Đồ Án Cung Cấp Điện Nhà Máy Bia

8/3/2019 n Cung Cp in Nh My Bia

1/47

GVHD: L MINH PHNG B mn Cung Cp in

PHN M U

DIN N INhttp://diendandien.comDIENDANDIEN.COM || Sn chi b

ch thit thc cho dn inCng giao lu Hc hi Vcng chia s

Mi thng tin chia s v ng gp lin h qua:Yahoo: dddvn_spMail: [email protected]

Chc cc bn vui v!

------- -------

SVTT:L MINH TRUNG .MSSV:402N0060 Trang - 1 -
http://diendandien.com/mailto:[email protected]://diendandien.com/mailto:[email protected]


2/47


Thit k mt h thng cung cp in cho mt nh my, x nghip l mt trongnhng cng tc quan trng, i hi c chuyn mn, c tm nhn chin lc vo kh nng

pht trin kinh t -x hi ca t nc. Trn ht, h thng cung cp in phi m bo cc yucu v tin cy , cht lng in , an ton lin tc v kinh t.

Tp n mn hc ny c xem nh mt bi tp ln, sinh vin tng hp kinthc hc, p dng vo thc t tnh ton, thit k cung cp in .Nhn thc hin ti thit k mn hc Cung cp in cho phn xng nh my Bia , mcd c nhiu c gng trong tnh ton, trnh by v su tm t liu nhng v trnh c hnnn khng trnh khi sai st. Knh xin qu Thy, C vui lng ch dn thm.

Tp n ny c hon thnh di s hng dn tn tnh ca Thy L Minh Phng,v cc thy c gio . Xin chn thnh cm n cc thy c !

Trn trng !

Sinh VinThc hin

L MinhTrung

-----------

NHNG NGUYN L C BN CA H THNG CUNG CP IN V NHNG VN CHUNG V CUNG CP INI C IMCA QU TRNH SN XUT V PHN PHI IN NNG

in nng l mt dng nng lngc nhiu u m nh : d dng chuyn ti (nhit , c , ha..)d truyn ti v phn b . Chnh v vy in nng c dng rt rng ri trong mi lnh vc ca conngi.

in nng ni chung khng tch tr c , tr mt vi trng hp c bit cng sut nh nh pin,cquy , v vy gia sn xut v tiu thn nng phi lun lun cn bng .SVTT:L MINH TRUNG .MSSV:402N0060 Trang - 2 -


3/47


Qua trnh sn xut in nng la qu trnh in t . c im ca qu trnh ny l xy ra rt nhanh. v vy m bo qu trnh cung cp v sn xut in an ton tin cy , m bo cht lng in phip dng nhiu bin php ng b nh iu , thng tin , o lng , bo v v t ng ha

in nng l ngun nng lng chnh ca cc nghnh cng nghip .Liu kin quan trngpht trin cc o th v cc khu dn c.v.v.. V l do o khi lp k hoch pht trin kinh t x

hi ,k hoch pht trin in nng phi i trc mt bc, nhm tho mn nhu cu in nng khngnhng trong giai on trc mtm cn d kin cho s pht trin trong tng lai.

Nhng c im trn cn phi xem xt thn trng v ton din trong sut qu trnh t nghin cuthit k ,xy dng n vn hnh khai thc h thng sn xut , phn phi v tiu th in nng.I I NHNG YU CU KHI THIT K CUNG CP IN

Mc tiu c bn ca nhin v thit k cung cp in l m bo cho h tiu th c lngin nng yu cu vi cht lng in tt.

* Mt s yu cu chnh sau y:1. tin cy cung cp in

tin cy cung cp in ty thuc vo h tiu th loi no.Trong iu kin cho php ngi ta cgng chn phng php cung cp in c tin cy cng cao cng tt.

2. Cht lng inCht lng in c nh gi bng hai ch tiu tn s v n p.Ch tiu tn s do iu min iu chnh .Ch c nhng h tiu th ln hng chc MW tr ln

mi phi quan tm n ch vn hnh ca mnh sao cho hp l gp phn n nh tn s ca hthng in .

V vy ngi thit k cung cp in thng ch phi quan tm cht lng in p cho khch hng .Ni chung in p li trung h p cho php dao ng xung quanh gi tr 5% n p nh

mc . i vi nhng ph ti c yu cu cao v cht lng in p nh nh my ha,cht in t , ckh chnh xc in p ch cho php dao ng 2,5%.3. An ton trong cung cp:

H thng cung cp in phi c vn hnh an ton i vi ngi v thit b .Mun at c yu

cu , ngi thit k phi chn h s cung cp in hp l . r rng , mch lc d hiu trnh c snhm ln trong vn hnh, cc thit b in phi c chn ng chng loi , ng cng sut.

Cng tc xy dng lp t h thng cung cp in nh hng n an ton cung cp in .Cui cng,vic vn hnh qun l cung cp in c vai tr c bit quan trng.ngi s dng phi

chp hnh nhng quy nh v an ton s dng din .4. Tnh kinh t :

Khi nh gi so snh cc phng n cung cp in,ch tiu kinh t c xt n khi cc ch tiuk thut nu trn c m bo .

Ch tiu kinh t nh gi thng qua: tng s v u t , chi ph vn hnh v thi gian thu hi vnu t .

I I I . CC BC THIT K CUNG CP IN

1- Tng quan gii thiu thit b .2- Tnh ton ph ti s dng in .3-La chn my bin p , trm phn phi , b cng sut phn khng .4-La chn dy dn v kim tra st p .5-Tnh ton ngn mch v la chn thit b bo v (CB) , khi ng t ,cu ch .v .v6-Tnh ton v an ton.Chng st .



4/47


ChngI : TNG QUAN THUYT MINH CHUNGI.1 . GII THIU V PHN XNG :

Nh my Bia chai l mt phn ca nn cng nghip nh,c mt v tr c bit trong nnkinh t quc dn.

Phn xng Bia l mt phn ca x nghip cng nghip. Nhim v ca phn xng lch bin , gia cng nguyn liu th thnh cc loi s phm tiu dng v phc v sn xut phc v cho cng vic pht trin v xy dng t nc

Phn xng Bia theo ti c giao l thit k phn cung cp in cho mt xngchim din tch 727 m2 , bao gm cc cc b phn v thit b t sn theo bn v mt bng. I.2 . PHN NHM NG LC :

Nhm mc ch to s thun tin trong cng tc qun l , vn hnh cng nh khi thicng i cp, ta phn nhm thit b da vo cc yu t sau :

- Theo quy trnh sn xut tng b phn trong nh my , v theo cch b tr cc mynm gn nhau vo cng mt nhm .

- S lng cc t ng lc phi c phn b u trn cc b phn sn xut ca phnxng , sao cho khi vn hnh hoc sa cha khng gy nh hng n cc b phn khc .

I.3. XC NH TM PH TI :Mc ch ca vic xc nh tm ph ti l ti u ha vic phn nhm cc thit b

va ph hp vi cng ngh sn xut li va thun tin cho vic i dy ; mt khc vic xcnh tm ph ti cho php ta gim c tn tht in nng , tn tht in p li va c th titkim c dy dn m vn c th bo m vn hnh mng in theo cch ti u nht c thc c .

Phng php xc nh tm ph ti :

Chn h trc to xOy, ta tm ph ti ca phn xng dt c xc nh theocng thc sau :

;

.

1

1

=

==n

i

dmi

n

i

dmii

P

Px

X ;.

1

1

=

==n

i

dmi

n

i

dmii

P

Py

Y

Trong :xi , yi :l ta trng tm cc thit b ca phn xng trn h trc XOY

chn(xI :tnh theo chiu ngang, yI: tnh theo chiu dc ca mt bng)Pi : Cng sut tnh ton ca cc my ( hoc nhm my ) .

T cc ta xi , yi ca cc thit b trong tng nhm my ng vi cng sut tnh tonca tng nhm my , ta xc nh c tm ph ti ca phn xng dt .

Khi xc nh c v tr tm ph ti ca tng nhm my v ca ton phn xng ,vic quyt nh v tr t t phn phi v cc t ng lc cho tng nhm my cn kt hp vicc yu t sau y :

- Phi ph hp vi hot ng ca cng ngh sn xut v khng gy nh hngchung n v m quan ca phn xng .

- Thun tin cho vic thi cng mng cp v i cp n cc thit b, ng thithun li cho cng tc bo tr, sa cha sau ny .

- Bo m an ton tuyt i cho con ngi v thit b .



5/47


Nu tm ph ti tm c khng tha mn cc yu t trn ta c th di n mt v trthch hp gn nht.

I.4 . CC PHNG PHP XC NH PH TI TNH TON :

I.4.1 . Mc ch :Ph ti tnh ton Ptt l mt s liu quan trng thit k cung cp in .Ph titnh ton ph thuc vo nhiu yu t nh : cng sut v s lng cc my, ch vn hnhca chng , quy trnh cng ngh sn xut, trnh vn hnh ca cng nhn v.vV vy xcnh chnh xc ph ti tnh ton l mt nhim v kh khn nhng rt quan trng. Bi v nu

ph ti tnh ton c xc nh nh hn ph ti thc t th s lm gim tui th cc thit bin, c khi dn ti n, chy rt nguy him. Nu ph ti tnh ton ln hn ph ti thc t nhiuth cc thit b in c chn s qu ln so vi yu cu, do gy lng ph.

Do xc nh ph ti tnh ton lm c s cho vic chn la dy dn v cc thit btrong h thng cung cp.

I.4.2 . Mt s phng php xc nh ph ti tnh ton :

V ph ti in ca cc my l mt hm bin i theo thi gian v c nhiu yut nh hng ti n nn thng ph ti in khng bin thin theo mt quy lut nht nh. Do xc nh chnh xc ph ti tnh ton l mt iu rt kh khn.Hin nay c nhiu phng

php xc nh ph ti tnh ton ty theo tnh cht kinh t m ta chn ph ti tnh ton theophng php chnh xc hay gn ng,nhng thng dng nht hin nay l phng php s thitb hot ng c hiu qu nhq & trong phm vi ca n ny ta s p dng theo phng phpny xc nh ph ti tnh ton cho phn xng nh my si .

Cc phng php xc nh ph ti tnh ton thng dng:a/ Xc nh ph ti tnh ton theo cng sut t v h s nhu cu

Cng thc tnh :

Ptt = knc..=

n

i

diP1

Qtt = Ptt .tg

Stt = 22 tttt QP + =cos

ttP

Gn ng c th P = Pm

Do Ptt = knc..=

n

i

dmiP1

Trong : Pi , Pmi - cng sut t v cng sut nh mc ca thit b th i, kWPtt , Qtt , Stt cng sut tc dng , phn khng v ton phn tnh ton ca nhm thit

b, kW,kVAr,kVAn s thit b trong nhmknc h s nhu cu ca cc my, thng cho trong cc s tay

knc = Ptt / Pm ]Nu h s cng sut cos ca cc thit b trong nhm khc nhau th phi tnh h s

cng sut trung bnh theo cng thc sau :

n

nn

PPP

PPP

+++

+++

...

cos....coscos

21

2211

Xc nh ph ti tnh ton theo sut ph ti trn mt n v din tch sn xutCng thc tnh :

Ptt = p0.F



6/47


Trong : p0 sut ph ti trn 1 m2 din tch sn xut ,kW/m2 (tra s tay )F -din tch sn xut,m2(tc l din tch dng t my sn xut)

b/ Xc nh ph ti tnh ton theo sut ph ti trn mt n v din tch sn xutCng thc tnh :

Ptt =max

0

T

Mw

Trong : Ms n v sn phm c sn xut ra trong mt nm(sn lng)w0-sut tiu hao in nng cho mt n v sn phm,kWh /vspTmax thi gian s dng cng sut ln nht ,h

c / Xc nh ph ti tnh ton theo h s cc i kmaxv cng sut trung bnh PtbCng thc tnh :

Ptt = kmax.ksd.PmTrong : Pm - cng sut nh mc, Wkmax , ksd h s cc i v h s s dng max=Ptt/Ptb

ksd = Ptbnh /Pm = ==

n

i

dmi

n

i

dmisdi PPk11

/.

