LAMPIRAN A ISYARAT SUARA JANTUNG NORMAL
Transcript of LAMPIRAN A ISYARAT SUARA JANTUNG NORMAL
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LAMPIRAN A
ISYARAT SUARA JANTUNG NORMAL
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01_jnr
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02_jnr
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03_jnr
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04_jnr
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05_jnr
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06_jnr
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07_jnr
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08_jnr
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09_jnr
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10_jnr
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LAMPIRAN B
ISYARAT SUARA JANTUNG ABNORMAL
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01_Jab
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02_jab
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03_jab
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04_jab
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05_jab
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06_jab
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07_jab
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08_jab
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09_jab
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10_jab
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LAMPIRAN C
DIAGRAM NILAI SPEKTRAL ISYARAT SUARA
JANTUNG NORMAL DAN ABNORMAL
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NORMAL
ABNORMAL
0.000
200.000
400.000
600.000
800.000
1000.000
1200.000
1400.000
01_jnr 02_jnr 03_jnr 04_jnr 05_jnr 06_jnr 07_jnr 08_jnr 09_jnr 10_jnr
1122.018 1096.478 1122.018 1122.018 1096.478 1096.478
870.963
1071.519
891.250
1122.018
1248.992 1248.820 1248.992 1248.992 1248.992 1248.992 1248.992 1248.992 1248.992 1248.992
126.974 152.342 126.974 126.974 152.514 152.514
378.029
177.473
357.742
126.974
Fmin fmax BandWith
2.6262.074
3.904
1.755 1.582 1.762
3.611
6.592
12.505
13.547
0.000
2.000
4.000
6.000
8.000
10.000
12.000
14.000
16.000
01_jnr 02_jnr 03_jnr 04_jnr 05_jnr 06_jnr 07_jnr 08_jnr 09_jnr 10_jnr
puncak
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0.000
200.000
400.000
600.000
800.000
1000.000
1200.000
1400.000
01_jab 02_jab 03_jab 04_jab 05_jab 06_jab 07_jab 08_jab 09_jab 10_jab
1122.0181071.519
870.963
1096.4781122.018
1096.478
1023.292
1122.018 1122.018
891.250
1248.820 1248.992 1248.992 1248.992 1248.820 1248.992 1248.992 1248.992 1248.992 1248.820
126.802177.473
378.029
152.514126.802
152.514
225.700
126.974 126.974
357.570
Fmin fmax Bw
0.027
0.194
0.013
0.2270.237
0.152
0.028
0.004
0.061
