Gording Memed

PERHITUNGAN GORDING DAN SAGROD

A. DATA BAHAN

= 240 Mpa

= 370 Mpa

= 70 MpaE = 2100000 Mpa

B. DATA PROFIL

Lip Channel C 200.75.20.3,2

luas penanmpang cnp A = 61.9 cm2berat penampang cnp g = 34.6 kg/mdimensi cnp Iy = 306 cm4

Ix = 4180 cm4iy = 2.71 cm ix = 7.77 cm

wy = 16.8 cm3wx = 72.1 cm3

jarak gording s = 1.35 m

= 7 m

= 2.33 mα = 18 ⁰

rad = 0.31

PEMBEBAN PADA GORDING

Jarak Gording / s =1. Beban Mati (dead load)

- Berat Sendiri Gording =- Penutup Atap Seng (dr Brosur) 2.65 * 1,35 =

Jumlah =- Beban Alat - Alat pengikat 10% * 11.08 =

QD =

2. Beban Hidup (live load)

fy

fu

fr

L1

L2

- q Hujan =- Beban Merata Akibat Air Hujan

20 X 1.35 m =

- Beban Terpusat Akibat Pekerja =

3. Beban Anginbangunan direncanakan jauh dari pantai sehingga diambil tekanan angin 25 kg/m2 (PPIUG pasal 4.2)

Tekanan Angin =

PEMBEBANAN DENGAN KOEFISIEN ANGIN KONDISI 1- Angin Tekan (+0.8) = Tekanan Angin x Jarak Gording x Koefesien Angin

Koefesien Angin 0.8 =koefisien angin 0 =

E. PERHITUNGAN MOMEN

1. Beban Mati

- =

- =

2. Beban Hidup

- =

- =

3. Beban Angin

- =

- =

Beban kombinasi

1 1.2D + 1.6L2 1.2D + 1.6L + 0.8W3 0.9D + 1.3W

1 1.2D + 1.6L

Pembebanan

QL

PL

Mxd = 1/8 (QD x cosα ) x L2

Myd = 1/8 (QD x sinα ) x L/32

Mxl = 1/8 (QL x cosα ) x L2

Myl = 1/8 (QL x sinα ) x L/32

Mxw = 1/8 (QW) x L2

Mxw = 1/8 (QW ) x L2

Sumbu X : Sumbu Y :qd = 39.94 kg/m qd =ql = 95.11 kg/m ql =

qw1 = 27.00 kg/m qw =qw2 = 0.00 kg/m

= == 200.10 kg/m =

= == 65.02 kg/m =

LENDUTAN

Lendutan ijin L/250 (PPBBI) 0.9333333 cm

Lendutan

fx = 5 x qux x384 E x Ix

= 5 x 2.00 x 700 4

384 x 2100000 x 4180

= 0.71 cm 0.0016 cm =

fy = 5 x quy x384 E x Iy

= 5 x 0.65 x 700 4

384 x 2100000 x 306

= 3.16 cm 0.01 cm =

TEGANGAN YANG TERJADI

Mux Muy

Wx Wy

1962.52593437 < 1600

qux 1,2 qd + 1,6 ql Mux

quy 1,2 qd + 1,6 ql Muy

L4

L4

σ =

σ =

2 1.2D + 1.6L + 0.8W

1. Beban MerataSumbu X : Sumbu Y :

qd = 39.94 kg/m qd =ql = 95.11 kg/m ql =

qw1 = 27.00 kg/m qw =qw2 = 0.00 kg/m

= == 221.70 kg/m =

= == 200.10 kg/m =

= == 65.02 kg/m =

LENDUTAN


Lendutan


= 5 x 2.22 x 700 4

384 x 2100000 x 4180

= 0.79 cm 0.002 cm =


= 5 x 0.65 x 700 4

384 x 2100000 x 306

= 3.16 cm 0.01 cm =

qux1 1,2 qd + 1,6 ql + 0,8 qw Mux1

qux2 1,2 qd + 1,6 ql + 0,8 qw Mux2

quy 1,2 qd + 1,6 ql + 0,8 qw Muy

L4

L4


Mx My

Wx Wy

1992.48432549

20.9D + 1.3W


qd = 39.94 kg/m qd =ql = 95.11 kg/m ql =

qw1 = 27.00 kg/m qw =qw2 = 0.00 kg/m

= == 71.05 kg/m =

= == 35.95 kg/m =

= == 11.68 kg/m =

LENDUTAN


Lendutan


= 5 x 0.71 x 700 4

384 x 2100000 x 4180

= 0.25 cm 0.001 cm =


σ =

σ =

qux1 0.9 qd + 1.3 qw Mux1

qux2 0.9 qd + 1.3 ql Mux2

quy 0.9 qd + 1.3 ql Muy

L4

L4

= 5 x 0.12 x 700 4

384 x 2100000 x 306

= 0.57 cm 0.001 cm =


Mx My

Wx Wy

401.235142569

PERHITUNGAN PEMBEBANAN DENGAN KOEFISIEN ANGIN KONDISI 2

Beban Anginbangunan direncanakan jauh dari pantai sehingga diambil tekanan angin 25 kg/m2 (PPIUG pasal 4.2)

