Circuito 1

REQ1= R3 + R4 = 10K + 12K =22K

REQ2 = REQ1//R2 = (33K*22K)/55K = 13.2K

REQ3= REQ2 + R1 = 4.7K + 13.2K = 17.9KIREQ3 = 5V/17.9K =279.32mA. VR1= 279.32mA * 4.7k = 1.31 VVR2 =279.32mA *13.2k = 3.68 VIREQ1 = 3.68 V / 22K = 167.59 mA VR3 = 167.59 mA * 10K = 1.67 VVR4 =167.59 mA * 12K = 2VPor ley de Ohm se obtiene la corriente en cada ResistenciaIR1= 1.31V/4.7K=0.217mAIR2= 3.68V/33K=0.1114mAIR3= 1.67V/10K=0.167mAIR4= 2V/12K=0.166mA

Circuito 2

7V

7V

REQ1 = R5 + R6 = 1K + 4.7K = 5.7K

7V

REQ2 = REQ1 // R3 = 5.7K//33K = (33K*5.7K)/38.7K=4.86K7V

REQ3 = REQ2 + R4 = 4.86K + 56K = 60.86K

7V

REQ4= REQ3 // R2 = 60.86K//56K = (60.86K*56K)/116.86K=29.16K7V

REQ5 = REQ4 + R1 = 29.16K + 1K = 39.16KIREQ5=7V/39.16K = 178.75 mA VR1 = 178.75 mA * 10k = 1.7875 VVR2= 178.75 mA * 29.16k =5.21VIREQ3 = 5.21V / 60.86K = 85.64MaVR3 = VREQ1 = 85.64Ma *4.86k = 0.41VVR4= 85.64mA *56k = 4.8VIREQ1 = 0.41V / 5.7K = 73.025mAVR5= 73.025mA *1k = 73.025mVVR6 = 73.025mA * 4.7k =0.34 V

Por ley de Ohm se obtiene la corriente en cada ResistenciaIR1= 1.7875V/4.7K=0.38mAIR2= 5.21V/56K=0.093mAIR3= 0.41V/33K=0.0124mAIR4= 4.8V/56K=0.085mAIR5= 73.025mV/1K=0.073mAIR6= 73.025mV/4.7K=0.0155mA

Circuito 3Obteniendo las ecuaciones por medio de anlisis de mallas se obtiene:

I1 = 0.1731 AI2 = -0.0625 AI3 = -0.1114AVR1= 0.1731*1K = 0.1731VVR2 = (0.1731A + 0.0625A)12K = 2.82VVR3 = -0.0625A *33K =2.06VVR4 = (-0.0625 + 0.1114)100K =4.89VVR5= -0.1114 * 1K =0.1114V

Por ley de Ohm se obtiene la corriente en cada ResistenciaIR1= 0.1731V/1K=0.1731mAIR2= 2.82V/12K=0.235mAIR3= 2.06V/33K=0.0624mAIR4= 4.89V/100K=0.0489mAIR5= 0.1114V/1K=0.1114mA