MC LCBNG K HIU CH VIT TT3DANH MC CC BNG4DANH MC CC HNH V,BN V5LI M U6CHNG 1 : NGHIN CU N HNG71.1. Nghin cu n hng71.2. Nghin cu mu71.2. Bng thng k s lng chi tit101.3. Nghin cu bng thng s kch thc sn phm111.4. M t nguyn ph liu141.4.1. Vi141.4.2. Ph liu141.4 Cu trc ng may sn phm161.5 Nhn xt v xut201.5.1 Nhn xt:201.5.2 xut:20CHNG 2:XY DNG QUY TRNH CNG NGH MAY M HNG 11101510010212.1. S khi gia cng sn phm212.2. S phn tch quy trnh cng ngh may222.3 S lp rp sn phm232.4 Phng php o thi gian242.4.1. Mc ch242.4.2. Cc yu t nh hng ti thi gian lm vic242.4.3. Cc phng php tnh thi gian242.4.4. Phng php o thi gian may sn phm m hng 11101510010252.3.4.1. Thao tc lm vic262.3.4.2 Trnh t thc hin tnh ton thi gian nh mc262.5. Quy trnh cng ngh may sn phm jacket m hng 1110151001030Bng 2.3: bng quy trnh cng ngh m hng 1110151001030CHNG 3: XY DNG TIU CHUN K THUT SN PHM O JACKET M HNG 11101510010333.1. Xy dng tiu chun k thut ct - tri vi333.1.1. Tiu chun k thut tri vi333.1.2. Tiu chun k thut ct vi333.1.3 Tiu chun v nh s, phi kin343.2 Tiu chun k thut may sn phm363.3 Tiu chun hon thin sn phm38KT LUN40DANH MC TI LIU THAM KHO41PH LC42

BNG K HIU CH VIT TTSTT K hiu Gii thch

1TTThn trc

2TSThn sau

3BTPBn thnh phm

4SPSn phm

5NPLNguyn ph liu

DANH MC CC BNG(M hng : 11101510010)

Bng 1.1: Bng thng k chi tit10Bng 1.2:Bng thng s kch thc thnh phm m hng 1110151001011Bng 1.3: Bng thng k nguyn ph liu m hng 1110151001015Bng 1.4: Bng m t mt ct sn phm jacket - m hng 1110151001018Bng 1.5: Bng NPL xut20Bng 2.1: Bng thao tc thc hin cng on may chp cu vai thn sau28Bng 2.2: Bng thao tc thc hin cng on may np ve thn trc30Bng 2.3: bng quy trnh cng ngh m hng 1110151001030Hnh 3.1: V tr nh s chi tit sn phm m hng1110151001035

DANH MC CC HNH V,BN V(M hng : 11101510010)

Bn v 1.1: Bn v m t sn phm mu m hng 111015100108Bn v 1.2: Bn v m t v tr o 12Bn v 1.3:Bn v m t v tr ct ng may16Bng 1.4: Bng m t mt ct sn phm jacket - m hng 1110151001018Hnh 2.1:S khi gia cng sn phm21Hnh 2.2:S phn tch quy trnh cng ngh 22Hnh 2.3: S lp rp sn phm23Hnh 3.1: V tr nh s chi tit sn phm m hng1110151001035Hnh 3.2: M t k thut may37Hnh 3.3: M t k thut may lp lt38

LI M UKhi nn kinh t ha nhp vi nn kinh th trng v nn kinh t quc t cc ngnh ngh trong c cu cc ngnh cng nghip Vit Nam ngy cng pht trin.Ngnh dt may cng nm trong s cc ngnh c mc tng trng cao.Mun nng cao nng sut lao ng tng trng v pht trin kinh t m ch c phng tin cng ngh thi cha , m cn pht trin mt cch tng xng nng lc ca con ngi s dng nhng phng tin . c ngun nhn lc ph hp vi yu cu cng nghip ha khoa cng ngh may v thi trang trng H s phm k thut Hng Yn gp phn to ra c cu ngun nhn lc p ng c nhu cu trong ngnhL sinh vin nm cui khoa cng ngh may & thi trang Trng H s phm k Yn b sung kin thc thc t trong sn xut em thc hin n mn hc vi ti :"Xy dng quy trnh cng ngh may sn phm ca m hng 11101510010" vi s hng dn ca thy Trn Trung HiuDo kin thc v kinh nghim cn hn ch nn khng th trnh khi nhng sai st em rt mong nhn c s gip ,ch bo ca thy c v cc bn

