Do an Mon Cung Cap Dien Cua Ngo Xuan Loi

8/3/2019 Do an Mon Cung Cap Dien Cua Ngo Xuan Loi

1/78

Trng i Hc Cng Nghip H Ni Mn Cung Cp in---- Khoa i n ----

chng I

gii thiU CHUNG V NH MY

Danh sch cc phn xng trong nh my:

Theos mt

bng

Tn phn xng v ph ti Slngthit b

in

Tngcng

sut t,kW

H snhu cu,

Ksd

H scngsut,cos

1 Phn xng trm t 280 500 0.34 0.68

2 Phn xng vt liu hn 200 800 0.35 0.56

3 Phn xng nha tng hpPlasmace 100 1100 0.37 0.67

4 Phn xng tiu chun 70 250 0.37 0.78

5 Phn xng kh c in 100 700 0.37 0.72

6 Phn xng dp 100 800 037 0.67

7 Phn xng xi mng aming 50 850 0.4 0.72

8 Kho thnh phm 15 85 048 0.87

9 Kho ph liu kim loi 15 70 0.48 0.8110 Phn xng m in 50 70 0.48 0.76

11 Xem d liu phn xng

12 Trm trung ha 10 100 0.52 0.66

13 Ra knh thot axit 3 30 0.7 0.68

14 Trm bm 8 260 0.55 0.68

15 Nh n 30 70 0.43 0.56

16 Phn xng in 25 150 0.44 0.72

17 Nh iu hnh 20 50 0.46 0.78

18 Phn xng lm ngui 2 30 0.79 0.77

19 Kho axit 2 20 0.79 0.67

20 My nn s N0 1 15 200 0.48 0.72

- 1 - nmn hc : SV : Ng xun Li H in 1_K3


2/78


Cp in theo tiu chun loi 1Gi thnh tn tht in nng C=1000/kWhSut thit hi do mt in Gth=7500/kWhHao tn in p cho php trong mch tnh t ngun ( im u in) l Ucp

= 5%Cc s liu khc ly trong ph lc v s tay thit k in

Ngun in c ly t li cch nh my cch 468.72m, dng dy ACDung lng ngn mch v phia h p ca trm bin p : 250MVA, nh mylm vic 3 ca

Nhim v thit kI. Tnh ton ph ti Xc nh ph ti tnh ton phn xng Xc nh ph ti ca cc phn xng khc Tng hp ph ti ca ton x nghip, xy dng biu ph

ti trn mt bng x nghip di dng cc hnh trn bn knhr

II Xc nh s ni mng in ca nh my Xc nh v tr ca trm bin p Chon cng sut v s lng nh my bin p Chn dy dn t ngun ti trm bin p La chn s ni in t trm bin p n phn xng

( so snh t nht 2 phng n)III Tnh ton in Xc nh tn hao in p trn ng dy v trong nha my Xc nh tn hoa cng sut Xc nh tn tht in nng

IV Chn v kim tra thit b Tnh ton ngn mch ti cc im c trng Chn v kim tra thit b

Kim tra thit b m my ca ng cV Tnh ton b h s cng sut Tnh ton b cng sut phn khng nng cao h scng sut ln cos 2 = 0.9 nh gi hiu qu b

VI Tnh ton ni t v chng stVII Hch ton cng trnh

Lit k cc thit b Xc nh cc ch tiu kinh t



3/78


S mt bng x nghip vi s b tr cc thiwwts v vbiu ph ti

S mng in trn mt bng x nghip( gm c s cacc phng n so snh)

S trm bin p ( s nguyn l, s mt bng v s mt bng v mt ct trm bin p)

S ni t Bng s liu tnh ton so snh cc phng n

chng II

Xc nh ph ti tnh toncho cc phn xng v cho ton nh my

Ph ti in l cng sut tc dng P v cng sut phn khng

Q yu cu ti mt im no ca li. Khi thit k cung cp

in cho mt cng trnh tc l tnh ton lng cng sut yu

cu ca ph ti cung cp vi cng sut in m ph

ti yu cu. Do , vic u tin khi thit k cung cp incho mt cng trnh l xc nh ph ti in ca cng trnh

, tc l phi d bo ph ti ngn hn hoc di hn. y,

trong gii hn v thit k v kh nng ta ch xt bi ton xc

nh ph ti ngn hn.

D bo ph ti ngn hn l xc nh ph ti ca cng trnh

ngay sau khi cng trnh i vo vn hnh. Ph ti ny c gi

l ph ti tnh ton. Ph ti tnh ton l mt s liu cn thit

v quan trng. Bi n chnh l s liu la chn cc thit

b in nh: my bin p, thit b bo v, thit b ng ct,

dy dn, tnh ton cc tn tht cng sut, tn tht

in p, la chn cc thit b b.

Tu thuc vo qui m, c im ca cng trnh, tu

thuc vo giai on thit l s b hay k thut thi cng m- 3 - n

mn hc : SV : Ng xun Li H in 1_K3


4/78


ngi thit k phi cn nhc, la chn phng php tnh ton

ph ti cho thch hp.

I. Cc i lng c bn v h s tnh ton

1. Cng sut nh mc(Pm):

Cng sut nh mc ca mt thit b tiu th in l cng

sut ghi trn nhn hiu ca my hoc ghi trong l lch my.Vi

ng c cng sut nh mc ghi trn nhn hiu my chnh l

cng sut c trn trc ng c.

2. Cng sut t ( P ):

ng c c hiu sut c th cng sut t ca ng c:

c

m

P=P

Trong thc t th c = 0,8 0,9 c gi tr kh cao nn c ta

th xem P = Pm.

Vi thit b chiu sng cng sut t chnh l cng sut t-

ng ng vi s ghi trn hay bu n.

Vi ng c in lm vic ch lp li v d nh: cu trc,my hn th khi tnh ton ph ti in ca chng phi thc

hin qui i v cng sut nh mc lm vic ch di

hn tc l phi qui i v ch lm vic c h s tip in:

% = 100% .

Gi Pm l cng sut nh mc qui i v ch lm

vic di hn th Pm c xc nh:

Pt = Pm = Pm. m

Vi Pm, m: Cho trong l lch my.

Vi my bin p ca l in cng sut t l :

Pm = Sm. cos m

Trong :

Sm- cng sut biu kin nh mc c trong l

lch my.- 4 - n



5/78


cos m- h s cng sut ca l in khi ph ti

ca n t n nh mc.

Vi my bin p hn: Pm = Sm. cos m . m

3. Ph ti trung bnh(Ptb):

L mt c trng tnh ca ph ti trong khong thi gian

no . Tng ph ti trung bnh ph ti ca cc thit b cho

ta cn c nh gi gii hn di ca ph ti tnh ton. Hin

ti, ph ti trung bnh c tnh:

ptb = tP

; qtb = tQ

Trong :

P, Q - in nng tiu th trong thi gian kho st,

kW, kVAR.

t - khong thi gian kho st, h

Nu l mt nhm thit b th ph ti trung bnh c tnh:

Ptb = =

n

1i

ip ; Qtb = =

n

1iiq

Ph ti trung bnh l mt s liu quan trng nh gi

mc s dng in cu thit b, xc nh ph ti tnh

ton v tnh tn hao in nng.

4. Ph ti tnh ton (Ptt):

L mt ph ti gi thit lu di khng i, tng ng vi

ph ti ph ti thc t (bin i) v mt hiu ng nhit ln

nht.Tc l ph ti tnh ton l ph ti c tc dng lm nngdy dn ln ti nhit ln nht do ph ti thc t gy ra.

Ph ti tnh ton c gi tr:

Ptb Ptt Pmax

5. H s s dng (ksd): L t s gia ph ti tcdng trung bnh vi cng sut t trong khong thi gian

xem xt.



6/78


i vi mt thit b:

ksd =dm

tb

P

P

i vi mt nhm thit b:

ksd =dm

tb

P

P=

=

=n

i

dmi

n

i

tbi

P

P

1

1

H s s dng c ngha l h s ni ln mc s dng,

mc khai thc cng sut ca thit b trong khong thi

gian xem xt.

6. H s ph ti (hay cn gi l h s mang ti kpt):

L t s gia cng sut ca thit b in trong thc t vi

cng sut nh mc trong khong thi gian ang xt. N c

th hin bi cng thc:

kpt =dm

thct

P

P

H s ph ti c ngha tng t nh h s s dng l n

ni ln mc s dng, mc khai thc ca thit b trong

khong thi gian xem xt.

7. H s nhu cu (knc):

L t s gia cng sut tnh ton hoc cng sut tiu th vi

cng sut t (cng sut nh mc) ca nhm h tiu th:

knc =dm

tb

tb

tt

dm

tt

P

P.

P

P

P

P= = kmax . ksd

H s nhu cu thng dng tnh cho ph ti tc dng. Trong

thc t h s nhu cu thng do kinh nghim vn hnh tng

kt li. N c gi tr nh hn 1: knc1

8. H s cc i (kmax ) :

L t s gia ph ti tnh ton ph ti trung bnh trong mt

khong thi gian ang xt:



7/78


kmax =tb

tt

P

P

H s ny c gi tr ln hn 1 (kmax 1).H s cc i ph

thuc vo nhiu yu t: ph thuc vo sthit b hiu qu,ph thuc vo h s s dng, cc ch c trng cho ch vn hnh ca thit b. N thng oc tnh vi ca lm vicc ph ti ln nht. 9. S thit b tiu th in nng hiu qu (nhq):

Xt mt nhm gm c n thit b c cng sut nh mc vch lm vic khc nhau. Th nhq c gi l s thit b tiuth in nng hiu qu ca nhm, l mt s qui i gm

c nhq thit b c cng sut nh mcv ch lm vic nhnhau to nn ph ti tnh ton bng ph ti tiu th thc t bin thit b ca nhm ang xt.

Khi s thit b n 5 th s thit b hiu qu c xc nh:

nhq =( )

=

=

n

i dmi

n

i

dmi

P

P

1

2

2

1 (*)

Nu m nhm c tt c cc thit b cng c cng sut nhmc nh nhau th:

nhq =( )

2

2

.

