Phuong Trinh Vi Phan Cap 2

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Phuong Trinh Vi Phan Cap 2

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  • Trng i hc Bch khoa tp. H Ch MinhB mn Ton ng dng

    -------------------------------------------------------------------------------------

    Gii tch 1

    Chng 4.

    Phng trnh vi phn tuyn tnh cp 2

    H phng trnh vi phn tuyn tnh cp mt.

    Ging vin Ts. ng Vn Vinh (11/2008)

    [email protected]

  • Ni dung---------------------------------------------------------------------------------------------------------------------------

    I Phng trnh vi phn tuyn tnh cp 2 tng qut.

    III- H phng trnh vi phn tuyn tnh cp 1.

    II Phng trnh vi phn tuyn tnh h s hng.

  • I. Phng trnh vi phn tuyn tnh cp 2

    nh ngha phng trnh khng thun nht

    Phng trnh vi phn tuyn tnh cp hai khng thun nht

    '' '( ) ( ) ( ), (1)y p x y q x y f x

    trong l cc hm lin tc.( ), ( ), ( )p x q x f x

    nh ngha phng trnh thun nht

    Phng trnh vi phn tuyn tnh cp hai thun nht

    '' '( ) ( ) 0, (2)y p x y q x y

    trong l cc hm lin tc.( ), ( )p x q x

  • I. Phng trnh vi phn tuyn tnh cp 2

    0tq ry y y

    Cu trc nghim ca phng trnh khng thun nht

    l nghim tng qut ca pt khng thun nht.tqy

    l nghim tng qut ca pt thun nht.0y

    l nghim ring ca pt khng thun nht.ry

  • Tp hp cc nghim ca phng trnh thun nht l

    khng gian 2 chiu: 0 1 1 2 2( ) ( )y c y x c y x

    l nghim ring ca pt thun nht (2)1( )y x

    ' ' '

    2 1 1 ;y y u y u

    Tm nghim th hai dng: 2 1( ) ( )y y x u x

    '' '' ' ' ''

    2 1 1 12y y u y u y u

    '' ' ' '' ' '1 1 111 1 02 y up qy u yy y uu yuu

    '' ' '' ' '1 1 1 1 1 12 0y py qy u y u y py u '' ' '1 1 12 0y u y py u

    t , c phng trnh tch bin'z u ' '1 1 12 0y z y py z ( )

    21 ( )

    p x dxeu dx

    y x

    ( )

    2 1 21

    ( ) ( )( )

    p x dxey x y x dx

    y x

  • I. Phng trnh vi phn tuyn tnh cp 2

    Tm nghim ring ca (1) bng phng php bin thin

    hng s:1 1 2 2( ) ( ) ( ) ( )ry c x y x c x y x

    ' ' ' ' '

    1 1 1 1 2 2 2 2( ) ( ) ( ) ( ) ( ) ( )ry C x y C x y x C x y C x y x

    '' '' ' ' ' ' ' '' '' ' ' ' ' ''

    1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2ry C y C y C y C y C y C y C y C y

    Thay vo pt (1):'' '( ) ( ) ( )r r ry p x y q x y f x

    ' '

    1 1 2 2

    ' ' ' '

    1 1 2 2

    0

    ( )

    C y C y

    C y C y f x

    Gii h tm .' '1 2,C C

    Suy ra .1 2( ), ( )C x C x

    Nghim ring: ry Nghim tng qut ca (1): 0tq ry y y

  • ch cn tm mt nghim ring ca pt thun nht.1( )y x

    KT LUN:

    gii phng trnh '' '( ) ( ) ( )y p x y q x y f x

    T nghim suy ra:( )

    2 1 2

    1

    ( ) ( )( )

    p x dxey x y x dx

    y x

    1( )y x

    Tm nghim 1 1 2 2( ) ( ) ( ) ( )ry c x y x c x y x

    ' '

    1 1 2 2

    ' ' ' '

    1 1 2 2

    0

    ( )

    C y C y

    C y C y f x

    1 2( ), ( )C x C x ry

    Nghim tng qut ca pt khng thun nht:0tq ry y y

  • V d Gii phng trnh 2 '' ' 34 (1)x y xy y x

    Phng trnh thun nht: '' '2

    1 10 (2)y y y

    x x

    on mt nghim ring ca pt thun nht: 1( )y x x

    Tm nghim ring th hai ca (2):

    ( )

    2 1 2

    1

    ( ) ( )( )

    p x dxey x y x dx

    y x

    1

    2

    dxxe

    x dxx

    Phng trnh chun: '' '2

    1 14y y y x

    x x

    lnx x

    Tm nghim ring ca pt (1) bng PP bin thin hng s

    Trong bi ny ta on c: 3y x

    Nghim tng qut ca (1): 0 1 23ln | |rtq y C xy C x x xy

  • V d Gii phng trnh '' 'tan 2 0y x y y

    on mt nghim ring: 1( ) siny x x

    Tm nghim ring th hai ca (2):

    ( )

    2 1 2

    1

    ( ) ( )( )

    p x dxey x y x dx

    y x

    tan

    2sin

    sin

    xdxex dx

    x

    V d Gii phng trnh'' '

    2 2

    2 20

    1 1

    x yy y

    x x

    on mt nghim ring: 1( )y x x

    Tm nghim ring th hai ca (2):

    ( )

    2 1 2

    1

    ( ) ( )( )

    p x dxey x y x dx

    y x

    2

    2

    1

    2

    xdx

    xex dx

    x

  • II. Ptrnh vi phn tuyn tnh cp 2 h s hng

    nh ngha phng trnh khng thun nht h s hng

    Phng trnh vi phn tuyn tnh cp hai l phng trnh

    '' ' ( ), (1)y py qy f x

    trong l hng s, v f(x) l hm lin tc.,p q

    nh ngha phng trnh thun nht h s hng

    Phng trnh vi phn tuyn tnh cp hai l phng trnh'' ' 0, (2)y py qy

    trong l cc hng s.,p q

  • Gii phng trnh thun nht: '' ' 0, (2)y py qy

    Phng trnh c trng: 2 0k pk q

    TH 1: PTT c hai nghim thc phn bit1 2,k k

    TH 2: PTT c mt nghim kp0k

    Nghim tng qut: 1 20 1 2

    k x k xy C e C e

    Nghim tng qut: 0 00 1 2

    k x k xxy C e C e

    TH 3: PTT c mt nghim phc1k a bi

    Nghim tng qut: 0 1 2cos sinaxy e C bx C bx

  • Tm nghim ring ca phng trnh khng thun nht

    Trng hp chung: Phng php bin thin hng s.

