DoAn PLC
Transcript of DoAn PLC
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Phn 1: KHI NG NG C IN MT CHIUKCH T C LP
1. Gii thiu v ng c in mt chiu v Ml :
ng c in mt chiu l loi ng c hot ng bng dng in mtchiu. u im ni bt ca ng c in mt chiu so vi cc ng c inxoay chiu l d iu chnh tc v mmen. ng c in mt chiu cng dng kh rng ri nh trong tu in ngm, my khoan, my cn, bngti, cn trc, qut, cnh tay robot,
ng c in mt chiu kch t c lp (Ml) l loi ng c c mchphn ng v mch kch t c cp in c lp nhau. Cc thng s nhmc ca Ml l cng sut Pm (kW), tc nm (v/ph), mmen Mm (Nm),tn s lm vic fm (Hz), in p Um, dng in phn ng I (A) v in tr
phn ng R ( ).
Hnh 1.1
2. Vn khi ng ca Ml : m my ng c in mt chiu c tt, phi thc hin nhng yu
cu sau y:1. M men m my (hay khi ng) Mk phi c tr s cao nht c th
c hon thnh qu trnh m my, ngha l t c tc quy nh trongthi gian ngn nht.
2. Dng in m my (hay khi ng) Ik phi hn ch n mc nh
nht trnh cho dy qun khi b chy hoc nh hng xu n i chiu.Trong khun kh yu cu trn, ngi ta p dng ba phng php m
my sau y:1). M my trc tip.2). M my dng in tr ph.3). M my bng in p thp ( U < Um ).
Khi khi ng trc tip Ml bng cch ng trc tip ng c vo li in,do sut in ng phn ng E = 0 nn dng in phn ng :
f f
U E UI
R R R R
= =
+ +Trong :
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CKT
K1G 2G 3G
Eo
a b
a
b c
d e
fg
1
2
3
I2 I1Ic
xl
1
2
3TN
Rf1 Rf2 Rf3
O
an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
- U l in p mch phn ng.- R l in tr cun dy phn ng.- Rf l in tr ph mch phn ng.Dng I c gi tr rt ln, gp 10 n 20 ln dng in nh mc. Dng
in ny s gy t nng ng c, sinh ra lc in ng ln lm ph hy qu
trnh c ca my v lm cho cc thit b bo v nh cu ch, aptmt tc ngnhm.
m bo an ton cho my, thng thng ngi ta s gii hn dng khing 2,5 ln dng nh mc bng cch a in tr ph vo mch phnng khi khi ng v sau loi b dn in tr ph a tc ng cln xc lp. Phng php ny gi l khi ng bng in tr ph:
Ikb = Inm =ufu
dm
RR
U
+= ( 22,5 ) Im Icp
3. c tnh khi ng ca Ml :
Hnh 1.
Xt Ml khi ng vi 3 cp in tr ph Rf1, Rf2 v Rf3 (xem hnh 1.2.a).Dng khi ng ca ng c c gii hn trong khong 2 1kI I I
(I2=1.1 1.3Ic, I1=2 2.5Im).c tnh khi ng s c dng nh hnh 1.2.b.
Ti a, ng c bt u khi ng vi ton b in tr phRf1+Rf2+Rf3. Tc ng c bt u tng dn ln (on ab). n b, tc ng c l 1, cp in tr ph th nht c ngn mch (Rf1 = 0) ang c ln tc cao hn, in tr ph mch phn ng cn li l Rf2 + Rf3.Do qun tnh nn tc ng c khng tng lin nn c on ngang (bc) sau mi tng tc (on cd). Ti c, tc ng c l 2, cp in tr ph thhai c ngn mch (Rf2=0), ch cn li in tr ph Rf3 trong mch phnng. Do qun tnh nn c on ngang (de) sau ng c tng tc ln tc 3 (on ef). Ti f, cp in tr cui cng c ngn mch (Rf3 = 0). Tng
t s c on ngang (fg) trc khi ng c tng tc ln tc xc lp ( xl),kt thc qu trnh khi ng.
