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Transcript of Chuong 6- tin học xây dựng
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Phn II- Phn mm SAP2000
279
Chng 6 Bi tp ng dng
1. Kt cu h thanh
1.1. To lp dng hnh hc cho kt cu t th vin mu - bin i
S dng th vin mu ca SAP2000, ng dng thc hnh to lp mt s dng cc kt cu
sau: ( ch chn n v, chn mu , a vo gi tr
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ng dng Tin hc trong Thit k cng trnh
280
1.2. Cc bi tp thit lp v phn tch kt cu h thanh:
1.2.1. Tnh dm lin tc
- S liu : Vt liu b tng E= 2.5 E5 kg/cm2; Tit din : 35x25 cm
- Yu cu : Tnh chuyn v v ni lc ca dm chu cc ti trng nh trn hnh v.
1.2.2. Tnh dn phng 1
S liu :
- Vt liu thp: E= 2.1 E10 kg/m2 ; W= 7800 kg/m3
- Cc khoang dn c chiu rng 2.5m; chiu cao dn 1.5 m
- Tit din : cc thanh cnh v thanh xin u dn c tit din ng PIPE N1 (D= 10 cm ; t = 2 mm ); cc thanh bng cn li c tit din ng N2 ( D = 8cm, t = 2mm)
- Ti trng P1 = 60 KN; P2 = 80 KN
Yu cu : Tnh chuyn v v ni lc ca dn vi s liu
nh trn
1.2.3. Tnh dn phng 2
S liu :
- Vt liu thp ng trn E= 2.1 E10 kg/m2; W= 7800 kg/m3. H s poisson=0.2
- Tit din : 3 t di x ngang & thanh cho di ca x ngang c : D= 15 cm, t =2 mm
- Cc thanh ging ca x ngang v 4 t trn c D= 10cm, t = 1 mm
- Ti trng ngang H= 30 KN ; TT ng V= 60 KN ti hai u dn.
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Phn II- Phn mm SAP2000
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- Lin kt khp chn ct.
Yu cu :Tnh chuyn v v ni lc ca dn cho 2 trng hp ti trng:
- TH1 : ch chu ti trng bn thn, h s 1.2.
- TH2 : ch chu ti trng tp trung ti 2 nt nh dn.
1.2.4. Tnh khung phng 1
S liu :
- Vt liu b tng E =2.5 x 10 5 kg/cm 2 ; W= 2500 kg/m3
- Cc ct c tit din 40x30 cm ; dm c tit din 30x40 cm ; thanh xin trn D= 20cm
- Ti trng: q1 = 400kg/m ; q2 = 200kg/m ; P = 2000 kg ; q3= 150 kg/m.
- Lin kt ngm cc chn ct .
Yu cu :
- Xc nh ni lc ca khung cho 2 trng hp ti trng :
- Trng hp 1 : ch chu ti trng bn thn vi h s 1.1
- Trng hp 2 : ch chu cc ti trng nh trong hnh v.
1.2.5. Tnh khung phng 2
S liu :
- Vt liu b tng E= 2.5 E5 kg/cm2 W= 2.4 T/m3 M= 0.24
- Tit din :
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ng dng Tin hc trong Thit k cng trnh
282
+ Ct ngoi : 35x25 cm ; Ct trong 45x25 cm
+ Dm chnh : 50x 25 cm ; Dm cnxn 30x 25cm
- Ti trng : khai bo 4 trng hp (theo dng ti trng trn hnh v ng vi cc ti trng cho tng trng hp sau ):
+ TH1 : ch chu ti trng bn thn
+ TH2 : chu cc ti trng q1, q2,q3, q6, q7
+ TH3 : chu cc ti trng q4, q5, P1, P2
+ TH4 : Gi tri theo phng X 3 tng di c gi tr q6, 2 tng trn c gi tr q7.
- Lin kt ngm di cc chn ct.
Yu cu : Tnh chuyn v v ni lc ca khung cho 2 t hp ti trng
- T Hp1 : 0.9TH1 + 0.8TH2 + 0.8 TH3
- T Hp2 : TH2+ 0.75 TH4
- Tnh khung vi 4 dng dao ng ring.
1.2.6. Tnh khung khng gian 1
S liu :
- Vt liu b tng E= 2.5 E5 kg/cm2 W= 2.4 T/m3 M= 0.24
- Tit din : + Ct cc tng, vung : 40x40 cm ;
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Phn II- Phn mm SAP2000
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+ Ct ngoi khu 2 tng, trn c D=50 cm
+ Cc dm = 50x 25 cm
- Ti trng : khai bo 3 trng hp :
+ TH1 : chu ti trng phn b u trn tt c cc dm q1 = 1.2 T/m
+ TH2 : chu cc ti trng phn b trn dm ca mt s dm (t xp ti) vi q2=1.5 T/m cho tng 3 v tng 4 ; q3= 0.8T/m cho tng mi (tng 5) ; v q4= 1.2
T cho tng 2 v 3.
