Seema enterprise

    can meet 36 hours processing time.

    Ans.

    In flow chart and program writing minimum time for Job A for program

    writing so take Job A last.

    A

    Compare the other than Job A minimum time for Job F for flow chart s

    take Job F first.

    F A

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    Compare the other than Job F minimum time for Job B for program

    writing so take Job B in second last.

    F B A

    Compare the other than Job B minimum time for Job C for programwriting so take Job C in third last.

    F C B A

    Compare the other than Job C minimum time for Job E for flow chart so

    take Job E in second position and Job D in third position.

    F E D C B A

    Job Flow charting time

    (hrs.)

    Program writing Time

    (hrs.)

    F 2 9E 6 8

    D 7 11

    C 5 4

    B 8 3

    A 9 1

    Total 37 36

    Job Flow charting

    time

    Program

    writing time

    Idle time in

    flow chart

    Idle time in

    programwriting.Start

    time

    Ending

    time

    Start

    time

    Ending

    time

    00 00

    F 00 02 02 11 00-00=00 02-00=02

    E 02 08 11 19 02-02=00 11-11=00

    D 08 15 19 30 08-08=00 19-19=00

    C 15 20 30 34 15-15=00 30-30=00

    B 20 28 34 37 20-20=00 34-34=00

    A 28 37 37 38 28-28=00 37-37=00

    Total 37 38 00 02

    Now flow charting processing time = 37hours.

    Program writing processing time = 38hours.

    Total completion time = 38hours

    Idle processing time in flow chart = 00hours.

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    Idle processing time in program writing = 02hours.

    Topis-7

    October/Novmeber-02

    Repeated Question: 32, 33, 3449.Define RDBMS and list the software of RDBMS.

    Topis-8

    October/Novmeber-02

    Repeated Question: 41, 4550. Differentiate between data and information. State the various types

    of data.

    51.Communication media: short note.