CHNG 1 : NGHIN CU N HNG1.1. Nghin cu n hng - Tn m hng:11101510010- M hng gm 5 c: S-M-L-XL-XXL- C gc: L1.2. Nghin cu mu c im chung- o jacket nam c 2 lp : lp ngoi bng vi chnh, lp lt trong c chn bng- C tu- Gu o c chn chun Mt trc ca sn phm- Thn trc c kha np,np kha 2 bn i xng- cp sn i xng 2 bn thn o- Ti kha sn may ti ng chp cp vi thn trc- Trn ti sn c np ti gn vi thn chnh bng nhm dnh- Ti v tr chp vai con c 2 c vai, c dy dt trang tr, cc bm ti v tr u vai Mt sau ca sn phm- Thn sau c cp ri- cp sn i xng 2 bn Tay o- Ca tay c bo tay- Tay tri c ti vt gc p ngoi, trang tr bng dy dt, ti np ti c cc bm, c vi ming ti, 2 oz y ti .Mang sau tay c chia lm 2 phn chp i vi cu vai Lp lt- Vi lt c chn vi m bng- Gu o c chn chun- Dy treo may cn gia c sau- Nhn chnh, nhn c nm gia di chn c- Nhn s dng nm sn o bn tri- Np kha bn trong di bng chiu di khaBn v 1.1: Bn v m t sn phm mu m hng 11101510010

Hnh v 1.1: bn v m t mu k thut ca sn phm m hng 11101510010

Mt trc sn phm

Mt sau ca sn phm

1.2. Bng thng k s lng chi tit Bng 1.1: Bng thng k chi titSTTTn chi titS lngCanh siLai vi

1Thn trc2DcChnh

2 cp TT2DcChnh

3Np ti ln chnh2DcChnh

4Ci ti2DcChnh

5p ti2NgangChnh

6Np kha TT2DcChnh

7C vai4DcChnh

8C o2DcChnh

9Mang tay ln2DcChnh

10Mang tay nh2DcChnh

11Cu vai1DcChnh

12Thn sau1DcChnh

13 cp TS2DcChnh

14Ti tay o1DcChnh

15C ti1DcChnh

16Thn sau lt1DcLt

17Tay o lt2DcLt

18Dy chn c vai2DcChnh

19p gu ln chnh2NgangChnh

20p gu ln lt2NgangChnh

21Bo tay2Bo len nguyn chic

22Bo gu1Bo lennguyn chic

1.3. Nghin cu bng thng s kch thc sn phmBng 1.2:Bng thng s kch thc thnh phm m hng 11101510010 (n v cm)STTV tr oCDung sai(+/-)

SMLXLXXL

1Rng c19,219,620,020,420,8+1,0

3Rng ngang nch thn trc41,642,844,045,246,4 1,0

4Rng ngang ngc di nch 2cm56,058,060,062,064,0 1,0

5Di gu khi chun48,050,052,054,056,0 1,0

5Rng ngang gu51,053,055,057,059,0 1,0

10Di o o t gia thn trc55,557,058,560,061,5 1,0

11Di o thn trc65,166,868,570,271,9 1,0

12Di o thn sau66,868,470,071,673,2 1,0

13Rng ngang nch thn sau44,845,947,048,149,2 1,0

14Di o o t gia thn sau65,066,568,069,571,0 1,0

15H nch26,026,527,027,528,0 1,0

16Rng vai con15,515,916,216,616,90,5

17Di tay o c bo tay68,369,971,573,174,70,5

19Rng bp tay o di nch 2 cm20,421,222,022,823,6 1,0

20Di bo tay8,48,79,09,39,6 1,0

20Rng ca tay14,114,414,715,015,3 1,0

21Chu vi vng c50,451,452,453,454,40,5

29Di ming ti16,016,017,017,018,0

35Di kha ko62,063,565,066,568,0

Bn v 1.2: Bn v m t v tr o

1.4. M t nguyn ph liu1.4.1. Vi Vi chnh- Vi chnh: l vi dt thoi, thnh phn 100% polyester- Bo tay: l vi dt kim , thnh phn 100% nylon Vi lt- L vi dt thoi, thnh phn 100% polyester1.4.2. Ph liu- m bng: thnh phn 100% polyester- Kha np: m trn c cht chn di- Cc dp (d=1.4cm). khuyt bng kim loi (d=0.7cm),inh tn (d=0.9cm)- Dy dt trangt tr ti cc v tr c vai, ti- Dy chun chn ti gu bn rng 6.5cm- Bng gai- Nhn: nhn chnh, nhn c, nhn s dng