Vi : Pm -cng sut nh mc ca nhmksdi h s s dng ca thit b th i ( tra bng s tay )H s thit b hiu qu nhq

nhq = (2

1

2

1

)(/) ==

n

i

dmi

n

i

dmi PP

Nu nhq < 4 v n < 4 th : P tt = =

n

i

dmiP1

; Qtt = =

n

i

dmiP1

.tgmi

Nu nhq < 4 v n 4 th : Ptt = =

n

i

dmiP1

.kpti ; Qtt = =

n

i

dmiP1

.tgmi .kpti

kpt h s ph ti ca tng my.kpt =0.9 i vi thit b lm vic ch di hn .kpt =0.75 i vi thit b lm vic ch ngn hn lp li.

Nu nhq 4 : Tm kmax theo nhq v ksd

Ptt = kmax.ksd.Pm = kmax.PtbQtt =1.1Qtb nu nhq 10

Qtt = Qtbnh nu nhq > 10 y Qtb = Ptb .tgtb ; costb = (cosi.Pmi) /(Pmi)Trong 4 phng php xc nh ph ti tnh ton trn ,khi tnh cho tng nhm my

mng in p thp (U < 1000 V) nn dng phng php tnh theo h s cc i kmax (tcphng php thnh theo h s hiu qu),bi v phng php ny c kt qu tng i chnhxc.

I.5 . XC NH PH TI NH :L ph ti ngn hn, c dng tnh ton bo v, tnh ton khi ng; quy

nh xc nh gi tr nh ca mt nhm ng c l chn gi tr nh ca mt ng c c



7/47


dng m my ln nht cng vi dng lm vic bnh thng ca cc ng c cn li trongnhm . xc nh dng nh nhn In ta p dng theo cng thc sau :

In = kmm * ikmax + Itt - ksd * immaxTrong :

ikmax: dng khi ng ca ng c c dng khi ng ln nht .Itt : Dng in tnh ton ca mt nhm ng c .immax :dng in nh mc ca ng c c dng khi ng ln nht .

ChngII : TNH TON THIT K CUNG CP INIIA . XC NH PH TI TNH TONIIA1 . PHN NHM V XC NH TM PH TI CC NHM :Da theo dy chuyn cng ngh v v tr phn b thit b , theo cng sut ,ta tin hnh

phn chia cc thit b theo nhm, mi nhm thch ng vi t cp in ring.

Cn c thc t ta chia thnh 5 nhm ng vi 5 t ng lc nh sau :

IIA1/1: NHM I: Gm cc ti sau :

Chn h trc to XOY, ta tm ph ti ca phn xng bia ta c xcnh theo cng thc sau :

;

.

1

1

=

==n

i

dmi

n

i

dmii

P

Px

X ;.

1

1

=

==n

i

dmi

n

i

dmii

P

Py

Y

Nhm I gm 14 thit b v c thng s nh sau :

S LIU CC THIT B TRONG PHN XNG BIA CHAI

Tn thit b KH SL Pm(KW) Ksd CosMy gp rng 67 2 7 0,6 0.7

My gp y 69 2 54 0,65 0.7My xc chai 68 2 7 0,7 0.7My gp y 69 1 7 0,65 0.8Motor v di 71 1 7 0,65 0.8My chit bia 72 2 25 0,65 0.8My bm nc nnghp 73 11 4 0,6 0;8Motor cu 74 27 1 0,6 0;8Qut cng nghip 75 3 0,75 0,6 0;8

Cng thc tnh dng in m my v dng nh mc ca cc thit b :



8/47


Imiidmi

dmi

U

P

cos3= Immi =Kmm * Im i

My xc chai :

Imidmi

dmi

UP

cos3= = )(18,11

7,0*380*3

1000*54 A==

Imm =Kmm * Im = 5*117,18 =589,90 (A)

Tng t ta c bng tnh sau y cho cc thit b khc :



9/47



STT

TN THIT B: nhm1 KH X Y P m Ksd COS I m Imm

1 Motor cu 74 15 20,4 1 0,6 0,8 1,90 9,502 My bm nc nnghp 73 29 23 4 0,6 0,8 7,60 37,983 Motor cu 74 57 20,4 1 0,6 0,8 1,90 9,504 Motor cu 74 75 20,4 1 0,6 0,8 1,90 9,505 My bm nc nnghp 73 93 23 4 0,6 0,8 7,60 37,986 Motor cu 74 111 20,4 1 0,6 0,8 1,90 9,507 Motor cu 74 129 20,4 1 0,6 0,8 1,90 9,508 My bm nc nnghp 73 147 23 4 0,6 0,8 7,60 37,989 Motor cu 74 165 20,4 1 0,6 0,8 1,90 9,5010 Motor cu 74 183 20,4 1 0,6 0,8 1,90 9,5011 My bm nc nnghp 73 223 23 4 0,6 0,8 7,60 37,9812 Motor cu 74 241 20,4 1 0,6 0,8 1,90 9,5013 Motor cu 74 259 20,4 1 0,6 0,8 1,90 9,5014 Qut cng nghip 75 262,5 46 0,75 0,6 0,8 1,42 7,12

Tng theo nhm 133,3

23 25,5 0,6 0,8 48,92

244,6

STT


1 Qut cng nghip 75 17,5 59,1 0,75 0,6 0,8 1,42 7,122 Motor cu 74 15 79,5 1 0,6 0,8 1,90 9,503 Motor cu 74 15 97,5 1 0,6 0,8 1,90 9,504 My bm nc nnghp 73 17,5 115,5 4 0,6 0,8 7,60 37,98

5 Motor cu 74 15 133,5 1 0,6 0,8 1,90 9,506 Motor cu 74 15 161,4 1 0,6 0,8 1,90 9,507 My bm nc nnghp 73 17,5 179,5 4 0,6 0,8 7,60 37,988 Motor cu 74 15 197,5 1 0,6 0,8 1,90 9,509 Motor cu 74 15 215,5 1 0,6 0,8 1,90 9,5010 Motor cu 74 38 215,5 1 0,6 0,8 1,90 9,5011 My bm nc nnghp 73 40,5 179,5 4 0,6 0,8 7,60 37,9812 Motor cu 74 38 197,5 1 0,6 0,8 1,90 9,5013 Motor cu 74 38 161,5 1 0,6 0,8 1,90 9,50

14 Motor cu 74 15 234,5 1 0,6 0,8 1,90 9,50

15 My bm nc nnghp 73 29 232 4 0,6 0,8 7,60 37,98Tng theo nhm 16,5 162,

526,75

0,6 0,8 50,82

254,04

STT


1 Motor cu 74 57 234,5 1 0,6 0,8 1,90 9,502 Motor cu 74 75 234,5 1 0,6 0,8 1,90 9,503 My bm nc nnghp 73 93 232 4 0,6 0,8 7,60 37,984 Motor cu 74 111 234,5 1 0,6 0,8 1,90 9,505 Motor cu 74 129 234,5 1 0,6 0,8 1,90 9,50

6 My bm nc nnghp 73 147 232 4 0,6 0,8 7,60 37,987 Motor cu 74 165 234,5 1 0,6 0,8 1,90 9,50


10/47


7,25

)1*1831*1654*1471*1291*1114*931*751*574*291*15(1

+++++++++=X +

75,25

)75,0*5,2621*2591*2414*223( +++= 133,32mm

+++++++++

=5,27

)1*4,204*231*4,201*4,204*231*4,204*231*4,20(1Y

=+++

+75,25

)75,0*461*4,204*231*4,20( 23 mm

Do t l ca cc thit b phn b trn bn v l 1/100 nn t cc gi tr trn ta cc tm ph ti ca nhm I nh sau :

Ta chn O1 ( 130 ;5 ).IIA1/2: NHM II:

Tng t ta c tm ph ti ca nhm II nh sau : X=16,5 Y=126,6Ta chn O2 ( 5 ;160). mm

IIA1/3: NHM III:.Tng t ta c tm ph ti ca nhm III nh sau : X=158 Y= 232


STT


8 Motor cu 74 183 234,5 1 0,6 0,8 1,90 9,509 My bm nc nnghp 73 223 232 4 0,6 0,8 7,60 37,98

10 Motor cu 74 241 234,5 1 0,6 0,8 1,90 9,5011 Motor cu 74 259 234,5 1 0,6 0,8 1,90 9,5012 Motor cu 74 262,5 234,5 1 0,6 0,8 1,90 9,50

Tng theo nhm 20,75 0,6 0,8 39,42 197,1ST

TTN THIT B: nhm4 KH X Y P m Ksd COS I m Imm

1 My gp y 69 153 164 7 0;7 0,7 15,19 75,972 Motor v di 71 183 164 7 0,65 0,8 13,29 66,473 My chit bia 72 163,7 108,2 25 0,65 0,8 47,48 237,54 My gp y 69 153 164 7 0;7 0,7 15,19 75,97

5 Motor v trn 70 183 52,5 7 0,65 0,8 13,29 66,476 My gp rng 67 213 126 7 0,6 0,7 15,19 75,977 My gp rng 67 213 90,5 7 0,6 0,7 15,19 75,978 My chit bia 72 163,7 108,2 25 0,65 0,8 47,48 237,5

Tng theo nhm 181,7 108,2 92 0,65 0,8 182,2 919,6ST

TTN THIT B: nhm5 KH X Y P m Ksd COS I m Imm

1 My xc chai 68 245 139 54 0,65 0,7 117,2 358,92 My xc chai 68 245 139 54 0,65 0,7 117,2 358,9

Tng theo nhm 108 0,65 0,,7 234,4 1172


11/47


Ta chn O3 ( 160 ;230).IIA1/4: NHM IV:.

Tng t ta c tm ph ti ca nhm IV nh sau : X= 177,4 Y=108,2Ta chn O4 ( 170 ; 50 ).

IIA1/5: NHM V :.Tng t ta c tm ph ti ca nhm V nh sau : X=245 Y=108,2Ta chn O5 ( 250 ;108 ).

IIA2 XC NH TM PH T CA TON PHN XNG :Chn h trc to XOY, ta tm ph ti ca phn xng bia c xc nh theo

cng thc sau :

;

.

1

1

=

==n

i

dmi

n

i

dmii

P

Px

X ;.

1

1

=

==n

i

dmi

n

i

dmii

P

Py

Y

Vi cc s liu tnh c trn ta c :

X =25,273

108*2454,177*9275,20*15875,26*5,1675,25*3,133 ++++= 12,8 (m)

Y =25,276

108*25,1082,108*9275,20*232163*75,2675,25*23 ++++= 14,9 (m).

Vy tm ph ti ca nh my l : O ( 12,8 ; 14,9 m )

NHN XT :- Vi phng n phn nhm trn vic thit k cc t ng lc ph hp vi thit

k v xy dng c bn cho tng b phn ca phn xng .- V tr T phn phi ta c th chn gn trm bin p , gn ca ra vo , gn vi

tm ph ti ca nhm tnh ton, do s tit kim c dy dn v gim c tntht in nng.

- Do s thit b c chia kh u theo cng sut ca tng my trong xng,nn khc bit v dy dn, CBl khng ln .Vic c lp kim tra, hay c s c ti mtnhm thit b ta vn cn ngun in s dng cho vic sa cha.

- S i dy thong d thi cng,thit k va t v m quan , va thun tincho vn hnh nn p ng c tnh k thut v m thut .

IIA2 . XC NH PH TI TNH TON CA CC NHM THIT B :

Nhm 1 : P m1 = 25,75 KW ; s thit b ca nhm l n =14 ; H s cng sut ca nhmly cos = 0.6 .

