Mathcad - Eje2 Guia

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ϕ 0.05 := r ϕ 2 0.025 = := A 4 π r 2 7.854 10 3 - × = := h 15 := ε 0.8 := Tp 70 273.15 + 343.15 = := Tinf 20 273.15 + 293.15 = := σ 5.67 10 8 - := Qh hA Tp Tinf - ( ) 5.89 = := W Qσ σε A Tp 4 Tinf 4 - ( 29 2.309 = := W Qt Qh Qσ + 8.199 = := W

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Transcript of Mathcad - Eje2 Guia

  • 0.05:= r 2

    0.025=:=A 4 pi r2 7.854 10 3=:=

    h 15:= 0.8:= Tp 70 273.15+ 343.15=:=

    Tinf 20 273.15+ 293.15=:= 5.67 10 8:=

    Qh h A Tp Tinf( ) 5.89=:= W

    Q A Tp4 Tinf 4( ) 2.309=:= WQt Qh Q+ 8.199=:= W