.

dm

dm

Pn

Pn= n

Nu n > 5 th vic tnh nhq theo cng thc (*) kh phc tpnn thng s dng phng php n gin ho tnh nhq vi

sai s cho php trong phm vi 10%. Trnh t tnh ton Xc nh s thit b trong nhm n v tng cng sut nhmc dmnP

Chn nhng thit b c cng sut m cng sut nh mcca mi thit b ny nh hn hoc bng mt na cng sutca thit b c cng sut ln nht trong nhm thit b xt.

Xc nh s n1: l s thit b c cng sut khng nh hnmt na cng sut ca thit b cng sut ln nht, v ng vi

s thit b n1 xc nh tng cng sut nh mc: 1dmnP- 7 - n



8/78


Tm gi tr n* =n

n1 v p*=

dmn

dmn

P

P1

Sau khi xc nh c ( n*, p*) da vo cm nang tra ta s c

nhq*, t rt ra nhq* nhq = nhq* . nII. Cc phng php xc nh ph ti tnh Ton

1. Xc nh ph ti tnh ton theo sut ph ti trn mtn v din tch sn xut:

Cng thc tnh: FpPtt .0=

Trong :po - sut ph ti trn 1 m2 din tch sn xut,

KW/m2(thng c tra trong cc s tay k thut).

F - din tch sn xut, m2.Sut ph ti tnh ton trn mt n v din tch sn xut

ph thuc vo dng sn xut v theo s liu thng k.2. Xc nh ph ti tnh ton theo sut tiu hao

in nng cho mt n v sn phm:

Cng thc tnh:max

0catt

T

W.MP =

Trong :Mca - s n v sn phm sn xut ra trong

mt ca.Wo - sut tiu hao in nng cho mt n v sn phm

(KWh/nsn phm).Tmax- thi gian ca ca ph ti ln nht, h.

3. Xc nh ph ti tnh ton theo cng sut t

v h s nhu cu:Ph ti tnh ton ca nhm thit b c cng ch lm vic

c tnh theo cng thc :

tgPQ

PkP

tttt

n

i

dminctt

.

.1

=

= =

Trong :



9/78


knc - h s nhu cu (thng c tra trong cc s tayk thut).n - l s thit b trong nhm.

tg - ng vi cos c trng cho nhm thit btra trong cn

Nu h s cng sut cos ca cc thit b trong nhmkhng ging nhau th phi tnh h s cng sut trung bnhtheo cng thc:

cos tb =n

n

PPP

PPP

++++++

...

cos....cos.cos.

21

21

Phng php tnh ph ti theo cng sut t v h s nhu

cu c u im l n gin, tnh ton n gin. Nhng cnhoc im l chnh xc khng cao v knc tra trong stay.

4. Xc nh ph ti tnh ton theo h s cc ikmax v cng sut trung bnh Ptb(hay phng php sthit b hiu qu nhq):

nng cao chnh xc ca ph ti tnh ton hoc khi

khng c cc s liu p dng cc phng php n ginth s dng phng php xc nh ph ti tnh ton theo hs cc i v cng sut trung bnh. Theo phng php nyph ti tnh ton c tnh:

=

==n

i

dmisdtbtt PkkPkP1

maxmax ...

Trong :

kmax - h s cc i c tra bng da theonhq v ksd.

Phng php ny cho kt qu tng i chnh xc v khi xc

nh s thit b hiu qu th xt n mt lot cc yu t

quan trng nh: nh hng ca s lng thit b trong nhm, s

thit b c cng sut ln nht, s khc nhau v ch lm

vic ca cc thit b ...- 9 - n



10/78


Khi tnh ph ti theo phng php ny, trong mt s trng

hp c th dng cc cng thc gn ng sau xc nh ph

ti tnh ton :

Trng hp n 3 , nhq < 4 :

=

=

=

=

n

i

dmitt

n

i

dmitt

QQ

PP

1

1

Trng hp n > 3 v nhq < 4 :

dmi

n

i

ptitt PkP .1==

Trong : Kpti - h s ph ti ca thit b th i.

Nu nhq > 300 v ksd < 0,5 th h s cc i

kmax s ly ng vi n hq= 300. Cn nu nhq> 300

v ksd 0,5 th:

Ptt = 1,05.ksd.Pdm

III Xc nh ph ti tnh ton c th

A. Xc nh ph ti tnh ton phn xng

Tu theo thng tin thu nhp c ca ph ti in m ta

chn phng php xc nh ph ti tnh ton cho hp l.

Do mi ch bit cng sut t ca tng phn xng nn ta

xc nh ph ti tnh ton theo phng php cng sut t

v h s nhu cu.

i vi ph ti chiu sng th ta xc nh ph ti tnh ton

theo phng php sut ph ti trn mt n v din tch sn

xut



11/78


Din tch thc t: din tch bn v x 10002 ( t l : 1/10002)

Theo t l ta c thng s din tch theo bng s liu sau:

theos mt

bng

Tn Phn Xng Din tchbn v(mm2)

Din tchthc t(m2)

1 Phn xng trm t 33*19 627

2 Phn Xng vt liu hn 36*29 1044

3 Phn xng nha Tng hpPlasmace

34*12 408

4 Phn xng tiu chun 33*11 363

5 Phn xng kh c in 34*7 238

6 Phn xng dp 38*16 608

7 Phn xng Xi mng aming 12*22 264

8 Kho thnh phm 12*22 264

9 Kho ph liu kim loi 10*8 80

10 Phn xng m in 6*22 13211 Xem d liu phn xng 15*10 150

12 Trm trung ha 14*9 126

13 Ra knh thot axit 11*8 88

14 Trm bm 9*10 90

15 Nh n 8*12 96

16 Phn xng in 15*10 150

17 Nh iu hnh 13*8.5 110.5

18 Phn xng lm ngui 28*9 252



12/78


19 Kho axit 10*8 80

20 My nn s No 1 12*10 120

Phn xng trm t

Cng sut tnh ton ng lc:

Pdl = knc.P = 0.34*500=170kW

Cng sut tnh ton chiu sng:

Pcs = p0.F = 15*627 = 9.405kW

Cng sut tnh ton tc dng ca phn xng:

Ptt= Pdl + Pcs =170 + 9.405= 179.405kW

Cng sut tnh ton phn khng ca phn xng:

Qtt = Qdl = Ptt.tg =179.405*1.078= 193.4kW- 12 - n



13/78


Cng sut tnh ton ton phn ca phn xng:

Stt = Ptt/cos = 179.405/0.68 =263.83kW

Cc phn xng khc tnh tng t, kt qu c ghi trong bng

sau:



14/78



peo

t

ng

Tn Phn Xng Pd,kW

cos

Ksd Po,W/m2

Pdl,kW

F(m2)

Pcs,kW

Ptt,kW

Qtt,kWAr

Stt,KVA

1 Phn xng trm t 500 0.68 0.34 15 170 627 9.405

179.4

193.4

263.8

2 Phn Xng vt liu hn 800 0.56 0.35 15 280 1044

15.66

295.7

437.5

528

3 Phn xng nha Tng hpPlasmace

1100

0.67 0.37 15 407 408 6.12 413.1

457.7

616.6

4 Phn xng tiu chun 250 0.78 0.38 15 95 363 5.445

100.4

80.55

128.8

5 Phn xng kh c in 700 0.72 0.37 15 259 238 3.57 262.6

253.1

364.7

6 Phn xng dp 800 0.67 0.37 15 296 608 9.12 305.1

338.1

455.4

7 Phn xng Xi mngaming

850 0.72 0.4 14 340 264 3.696

343.7

331.3

477.4

8 Kho thnh phm 85 0.87 0.48 15 40.8 264 3.96 44.76

25.37

51.45

9 Kho ph liu kim loi 70 0.81 0.48 14 33.6 80 1.12 34.72 25.14 42.8610 Phn xng m in 120

00.76 0.4 14 480 132 1.84

8481.

8412 634

11 Xem d liu phn xng 150 0 012 Trm trung ha 100 0.66 0.52 12 52 126 1.51

253.5

160.9

181.0

813 Ra knh thot axit 30 0.68 0.7 10 21 88 0.88 21.8

823.6 32.1

814 Trm bm 260 0.68 0.55 15 143 90 1.35 144.

4155.

7212.

315 Nh n 70 0.56 0.43 15 30 96 1.44 31.4

446.5

156.1

416 Phn xng in 150 0.72 0.44 15 66 150 2.25 68.2

565.7

894.7

917 Nh iu hnh 50 0.78 0.46 20 23 110.

52.21 25.2

120.2

332.3

2

18 Phn xng lm ngui 30 0.77 0.79 14 23.7 252 3.528 27.23 22.56 35.3619 Kho axit 20 0.67 0.79 14 15.8 80 1.12 16.9

218.7

525.2

520 My nn s No 1 200 0.72 0.48 10 96 120 1.2 97.2 93.6

8135


15/78


Ph ti tnh ton tc dng ton nh my:

Pttnm=kt.20

1

Ptti

Pttnm = 0.8*(179.4 + 295.7+ 413.1+ 100.4+ 262.6+ 305.1+ 343.7+44.76+ 34.72+ 481.8+ 53.51+ 21.88+ 144.4+ 31.44+ 68.25+25.21+ 27.23+ 16.92+ 97.2)

Pttnm= 0.8*2947 =2357.6 (kW)Ph ti tnh ton phn khng ton nh my:

Qttnm= kt.20

1

Qtti

Qttnm = 0.8*3062 = 2449.6 (kW)Ph ti tnh ton ton phn ca nh my:

Sttnm= )6.2449*6.2449()6.2375*6.2357( + =3399.826(kW)

H s cng sut ca nh my:cos nm= Pttnm/Sttnm =2357.6/3399.826 =0.6934

Vy Pttnm = 2357.6(kW)Qttnm = 2449.6 (kW)Sttnm = 3399.826(kW)

Xy dng bn ph ti

Xc nh biu ph ti:

-Vic phn b hp l cc trm bin p trong phm vi x nghip l mt vn quan trng xy dng s cung cp in c cc ch tiu kinh t, k thut

cao, m bo c chi ph hng nm nh. xc nh c v tr t cc trm

bin p ta xy dng biu ph ti trn mt bng tng ca x nghip.