Tnh theo phng php h s cc i kmax v cng sut trung bnh.Trnh t tnh ton nh sau :

- Tnh h s s dng :



12/47


Ksdnhm =dm

tbnh

P

P=

=

=

n

i

dmi

n

i

dmisdi

P

PK

1

1

Tnh c : Ksdnhm = 0,6

- Tnh nhq = (2

1

2

1

)(/) ==

n

i

dmi

n

i

dmi PP

5625,0649

)75,25(2

++=hqn = 9

- Tm kmax nhm 1 theo nhq v ksd (tra bng 3-2 /[HTCC NCH])

vi Ksd nhm = 0,6 v nhq = 9 KMax 1 = 1,28- Tnh Ptb1 ca nhm 1

Ptb 1 = Ksd1 * Pm1 = 0,6*25,75 =15,45 (KW)- Tnh h s cng sut trung bnh(nhm) :

=

dmi

i

n

dmi

tbp

cos.p

cos 11

=0,8

- Tnh Qtb1ca nhm 1Qtb = Ptb 1 * tgtb1 =15,45*0,75 =11,588 (KVAr)

- Tnh Ptt ca nhm 1: xc nh theo cng thc sauPtt1 = KMax. Ptb1 = KMax . Ksdnhm . Pmnhm1Ptt1 = 1,28*15,45 = 19,776 (kW)

- Tnh Qtt1 : do nhq1 = 9 < 10 nn :Qtt1 = 1,1Qtb1 =1,1*11,588 = 12,746 (KVAR) .

.- Tnh Stt1: xc nh theo cng thc :

Stt1 = 528,23558,11776,19 22212

1 =+=+ tttt QP ( KVA) .

- Tnh Itt1= )(75,3538,0.3

58,23

.3

1A

U

S

dm

tt==

- Tnh Idn1 = ikmax1 + [ Ittn1 - ( Ksd1 . immax1 )]Trong nhm 1, my bm nc nng hp c dng nh mc ln nht

im max1 = 37,98Vy : In1 = 37,98+35,75-0,6 * 7,60 = 69,17(A)

Nhm 2 : P m2 =26,75 KW ; s thit b ca nhm l n = 15 ;Tnh theo phng php h s cc i kmax v cng sut trung bnh.Trnh t tnh ton nh sau :

- Tnh h s s dng :



13/47


Ksdnhm =dm

tbnh

P

P=

=

=

n

i

dmi

n

i

dmisdi

P

PK

1

1


- Tnh nhq = (2

1

2

1

)(/) ==

n

i

dmi

n

i

dmi PP

4*16105625,0

)75,26(2

2++

=hqn = 10

- Tm kmax nhm 2 theo nhq v ksd (tra bng 3-2 /[HTCC NCH])

vi Ksd nhm = 0,6 v nhq = 10 KMax 2 = 1,26- Tnh Ptb2 ca nhm 2

Ptb 2 = Ksd2 * Pm2 = 0,6*26,75 =16,05 (KW)- Tnh h s cng sut trung bnh(nhm) :

=

dmi

i

n

dmi

tbp

cos.p

cos 11

= 0,8

- Tnh Qtb2ca nhm 2Qtb2 = Ptb 2 * tgtb1 =16,05*0,75 =12,037 (KVAr)


- Tnh Qtt2 : do nhq2 = 10 nn :Qtt2 = 1,1Qtb2 =1,1*12,037 = 13,24 (KVAR) .


Stt2= 17,24233,2024,13 22222

2 =+=+ tttt QP ( KVA) .

- Tnh Itt2= )(72,3638,0.3

17,24

.3

2 AU

S

dm

tt ==


im max2 = 37,98Vy : In2 = 37,98+36,72 -0,6 * 7,60 = 70,14(A)

Nhm 3 : P m3 = 20,75 KW ; s thit b ca nhm l n = 12 ;Tnh theo phng php h s cc i kmax v cng sut trung bnh.Trnh t tnh ton nh sau :

- Tnh h s s dng :



14/47


Ksdnhm =dm

tbnh

P

P=

=

=

n

i

dmi

n

i

dmisdi

P

PK

1

1


- Tnh nhq = (2

1

2

1

)(/) ==

n

i

dmi

n

i

dmi PP

5625,0488

)75,22( 2

3++

=hqn = 7,6

- Tm kmax nhm 3 theo nhq v ksd (tra bng 3-2 /[HTCC NCH])vi Ksd nhm = 0,6 v nhq = 7,6 KMax 3 = 1,32

- Tnh Ptb1 ca nhm 3

Ptb 3 = Ksd3 * Pm3 = 0,6*20,75 =12,45 (KW)

- Tnh h s cng sut trung bnh(nhm) :

=

dmi

i

n

dmi

tbp

cos.p

cos 11

= 0,8

- Tnh Qtb1ca nhm 3Qtb3 = Ptb 3 * tgtb3 =12,45*0,75 = 9,34 (KVAr)


- Tnh Qtt3 : do nhq3 = 7,6 < 10 nn :Qtt3 = 1,1Qtb3 =1,1* 9,34 = 10,27 (KVAR) .


Stt3 = 38,19434,1627,10 22232

3 =+=+ tttt QP ( KVA) .

- Tnh Itt3= )(44,2938,0.3

38,19

.3

3 AU

S

dm

tt ==


im max3 = 37,98Vy : In3 = 37,98+29,44-0,6 * 7,60 = 62,87(A)

Nhm 4 : P m4 = 92 KW ; s thit b ca nhm l n = 8 ;Tnh theo phng php h s cc i kmax v cng sut trung bnh.Trnh t tnh ton nh sau :

- Tnh h s s dng :



15/47


Ksdnhm =dm

tbnh

P

P=

=

=

n

i

dmi

n

i

dmisdi

P

PK

1

1


- Tnh nhq = (2

1

2

1

)(/) ==

n

i

dmi

n

i

dmi PP

1250294

)92( 2

4+

=hqn = 5,44

- Tm kmax nhm 4 theo nhq v ksd (tra bng 3-2 /[HTCC NCH])vi Ksd nhm = 0,65v nhq = 5,44 KMax 4 = 1,34

- Tnh Ptb1 ca nhm 4

Ptb 4 = Ksd4 * Pm4 = 0,65* 92 =61,64 (KW)

- Tnh h s cng sut trung bnh(nhm) :

=

dmi

i

n

dmi

tbp

cos.p

cos 11

= 0,75

- Tnh Qtb1ca nhm 4Qtb4 = Ptb 4 * tgtb4 = 61,64* 0,881 = 54,36 (KVAr)

- Tnh Ptt ca nhm 4: xc nh theo cng thc sauPtt4 = KMax4. Ptb4 = KMax . Ksdnhm . Pmnhm4Ptt4 = 1,34*61,64 = 82,59 (kW)

- Tnh Qtt4 : do nhq4 = 5,44 < 10 nn :Qtt4 = 1,1Qtb4 =1,1* 54,36 = 59,796 (KVAR) .


Stt4 = 102796,5959,82 22242

4=+=+

tttt QP ( KVA) .

- Tnh Itt4= )(15438,0.3

102

.3

4 AU

S

dm

tt ==

- Tnh Idn4 = ikmax4 + [ Ittn4 - ( Ksd4 . immax4 )]Trong nhm 4, my chit bia c dng nh mc ln nht

im max4 = 237,4Vy : In1 = 237,4 +154 0,65*47,48 = 360,538(A)

Nhm 5 : P m4 = 108 KW ; s thit b ca nhm l n = 2 ;Tnh theo phng php h s cc i kmax v cng sut trung bnh.Trnh t tnh ton nh sau :

- Tnh h s s dng :

Ksdnhm =dm

tbnh

P

P=

=

=

n

i

dmi

n

i

dmisdi

P

PK

1

1




16/47


- Tnh nhq = (2

1

2

1

)(/) ==

n

i

dmi

n

i

dmi PP

29162916

)108( 2

5+

=hqn = 2

- Tnh Ptb1 ca nhm 5

Ptb 5 = Ksd5 * Pm5 = 0,65* 108 = 70,2 (KW)-

- Tnh Qtb1ca nhm 5Qtb5 = Ptb 5 * tgtb5 = 70,2*1,02 = 71,62 (KVAr)

- Tnh Ptt ca nhm 5: xc nh theo cng thc sauDo nhq5 < 4 v N5 < 3

Nn Ptt = 108 (KW)

- Tnh Qtt5 = Ptt 5 * tgtb5 = 108*1,02 =110,16(KVAr).

- Tnh Stt5: xc nh theo cng thc :Stt5 = 27,15416,110108 2225

2

5 =+=+ tttt QP (KVA) .

- Tnh Itt5= )(39,23438,0.3

27,154

.3

4 AU

S

dm

tt ==

- Tnh Idn5 = ikmax5 + [ Ittn5 - ( Ksd4 . immax4 )]

In5 = 585,90+234,39 -0,7*117,18 = 738,26 (A)

. TNH TON PH TI CHO TNG NHM THIT B

Tn nhm & thit b KH Pm(KW)

Im(A)

Imm(A) K

sd

C Sut TB cos

nhq kmaxPh ti tnh ton

Ptb ,KW Qtb,KVAr

Ptt,KW

Qtt,KVAR

Stt,KVA Itt,A

TN THIT B: nhm1 1

Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8

Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Qut cng nghip 75 0,75 1,42 7,12 0,6 0,8Tng theo nhm 25,75 48,92 244,6 0,6 15,45 11,59 0,8 9 1,28 19,77

612,746 23,528 69,17

TN THIT B: nhm2 KH Qut cng nghip 75 0,75 1,42 7,12 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8

Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8



17/47


Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Tng theo nhm 26,75 50,82 254,04 0,6 16,05 12,073 0,8 10 1,26 20,22

3

13,24 24,17 36,72

TN THIT B: nhm3 KH Motor cu 74 1 1,90 9,50 0,6

0,8Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8

Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8My bm nc nnghp 73 4 7,60 37,98 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Motor cu 74 1 1,90 9,50 0,6 0,8Tng theo nhm 20,75 39,42 197,1 0,6 12,45 9,34 0,8 8 1,32 16,43

4

10,27 19,38 29,44

TN THIT B: nhm4 KH My gp y 69 7 19,51 75,97 0,7 0,7Motor v di 71 7 13,29 66,47 0,65 0,8My chit bia 72 25 47,48 237,5 0,65 0,8My gp y 69 7 19,51 75,97 0;7 0,7Motor v trn 70 7 13,29 66,47 0,65 0,8My gp rng 67 7 15,19 75,97 0,6 0,7My gp rng 67 7 15,19 75,97 0,6 0,7My chit bia 72 25 47,48 237,5 0,65 0,8Tng theo nhm 92 182,2 919,6 0,65 61,64 54,36 0,75 5;54 1,34 82,59 59,8 102 154

TN THIT B: nhm5 KH My xc chai 68 54 117,2 358,9 0,65 0,7My xc chai 68 54 117,2 358,9 0,65 0,7Tng theo nhm 108 234,4 1172 0,65 70,2 71,61 0,7 2 108 110,16 154,2

7234,39

IIA3 . XC NH PH TI CHIU SNG CHO PHN XNG :

Ph ti chiu sng ca phn xng c xc nh theo phng php h s sdng.Phng php ny dng tnh ton chiu sng chung ,khng ch n h s catng ,ca trn v ca vt cn.