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4. Tnh cc gi tr ca in tr khi ng :Gi s ng c khi ng vi 3 cp in tr ph. c tnh khi ng
u tin v dc nht l ng 1 (xem hnh 1.2.b), sau n ng 2, 3 ngvi cp in tr ph th 2, 3 v cui cng l c tnh c t nhin.
in tr tng ng vi mi c tnh c l:
R1 = R + Rf (1) = R + ( Rf1 + Rf2 + Rf3 )
R2 =R + Rf (2) = R +( Rf2 + Rf3 )
R3 =R + Rf (3) = R +(Rf3 )
- Ti b, ta c 121
mU EIR
=
- Ti c, ta c1
1
2
mU EIR
=
Trong qu trnh khi ng, 1
2
Iconst
I= =
1 1 2
2 2 3
I R R
I R R= = =
3
2
2 3
3
1 2
R R
R R R
R R R
=
= =
= =
13 31.
m
R U
R R I= =
Trong 11
mURI
=
Cc gi tr in tr ph ca tng cp l:
3 3
2 2 3
21 1 2
( 1)
( 1)
( 1)
f
f
f
R R R R
R R R R
R R R R
= =
= =
= =
5. Qu trnh qu c ca Ml :
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Xt QTQ khi khi ng Ml vi 3 cp in tr ph (xem hnh 1.2a), s c4 giai on QTQ khi ng :
1
M
2
3
b
a
c
d e
f g
1
2
3
TN
Mc M2 M1
xl
O
I
O t
xl
I2
Ic
I1
t1 t2 t3 t4
a) b)Hnh 1.3
a). Giai on 1: on ab, c tnh 1 :
f f1 f2 f3 1 f1 f2 f3R =R +R +R R =R +R +R +R
Theo c tnh 1, cng c tnh c:2
1 21
1 1
( )k M M
R
= =
- Hng s thi gian c:1 2 3
1 2 2
1
1
( )( )
( ) ( )
f f f
c
J R R R RJ JT s
k k
R
+ + += = =
- iu kin ban u, im a: b1 = 0, Mb1 = M1
- iu kin xc lp: xl1 (xc nh theo c tnh c), Mxl1 = M2
- Phng trnh QTQ trong giai on 1 l:
1
1
1
1
(1 )
( )
c
c
tT
xl
tT
c c
e
M M M M e
=
= +
- Khi = 1, QTQ s chuyn sang giai on 2 .
b). Giai on 2: on bcd, c tnh 2 :
f f2 f3 2 f2 f3R =R +R R =R +R +R
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- Theo c tnh 2, cng c tnh c:2
1 22
2 1 2
( )k M M
R
= =
- Hng s thi gian c:
2 3
2 2 2
2
2
( )( )
( ) ( )
f f
c
J R R RJ JT s
k kR
+ += = =
- iu kin ban u, im c: b2 = 1, Mb2=M1
- iu kin xc lp: xl2 (xc nh theo c tnh c), Mxl2 = M2
- Phng trnh QTQ trong giai on 2 l :
2
2
2 1 2
1
( ) )
( )
c
c
tT
xl xl
tT
c c
e
M M M M e
= +
= +
- Khi = 2, QTQ s chuyn sang giai on 3
c). Giai on 3: on def, c tnh 3 :
f f3 3 f3R =R R =R +R
- Theo c tnh 3, cng c tnh c:2
1 23
3 2 3
( )k M MR
= =
- Hng s thi gian c:3
3 2 2
3
3
( )( )
( ) ( )
f
c
J R RJ JT s
k k
R
+= = =
- iu kin ban u, im c: b3 = 2, Mb3 = M1
- iu kin xc lp: xl3 (xc nh theo c tnh c), Mxl3 = M2
- Phng trnh QTQ trong giai on 3 l:
3
3
3 2 3
1
( ) )
( )
c
c
tT
xl xl
tT
c c
e
M M M M e
= +
= +
- Khi = 3, QTQ s chuyn sang giai on 4
d). Giai on 4: on fg, c tnh TN:
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f 4 R =0 R =R
- Theo c tnh TN:
2
4 3 22
( )
( )( )( )
TN c TN
k J J J R
T sR kk
R
= = = = =
- iu kin ban u, im g: b4 = 3, Mb4 = M1
- iu kin xc lp: xl4 = xl, Mxl4 = Mc
- Phng trnh QTQ trong giai on 4 l:
4
4
3
1
( )
( )
c
c
tT
xl xl
tT
c c
e
M M M M e
= +
= +
- Khi xl, M Mc xem nh kt thc QTQ khi ng.