Bng 1.3: Bng thng k nguyn ph liu m hng 11101510010Tn nguyn ph liuQuy cchV tr

K hiuThnh phnc im

Vi chnhW50-05-42100% polyester#2950 dress blues,65gr/m2, kh rng 1,5 mLp chnh o, np kha

Bo tayRy50-16-2x2100% nylon700g/m2Ca tay

Vi ltL101100% polyester65g/m2Lp lt o

m bongP060100% polyester60g/m2Chn vi lp lt

Kha npVislon,#8Kim loi#2950 dress blues,bn rng 1cm,kha m c cht diGia thn trc o

M cc#60_002Kim loid = 1,4cmCu vai

inh tn#0_020Kim loiPantone19-4024 dress bluesTPX p.190,d = 0,9cmTi o sn

zKim loiPantone19-4024 dress bluesTPX p.190d = 0,7cmTi tay o

Dy dtRng bn 2cmMing ti, cu vai

Dy dt(ti v tr ti bn tay tri)Rng bn 1cm

Ming ti tay o

Dy chun guBlack,rng bn 6,5cmGu o

Bng gai#2590 dress blues, c 2,0 x 2,0cmNp ti

1.4 Cu trc ng may sn phm Bn v 1.3:Bn v m t v tr ct ng may

Bng 1.4: Bng m t mt ct sn phm jacket - m hng 11101510010 STTMt ctng mayHnh v kt cuGhi ch

1

A-AMay c o vi thna. L c ngoib. L c trongc. Thn chnhd. Thn lt1. ng may ln2. ng may chp3. ng may ghim4. ng may diu5. ng may trang tr

2

B-BMay cp vi thn,may cu vai, may sng tay ln vi sng tay nha.Thn trcb. cp1.ng chp cp vi thn trc2.Diu cp

3

C-C

Tra khaa.TT trib.TT phic. Khad. Np khae. Np1. May ln np 2. May kha vo np 3. May kha vo vi TT4. Quay ln kha5. diu kha np

4

D-D

Tra taya. tay ob. thn trc1. ng may can r

5

E-E

May np ti

a. Np ti l ngoib. Np ti l ltc. Mex1. ng may ln2.ng may diu

6May np ti vo thn

a.Thn ob.Np ti1.ng may can ln

1.5 Nhn xt v xut1.5.1 Nhn xt:- n hng cung cp y thong tin v thng s sn phm- Bng hng dn o sn phm chi tit- Cu trc ng may khng qu phc tp ch yu l cc ng chp,diu s dng may may 1 kim - Hnh v k thut khng nu c im ng may1.5.2 xut:- Sn phm l hng may xut khu nn vic tm mu nguyn ph liu theo yeu cu gp nhiu kh khn nn nguyn ph liu s dng may sn phm c thay th bng nguyn ph liu khc c tnh cht tng ng ph hp vi kiu dng ca sn phm- Do thiu thit b dp chuyn dng nn oze ti v tr ti o trang tr bn tay tri khng s dng- Do khng tm c bn rng dy chun 6.5cm nn gu o c maykhng thay th bng bo dt-Kh rng ca dy dt trang tr rng 2cm thay bng dy dt rng 1cm-Nhm dnh 2x2cm thay th bng nhm dnh 2.5x2.5 cmBng 1.5: Bng NPL xutSTTTn NPLc dim

1Vi chnhThay th (vi dt thoi )

2Vi ltThay th (cng mu vi chnh)

3CcThay th(kim loi)

4Nhm dnhThay th(mu en (2.5x2.5cm))

5KhaThay th (kha nha rng c su)

6Mc chnhThay th

7Mc cThay th

8Mc s dngThay th

9ChThay th (cng mu vi chnh 60/3)

