EP MINTEGIA 2009/03/04 Azterketa (2008ko Iraila) [ebazpena - A atala]
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Transcript of EP MINTEGIA 2009/03/04 Azterketa (2008ko Iraila) [ebazpena - A atala]
λ
(J1)1 (J1)2
(IC)1
€
U1
U2
1
=12000400
€
U1
U2
2
=12000400
ISARE
Δ λ
Δ
(IC)2=(IC)1=IC
€
U1
U2
1
=12000400
⇒n1n2
1
=U1
U2
=12000400
= 30
U1
U2
2
=12000400
⇒n1n2
2
=
U13
U23
=12000
3400
3= 30
λ
Δ
λ
Δ
(V13)1
(V13)2
60o
(VL)1
IS1
IC
D1
D3
RL
IS2
IS3 €
23IC
€
13IC
€
IS1 =23IC
IS2 = −13IC
IS3 = −13IC
(V13)1
€
23IC
(Is1)1
(Is3)1
€
−23IC
€
−13IC €
13IC
30 60 90 120 150 180 210 240 270 300 330 360
(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1
(Is1)1
(Is3)1
IS1
IC
D1
D3
RL
IS2
IS3
€
23IC
€
13IC
€
IS1 =13IC
IS2 =13IC
IS3 = −23IC
(V23)1
€
23IC
€
23IC
€
13IC
€
13IC
€
−13IC
€
−13IC
€
−23IC
€
−23IC
(VL)1
30 60 90 120 150 180 210 240 270 300 330 360
(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1
(Is1)2
(Is3)2
IS1
IC
D1
D2
RL IS2
IS3 €
23IC
€
13IC
(V12)1
€
IS1 =13IC
IS2 = −23IC
IS3 =13IC
€
23IC
€
23IC
€
13IC
€
13IC
€
−13IC
€
−13IC
€
−23IC
€
−23IC
(VL)1
30 60 90 120 150 180 210 240 270 300 330 360
(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1
(Ip3)1
(Ip1)1
(J1)1 = (Ip1)1 - (Ip3)1
30 60 90 120 150 180 210 240 270 300 330 360
Δ
(J1)1
€
n1n2
1
IC
Δ
€
23x
€
23x
€
13x
€
13x
€
−13x
€
−13x
€
−23x
€
−23x
€
−x
€
x
30 60 90 120 150 180 210 240 270 300 330 360
(VL)2
(Is1)2
(V13)2 (V23)2 (V21)2 (V31)2 (V12)2
(J1)2 = (Ip1)2
IC
-IC
€
n2n1
1
⋅ IC( )1 = x
€
−n2n1
1
⋅ IC( )1 = −x
(V32)2
λ
(J1)2
IC
λ
€
n1n2
2
=n1n2
1
ISARE
€
2x
€
−2x
30 60 90 120 150 180 210 240 270 300 330 360
(J1)2
(J1)1
€
x
€
−x
€
ISARE =12π
⋅ 2 ⋅ 2π3⋅ 2x( )2
ISARE = 2 ⋅ 23⋅n2n1
1
⋅ IC
ISARE = 2 ⋅ 23⋅130
⋅ 600 = 32.66A
€
x
€
−x
€
(J1)1 = (J1)2 =12π
⋅ 2 ⋅ 2π3⋅ x( )2
(J1)1 = (J1)2 =23⋅n2n1
1
⋅ IC
(J1)1 = (J1)2 =23⋅130
⋅ 600 =16.33A
€
VLC( )1 = VLC 0( )1 − ΔVX( )1 = VLC 0( )1 − 0.12 VLC 0( )1= (1− 0.12) ⋅ VLC 0( )1 = 0.88 ⋅ 540 = 475v
VLC 0( )1 =VLC 0 S3 =3VO S3
π=3 ⋅ 400 2( )
π= 540v
VO S3 = 2 ⋅U2 = 400 2
λ
Δ
λ
Δ
€
VLC( )2 = VLC 0( )2 − ΔVX( )2 = VLC 0( )2 − 0.12 VLC 0( )2= (1− 0.12) ⋅ VLC 0( )2 = 0.88 ⋅ 540 = 475v
VLC 0( )2 =VLC 0 PD3=3 3 ⋅VO PD3
π=
3 ⋅ 3 ⋅ 400 23
π= 540v
VO PD3 = 2 ⋅ U23
= 400 2
3
€
FSARE =PLC( )1 + PLC( )23 ⋅U1 ⋅ ISARE
=VLC( )1 ⋅ (IC )1[ ] + VLC( )2 ⋅ (IC )2[ ]
3 ⋅U1 ⋅ ISARE=475 ⋅ 600[ ] + 475 ⋅ 600[ ]
3 ⋅12000 ⋅ 32.66= 0.84
€
cos ϕ1( )1 =1− ΔVX
VLC 0
1
cos ϕ1( )1 =1− 0.12 = 0.88
ϕ1( )1 = arccos 0.88( ) = 28.35º
cos ϕ1( )2 =1− ΔVX
VLC 0
2
cos ϕ1( )2 =1− 0.12 = 0.88
ϕ1( )2 = arccos 0.88( ) = 28.35º
VR
(I1)1
€
ϕ1( )1 = ϕ1( )2
(I1)2 (I1)SARE = (I1)1 + (I1)2
€
I1( )SARE = I1( )1 + I1( )2 =VLC 0( )1 ⋅ (IC )1
3 ⋅U1
+VLC 0( )2 ⋅ (IC )2
3 ⋅U1
=540 ⋅ 600 + 540 ⋅ 600
3 ⋅12000= 31.17A
€
τ SARE =I≈( )SAREI1( )SARE
=ISARE2 − I1( )SARE
2
I1( )SARE=
ISAREI1( )SARE
2
−1 =32.6632.17
2
−1 = 0.31