Rigidez Segun GERE
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Transcript of Rigidez Segun GERE
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1 2 3
SECCIONESB H B H B H
60 120 50 100 40 80
INERCIA(I)-CM4 8640000 4166666.66666667 1706666.66666667LONGITUD(L)- CM 1200 1000 800
RELACION(I/L =R) 7200 4166.6666666667 21 .
E= 15000!"#C$1/2- %G/CM2 217 70.6511&2842
AD800000
AD-ADL08000
-600000 828000-1000000 -1000000
ADL-2508000-1428000
0
% 4E(R1'R2) 2E(R2) 0 &88 118&40.&012 18114220& .27 682E(R2) 4E(R2'R ) 2E(R ) = 18114220& .27 68 5477740410.05&61
0 2E(R ) 4E(R ) 0 &27448111.756124
0.000000000108 58 -0.0000000000 &147-0.0000000000 &147 0.00000000021 580.00000000001&57 -0.0000000001067&2
D =0.000 064602&8654
(AD-ADL) = 0.00015414210678& =-0.0006161847716 1
$( 1)=
$
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GL=
0&27448111.75612418548&622 .51225
0.00000000001&57-0.0000000001067&20.0000000005&2510
0.01755884060.0088 16715
-0.0 5 04704
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1 2
SECCIONESB H B H
50 100 50 100
INERCIA(I)-CM4 4166666.66666667 4166666.66666667
LONGITUD(L)- CM 500 500
RELACION(I/L =R) 8 . 8 .
E= 15000!"#C$1/2- %G/CM2 217 70.6511&2842
AD0
AD-ADL00
ADL14400000-&600000
0
% 4E(R1) 2E(R1) 02E(R1) 8E(R1) 2E(R1) =
0 2E(R1) 4E(R1)
D = (AD-ADL) =
$( 1)=
$( 1)
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3B H GL=0 0
0
800
0
-14400000&600000
0
7245688 7 .0&472 622844186.547 6 0622844186.547 6 144&1 76746.18&4 622844186.547 6
0 622844186.547 6 7245688 7 .0&472
0.000000000161015 -0.000000000046004 0.00000000002 002-0.000000000046004 0.0000000000&200& -0.0000000000460040.00000000002 002 -0.000000000046004 0.000000000161015
-0.0027602622 7 6& -0.15815100670.001545746852&27 = 0.08856456 8
-0.00077287 42646 -0.044282281&
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1 2
SECCIONESB H B H
50 100 50 100
INERCIA(I)-CM4 4166666.66666667 4166666.66666667
LONGITUD(L)- CM 500 500
RELACION(I/L =R) 8 . 8 .
E= 15000!"#C$1/2- %G/CM2 217 70.6511&2842
AD0
AD-ADL00
ADL14400000-&600000
0
% 4E(R1) 2E(R1) 02E(R1) 8E(R1) 2E(R1) =
0 2E(R1) 4E(R1)
D = (AD-ADL) =
$( 1)=
$( 1)
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3B H GL=0 0
0
800
0
-14400000&600000
0
7245688 7 .0&472 622844186.547 6 0622844186.547 6 144&1 76746.18&4 622844186.547 6
0 622844186.547 6 7245688 7 .0&472
0.000000000161015 -0.000000000046004 0.00000000002 002-0.000000000046004 0.0000000000&200& -0.0000000000460040.00000000002 002 -0.000000000046004 0.000000000161015
-0.0027602622 7 6& -0.15815100670.001545746852&27 = 0.08856456 8
-0.00077287 42646 -0.044282281&
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0.41666667 0.080.08 0.41666667
2.5 -0.5 - 2
-0.5 2.5 .
-&6.665&&. 25
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TRAMOS O ELEMENTOS 1SECCIONES
B H B0. 0.7 0.