Trnh t tnh ton :Theo hng dn [HDAMH PTTB]1* Kch thc :

chiu di a = 28,5 m chiu cao H = 726,75 mchiu rng b = 25,5m din tch S = 198 m2

2* Mu sn :Tra bng 1 [HDAMH PTTB] xc nh cc h s phn xtrn : mu trng H s phn x : tr = 0,75tng : mu vng creme H s phn x :tg = 0,7sn : mu xanh m H s phn x :s = 0,2

3* ri yu cu :Tra bng 2 [HDAMH PTTB]Ta chn Etc = 300 lx

4* Chn h chiu sng : chung uChn khong nhit mu :

Tra bng 3 [HDAMH PTTB]Tm = 2900 4200 0K



18/47


6* Chn bng n :StandardTra bng 4 [HDAMH PTTB]Loi trng univesel (hiu sut cao ) Tm = 4000 0KRa = 76 P = 36 W , = 2500 lm

7* Chn b n :

Tra bng 5 [HDAMH PTTB]Loi : EBP StandanrdCp b n : 0,63G+0,09T Hiu sut :Nd = 0,63 ; Ni=0,09S n / 1 b : 2 Quang thng cc bng /1b : 5000 lmLdcmax = 1,8.htt =5,67m Lngangmax = 2,2.htt =6,93m

8* Phn b cc b n:Cch trn h/ = 1 mB mt lm vic : 0,85 mChiu cao treo n so vi b mt lm vic : h tt = 3,15 m

9* Ch s a im :

)5,255,28(5,315,25*5,28

).(

.

+=+= bahba

Ktt =4,272

10* H s b :Chn h s suy gim quang thng 1 = 0,7Chn h s suy gim do bm bi 2 = 1,25

H s b d= 1/12 =1,14211* T s treo :

j = h/ /(h/+htt ) =+

=15,31

5,11/3

12* H s s dng :Tra bng 7 [HDAMH PTTB] :Km=1 ;Kp=0,5; j=1/3 ; K=5 ; HSPX=753

U = 0,63*1,03+0,09*0,06=0,70813* Quang thng tng :

tng = ==078,00

412,1*75,726*300..

U

dSEtc 351674lm

14* Xc nh s b n :

Nb =5000

351673

1/

=bocacbong

tong

= 70,4

Chn s b n l Nb = 7215* Kim tra sai s quang thng :

=

=

=412,1*75,726

3516735000*72. 1/0

0

tong

tongbocacbongbdN

0,02

Sai s quang thng t yu cu (nm trong khong cho php t 10% 20% )16i* Kim tra ri trung bnh trn b mt lm v c :

===142,1*75,726

708,0*5000*72

.

.. 1/

dS

UNE

bocacbongbd

tb

300,1(lx)

17* Phn b cc b n :Phn b thnh 8 dy n, mi dy gm 9 b

Kim tra : a=28,5 ;b=25,5 ; p= 0,5 Lngang ; q=0,5 LdcSuy ra :(m-1).Ldc+2q +1,2m = a ; m(Ldc =1,2) = 28,5m

(n-1)Lngang +2p = p ; n.Lngang = 25,5m

Chn m= 9 ; n = 8Lng = 3,18m m < Lngmax =6,93



19/47

lng=3,18m ldc=1,9m


Ldc = 29/12 = 2,416 m < Ldcmax -1,2= 4,47m Cc b n c phn b t yu cu18 Ph ti chiu sng :

18 Ph ti chiu sng :

Pcs = 2*Nb dn* (Pn + Pbalt) =2*72 ( 36 +0,2 *36 ) = 6,22 (KW )Qcs = Pcs.tg= 6,22 * 0,75 = 4,665 (KVAr )

Scs = 107,11931,7776,7 2222 =+=+ cscs QP =7,76 (KVA)

Ics= AU

S

dm

cs 15,29220.3

10.107,11

.3

3

== =11,8 A

19* cm sinh hot :

Vi chu vi= 108m ; chn 1 cm = 10 (A)S =10 * 10 *0,22 =22 (KVA)

20*Ph ti chiu sng ton phn xng :

Psh = Pcs + P cm = 26,22 (KW)Qsh = Qcs + Qsh = 4,665 (KVAr)

Ssh= 107,11931,7776,7 2222 =+=+ cscs QP = 30 (KVA)

Ics= AU

S

dm

cs 15,29220.3

10.107,11

.3

3

== =78,7 (A)

IIA4. XC NH PH TI TNH TON CHO TON PHN XNG :

- V tr ca t phn phi c xc nh nh sau :



20/47


;

.

1

1

=

==n

i

tti

n

i

ttii

P

PX

X ;

.

1

1

=

==n

i

tti

n

i

ttii

P

PY

Y

X = 12,8( cm )Y = 16,9( cm )

Trong thc t ta chn v tr t PP gn hng trm BA ,gn v tr ca ra vo ,thun tincho vic i dy n t ng lc v TB Ta Chn : X =0,5(m) : Y = 4 (m)

- Cng sut tnh ton t phn phiPttpp =.Pttl + Psh

Pttpp = 248,21 +28,22 = 276,43 (KW) - Cng sut phn khng :

Qttpp = t.Qttl + QshQttpp = 206,21+ 4,665 = 210,875 (KVAR

- Cng sut biu kin :Sttpp = =+=+ 2222 875,21043,276ttppttpp QP 347,68 (KVA)

Dng tnh ton ca ton phn xng :Ittpp = Sttpp / 3 Um = 347,68 / 3 * 0,38 = 528 (A)

- H s cng sut ton phn xng :

Cos = Pttpp / Sttpp = 0,795

Chng III LA CHN MY BIN P CHO PHN XNG V B CNGSUT PHN KHNG

Theo ti thit k th in p ngun cung cp cho phn xng l 22 KV , nn

cung cp in cho cc thit b ca phn xng ( in p nh mc U m = 380 V cho cc thit bng lc v Um = 220 V i vi ph ti chiu sng ) ta phi thit k trm bin p phnxng , trm ny c nhim v bin i in p t 22 KV xung 0,4 KV cung cp cho mng hp .

I .CHN V TR T MY BIN P V KT CU TRM :

V mt nguyn l th v tr t trm bin p phn xng cng gn tm ph ti cng ttv cc yu t sau :

- Gim c chiu di mng phn phi h p gim chi ph kim loi mu gim githnh .

- Gim c tn tht in nng .Tuy nhin vi tm ph ti ca phn xng tm c phn trn v vi cc thit b

h p c nh v trn bn v mt bng s 34 , ta nhn thy khng th thit k trm bin p bn trong phn xng , do vy ta s chn v tr t my bin p bn ngoi v st vi tngca phn xng , kt cu trm bin p theo nguyn l trm t trn nn ngoi tri , xungquanh ro li thp .

Cch chn trn c u im l thi cng d dng , nhanh chng v chi ph xy dng thphn nhiu so vi cch lp t bn trong phn xng ; ngoi ra c th k n cc yu t phnh : gi c v m quan ca phn xng , khng gy tr ngi cho quy trnh sn xut vcng tc phng chy cha chy cng d dng hn so vi cch lp t MBA bn trong phnxng .



21/47


II . CHN KIU MY BIN P :Theo cng sut tnh ton ca phn xng m ta tnh c th cng sut my bin p

phn xng tng i nh v theo cp in p cho mng ng lc ( 380 V ) v mng chiusng ( 220 V ) , ta chn my bin p l loi my bin p in lc 3 pha lm mt t nhin doABB ch to c cp in p l 22 KV/0,4KV. y ta khng dng t 3 my bin p 1 pha v

chn nh th s lm tng chi ph u t ban u do gi thnh cao hn v t 3 MBA 1 phachim nhiu din tch t hn so vi MBA 3 pha c cng sut tng ng .

III .CHN S LNG V CNG SUT MY BIN P :IIB3.1/Chn s lng :

Xc nh s lng my bin p ca trm bin p xut pht t vic m bo tin cycung cp in i vi loi h tiu th .Vi phn xng dt ta c th xp vo nhm h tiu thloi 2 & 3( h c th ngng cung cp trong mt thi gian no ), ta gi thit rng khi thit kchung cho ton x nghip th ta c tnh vic phn cng sut cho cc trm bin p phnxng v c tnh n khong d tr chung (tc l c MBA d phng hoc c d tr t

cc trm bin p phn xng k cn chung nh my vi phn xng dt ),v vy khi thit ktrm bin p phn xng dt ta ch t mt my bin p.

IIB3.2/ Chn cng sut bin p :

Khi xc nh cng sut MBA cn tnh n kh nng qu ti ca my bin p . Nukhng xt n kh nng qu ti ca my bin p c th lm tng cng sut t ca chng mtcch v ch . Kh nng qu ti ca my bin p c xc nh ty thuc vo th ph ti cah tiu th nhn in t my bin p .

- th ph ti ca phn xng bia c cho nh sau :

(KVA) 100%90% 95%

75%60% 80%

40% 40%tqt 10h

t(h)

0 6 7 10 12 13 15 17 24

- Chn my bin p theo iu kin qu ti thng xuyn khi vn hnh :0,7.S < SMBA < S

-Bin i th ph ti nhiu bc ca MBA thnh th ph ti hai bc ng tr .-Da vo iu kin qu ti thng xuyn v cng sut tnh ton phn xng

( Sttpp = 347,68 KVA ) ta chn s b cng sut nh mc MBA l S = 320 KVA.-T th ph ti v cng sut nh mc my bin p ta tin hnh xc nh vng qu ti

(vng gch cho ) nh hnh v.- Cng sut ng tr ca MBA c chn xc nh theo biu thc :

qt

ii

dtt

tSS

.2

2

= ;

h

tSS iidt

10

.2

1

= 0.

trong : Si - ph ti ca MBA thi gian t i .tqt thi gian qu tiSVTT:L MINH TRUNG .MSSV:402N0060 Trang - 21 -


22/47


Xc nh Smax theo 2h qu ti :Ta c Sttpp = 1817,66 KVA

S max=qt

ii

dtt

tSS

.2

2

= = 357,337

5

2.68,3473.296,330 22

=+ KVA

Xc nh Smin theo 10h non ti :

S min =h

tSS iidt

10

.2

1

= KVA

27310

)4,0.575,0.295,0.28,0()68,347(2

=+++

= KVA

Xc nh h s ph ti :

Kphti =K1tt =m

min

S

S= 85,0

320

273= < 1

K2tt = m

max

S

S

=05,1

320

357,337

= - Xc nh c K2cp = K2 da theo cc ng cong qu ti ca my bin p ,tra hnh

A.3[HDAMH -PTTB]Chn biu i) trong nhm :Vi K1tt =0,85 , ng cong 2h c K2cp =1,32 > K2tt =1,05

(tha iu kin cho php)Chn MBT ny

Tra bng 8.20 [HDAMH -PTTB],ta c cc thng s my bin p c chn :Loi : MBA 3 pha Hiu :ABBch to :22/0,4 KVCng sut nh mc : S = 1600 KVATn hao khng ti : P0 = 720 (W) .Tn hao ngn mch : PN = 4850 (W)in p ngn mch : UN %= 4%Kch thc : ( 1380-865-1525)Trng lng : 1270(Kg)

IV . B CNG SUT PHN KHNG :

Do Cos ca ton phn xng =0,795 < 0,85 nn gim tn tht cho my bin p v ccthit b s dng in ta tin hnh tnh ton v lp t t b .

- Vi Cos =0,795 (trc b ) tg = 0,763- Ta cn b Cos =0,95 (sau b) tg =0,328

Qb = Pttpx (tg(trc b ) - tg(sau b ) ) =294,43*0,535 =128 (KVAr)

Vy ta cn lp nm t b mi t 25(KVAr) Tng cng l 150(KVAr)

Chng IV : CHN DY DN V TNH TON NGN MCHI.PHNG N I DY DN H P N CC THIT B :

Trong thit k ny ta chn phng n i dy ngm trong rnh v chn di t chomng ng lc t t phn phi chnh i n cc t ng lc v t t ng lc i n cc thit

b , ring phn dy dn cung cp cho mng chiu sng ta s thit k i dy ni t trong ngnha PVC v lp t trn tng , s ni dy v s nguyn l c th hin trn cc bnv . Ta c cc nhn xt sau v phng n i dy chn :



23/47


- u im : thun tin trong thi cng ; trnh c nh hng ca nhit ca mitrng trong phn xng,trnh c cc tc ng ri ro khch quan tc ng ln dy dn lmcho dy mau b gi ci, h hng cch in to c s thng thong v khng gian domng in khng gy nh hng n cc hot ng i li, vn chuyn trong phn xng, gic v m quan chung trong ton xng .