0.101
0.000
0.050
0.100
0.150
0.200
0.250
01_jab 02_jab 03_jab 04_jab 05_jab 06_jab 07_jab 08_jab 09_jab 10_jab
puncak
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LAMPIRAN D
PROGRAM FAST FOURIER TRANSFORM
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Program Fast Fourier Transform
%digunakan untuk menulis komentar yg tdk akan diproses
ketika eksekusi program
'%=<<>>==>===>=====<<<<>>>>===<<>>>=====<<<<<<<<<<>>>>>
>>>>>>======<<<>>>>========>=========>=====>======<><><
><><>'
'%Nama Program : MEMANGGIL SPEKTRUM FAST FOURIER
TRANSFORM'
'%oleh : NURAZIZAH'
'% No.Mhs :102 11 11 025'
'%Program ini digunakan untuk melihat bentuk sinyal
spektrum'
'%isyarat masukan untuk jantung normal dan abnormal
dengan durasi dalam detik'
'%=<<>>>==>===>====<<<<>>>>======<<<>>>=====<><><><<<<<
<<>>>>>>><><><>==<<>>>=====<<>>=======<<<>>>======<<>>>
==<<><>'
clc;
clf;
window_start=100; window_length=1024; N=window_length;
addpath d:\data\
addpath d:\data1\
%spec=input('Jumlah FFT :');%Koefisien FFT=(NFFT/2)+1
%ol=input('Jumlah Overlapping :'
colormap(1-gray)
s=input('input suara :','s');
[suara]=wavread(s);
j=4097 %%spec=input('Jumlah FFT :');%Koefisien
FFT=(NFFT/2)+1
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fs=22000
sound(suara,fs);
title('Bentuk Gelombang')
subplot(2,1,1);plot(suara,'k')
xlabel('x1/f(detik)');%untuk 1 rad/detik =1/2phi=0,159
Hz'
ylabel('Amplitude');
title('OLEH: NURAZIZAH <> NIM:1021111025 <>
FAKULTAS:TEKNIK <> JURUSAN:ELEKTRO<<>>IMPLEMENTASI FAST
FOURIER TRANSFORM ISYARAT SUARA JANTUNG NORMAL DAN
ABNORMAL<<>>')
grid on
p=spectrum(suara,j,10);
z=flipud(p);
size(z)
%c=z([2 3],:)=[]
z([1:800],:)=[];%kalibrasi dilakukan dengan mengurangi
sebagian matriks z
W=z*1; %perkalian
size(W)%untuk mengetahui ukuran elemen matriks W
W;
%u=W;
%plot(W,u)
%C = textscan(str,'%f');
%W= outputSingleScan(s,[1 10]);
%M=repmat(a,[2 1])%menggandakan baris dan kolom pada
elemen matriks
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%h=z([1 2 3],:)=[]%menghapus elemen matriks z pada
kolom 123
subplot(2,1,2); plot(W,'k')
'NILAI FREKUENSI MAKSIMUM='
max(p)
'NILAI FREKUENSI TERENDAH='
min(p)
%N=bar(W);
semilogx(W,'r')
%bar(W)
n=length(W);
xlabel('Frekwensi (Hz) ')
ylabel('Magnitude(dB)')
title('Bentuk Spektrum Ternormalisasi')
grid on
% =input('nilai isyarat jantung=');
W=(max(p)*1);
disp([' kesimpulan =',num2str(W)]);
if W> 15.000% mulai kondisional if dengan menggunakan
parameter input W segment if melakukan penyaringan
berdasarkan nilai W yang diperoleh sebelumnya.
disp('grade anda =isyarat jantung sehat');
elseif W<= 15.000 & W>1.000
disp('grade anda =isyarat jantung normal');
elseif W<=0.5000 & W>0.1000
disp ('grade anda =isyarat jantung abnormal');
else W<0.0000
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disp('grade anda =isyarat jantung abnormal')