- Biu ph ti l mt vng trn c din tch bng ph ti tnh ton ca

phn xng theo mt t l la chn.



16/78


- mi phn xng c mt biu ph ti. Tm ng trn biu ph ti

trng vi tm ca ph ti phn xng, tnh gn ng c th coi ph ti ca phn

xng ng u theo din tch ca phn xng.

- Biu ph ti cho php hnh dung c r rng s phn b ph ti trong

x nghip

- Mi vng trn biu ph ti chia ra thnh hai phn hnh qut tng ngvi ph ti ng lc v ph ti chiu sng

1.2.3/ Xc nh bn knh vng trn ph ti:

- ng knh t l ca biu ph ti:

gip cho vic t trm phn phi v cc trm bin p

phn xng mt cch hp l t hiu qu kinh t nht v gim

c tn tht n mc thp nht ta phi xc nh trung tm

ph ti ca tng trm. Mun xc nh trung tm ph ti ta

cn phi da vo bn ph ti ca cc phn xng. Tm ca

nhng ng trn chnh l trung tm ph ti ca cc phn x-

ng.

+Cng thc tnh:

RX=m

SttX.

Tron :

+ S ttX :Ph ti tnh ton ca phn xng th X ( kva)

+ Ri : Bn knh vng trn biu ph ti ca phn xng th X (mm)

+ m : T l xch ( kva/mm 2 )

*/ Gc chiu sng ca biu ph ti :

cs =tt

cs

P

P.360

xc nh biu ph ti ta chn m=50 kva/cm 2

1.2.4. Biu xc nh tm ph ti.- 16 - n



17/78


Trn s mt bng x nghip v mt h to xoy, c

v tr to trng tm ca cc phn xng l ( xi, yi ) ta xc

nh c to ti u M0(x0, y0 )

Vng trn ph ti :

1545

1

Tn phn xng; Cng sut tnh ton ca phn xng

Phn Xng trm t:


Gc ph ti chiusng.

Ph ti nglc.

cs


18/78


theos mt

bng

Tn Phn Xng Pcs,kW

Ptt,kW

Qtt,kWAr

Stt,KVA

R(mm)

0cs

1 Phn xng trm t 9.405 179.4 193.4 263.8 8.2 18.872 Phn Xng vt liu hn 15.66 295.7 437.5 528 10.5 19.063 Phn xng nha Tng hp Plasmace 6.12 413.1 457.7 616.6 6.6 5.334 Phn xng tiu chun 5.445 100.4 80.55 128.8 6.2 19.55 Phn xng kh c in 3.57 262.6 253.1 364.7 5 4.896 Phn xng dp 9.12 305.1 338.1 455.4 8 10.7

7 Phn xng Xi mng aming 3.696 343.7 331.3 477.4 5.3 3.878 Kho thnh phm 3.96 44.76 25.37 51.45 5.3 31.89 Kho ph liu kim loi 1.12 34.72 25.14 42.86 3 11.6

10 Phn xng m in 1.848 481.8 412 634 3.75 1.38

11 Xem d liu phn xng 0 0

12 Trm trung ha 1.512 53.51 60.91 81.08 3.65 10.1713 Ra knh thot axit 0.88 21.88 23.6 32.18 3 14.47

14 Trm bm 1.35 144.4 155.7 212.3 3.1 3.36615 Nh n 1.44 31.44 46.51 56.14 3.2 16.4816 Phn xng in 2.25 68.25 65.78 94.79 4 11.8617 Nh iu hnh 2.21 25.21 20.23 32.32 3.4 31.5518 Phn xng lm ngui 3.528 27.23 22.56 35.36 5.2 46.6419 Kho axit 1.12 16.92 18.75 25.25 2.9 23.8320 My nn s N0 1 1.2 97.2 93.68 135 3.57 4.44



19/78




20/78


21

10

53 4

18

15

8 7 611

16

149 19 20 13 12

17

- 20 - n mn hc : SV : Ng xun LiH in 1_K3


21/78


CHNG III

Thit k mng cao p cho ton nh my

Theo s liu ban u th Nh my c c cung cp in

t trm bin p trung gian (BATG) cch nh my 507,05m. ch-

ng 2, ta xc nh c cng sut tnh ton ca cc phn

xng v ton nh my. Vi s liu d nh t trm phn

phi trung tm (PPTT) nhn in t trm BATG v ri phn

phi cho cc trm bin p phn xng (BAPX).

I. V tr trm phn phi trung tm.

gim chi ph u t cho dy dn v gim tn tht in

nng tc m bo v tiu chun kinh t th trm phn phi

trung tm phi t trung tm ph ti ca ton nh my.

Trn mt bng nh my gn mt h to vung gc XOY.

V tr tm ph ti ca ton nh my M(X,Y) c xc nh

theo cng thc:

X =

=

=11

1

11

1

.

i

i

i

i

i

S

xS

; Y =

=

=11

1

11

1

.

i

i

i

i

i

S

yS

(3.1)

Trong :

xi ,yi : To tm ph ti ca phn xng th i.

X,Y : To tm ph ti in ton nh my.

Si : Cng sut tnh ton ph ti phn xng

th i,kVA.



22/78


Bng 3.1 Ta tm ph ti ca cc phn xng, trm

BA trung tm v ngun.

theos mt

bng Tn Phn Xng X Y1 Phn xng trm t 77.5 54.52 Phn Xng vt liu hn 83 21.53 Phn xng nha Tng hp Plasmace 84.5 102.54 Phn xng tiu chun 84.5 102.55 Phn xng kh c in 84.5 84.256 Phn xng dp 51.5 104.57 Phn xng Xi mng aming 45.5 64.58 Kho thnh phm 45.5 419 Kho ph liu kim loi 14 58.510 Phn xng m in 103 5311 Xem d liu phn xng 45.5 141.512 Trm trung ha 13 124

13 Ra knh thot axit 15.3 105.514 Trm bm 11.5 42.515 Nh n 71.75 144.7516 Phn xng in 30.5 141.517 Nh iu hnh 11 42.7518 Phn xng lm ngui 91.5 143.519 Kho axit 14 69.520 My nn s No 1 14.75 87.5



23/78


Tm ph ti ca ton nh my c to l : M

(67.57;73.47)

trong :

X=67,57

Y=73.47

Cc phng n t trm bin p

Phng n 1: Ch dng mt trm bin p t ngay trmphn phi trung tm. Trm ny c ta 00O(67,57;73,47)

Phng n 2: : Dng 4 trm bin p : TBA1,TBA2,TBA3,TBA4

Trm 1 cung cp cho phn xng:1, 2, 10

Trm 2 cung cp cho phn xng: 3, 4, 5, 18, 15

Trm 3 cung cp cho phn xng: 7, 8, 9, 14, 19

Trm 4 cung cp cho phn xng: 6, 11, 12, 13, 16, 17, 20

Ta xc nh to ca cc trm bin p theo cng thc:

+ X BAi =

i

ii

S

.xS; + Y BAi =

i

ii

S

.yS

-Trm 1:

X 1BA = 87.908.1425

5.129570

5286348.263

103*52883*6348.263*5.77==

++++

Y1BA

=27.39

8.1425

1.55992

5286348.263

53*5285.21*6348.263*5.54==

++

++

-Trm 2:

X 2BA = 11.846.1201

101067

36.3514.567.3648.1286.616

101067==

++++

Y 2BA = 14.1006.1201

120330

36.3514.567.3648.1286.616

16.5074265.812630726132025.63201 ==++++++++

-Trm 3:

X 3BA = 25.253.21286.4245.514.477 14*25.253.212*5.1114*86.425.45*45.515.45*4.477 ++++ ++++ = 93.3326.809 66.27457 = - 23 - n



24/78


Y 3BA =25.253.21286.4245.514.477

5.69*25.253.212*5.425.58*86.4241*45.515.64*4.477

++++++++

= 57.07

-Trm 4:

X 4BA = =+++++ +++++ 13532.3279.9418.3208.814.455135*75.1432.32*1179.94*5.3018.32*3.1508.81*134.455*5.51 36.4

Y 4BA =

5.10513532.3279.9418.3208.814.455

135*5.8732.32*75.4279.94*5.14118.32*5.10508.81*1244.455*5.104=

++++++++++

Ta xc nh c to ca cc trm bin p trn l:

Trm 1 O 1 (90.87;39.27)

Trm 2 O 2 (84.11 ; 100.14)Trm 3 O 3 (33.93 ; 57.07)

Trm 4 O 4 (36.4; 105.5)

Phng n 3: chia thnh 7 nhm:

Trm 1 cp in cho Phn xng 1; 5

Trm 2 cp in cho Phn xng 2

Trm 3 cp in cho Phn xng 10Trm 4 cp in cho Phn xng 3

Trm 5 cp in cho Phn xng 4; 15; 18

Trm 6 cp in cho Phn xng 7; 8; 9; 14; 19

Trm 7 cp in cho Phn xng 6; 11; 12; 13; 16; 17; 20

S ni dy t trm bin p n cc phn xng:

m bo an ton v m quan trong x nghip cc tuyn dy s c xy dngbng ng cp.

C th so snh theo cc phng n sau:

Phng n 1: Ta dng 1trm bin p t ngay trm phn phi trung tm.

T trm bin p ni dy n cc phn xng theo ng thng, cc t phn phi s

c t ngay ti u cc phn xng cung cp in cho cc thit b trong xng



25/78


Phng n ny c tng chiu di nh nht nhng khng thun tin cho vic thi cng,

vn hnh v pht trin mng in nn khng c tnh kh thi. V vy ta loi b phng

n ny.