INERCIA(I)-CM4 0.008575 0.00LONGITUD(L)- CM 4
RELACION(I/L =R) 0.00214 75 0.001
E= 15000!"#C$1/2- %G/CM2 217 70.6511&2842 1410000
1
GH = 6 GL=
D =
2AD =
ADL =
AD - ADL =
% =
GIROS =
DE"INIENDOEL SENTIDODE GIRO EN"UNCION AL
GL
1 2
1
A2
AA
1A
2
1 2
11 1 2 * 1
21 22 * 2
1 ( 2 )
$(1)
=
+( 0 @) 1
2
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12= ( 12) 12 0)4 / ( '(2 12) 12 / ( 1)
21= ( 21) 21 0)2 / ( '(4 21) / 21 ( 1)
2 = ( 2 ) 2 1)4 / ( '(2 2 ) / 2 ( 2)
2= ( 2) 2 1)2 / ( '(4 2) / 2 ( 2)
4= ( 4) 4 2)4 / ( '(2 4) / 4 ( )
4 = ( 4 ) 4 2)2 / ( '(4 4 ) / 4 ( )
45= ( 45) 45 )4 / ( '(2 45) / 45 ( 4)
54= ( 54) 54 )2 / ( '(4 54) / 54 ( 4)
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3 4H B H B H0.7 0. 0.7 0. 0.7
575 0.008575 0.0085758 5
71875 0.001071875 0.001715
0= 0
0
-4= 16
-16
4= -16
16
181 6.125 022.6875 0= 022.6875 120&0.75 022.6875
0 022.6875 15717.&75
5.766252E-005 -1.514 7E-005 2.&12248E-006-1.514 7E-005 &.086215E-005 -1.747 5E-005
2.&12248E-006 -1.747 5E-005 6.6&8171E-005
0 , , 30.00051&5451 3 0.02&767672&-0.0017& &45 3 -0.1027852 84
0.001 62& 2 3 0.0780&008 70 , , 3
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.1408450704
6.2816&01408
-2.2816&01408
-&.274647887
-6.725 521127
2.816&014085
1 .18 0&85&2
6.5&154&2&58
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TRAMOS O ELEMENTOS 1 2 3 MODULO DE EL
SECCIONESB H B H B H E= 15000!"#C$
0.6 1.2 0.5 1 0.4 0.8
INERCIA(I)-M4 0.0864 0.0416666667 0.0170666667LONGITUD(L)- M 12 10 8
RELACION(I/L =R) 0.0072 0.0041666667 0.0021
E 217 706.511&2842
TERMINACION DE GRADO DE LIBERTAD: GIRO EN LOS NUDGL= R- = 6- =
DEFINICION DE LOS SENTIDOS DE GIRO DE LAS DEFORMACIONES ANGULARES, ASOCIADO AL GRADO DE LIBERTAD
MOMENTOS EXISTENTES EN LOS NUDOS DE LA ESTRUCTURA REAL8
= -6-10
MOMENTO DE EMPOTRAMIENTO PERFECTO EN LOS TRAMOS O ELEMENTOS-25.08-14.28
L= 12 L= 10 L= 8 H
:;8 1(
@2@ )<
:D
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0.08
= 8.28-10
MATRIZ DE RIGIDEZ&88 1.18&40& 18114.220& 0
= 18114.220& 54777.404101 &274.48111760 &274.4811176 18548.&622 5
MATRIZ INVERSA1.08 576E-005 - .&1465E-006 1.&57 26E-006- .&1465E-006 2.1 58 4E-005 -1.067&2E-005
1.&57 26E-006 -1.067&2E-005 0.00005&251DETERMINANDO LOS ANGULOS DE GIRO
0 , , 30.000 06460 3
= 0.0001541421 3-0.0006161848 3
MOMENTOS POR TRAMOS EN LA ESTRUCTURA
&.5&2628 544
1&.18525670&
1 .8&474 2&1
11.1 5617&12
12= ( 12) 12 0)4 / ( '( 12) 12 1)2 / ( =2E 1( 0 1)2 +
21= ( 21) 21 0)2 / ( '( 21) 21 1)4 / ( =2 1 0' 1)E ( 2
2 = ( 2 ) 2 1)4 / ( '( 2 ) 2 2)2 / ( =2 E 2( 2 1 + 2)
2= ( 2) 2 1)2 / ( '( 2) 2 2)4 / ( =2 E 2 ( 1' 2 2)
)<
= 1
2
)<
4 )< =
( <
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-2.855617&117
-10
REACCIONES
= '( 4) 4 )2 / ( =2 E ( 2 2 + )
4 = ( 4 ) 4 2)2 / ( '( 4 ) 4 )4 / ( =2 E ( 2' 2 )
=(_)/2
=(_)/2
=( $2_ ( )) $3 + /
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STICIDAD CONCRETO/2 ! 10 T/M2
= 1.2 9 B =0.60 = 1.0 9 B =0.50
= 0.8 9 B =0.40
/11 >? /10≤ @
$ )/12( .
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=( $2_ ' )) $( 3 /
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TRAMOS O ELEMENTOS 1 2SECCIONES
B H B H0. 0.6 0. 0.6
INERCIA(I)-CM4 0.0054 0.0054LONGITUD(L)- CM 6 6
RELACION(I/L =R) 0.000& 0.000&
E= 1580000
1
GH = 6 GL=
D =
2AD = =
ADL = =
AD - ADL = =
% = =
GIROS =
DE"INIENDOEL SENTIDODE GIRO EN"UNCION AL
GL
1 2
1A 2A A
1A
2
1 2
11 12 * 1
21 22 * 2
1 ( 2 )
$(1)
=
+ (0 @) 1
2
:{
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= 4 ( ( 12) 12 1)2 / ( =2E 1 (2 0 ' 1 ) 21= ( 21) 21 0)2 / ( '( 21) 21 1)4 / ( =2E 1 ( 0 '2 1 )
2 = ( 2 ) 2 1)4 / ( '( 2 ) 2 2)2 / ( =2E 2 (2 1 ' 2 )
2= ( 2) 2 1)2 / ( '( 2) 2 2)4 / ( =2E 2 ( 1 '2 2 )
4= ( 4) 4 2)4 / ( '( 4) 4 )2 / ( =2E (2 2 ' )
4 = ( 4 ) 4 2)2 / ( '
( 4 ) 4 )4 / (
=2E
( 2
'2
)
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000
65.25
-11.25
-6-5.25
11.25
5688 2844 0
2844 11 76 28440 2844 5688
0.0002051102 -5.8602&E-005 2.& 0145E-005-5.8602&E-005 0.0001172058 -5.8602&E-005
2.& 0145E-005 -5.8602&E-005 0.0002051102
0 , , 3-0.0005& 544 3-0.000&22&&58 3
0.0024 & 46 3
D
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-6
-6.& 75
1.6875
11.25