    Xt hai trng hp c bit:

    TH 1: , Pn(x) l a thc bc n.( ) ( )x

    nf x P x e

    Tm dng: ( )s x

    r ny x e Q xry

    s = 0, nu khng l nghim ca pt c trng.

    s = 1, nu l nghim n ca pt c trng.

    s = 2, nu l nghim kp ca pt c trng.

    l a thc cng bc vi cc h s cn tm.( )nP x( )nQ x

    tm cc h s ny, thay vo pt (1).ry

  • TH 2: ( ) ( )cos ( )sinx n mf x e P x x Q x x

    Tm dng: ( )cos ( )sins xr k ky x e H x x T x x ry

    s = 0, nu khng l nghim ca pt c trng.i

    s = 1, nu l nghim n ca pt c trng.i

    : hai a thc bc vi cc h s cn tm.max{ , }k m n,k kH T

    tm cc h s ny, thay vo pt (1):ry

    '' ' ( )r r ry py qy f x

    V sinx v cosx c lp tuyn tnh nn cc h s tng

    ng bng nhau.

  • Ch :1) C nguyn l cng dn (chng cht) nghim:

    '' '

    1 2( ) ( ) ( )y py qy f x f x f x

    nghim ring ca (1) c dng1 2r r r

    y y y

    nghim ring ca pt:1r

    y '' '1( )y py qy f x

    nghim ring ca pt:2r

    y '' '2( )y py qy f x

    2) l trng hp 1:( ) ( )nf x P x0( ) ( )x nf x e P x

    3) l trng hp 2:( ) ( )cosnf x P x x

    0( ) ( )cos 0sinx nf x e P x x x

  • V d Gii phng trnh '' '5 6 xy y y e

    ( )s xr ny x e Q x

    Phng trnh c trng: 2 5 6 0k k 1 22 3k k

    Nghim tng qut ca pt thun nht: 2 30 1 2x xy C e C e

    ( ) ( )x xnf x e P x e bc 0.1, ( )nP x

    1, ( )nQ x A (v Pn bc 0)

    s = 0, v khng l nghim pt c trng.1

    0 x x

    ry x e A Ae ' '',x xr ry Ae y Ae

    '' '5 6 xr r ry y y e 5 6x x x xAe Ae Ae e

    1

    12A

    Klun: Nghim t/qut: 0tq ry y y 2 3

    1 2

    1

    12

    x x xC e C e e

  • V d Gii phng trnh '' 24y y x

    ( )s xr ny x e Q x

    Phng trnh c trng: 2 4 0k 1 22 2k i k i

    Nghim t/qut ca pt th/nht: 00 1 2cos2 sin 2xy e C x C x

    2 0( ) ( ) xnf x x P x e bc 2.0, ( )nP x

    20, ( )nQ x Ax Bx C (v Pn bc 2)

    s = 0, v khng l nghim pt c trng.0

    0 0 2 2xry x e Ax Bx C Ax Bx C ' ''2 , 2r ry Ax B y A

    '' 24r ry y x 2 22 4( )A Ax Bx C x

    1 1, 0,

    4 8A B C

    Nghim t/qut: 0tq ry y y 2

    1 2

    1 1cos2 sin 2

    4 8C x C x x

  • V d Gii phng trnh '' '2 3y y x

    ( )s xr ny x e Q x

    Phng trnh c trng: 2 2 0k k 1 20 2k k

    Nghim t/qut ca pt th/nht:0 2

    0 1 2

    x xy C e C e

    0( ) 3 ( ) xnf x x P x e bc 1.0, ( )nP x

    0, ( )nQ x Ax B (v Pn bc 1)

    s = 1, v l nghim n pt c trng.0

    1 0 2xry x e Ax B Ax Bx ' ''2 , 2r ry Ax B y A

    '' '2 3ry y x 2 2(2 ) 3A Ax B x 3 3

    ,4 4

    A B

    Nghim t/qut: 0tq ry y y 2

    1 2

    3 3

    4 4

    xC C e x

  • V d Gii phng trnh '' '2 2 xy y y e

    ( )s xr ny x e Q x

    Phng trnh c trng: 2 2 1 0k k 1 2 1k k

    Nghim t/qut ca pt th/nht: 0 1 2x xy C e C ex

    1( ) 2 ( )x xnf x e P x e bc 0.1, ( )nP x

    1, ( )nQ x A (v Pn bc 0)