CHNG 2:XY DNG QUY TRNH CNG NGH MAY M HNG 111015100102.1. S khi gia cng sn phmHnh 2.1:S khi gia cng sn phm

2.2. S phn tch quy trnh cng ngh may S nhnh cy th hin cch lp rp cc chi tit theo 1 th t hp l to thnh sn phm.n gip b sung v han chnh quy trnh cng ngh may Mc ch :- Trnh sai st trong qu trnh thit k chuyn v b tr mt bng nh xng- Sa cha bt hp l v thi gian hay ng i ca bn thnh phm trong chuyn- Gip cho t trng ri chuyn 1 hp lHnh 2.2:S phn tch quy trnh cng ngh

2.3 S lp rp sn phmHnh 2.3: S lp rp sn phm

2.4 Phng php o thi gian2.4.1. Mc ch - xc nh thi gian ch to cho tng cng vic, lm cn c thit k chuyn may, phn cng lao ng v tnh lng cho cng nhn- Xc nh thi gian hon thin 1sn phm- xc nh cng sut ca 1 nh may v vch ra k hoch nhm t c mt sn lng theo mc tiu thch hp, phm vi phn cng lao ng cn thit v sn xut ti u- Xc nh s thi gian s dng trong mi thnh phn cng vic h tr cho vic ci tin v tiu chun ha- c tiu chun nh gi khi nhn cc n t hng, s dng vic nghin cu thi gian c tnh chi ph v kim tra- Dng lm c s xc nh chi ph cho 1 n v sn phm v tin lng2.4.2. Cc yu t nh hng ti thi gian lm vic- Cht lng ca nguyn liu: mu sc, canh si- phc tp ca sn phm- iu kin, trang thit b, nh xng- Tm l ca ngi cng nhn trong qu trnh lm vic- Cch b tr, iu hnh, t chc sn xut trong x nghip- Tay ngh ca cng nhn2.4.3. Cc phng php tnh thi gian- Phng php c tnh kinh nghim : Da vo kinh nghim c tnh ca trng ca, t trng, th gii nh mc thi gian- Phng php thng k kinh nghim : Da vo giy bo nng sut ca, giy bo nhim v sn xut tnh bnh qun+ Nhn xtHai phng php trn cha c thi gian bt hp l v thi gian lng ph m ta cha th bc tch ra, khng c cn c iu chnh nh mc- Phng php iu tra phn tch: Da vo phng php o ghi cc thi gian tiu hao, thi gian lm vic ca cng nhn hoc my mc thit b di hnh thc chp nhthi gian lm vic v thi gian bm gi xy dng nh mc+ Quy trnh thc hin vic bm thi gian Gii thch cho cng nhn bit mc ch ca vic nghin cu thi gian Xc nh cc cng on c lin quan Xc nh cng nhn chu trch nhim cho tng cng on Ngi bm gi ng cho sau ngi cng nhn nhn thy 2 tay ca ngi cng nhn theo mt ng thng ngn nht.Ghi li iu kin lm vic ca ngi cng nhn gip ta tm c nhng c im ci tin- Xc nh mc bt u v kt thc mt cng on- Ngay trc khi ngi cng nhn nhc BTP ln hy tin hnh bm gi v sau khi cng nhn may xong t BTP xung th bm ng h ngng- Nu cng nhn c ng tc no bt thng th thi gian khng c tnh vo thi gian thc hin Nhn xt: i vi phng php ny phi c cch lm vic khoa hc chnh xc, phi c c quan st tng hp, chnh xc Trong qu trnh bm gi c th nh hng bi tc ng xung quanh v tm l ca ngi cng nhn khi thc hin thao tc chun Phng php tnh ton phn tch : thi gian tnh ton theo cc cng thc cng ngh, cc loi thi gian cn li c tra