Tekanan Angin =

koefisien angin terbuka dalam kondisi 1

- Angin Hisap 1 (-1.2) = Tekanan Angin x Jarak Gording x Koefesien Angin- Angin Hisap 2 (-0.4) = Tekanan Angin x Jarak Gording x Koefesien Angin

Koefesien Angin 1.2 =koefisien angin 0.4 =


1. Beban Mati

- =

- =

2. Beban Hidup

- =

- =

σ =

σ =





3. Beban Angin

- =

- =

Beban kombinasi

1 1.2D + 1.6L2 1.2D + 1.6L + 0.8W3 0.9D + 1.3W

1 1.2D + 1.6L


qd = 39.94 kg/m qd =ql = 95.11 kg/m ql =

qw1 = 40.50 kg/m qw =qw2 = 13.50 kg/m

= == 200.10 kg/m =

= == 65.02 kg/m =

LENDUTAN


Lendutan


= 5 x 2.00 x 700 4

384 x 2100000 x 4180

= 0.71 cm 0.002 cm =

Mxw = 1/8 (QW) x L2

Mxw = 1/8 (QW ) x L2

qux 1,2 qd + 1,6 ql Mux

quy 1,2 qd + 1,6 ql Muy

L4


= 5 x 0.65 x 700 4

384 x 2100000 x 306

= 3.16 cm 0.01 cm =


Mx My

Wx Wy

1962.52593437

2 1.2D + 1.6L + 0.8W

1. pembebananSumbu X : Sumbu Y :

qd = 39.94 kg/m qd =ql = 95.11 kg/m ql =

qw1 = 40.50 kg/m qw =qw2 = 13.50 kg/m

= == 232.50 kg/m =

= == 210.90 kg/m =

= == 65.02 kg/m =

LENDUTAN


Lendutan

fx = 5 x qux x

L4

σ =

σ =

qux1 1,2 qd + 1,6 ql + 0,8 qw Mux1

qux2 1,2 qd + 1,6 ql + 0,8 qw Mux2

quy 1,2 qd + 1,6 ql + 0,8 qw Muy

L4

fx =384

xE x Ix

= 5 x 2.32 x 700 4

384 x 2100000 x 4180

= 0.83 cm 0.002 cm =


= 5 x 0.65 x 700 4

384 x 2100000 x 306

= 3.16 cm 0.01 cm =


Mx My

Wx Wy

2007.46352105

20.9D + 1.3W


qd = 39.94 kg/m qd =ql = 95.11 kg/m ql =

qw1 = 40.50 kg/m qw =qw2 = 13.50 kg/m

= == 88.60 kg/m =

= == 53.50 kg/m =

= == 11.68 kg/m =

L4

σ =

σ =

qux1 0.9 qd + 1.3 qw Mux1

qux2 0.9 qd + 1.3 ql Mux2

quy 0.9 qd + 1.3 ql Muy

LENDUTAN


Lendutan


= 5 x 0.89 x 700 4

384 x 2100000 x 4180

= 0.32 cm 0.001 cm =


= 5 x 0.12 x 700 4

384 x 2100000.00 x 306

= 0.57 cm 0.00 cm =


Mx My

Wx Wy

425.576335357

L4

L4

σ =

σ =


1.35 m

34.60 kg/m3.58 kg/m

38.18 kg/m3.81775 kg/m

42.00 kg/m = 39.94 kg/mQDy = 12.98 kg/m

QDx

20 kg/m2

27 kg/m

100 kg QLx 95.1056516 kg/m Qly 30.901699 kg/m

bangunan direncanakan jauh dari pantai sehingga diambil tekanan angin 25 kg/m2 (PPIUG pasal 4.2)

25(PPIUG Pasal 4.2.1)

Angin Tekan (+0.8) = Tekanan Angin x Jarak Gording x Koefesien Angin27 kg/m0 kg/m