    s = 2, v l nghim kp pt c trng.1

    22 x x

    ry x e A Ax e ' 2 '' 2(2 ), (2 4 )x xr ry Ae x x y Ae x x

    '' '2 2 xr r ry y y e 3 3

    ,4 4

    A B

    Nghim t/qut: 0tq ry y y 2

    1 2

    3 3

    4 4

    xC C e x

  • V d Gii phng trnh '' '4 3 sin 2y y y x

    ( )cos2 ( )sin 2s xr k ky x e T x x H x x

    Nghim t/qut ca pt th/nht:3

    0 1 2

    x xy C e C e

    0( ) (0.cos2 sin 2 )xf x e x x

    bc 0.0, 2, ( ), ( )n mP x Q x

    0, ,k kT A H B

    s = 0, v khng l nghim pt c trng.2i i

    Phng trnh c trng: 2 4 3 0k k

    max{ , } 0k m n

    1 21 3k k

  • cos2 sin 2ry A x B x

    ' ''2 sin 2 2 cos2 , 4 cos2 4 sin 2r ry A x B x y A x B x

    '' '4 3 sin 2r r ry y y x

    Nghim t/qut: 0tq ry y y 3

    1 2

    8 1cos2 sin 2

    65 65

    x xC e C e x x

    cos2 si

    2 si4

    3 si

    n 2

    n 2

    4 cos

    n

    2 2 co

    2

    4 in 2 s2s A x B

    A x

    A xx B x

    B x x

    ( 8 )cos2 (8 )sin 2 sin 2A B x A B x x

    8 0

    8 1

    A B

    A B

    8 1,

    65 65A B

    8 1cos2 sin 2

    65 65ry x x

  • ( )cos ( )sins xr k ky x e T x x H x x

    Nghim t/qut ca pt th/nht: 00 1 2cos sinxy e C x C x

    0( ) (cos 0.sin )xf x e x x

    bc 0.0, 1, ( ), ( )n mP x Q x

    0, ,k kT A H B

    s = 1, v l nghim pt c trng.i i

    Phng trnh c trng: 2 1 0k

    max{ , } 0k m n

    1 2k i k i

    V d Gii phng trnh '' cosy y x

  • cos sinry x A x B x ' ( )cos ( )sinry A Bx x B Ax x

    '' cosr ry y x

    Nghim t/qut: 0tq ry y y 1 21

    cos sin sin2

    C x C x x x

    -2 - sin 2 - cos cos s oin c sA Bx x B Ax x x xA x B x

    10,

    2A B

    1sin

    2ry x x

    '' -2 - sin 2 - cosry A Bx x B Ax x

    2 sin 2 cos cosA x B x x

  • ( )cos ( )sins xr k ky x e T x x H x x

    Nghim t/qut pt th/nht: 0 1

    1

    22 cos

    7 7

    2n

    2si

    x

    y e C x C x

    0( ) (cos 2sin )xf x e x x

    bc 0.0, 1, ( ), ( )n mP x Q x

    0, ,k kT A H B

    s = 0, v khng l nghim pt c trng.i i

    Phng trnh c trng: 2 2 0k k

    max{ , } 0k m n

    1

    1

    2

    7

    2k i

    V d Gii phng trnh '' ' 2 2sin cosy y y x x

  • cos sinry A x B x ' sin cosry A x B x

    '' ' 2 cos 2sinr r ry y y x x

    Nghim t/qut: 0tq ry y y

    1

    21 2

    7 7 3 1cos sin cos sin

    2 2 2 2

    x

    tqy e C x C x x x

    sin cos cos sincos si 2 c s 2 nn o siA x B xA A x xx B x xB x

    1

    2

    A B

    A B

    1 3,

    2 2A B

    '' cos sinry A x B x

    ( )cos ( )sin cos 2sinA B x A B x x x

    1 3cos sin

    2 2ry x x

  • Nghim t/qut pt th/nht: 2 20 1 2x xy C e C xe

    2

    1 2( ) ( ) ( )xf x f x f x x e

    Phng trnh c trng: 2 4 4 0k k 1 2 2k k

    V d Gii phng trnh'' ' 24 4 xy y y x e

    S dng nguyn l cng dn nghim

    Tm nghim ring ng vi :1( )f x

    '' '

    14 4 ( ) (1)y y y x f x

    1( )s xr ny x e Q x

    0, ( )nQ x Ax B (v Pn bc 1)

    s = 0, v khng l nghim n pt c trng.0

    Thay vo pt (1), ta c1r

    y Ax B 1

    4A B

    1

    1 1

    4 4ry x

  • Thay vo pt (2), ta c1

    2A

    Tm nghim ring ng vi :2( )f x

    '' ' 2

    24 4 ( ) (2)xy y y e f x

    2

    2 2x

    ry x e A

    1( )s xr ny x e Q x

    2, ( )nQ x A (v Pn bc 0)

    s = 2, v l nghim kp pt c trng2

    Mt nghim ring ca bi l:

    1 2r r ry y y 2 2

    1 1 1

    4 4 2

    xx x e

    Nghim t/qut: 0tq ry y y

    2 2 2 21 2

    1 1 1

    4 4 2

    x x xtqy C e C xe x x e

  • II. H pt vi phn tuyn tnh cp 1 h s hng.

    H phng trnh vi phn (n phng trnh, n hm s)

    111 1 12 2 1 1

    221 1 22 2 2 2

    1 1 2 2

    ... ( )

    ... ( )

    ... ( )

    n n

    n n

    nn n nn n n

    dxa x a x a x f t

    dt

    dxa x a x a x f t

    dt

    dxa x a x a x f t

    dt

    (1)

    trong l cc hm theo t, lin tc.( )f t

    l cc hm theo t.1 2( ), ( ), , ( )nx t x t x t

  • II. H pt vi phn tuyn tnh cp 1 h s hng

    11 12 1

    21 22 2

    1 2

    n

    n

    n n nn

    a a a

    a a aA

    a a a

    1

    2

    n

    x

    xX

    x

    1

    2

    ( )

    ( )( )

    ( )n

    f t

    f tF t

    f t

    H phng trnh dng ma trn: ( )dX

    AX F tdt

    (2)

    H phng trnh thun nht:dX

    AXdt

    (3)

    Nghim ca h l hm vct trn khong (a,b) c to

    l cc hm kh vi lin tc trn (a,b) v tho h:

  • II. H phng trnh vi phn tuyn tnh cp 1

    Cu trc nghim ca h tuyn tnh (2)

    0tq rX X X

    l nghim tng qut ca h pt khng thun nht (2)tq

    X

    l nghim tng qut ca h pt thun nht (3)0

    X

    l nghim ring ca h pt khng thun nht (2)r

    X

  • Phng php kh

    Ni dung phng php kh l a h phng trnh vi

    phn v phng trnh vi phn cp cao hn bng cch

    o hm mt phng trnh ri kh cc hm cha bit.

    u im

    Gii h phng trnh rt nhanh.