Phng n 2 : Cng ko trc tip t trm bin p n cc phn xng ,

nhng theo ng b gc , Cc ng cp s c xy dng dc theo cc mp

ng v nh xng , nh vy s thun tin cho vic xy dng , vn hnh v

pht trin mng in , tuy nhin chiu di ca cc tuyn dy s tng hn so vi

phng n 1.

Phng n 3: Dng 2 trm bin p c ni t trm phn phi trung

tm. Phng n ny ni dy t cc trm bin p n cc phn xng theo

ng thng, cc t phn phi s c t ngay ti u cc phn xng cung

cp in cho cc thit b trong xng.

Phng n ny c tng chiu di nh nht nhng khng thun tin cho vic

thi cng , vn hnh v pht trin mng in nn khng c tnh kh thi. V vy ta

loi b phng n ny.

Phng n 4: Dng 2 trm bin p c ni t trm phn phi trung tm.

Phng n ny cng ko dy trc tip t trm bin p n cc phn xng nhng theo

ng b gc, cc ng cp s c xy dng dc theo cc ng mp v nh xng.

Nh vy s thun tin cho vic xy dng, vn hnh v pht trin mng in, tuy nhin

chiu di tuyn dy s tng ln so vi phng n 3.

Phng n 5: Dng 4 trm bin p c ni t trm phn phi trung tm.

Phng n ny c ni dy trc tip t cc trm bin p n cc phn xng theo

ng cho. Phng n ny c chiu di dy ngn nhng kh lp t v vn hnh.

Do vy phng n ny cha c ti u.

Phng n 6: Dng 4 trm bin p c ni t trm phn phi trung tm.- 25 - n



26/78


Phng n ny c ni dy trc tip t cc trm bin p n cc phn xng theo

cc ng b vung gc. Phng n tuy chiu di dy ln nhng d lp t v vn

hnh, pht trin nh my.

I./ LA CHN MY BIN P.

1. Cc phng n ni dy bin p.

1.1. Phng n 1: s ni dy hnh tia.

H1: S ni dy hnh tia

a. u - nhc im:

+ u im: tin cy cung cp in cao, thun tin cho qu trnh thi cng, vn

hnh

V sa cha.

+ Nhc im: Vn u t kh ln.

b. Thnh phn:

B: Trm bin p phn xng.

1 : Thanh ci trm bin p phn xng.

2 : Thanh ci t phn phi ng lc.

3 : Ph ti dng in.


B

22

2 23

1


27/78


1.2. Phng n 2: S ni phn nhnh.

H 2: S ni phn nhnh.

a. u_nhc im:

-u im: Gi thnh r, lp rp nhanh v tit kim c t phn phi.

-Nhc im: tin cy cung cp in thp, phc tp khi bo v.b. Thnh phn: trm bin p trn gm c:

B : Trm bin p phn xng.

1 : Thanh ci trm bin p phn xng.

2 : Thanh ci t phn phi ng lc.

3 : Ph ti dng in.

Cn c kt qu trn chn dng cc b t 3 pha do Lin X ch to, b t c

bo

v bng ptmt, trong t c t cc bng n lm in tr phng in.

1.3. Phng n 3: S ni dy hn hp.- 27 - n


B

122

23


28/78


H 3: S ni dy hn hp.a. c im:

- tin cy cung cp in cao, thun li cho qu trnh vn hnh v sa cha.

- Gi thnh thp, lp rp nhanh, tit kim t phn phi.

b. Thnh phn:

B : Trm bin p phn xng.

1 : Thanh ci trm bin p phn xng.2 : Thanh ci t phn phi ng lc.

3 : Ph ti dng in.

Trong cc phng n trn ta thy phng n 3 l kh thi nht v n kt hp

c c 2 ch tiu kinh t v k thut.

1. Xc nh s lng, dung lng trm bin p.

2.1./ Gii thiu chung.

Trong h thng in bin i t cp in p ny sang cp in p khc

ngi

ta dng my bin p. Vn u t cho my bin p trong tng vn u t l kh

ln,


B

21

2

2

211

1

3


29/78


v vy vic la chn s lng v cng sut cc my bin p trn c s kinh t,

k

thut cho cc trm bin p phn xng c ngha quan trng xy dng hp

l s

cung cp in cho nh my.

1.1.1. S lng trm bin p.

H tiu th loi 1 cn c cung cp t hai ngun in c lp trong

c th m bo cung cp cho tt c cc h tiu th khc. m bo tin

cy cung cp in cho

h tiu th loi 1 t mt trm bin p, t nht mi phn on thanh ci phi ni

vi mi my bin p v cng sut ca my bin p c chn sao cho khi hng

mt trong

chng th my cn li vi kh nng qu ti ca mnh, phi m bo cung cp

cho tt

c cc h tiu th loi 1.

Cn lu rng, ti cc trm bin p phn xng vi hai my bin p,

hp l nht l cc phn on thanh gp in p thp lm vic ring r. Khi

dng in ngn mch s gim bt hai ln v iu kin lm vic ca cc kh c

in, in p thp s c

gim nh. Khi ct mt my bin p my cn li s m nhn c ph ti ca my

kianh ng ptmt phn on. Vic ng ngun d tr cho h loi 1 c thc

hin t ng. Cc phn xng loi 3 ly in t pha h p ca trm bin p

phn xng

cnh hoc t ring trm bin p c mt my bin p.

2.1.2.V tr cc trm bin p.- 29 - n



30/78


Trm c t cnh cc phn xng, v kt cu trm c xy kn mt

tng l

tng ca phn xng. Cc trm bin p p dng s ni my bin p qua

dao cch

ly-cu ch. i vi trm mt my b tr thnh hai phng: phng cao p t cc

thit b

cac p, phng h p t my bin p v cc thit b phn phi h p. Trm hai

my bin p b tr 4 phng, mt phng t hai t cao p, mt phng t cc t

h p v hai phng cn li mi phng t mt my bin p.

2.1.3. Chn dung lng my bin p.

Trong h thng in cung cp in cho nh my, cng sut ca my bin

p in

lc trong iu kin bnh thng phi cung cp cho tt c cc h tiu th. Khi

chn cng sut MBA cn phi m bo ch lm vic v mt kinh t, m

bo d tr r nt hoc khng r rt thch hp cung cp cho h tiu th khi

ct mt my bin p. Thm vo ph ti ca MBA trong iu kin bnh

thng khng c lm gim tui th ca MBA (theo iu kin pht nng).

tin cy cung cp in ca nh my t c nh trm hai MBA. Cn

lu rng trong khi s c mt MBA my cn li phi m bo ton b cng

sut yu cu ca h tiu th loi 1. Vic m bo cng sut yu cu thc hin

c khng ch do s dng cng sut danh nh ca MBA m phi k n khnng qu ti ca n (vi mc ch gim cng sut t ca MBA). Kh nng qu

ti ca MBA tu thuc vo th ph ti ca h tiu th nhn in t MBA. C

hai trng hp cho php qu ti MBA: qu ti s c v qu ti thng xuyn

khi vn hnh.

Qu ti s c: l ch qu ti cho php trong mt s trng hp ngoi l

(s c) vi mt thi gian hn ch khng gin on vic cung cp in nng.- 30 - n



31/78


Trong iu kin s c, cho php MBA (vi bt k h thng lm mt no)

khng ph thuc nhit mi trng lm mt, c th lm vic trong thi gian 5

ngy m theo th ph ti hai bc, vi ph ti bc hai khng qu 0,93 v ph

ti bc hai t n 1,4 cng sut nh mc nhng thi gian bc hai khng qu 6

gi mt ngy (tng thi gian gin on hay lin tc). Lc ny cn tng cng

lm mt.

Qu ti thng xuyn: l ch lm vic xt trong mt khong thi gian

no (ngy, thng, nm), trong c mt khong thi gian MBA lm vic

non ti v khong thi gian cn li ca chu k kho st MBA mang ti nh hn

nh mc.Mc qu ti c tnh ton sao cho hao mn cch in trong

khong thi gian xt khng vt qu nh mc, tng ng vi nhit cun

dy 98 .

C hai kh nng qu ti cho php cng li nhng khng c vt qu 50% tc

l

S qt 1,5.S dd

Tm li chn cng sut MBA ta s dng CT sau:

Vi trm t 1 MBA: iu kin S mB ttS

Vi trm t 2 MBA: iu kin S mB 2

ttS v S mB 4,1

SCS

Trong :

S mB - cng sut nh mc MBA (kVA).

Stt

- cng sut tnh ton ca ph ti (kVA).S SC - cng sut yu cu lc s c (kVA).

Chn MBA loi do ABB sn sut, khng cn hiu chnh nhit , ng thi

gim c chi ph u t do tit kim ngoi t. Sau y tin hnh tnh ton la

chn MBA cho cc trm bin p.

2.2. Tnh ton v la chn.



32/78


Ph ti loi 1

Gi thnh tn tht in nng C = 1000 / kwh

Sut thit hi do mt in g th = 7500 / kwh.

2.2.1. Phng n 1:

Dng mt trm bin p t ngay trm phn phi trung tm. Trm ny cung cp

cho tt c cc phn xng nn ta chn t 2 MBA lm vic song song.

Chn MBA c: S mBA 4,1

ttS = 30474,1

4267 = (kVA)

Ta chn 2 MBA c cng sut = 3200 (kVA) do ABB ch to

2.2.4. Phng n 2:Ta dng 4 trm bin p:

Trm 1 cung cp in cho cc phn xng : 1, 2, 10

Trm 2 cung cp in cho cc phn xng : 3, 4, 5, 18, 15

Trm 3 cung cp in cho cc phn xng : 7, 8, 9, 14, 19

Trm 4 cung cp in cho cc phn xng : 6, 11, 12, 13, 16, 17, 20

Vi trm 1 ta c:

S 1ttN = Stt1+ Stt2+ Stt10 = 1398

Chn MBA c : S 1mBA 4,1

1ttS = 10004,1

1398= (kVA)

Nh vy ta chn 2 MBA c cng sut S 1mBA =1000 (kVA).