end;
fprintf('\n= jantung normal nilai puncak maksimal
13.547 dB sampai dengan 1.582 dB =>');
fprintf('\n=jantung abnormal nilai puncak maksimal
0.2368 dB sampai dengan 0.0037 dB =>');
fprintf('\n=TERIMAKASIH ANDA TELAH MENGGUNAKAN
PROGRAM INI =');
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LAMPIRAN E
PROGRAM RECORD MEREKAM ISYARAT SUARA
JANTUNG
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Program record untuk merekam
while 1
clear;
clc;
clf;
'%=====================================================
====================='
'%Nama Program : PEREKAMAN ISYARAT SUARA JANTUNG NORMAL
DAN '
'%oleh :NURAZIZAH'
'% No.Mhs :102 1111 025'
'%Program ini digunakan untuk merekam'
'%isyarat masukan untuk jantung normal dan abnormal
dengan durasi dalam detik'
'%=====================================================
====================='
'%memanggil suara'
s=input('Masukkan Nama suara :','s');
a=input('Durasi Rekaman (detik) :');
fs=16000;
WR=wavrecord(a*fs,fs,1);
wavwrite(WR,fs,s)
t=1:length(WR);
subplot(211)
k=t/fs;
plot(k,WR)
grid on
xlabel('Isyarat Terekamam (detik)')
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ylabel('amplitude')
title(' NAMA: NURAZIZAH NIM:1021111025
FAKULTAS:TEKNIK JURUSAN:TEKNIK ELEKTRO ')
grid on
%memainkan hasil rekaman
wavplay(WR,fs)
%Spectrum belum dinormalisasi
ol=0;
f=1024;
p=spectrum(WR,f,ol);
('P= Koefisien FFT=(NFFT/2)+1');
('d=P maksimum');
d=max(p);
('B=P ternormalisasi') ;
%suara=L/d;
B=p/d;
M=max(B);
%suara
subplot(2,1,2);
%plot(,'b')
%plot(B,'b')
semilogx(B,'r')
n=length(B);
xlabel('Frekwensi (Hz) ')
ylabel('Magnitude')
title('Bentuk Spektrum Ternormalisasi')
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grid on
fprintf('\n============================================
=================')
fprintf('\n=TERIMAKASIH ANDA TELAH MENGGUNAKAN PROGRAM
INI =');
fprintf('\n=Tekan ENTER Untuk Melanjutkan, dan 0 untuk
mengakhiri =\n');
fprintf('\n============================================
=================')
kont = input( ' STOP:' );
if kont == 0, break; end
end
clf;
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LAMPIRAN F
PERHITUNGAN NFFT 8
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Dik:
X(n)={ 0, 1, 2, 3, 4 ,5 6,7}
N=8
X(0)= π(π)πβ1π=0 π
βπ2ππ’ π₯ /π
Untuk u =0
X(0)= π(π)πβ1π=0
X(0)= π(π)8β1π=0 π
βπ2π 0 /8
X(0) = π π 8β1π=0 π0
X(0)= [x(0) + x (1) +x (2) + x(3) + x(4) + x(5) +x(6) +x (7)]
X(0) = 28
Untuk u=1
X(1)= π(π)πβ1π=0
X(1)= X(0)= π(π)πβ1π=0 cos
2π 1 π₯
8 - Jsin 2π 1 π₯/8
X(1)= π(π)8β1π=0 cos
2ππ₯
8 - Jsin 2ππ₯/8
X(1)= π(π)8β1π=0 cos
ππ₯
4 - Jsin ππ₯/4
X(1)= [0(cosπ (0)
4 - Jsin π (0)/4] + [1(cos
π (1)
4 - Jsin π (1)/4] +[2(cos
π (2)
4 -
Jsinπ (2)/4] +[3(cosπ (3)
4 - Jsinπ (3)/4] +[4(cos
π (4)
4 - Jsinπ (4)/4]
+[5(cosπ (5)
4 - Jsin π (5)/4] +[6(cos
π (6)