244.63 kgm

8.81 kgm

582.52 kgm

20.97 kgm

165.38 kgm

0.00 kgm

kg/m2

Sumbu Y :12.98 kg/m30.90 kg/m

0.00 kg/m

1225.59 kgm

44.13 kgm

1 x qux x L348 E x Ix

1 x 2.00 x 700 3

48 x 2100000 x 4180

0.71 cm <

1 x quy x L348 E x Iy

1 x 0.65 x 700 3

48 x 2100000 x 306

3.17 cm <

1,2 Md + 1,6 Ml

1,2 Md + 1,6 Ml


0.00 kg/m

1247.19 kgm

1225.59 kgm

44.13 kgm


1 x 2.22 x 700 3

48 x 2100000 x 4180

0.79 cm


1 x 0.65 x 700 3

48 x 2100000 x 306

3.17 cm

1,2 Md + 1,6 Ml + 0,8 Mw

1,2 Md + 1,6 Ml + 0,8 Mw

1,2 Md + 1,6 Ml + 0,8 Mw


0.00 kg/m

255.27 kgm

220.17 kgm

7.93 kgm


1 x 0.71 x 700 3

48 x 2100000 x 4180

0.25 cm


0.9 Md + 1.3 Mw

0.9 Md + 1.3 Mw

0.9 Md + 1.3 Mw

1 x 0.12 x 700 3

48 x 2100000 x 306

0.57 cm


25(PPIUG Pasal 4.2.1)

Angin Hisap 1 (-1.2) = Tekanan Angin x Jarak Gording x Koefesien AnginAngin Hisap 2 (-0.4) = Tekanan Angin x Jarak Gording x Koefesien Angin

40.5 kg/m13.5 kg/m

244.63 kgm

8.81 kgm

582.52 kgm

20.97 kgm

kg/m2

248.06 kgm

82.69 kgm


0.00 kg/m

1225.59 kgm

44.13 kgm


1 x 2.00 x 700 3

48 x 2100000 x 4180

0.71 cm

1,2 Md + 1,6 Ml

1,2 Md + 1,6 Ml


1 x 0.65 x 700 3

48 x 2100000 x 306

3.17 cm


0.00 kg/m

1257.99 kgm

1236.39 kgm

44.13 kgm

1 x qux x L3

1,2 Md + 1,6 Ml + 0,8 Mw

1,2 Md + 1,6 Ml + 0,8 Mw

1,2 Md + 1,6 Ml + 0,8 Mw

48x

E x Ix

1 x 2.32 x 700 3

48 x 2100000 x 4180

0.83 cm


1 x 0.65 x 700 3

48 x 2100000 x 306

3.17 cm


0.00 kg/m

272.82 kgm

237.72 kgm

7.93 kgm

0.9 Md + 1.3 Mw

0.9 Md + 1.3 Mw

0.9 Md + 1.3 Mw


1 x 0.89 x 700 3

48 x 2100000 x 4180

0.32 cm


1 x 0.12 x 700 3

48 x 2100000 x 306

0.57 cm


A. DATA BAHAN

= 240 Mpa

= 370 Mpa

= 70 MpaE = 2100000 Mpa

B. DATA PROFIL

Lip Channel C 125.50.20.4,5

A = 11.81 cm4g = 9.27 kg/m

Iy = 87.5 cm4Ix = 721 cm4iy = 2.71 cm ix = 7.77 cm

wy = 16.8 cm3wx = 72.1 cm3

jarak gordi s = 1.35 m

= 7 m

= 2.33 mα = 18 ⁰

rad = 0.31

PEMBEBAN PADA GORDING

Jarak Gording / s = 1.35 m1. Beban Mati (dead load)

- Berat Sendiri Gording = 9.27 kg/m- Penutup Atap Seng (dr Brosur) 2.65 * 1,35 = 3.58 kg/m

Jumlah = 12.85 kg/m- Beban Alat - Alat pengikat 10% * 11.08 = 1.28475 kg/m

= 14.13 kg/m

2. Beban Hidup (live load)

- q Hujan = 20 kg/m2- Beban Merata Akibat Air Hujan

20 X 1.35 m = 27 kg/m

fy

fu

fr

L1

L2

QD

QL

- Beban Terpusat Akibat Pekerja = 100 kg

3. Beban Anginbangunan direncanakan jauh dari pantai sehingga diambil tekanan angin 25 kg/m2 (PPIUG pasal 4.2)

Tekanan Angin = 25(PPIUG Pasal 4.2.1)