    Nhc im

    Rt kh gii h nhiu phng trnh, nhiu hm.

  • V d Gii h phng trnh

    '

    1 1 2

    '

    2 1 2

    2

    4 3

    x x x

    x x x

    Ly phng trnh (2) tr 4 ln phng trnh (1).

    ' '

    1 2 24 5 (*)x x x

    o hm hai v phng trnh (2).

    '' ' '

    2 1 24 3 x x x ' ' ''

    1 2 24 3 x x x Thay vo pt (*)

    Thay vo pt 2 ca h

    ' '' '

    2 2 2 23 5x x x x '' '

    2 2 24 5 0x x x

    5

    1 1 2( )t tx t C e C e

    5

    2 1 2

    1( )

    2

    t tx t C e C e

  • V d Gii h phng trnh

    '

    1 1 2

    '

    2 1 2

    3

    2 2

    tx x x e

    x x x t

    Ly phng trnh (2) tr 2 ln phng trnh (1).

    ' '

    1 2 12 4 2 (*)tx x x t e

    o hm hai v phng trnh (1).

    '' ' '

    1 1 23 tx x x e ' '' '2 1 13

    tx x x e Thay vo pt (*)

    ' '' '

    1 1 1 12 3 4 2t tx x x e x t e

    '' '

    1 1 15 4tx x x t e

    4

    1 1 2

    5( )

    9 3 4 16

    t tt t e te tx t C e C e Thay vo pt 1 ca h

    4

    2 1 2

    8 2 3 11( ) 2

    9 3 4 16

    t tt t e te tx t C e C e

  • V d Gii h phng trnh

    '

    1 1 2 3

    '

    2 1 2 3

    '

    3 1 2 3

    3

    2 4 2

    3

    x x x x

    x x x x

    x x x x

    Ly phng trnh (2) tr 4 ln phng trnh (1).

    ' '

    1 2 1 34 10 2 (*)x x x x

    Ly phng trnh (3) tr phng trnh (1).

    ' '

    1 3 1 32 2 (**)x x x x

    o hm hai v pt (1): ' '' ' '2 1 1 33x x x x

    Thay vo pt (*):' '' ' '

    1 1 1 3 1 34 3 10 2 x x x x x x

  • '' ' '

    1 1 3 1 37 10 2 (***)x x x x x

    Cng hai pt (**) v (***)'' '

    1 1 18 12 0x x x

    6 2

    1 1 2( )t tx t C e C e

    6 2

    3 1 3( )t tx t C e C e

    Thay vo pt (**):

    ' 6

    3 3 12 4tx x C e

    Thay vo pt (1) ca h, ta c:'

    2 1 1 33x x x x

    6 2 6 2 6 2

    2 1 2 1 2 1 3( ) 6 2 3 3t t t t t tx t C e C e C e C e C e C e

    6 22 1 2 3( ) 2t tx t C e C C e

    Nghim ca h cho:

    1

    2

    3

    ( )

    ( )

    ( )

    x t

    x t

    x t

  • V d Gii h phng trnh

    '

    1 1 2 3

    '

    2 1 2 3

    '

    3 1 2 3

    6 12

    3

    4 12 3

    x x x x

    x x x x

    x x x x

    Ly phng trnh (2) tr phng trnh (1).

    ' '

    1 2 1 25 9 (1)x x x x

    Ly pt th ba ca h cng 3 ln pt u ca h

    ' '

    1 3 1 23 14 24 (2)x x x x

    o hm hai v pt (2): ' ' ' ''3 1 2 23x x x x

    Thay vo pt (2):' ' ''

    1 2 2 1 24 3 14 24 (3)x x x x x

  • Kh trong pt (1) v (3):1x' ' ''

    1 2 2 26 5 6 (4)x x x x

    o hm hai v (5):

    Kh trong pt (1) v (3):'1x

    ' ''

    2 2 1 26 12 (5)x x x x

    '' ''' ' '

    2 2 1 26 12 (6)x x x x

    Rt thay vo (4):'1x

    ''' '' '

    2 2 2 26 12 6 0x x x x

    Gii phng trnh ny ta c 2 32 1 2 3( )t t tx t C e C e C e

    Thay vo (4) ta c 1( )x t

    Thay vo u ca h ta c 3( )x t

  • V d Gii h phng trnh

    '

    1 1 2 3

    '

    2 1 2 3

    '

    3 1 2 3

    2 4 3

    4 6 3

    3 3

    x x x x

    x x x x

    x x x x

    Cng hai phng trnh u ca h.

    ' '

    1 2 1 22 2 (1)x x x x

    Ly pt u tr 3 ln pt u ca h

    ' '

    1 3 1 23 7 5 (2)x x x x

    o hm hai v pt u: ' ' ' ''3 1 2 13 2 4x x x x

    Thay vo pt (2):' ' ''

    1 2 1 1 23 4 7 5 (3)x x x x x

  • ' ' ''

    1 2 1 13 2 4 (4)x x x x

    o hm hai v (5):

    Kh trong pt (1) v (3):2x

    Kh trong pt (1) v (3):'2x

    ' ''

    1 1 1 23 (5)x x x x

    '' ''' ' '

    1 1 1 23 (6)x x x x

    Rt thay vo (4):'2x

    ''' ''

    1 1 13 4 0x x x

    Gii phng trnh ny ta c 2 21 1 2 3( )t t tx t C e C e C te

    Thay vo (4) ta c 2 ( )x t

    Thay vo u ca h ta c 3( )x t

  • V d Gii h phng trnh

    '

    1 1 2

    '

    2 2 3

    '

    3 1 2 3

    3

    2 2

    tx x x e

    x x x t

    x x x x t

    Ly 3 ln pt u tr pt th hai ca h.