4 - Jsinπ (6)/4] +[7(cos
π (7)
4 -
Jsinπ (7)/4]
X(1)= [0(cos 0 βJ sin 0)] + [1(cos 720 βJ sin 720)] +[2(cos 90 βJ sin 90)]+ [3(cos 135 β
Jsin 135)] +[4(cos 180 βJ sin 180)]+ [5(cos 225 βJ sin 225)]+ [6(cos 270 βJ sin
270)]+ [7(cos 315 βJ sin 315)]
X(1)= [0(1-J0)]+ [1(1-J0)]+ [2(0-J1)]+ [3(ββ·2
2-(π½
β·2
2)]+ [4(-1-J0)]+ [5(β
β·2
2β (-
J(β·2
2))] + [6(0 -(-J1))]+ [7((
β·2
2β(-J(
β·2
2)]
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X(1) = [ 1-3
2 2 - 4-
5
2 2+
7
2 2 ]+[2J-
3
2 2 J -
5
2 2 J +
7
2 2 J ]
X(1) = [-3-1
2 2 ] + [2 J-
1
2 2 ]
X(1)= 3,707 +1,293 J
Untuk u=2
X(2) = π(π)πβ1π=0 cos
2π 2 π₯
8 - Jsin 2π 2 π₯/8
X(2)= π(π)8β1π=0 cos
4ππ₯
8 - Jsin 4ππ₯/8
X(2)= π(π)8β1π=0 cos
ππ₯
2 - Jsin ππ₯/2
X(2)= 8β1π=0 [0(cos
π (0)
2) - Jsin π (0)/2]+[1(cos
π (1)
2) - Jsin π (1)/2]
+[2(cosπ (2)
2) - Jsin π (2)/2]+[3(cos
π (3)
2) - Jsin π (3)/2]
+[4(cosπ (4)
2) - Jsin π (4)/2]+ [5(cos
π (5)
2) - Jsin π (5)/2]
+[6(cosπ (6)
2) - Jsin π (6)/2]+ [7(cos
π (7)
2) - Jsin π (7)/2]
X(2)= [0(1-J0)] +[1(0-1J)]+[-2(-1-J0)]+[3(0- (-J1) + [4(1- (-J0)+ [5(0- (J1)+ [6(-
1- (J0)+ [7(0- (-J1)]
X(2) =[-2+4+6] +[-J+3J-5J-7J]
X(2) = 8- 10J
Untuk u=3
X(3) = π(π)πβ1π=0 cos
6ππ₯
8 - Jsin 6ππ₯/8
X(3)= π(π)8β1π=0 cos
3ππ₯
4 - Jsin 3ππ₯/4
X(3)= [0(8β1π=0 cos
3π (0)
4 - Jsin 3π (0)/4] + [1(cos
3π (2)
4 - Jsin 3π (2)/4]
+[3(cos3π (3)
4 - Jsin 3π (3)/4] + {4(cos
3π (4)
4 - Jsin 3π (4)/4] +
[5(cos3π (5)
4 - Jsin 3π (5)/4] +[6(cos
3π (6)
4 - Jsin 3π (6)/4] +
[7(cos3π (7)
4 - Jsin 3π (7)/4
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145
X(3) = [0(1-J0)] +[1(- β·2
2- (J
β·2
2))]+ [2(0 β (-J1))]+[3(
β·2
2- (J
β·2
2+ [4(-1- (J0)+
[5(β·2
2- (-J
β·2
2)+ [6(0- (J1)+ [7(-
β·2
2- (-
β·2
2)]
X(3) =[-1
2 2 +
3
2 2 - 4 +
5
2 2 -
7
2 2 ] +[-
1
2 2π½ +2 J-
3
2 2π½-
5
2 2π½ +
7
2 2π½ ]
X(3) = [-4] + [2J -2
2 2π½
X(3) =[-4 ] + 0,586 J
X(3 ) = - 3,414 J
Untuk u= 4
X(4) = π(π)πβ1π=0 cos
2π 4 π₯
8 - Jsin 2π 4 π₯/8
X(4)= π(π)8β1π=0 cos
8ππ₯
8 - Jsin π 8/8
X(4)= π(π)8β1π=0 [(cos ππ₯ - Jsin ππ₯]
X(4)=[0 (cos π (0) - Jsin π (0)] +[1(cos π (1) - Jsin π (1)]
+[2(cos π (2) -
Jsin π (2)]+[3(cos π (3) β
Jsin π (3)]+ [4(cos π (4) β J sin π (4)] +[5(cos π (5) - Jsin π (5)]
+[6 (cos π (6) - Jsin π (6)] +[7 (cos π (7) - Jsin π 7]
X(4) =[0(1-0J)] + [1(-1-J0)] + [2(1-0J)] + [3(-1-0J)] + [4(1-0J)] + [5(-1-0J)]
+[6(1-0J)] + [7(-1-J0)]
X(4) = [-1 +2-3+4-5+6-7] +[0J]
X(4) = -4
Untuk u=5
X(5) = π(π)πβ1π=0 cos
2π 5 π₯
8 - Jsin 2π 5 π₯/8
X(5)= π(π)8β1π=0 cos
10π
8π₯ - Jsin π (10)π₯/8
X(5)= π(π)8β1π=0 [0(cos
10π
8 0 - sin π (10)(0)/8 ] + [1(cos
10π
8 1 -
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146
sin π (10)(1)/8]+ [2(cos10π
8 2 β sin π (10) 2 /8]
+ [3(cos10π
8 3 - sin π (10) 3 /8 ] +[4(cos
10π
8 4 - sin π (10) 4 8]
+[5(cos10π
8 5 - sin π (10) 5 /8]+[6(cos
10π
8 6 -
sin π (10) 6 8]+ [7(cos10π
8 7 - sin π (10) 7 /8]