trong bng nh mc thi gian chun.trn c s tng hp nn mc thi gian Nhn xty l phng php tnh ton ti gian da trn nh mc tiu chun c nh trc cho tt c cc hot ng ngnh may v th phng php ny c chnh xc cao, thi gian khng b nh hng bi cc yu t khch quan khc khi thc hin tnh thi gian.nh gi chnh xc thc lc ca ngi cng nhn2.4.4. Phng php o thi gian may sn phm m hng 11101510010Sau khi xem xt v tnh ton thi gian nh mc trn t sn xut trn em la chn phng php o thi gian cho cc cng on may sn phm jacket m hng 1110510010 em bng phng php tnh ton phn tch.Bn cnh mt s cng on em s dung phng php bm gi.2.3.4.1. Thao tc lm vic Trong qu trnh sn xut ngi cng nhn lp i lp li mt cng vic nht nh.Chu trnh lm vic c chia thnh 3 thao tc sau:- Thao tc c lp i lp li trong tt c cc chu trnh- Thao tc lin quan n vic bt u v kt thc mt b hng- Thao tc thc hin tnh c do iu kin lm vic m khng lin quan n vic thc hin b hngCng nhn may sn phm phi thc hin cc thao tc sau- Nhn cc thao tc cn may,sp xp cc chi tit theo th t a ti chn vt.- a cc chi tit xp vo mayvaf kim sot ng may.ng may phi m bo ng yu cu k thut- Ct ch v a sn phn ra khi my- Tm ngng s dng my chun b cho chu trnh ln sauThi gian thc hin mt chu trnh lm vic gm 2 thnh phn:+ Thi gian may l thi gian my chy v thc hin mi mayThi gian may l thi gian c ch+ Thi gian khng may l thi gian dng my2.3.4.2 Trnh t thc hin tnh ton thi gian nh mc- Phn tch nguyn cng thnh cc tao tc v c ng- Kim tra ch vn hnh ca c thit b theo ng tiu chun k thut,tnh hnh t chc lao ng v chc v ni lm vic- Xc nh trnh t thao tc v hot ng 1cch hp l nht- Tnh ton thi gian nh mc cho cc nguyn cng da trn thi gian chun+ Theo phng php ny mi thao tc v c ng c quy nh bng 1 gi tr thi gian chun.Sau khi xem xt hp l cc thao tc v c ng bng cc ng tc thi gian chun ca thao tc v c ng c th xc nh c thi gian nh mc cho nguyn cng ang c xem xt+ Trong qu trnh xc nh thi gian nh mc, ta c th kim tra c vic s dng dng c, thit b v s hp l trong thao tc ca cng nhn tm ra nhng u v nhc im nhm loi b cc thao tc tha, ci tin thao tc t cng sut ti a cho cng on n v o lng thi gian:+ 1giy = 27.8 TMU+ 1pht = 1667 TMU+ 1gi = 1000000 TMU Cng thc tnh thi gian mayX = (BSTGTMC) +18 +PBST = (ST/CM) / (RPM0.0006)Trong :- X: thi gian may- BST: thi gian may c bn- ST/CM: s mi mi cm- RPM: s vng ti a ( s mi mi pht khi chy my )- 0.0006 : chuyn pht cho mi TMU- GT : kh ca ng may- MC : chiu di ng may- 18: cho my bt u chy v dng- P: dng chnh xc (21)V d 1 : Dng phng php tnh ton phn tch tnh thi gian ng may chp cu vai o jacket m hng 11101510010 Bit:-Tc ti a ca my 1 kim l 3450 vng/pht- Mt mi may l 4 mi/cm- Li mi u v cui ng may- Chiu di cc ng may l: L1= 20cm , L2=27cmHnh v m t:

