hidraulika vezba 3
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Transcript of hidraulika vezba 3
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7/24/2019 hidraulika vezba 3
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Zadatak 3. Kruti udar
= 9.1
= 8.9
20 0.031
= 0.2 ! 0.02"
#= 2$" !
9.1 !
2 !
3
%= 0.02&
1' (ro!ena srednje )r*ine vode u +evi sa *ane!arenje! trenja
0.0$1&
".&0s
,r= !2 ,+= !2
%ef=
-r=
-*=
*at
=
ust
= !3/s
0=
( ) 23
2
ust
ef
ZRC Q
DL
gA
=
( )ZRCust
L
gA
T
Q=
0
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2' (ro!ena srednje )r*ine vode u +evi sa trenje!
n t t
45 s5 s5 !5 !5 65
0 0 9.1 2 0 100
1 2 2 9.1 2 0.01$ "3.37
2 2 7 9.1 2 0.032 78.&"
3 2 $ 9.1 2 0.077 28.9$
7 2 8 9.1 2 0.0&2 1&."$
& 2 10 9.1 2 0.0&" 8.02
$ 2 12 9.1 2 0.0&9 3.91
" 2 17 9.1 2 0.0$0 1.8"
8 2 1$ 9.1 2 0.0$1 0.88
3' re!e pranjena re*ervoara do kote 9:0! ;!ode< kva*i 4 usta
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7' re!e pranjena re*ervoara do kote 9:0! ;!ode< kruto udara'
n t t
45 s5 s5 !5 !5
0 0 9.1 2 0
1 & & 9.1 2 0.071
2 & 10 9.09 2 0.0$7
3 & 1& 9.0" 2 0.0$1
7 & 20 9.0$ 2 0.0$2
& & 2& 9.07 2 0.0$1
$ & 30 9.03 2 0.0$1" & 3& 9.01 2 0.0$1
8 & 70 9.00 2 0.0$1
!ate!ati>ki
nu!eri>ki !
?e*ervoar se ispra*ni do kote 9! *a@ t = 70 s
-r
-*
n
!3/s5
=
DgA ef
C
ZR2
2
( )
=
=
QQDL
gA
dt
dQ
Qdt
d
ef
ZR
C
3
2
+=
=
++
+
nnef
Z
n
R
n
RC
nn
n
R
nR
nR
QQDL
gA
t
QQ
QAt
3
11
1
2
2
1
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0 2 7 $ 8 10 12 17
0.0000
0.0100
0.0200
0.0300
0.0700
0.0&00
0.0$00
0.0"00
Dijagram promene protoka
t [s]
Q [m3/s]
0 & 10 1& 20 2& 30 3&
Dijagram promene - kote pri pranjenju r
Kva*i 4 usta
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0 & 10 1& 20 2& 30 3&
0
Kva*i 4 usta
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>enja'
ode