Hoc 1 MBA c cng sut 2000 (kVA).

Vi trm 2 ta c:

S 2ttN = Stt3+ Stt4+ Stt5 + Stt15+ Stt18 = 1202


1ttS = 2.8584,1

1202= (kVA)

Nh vy ta chn 2 MBA c cng sut S 1mBA =1000 (kVA).

Hoc 1 MBA c cng sut 2000 (kVA).- 32 - n



33/78


Vi trm 3 ta c:

S 3ttN = Stt7+ Stt8+ Stt9 + Stt14+ Stt19 = 809.26

Chn MBA c : S1mBA

4,11ttS

=578

4,1

26.809

= (kVA)Nh vy ta chn 2 MBA c cng sut S 1mBA =630 (kVA).


Vi trm 4 ta c:

S 1ttN = Stt6+ Stt16+ Stt12 + Stt13+ Stt17 + Stt20= 830.77


1ttS = 407.5934,1

77.830= (kVA)

Nh vy ta chn 2 MBA do ABB sn xut c cng sut S 1mBA =630 (kVA).


Phng n 3: chia thnh 7 nhm:

Trm 1 cp in cho Phn xng 1; 5




Trm 5 cp in cho Phn xng 4; 15; 18

Trm 6 cp in cho Phn xng 7; 8; 9; 14; 19

Trm 7 cp in cho Phn xng 6; 11; 12; 13; 16; 17; 20

Vi trm 1 ta c:

S 1ttN = Stt1+ Stt5 = 263,8 + 364,7 = 628,5 (kVA)


1ttS = 4494,1

5.628= (kVA)

Nh vy ta chn 2 MBA do ABB sn xut c cng sut S 1mBA =500(kVA).


Vi trm 2 ta c:

SttN2 = Stt2 = 528 (kVA)- 33 - n



34/78



1ttS = 3774,1

528 = (kVA)


Hoc 1 MBA c cng sut 800 (kVA).Vi trm 3 ta c:

SttN3 = Stt10 = 528 (kVA)


3ttS = =4,1

634453(kVA)



Vi trm 4 ta c:

SttN4 = Stt3 = 528 (kVA)


4ttS = =4,1

3.616440(kVA)



Vi trm 5 ta c: SttN5 = Stt4+ Stt15 + Stt18 = 128.8 + 56.14 + 35.35= 220.3(kVA)


1ttS = 35.1574,1

3.220 = (kVA)



Vi trm 6 ta c:

SttN6 = Stt7+ Stt8 + Stt9 + Stt14+ Stt19 = 477.4+ 51.45+ 42.86+ 212.3+ 25.25

= 810(kVA)


6Stt= 578

4,1

810= (kVA)





35/78


Vi trm 7 ta c:

SttN7 = Stt6+ Stt12+ Stt13+ Stt16+ Stt17+ Stt20=455.4+ 81.08+ 32.18+ 94.79+

135+32.32= 830.77(kVA)


7SttN= 4.593

4,1

77.830 = (kVA)



Ta c bng tnh ton sau:

Phngn

S trmv

S trng hp

Cngsut

nh

mc

Cngsut

tnh

ton

Hao tncng

sut

inp

NM

Vnu t

Trm Trng

hp

S mBA S tt 0P KP U K K.10 6

VN1 1 1 23200 4267 1,75 13 7 220.5

2

1 1 21000 1398 1,75 13 5 220.52 12000 2,7 22,5 6 731.5

2 1 2 1000 1202 1,75 13 5 204.35

2 12000 2.7 22.5 6 731.53 1 2630 809,26 1,3 8,2 4,5 204.35

2 11000 1.9 13 6.5 220,5

4 1 2630 830.77 1,3 8,3 4,5 204.352 11000 1,75 13 5 220,5

3 1 1 2500 628.5 1 7 4 187.352 11000 1.75 13 5 220.5

2 1 2400 528 0.84 5.75 4 167.652 1800 1.4 10.5 5

3 1 2630 809.26 1.3 8.3 4,5 204.35- 35 - n



36/78


2 11000 1,75 13 5 220.54 1 2500 528 1 7 4 187.35

2 11000 1,75 13 5 220.55 1 2160 220.3 0.5 2.95 4

2 1315 0.72 4.85 4 158.256 1 2630 810 1.3 8.3 4.5 204.35

2 11000 1.9 13 5 220.57 1 2630 830.77 1.3 8.3 4.5 204.35

2 11000 1.9 13 5 220.5

Bng cc tham s ca my bin p do ABB Vit Nam sn xut

So snh cc phng n:

By gi ta s i so snh 4 phng n la chn trn tm ra phng n ti

u.

Phng n 1 :

t 1 trm trung tm 2 my bin p c cng sut 3200 KVA

Phng n 2 :

Trm 1 :t 2 my bin p c cng sut = 2000 (KVA)




Phng n 3 :








Ta c:

= ( 0,124+ T M .10 4 ) 2 . 8760- 36 - n



37/78


= ( 0,124 + 4500.10 4 ) 2 . 8760 = 2886,21 (h)

a. Phng n 1:

S SC = m12 . S tt = 0,7.1679,89= 1175,9 (kVA)

Kqt = 1759,11000

9,1175==

mBA

SC

S

S

Xc nh tn tht do mt in :

Do phng n ny chu c qu ti khi gp s c nn khng mt in

Vy Y 2 =0

Tn tht trong MBA c xc nh theo biu thc:

A 1BA = (n.P 01 .8760 + ..2 2 1

21

nBA

K

S

SP )

= 2.1,75.8760 + 21,2886.1000

89,1679.

2

132

2

= 83602,32 (kWh).

Chi ph b tn tht l:

C 1 =C . 1BAA = 1000. 83602,32 = 83,6.10 6 (/nm).

Chi ph qui i :

Z = (a vh + a tc ).V + C

Suy ra: Z 1 = 0,185.220,5.10 6 + 83,6.10 6 =124,4.10 6 (/nm).

b. Phng n 2:

- Trm 1:

Tn tht trong MBA c xc nh theo CT:

A 21BA =(n. 01P .8760+ ..2 2 1

21

nBA

K

S

SP)

= 2.1,75.8760 + 21,2886.1000

1398.

2

132

2

= 67325.33 (KWh)

Chi ph b tn tht l:

C 21 =C. 21BAA =1000. 67325.33= 67,325.10 6 (/nm).



38/78


Chi ph qui i :

Z = (a vh + a tc ).V + C

Z 21 = 0,185.220,5.10 6 + 67,325.10 6 =108,117.10 6 (/nm).

Trm 2:


22BAA =(n.P 02 .8760 + ..2 2 2

221

nBA

K

S

SP)

= 2.1,75.8760 + 21,2886.1000

1202.

2

132

2

= 57765,05 (KWh).Chi ph b tn tht l:

C 22 = C . 22BAA = 1000 . 57765,05 =57.765.10 6 (/nm).

Chi ph qui i :

Z = (a vh + a tc ).V + C

Z 22 = 0,185.220.5.10 6 + 57,765.10 6 =98,557.10 6 (/nm).

Trm 3:


A 31BA =(n. 01P .8760+ ..2 2 1

21

nBA

K

S

SP)

= 2.1,3.8760 + 21,2886.630

5.628.

2

2,82

2

= 42301.7(KWh)

Chi ph b tn tht l:C23=C. A BA23 =1000. 42301.7= 42,301.10 6 (/nm).

Chi ph qui i :

Z = (a vh + a tc ).V + C

Z23= 0,185.204,35.10 6 + 42,301.10 6 =80,105.10 6 (/nm).

Trm 4:

Tn tht trong MBA c xc nh theo CT:- 38 - n



39/78


ABA24 =(n.P 02 .8760 + ..2 2 2

2

nBAS

SP)

= 2.1,3.8760 + 21,2886.630

77.830.

2

2,82

2

= 43353.48 (KWh).

Chi ph b tn tht l:

C24 = C .ABA24= 1000 . 43353.48 =43,354.10 6 (/nm).

Chi ph qui i :

Z = (a vh + a tc ).V + C

Z24= 0,185.204.35.106

+ 43,354.106

=72,158.106

(/nm).Vy tng chi ph qui i l: Z2= Z21+ Z22+Z23+Z24= 108,117.10 6 +80,105.10 6

+98,557.10 6 +72,158.10 6 = 358,973.10 6 (/nm).

c. Phng n 3:

Trm 1:


ABA31=(n.P 03 .8760 + ..2 2 3

231

nBA

K

S

SP)

= 2.1.8760 + 21,2886.500

5.628.

2

72

2

= 33481,23 (KWh).

Chi ph b tn tht l:

C31 = C

.ABA31= 1000 . 33481,23 =33,481.106

(/nm).Chi ph qui i :

Z = (a vh + a tc ).V + C

Z31= 0,185.187,35 6 + 33,481.10 6 =58,44.10 6 (/nm).

Trm 2:- 39 - n



40/78



A 41BA =(n. 01P .8760+ ..2 2 1

21

nBA

K

S

SP)

= 2.0,84.8760 + 21,2886.400

528.

2

75,52

2

= 14716.85(KWh)

Chi ph b tn tht l:

C 32 =C. 32BAA =1000. 14716.85 = 14,716.10 6 (/nm).

Chi ph qui i :

Z = (avh

+ atc

).V + C Z 32 = 0,185.167,65.10 6 + 14,716.10 6 =45,731 .10 6 (/nm).

Trm 3:


ABA33=(n.P0.8760 + ..2 2 2

233

nBA

K

S

SP)

= 2.1,3.8760 + 21,2886.63026.809

.2

3,8

2

2

= 42540 (KWh).

Chi ph b tn tht l:

C 42 = C. 42BAA = 1000 . 42540= 42,54.10 6 (/nm).

Chi ph qui i :

Z = (a vh + a tc ).V + C

Z33= 0,185.204,35.106

+ 42,54.106

=80,345.106

(/nm).Trm 4:


34BAA =(n.P 03 .8760 + ..2 2 3

234

nBA

K

S

SP)

= 2.1.8760 + 21,2886.500

528.