Da vo cc phng trnh QTQ ca (t), M(t) trong 4 giai on, tac th v c c tnh (t) v M(t) khi khi ng vi m = 3 cp in tr
ph nh hnh 1.3a
6. Tnh thi gian khi ng :
tk = tq + t1 + t2 + t3 + t4 (ng vi m = 3 cp)T phng trnh M(t), ta c th tnh c cc thi gian:
1
2
ln ci cic
M Mt T
M M
=
vi i=1 4
4 4
1
1 1 2ln
c
k q i cii i c
M M
t t t T M M= =
= = =
Phn 2 : TNG QUAN V PLC S7-200
I. Gii thiu v PLC :1. PLC :
PLC (Programmable Logic Controller) l thit b logic kh trnh cdng trong cc ng dng cng nghip iu khin my mc v cc dychuyn sn xut t ng. N theo di cc u vo, a ra cc quyt nh, v
iu khin cc u ra theo t ng ha my mc cc dy chuyn sn xut.
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PLC hin nay c ng dng rt ph bin, chng hn nh trong ccdy chuyn ng chai, ng gi sn phm t ng, iu khin thang my,
bm, my trn, iu khin khi ng, dng v o chiu ng c in,
2. Nhng thun li ca PLC :
- Kch thc gn, d bo qun.- D lp trnh v thay i chng trnh.- Dung lng b nh ln, thch hp cho cc chng trnh phc tp.- Chng nhiu tt, lm vic tin cy trong mi trng cng nghip.
- Giao tip c vi cc thit b thng minh khc nh: my tnh, nimng, cc mun m rng,
- Gi c hp l.3. So snh PLC vi cc h thng iu khin khc :
Ch tiuso snh
RLE MCH S MY TNH PLC
Gi thnh kh thp thp cao thpKch thc ln rt gn kh gn rt gn
Tc x l chm rt nhanh kh nhanh nhanhKh nng chng
nhiuxut sc tt kh tt tt
Lp tmt thi gianthit k v lp
t
mt thi gianthit k
mt nhiuthi gian lp
trnh
lp trnh vlp t n
ginKh nng iu
khin tc v phctp
rt kh kh kh n gin rt n gin
Thay i iukhin
rt kh kh kh n gin rt n gin
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Cng tc bo trkm do c rtnhiu cng tc
km nu ICc hn
km do cnhiu mch
in tchuyn dng
tt do ccmun ctiu chun
ha
II. Cu trc v hot ng ca PLC :1. Cu trc ca PLC :
Cc thnh phn c bn ca mt PLC l cc mun u vo, n v x ltrung tm - CPU (Central Processing Unit) v cc mun u ra (xem hnh2.2).
Cac
mounau vao
CPU
n vxltrung tam
Cac
mounau ra
Thiet blap trnh
Moungiam sat
Hnh 2.2
Cc mun u vo: nhn cc tn hiu tng t v s t cm bin vchuyn i thnh cc tn hiu logic cho CPU x l.
CPU: a ra cc quyt nh v thc thi cc cu lnh ca chng trnhiu khin c lu sn trong trong b nh.
Cc mun u ra: nhn ch th t CPU thay i tn hiu u raphc v cho vic iu khin thit b.
Thit b lp trnh: c dng np chng trnh vo PLC, cho bitPLC s lm g khi nhn c cc tn hiu vo.
Mun gim st: dng hin th thng tin ca tin trnh v cho phpnhp vo cc thng s iu khin mi.CPU gm 3 phn: b x l, h thng b nh v h thng ngun cung
cp
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CPU(n vxltrung tam)
Bonh
Nguoncung cap
Hnh 2.3
C 3 loi b nh chnh l ROM, RAM v EPROM:
ROM (Read Only Memory) l b nh ch c, dng lu tr ccchng trnh c nh, khng th thay i.
RAM (Random Access Memory) l b nh truy xut ngu nhin, dng lu tr cc d liu tm thi.
EPROM (Erasable Programmable Read-Only Memory) l ROM c thlp trnh v xa c.
2. Hot ng ca mt PLC :
u tin, cc mun vo nhn cc tn hin bn ngoi t cc cm bin,cng tc, chuyn i sang dng s v a n cho CPU x l. Khi CPUnhn c tn hiu ng vo, n s x l v a cc tn hiu iu khinqua ng ra n cc thit b cn iu khin.
Trong sut qu trnh hot ng, CPU qut d liu hoc trng thi cacc thit b ngoi vi thng qua ng vo, sau thc hin cc chng trnhtrong b nh. Chng trnh c vit dng STL (lit k lnh) hoc LAD(hnh thang) c dch ra ngn ng my trc khi lu vo b nh. Khithc hin xong chng trnh, qu trnh truyn thng ni b v kim tra lic thc hin. Cui cng CPU s gi hoc cp nhp tn hiu ti cc thit
b iu khin thng qua ng ra. Nh vy mt vng qut s gm 4 khu:c tn hiu ng vo, thc hin chng trnh, truyn thng ni b, tkim tra li v gi cp nhp tn hiu ng ra.
