diagrame de fases
4
1) V W Vt = 1 d Ῠ Vv = t Ῠ − d Ῠ d Ῠ ∗w Ῠ ∗ Sr A 0 Wt = t Ῠ Ῠ Vw = t Ῠ − d Ῠ d Ῠ ∗w Ῠ W Ww = t Ῠ − d Ῠ d Ῠ Vv Vs = ( w Ῠ ∗ Sr )(t Ῠ − d Ῠ ) d Ῠ ∗w Ῠ ∗ Sr S 1 Gs = Ws Vs . Ῠ w = ? Gs = 1 ( w Ῠ ∗ Sr ) ( t Ῠ − d Ῠ ) d Ῠ ∗ w Ῠ ∗ Sr .Ῠ w Gs = d Ῠ ∗ Sr ( w Ῠ ∗ Sr ) −( t Ῠ − d Ῠ ) d Ῠ = Ws Vt Vt = 1 d Ῠ t Ῠ = Wt Vt Wt = t Ῠ ∗VtWt = t Ῠ d Ῠ Sr = Vw Vv Vv = Vw Sr Vv = t Ῠ − d Ῠ d Ῠ ∗w Ῠ Sr Vv = t Ῠ − d Ῠ d Ῠ ∗w Ῠ ∗ Sr w Ῠ = Ww Vw Vw = t Ῠ − d Ῠ d Ῠ w Ῠ Vw = t Ῠ − d Ῠ d Ῠ ∗w Ῠ Ww = Wt = t Ῠ d Ῠ − 1 Ww = t Ῠ − d Ῠ d Ῠ Vs = 1 d Ῠ − t Ῠ − d Ῠ d Ῠ ∗ w Ῠ ∗ Sr Vs= ( w Ῠ ∗ Sr ) −( t Ῠ − d Ῠ ) d Ῠ ∗w Ῠ ∗ Sr
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como despejar y dejar en funcion las formulas de parametross conocidos
Transcript of diagrame de fases
1) V W
A0
W
VvS1
2)d=Gs= 2.71 = 2% - 15%Sr= 65%Sr= 75%Sr= 85%Sr= 100%
dddd
2,50122,52722,54822,5712
2,40932,44532,47332,5063
2,32342,36842,40342,4454
2,24352,29552,33752,3875
2,16862,22762,27562,3316
2,09872,16372,21672,2787
2,03282,10282,15982,2278
1,97192,04592,10692,1799
1,913101,991102,055102,13210
1,858111,939112,006112,08811
1,806121,890121,960122,04512
1,757131,844131,916132,00413
1,711141,800141,874141,96514
1,667151,757151,833151,92715
En la grfica se observa que entre ms saturada esta la muestra menor es su peso seco
1)