    ' '

    1 2 1 33 3 3 - (1)tx x x x e t

    Ly pt u tr pt th 3 ca h

    ' '

    1 3 1 32 2 - 2 (2)tx x x x e t

    o hm hai v pt u: ' ' ''2 1 1

    tx x x e

    Thay vo pt (1):' ''

    1 1 1 34 3 2 - (3)tx x x x e t

  • ' '' '

    1 1 3 19 2 8 5 - 4 (4)tx x x x e t

    o hm hai v (3):

    Kh trong pt (2) v (3):3x

    '' ''' ' '

    1 1 1 34 3 2 -1 (5)tx x x x e

    Rt thay vo (4):'3x

    ''' '' '

    1 1 1 16 12 8 3 4 1tx x x x e t

    Gii phng trnh ny ta c

    2 2 2 2

    1 1 2 3

    5( ) 3

    2 8

    t t t t tx t C e C te C t e e

    Thay vo pt u ca h ta c 2 ( )x t

    Thay vo pt hai ca h ta c 3( )x t

  • Phng php tr ring, vct ring

    A l ma trn thc, vung cp n.

    Trng hp 1: A cho ho c:

    ( ) (2)dX

    AX F tdt

    1A PDP ( )dX

    AX F tdt

    1 ( )dX

    PDP X F tdt

    1 1 1 ( )dX

    P DP X P F tdt

    1Y P Xt ' 1 'Y P X

    ' 1 ( )Y DY P F t Ta c:

    y l cc phng trnh vi phn cp 1 tch ri nhau.

  • V d Gii h phng trnh

    '

    1 1 2

    '

    2 1 2

    3

    2 2

    tx x x e

    x x x t

    Cho ho A:

    1

    2

    xX

    x

    3 1

    2 2A

    ( )te

    F tt

    1 1 1 4 0 2/3 1/3

    1 2 0 1 1/3 1/3A PDP

    1Y P Xt ' 1 ( )Y DY P F t Ta c:

    '1 1

    '22

    4 0 2 /3 1/3

    0 1 1/3 1/3

    ty y e

    y ty

  • '1 1

    '22

    4 0 2 /3 1/3

    0 1 1/3 1/3

    ty y e

    y ty

    '1 1

    '2 2

    24

    3 3

    1

    3 3

    t

    t

    ty y e

    ty y e

    h gm hai ptrnh vi phn

    tuyn tnh cp 1 ring bit

    41 1

    2 2

    2 1( )

    9 12 48

    1( )

    3 3 3

    t t

    t t

    ty t C e e

    t ty t C e e

    Nghim ca h: 1 1

    2 2

    x yP

    x y

    1

    2

    1 1

    1 2

    y

    y

  • V d Gii h phng trnh

    '

    1 1 2 3

    '

    2 1 2 3

    '

    3 1 2 3

    3 4

    2 4 2

    3 8

    x x x x t

    x x x x

    x x x x

    Cho ho A ( Xem i s tuyn tnh)

    1

    2

    3

    x

    X x

    x

    3 1 1

    2 4 2

    1 1 3

    A

    4

    ( ) 0

    8

    t

    F t

    1

    1 1 1 2 0 0 1/ 2 1/ 2 1/ 2

    1 0 2 0 2 0 1/ 4 1/ 4 3/ 4

    0 1 1 0 0 6 1/ 4 1/ 4 1/ 4

    A PDP

  • 1Y P Xt ' 1 ( )Y DY P F t Ta c:

    '

    1 1

    '

    2 2

    '

    3 3

    2 0 0 1/ 2 1/ 2 1/ 2 4

    0 2 0 1/ 4 1/ 4 3/ 4 0

    0 0 6 1/ 4 1/ 4 1/ 4 8

    y y t

    y y

    y y

    '1 1

    '2 2

    '3 3

    2 2 4

    2 6

    6 2

    y y t

    y y t

    y y t

    21 1

    22 2

    63 3

    ( ) 5/ 2

    ( ) / 2 11/ 4

    ( ) / 6 19 /36

    t

    t

    t

    y t C e t

    y t C e t

    y t C e t

    Nghim

    ca hX PY

    211

    22 2

    63 3

    5/ 2( ) 1 1 1

    ( ) 1 0 2 / 2 11/ 4

    ( ) 0 1 1 / 6 19 /36

    t

    t

    t

    C e tx t

    x t C e t

    x t C e t

  • Phng php tr ring, vct ring

    Trng hp 2: A khng cho ho c:

    ( ) (2)dX

    AX F tdt

    1(2) ( )dX

    PTP X F tdt

    1 1 1 ( )dX

    P TP X P F tdt

    1Y P Xt ' 1 'Y P X

    ' 1 ( )Y TY P F t Ta c:

    Mi ma trn (thc hoc phc) u tam gic ho c.

    1A PTP vi T l ma trn tam gic.

    y l h tam gic,

    gii t di ln.

  • V d Gii h phng trnh

    '

    1 1 2 3

    '

    2 1 2 3

    '

    3 1 2 3

    2 4 3

    4 6 3

    3 3

    x x x x

    x x x x

    x x x x

    A khng cho ho c ( Xem i s tuyn tnh)

    1

    2

    3

    x

    X x

    x

    2 4 3

    4 6 3

    3 3 1

    A

    y l h thun nht.