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Vong quetPLC
Hnh 2.4
Thc t, khi thc hin chng trnh, PLC khng cp nhp tc thi ccng ra m qua 2 bc: trong sut qu trnh thc hin chng trnh, tn hiua ra ng ra s c lu tm thi trong chng trnh ni vi cc mclgc l ON v OFF. Khi chng trnh c thc hin xong, CPU schuyn cc tn hiu lu ra cc ng ra thc i iu khin ccthit b.
Thng thng, thi gian thc hin mt vng qut rt ngn, khong t 1ms n 100 ms, ph thuc ch yu vo di chng trnh PLC v tc
giao tip gia PLC vi cc thit b ngoi vi. B vi x l cng ch c th cc tn hiu ng vo khi tn hiu ny tc ng trong thi gian ln hnmt chu k qut. Nu thi gian tc ng ng vo nh hn mt chu kqut th b vi x l xem nh khng c tn hiu ny. Tuy nhin trong thc tsn xut, thng thng cc h thng chp hnh l cc h thng c kh nntc qut nh trn hon ton c th p ng c cc chc nng ca dychuyn sn xut.
III. PLC S7-200 :
1. Gii thiu v S7-200 :
S7-200 l mt PLC c kch thc nh do hng Siemens ca c snxut. Cc chc nng cp ngun v cng I/O c thit k on-board.
S7-200 rt thch hp cho cc ng dng n nh iu khin my trn,thang my, khi ng v o chiu ng c, N cng c th c dngtrong cc ng dng cng nghip phc tp nh cc dy chuyn ng chaiv ng gi sn phm,
2. Cu trc phn cng ca S7-200 (CPU 214) :
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Hnh 2.5
S7-200 (CPU 214) c 14 cng u vo v 10 cng u ra, mt cng lp
trnh giao tip vi my tnh np chng trnh vo PLC. Cc tnh nngca CPU 214 nh sau:
B nh:
Chng trnh: 6 KB
D liu ngi dng: 5 KB
Loi b nh: EEPROM
Loi b nh chp nh: EEPROM
Thi gian lu d liu khi PLC mt in: 50 gi
I/O:
S lng I/O c sn: 14 vo/10 ra
S mun m rng ti a: 7
S cng I/O s m rng ti a: 94 vo/14 ra
S cng I/O tng t m rng ti a: 28 vo/7 ra hoc 0 vo/14 ra
Tp lnh:
Tc x l lgc: 0,37 s/lnh
S lng rle ni: 256
S lng b m: 256
S lng timer: 256
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S lng rle iu khin tun t: 256
Vng lp for/next: c
Tnh ton trn s nguyn (+-*/): c
Tnh ton trn s thc (+-*/): c
3. Cu trc chng trnh ca S7-200 :
Chng trnh cho S7-200 c th c vit bng STEP7 Micro/WINhoc STEP7 Micro/DOS, c cu trc gm chng trnh chnh, ccchng trnh con v cc chng trnh x l ngt:
- Chng trnh chnh kt thc bng lnh MEND.
- Chng trnh con l mt b phn ca chng trnh, kt thc bng lnhRET. Cc chng trnh con phi vit sau lnh kt thc chng trnhchnh (MEND).
- Chng trnh ngt l mt b phn ca chng trnh, c dng khi cn,kt thc bng lnh RETI v cng phi c vit sau lnh MEND.
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Main Program...MEND
Chng trnh chnh
SBR 0...RET
Chng trnh con 1
SBR n...RET
Chng trnh con n+1
INT 0...RETI
Chng trnh xl ngat 1
Chng trnh xl ngat n+1
INT n.
..RETI
Thc hien trong mot vong quet
Thc hien khi c chng trnhchnh goi
Thc hien khi cotn hieu bao ngat
Hnh 2.6
4. Phng php lp trnh LAD v STL :
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Network 1
LD I0.2O I0.3= Q0.1
Q0.1I0.2
I0.3
a) dang LAD
b) dang STL
Hnh 2.7
a) Phng php LAD (hnh thang) :
LAD l phng php s dng cc k hiu ha biu din cc phnt v cc lnh lgc ca chng trnh PLC:
- Tip im: thng m -| |- hoc thng ng -|/|-
- Cun dy: -( )-
- Hp: thay th cho cc timer, b m v cc hm ton hc,
b) Phng php STL (lit k lnh):
STL l phng php th hin chng trnh PLC di dng tp hp cacc cu lnh n.