2

72

2

= 28785 (KWh).- 40 - n



41/78


Chi ph b tn tht l:

C 43 = C . 43BAA = 1000 . 28785= 28,785.10 6 (/nm).

Chi ph qui i :

Z = (a vh + a tc ).V + C

Z34= 0,185.187,35.10 6 + 28,785.10 6 = 63,444.10 6 (/nm).

Trm 5:


ABA35=(n.P 04 .8760 + ..2 2 4

235

nBA

K

S

SP)

= 2.0,5.8760 + 21,2886.160

3.220.

2

95,22

2

= 16830,65 (KWh).

Chi ph b tn tht l:

C35 = C . 44BAA = 1000 . 16830,65 =16,83.10 6 (/nm).

Chi ph qui i :

Z = (a vh + a tc ).V + C

Z 44 = 0,185.100,25.10 6 + 16,83.10 6 = 35,376.10 6 (/nm).

Trm 6:


ABA36=(n.P0.8760 + ..2 2 2

233

nBA

K

S

SP)

= 2.1,3.8760 + 21,2886.630

810.

2

3,8

2

2

= 42576 (KWh).

Chi ph b tn tht l:

C36 = C . 36BAA = 1000 . 42575= 42,576.10 6 (/nm).

Chi ph qui i :

Z = (a vh + a tc ).V + C

Z33= 0,185.204,35.106

+ 42,576.106

=80,380.106

(/nm).- 41 - n



42/78


Trm 7:


ABA37=(n.P0.8760 + ..2 2 2

233

nBA

K

S

SP

)

= 2.1,3.8760 + 21,2886.630

77,830.

2

3,82

2

= 43604,4 (KWh).

Chi ph b tn tht l:

C37 = C . 42BAA = 1000 . 43604,4= 43,604.10 6 (/nm).

Chi ph qui i :Z = (a vh + a tc ).V + C

Z37= 0,185.204,35.10 6 + 43,604.10 6 =81,408.10 6 (/nm).

Vy tng chi ph qui i l:

Z3 = Z31+ Z32+Z33+Z34+ Z35+Z36+ Z37

= 58,44.10 6 + 45,731.10 6 + 80,345.10 6 + 63,444.10 6 +35,376.10 6

+80,380.10 6 + 81,408.10 6 = 445,124 (/nm).

T cc phng n trnh by trn, ta c th thy l phng n 2(Phng n

s dng 2 my bin p c cng sut 1000 (KVA) ,2 my bin p c cng sut

630 (KVA) c chi ph nh nht ng thi cng m bo cc yu cu k thut.

Phng n ny cn t 2 trm bin p ngay trm phn phi trung tm vi 2

my bin p lm vic song song c cng sut l 1000(KVA). 2 my bin p c

cng sut 630 (KVA)



43/78


H 1: S ni trm bin p phn xng t 1 MBA

H 2: S ni cc trm phn xng t 2 MBA.



44/78


Hnh 3- 6: S nguyn l mng cao p ton x nghip


35KV

CSV

MC

BATT

MCBU

TG 10 KV MCLL TG 10 KV

0,4 KV

B1

CC

CD

B2 B3 B4 B7 B8 B9


45/78


II. La chn dy dn.

Khi la chn phng n c th chn chi tit dy dn theo phng

php n gin nht theo dng in t nng cho php, nhng sau khi xc

nh c phng n ti u th tit din dy dn phi c kim tra li theo hao

tn in p cho php. Do dy l mng in h p nn cht lng in p dc

t ln hng u, do ta chn tit din dy dn ln hng u, do ta ch tit

din dy dn theo hao tn in p, ly gi tr hao tn in p cho php l cpU

= 5% (i vi mng in cp in p 380V, = cpU 19%). D nh t cp

trong cc rnh ngm di lng t . Do s b chn gi tr in tr khng l X0

= 0,07/km.

1. Phng n .

S ni cc dy ca mng in c th hin hnh trn. Chiu di dy dn

c ni t trm bin p n cc phn xng theo ng b gc c xxc

nh bng biu thc:

Li = ( ) ( ) 22 iBAiBA yYxX +

Vi phn xng 1:

Chiu di dy dn c ni t trm bin th n phn xng 1 theo ng b

gc c xc nh :

L1 = ( ) ( ) ( ) ( ) 22212

1 5.5457,735,7747,67 +=+ yYxXBABA

= 29.1 (m)

Thnh phn phn khng ca hao tn in p:

)(036.138,0

10.1,29.07,0.4,193.. 311 V

U

LxQU Nx ===

Thnh phn tc dng ca hao tn in p:

11 XcpR UUU = =19 1,036 = 17,97 (V).



46/78


Tit din dy :

( )21

11

1 2497,1738,032

1,29.4,179mm

UU

LPF

R

=

=

=

Ta chn cp loi ABBG c F Ch = 25mm 2 c r=1,25 / km v x= 0,06

/ km.

Hao tn in p thc t:

3

1

0101

1 101,2938,0

06,0.4,19325,1.4,179 +

=+

= LU

xQrPU = 18,06(V) 1000A do khng phi

kim tra dng n nh nhit.

b. Chn my ct hp b 10kv:

- Cc my ct ni vo thanh ci 10kv chn cng mt loi

SF6, k hiu 8DC11 do SIEMENS ch to c bng thng s sau:

Loi Um,kV Im, A Im.C, 2skA

i, kA

8DC11 12 1250 25 63

- Kim tra :

Im.MC Icb = 364,72 (A)

Im.ct IN = 4,55 (kA)

im. ixk = 11,58 (KA)

2.2. Chn v kim tra dao cch li cp 35 kV:

iu kin chn v kim tra:

- in p nh mc, kV : UmDCL Um.m- 54 - n



55/78


- Dng in lu di nh mc, A : Im.DCL Icb

- Dng n nh ng, kA : im. ixk

- Dng n nh nhit, kA : tm.nh.I2

m.nh tq.I2

Chn dao cch li t ngoi tri, li dao quay trong mt

phng nm ngang loi 3DE do SIEMENS ch to:

Loi Um, kv Im, A INt, kA IN max, kA

3DC 36 1000 25 60

- Kim tra: UmDCL Um.m = 35 kV

Im.DCL Icb =104 A

IN max ixk = 16,8 kA

2.3. Chn t cao p trn b cp 10kv

- Chn t cao p trn b, c dao cch ly 3 v tr, cch in

bng SF6 do SIEMENS ch tao, loi 8DH10

Loi t Um, kV Im, A INt, kA IN max,kA

Thit b

8DH10 12 200 25 25 Dao ct phti

3.Cu ch

2.4 Chn v kim tra cp :

Chn cp ng 3 li, cch in XLPE, ai thp, v PVC

do hng FURUKAWA ch to, cp c t trong hm cp :

ng cp F, 1li Hnh ICP, IN, 1s Um, kV- 55 - n



56/78


mm2 dng250c

AkA

BATT-B1,2,6 25 Vn

xon

140 3,37 10

BATT-B3,4,5,7

16 Vnxon

110 2,28 10

- Kim tra iu kin n nh nhit:

qdN tI.F

Trong :

- h s nhit , vi ng =7.

tq- thi gian qui i, s.

- Ngn mch trong h thng cung cp in c coi l

ngn mch xa

ngun: I=I do thi gian qui i ly bng thi gian tn ti

ngn mch.

tq = tnm = tbv + tmc .

Ta ly:

+ Thi gian tc ng ca bo v : tbv =0,02 s

+ Thi gian tc ng ca my ct :tmc =0,1 s

Thi gian quy i tq =0,12 s.

- Ta ch cn kim tra cho tuyn cp no c dng ngn

mch ln nht. Tuyn cp BATT-B6 c dng ngn mch ln nht

IN3 = 4,55KA.

Fmin= . IN3 max qdt = 7 . 4,55 . 12,0 =11mm2 < F =16mm2

- Cp c chn vt cp v c di ngn nn khng cn

kim tra iu kin tn tht in p v dng cho php.- 56 - n



57/78


2.5. Chn v kim tra Aptomat .

- Vi trm 2 MBA ta t 2 t aptomat tng, 2 t aptomatnhnh v 1 t aptomat phn on.

- Vi trm 1MBA ta t 1 t aptomat tng v 1 t aptomat

nhnh.

- Mi t aptomat nhnh t 2 aptomat.

Aptomat c chn theo dng lm vic lu di:

m.dmdmA

dm

tt

ttmax.lvdmA

UU

U*3

SIII

==

- Vi aptomat tng sau my bin p, d tr c th

chn theo dng nh mc ca MBA.

dm

B.dm

B.dmA.dm U.3

S

II =

- Aptomat phi c kim tra kh nng ct ngn mch : ICt

m IN

Dng qua cc aptomat:

- Dng ln nht qua aptomat tng, MBA 1000 kVA

)A(14434,0.3

1000Imax

==

- Dng ln nht qua aptomat tng, MBA 630 kVA

)(32,9094,0.3

630max AI ==

2.6. Chn v kim tra thanh dn:



58/78


- Thanh dn cp in p 10kv c chn thanh dn ng

cng.

Chn thanh dn theo iu kin pht nng lu dicho php:

K1 . K2 . ICP Icb.

- Thanh dn t nm ngang : K1=0,95.

- K2 : h s hiu chnh theo nhit .

0CP

'

0CP

2K

=

Trong :

cp =700c : nhit cho php ln nht khi lm vic bnh

thng.

0 =250c : nhit mi trng thc t.

K2 = 0,88

- Chn Icb theo iu kin qu ti ca my bin p:

)A(71510.3.88,0.95,0

7500.4,1

U.3.K.K

S.4,1I

U.3

S.4,1I

dm21

B.dmcp

dm

B.dmcb

==

=

Chn thanh dn ng, tit din trn 40x5, c dng Icp

=700(A)

Kim tra iu kin n nh ng: cp tt


ah

b


59/78


- Lc tnh ton do tc dng ca dng in ngn mch :

)KG(i.al.10.76,1F 2

XK

8

tt=

Trong :

l =100cm : khong cch gia cc s .

a =50cm : khong cch gia cc pha.

ixk : dng in xung kch ca ngn mch ba pha, A

ta c : ixk = 2 .1,8 . IN2 = 2 .1,8 . 4,6 = 11,71.103 A

Ftt =1,76.10-8.50

100.(11,71.103 )2 = 4,83 KG.