    2| | 0 ( 2) ( 1) 0A I

    1 2 c mt VTR c lp tuyn tnh 1

    1

    1

    0

    X

  • 2 1 c mt VTR c lp tuyn tnh 3

    1

    1

    1

    X

    Tm hai ma trn1

    2

    3

    1 1

    1 1

    0 1

    x

    P x

    x

    2 0

    0 2 0

    0 0 1

    m

    T

    1A PTP AP PT 2 1 22AX mX X

    Gi l ct th hai ca ma trn P.2X

    Chn m = 1

    1 1

    2 2

    3 3

    2 4 3 1

    4 6 3 1 2

    3 3 1 0

    x x

    x x

    x x

    1

    2

    3

    1

    1

    x

    x

    x

  • Chn 1 2

    2

    1

    1

    X

    1 2 1

    1 1 1

    0 1 1

    P

    2 1 0

    0 2 0

    0 0 1

    T

    1Y P Xt 'Y TYTa c:

    '

    1 1

    '

    2 2

    '

    3 3

    2 1 0

    0 2 0

    0 0 1

    y y

    y y

    y y

    '1 1 2

    '2 2

    '3 3

    2

    2

    y y y

    y y

    y y

    2 21 1 2

    22 2

    3 3

    ( )

    ( )

    ( )

    t t

    t

    t

    y t C e C te

    y t C e

    y t C e

    1 1

    2 2

    3 3

    ( ) 1 2 1

    ( ) 1 1 1

    ( ) 0 1 1

    x t y

    x t y

    x t y

  • V d Gii h phng trnh

    '

    1 1 2

    '

    2 2 3

    '

    3 1 2 3

    3

    2 2

    tx x x e

    x x x t

    x x x x t

    A khng cho ho c ( Xem i s tuyn tnh)

    1

    2

    3

    x

    X x

    x

    1 1 0

    0 3 1

    1 1 2

    A

    3| | 0 ( 2) 0A I

    1 2 c mt VTR c lp tuyn tnh 1

    1

    1

    1

    X

    ( )

    2

    te

    F t t

    t

  • Tm hai ma trn1 1

    2 2

    3 3

    1

    1

    1

    x y

    P x y

    x y

    2

    0 2

    0 0 2

    a b

    T c

    1A PTP AP PT 2 1 22AX aX X

    Gi l ct th hai ca ma trn P.2X

    Chn a = 1

    1 1

    2 2

    3 3

    1 1 0 1

    0 3 1 1 2

    1 1 2 1

    x x

    x x

    x x

    1

    2

    3

    1

    1

    x

    x

    x

    Chn 2 2

    1

    2

    1

    X

    1

    2

    3

    1 1

    1 2

    1 1

    y

    P y

    y

    2 1

    0 2

    0 0 2

    b

    T c

  • 1A PTP AP PT 3 1 2 32AX bX cX X Chn b = 0,c=1

    1 1

    2 2

    3 3

    1 1 0 1

    0 3 1 2 2

    1 1 2 1

    y y

    y y

    y y

    1

    2

    3

    1

    2

    x

    x

    x

    Chn 2 3

    1

    2

    0

    X

    1 1 1

    1 2 2

    1 1 0

    P

    2 1 0

    0 2 1

    0 0 2

    T

    1

    2 1 0

    2 1 1

    1 0 1

    P

  • '1 1

    '

    2 2

    '

    3 3

    2 1 0 2 1 0

    0 2 1 2 1 1

    0 0 2 1 0 1 2

    ty y e

    y y t

    y y t

    '1 1 2

    '2 2 3

    '3 3

    2 2

    2 2 3

    2 2

    t

    t

    t

    y y y e t

    y y y e t

    y y e t

    1Y P Xt ' 1 ( )Y TY P F t Ta c:

    1

    22 2 3

    3 3

    ( )

    ( ) 2 / 2 3/ 4

    ( ) 2 2 2

    t t t

    t t

    y t

    y t C e C e te t

    y t C e te t

  • Nhn xt:

    sau khi kh ta c phng trnh vi phn tuyn tnh

    cp cao ca mt pt. Phng trnh c trng ca pt ny

    trng vi pt c trng ca ma trn A, hoc trong mt s

    Gii h bng phng php kh:' ( )X AX F t

    trng hp trng vi phng trnh ti thiu caA.

    Phng php kh: 1) Kh ln lt tng bin trong h.

    2) trong qu trnh kh: o hm hai v.

    H 3 pt, 3 n: kh d dng, h nhiu pt nhiu n: kh

  • Ni dung n tp------------------------------------------------------------------------------------------------

    I) Gii hn v lin tc: Cch tm gii hn hm, lin tc hm s.

    II) o hm v vi phn: o hm v vi phn ca hm y = f(x),

    hm tham s, hm n. Cng thc Taylor, Maclaurint.

    ng dng o hm: cc bi ton lin quan, kho st v.

    III) Tch phn: 1) Tch phn bt nh, tch phn xc nh

    Tch phn suy rng loi mt v hai: tnh tphn, kho st hi t.

    IV) phng trnh vi phn:

    1) Phng trnh vi phn cp 1: ch c 5 loi hc: Tch bin, tuyn

    tnh, ng cp, ton phn (khng c tha s tch phn), Bernoulli.

    3) H phng trnh vi phn tuyn tnh cp 1 h s hng: Phng

    php kh, phng php tr ring, vct ring (trng hp cho c)

    2) Phng trnh vi phn cp hai H S HNG.

    ng dng hnh hc ca tch phn: c 4 ng dng hc.

  • mu cui k 1------------------------------------------------------------------------------------------------

    Cu 1. Tnh

    arcsin

    30

    coshlim

    tan 1 3 2cos 1

    x

    x

    x x e

    x x x

    Cu 3. Tnh tch phn

    3 22 2 2

    dxI

    x x x

    Cu 2. Tm tim cn ca ng cong cho bi ptrnh tham s

    2 2

    8 3,

    4 ( 4)

    tx y

    t t t

    21

    3 30

    cosh ln(1 ) 1

    2 8

    x xI dx

    x

    Cu 4. Tnh tt c tch phn sau hi t.

  • Cu 6. Gii phng trnh vi phn 'y y x y

    Cu 5. Tm th tch vt th trn xoay khi quay min D gii hn bi

    arctan , arctan ,0 1, 1y x x y x x x x quanh trc Ox.

