Mathematics Sk Saujana Impian
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Transcript of Mathematics Sk Saujana Impian
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SK SAUJANA IMPIAN
2012
MATHEMATICS
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WHOLE NUMBERS
Place Values and Values of Digits
2 5 3 9 4 1 7
MillionsHundreds ThousandsTen ThousandsThousandsHundredsTensOnes
710
4009 00030 000500 0002 000 000
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Round Off Numbers
3 2 8 6 9 7 0 = 3 290 000
(to the nearest ten thousands)
6 is more than 5. Thus, add I to the digit to be rounded off
6 1 3 4 8 9 5 = 6 000 000
(to the nearest million)
1 is less than 5. Thus, retain the digit to be rounded off.
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Mixed Operations
Follow rules of
B O D M A S
Brackets
Of
Division
Multiplication
Addition
Subtraction
Left to Right
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Subtraction
4
127
6
31
6
12
6
47
2
11
6
12
3
27
2
11
6
12
3
27
3
3
2
2
x
x
x
x
06
3
6
1
6
4
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Multiplication
850
5017
2004
17
200
4
14
200414
of
1
50
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Division
4
1
61
31
63
1
6
16 aswrite
change
5
3
4
1
5
12
45
22
3
1
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4
1
1
2
8
1
2
1
8
1
1
4
3
1
2
2
3
2
1
2
11
1
1
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Convert 1.05 to fraction
20
1
1100
5
1 5
5
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Convert Mixed Number toImproper Fraction
1017
107101
1071
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Convert Improper Fraction toMixed Number
4
3
20
235523
534
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Equivalent Fraction
9
6
3
2 3
3
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Fraction of The Shaded Part
4
3
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Fraction in Simplest Form
3
1
24
8
8
8
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DECIMALSAddition
6.2 + 1.05 =
25.7
05.1
20.6
+
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Subtraction
7 4.103 =
897.2
103.4
000.7
-
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Multiplication
0.27 x 19 =
x0.27
19
2 43
2 47
5.13
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Division
03.124.88
8
2
0
2424
. .
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Mixed Operation
10 2.84 + 3.167 6 =
1 0 . 0 0 0
2 . 8 4 0
7 . 1 6 0
3 . 1 6 7
1 0 . 3 2 7
6 . 0 0 0
4 . 3 2 7
+
Calculate from
left to right
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Convert to decimals
5
24.0
0
02
0.25
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Convert Decimals to Percentages
10029129.1
%129
100
129
100
291001
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Percentage of Quantity
40% of 180 marbles
marbles72
184
018
001
04
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One Number as a Percentage of Another
RM30 out of RM120
%25
%
12
1030
%100
120
30
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Percentage of the shaded part
%25
%1004
1
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MONEY
70.168
20.7650.92
20.7681050.902
RM
RMRM
RMRMRM
Mixed Operation
00.810
50.905
RM
RM
20.76
50.92
RM
RM
70.168RM
-
+
Calculate from left toright
Decimal point are in a
vertical line
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90.6747
00.254690.4201)825.318(90.4201
RM
RMRMRMRM
Do the calculation inbrackets first.
25.318RM
8
00.2546RM
90.4201RM
00.2546RM+
90.6747RM
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Time
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Units of time
1 minutes = 60 seconds
1 hour = 60 minutes1 day = 24 hours
1 week = 7 days1 year = 12 months
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12-hour System and 24-hour System
0000hours
12:00midnight
0600hours
1200hours
1800hours
2400hours
6:00 a.m 12:00noon
6:00 p.m 12:00midnight
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Fraction of time duration
3
4of 1
year=
3
4x 1 year
3
4 x 12 months
3
=
= 9 month
Start time and End time
End time = Start time + Time duration
Start Time = End Time - Time duration
Duration = End Time Time duration
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Fraction involving length
4
5of 70 km =
4
5x 70 km
14
= 56 km
213
of 12 m =5
3x 12 m
4
= 20 km= ( 20 X 100 )
cm= 2 000 cm
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addition
= ( 4.2 X 1 000 ) m + 250 m
4.2 km + 250
m
= 4 200 m + 250 m
= 4 450 m
4 200 m
250 m4 450 m
+
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subtraction
= 7.6 cm - ( 8 10 ) cm
7.6 cm + 8
mm
= 7.6 cm 0.8 cm
= 6.8 cm
7.6 cm0.8 cm
6.8 cm
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MASS
RELATIONSHIP BETWEEN UNITS OF MASS
kg g
X 1000
1000
1 kg = 1 000 g
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Fraction involving mass
4
7of 1 022 g=
4
7x 1 022 g
146
= 584 g
324
of 20 kg =11
4x 20 kg
5
= 55 kg
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addition
= ( 5.9 X 1 000 ) g + 1 360 g
5.9 kg + 1 360 g
= 5 900 g + 1 360 g
= 7 260 g
1 360 g5 900 g
7 260 g
+
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subtraction
= 7.1 kg - ( 280 1 000 ) kg
7.1 kg - 280 g
= 7.1 kg 0.28 kg
= 6.82 kg
7.10 kg0.28 kg
6.82 kg
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Volume of liquid
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Convert 1.08 to1.08 = (1.08 x 1000)
= 1080
Fractions Involving Volume of Liquidof 135 kg = x 135 kg
= 75 kg
l ml
l ml
ml
9
5
9
5
Volume of liquid
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Addition
0.86 + 120
= 0.86 + (120 1000)
= 0.86 + 0.12= 0.98
subtraction
4036 - 2.9
= 4036 - (2.9 x1000)
= 4036 - 2900
= 1136
l
ml
l
mll ml
l
ml
ml
ml
mll
l
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Area
a x b
a = length,
b = breath
x base xheight
Volume 3D shapes
= Length x width xheight2
1
a
b
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Shape and Space
square TriangleRectangle
Isosceles
triangle
Equilateral
triangle
Right angled
triangle
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3-D shapes
CubeCone
Cuboid
Cylinder
SphresPyramid
P i t
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b b a + b + a + b(2 x a) + (2 x b)
a
a
Surface area of P = 5 x ( 3 cm x 3
cm )
= 45
Surface area of Q = 5 x ( 3 cm x 3cm )
= 45 cm
Total surface area = 45 + 45
= 90
2cm
2cm
2cm
2cm
2cm
Perimeter
Total surfacearea
P
Q
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Data handling
Average =Total values of the items
Number of items
Average of 6, 24, 18 and
32= 6 + 24 + 18 +
32
4
= 804
= 20
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Pie chart- The pie chart shows the favourite fruits of 20 children
35%
20%
20%
25% Durian
Mango
Startfruit
Apple
The frequency of the favourite fruit is the number of
children who like the fruit.
Example : frequency of durian = x 20 children
= 7 children
100
35
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Range is the difference between the highest and the
lowest number of pupils.
Example: durian 7 ( highest)
Mango or starfruit - x 20 = 4 (lowest)
Range = 7 4 = 3 children
100
20
Mean is the average number of children for the various
types of favourite fruit.
Example; Mean = = 5 children
Mode is a value or item which occurs most frequently.
Eg : Durian is the mode and its frequency is 7.
4
20