-Khuyt im: Vn lp t h thng cp ngm t tin hn h thng i dy ni .Nhng do quy m ca phn xng bia cho khng ln v vy ta chn phng n cp

ngm cp in cho phn xngII. TNH TON LA CHN DY DN CHO MNG H P PHN XNG :

Dng in cho php: Icp dy 76541

... kkkk

Ilvlo

(A.10)[HDAMH -PTTB]Vi k4 :h s nh hng ca cch lp t

k5 :h s nh hng ca s dy t k nhauk6 :h s nh hng ca t chn cp

k7 :h s nh hng ca nhit ca tTra bng H1-19,H1-20,H1-21,H1-22 [HDTKCTBTTC IEC] cho cc h s k :

Khi ta chn cp ta c s dng h s K l tch cc h s hiu chnh , y cc dydn c chn di t do h s hiu chnh :

K= k4.k5. k6 .k7- Vi k4 = 0,8- Ti phn xng bia chai t m nn k6 =1,33- Nhit ca t t0 =250 C k7 = 0,95

1/ Chn cp t trm bin p v t phn phi phn xng:T my bin p v t phn phi ch c mt nha1nhnh nn k5 =1,do h s hii

chnh: K = 0,8.1.1,13.0,95 = 0,858

Chn sao cho Icp dy k

Ittpp

= 858,0528

= 614,8Chn cp ng 3 li trung tnh cch in bng giy tm nha thng khng chy c vch hay nhm , t trong t ,in p < 1KV,loi CBT(3G 300). Icp = 621A ,r0 =0,0601 ( /km)

2/ chn cp t t phn phi n t ng lc:T t phn phi gm 6 nhnh i dy n 5 t ng lc v mt t chiu sng nn k5

= 0,75 ,do h s hii chnh:K = 0,8.0,75.1,13.0,95 = 0,6441

T t PP n t ng lc 1:


Itt 1= 6441,0

75,35

= 55,50 (A)Chn cp mt li : F = 6 mm2

Icp =66 (A) r0 =3,08 (/km)

T t PP n t ng lc 2:



24/47



Itt2= 6441,0

9,38

= 60,4 (A)Chn cp mt li : F = 6 mm2

Icp =66 (A) r0 =3,08 (/km)

T t PP n t ng lc 3:


Itt3= 6441,0

44,29

= 47,71 (A)Chn cp mt li : F = 6 mm2

Icp = 66 (A) r0 = 3,08 (/km)

T t PP n t ng lc 4:

Chn sao cho Icp dy kItt4

= 6441,0154

= 239,09 (A)Chn cp mt li : F = 70 mm2

Icp =254 (A) r0 = 0,268 (/km) T t PP n t ng lc 5:


Itt5= 6441,0

39,234

= 336,9 (A)Chn cp mt li : F = 150 mm2

Icp =387 (A) r0 = 0,124 (/km)

T t PP n t sinh hot:


Ittsh= 6441,0

5,45

= 70,7 (A)Chn cp mt li : F = 16 mm2

Icp = 113 (A) r0 = 1,15 (/km)4/ chn dy cho cc thit b :

T ng lc 1,2,3, c 3 loi thit b :my bm nc nng hp ,motor cu v qutcng nghip , chn k5 = 0,45

H s hu chnh K = 0,8.0,45.1,13.0,95 =0,4

T ng lc 4, c 5 loi thit b :my gp rng ,my gp y ,motor v trn motor vdi v my chit bia, chn k5 = 0,52

H s hu chnh K = 0,8.0,52.1,13.0,95 =0,5

T ng lc 5 ch c 1 loi thit b :my xc chai , chn k5 = 0;8H s hu chnh K = 0,8.0,8.1,13.0,95 =0,7

* My gp rng :Im =15,19(A)


Ilvmax = 5,0

19,15

= 31,8(A)SVTT:L MINH TRUNG .MSSV:402N0060 Trang - 24 -


25/47


Chn cp mt li : F = 2,5 mm2

Icp = 41 (A) r0 = 7,41 (/km)* My gp y :

Im =15,19(A)


Ilvmax= 5,0

19,15

= 31,8(A)


Icp = 41 (A) r0 = 7,41 (/km)* My xc chai :

Im = 117,18(A)


Ilvmax= 7,0

18,117

= 168,28(A)

Chn cp mt li : F = 35 mm2

Icp = 174 (A) r0 = 0,524 (/km)

* Motor v trn :Im =13,29(A)


Ilvmax= 5,0

29,13

= 26,58(A)


Icp = 41 (A) r0 = 7,41 (/km)

* Motor v di :Im =13,29(A)


Ilvmax= 5,0

29,13

= 26,58(A)


Icp = 41 (A) r0 = 7,41 (/km)

* My chit bia :Im = 47,48(A)


Ilvmax= 5,0

48,47

= 94,96(A)

Chn cp mt li : F = 25 mm2

Icp = 144 (A) r0 = 0,727 (/km)



26/47


* My bm nc nng hp :Im =7,6(A)


Ilvmax

=4,0

6,7

= 19(A)Chn cp mt li : F = 1,5 mm2

Icp = 31 (A) r0 =12,11 (/km)

* Motor cu :Im =1;9(A)


Ilvmax= 4,0

9,1

= 4.75(A)


Icp = 31 (A) r0 = 12,1 (/km)* Qut cng nghip :

Im =1,42(A)


Ilvmax= 4,0

42,1

= 3,35(A)


Icp = 31 (A) r0 = 12,1 (/km)

II.TNH TON NGN MCH - KIM TRA ST P :II.A. TI CC T NG LC V T PHN PHI :

1. Ti t phn phi :Theo u bi cho :

X0 = 0.08 (/Km)r0 =0,075 (/Km)Rcb = 0,15 (m)

* in tr MBA :

RMBA = 587,7320

10.4,0.580,410.2

32

32

2

==

dm

dmN

S

UP( m)

* in khng MBA :

XMBA = ==320

.400*04,0

. 22

00

dm

dmN

S

UU20 (m)

* Tng tr MBA :

ZMBA = 38,2120578,7 2222 == MBAMBA XR (m)



27/47


Rdy = (r0 .l) = (0,075.20) = 1,5 m

Xdy = (x0 .l) = (0,075.20)/3 = 1.6 m

Zk1 = 22 )XdXmba()RcbRd(Rmba ++++

= 22 )1,620()0,000151,5(7,578 ++++ = 23,43 (m)Tnh ngn mch ti t phn phi chnh:

INk1 = 85,943,23.3

10.4,0

1.3

3

==Zk

Udm KA

Kim tra st p : Upp = )sin.cos..(.3 pppptt XRI +

Vi Ppp = 276,43 KW ; Ittpp = 528 (A)Spp = 347,68 KVA

cos= Ppp /Spp = 0.795sin= 0,606

Rpp = Rdy = 1,5 mXpp =Xdy = 1,6 m

Upp = 4,110).606,0*6,1795,0.5,1.(528.3 3 =+ (V)

Upp%= 100.380

4,1100. =

dm

pp

U

U= 0,36 %

2. Ti t ng lc 1: Thng s cp t ng lc 1 :

Tit din F = 6 mm2

Icp =66 A ; r0 = 3,08 /kmChiu di cp l = 24 m

Rdy1= (r0 .l)/3 = (3,08*24) = 73,92 m ( v mi pha c 3 si nn Rdy/3 )Xdy1 = (x0 .l)/ = (24*0,08)/ = 1,92 mZk2-1 = 22 )XdXmba()Rcb2RdRd1(Rmba +++++

= 22 )1,9220()2.0,0001573,921,5(7,578 +++++ = 85,6 (m)

INk2-1 = 7,26,85.3

10.4,0

.3

3

==Zk

Udm KA

Kim tra st p :

U1-1 = )sin.cos..(.3 1 daydaytt XRI + Vi Itt1 = 25,88 A

cos= 0,8 sin= 0,6U1-2 = 5,210).6,0.92,18,0.92,73.(88,25.3 3 =+ (V)

U1-1%= 100.380

5,2100.11 =

dmU

U= 0,65 %

3.Ti t ng lc 2:

Thng s cp t ng lc 2 :Tit din F = mm2



28/47


Icp =66 A ; r0 = 4,61 /kmChiu di cp l = 43m

Rdy2= (r0 .l) = (3,08*12)= 36,98 mXdy2 = (x0 .l) = (12*0,08) = 0,96 mZk2-2 = 22 )XdXmba()Rcb2RdRd2(Rmba +++++

= 22 )0,9620()2.0,0001536,981,5(7,578 +++++ = 50,6 (m)

INk2-2 = 5,46,50.3

10.4,0

.3

3

==Zk

Udm KA

Kim tra st p :U1-2 = )sin.cos..(.3 1 daydaytt XRI + Vi Itt1 = 38,9 A

cos= 0,8 sin= 0,6U1-2 = 210).6,0.92,08,0.98,36.(9,38.3 3 =+ (V)

U1-2%= 100.3802

100.21 =

dmU

U

= 0,52 %

4. Ti t ng lc 3:

Thng s cp t ng lc 2 :Tit din F = 6 mm2Icp = 66 A ; r0 = 3,08 /kmChiu di cp l = 43m

Rdy3= (r0 .l) = (43*3,08)= 130 m

Xdy3 = (x0 .l) = (43*0,08) = 3,44 mZk2-3 = 22 )XdXmba()Rcb2RdRd3(Rmba +++++

= 22 )3,4420()2.0,000151301,5(7,578 +++++ = 141 (m)

INk2-3 = 63,1141.3

10.4,0

.3

3

==Zk

Udm KA

Kim tra st p :


cos= 0,8 sin= 0,6U1-3 = 4,510).6,0.44,38,0.130.(44,29.3 3 =+ (V)

U1-3%= 100.380

4,5100.31 =

dmU

U= 1,42%

5. Ti t ng lc 4:

Thng s cp t ng lc 4 :Tit din F = 70 mm2Icp =254 A ; r0 = 0;268 /kmChiu di cp l = 29mRdy4= (r0 .l) = (0,268*32)= 8,578 m



29/47


Xdy4 = (x0 .l) = (32*0,08) = 2,56 mZk2-4 = 22 )XdXmba()Rcb2RdRd4(Rmba +++++

= 22 )2,5620()2.0,000158,5781,5(7,578 +++++ = 28,7 (m)

INk2-4 = 85,28.3

10.4,0

.3

3

==

Zk

Udm KA

Kim tra st p :

U1-4= )sin.cos..(.3 1 daydaytt XRI + Vi Itt1 = 154 A

cos= 0,75 sin= 0,66U1-4 = 210).6,0.92,08,0.98,36.(9,38.3 3 =+ (V)

U1-4%= 100.380

2100.41 =

dmU

U= 0,52 %

6. Ti t ng lc 5:

Thng s cp t ng lc 5 :Tit din F = 150 mm2Icp =387 A ; r0 = 0,124 /kmChiu di cp l = 40m

Rdy5= (r0 .l) = (40*0,124)= 4,96 mXdy5 = (x0 .l) = (40*0,08) = 3,2 mZk2-5 = 22 )XdXmba()Rcb2RdRd5(Rmba +++++

= 22 )3,220()2.0,000154,961,5(7,578 +++++ = 27,15 (m)

INk2-5 = 9,715,27.310.4,0

.3

3

==Zk

Udm KA

Kim tra st p :


cos= 0,7 sin= 0,714U1-5 = 3,210).714,0*2,37,0*96,4.(39,234.3 3 =+ (V)

U1-5%= 100.380

3,2100.51 =

dm

U

U= 0,6%

7. Ti t chiu sng sinh hot :

Thng s cp t ng lc 2 :Tit din F = 16 mm2Icp = 113 A ; r0 =1,15 /kmChiu di cp l = 8m