PEMBEBANAN DENGAN KOEFISIEN ANGIN KONDISI 1- Angin Tekan (+0.8) = Tekanan Angin x Jarak Gording x Koefesien Angin

Koefesien Angin 0.8 = 27 kg/mkoefisien angin 0 = 0 kg/m


1. Beban Mati

- = 82.32 kgm

- = 2.96 kgm

2. Beban Hidup Merata

- = 157.28 kgm

- = 5.66 kgm

3. Beban Terpusat

- = 166.43 kgm

- = 18.00 kgm

4. Beban Angin

- = 165.38 kgm

- = 0.00 kgm

Beban kombinasi

1 1.2D + 1.6L2 1.2D + 1.6L + 0.8W3 0.9D + 1.3W

1 1.2D + 1.6L


PL

kg/m2





Mxl = 1/4 (PL x cosα) x L

Myl = 1/4 (PL x sinα) x L

Mxw = 1/8 (QW) x L2

Mxw = 1/8 (QW ) x L2

qd = 14.13 kg/m qd = 14.13 kg/mql = 27.00 kg/m ql = 27.00 kg/m

qw1 = 27.00 kg/m qw = 0.00 kg/mqw2 = 0.00 kg/m

= == 60.16 kg/m = 350.44 kgm

= == 60.16 kg/m = 12.62 kgm

2. Beban TerpusatSumbu X : Sumbu Y :

qd = 14.13 kg/m qd = 14.13 kg/mPl = 100.00 kg/m Pl = 100.00 kg/m


= == 176.96 kg/m = 365.08 kgm

= == 176.96 kg/m = 127.59 kgm

2 1.2D + 1.6L + 0.8W




= == 81.76 kg/m = 372.04 kgm

= == 60.16 kg/m = 350.44 kgm

= == 60.16 kg/m = 12.62 kgm


qux 1,2 qd + 1,6 ql Mux 1,2 Md + 1,6 Ml

quy 1,2 qd + 1,6 ql Muy 1,2 Md + 1,6 Ml

qux 1,2 qd + 1,6 ql Mux 1,2 Md + 1,6 Ml

quy 1,2 qd + 1,6 ql Muy 1,2 Md + 1,6 Ml

qux1 1,2 qd + 1,6 ql + 0,8 qw Mux1 1,2 Md + 1,6 Ml + 0,8 Mw


quy 1,2 qd + 1,6 ql + 0,8 qw Muy 1,2 Md + 1,6 Ml + 0,8 Mw



= == 198.56 kg/m = 372.04 kgm

= == 176.96 kg/m = 350.44 kgm

= == 176.96 kg/m = 12.62 kgm

20.9D + 1.3W




= == 47.82 kg/m = 109.19 kgm

= == 12.72 kg/m = 74.09 kgm

= == 12.72 kg/m = 2.67 kgm




= == 47.82 kg/m = 109.19 kgm

= == 12.72 kg/m = 74.09 kgm

= == 12.72 kg/m = 2.67 kgm




qux1 0.9 qd + 1.3 qw Mux1 0.9 Md + 1.3 Mw

qux2 0.9 qd + 1.3 ql Mux2 0.9 Md + 1.3 Mw

quy 0.9 qd + 1.3 ql Muy 0.9 Md + 1.3 Mw

qux1 0.9 qd + 1.3 qw Mux1 0.9 Md + 1.3 Mw

qux2 0.9 qd + 1.3 qw Mux2 0.9 Md + 1.3 Mw

quy 0.9 qd + 1.3 qw Muy 0.9 Md + 1.3 Mw

PERHITUNGAN PEMBEBANAN DENGAN KOEFISIEN ANGIN KONDISI 2

Beban Anginbangunan direncanakan jauh dari pantai sehingga diambil tekanan angin 25 kg/m2 (PPIUG pasal 4.2)

Tekanan Angin = 25(PPIUG Pasal 4.2.1)

koefisien angin terbuka dalam kondisi 1

- Angin Hisap 1 (-1.2) = Tekanan Angin x Jarak Gording x Koefesien Angin- Angin Hisap 2 (-0.4) = Tekanan Angin x Jarak Gording x Koefesien Angin