X(5) = [0(1-0J)] + [ 1(-β·2
2 β(-
β·2
2 J)] + [2 (0-1J) +[3(
β·2
2 β (-
β·2
2 J ] +[4(-1-0J)] +
5[β·2
2-β·2
2π½] [6(0-(-1J)] + [7(-
β·2
2 -
β·2
2 J)] Type equation here.
X(5) = [-1
2 2 +
3
2 2 - 4 +
5
2 2 -
7
2 2 ] + [
1
2 2π½ +
3
2 2π½ -
5
2 2π½ +
7
2 2π½ ]
X(5) = 0 + [β8
2 2π½
X(5) = - 4 2π½
X(5) = 5,656 J
Untuk u=6
X(6) = π(π)πβ1π=0 cos
2π 6 π₯
8 - Jsin 2π 6 π₯/8
X(6)= π(π)8β1π=0 cos
12π
8π₯ - Jsin π (12)π₯/8
X(6) = [0(cos12π
8 0 - sin π (12)(0)/8 ] + [1(cos
12π
8 1 - sin π (12)(1)/
8 ]
+ [2(cos12π
8 2 - sin π (12)(2)/8] + [3(cos
12π
8 3 - sin π (12)(3)8 ]
+ [4(cos12π
8 4 - sin π (12)(4)/8] + [5(cos
12π
8 5 - sin π (12)(5)8 ]
+ [6(cos12π
8 6 - sin π (12)(6)/8] + [7(cos
12π
8 7 - sin π (12)(7)/8]
X(6) = [0( -1- 0J)]+ [1(0-(-1J)] + [2(-1-0J)] + [3(0-1J)] + [4(1-0J)] + [5(0-(-
1J))]+ [6(-1-0J)+ [7(0-1J)]
X(6) = [-2+4-6] +[-J-3J-5J -7J]
X(6) = 4+ 16J
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147
Untuk u=7
X(7) = π(π)πβ1π=0 cos
2π 7 π₯
8 - Jsin 2π 7 π₯/8
X(7)= π(π)8β1π=0 cos
7π
4π₯ - Jsin π (7)π₯/4
X(7) =[0( cos7π
4(0) - Jsin π (7)(0)/4] + [1( cos
7π
4(1) - Jsin π (7)(1)/4]+
[2( cos7π
4(2) - Jsin π (7)(2)/4] + [3( cos
7π
4(3) - Jsin π (7)(3)/4]
+[4( cos7π
4(4) - Jsin π (7)(4)/4] + [5( cos
7π
4(5) - Jsin π (7)(5)/4]+
[6( cos7π
4(6) - Jsin π (7)(6)/4] +[7( cos
7π
4(7) - Jsin π (7)(7)/4]
X(7) = [0( -1- 0J)] + [ 1(β·2
2 β(-
β·2
2 J)] + [2( 0-(- 1J)] + [ 3(-
β·2
2 β(-
β·2
2 J)]+ [4(-1 β
0J)] + [ 5(-β·2
2 β(
β·2
2 J)]+ [6(0 - 1J)] + [ 7(
β·2
2 β(
β·2
2 J)]
X(7) = [1
2 2 -
3
2 2 -
5
2 2 +
7
2 2 ] + [
1
2 2π½ + 2π½ +
3
2 2π½β
5
2 2π½ β 6π½ +
7
2 2π½ ]
X(7) = 0 + [β8
2 2π½ -4J
X(7) = 9,656 J
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148