Rdycs= (r0 .l) = (1,15.8)= 9.2 mXdycs = (x0 .l) = (8*0,08) = 0,64 mZk2-cs = 22 )XdXmba()Rcb2RdRd(Rmba +++++

=22

)0,6420()2.0,000159.21,5(7,578 +++++ = 30 (m)



30/47


INk2-cs = 7,730.3

10.4,0

.3

3

==Zk

Udm KA

Kim tra st p :

U1-cs = )sin.cos..(.3 1 daydaytt XRI + Vi Itt1 = 45,5 A

cos= 0,8 sin= 0,6U1-cs = 6,010).6,0.64,08,0.2,9.(5,45.3 3 =+ (V)

U1-cs%= 100.380

6,0100.1 =

dm

cs

U

U= 0,15 %

II.BTNH ST P TI CC THIT B :

1. nhm 1 i vi my xa v c cng sut ln nht l motor cu (74)_:Theo cc kt qu ta tnh trong bng 1 ta c :

Im = 1,9 A Imm = 9,5 Acos1 = 0,8

Khong cch t thit b n t ng lc s 1 theo s ta c :L = 16 m, r0 = 12,1 /Km , x = 0 ( v tit din dy nh hn 50 mm2 )

R= r0.L = 12,1*16 = 193 m U2 -1 = )sincos..(.3 XRI +

= 5,2001,0*)6,0.08,0.193.(5,9.3 =+ (V)

U2-1%= 100.380

5,2100.12 =

dmU

U= 0,64 %

2. nhm 2 i vi my xa v c cng sut ln nht l motor cu(74):Theo cc kt qu ta tnh trong bng 1 ta c :

Im = 1,9 A Imm = 9,5 Acos1 = 0,8

Khong cch t thit b n t ng lc s 1 theo s ta c :L = 11m, r0 = 12,1 /Km , x = 0 ( v tit din dy nh hn 50 mm2 )

R= r0.L = 12,1*11 = 133 m U2 -2 = )sincos..(.3 XRI +

= 75,1001,0*)6,0.08,0.133.(5,9.3 =+ (V)

U2-2%= 100.

380

75,1100.12 =

dmU

U= 0,45 %

3. nhm 3 i vi my xa v c cng sut ln nht l motor cu(74):Theo cc kt qu ta tnh trong bng 1 ta c :

Im = 1,9 A Imm = 9,5 Acos1 = 0,8

Khong cch t thit b n t ng lc s 1 theo s ta c :L = 14m, r0 = 12,1 /Km , x = 0 ( v tit din dy nh hn 50 mm2 )

R= r0.L = 12,1*14 = 169,4 m U2 -3 = )sincos..(.3 XRI +

= 2,2001,0*)6,0.08,0.169.(5,9.3 =+ (V)



31/47


U2-2%= 100.380

2,2100.12 =

dmU

U= 0,57 %

4. nhm 4 i vi my xa v c cng sut ln nht l my chit bia(72):Theo cc kt qu ta tnh trong bng 1 ta c :

Im = 47,48A Imm = 237,4 Acos1 = 0,8Khong cch t thit b n t ng lc s 1 theo s ta c :

L = 9m, r0 = 1,15 (/Km) , x = 0 ( v tit din dy nh hn 50 mm2 ) R= r0.L = 9 *1,15 = 10,35m U2 -4 = )sincos..(.3 XRI +

= 7,0001,0*)6,0.08,0.35,10.(48,47.3 =+ (V)

U2-4%= 100.380

7,0100.12 =

dmU

U= 0,2 %

5. nhm 5 c 2 my ging nhau (my xc chai):Theo cc kt qu ta tnh trong bng 1 ta c :

Im = 117,18A Imm = 585,90 Acos1 = 0,7

Khong cch t thit b n t ng lc s 5 theo s ta c :L = 6,5m, r0 = (/Km) , x = 0,08*6,5 = 0,52(/Km)

R= r0.L = 6,5 *0,124 = 0,806 m U2 -5 = )sincos..(.3 XRI +

= 35,0001,0*)66,0.52,07,0.806,0.(90,585.3 =+ (V)

U2-5%= 100.380

35,0100.52 =

dmU

U= 0,09 %

II.C Kim tra st p trn ton b ng dy t trm bin p cho n thit b s dng

chn:Ud1 = Upp% + U1-1%+ U2-1% = 0,36% + 0,65 % + 0,64 % = 1,65 %

Ud2= Upp% + U1-2%+ U2-2% = 0,36% + 0,52% + 0,45 % =1,33 %

Ud3 = Upp% + U1-3%+ U2-3% = 0,36% + 1,42 % + 0,2 % = 1,98%

Ud4 = Upp% + U1-4%+ U2-4% = 0,36% + 0,52 % + 0,57 % = 1,45 %

Ud5 = Upp% + U1-5%+ U2-5% = 0,36% + 0,6 % + 0,09% =1,05 %

Udsh = Upp% + U1-cs% = 0,36% + 0,15 % + =0,51 %

i vi li in phn xng th tn tht in p cho php l 5% , qua tnh ton tathy trong iu kin vn hnh xu nht th cc thit b la chn xa nht & c cng sut ln vnc th hot ng bnh thng ( v tn tht in p tnh ton nh hn tn tht cho php ).



32/47


STT Tn my Sln

g

Pm(KW)

Ilv(A) K Icptt (A) Tit dinmm2

Icp(A)

Chiudi(m)

1 My nn kh 1 1 18,2 37,5 0,48 78,1 4G10 87 102 My nn kh 1 1 18,2 37,5 0,48 78,1 4G4 87 113 My nn kh 2 1 10,5 21,54 0,48 44,87 4G2,5 53 114 My nn kh 3 1 7,5 15,38 0,48 32,04 4G15 41 105 My lc bi 1 27 53,4 0,48 111,2 4G70 113 126 My bng 1 1 62 125,17 0,64 195,6 4G95 254 1,5

7 My bng 2 1 71,92 147,54 0,64 203,5 4G4 301 3,58 My ng 2 5,92 24,4 0,45 53,5 4G4 55 89 My ng 2 5,92 24,4 0,45 53,5 4G4 55 10,510 My ng 2 5,92 24,4 0,45 53,5 4G4 55 1311 My ng 2 5,92 24,4 0,45 53,5 4G4 55 1512 My ng 2 5,92 24,4 0,45 53,5 4G4 55 1713 My hp si 1 11,5 23,7 0,45 51,97 4G4 55 18

Chn CB :Theo cc iu kin sau :

ImCB> Ilvmax1 = 37,5 A

Chn mc CB theo bng tra PL 3.1 [ HTCC NCH ]:Mc C60NIm = 40 AUm = 440 VACIN =3 kA

Itt Ir Icpdy ( Ir : dng ct nhit CB ) Imm Im I(1)N ( Im : dng ct t CB , Imm : dng m my ng c

I(1)N : dng ngn mch 1 pha )Vi mc CB C60a ta c I r = Im = 40 A

Im = 5.Im = 200 ATng t cch tnh ton trn ta c c CB cho cc my cn li:

Tn my S lng Ilv (A) Tn CB Trip Unit k r Im (A) Um (V) Icu (A)



33/47


My nn kh 1 1 37,5 C60N 40 440 10My nn kh 1 1 37,5 C60N 40 440 10My nn kh 2 1 21,54 C60N 25 440 10My nn kh 3 1 15,38 C60N 16 440 10My lc bi 1 53,4 C60N 63 440 10My bng 1 1 125,17 NS160 STR22SE 0,5 160 690My bng 2 1 147,54 NS160 STR22SE 0,5 160 690My ng 2 24,4 C60N 32 440 10My ng 2 24,4 C60N 32 440 10My ng 2 24,4 C60N 32 440 10My ng 2 24,4 C60N 32 440 10My ng 2 24,4 C60N 32 440 10

IIC2.2 . Dy dn , CB cho cc l thuc nhm 2 :Gm 12 l, t ng lc chnh thuc mt bng ca xng ln

Chn dy & cp

STT Tn my S

lng

Pm(KW)

Ilv (A) K Icptt (A) Tit dinmm2

Icp(A)

Chiudi(m)

1 My se 1 9 18,55 0,56 33,13 4G2,5 41 0,52 My se 1 9 18,55 0,56 33,13 4G2,5 41 13 My se 1 9 18,55 0,56 33,13 4G2,5 41 1,54 My se 1 9 18,55 0,56 33,13 4G2,5 41 0,55 My se 1 9 18,55 0,56 33,13 4G2,5 41 16 My se 1 9 18,55 0,56 33,13 4G2,5 41 1,5

7 My chi 4 4,7 38,76 0,45 85 4G15 113 118 My chi 4 4,7 38,76 0,45 85 4G15 113 119 My chi 4 4,7 38,76 0,45 85 4G15 113 1110 My chi 4 4,7 38,76 0,45 85 4G15 113 1111 My ghp s 1 4,7 9,69 0,45 21,25 4G1,5 31 712 My ghp s 1 4,7 9,69 0,45 21,25 4G1,5 31 7

Chn CB :

STT Tn TB Sln

g

Ilv (A) Im (A) Tn CB Um (V) Im (A) Icu (A)

1 My se 1 18,55 20 C60N 440 100 102 My se 1 18,55 20 C60N 440 100 103 My se 1 18,55 20 C60N 440 100 104 My se 1 18,55 20 C60N 440 100 105 My se 1 18,55 20 C60N 440 100 106 My se 1 18,55 20 C60N 440 100 107 My chi 4 38,76 40 C60N 440 200 108 My chi 4 38,76 40 C60N 440 200 109 My chi 4 38,76 40 C60N 440 200 1010 My chi 4 38,76 40 C60N 440 200 1011 My ghp s 1 9,69 16 C60N 440 80 10



34/47


12 My ghp s 1 9,69 16 C60N 440 80 10IIC2.3 . Dy dn , CB cho cc l thuc nhm 3 :

Gm 21 l, t ng lc chnh thuc mt bng ca xng lnChn dy & cp

STT Tn my Sln

g

Pm(KW)

Ilv (A) K Icptt (A) Tit dinmm2

Icp(A)

Chiudi(m)

1 My ci 1 9 15,46 0,36 42,9 4G2,5 41 52 My ci 1 9 15,46 0,36 42,9 4G2,5 41 53 My ci 1 9 15,46 0,36 42,9 4G2,5 41 64 My ci 1 9 15,46 0,36 42,9 4G2,5 41 65 My ci 1 9 15,46 0,36 42,9 4G2,5 41 76 My ci 1 9 15,46 0,36 42,9 4G2,5 41 7

7 My ci 1 9 15,46 0,36 42,9 4G2,5 41 88 My ci 1 9 15,46 0,36 42,9 4G2,5 41 89 My ci 1 9 15,46 0,36 42,9 4G2,5 41 3,510 My ci 1 9 15,46 0,36 42,9 4G2,5 41 4,511 My ci 1 9 15,46 0,36 42,9 4G2,5 41 5,512 My ci 1 9 15,46 0,36 42,9 4G2,5 41 6,513 My ghp 1 4,7 18,55 0,56 33,12 4G4 53 1114 My ghp 1 4,7 18,55 0,56 33,12 4G4 53 915 My chi k 5 15 30,9 0,56 55,17 4G15 113 1216 My th 1 18,2 37,5 0,45 55,17 4G15 113 617 My th 1 18,2 37,5 0,45 55,17 4G15 113 7,5

18 My th 1 18,2 37,5 0,45 55,17 4G15 113 919 My th 1 18,2 37,5 0,45 55,17 4G15 113 1120 My th 1 18,2 37,5 0,45 55,17 4G15 113 12,521 My th 1 18,2 37,5 0,45 55,17 4G15 113 14

Chn CB :

STT Tn TB Slng

Ilv (A) Im (A) Tn CB Um (V) Im (A) Icu (A)

