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  • Lecture 24

    General Physics (PHY 2130)

    http://www.physics.wayne.edu/~apetrov/PHY2130/

    Solids and fluids Fluids in motion

    Oscillations Simple harmonic motion

  • Lightning Review

    Last lecture: 1. Solids and fluids

    different states of matter; fluids density, pressure, etc.

    Review Problem: A piece of metal is released under water. The volume of the metal is 50.0 cm3 and its specific gravity is 5.0. What is its initial acceleration? (Note: when v = 0, there is no drag force.)

  • 3

    Example: A piece of metal is released under water. The volume of the metal is 50.0 cm3 and its specific gravity is 5.0. What is its initial acceleration? (Note: when v = 0, there is no drag force.)

    FBD for the metal mawFF B ==

    VgFB water=

    The magnitude of the buoyant force equals the weight of the fluid displaced by the metal.

    Solve for a:

    === 1

    objectobject

    water

    objectobject

    water

    VVgg

    VVgg

    mFa B

    Idea: apply Newtons 2nd Law to the piece of metal:

    x

    y

    w

    FB

  • 4

    Since the object is completely submerged V=Vobject.

    water

    gravity specific

    =

    where water = 1000 kg/m3 is the density of water at 4 C.

    Given 0.5gravity specificwater

    object ==

    2

    objectobject

    water m/s 8.710.5

    11..

    11

    =

    =

    =

    = g

    GSg

    VVga

    Example continued:

  • 5

    Fluid Flow

    A moving fluid will exert forces parallel to the surface over which it moves, unlike a static fluid. This gives rise to a viscous force that impedes the forward motion of the fluid.

    A steady flow is one where the velocity at a given point in a fluid is constant. Steady flow is laminar; the fluid flows in layers.

    V1 = constant

    V2 = constant

    v1v2

    An ideal fluid is incompressible, undergoes laminar flow, and has no viscosity.

  • Fluids in Motion: Streamline Flow Streamline flow

    every particle that passes a particular point moves exactly along the smooth path followed by particles that passed the point earlier

    also called laminar flow Streamline is the path

    different streamlines cannot cross each other the streamline at any point coincides with the direction of fluid

    velocity at that point

    Fluids in Motion: Turbulent Flow The flow becomes irregular

    exceeds a certain velocity any condition that causes abrupt changes in velocity

  • 7

    The amount of mass that flows though the cross-sectional area A1 is the same as the mass that flows through cross-sectional area A2.

    Equation of Continuity

    AvtV=

    is called the volume flow rate (units m3/s)

  • 8

    is the mass flow rate (units kg/s) Avtm

    =

    222111 vAvA =The continuity equation is

    If the fluid is incompressible, then 1= 2.

  • 9

    Example: A garden hose of inner radius 1.0 cm carries water at 2.0 m/s. The nozzle at the end has radius 0.20 cm. How fast does the water move through the constriction?

    ( ) m/s 50m/s 0.2cm 0.20

    cm 0.1 2

    122

    21

    12

    12

    2211

    =

    =

    =

    =

    =

    vrrv

    AAv

    vAvA

  • Oscillations Simple Harmonic Motion

  • Recall: Hookes Law Fs = - k x

    Fs is the spring force k is the spring constant

    It is a measure of the stiffness of the spring A large k indicates a stiff spring and a small k indicates a soft spring

    x is the displacement of the object from its equilibrium position

    The negative sign indicates that the force is always directed opposite to the displacement

    The force always acts toward the equilibrium position It is called the restoring force

  • Hookes Law Applied to a Spring Mass System

    When x is positive (to the right), F is negative (to the left)

    When x = 0 (at equilibrium), F is 0

    When x is negative (to the left), F is positive (to the right)

  • Example: two springs The springs 1 and 2 in Figure have spring constants of 40.0 N/cm and 25.0 N/cm, respectively. The object A remains at rest, and both springs are stretched equally. Determine the stretch.