- M men un : )cm.KG(3,4810

100.83,4

10

l.FM tt ===

- ng sut tnh ton : )/(2cmKG

W

M

tt =

6

h.bW

2

= (cm3)

Thanh dn c b =0,5cm ; h = 4cm

)cm/KG(23,364.5,0

3,48.6

h.b

M.6 222tt===

ng sut cho php ca thanh dn ng cp=1400kG/cm2

cp >> tt= 36,23(kG/cm2).

Kim tra n nh nhit : qdtI.S

Ta c: =7; I= 4,6 (KA); tq = 0,12s

. I qdt = 7 . 4,6 . 12,0 = 11,15 mm2 .



60/78


S =40 . 5 = 200mm2>> 11,15mm2

2.7. Chn v kim tra s :

Chn s t ngoi tri doLin X ch to loi OH-10-

500(H-10)

C Um =10kv, Fph =500 KG.

- Kim tra n nh ng : Fcp Ftt.

Thanh dn t nm ngang nn lc tc ng cho phptrn u s l Fcp=0,6Fph0,6 Fph Ftt .

)KG(05,86,083,4

6,0

FF ttph

== , s chn tho mn.

2.8. Chn bin dng in BI

- Chn bin dng do SIEMENS ch to loi 4MA72 c thng

s k thut cho bng sau.

K hiu UmkV

Uchung

kV

Uchu pxung

kV

I1 mA

I2.mA

I.ngkA

4MA72 12 28 75 20 -2500

1hoc

5

120

2.9. Chn my bin p BU

- Chn my bin in p 3 pha 5 tr do Lin X ch to loi

HTM-10 c cc thng s k thut sau:

Loi Um, V Cng sut nh mctheo cp chnh xc

VA

SmVA


Ftt


61/78


Scp Thcp

0,5 1 3

HTM-10 10000 100 120 120 200 1200

Chng 4.

xc nh cc tham s ca mng in

I. Hao tn in p

1. Trn ng dy

Nh tnh ton, tn tht trn ng dy vi phng n ti u

(Phng n 2) l U = 159,7 (V). Trong tn hao in p ln

nht trn ng dy l on M

2. Trong my bin p

2

2

dmBA

dm

NBAS

UPR =

dmBAdm

nBAS

UUX

=

100%

2

RBA1 = 15 . 322

10.1000

4,0 = 2,4 . 10

-3

XBA1 = 5,5 . 32

10.1000.100

4,0 = 8,8 . 10

-3

Khi my bin p lm vic song th :

RBA =2

BAR = 1,2 . 10-3

XBA =2BAR = 4,4 . 10-3

II. Hao tn cng sut- 61 - n


68,11=+

=U

XQRPU BABABA


62/78


1. Trn ng dy

Hao tn cng sut tc dng trn on dy OV c xc nh

theo biu thc

1mP = lrU

QP.02

22 + = 83,810.76.67,038,0

73,9726,124 62

22

=+ (kw)

Hao tn cng sut phn khng trn on dy OM c xc

nh theo biu MQ0 = lxU

QP.02

22 += 79,010.76.06,0

38,0

73,9726,124 62

22

=+

(kVAR)

Tnh ton tng t cho cc on dy khc ghi trong bng di

y.

NQ P

L0i r0 x0 P Q

KVar KVar m /km /km KW KVarM1 193.4 179.4 29.1 1.25 0,06 8.81 0.79

M2 437.5 295.7 46 0,95 0,06 7.77 0.49M3 457.7 413.1 53 0,95 0,06 10.81 0.68M4 80.55 100.4 146 0,48 0,06 6.54 0.82M5 253.1 262.6 102 0,4 0,06 16.82 2.52M6 338.1 305.1 146 0,18 0,06 10.85 3.62M7 331.3 343.7 158 0,18 0,06 11.15 3.72M8 25.37 44.76 90 0,48 0,06 11.17 1.4M9 25.14 34.72 118 0,4 0,06 15.6 2.34M10 412 481.8M12 60.91 53.51M13 23.6 21.88M14 155.7 144.4M15 46.51 31.44M16 65.78 68.25M17 20.23 25.21M18 22.56 27.23M19 18.75 16.9

M20 93,68 97.2- 62 - n



63/78


2. Trong my bin p

=

+=

+=

22

03200

4267.

2

159,4.2..

2

1.2

nBA

kBAS

SPPP 32,72 (kW)

Iii. Tn tht in nng

Tng tn tht in nng trong ton mng in

BAdd AAA += = 287187,5 + 61517,8 + 67899,3 =

416604,6 (kWh)

(Gi tr ddA tng tn tht in nng trn ng dy (Mc

III.1), tng tn tht in nng trong cc my bin p BAA -

c tnh theo phng n 2 (Theo 2.2.4.b))

CHNG 5. TNH TON NI T CHO TRM BIN P CA PHN

XNG N

1. Khi nim v ni t.

Dng in c th ngi gy nn nhng tc dng nguy him :gy

bng,git,trng hp s lm cht ngi, do tc dng ca ni t l tn

dng in v gi mc in th thp trn cc thit b c ni t.H thng

ni t c 2 chc nng: ni t lm vic va ni t an ton.

- Ngi b tai nn v in l do chm phi nhng phn t mang in,

song cng c th chm phi nhng b phn ca thit b ih bnh thng khng

mang in nhng li c in p khi cch in b hng.trong trng hp ny,

m bo an ton c th thc hin bng cch ni t tt c nhng b phn bnh

thng khng mang in nhng khi chc in b hng c th c in p.



64/78


- Khi c ni t ,qua ch cch in b chc thng v thit b ni t s

co dng in ngn mch mt pha vi t v in p i vi u ca v thit b

bng : U =I R

Trong :

+I : dng in mt pha chm t.

+ R : in tr ni t ca cc trang b ni t.

Trng hp ngi chm phi v thit b c in p ,dng in qua ngi xc

dnh theo biu thc : I ng .Rng =I R .

V R


65/78


in tr ni t theo thi tit. Cc in cc c ni vi nhau bng cch hn

vi thp nm ngang t su 0,5 0,8m. chng n mn cc ng thp

trong t phi c b dy khng nh hn 3,5mm, cc thanh thp dt, gc khng

c nh hn 4mm,v dy ni t cn c tit din ho mn bn c kh n

nh nhit v chu c dng lm vic lu di.

in tr ni t ch yu xc nh bi in tr xut ca t , hnh

dng kch thc in ccv chn su trong t. ni t thng bao gm mt

s in cc ni song song vi nhau v t cch nhau mt khong tng i

nh, v vy khi c dng ngn mch chm t th tch t tn dng in t mi

cc gim i do lm tng in tr ni t, h s s dng in cc ni t s

gim xung khi tng s in cc v gim khong cch gia chng, ngoi ra cn

ph thuc vo dng ni t.

in tr sut ca t ph thuc vo thnh phn, mt , m v

nhit ca t v ch c th xc nh bng o lng. in tr sut khng phi

c nh trong c nm m hay i do s thay i m, v vy trong tnh ton

ni t phi dng in tr sut tnh ton l tr s ln nht trong c nm tt

=kmax. ; kmax l h s tng cao, ph thuc vo iu kin kh hu ni s xy

dng trang b ni t.

2.Xc nh in tr ni t nhn to.

Cng thc tnh

tnndnt RRR

111=

Trong :

+ Rnt : in tr ni t nhn to

+ Rnt

: in tr ni t cho php ca h thng- 65 - n



66/78


+ Rtn : in tr ni t t nhin

- i vi li h p c trung im ni t trc tip, theo quy phm ca trang b

in th Rnd 4 .

Do khng bit r cc h thng ni t ca cc cng trnh khc nn coi Rtn 0.

Vy ta c :Rnt = Rn = 4.

2. XC NH IN TR TN CA MT IN CC CHN SU.

3.1 Xc nh in tr sut tnh ton

Trang b in s c xy dng ti ni dt thuc loi t vn c in tr sut

=50 m ( bng 8_1sch tra cu cung cp in )

- h s nng cao K cho in cc nm ngang khi chn su 0,8m l K= 1,6 in

trsut

tnh ton ca thanh nm ngang tt.ng =1,6.50 =80 m.

- h s nng cao K cho in cc thng ng 2 3m chn su cch mt tkhong 0,5 0,8m l K=1,4

=>in tr sut tnh ton ca cc thng ng tt =1,4.50 = 70 m

3.2 Cch thc chn su v loi in cc.

- in cc c chn thng ng, u trn cch mt t khoang h = 0,7m c

chiu di l= 2,5m, cc in cc cach nhau khong a= 5m v c ni vi nhaubng cc thanh in cc ngang chn su khong h= 0,8m .

- Chn in cc thng ng bng thp gc c kch thc 70.70mm.

- Chn in cc ngang bng thanh dt c kch thc 40.4mm.

- 66 - nmn hc : SV : Ng xun Li H in 1_K3 t h =0,7 m

l =2,5 m


67/78


3.3 Tnh in tr ca mt cc in thng ng.

Cng thc tnh cho in cc trn: ( sch tra cu cung cp in)

+

+

=

lt4

lt4ln

2

1

d

l2ln

l.2R d.tt

dc

Trong :

+ l : chiu di in cc, m

+ d : ng knh in cc trn, m

+ t : chn su, m

- tnh cho in cc l thp gc phi quy i v in

cc trn theo

cng thc d = 0,95.b; b = 0,07 m: b rng ca in cc vung

=> d = 0,95.0,07 = 0,0665m

- chn su : t = 0,7 + l/2 = 1,95 m.