1 My ci 1 15,46 20 C60N 440 100 102 My ci 1 15,46 20 C60N 440 100 10

3 My ci 1 15,46 20 C60N 440 100 104 My ci 1 15,46 20 C60N 440 100 105 My ci 1 15,46 20 C60N 440 100 106 My ci 1 15,46 20 C60N 440 100 107 My ci 1 15,46 20 C60N 440 100 108 My ci 1 15,46 20 C60N 440 100 109 My ci 1 15,46 20 C60N 440 100 1010 My ci 1 15,46 20 C60N 440 100 1011 My ci 1 15,46 20 C60N 440 100 1012 My ci 1 15,46 20 C60N 440 100 10

13 My ghp 1 18,55 20 C60N 440 100 1014 My ghp 1 18,55 20 C60N 440 100 10



35/47


15 My chi k 5 30,9 32 C60N 440 160 1016 My th 1 37,5 40 C60N 440 200 1017 My th 1 37,5 40 C60N 440 200 1018 My th 1 37,5 40 C60N 440 200 1019 My th 1 37,5 40 C60N 440 200 1020 My th 1 37,5 40 C60N 440 200 1021 My th 1 37,5 40 C60N 440 200 10

IIC2.10 .Dy dn , CB cho cc t ng lc ,t phn phi ( 03 t): T ng lc 1 : Chn dy & cp cho t ng lc theo:

Il1 = Itt1 = 476,86 A

Dng in cho php: Icp dy 76541

... kkkk

Idl

(A.10)[HDAMH -PTTB]Vi k4 :h s nh hng ca cch lp t

k5 :h s nh hng ca s dy t k nhauk6 :h s nh hng ca t chn cpk7 :h s nh hng ca nhit ca t

Tra bng H1-19,H1-20,H1-21,H1-22 [HDTKCTBTTC IEC] cho cc h s k :Cp t trong rnh c k4 = 0,8S si cp 04 rut = 3 chn k5 = 0,8( Xem bng v mt bng v s ni dy ca phn xng )t kh k6 = 1Nhit ca t t0 =200 C k7 = 1

Icpdy 86,7541.1.8,0.8,0

86,476 = A

Tra bng PL4.29 [ HTCC NCH ] chn dy n t t phn phi loi :Cp ng 4 li ; v bc cch in PVCTit din F = 4G150 mm2Icp = 387 A ; r0 = 0,124 /kmChiu di cp l = 16 m

Mi pha gm 2 si.Tng t cch tnh ton trn ta c c dy dn cho cc nhm my cn li:

Nhm Ptt(KW)

Itt (A) K Ittcp (A) Icp(A)

R0(/km)

Tit din(mm2)

Chiudi (m)

Ghi ch

1 242,26 476,86 0,64 754,09 387 0,124 4G150 16 Mi pha 2 si2 107,69 211 0,64 329,68 174 0,524 4G35 26 Mi pha 2 si3 180,42 353,6 0,64 552,5 301 0,193 4G95 7 Mi pha 2 si4 336,3 662 0,56 1182,14 484 0,0991 4G185 16 Mi pha 3 si5 336,3 662 0,56 1182,14 484 0,0991 4G185 16 Mi pha 3 si6 236,55 487,7 0,56 870,89 301 0,193 4G95 18 Mi pha 3 si

Chn CB :Theo cc iu kin sau :

ImCB> Il1 = 476,86 AChn mc CB theo bng tra [HDTKCTBTTC IEC]:

Mc NS630N



36/47


Im = 630 AUm = 690 VACIN = 35 kA

Itt Ir Icpdy ( Ir : dng ct nhit CB )Itt Ir = k0.kr.Im Icpdy

476,86 k0.kr.630 754,860,757 k0.kr 1,19

Tra bng [HDTKCTBTTC IEC] ta chn Trip unit STR23SEk0 = 1 v kr = 0.8

0,757 k0.kr = 1 1,19 Imm Im=km.Ir I(1)N (Im :dng ct t CB , Imm : dng m my ng c

I(1)N : dng ngn mch 1 pha )Chn km = 6 Im = 6.1.630 = 3780 A



37/47


Tng t cch tnh ton trn ta c c CB cho cc nhm my cn li:Nhm Ilv (A) Icp (A) Tn CB Trip Unit K r Ir

(A)Icu (A) Im

(A)Um

(VAC)IN

(KA)1 476,86 754,09 NS630N STR23SE 0,8 540 630 690 102 211 329,68 NS250 STR22SE 0,9 225 250 690 83 353,6 552,5 NS400N STR23SE 0.9 360 400 690 104 662 1182,14 C801 STR25DE 0,9 720 800 690 255 662 1182,14 C801 STR25DE 0,9 720 800 690 256 487,7 870,89 NS630N STR23SE 0,8 504 630 690 10

T phn phi : Chn dy & cp cho t phn phi theo:Ipp = Ittpx = 2623,56 A

Icpdy 2623,56 ATra bng PL4.28 [ HTCC NCH ] chn dy n t MBA loi :

Cp ng 1 li ; v bc cch in PVCTit din F = 1 x 630 mm2Icp = 950 A ; r0 = 0,0283 /kmChiu di cp l = 12 m

Mi pha gm 3 si.Chn CB :Theo iu kin sau :

ImCB> Ipp = 2623,56 AChn mc CB theo bng PL3.3 [ HTCC NCH ]:

Mc CM3200NIm = 3200 AUm = 690 VACIN = 50 kA

IIC3 .TNH TON NGN MCH - KIM TRA ST P :IIC3.1. TI CC T NG LC V T PHN PHI :1. Ti t phn phi :

RMBA = 3,11600

10.4,0.2110

.2

32

3

2

2

==

dm

dmN

S

UPm

ZMBA= 0,7100.1600

7.400

100.

20

02

20==

dm

N

S

UUm

XMBA= 88.63,10,7 2222 == MBAMBA RZ mRdy = (r0 .l)/3 = (0,0283.12)/3 = 0,1132 m ( v mi pha c 3 si nn Rdy/3 )Xdy = (x0 .l)/3 = (0,08.12)/3 = 0,32 mZdy = 339,032,01132,0 2222 =+=+ dayday XR m

Zpp = ZMBA + Zdy = 7,0 + 0,339 = 7,339 mTnh ngn mch ti t phn phi chnh:

IN = 46.31339,7.3

10.4,0

.3

3

==IIZ

U

pp

dmKA

Kim tra st p : Upp = )sin.cos..(.3 pppptt XRI +

Vi Ppp = 1303,4 KW ; Ittpp = 2623,56 A

Spp = 1226,9 KVA cos= Ppp /Spp = 1303,4 /1226,9 = 0,717



38/47


sin= 0,697Rpp = Rdy = 0,1132 mXpp =Xdy = 0,32 m

Upp =0

03 3 8,11 0).6 9 7,0.3 2,07 17,0.1 1 3 2,0.(5 6,2 6 2 3.3 =+

2. Ti t ng lc 1: Thng s cp t ng lc 1 :

Cp ng 4 li ; v bc cch in PVCTit din F = 4G150 mm2Icp =387 A ; r0 = 0,124 /kmChiu di cp l = 12 m

Mi pha gm 2 si.Rdy = (r0 .l)/2 = (0,124.16)/2 = 0,992 m ( v mi pha c 2 si nn Rdy/2 )Xdy = (x0 .l)/2 = (0,08.16)/2 = 0,64 mZdy = 65,064,0124,0 2222 =+=+ dayday XR m

Z1 = ZMBA + Zdy = 7,0 + 0,65 = 7,65 mTnh ngn mch ti t phn phi chnh:

IN1 = 18,3065,7.3

10.4,0

3

3

1

==IIZ

Udm KA

Kim tra st p : U1 = )sin.cos..(.3 1 daydaytt XRI +

Vi Itt1 = 377 Acos= 0,733 sin= 0,68

U1 =0

03 7 6,01 0) .6 8,0.6 4,07 3 3,0.9 9 2,0.(3 7 7.3 =+

3. Ti t ng lc 2: Thng s cp t ng lc 2 :Cp ng 4 li ; v bc cch in PVCTit din F = 4G35mm2Icp = 174 A ; r0 = 0,524 /kmChiu di cp l = 26 m

Mi pha gm 2 si.Rdy = (r0 .l)/2 = (0,524.26)/2 = 6,812 m ( v mi pha c 3 si nn Rdy/3 )Xdy = (x0 .l)/2 = (0,08.26)/2 = 1,04 mZdy = 89,604,1812,6 2222 =+=+ dayday XR m

Z2 = ZMBA + Zdy = 7,0 + 6,89 = 13,89 m

Tnh ngn mch ti t phn phi chnh:IN2 = 67,16

89,13.3

10.4,0

3

3

2

==IIZ

Udm KA


Vi Itt2 = 164,84 Acos = 0,736 sin= 0,677

U2 =0

03 6 3,11 0) .6 7 7,0.0 4,17 36,0.8 1 2,6.(8 4,1 6 4.3 =+

4. Ti t ng lc 3:

Thng s cp t ng lc 3 :Cp ng 4 li ; v bc cch in PVC



39/47


Tit din F = 4G95 mm2Icp = 301 A ; r0 = 0,103 /kmChiu di cp l = 7 m

Mi pha gm 2 si.Rdy = (r0 .l)/2 = (0,103.7)/2 = 0,36 m ( v mi pha c 3 si nn Rdy/3 )

Xdy = (x0 .l)/2 = (0,08.7)/2 = 0,28 mZdy = 456,028,036,0 2222 =+=+ dayday XR m

Z3 = ZMBA + Zdy = 7,0 + 0,456 = 7,456 mTnh ngn mch ti t phn phi chnh:

IN3 = 97,30456,7.3

10.4,0

3

3

3

==IIZ

Udm KA


Vi Itt3 = 276,25 Acos= 0,736 sin= 0,677

U3 =0

03 2 1 7,01 0) .3 7 7,0.2 8,07 3 6,0.3 6,0.(2 5,2 7 6.3 =+

IIC3.2.TNH ST P TI CC THIT B :

1. nhm 1 i vi my 9 :Theo cc kt qu ta tnh trong bng 1 ta c :

Im9 = 23,7 A Imm9 = 5.23,7 = 118,5 Acos9 = 0,7

Khong cch t thit b n t ng lc s 1 theo s ta c :l9 = 18 m, r0 = 4,61 /Km , x = 0 ( v tit din dy nh hn 50 mm2 )

R= r0.l9 = 4,61.18 = 82,98 m Uf = )sincos..(.3 XRI +

= 11922)714,0.07,0.98,82.(75,118.3 =+ mV = 11,438 V

U9%= 100.400

922,11100. =

dm

f

U

U= 2,98 %


Im11 = 4.9,69 = 36,76 A Imm11 = 5.36,76 = 193,8 Acos11 = 0,7



= 3,2972)714,0.07,0.65,12.(8,193.3 =+ mV = 2,97 V

U11%= 100.400

97,2100. =

dm

f

U

U= 0,74 %


Im17 = 37,5 A Imm17 = 5.37,5 = 187,5 Acos9 = 0,7




40/47



= 3660)714,0.07,0.1,16.(5,187.3 =+ mV = 3,66 V

U17%= 100.400

66,3100. =

dm

f

U

U= 0,915 %

C3.3 Kim tra st p trn ton b ng dy chn:B qua st p trn on t My bin th n t phn phi ( chiu di ngn )Ud1 = Upp% + U1%+ U9% = 1,38 % + 0,569 % + 2,98 % = 4,929 %Ud2 = Upp% + U2%+ U11% =1,38 % + 1,63 % + 0,74 % =3,75 %Ud3 = Upp% + U3%+ U17% =1,38 % + 0,217 % + 0,915 % =2,512 %i vi li in phn xng th tn tht in p cho php l 5% , qua tnh ton ta

thy trong iu kin vn hnh xu nht th cc thit b la chn xa nht & c cng sut ln vnc th hot ng bnh thng ( v tn tht in p tnh ton nh hn tn tht cho php ).