5. Mt s lnh thng dng ca S7-200 :
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LAD STL M t
n LD n Np gi tr logic ca tipim n vo bt u tin trnngn xp.
n LDN n Np gi tr lgc o catip im n vo bt u tintrn ngn xp.
n = n Sao chp gi tr ca nhngn xp ra tip im n.
I0.0 I0.1 Q0.0 LD I0.0
A I0.1
= Q0.0
Thc hin php AND lgc.
I0.2 Q0.1
I0.3
LD I0.2
O I0.3
= Q0.1
Thc hin php OR lgc.
MENDMEND Kt thc khng iu kin
chng trnh hin hnh.
Txx
IN
PT
TON
TON Txx n Khai bo timer s hiu xxkiu TON to thi giantr tnh t khi u vo INc kch. Nu gi tr mtc thi ln hn hoc bnggi tr t trc PT th T-bitc gi tr lgc bng 1. Cth reset timer kiu TON
bng lnh R hoc gi trlgc 0 ti u vo IN.
Txx
IN
PT
TONR
TONR Txxn
Khai bo timer s hiu xxkiu TONR to thi giantr tnh t khi u vo INc kch. Nu gi tr mtc thi ln hn hoc bnggi tr t trc PT th T-bit
c gi tr lgc bng 1. Chc th reset timer kiuTONR bng lnh R cho T-
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bit.
Cxx
CTUCU
PV
R
CTU Cxxn
Khai bo b m tin theosn ln ca CU. Khi gi trm tc thi C-word Cxx
ln hn hoc bng gi trt trc PV, C-bit (Cxx)c gi tr lgc bng 1. Bm c reset khi u voR c gi tr lgc bng 1.B m ngng m khi C-word Cxx t gi tr cc i32767.
Cxx
CTUDCU
PV
R
CTUD Cxx
n
khai bo b m tin/li,
m tin theo sn ln caCU v m li theo snln ca CD. Khi gi tr mtc thi C-word Cxx lnhn hoc bng gi tr ttrc PV, C-bit Cxx c gitr lgc bng 1. B mngng m tin khi C-wordt gi tr cc i 32767 v
ngng m li khi t gitr cc tiu -32767. CTUDreset khi u vo R c gitr lgc bng 1.
Phn 3 : LP TRNH PLC IU KHIN QU TRNHKHI NG Ml BA CP IN TR PH
1. Yu cu bi ton :Lp trnh PLC iu khin khi ng ng c1GH5 132-OJG6-6VV1
ca hng Siemens vi 3 cp in tr ph. S liu ca ng c nh sau:- Pm = 25 KW- nm = 2000 vng/pht- U = 220V- Im = 120 A- R = 0,08
- J = 0,15 kgm2
.
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2. Gii thiu v cng ngh :
Hnh 3.1Giao tip
gia ngi dngvi ng c rt
n gin, chgm mt nt nkhi ng vmt nt ndng. y l ccnt n khng ckh nng t gi.
Khi ngi dng n nt khi ng, b iu khin PLC s iu khin atn hiu ra cc CTT ngn mch dn cc in tr ph trn mch phn ng v
a tc ng ng c nhanh chng t ti gi tr xc lp, kt thc qu trnhkhi ng. dng my, ngi dng ch vic n nt dng. PLC s iu khina tn hiu ra CTT hm ng in tr hm vo trong thi gian c nhsn nhm gim tc ng c v 0.