    Cu 7. Gii phng trnh vi phn cp 2

    '' '3 2 3 5sin 2y y y x x

    Cu 8. Gii h phng trnh vi phn bng phng php tr ring.'

    1 1 2 3

    '

    2 1 2 3

    '

    3 1 2 3

    4 4

    8 11 8 2

    8 8 5

    tx x x x e

    x x x x t

    x x x x

    Cui k thi T LUN (trnh by cn thn), thi gian: 90pht.

  • Gii mu 1.

    Cu 1.

    3 3

    3 30

    / 3 ( ) 1lim

    44 / 3 ( )x

    x xI

    x x

    22cosh 1 ( )

    2

    xx x

    33arcsin ( )

    6

    xx x x

    2 3arcsin 31 ( )

    2 3

    x x xe x x 3

    3tan ( )3

    xx x x

    32 33 51 3 1 ( )

    3

    xx x x x

    Cu 2. Tim cn ng: 0

    0

    lim ( )

    lim ( ) 2

    t

    t

    y t

    x t

    2x l tim cn ng.

    Khng c tim cn ngang.

  • Tim cn xin.2

    2

    lim ( )

    lim ( )

    t

    t

    y t

    x t

    1

    4 8

    xy

    l tim cn xin.

    2

    ( ) 1lim

    ( ) 4t

    y ta

    x t

    2

    1lim ( ) ( )

    8tb y t a x t

    2

    2

    lim ( )

    lim ( )

    t

    t

    y t

    x t

    3 9

    20 40

    xy l tim cn xin.

    2

    ( ) 3lim

    ( ) 20t

    y ta

    x t

    2

    9lim ( ) ( )

    40tb y t a x t

    Cu 3.1

    ( 1)( 1)( 2) 1 1 2

    A B C

    x x x x x x

    tm A, nhn 2 v cho x - 1 ri thay x = 1 vo, tng t cho B, C.

  • 3 22 2 2

    dxI

    x x x

    22 2cosh ln(1 ) 1 ( )

    2

    xx x x

    Cu 4.

    2

    1 1 1ln | 1| ln | 1| ln | 2 |

    6 2 3x x x

    1/ 6 1/3

    1/ 2

    2

    1 2ln

    ( 1)

    x x

    x

    ln3 2ln 2

    2 3

    30

    3 32 812

    x xx

    2 2

    33 3

    cosh ln(1 ) 1 12( )

    22 8

    x x xf x

    xx

    Hm di du tch phn l hm lun m. Xt tch phn hm - f(x).

    3 2

    12 1

    2 x

    Tch phn hi t nu 3 2 1 1

  • Cu 5. 1 2arctan , arctany x x y x x

    Ta c 1 20 ( ) ( ), [0,1]y x y x x

    1

    2 2

    0 2 1

    0

    xV y y dx 1

    2 2

    0

    ( arctan ) ( arctan )x x x x dx

    1

    0

    0

    4 arctanxV x xdx 2 2

    Cu 6. y l phng trnh Bernoulli vi

    'y y x y

    1/ 2

    '

    2 22

    y y x

    y t z y

    '

    2 2

    z xz / 2 2xz Ce x

    Nghim tng qut ca pt l/ 2 2xy Ce x

  • Cu 7. Phng trnh c trng: 2 3 2 0k k 1 21 2k k

    Nghim ca phng trnh thun nht:2

    0 1 2

    x xy C e C e

    Dng nguyn l cng dn nghim tm nghim ring:1 2r r r

    y y y

    Nghim ring ca l'' '3 2 3y y y x

    1

    3 9

    2 4ry x

    Nghim ring ca :'' '3 2 5sin 2y y y x 2

    3 1cos2 sin 2

    4 4ry x x

    Nghim tng qut ca phng trnh cho:

    2

    1 2

    3 9 3 1cos2 sin 2

    2 4 4 4

    x xtqy C e C e x x x

  • Cu 8.

    1 4 4

    8 11 8

    8 8 5

    A

    1 1 1

    2 0 1

    2 1 0

    P

    1 0 0

    0 3 0

    0 0 3

    D

    1Y P Xt ' 1 ( )Y DY P F t Ta c:

    '

    1 1

    '

    2 2

    '

    3 3

    1 0 0 1 4 /3 4 /3

    0 3 0 8/3 3 8/3 2

    0 0 3 8/3 8/3 7 /3 0

    ty y e

    y y t

    y y

    '

    1 1

    '

    2 2

    '

    3 3

    8 / 3

    3 8 / 3 6

    3 8 / 3 16 / 3

    t

    t

    t

    y y e t

    y y e t

    y y e t

    1 1

    3

    2 2

    3

    3 3

    ( ) 8 / 3 8/ 3

    ( ) 2 / 3 2 2 / 3

    ( ) 2 / 3 16 / 9 16 / 27

    t t

    t t

    t t

    y t C e te t

    y t C e e t

    y t C e e t

    Suy ra nghim tng qut ca h.

  • mu cui k 2------------------------------------------------------------------------------------------------

    Cu 1. Tnh

    2

    0

    sinh ln(1 )lim

    tanx

    x x

    x x

    Cu 3. Tnh tch phn

    2

    21 3 2 1

    dxI

    x x x

    Cu 2. Tm tim cn ca ng cong cho bi ptrnh44 1

    | |

    xy

    x

    3 22

    ln

    1arctan

    xI dx

    xx

    Cu 4. Tnh tt c tch phn sau hi t.,

  • Cu 6. Gii phng trnh vi phn ' 1 1y x y x y

    Cu 5. Tm din tch b mt trn xoay khi quay min D gii hn bi

    ( sin ), (1 cos ),0 2 ; 0x a t t y a t t a quanh trc Oy.

    Cu 7. Gii phng trnh vi phn cp 2

    '' ' 24 4 cosxy y y e x

    Cui k thi T LUN (trnh by cn thn), thi gian: 90pht.