  • Motion of the Spring-Mass System Assume the object is initially pulled to x = A and released from rest

    As the object moves toward the equilibrium position, F and a decrease, but v increases

    At x = 0, F and a are zero, but v is a maximum The objects momentum causes it to overshoot the equilibrium position

    The force and acceleration start to increase in the opposite direction and velocity decreases

    The motion continues indefinitely

  • Simple Harmonic Motion Motion that occurs when the net force along the direction of motion is a Hookes Law type of force The force is proportional to the displacement and in the

    opposite direction The motion of a spring mass system is an example of Simple Harmonic Motion

    Not all periodic motion over the same path can be considered Simple Harmonic motion

    To be Simple Harmonic motion, the force needs to obey Hookes Law

  • Amplitude, Period and Frequency Amplitude, A

    The amplitude is the maximum position of the object relative to the equilibrium position

    In the absence of friction, an object in simple harmonic motion will oscillate between A on each side of the equilibrium position

    The period, T, is the time that it takes for the object to complete one complete cycle of motion From x = A to x = - A and back to x = A

    The frequency, , is the number of complete cycles or vibrations per unit time

  • Acceleration of an Object in Simple Harmonic Motion

    Newtons second law will relate force and acceleration

    The force is given by Hookes Law

    F = - k x = m a or a = -kx / m

    The acceleration is a function of position Acceleration is not constant and therefore the uniformly

    accelerated motion equation cannot be applied

  • Elastic Potential Energy The energy stored in a stretched or compressed spring or other elastic material is called elastic potential energy

    PEs = kx2

    The energy is stored only when the spring is stretched or compressed

    Elastic potential energy can be added to the statements of Conservation of Energy and Work-Energy

  • Energy in a Spring Mass System

    Consider a situation:

    1. A block sliding on a frictionless system collides with a light spring

    2. The block attaches to the spring

  • Energy Transformations

    The block is moving on a frictionless surface The total mechanical energy of the system is the kinetic energy of the block

  • Energy Transformations, 2

    The spring is partially compressed The energy is shared between kinetic energy and elastic

    potential energy The total mechanical energy is the sum of the kinetic energy

    and the elastic potential energy

  • Energy Transformations, 3

    The spring is now fully compressed The block momentarily stops The total mechanical energy is stored as elastic potential energy of the spring

  • Energy Transformations, 4

    When the block leaves the spring, the total mechanical energy is in the kinetic energy of the block

    The spring force is conservative and the total energy of the system remains constant

  • Velocity as a Function of Position Conservation of Energy allows a calculation of the velocity of the object at any position in its motion

    Speed is a maximum at x = 0 Speed is zero at x = A The indicates the object can be traveling in either

    direction

    ( )22 xAmkv =

  • 25

    When a mass-spring system is oriented vertically, it will exhibit SHM with the same period and frequency as a horizontally placed system.

    A Vertical Mass and Spring

    At equilibrium position (b)

    0=+= mgkdFy

    )(, ydkF yspring =

    kymgkykdmgydkFy === )(

    At (c), displaced the equilibrium by y

    kyFy =

  • Example: oscillator A block of mass 1.00 kg is attached to a spring with a spring constant of 30.0 N/m, which is stretched 0.200 m from its equilibrium position. How much work must be done to stretch it an additional 0.100 m? What maximum speed will the block attain if the system is then let go?

  • Simple Harmonic Motion and Uniform Circular Motion A ball is attached to the rim of a turntable of radius A

    The focus is on the shadow that the ball casts on the screen

    When the turntable rotates with a constant angular speed, the shadow moves in simple harmonic motion

  • Period and Frequency from Circular Motion

    Period

    This gives the time required for an object of mass m attached to a spring of constant k to complete one cycle of its motion

    Frequency

    Units are cycles/second or Hertz, Hz The angular frequency is related to the frequency

    km2T =

    mk

    21

    T1

    ==

    mk2 ==

  • Motion as a Function of Time

    Use of a reference circle allows a description of the motion

    x = A cos (2t) x is the position at time t x varies between +A and -A

  • Graphical Representation of Motion

    When x is a maximum or minimum, velocity is zero

    When x is zero, the velocity is a maximum

    When x is a maximum in the positive direction, a is a maximum in the negative direction

  • Verification of Sinusoidal Nature

    This experiment shows the sinusoidal nature of simple harmonic motion

    The spring mass system oscillates in simple harmonic motion

    The attached pen traces out the sinusoidal motion

  • 32

    Example: The period of oscillation of an object in an ideal mass-spring system is 0.50 sec and the amplitude is 5.0 cm. What is the speed at the equilibrium point?

    Idea: lets use energy conservation: at equilibrium x = 0:

    222

    21

    21

    21 mvkxmvUKE =+=+=

    Since E=constant, at equilibrium (x = 0) the KE must be a maximum.

    Thus, v = vmax = A.

    ( )( ) cm/sec 8.62rads/sec 6.12cm 5.0 and

    rads/sec 6.12s 50.0

    22

    ===

    ===

    Av

    T