Koefesien Angin 1.2 = 40.5 kg/mkoefisien angin 0.4 = 13.5 kg/m


1. Beban Mati

- = 82.32 kgm

- = 2.96 kgm

2. Beban Hidup Merata

- = 157.28 kgm

- = 5.66 kgm

3. Beban Terpusat

- = 166.43 kgm

- = 18.00 kgm

4. Beban Angin

- = 248.06 kgm

- = 82.69 kgm

Beban kombinasi

1 1.2D + 1.6L2 1.2D + 1.6L + 0.8W3 0.9D + 1.3W

1 1.2D + 1.6L

kg/m2





Mxl = 1/4 (PL x cosα) x L

Myl = 1/4 (PL x sinα) x L

Mxw = 1/8 (QW) x L2

Mxw = 1/8 (QW ) x L2




= == 60.16 kg/m = 350.44 kgm

= == 60.16 kg/m = 12.62 kgm




= == 176.96 kg/m = 365.08 kgm

= == 176.96 kg/m = 32.36 kgm

2 1.2D + 1.6L + 0.8W




= == 92.56 kg/m = 382.84 kgm

= == 70.96 kg/m = 361.24 kgm

= == 60.16 kg/m = 12.62 kgm

qux 1,2 qd + 1,6 ql Mux 1,2 Md + 1,6 Ml

quy 1,2 qd + 1,6 ql Muy 1,2 Md + 1,6 Ml

qux 1,2 qd + 1,6 ql Mux 1,2 Md + 1,6 Ml

quy 1,2 qd + 1,6 ql Muy 1,2 Md + 1,6 Ml







= == 209.36 kg/m = 397.48 kgm

= == 187.76 kg/m = 375.88 kgm

= == 176.96 kg/m = 32.36 kgm

20.9D + 1.3W




= == 65.37 kg/m = 126.74 kgm

= == 30.27 kg/m = 91.64 kgm

= == 12.72 kg/m = 2.67 kgm




= == 65.37 kg/m = 126.74 kgm

= =




qux1 0.9 qd + 1.3 qw Mux1 0.9 Md + 1.3 Mw

qux2 0.9 qd + 1.3 ql Mux2 0.9 Md + 1.3 Mw

quy 0.9 qd + 1.3 ql Muy 0.9 Md + 1.3 Mw

qux1 0.9 qd + 1.3 qw Mux1 0.9 Md + 1.3 Mw

qux2 0.9 qd + 1.3 qw Mux2 0.9 Md + 1.3 Mw

= 30.27 kg/m = 91.64 kgm

= == 12.72 kg/m = 74.09 kgm

Dipilih beban yang terbesar di antara angin kondisi 1 & 2, dan dari 3 kombinasi pembebanan, diperoleh

kondisi angin 2 dengan kombinasi pembebanan 1,2 D + 1,6 L + 0,8 W

beban merataMux 382.84 kgm 38284 kgcmMuy 12.62 kgm 1262 kgcm

beban terpusatMux 375.88 kgm 37588 kgcmMuy 32.36 kgm 3236 kgcm


Beban merataMx My

Wx Wy

606.0888

Beban terpusatMx My

Wx Wy

713.9406

LENDUTAN

Lendutan ijL/250 (PPBBI) 2.8 cm

Lendutan Akibat Beban Merata (1)

fx = 5 x qux x = 5 x384 E x Ix 384 x

= 1.91 cm

fy = 5 x quy x = 5 x

quy 0.9 qd + 1.3 qw Muy 0.9 Md + 1.3 Mw

σ =

σ =

σ =

σ =

L4

L4

fy =384

xE x Iy

=384 x

= 10.24 cm

Lendutan Akibat Beban Terpusat (1)

fx = 1 x qux x L3 = 1 x48 E x Ix 48 x

= 0.01 cm

fy = 1 x quy x L3 = 1 x48 E x Iy 48 x

= 0.07 cm

Lendutan total yang terjadi

= = ( 1.91 + 0.01 10.24 + 0.07

10.48169 cm > 2.8 cm NOT OK

ftot = fx2 + fy2 (fx1 + fx2 )2 + (fy1 + fy2 )2

) 2 + (

ftot = fijin =


(PPIUG Pasal 4.2.1)

+ 1,6 Ml + 0,8 Mw

+ 1,6 Ml + 0,8 Mw

+ 1,6 Ml + 0,8 Mw


(PPIUG Pasal 4.2.1)

+ 1,6 Ml + 0,8 Mw

+ 1,6 Ml + 0,8 Mw

+ 1,6 Ml + 0,8 Mw

Dipilih beban yang terbesar di antara angin kondisi 1 & 2, dan dari 3 kombinasi pembebanan, diperoleh

0.93 x 700 4

2100000 x 721

0.60 x 700 4

2100000 x 87.5

2.09 x 700 3

2100000 x 721

1.77 x 700 3

2100000 x 87.5

) 2

Gording Memed

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