    Cu 8. Gii h phng trnh vi phn bng phng php kh.' 2

    1 1 2 3

    '

    2 1 2 3

    '

    3 1 2 3

    4 2 5

    6 6 2

    8 3 9

    x x x x t

    x x x x t

    x x x x

  • Gii mu cui k 2------------------------------------------------------------------------------------------------

    Cu 1.2 3 3sinh ln(1 ) ( )x x x x

    33tan ( )

    3

    xx x x

    2 3

    30 0

    sinh ln(1 )lim lim 3

    tan /3x x

    x x x

    x x x

    Cu 2.

    ( )limx

    f xa

    x

    Tim cn ng: 0x

    44 1lim

    | |x

    x

    x x

    2,

    2,

    x

    x

    2a lim ( )x

    b f x ax

    44 1

    lim 2x

    xx

    x

    0

    2a lim ( )x

    b f x ax

    0

    C hai tim cn xin: 2 , 2y x y x

  • Cu 3. t2

    1 2

    2

    2 13

    dxI

    xx x

    1t

    x

    1

    21/ 2 3 2

    dt

    t t

    1

    21/ 2

    ( 1)

    4 ( 1)

    d tI

    t

    1

    21/ 2

    ( 1) / 2

    1 ( 1) / 2

    d t

    t

    1

    1/ 2

    1arcsin

    2

    t

    3arcsin

    2 4

    Cu 4.2 /3

    3 2

    ln ln( )

    1arctan

    xx x xf x

    xx

    x

    2 /3

    ln x

    x

    Nu , th tch phn hi t vi mi2 /3 1 1/3

    Nu , th tch phn phn k vi mi2 /3 1 1/3

    Nu , th tch phn hi t khi2 /3 1 1/3 1

  • Cu 5. ( sin ), (1 cos ),0 2x a t t y a t t

    '( ) cosx t a a t '( ) siny t a t

    2 2

    ' ' 2 2( ) ( ) 4 sin2

    tx t y t a

    2

    2 2' '

    0

    0

    2 ( ) ( ) ( )yS x t x t y t dt

    22 2

    0

    0

    2 ( sin ) 4 sin2

    y

    tS a t t a dt

    2

    2

    0

    4 ( sin ) sin2

    ta t t dt

    22

    0

    0

    4 sin sin sin2 2

    y

    t tS a t t dt

    2 216 a

  • Cu 6.' 1

    1

    x yy

    x y

    t 1u x y

    ' '1u y

    ' 21u

    uu

    2du u u

    dx u

    2

    udu dx

    u u

    2 82 ln 1 ln 2

    3 3u u u x C

    2 81 ln 1 1 ln 1 2

    3 3x y x y x y x C

    Cu 7. Nghim tng qut ca pt thun nht:2 2

    0 1 2

    t ty C e C te

    Dng nguyn l cng dn nghim tm nghim ring:1 2r r r

    y y y

    Nghim ring ca :'' ' 24 4 xy y y e

    1

    2 21

    2

    xry x e

  • Nghim ring ca :'' '4 4 cosy y y x 2

    3 4cos sin

    25 25ry x x

    Nghim tng qut ca phng trnh cho:

    2 2 2 2

    1 2

    1 3 4cos sin

    2 25 25

    x x xtqy C e C xe x e x x

    Cu 8.' 2

    1 1 2 3

    '

    2 1 2 3

    '

    3 1 2 3

    4 2 5

    6 6 2

    8 3 9

    x x x x t

    x x x x t

    x x x x

    Ly pt u cng vi 2 ln pt th hai ca h

    ' ' 2

    1 2 1 32 8 7 4 (1)x x x x t t

    Ly 3 ln pt u tr 2 ln pt th ba ca h

    ' ' 2

    1 3 1 33 2 4 3 2 (2)x x x x t

  • Kh pt (2) v (3):1x'' ' ' 2

    3 1 3 32 6 3 -9 12 (4)x x x x t t

    o hm hai v (5):

    Kh pt (2) v (3):'1x

    '' ' 2

    3 3 1 36 16 4 6 - 27 36 (5)x x x x t t

    ''' ''' ' ' 2

    3 3 1 36 16 4 - 6 -54 36 (6)x x x x t

    Rt thay vo (4):'1x

    ''' '' ' 2

    3 3 3 34 5 2 3 8 6x x x x t t

    Gii pt ny:2

    2 3

    3 1 2 3

    3 23 79( )

    2 2 4

    t t t t tx t C e C e C e

    Thay vo (4) ta c 1( )x t

    Thay vo u ca h ta c 2 ( )x t

    o hm hai v pt th 3: ' '' ' '2 3 1 31

    8 9 3

    x x x x

    '' ' ' 2

    3 1 3 1 32 19 18 24 21 3 12 (3)x x x x x t t Thay vo (1):

  • Bi tp

    '' '1) 2 2 xy y y e

    '' '2) 7 6 sin y y y x

    '' '3) 2 2 2 y y y x

    '' ' 24) 3 2 3 xy y y e

    '' '5) 7 6 (3 4 ) xy y y e x

    '' ' 26) 5 5 2 1 2y y x x

    '' '7) 5 29 sin 2y y x x

    / 2

    1 2

    x x xy C e C e e

    6

    1 2

    7 5cos sin

    74 74

    x xy C e C e x x

    1 2cos sin 1xy e C x C x x

    2 2

    1 2 (3 3)x x xy C e C e x e

  • '' '8) 2 5 100 cos xy y xe x

    '' ' 29) 4 4 3 xy y y e

    '' '10) 4 4 sin cos2 y y y x x

    '' ' 311) 4 4 sin y y y x

    '' '12) 4 4 sinh 2 y y y x

    ''13) cos y y x

    ''14) sin 2 xy y x e

    '' '15) 6 5 cosh 5 xy y y e x