Tac c: ST/CM = 4 mi/cmRPM= 3450 vng/phtBST= (ST/CM)/(RPM0.0006)BST= 4/(34500.0006)BST= 1.93 (TMU) Ta c X=( BSTGTMC)+18+P Thi gian thc hin ng may L1= 20cmVi GT =1 , MC=20cm , P=21Vy X20MC = (1.9320)+18+21 = 77.6(TMU) Thi gian thc hin ng may L2=27 cmX27MC=(1.9327)+18+21 =91.11(TMU) Bng 2.1: Bng thao tc thc hin cng on may chp cu vai thn sauSTT M t thao tcM sTMU

1Ly v ghp 2 chi tit bng 2 tay cng 1 lcOM2T77

2a chi tit vo chn vtOMT39

3So mp v iu chnh 2 chi tit bng 2 tayAA2P60

4Li mi u ng may bng cn gtMHTB33

5May 1 on bng 20 cmX20MC77.6

6So mp v iu chnh 2 chi tit bng 2 tayAA2P60

7May 1 on bng 27 cmX27MC91.11

8Li m cui ng may bng cn gtMHTE37

9Ct ch t ngMHMC3

10 chi tit sang bn bng 2 tayDP2H43

Thi gian thc hin thao tc: 520.71 (TMU)=18.73(s)Thi gian hao ph bng 15%= 2.8(s)Tng thi gian thc hin thao tc chp cu vai thn sau l: 18.73+2.8=21.53(s)V d 2: Dng phng php tnh toan phn tch tnh thi gian gian may ng may chp np ve thn trc vi thnBit:- Tc ti a ca my 1 kim l 3450 vng/pht- Mt mi may l 4 mi/cm- Li mi u v cui ng may- Chiu di cc ng may l: L1= 30cm , L2=28.5cmHnh v m t:

Tac c: ST/CM = 4 mi/cmRPM= 3450 vng/phtBST= (ST/CM)/(RPM0.0006)BST= 4/(34500.0006)BST= 1.93 (TMU) Ta c X=( BSTGTMC)+18+P Thi gian thc hin ng may L1= 30cmVi GT =1 , MC=30cm , P=21Vy X30MC = (1.9330)+18+21 = 96.9(TMU) Thi gian thc hin ng may L2=28.5 cmX27MC=(1.9328.5)+18+21 =94 (TMU)Bng 2.2: Bng thao tc thc hin cng on may np ve thn trcSTT M t thao tcM sTMU

1Ly v ghp 2 chi tit bng 2 tay cng 1 lcOM2T77

2a chi tit vo chn vtOMT39

3So mp v iu chnh 2 chi tit bng 2 tayAA2P60

4Li mi u ng may bng cn gtMHTB33

5May 1 on bng 20 cmX30MC96.9

6So mp v iu chnh 2 chi tit bng 2 tayAA2P60

7May 1 on bng 27 cmX28.5MC94

8Li m cui ng may bng cn gtMHTE37

9Ct ch t ngMHMC3

10 chi tit sang bn bng 2 tayDP2H43

Thi gian thc hin thao tc: 542.9 (TMU)=19,53(s)Thi gian hao ph bng 15%= 2.93(s)Thi gian thc hin thao tc chp np ve thn trc l: 19.53+2.93=22.46(s)Tng thi gian chp np ve 2 thn l: 22.462=44.92(s)2.5. Quy trnh cng ngh may sn phm jacket m hng 11101510010- Quy trnh cng ngh may da vo s lp rp v b sung thm ct c ni dung thi gian,thit b,bc th- Th t ca cc cng on trong bng quy trnh cng ngh c sp theo mt th t hp l - Trong sn xut t trng da vo bng quy trnh cng ngh phn cng lao ngBng 2.3: bng quy trnh cng ngh m hng 11101510010STTTn bc cng vicThi gian (s)Thit bBc th

