Lecture1 - University of Alberta · Lecture1.jnt Author: ewoolgar Created Date: 7/14/2019 11:16:17...
Transcript of Lecture1 - University of Alberta · Lecture1.jnt Author: ewoolgar Created Date: 7/14/2019 11:16:17...
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Lecture 1 questions
Consider the curve shortening flow
∂ ~X(θ, t)
∂t= βκ ~N (∗)
Here ~X(θ, t) is a flowing curve. That means that if t has a fixed constant value, say t = 0
for example, then ~X(θ, 0) =
(x(θ, 0)y(θ, 0)
)is a parametrized curve in R2, with parameter θ. The
curvature of the curve is κ and ~N is the unit normal vector pointing from the curve toward thecentre of the asculating circle. Finally, β > 0 is a constant.The first question should be easy, the next one medium, and the last one a bit more difficult:
1. Consider a circle, flowing according to equation (∗). Write the flowing circle as
~X(θ, t) = a(t)(cos θ, sin θ) , θ ∈ [0, 2π] .
Say the flow begins at t = 0, with initial condition a(0) = a0 > 0. How long does it take for thecircle to disappear? (i.e., at what t-value does the radius a(t) become zero? Answer in termsof β and a0.)
2. Consider the ellipsex2
a2+y2
b2= 1 , 0 < a < b .
Now let this ellipse evolve under the mean curvature flow (∗). It disappears in some time Twhere β
b < T < βa . Explain this (hint: use circles, and use the answer to the first question).
3. Let
~X(s, t) =
(x(s, t)y(s, t)
)=
(arccos t√
t2+s2
ln t− ln√t2 + s2 − t
), t ∈ [0,∞) , s ∈ [0,∞) . (†)
Here arccos means the inverse function to cos, sometimes denoted by cos−1. At each fixed t,this is a curve. For example, at t = 1, this is the curve
~X(s, 1) = ~X(s) =
(arccos 1√
1+s2
−1− ln√
1 + s2
), s ∈ [0,∞) .
(Try to sketch this curve.) Show that ~X(s, t) obeys equation (∗) (i.e., treating t as constant,
compute κ and ~N ; then compare κ ~N to ∂ ~X∂t ). As t increases, the curve s 7→ X(s, t) moves
simply by translating downward. Can you see why?