3. Tnh thi gian khi ng :
m =55,9
dmn
=55,9
2000= 209,4 (rad/s)
Mm =dm
dmP
1000.=
4,209
1000.25= 119,39 Nm
- chn M1=2,5Mm=2,5 . 119,39 = 298,5 NmMmen cn : Mc Mm= 119,39 NmM2=1,3Mm=1,3 . 119,39 = 155,2 NmI1= 2,5 Im=2,5 . 120 = 300 A
-
- k =m
U
= 4,209
220= 1,1025
- (k )2 = 7,84- Khi ng vi 3 cp in tr ph (m=3) bi s dng in khi khi
ng = 31.IR
U
u
= 3300.08,0
220= 2,092
SVTH: Nguyn Manh Ha - L p 05SK1 Trang17
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8/9/2019 DoAn PLC
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an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
- Cc cp in tr ph l:
Rf1 = 2( -1).R = 2,0932 (2,093 - 1).0,08 = 0,383 Rf2 = ( -1).R = 2,092(2,093 - 1).0,08 = 0,183 Rf3 = ( -1).R = (2,093 - 1).0,08 = 0,08744
- Thi gian t1, t2, t3:
Tc1 = 2321
)(k
)(
+++
ufufufuRRRRJ
=
=1025,1
)08744,0183,0383,008,0.(15,0 +++= 0,1
t1 = Tc1lnc
c
MM
MM
2
1 = 0,1.ln39,1192,155
39,1195,298
= 0,161(s)
Tc2 = 232
)(k
)(
++
ufufuRRRJ
=1025,1
)08744,0183,008,0.(15,0 ++= 0,0477
t2 = Tc2lnc
c
MM
MM
2
1 = 0,0477.ln39,1192,155
39,1195,298
= 0,077 (s)
Tc3 = 23
)(k
)(
+
ufu RRJ=
1025,1
)08744,008,0.(15,0 += 0,0228
t3 = Tc3ln cc
MM
MM
2
1
=0,0228.ln 39,1192,15539,1195,298
= 0,0367(s)
4. Tnh thi gian hm ng nng :
thm = Tc . lnc
c
M
MM +1
Tc = J.M
= J.
1M
b
M1= 2,5.Mm = 298,5 Nmb = m = 119,39(rad/s)
Tc = 0,15. 5,2984,209 = 0,105 (s)
thm = 0,105.ln 39,11939,1195,298 +
= 0,132 (s)
SVTH: Nguyn Manh Ha - L p 05SK1 Trang18
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8/9/2019 DoAn PLC
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an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
5. Phn cng vo/ra cho cc thit b :
CKT
H
Rh
K
1G 2G 3G
Eo
Hnh 3.2
a ch Chc nngI0.0 Nt dngI0.1 Nt khi ng
Q0.0 Tn hiu ng K Q0.1 Tn hiu ng 1GQ0.2 Tn hiu ng 2GQ0.3 Tn hiu ng 3GQ0.4 Tn hiu ng HT33 Timer 1 (16x10ms=160ms)T34 Timer 2 (8x10ms=80ms)T35 Timer 3 (4x10ms=40ms)T36 Timer 4 (13x10ms=130ms)
SVTH: Nguyn Manh Ha - L p 05SK1 Trang19
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8/9/2019 DoAn PLC
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an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
6. S Thut ton:
SVTH: Nguyn Manh Ha - L p 05SK1 Trang20
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an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
Hm:
SVTH: Nguyn Manh Ha - L p 05SK1 Trang21
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8/9/2019 DoAn PLC
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an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
7. Gin thi gian
Q 0 . 4
T 3 6
T 3 5
Q 0 . 3
T 3 4
Q 0 . 1
Q 0 . 2
T 3 3
Q 0 . 0
I 0 . 1
I 0 . 0
1 6 0 m s
8 0 m s
4 0 m s
1 3 0 m s
SVTH: Nguyn Manh Ha - L p 05SK1 Trang22
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8/9/2019 DoAn PLC
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an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
8. Chng trnh LAD:
SVTH: Nguyn Manh Ha - L p 05SK1 Trang23
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8/9/2019 DoAn PLC
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an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
I 0 . 0 I 0 . 1
Q 0 . 0
Q 0 . 0
N E T W O R K 5
N E T W O R K 4
N E T W O R K 3
N E T W O R K 2
N E T W O R K 1
Q 0 . 1Q 0 . 0 T 3 3
I N T O N
P T 1 0 m s
Q 0 . 1
Q 0 . 1
T 3 3Q 0 . 0
1 0 m sP T
T O NI N
T 3 4Q 0 . 1 Q 0 . 2Q 0 . 0
Q 0 . 0 T 3 4
Q 0 . 2
Q 0 . 2
1 6
8
SVTH: Nguyn Manh Ha - L p 05SK1 Trang24
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an mn hoc: iu khin Logic GVHD: Ks.Nguyn Manh Ha
N E T W O R K 7
N E T W O R K 8
Q 0 . 3
Q 0 . 3
T 3 5Q 0 . 0
I 0 . 0 T 3 6
Q 0 . 4
Q 0 . 4
N E T W O R K 9
Q 0 . 4 T 3 6
I N
P T
T O N
1 0 m s
N E T W O R K 6
Q 0 . 1 Q 0 . 3Q 0 . 2 T 3 5
I N T O N
P T 1 0 m s
Q 0 . 0
4
1 3