1Kim tra BTP,sang du v tr ti,ng may,nhm dnh178BTC2

2May np ve thn trc50M1K3

3M np ve thn trc47M1K3

4May cp thn trc45M1K3

5M cp thn trc46M1K3

6May ci ti,dy dt,p ti vo lt52M1K3

7B ln ci ti18BTC3

8Chn ngnh tr,m chn ti40M1K3

9Diu ming ti43M1K3

10May nhm dnh vo lt np ti26M1K3

11May np ti ngc36M1K3

12Ct gt np ti ngc26M1K3

13M np ti ngc21BTC3

14Diu np ti ngc18M1K3

15May np ti vo thn34M1K3

16Diu np ti vi thn30M1K3

17May nhm dnh vo thn26M1K3

18Chp cp thn sau45M1K3

19Diu cp thn sau34M1K3

20Chp cu vai22M1K3

21Diu cu vai20BTC3

22Chp mang tay45M1K3

23Diu mang tay47M1K3

24May c np ti vo tay tri53M1K3

25Dn ti vo tay tri49M1K3

26Chp vai con (ln chnh)28M1K3

27Tra tay ln chnh54M1K3

28Chp sn (ln chnh)34M1K3

29Quay ln c vai38M1K3

30Diu c vai25M1K3

31Ct ln c vai20M1K2

32M c vai,dy dt vo vai con30BTC3

33May ai c vai26M1K3

34M ai vo vai con42M1K3

35May np ve vi TT (ln lt)50M1K3

36M np ve47M1K3

37May nhn chnh vo lt40M1K3

38May dy treo19M1K3

39Ghim dy treo vo lt13M1K2

40May vai con ln lt25M1K3

41Tra tay ln lt54M1K3

42Chp sn,t nhn dng36M1K3

43Diu ng trang tr c o30M1K3

44Tra c vi thn (ln lt)44M1K3

45Tra c vi thn (ln chnh)44M1K3

46May ln np kha50M1K3

47May p kha vo thn24M1K3

48Sa ln np 20BTC2

49M np kha55M1K3

50May np vo thn45M1K3

51M p kha27M1K3

52Ghim chun bo tay15M1K3

53May ln chun ca tay85M1K3

54Tra kha161M1K3

55Diu np o,c o93M1K3

56Ghim chun bo gu20M1K3

57May ln chun gu120M1K3

58Dp cc10My dp3

59V sinh cng nghip91M1K2

60L hon thin36Bn l hi3

61Thu ha76BTC3

CHNG 3: XY DNG TIU CHUN K THUT SN PHM O JACKET M HNG 111015100103.1. Xy dng tiu chun k thut ct - tri vi3.1.1. Tiu chun k thut tri vi- Kim tra cht lng vi trc khi a vo tri, loi b nhng l vi km cht lng- Kim tra kh vi trc khi tri ln bn ct m bo thng s kh rng s gic- Tri ng, yu cu ca bn tc nghip ct- S dng phng php tri vi xn u bn, l vi p mt tri xung di- Vi phi c t 12h trc khi tin hnh tri- Cc l vi phi m phng, khng nhn nhm, khng c trng, khng c co ko trong qu trnh tri vi, s dng thc di v nh v gt u l vi khi tri- Chiu cao ti a ca bn vi ti a 20cm- Hai bn bin vi v hai u bn vi phi ng thnh- Sau khi tri ht 1 cun vi phi ghi r y thng tin vo phiu hch ton bn ct ghi li cy vi, s lng vi u bn v gi li tem ca cy vi- Khi tri xong phi kim tra s lp vi, ghi vo phiu theo di s lng- S gic ln lp vi trn cng, ghim kp nh v chc chn, nh s mt bn theo quy nh cho tt c cc chi tit cng mt s gic3.1.2. Tiu chun k thut ct vi - Kim tra nh v s , n khp gia s v bn vi- Ct ng, chi tit theo s gic- Yu cu cc chi tit khi ct phi ng thnh, ng ct phi trn u, cc chi tit c i phi i xng nhau- Ct ph: dng my ct y tay ct cc cc chi tit ln: tay, cu vai, thn trc, thn sau, cp- Ct gt i vi tt c cc chi tit yu cu chnh xc cao: c o, np ti, c vai, ti o- Cc chi tit ct gt u phi dng kp trnh x lch khi chuyn sang my ct vng- Ct chi tit theo 1 chiu trnh bai, cm- Du bm phi chnh xc, su du bm 0,3 cm- Dng mu cng kim tra chnh xc ca chi tit sau ct-Mi tp bn thnh phm phi c b buc vi mu giy ca s gic- Khi ct xong ghi s th t mt bn ln mi tp BTP, in y thng tin vo phiu ct BTP v a BTP vo ng v tr bc tp phi kin3.1.3 Tiu chun v nh s, phi kin* nh s:- Dng bt ch hoc phn vit vo tt c cc chi tit ca BTP- S vit phi r rng, cao to khng qu 0.5cm (i vi nt bt ch),khng qu 1cm i vi nt phn, ch s st cnh ng ct 0.1cm- S c vit vo mt tri ca vi- V tr vit s:+ Thn trc, thn sau: dc sn pha nch+ Tay: dc bng tay ha nch+ Cu vai: gia vng nch+ Bn c: pha chn+ Np o: pha gt np, np ti: chn np ti