Ta tnh c :

=

+

+= 74,185,295,1.4

5,295,1.4ln

2

1

0665,0

5,2.2ln

5,2.14,3.2

70Rdc

4. Xc nh s b s in cc thng ng.

ntd.sd

dc

R.K

Rn=



68/78


- Ksd. : h s s dng in cc thng ng, khng xt

n nh hng ca thanh ni ngang; in cc t thnh

vng, la

=1chn s b Ksd.=0,58.

cc1097,94.58,0

74,20n ==

5. Xc nh in tr tn ca in cc nm ngang.

Cng thc tnh :

t.bL.2

lnL.2.KR

2

ng.sd

g.tt

ng

=

Trong :

+ L =10.2,5 =25m : tng chiu di ca in cc ngang.

+ b =40mm = 0,04m :chiu rng ca thanh dt.

+ t =0,8m : chn su.

+ Ksd.g =0,34 : h s s dng thanh ni ngang trong vng

in cc thng ng khi chng bng 10.

Thay vo cng thc trn tnh c :

== 85,158,0.04,0

25.2ln

25.14,3.2.34,080

R2

ng

6. Tnh chnh xc in tr ca in cc thng ng.Cng thc tnh :

=

=

= 35,5485,154.85,15

RR

R.RR

ntng

ntng

d

Tnh chnh xc s in cc thng ng c xt n nh

hng ca in cc ngang, h s s dng thanh ng Ksd.

=0,58. (Bng 8-5, sch tra cu cung cp in )- 68 - n



69/78


6n04,635,5.58,0

74,18

R.K

Rn

dd.sd

dc ====

Vy ta ly n =6 in cc thng ng.

Mt bng b tr cc in cc :


TBA

11

2

0,7

m

0,8

m

2,5

m

1. Cc2. Thanh ni

a 2,5m


70/78


Chng 6: TNH TON DUNG LNG B

Phn ln h cng nghip trong qu trnh lm vic tiu th t mnh in

c cng sut tc dng P ln cng sut phn khng Q. Cc ngun tiu th cng

sut phn khng l: ng c khng ng b, tiu th khong 60 65% tng

cng sut phn khngca mng in x nghip, my bin p tiu

th khong 20-25%. ng dy v cc thit b khc tiu th

khong 10%,... ty thuc vo thit b in m x nghip c

th tiu th mt lng cng sut phn khng nhiu hay t.

Truyn ti mt lng cng sut phn khng qua dy dn v my

bin p s gy ra tn tht in p, tn tht tn tht in

nng ln v lm gim kh nng truyn ti trn cc phn t ca

mng in do c li v kinh t - k thut trong li in

cn nng cao h s cng sut t nhin hoc a ngun b

cng sut phn khng ti gn ni tiu th tng h s cng

sut cos lm gim lng cng sut phn khng nhn t h

thng in .

- Nng cao h s cng sut t nhin bng cch :

+ Thay cc ng c non ti bng cc ng c cng sut nh

hn.

+ Gim in p t vo ng c thng xuyn non ti.

+ Hn ch ng c khng ng b chy khng ti.



71/78


+ Thay ng c khng ng b bng ng c ng b.

- Nu tin hnh cc bin php trn gim lng cng sut

phn khng tiu th m h s cng sut ca x nghip vn chat yu cu th phi dng bin php khc t thit b b

cng sut phn khng.

1. Xc nh dung lng b

1.1. Tnh h s Cos tb ca ton x nghip.Cng thc :

=PXi.tt

PXiPXi.tt

tb P

cos.PCos

Trong :

+ Ptt.Pxi : cng sut tnh ton ca phn xng th i.

CosXN

tb =17,1748

78,0.2448,0.08,11682,0.08,1768,0.19,160786,0.09,158 ++++

+ 17,174877,0.43,21875,0.27,19376,0.89,23775,0.14,244 +++

= 0,776

H s Cos ti thiu do nh nc quy nh l t (0,85 0,9),

nh vy ta phi b cng sut phn khng cho x nghip

nng cao h s Cos .

1.2. Tnh dung lng b tng ca ton x nghip :

Cng thc tnh :

Qb = Ptt.XN ( tg 1 - tg 2 )

Trong :



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+ tg 1 : tng ng vi h s Cos 1 trc khi b.

+ tg 2 : tng ng vi h s Cos 2 cn b, ta b n Cos 2 t

gi tr quy nh khng b pht t (0,85 0,95) ta b nCos 2 = 0,9.

Cos 1 = 0,776 tg 1=0,813

Cos 2 = 0,9 tg 2=0,484

Qb = 1003,9. ( 0,813 - 0,484) = 330,28 (KVAR)

Qb = 330,28 KVAR

2. Chn v tr t v thit b b.

2.1. V tr t thit b b .

V nguyn tc c li nht v mt gim tn tht

in p, tn tht in nng cho i tng dng in l t

phn tn cc b t b cho tng ng c in, tuy nhin nut phn tn qu s khng c li v vn u t, lp t v

qun l vn hnh . V vy vic t thit b b tp trung hay

phn tn l tu thuc vo cu trc h thng cp in ca i

tng, theo kinh nghim ta t thit b b pha h p ca

trm bin p phn xng ti t phn phi. V y ta coi gi

tin n v (/KVAR) thit b b h p ln khng ng k sovi gi tin n v tn tht in nng qua my bin p.

2.2. Chn thit b b .

b cng sut phn khng cho x nghip c th dng cc

thit b b sau:

My b ng b :



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+ C kh nng iu chnh trn.

+ T ng vi gi tr cng sut phn khng pht ra (c th tiu

th cng sut phn khng).+ Cng sut phn khng khng ph thuc in p t vo,

ch yu ph thuc vo dng kch t

+ Gi thnh cao.

+ Lp rp, vn hnh phc tp.

+ Gy ting n ln.

+ Tiu th mt lng cng sut tc dng ln .

T in :

+ Tn tht cng sut tc dng t

+ Lp t, vn hnh n gin, t b s c

+ Cng sut phn khng pht ra ph thuc vo in p tvo t.

+ C th s dng ni kh ro bt k t b t.

+ Gi thnh r.

+ Cng sut phn khng pht ra theo bc v khng th thay

i c.

+ Thi gian phc v, bn km.

Theo phn tch trn th thit b T b thng c dng

lp t nng cao h s cng sut cho cc x nghip

3. Tnh ton phn phi la chn dung lng b



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- S nguyn l t thit b b :

- S thay th .

C: Qb = 1003,9. ( 0,813 - 0,484) = 330,28 (KVAR)

Trong trng hp ny, ta s chn t b CEP131A1 c Qbu = 100

(kvar) v t CEP 124M8 c Qbu = 50 (kvar) ng vi cc phn x-

ng c th.

4. nh gi hiu qu b

Cng sut biu kin ca phn xng sau khi b l :SV = PV + j(QV - QbuV ) = 124,26 + j (97,73 50)

= 124,26 + j.47,73

Tn tht sau khi b l:

sbA =2

22

38,0

73,4726,124 +

. 0,67. 76 . 10-6 . 2886 = 18032,2 (kwh)

Lng in nng tch kim c do b cng sut phn khng l :

AAA = = 25433,9 - 18032,2 = 7401,2 (kwh)

S tin tit kim c trong nm

= cAC = 7401,2 . 1000 = 7,401 .106 (/nm)

Vn u t b- 74 - n


35KV 10KV

BATT

Qb

CpBAP

Xi

0,4KV P

i+JQ

i

Qbi

10KVR

CiR

Bi 0,4KV

Qb

(Qi- Q

bi)


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Vb = vob . Qbn = 75.103 . 50 = 3,75. 106 (/nm)

Chi ph quy i :

Zb = p.Vb = 0,185 . 3,75 . 106 = 0,694.106 (/nm)

Tnh ton tng t cho cc phn xng khc , kt qu ghi trong

bng sau:



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Phn

Xng

Qtt Qbn Loi t sbA

Kwh

sbA

Kwh

C

.106

(/n

m)

Vb

.106

(/

n)

Zb

.106

(/

n)

V 97,7

3 50

CEP

124M8

18032.2

3 7401.67 7.4 3,75

0,6

94

U 96,1

1 50

CEP

124M8

16200.2

1 6210.69 6.21 3,75

0,6

94

T 100,

79 100

CEP131

A1

20977.6

1

10221.9

9 10.22 7,5

1,3

88

69,6

5 50

CEP

124M8

12618.4

1 6253.79 6.25 3,75

0,6

94

152,

67 100

CEP131

A1

31804.2

4

16741.5

6 16.74 7,5

1,3

88

N 161,

45 100

CEP131

A1

19595.4

3

11704.2

7 11.7 7,5

1,3

88

A 154,

61 100

CEP131

A1

20274.9

3

11892.7

7 11.89 7,5

1,3

88

O 127,

83 100

CEP131

A1

18807.7

7

13441.1

3 13.44 7,5

1,3

88

H 139,

37 100

CEP131

A1

28149.6

8

16859.1

2 16.86 7,5

1,3

88

Tng 186460,

51 100727

100,7

27

56,2

5

10,

41


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Tng s tin tit kim c do t t b l :

TK = C - Zb = (100,727 10,41) . 106 = 90,32 .106 /nm

C th thy vic y t b mang li hiu qu kinh t rt ln

Nh vy ta s t mi phn xng mt t b loi CEP 124M8

hoc CEP131A1 ty thuc vo cc phn xng c th

S nguyn l, s lp t c biu din hnh di

y:

- S nguyn l t t b trong trm bin p.


X

XX

X

XX X X X


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- S lp t t b trong trm t 2 my.

- S lp t t b trong trm t 1 my:

T

aptomat tng

T b

cos

T b

cos

T

aptomattng

T

phn

phi

cho cc

phn x-

ng

T

aptomat

phn

on

T

phn

phi

cho cc

phn x

ng

T

aptomat

tng

T b

cos

T phn

phi cho

cc phn

xng

Do an Mon Cung Cap Dien Cua Ngo Xuan Loi

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