+ TH3 : chu cc ti trng gi trn cc dm v ct ln mt phng YZ bn tri theo phng +X vi q5= 0.6T/m.
Yu cu :
- Khai bo cc nhm v gn- GROUP ( ASSIGN )
+ G1 : gn cho tt c cc dm
+ G2 : gn cho tt c cc ct khu 5 tng
+ G3 : gn cho ct khu 2 tng
- Tnh chuyn v v ni lc ca khung cho 3 trng hp ti trng
- Khai bo 5 dng dao ng tnh theo phng php Ritz
- Xc nh din tch ct thp cho cc dm v ct trong cc trng hp trn.
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ng dng Tin hc trong Thit k cng trnh
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1.2.7. Tnh khung khng gian 2 - khung sn cng chu lc
Sn b tng ct thp dy 15cm cho khu 5 tng v 20cm cho khu 2 tng (ch mi sn phi chia nh cc phn t Shell v phn t dm, khu 5 tng mi sn chia thnh 4 phn t , khu 2 tng mi chia thnh 16 phn t ).Coi sn l tuyt i cng.
S khng gian Mt ng mt trc
S liu:
- Vt liu, n v cho E, W, M : kg - m
(Ch : AI c fy=2100 kg/cm2; AII c fy= 3000 kg/cm2; AIII c fy= 4000 kg/cm2 )
S liu Mc BT Thp dc Thp ai E W M
200 AIII AI 2.1E+09 2000 200
- Lin kt gia cc nt trong kt cu l cng
- Lin kt ni t l ngm.
- S liu hnh hc ( a, b, c, d : m ; b, h, t : cm )
+ Khong cch gia cc trc theo phng X l a, theo phng Y l b, chiu cao 3 tng l c, chiu cao tum l d. S liu :
a b c d C1
bxh
C2
bxh
B1
bxh
B2
bxh
B3
bxh
t
500 360 320 300 30x30 40x40 22x55 22x60 22x30 10
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Phn II- Phn mm SAP2000
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- Kt cu khung sn b tng ct thp :
- Cc ct bin c kch thc C1, ct gia C2
- Cc dm bin c kch thc B1, dm gia B2
- Cc ct, dm phn tum v dm cho mi B3
- Cc sn b tng chiu dy t, mi sn ch chia thnh 4 phn t. Cc mi dc khng
c phn t shell.
- Cc sn coi l tuyt l i cng, c quan h constraint vi nhau.
- S liu ti trng( kg - m )
Q1 Q2 Q3 Q4 Q5 Q6
1000 2000 500 200 450 150
Yu cu:
- Thit lp s kt cu vi cc s liu cho
- Khai bo cc trng hp ti trng v t hp :
+ Tnh ti (TT): Gm trng lng bn thn phn t (vi h s vt ti 1.05) v ti trng qui i ca cc tng ngn tc dng ln ton b cc dm bin c gi tr l Q1 kg/m, tc dng ln cc dm gia c gi tr l Q2 (kg/m).
+ Hot ti tnh ton sn (HT) : t ton b ln cc sn tng 2 v 3 l Q3, hot ti ln sn tng mi v tum l Q4 (kg/m2).
+ Ti trng gi thi theo phng +X (GX) ch tnh cho gi y l Q5 (kg/m), t gi n sn tng mi v t vo ct.
+ Ti trng gi theo phng ngang Y(GY) ch tnh cho gi ht l Q6 (kg/m), v t gi n sn tng mi, tc dng vo ct.
- Khai bo 4 t hp:
+ Tohop 1 =1.2TT+ HT ;
+ Tohop 2 = 1.4 TT+0.9HT+ 0.9GX;
+ Tohop 3 =TT+0.9HT+0.9GY;
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ng dng Tin hc trong Thit k cng trnh
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+ Tohop 4 (MAXMIN)= (TT, HT,Tohop3)
- Khai bo 3 group gm: nhm cho cc ct C1, nhm cho dm - B2 v nhm cho ton b dm, ct tng mi (khng k sn mi).
- Tnh chuyn v v ni lc ca mt trc khung kt cu, xut kt qu ra Excel.
- Khai bo 3 dng dao ng ring.
- Xc nh din tch ct thp cc phn t dm ct theo EUROCODE 2-1992. Hin kt qu tnh ln mt ca s lm vic ca SAP2000. Lp bo v dy 2cm cho tt c dm, ct.