Hnh 3.1: V tr nh s chi tit sn phm m hng11101510010

* Bc tp, phi kin- Trc khi bc tp phi hiu r sn phm c bao nhiu chi tit,chi tit no c i, i xng, chi tit no c ln ngoi, ln lt- Kim tra li s mt bn gia thn to v cc chi tit nh xem c khp nhau hay khng- Bc cc chi tit cng 1 c vi nhau sau buc li gn gng-Yu cu b buc ng quy nh: dy buc cng mu, b cht ch trnh ri chi tit- Sau khi bc tp,phi kin xp gn gng c km theo phiu bn ct- Kim tra li nu t tt c cc yu cu chuyn sang b phn chun b may3.2 Tiu chun k thut may sn phm* Yu cu chung- Tt c cc ng may phi m bo m phng, khng cng ch, si ch, b mi- Cc ng diu khng c ni ch, u v cui ng may li mi 3 ng ch trng kht- ng tra kha phi u,kha tra xong khng b vn sng- Tt c cc ng m diu: 9 mi/inch- Tt c cc ng chp sn, cp 1cm- ng tra tay: 0.8cm- ng tra c: 1cm - Tt c c ng m: 0.1cm, ng diu: 0.7cm- Sn phm may xong phi t yu cu k thut

* Thn trc

Diu xung quanh ti 0.7cmDiu np ti 0.7cmM np o 0.1cmNhm dnh 2.0x2.0cmCa tay may bo chunM xung quanh ti 0.1cmDy dt rng 2cmDiu c vai 1cm* Thn sau

ng may trang tr: 9 mi/inch

Diu cu vai, cp,tay 0,7cm

Hnh 3.2: M t k thut may

Dy treoNhn chnh may cn cch chn c 3cm* Lp lt

kha may vi np m ngoi 0.1cmNhn c may cn gia chn di nhn chnhNhn s dng cch gu 15cmLt may vi m bng5cm3cmHnh 3.3: M t k thut may lp lt

3.3 Tiu chun hon thin sn phm* Tiu chun v sinh cng nghip - Sn phm sau khi hon thin phi c nht ht cc u ch tha-Ty sch cc vt bn (ty bng xng thm), sn phm khng cn vt bn trong qu trnh gia cng* Tiu chun l hon thin - Sn phm c l hon thin bng bn l hi -Nhit l 1200C- Sn phm sau khi l phi gi c phom dng, khng b bng, m bo ng thng s k thut *Tiu chun hm hp+ Bao gi sn phm- Mi sn phm mt ti nylon,c mc treo- Sn phm gp i ng quy cch - Cnh sn bn tri vo trc, mt ti l mt trc ca sn phm- Ming gp v mt tri, c bng dnh dn li* Tiu chun hm hp- Thng carton loi 5 lp (2 lp sng)- C s dng m thng pha trn v pha di- Dn ming thng bng bng dnh trong loi bn 5cm- Thng carton c thng s:DRC=655540- S lng sn phm: 6 sn phm/thng - Cc sn phm c xp cng chiu trong hp- cnh thng c in cc thng tin v v sn phm+ Tn m hng+ S n dt hng( PO number)+ Thng tin v mu c,s lng+ Thng tin xut x,ni n ca thng hng+ Kch thc thng,trng lng thng

KT LUN Trong thi gian thc hin n bng nhng kin thc hc v s ch bo tn tnh ca thy gio hng dn:thy Trn Trung Hiu v cc thy c trong khoa em hon thnh n mn hc ca mnh vi ti:" Xy dng quy trnh cng ngh may sn phm ca m hng 11101510010" Ni dung ca ti gm c:Chng 1:Nghin cu n hngChng 2:Xy dng quy trnh cng ngh mayChng 3: Xy dng tiu chuuanr k thut sn phmQu trnh thc hin n gip em tm hiu su hn kin thc c p dng ngoi thc t.y cng l tin gip em c th thc hin n tt nghip ca mnh.Mt ln na em xin gi li cm n n thy gio hng dn v cc thy c trong khoa cng ngh may v thi trang trng H s phm k thut Hng Yn.

DANH MC TI LIU THAM KHO

1. cng bi ging mn Cng ngh sn xut - Nhm tc gi Khoa Cng ngh may & Thi trang - Trng i hc SPKT Hng Yn2. cng bi ging mn Chun b sn xut - Nhm tc gi Khoa Cng ngh may & Thi trang - Trng i hc SPKT Hng Yn3. cng bi ging mn Nghin cu thi gian & thao tc - Nhm tc gi Khoa Cng ngh may & Thi trang - Trng i hc SPKT Hng Yn4. cng bi ging mn Thit k dy chuyn sn xut - Nhm tc gi Khoa Cng ngh may & Thi trang - Trng i hc SPKT Hng Yn

PH LCTi liu m hng 11101510010

6

Chp sn chnh