41/47

PE

RnTBRnHT

N

L3

L2

L1

RnTB

L3

L2

L

PE

RnHT

L3

L2

L1


Phn III : TNH TON THIT K BO V AN TONH thng cung cp in lm nhim v truyn ti v phn phi in nng n cc h tiu

th .Khi cch in gia cc thit b b chcthng , ngi vn hnh c th b tai nn ingit cht ngi. Do o, phi c bin php anton chng in git , mt trong nhng bin

php an ton chng in git l thc hin ni tcho cc thit b .

Trang b ni t bao gm cc in cc v dy dn ni t .Cc in cc ni t bao gm cc thng ng cmsu vo t v in cc nm ngang chn ngm mt su nht nh . Cc dy ni t c dng ni cc b phn c ni t vi cc incc ni t . Trong h thng in c 3 loi ni t :

- Ni t an ton : thit b ni t loi ny c ni vo v thit b in - Ni t lm vic : thit b ni t loi ny c ni vo trung tnh ca my bin p - Ni t chng st : thit b ni t loi ny c ni vo kim thu li

III.1/ S LC V CC H THNG NI T :- S TT : S ni v kiu trung tnh ni t , v thit b ni t ring

Dy PE ( Protective earth : dy ni t bov ) c b tr ring bit vi dy trungtnh v c tit din c xc nh theodng s c ln nht c th xy ra.

- S IT : S ni v kiu trung tnh cch ly vi t , v thit b ni t

Dy PE ( Protective earth : dy ni t bo v ) c b tr ring bit vi dy trung tnh vc tit din c xc nh theo dng s c ln nht c th xy ra.

- S TN-C : S ni v kiu trung tnh ni t , v thit b ni vo trung tnh ,dytrung tnh v dy PE chung.

Dy trung tnh v PE ( Protective earth : dy ni t bo v ) c s dng chung gi l dyPEN. S ny khng c php s dng i vi cc dy nh hn 10 mm 2 (dy Cu) v 16mm2 (Al) v thit b in cm tay.

- S TN- S : S ni v kiu trungtnh ni t , v thit b ni vo trungtnh ,dy trung tnh v dy PE tch ri.

SVTT:L MINH TRUNG .MSSV:402N0060 Trang - 41 -PEN

RnHT

L3

L2

L1


42/47

TN-STN-C

PENPE PE

N

RnHT

LL2L1


Dy trung tnh v PE ( Protective earth : dy ni t bo v ) c s dng ring. S nyl bt buc i vi cc dy nh hn 10 mm2 (dy Cu) v 16 mm2 (Al) hoc cc thit b indi ng.

-S TN-C-S : S TN-C v TN-S c th c cng s dng trong cng mt li. Trongs TN-C-S,s TN-C (4 dy) khng bao gi c s dng sau s TN-S. im phndy PE tch khi dy PEN thng l im u ca li.



43/47


III .2/CHN S NI T : Do trong mng in c tit din dy thay i nn ta chn ni t dng s TN-C-S. Ccqui nh c th khi thc hin s ny:

- c p dng mng c trung tnh ngun ni t trc tip.- Trung tnh pha h p ca my bin p ngun , v t phn phi, v cc phn t khc trong

mng v cc phn t dn in trong mng phi c ni t chung.- Thc hin ni t lp li nhng v tr cn thit dc theo dy PEN.

- Dy PEN khng c i ngang mng dn ,cc ng dn st thoc lp vo kt cu thpv hin tng cm ng v hiu ng gn c th lm tng tng tr ca dy.

- Dy PEN khng c ct trong bt k trng hp no.Do khi s dng CB bo v cnm bo theo qui nh :

+ Loi 3 cc khi mng loi TN-C (dy PEN )+ Loi 4 cc khi mng loi TN-S ( 3 dy pha + dy trung tnh v dy PE )

III .3/TNH TON H THNG NI T :III.3.1.Chn dy PE :

Dy trung tnh ( PE ) i theo chu vi ca phn xng .Chiu di dy i t trung tnh my bin p n cui ng dy :

L = 2 ( 29 + 21 ) = 100 mNi dy trung tnh ni t n v tng thit b bo v dng chm v mt phaTit din ca dy trung tnh PE :

Theo IEC nu : + F pha < 16 mm2th : F PE = F pha

+ 16 F pha 35 mm2

th : F PE = 16 mm2+ F PE > 35 mm2

th : F PE = F pha

Trong phn xng ny a s tit din dy nh hn 35 mm2 nn ta chn FPE = 16 mm2 .Ni dy trung tnh n thit b ni t : S :

III.3.2. Tnh chm v ti cc t phn phi v ng lc :

Ti t phn phi :Do dy PEN ctit din F =16mm2 tra bng PL4.28 [ HTCC NCH ] ta c :r0 =1,15/km , x0 = 0,333/km

R = r0 .l =1,15.100 = 115 mX = x0 .l = 0,333.100 = 33,3 m Z = R + jX = 115 +j33,3I Zpen I= 119,72 m

Ta tnh :I Zvng I= I Zpp I + IZpen I = 7,339 + 119,72 = 127,059 m

Ichm v pp = 9,164410.059,127

220.95,0.95,0

3==

vong

p

Z

UA (B.24)[HDAMH

-PTTB]


T PP T.L

A A

PEN

DB B

C C

PEN PENNN

4


44/47


Ti t ng lc 1 :Tng t ta c I Zpen I= 119,72 m

I Zvng1 I= I Zpp I + IZpen I + IZ1 I = 7,339 + 119,72 + 7,885 = 134,944 m

Ichm v 1 = 79,154810.944,134

220.95,0.95,0

3

1

==

vong

p

Z

UA

Ti t ng lc 2 :

Tng t ta c I Zpen I= 119,72 m I Zvng2 I= I Zpp I + IZpen I + IZ2 I = 7,339 + 119,72 + 13,85 = 140,909 m

Ichm v 2 = 22,148310.909,140

220.95,0.95,0

3

1

==

vong

p

Z

UA

Ti t ng lc 3 :

Tng t ta c I Zpen I= 119,72 m I Zvng3 I= I Zpp I + IZpen I + IZ3 I = 7,339 + 119,72 + 7,456 = 134,515 m

Ichm v 3 = 73,155310.515,134

220.95,0.95,03

2

==

vong

p

Z

UA

Ta thy rng : Dng Ichm v d xa nht hay gn nht nu c xut hin u phthuc rt ln vo ZPEN .V vy, ni t cho cc v thit b l rt quan trng, nhm trnhnguy him cho ngi vn hnh my mc .Trong thit k ny & theo nhng tnh ton trn,dng chm v ti cc t ng lc v t phn phi chnh cng ln v tng tr gim.

III.3.3/ Ni t :

Ni t nhn to thng c thc hin bng cc thp , thanh thp dp hnh chnht hay hnh thp gc di t 2 n 3 m chn su xung t sao cho u trn ca chngcch mt t khong 0,5 n 0,7 m .

chng n mn kim loi , ng thp hay cc thanh thp c b dy khng cnh hn 4 mm, dy ni t khng c b hn 1/3 tit din dy pha, thng dng thpc tit din 120 mm2, nhm 35 mm2, ng 25 mm2

in tr ni t khng c ln hn cc tr s quy nh :i vi li in < 1000 V Rni t 4.Ni t lp li ca dy trung tnh :Rni t ll 10.

Ring vi cc thit b nh , cng sut tng ca my pht in , my bin pkhng qu 100 KVA cho php Rni t < 10.

(Ni t v chng st trang 146 [ HTCC NCH ] )* Tnh ton s cc t v in tr ni t :in tr ni t tiu chun R = 4 Dng thp gc L 60x60x6 chn su vo t cch mt t 0,5 m .Chiu di thp gc l = 2,5 m .Vng t tnh ton gi s c t = 100 m (PL 6.4 [ HTCC NCH ])H s hiu chnh l k = 1,4 khi chn su 0,5 0,8 m, t kh .

kng = 4,5 (PL 6.4 [ HTCC NCH ])in tr sut tnh ton vi in cc ngang v ng c tnh nh sau :

ttng = kng . t = 4,5 x 100 = 450 m tt = k . t = 1.4 x 100 = 140 m

in tr ca mt cc thng ng dng cho thp gc L60 di 2,5 m khi chn succh mt t 0,5 m c tnh theo cng thc :



45/47


R1 =

+

+lt

ltlg

d

llg

l

,tt

4

4

2

123660(8.2) [ HTCC NCH ]

T = 0,5 +2

l= 0,5 +

2

52.= 1,75 m

d ng tr = 0,95 b = 0,95 x 0,06 = 0,057 m

R1 = 42,295,275,1.4

5,275,1.4lg

2

1

057,0

5,2.2lg.140.

5,2

366,0=

+

+

Xc nh s b s cc ni t thng ng :Cc cc c chn thnh mch vng cch nhau a= 5 m, tra bng h s s dng

d cho cc ng l : d =0,69 (PL 6.7 [ HTCC NCH ])

S cc n = 114.69,0

42,29

.

1 ==dd

d

R

R

cc

Xc nh in tr ca thanh ni ngang (thp thanh 40 x 4 mm2 ) c hn utrn ca thp gc . H s s dng thanh ni ngang khi s in cc thng ng l 11 ccvi a/l = 2 ta c : ngang = 0,4

in tr ca thanh c chu vi vng L = n . a = 11 .5 = 55 m

Rng =tb

l

Lnttng

ngang .

2lg..

366,0.

1 2 (8.5),(8.6) [ HTCC NCH ]

Rng = 03,415,0.04,0

55.2lg.450.

55

366,0.

4,0

12

=

Tnh chnh xc in tr ca in cc thng ng :

R = 876,311.69,0

42,29

.

1 ==n

R

d

d

Xc nh in tr ca thit b ni t gm h thng cc v cc thanh ni nmngang :

54,303,41876,3

03,41.876,3.=

+=

+=

ngd

ngd

ndRR

RRR 4 (8.7) [ HTCC

NCH ] Nh vy thit b ni t theo thit k tha mn yu cu.



46/47


KT LUN n Thit k cung cp cho phn xng nh my bia yu cu phn phi cp in

cho mt khu vc nht nh ly t li quc gia & dng in p 22/ 0,4KV vi iu kin thct ca phn xng , da trn nn tng x nghip thit k sn.Qua vic thc hin n ny, em h thng ha, cng c nhng kin thc hc c .Hiur thm v cc qui tc, qui nh thit k trong cc sch tra c. Nhng thit k h thngcung cp in l mt bi ton kh .Mt ti d nh cng yu cu cn tng hp kin thc tnhiu chuyn ngnh hc nh : cung cp in, an ton, k thut cao p, thit b in ....Bncnh ,do em cha c c kinh nghim thit k nn tp n ny chc chn cn rt nhiuthiu st .Em rt mong c qu thy c gp , gip nhm nng cao kin thc trong tnglai.

TI LIU THAM KHO---*---

1 Hng dn n mn hc thit k cung cp in - tc gi Phan Th Thanh Bnh ,DngLan Hng, Phan Th Thu Vn .( Vit tt l [HDAMH -PTTB])2 Hng dn thit k cc thit b in theo tiu chun IEC. (Vit tt l [HDTKCTBTTCIEC] )3 An ton in tc gi Phan Th Thu Vn .( Vit tt l [AT PTTV] )4 - Nh my in & trm bin p - nhm tc gi:Trnh HngThm Nguyn H Khi , oQuang Thch , L Vn Ut , Phm Vn Ha , o Kim Hoa .5 Qui trnh Vn Hnh & Sa cha My Bin Ap ca Tng Cng ty in Lc Vit Nam6 H thng cung cp in ca x nghip cng nghip th v nh cao tng tc gi NguynCng Hin ,Nguyn Mnh Hoch .( Vit tt l [ HTCC NCH ] )



47/47


------------------------- ----------------------------

Đồ Án Cung Cấp Điện Nhà Máy Bia

Documents

Transcript of Đồ Án Cung Cấp Điện Nhà Máy Bia