- Tm gi tr lc dc ln nht ti chn ct.
- Tm gi tr t hp Mmen un ln nht ca phn t dm ca t hp 3.
1.2.8. Tnh khung khng gian 3 khung, sn b tng
Bng d liu : (n v: T,m)
a b c d D b1 b2 b3 h t P1 q1 q2 q3 g
4 4 3 4 0.4 0.25 0.3 0.22 0.45 0.12 1 1.2 0.8 0.5 0.6
S liu : (n v T-m)
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Phn II- Phn mm SAP2000
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- Vt liu : E= 2.1 E06 ; W= 2.5 ; m = 0.25 H s poisson = 0.2
- Kch thc hnh hc
+ a, b, c , d (m) : cc kch thc hnh hc ca khung : a,b,a rng cc nhp theo phng X v c,b,c l rng cc nhp theo phng Y, chiu cao cc tng l d.
+ Ct bin : ct trn k hiu C1 c ng knh D (cho c 4 tng)
+ Ct trong : ct vung k hiu C2 c kch thc b1xb1 (cho c 4 tng)
+ t : chiu dy cc tm sn ;
+ Kch thc dm tng 2 (b2 x h); dm tng 3 v 4 (b1 x h); Dm tng 5 (b3 x h)
+ Lin kt : ngm ti cc nt ni t.
g Tng 5 Mt ng
Tng 1
Yu cu :
- To lp s kt cu khung - sn theo d liu cho
- To 3 nhm ( group ) : N1 : mi phn t ca khung trc B, N2: dm tng 2 , N3: sn tng 4.
- Coi sn l tuyt i cng.
- Tnh kt cu vi 4 trng hp ti trng v 3 t hp:
+ Trng hp 1 TH1 : Chu ti trng bn thn h s 1.2 v ti trng tp trung P1
+ Trng hp 2- TH2 : Chu ti trng phn b q1 trn tt c cc dm ca tng 2 v tng 4
+ Trng hp 3 TH3 : Chu TT phn b u q2 trn 4 sn xung quanh ca tng 2 & 4, TT phn b q3 trn cc sn gia ca tng 3 v 5 .
d
d
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ng dng Tin hc trong Thit k cng trnh
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+ Trng hp 4 : Chu ti gi g theo phng X, thi vo mt phng YZ t tri qua phi ln cc ct .
- Cc t hp
+ T hp 1 : TH1 + 0.9 TH2
+ T hp 2 : TH1 + 0.9 TH2 + 0.8 TH3 + 0.7 TH4
+ T hp 3: MAXMIN( TH2 , TH3 , TH4)
- Tnh chuyn v v ni lc ca kt cu Kt qu cc dm a ra ti 4 v tr, ct ti 2 v tr .
- Xut kt qu chuyn v, ni lc ca t hp 2 cho 1 khung trc B ( trong mt phng XZ) ra file Excel ( *.xls ), ct trong cng th mc tp d liu.
- Tnh kt cu vi 4 dng dao ng ring. Tm gi tr v chu k, tn s dao ng ca dng dao ng 3.
1.2.9. Tnh khung khng gian 4
1 2 3 4 5
STT S liu hnh hc (m) Tit din (cm) TI trng (T; m)
L1 L2 L3 h Ct Dm q1 q2 q3 q4
2 4 1.8 5 3.9 30x30 25x50 1.3 0.5 0.24 0.075
S liu ( n v : tn, mt)
- Vt liu : Tn: BTM250; E = 2.65 x 106; W = 2.5, M = 0.25, m = 0.2.
- S liu hnh hc, tit din, tI trng cho nh bng.
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Phn II- Phn mm SAP2000
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- Cc trng hp ti trng: Tnh ti (TT); hot ti (HT); gi phong X (GIOX); gi phng Y ( GIOY)
- Ti trng:
+ Tnh ti : bao gm Ti trng bn thn, h s vt tI l 1.1;ti trng phn b u trn sn l q1, ti trng tng phn b u trn dm l q2 (tr dm mi)
+ Hot ti: q2 i vi sn tng 2,3,4; q4 i vi sn mi.
+ Khai bo ti trng gi tc dng ln cc ct: theo phng x l 0.8 T/m (GIOX); theo phng y l 0.6 T/m(GIOY); (ch khai bo phng gi y)
- T hp ti trng:
+ COMB1: TT + HT
+ COMB2: TT + 0.9 ( HT + GIOX)
+ COMB3: TT + 0.9 ( HT + GIOY)
+ COMB4: TT + 0.9 ( HT - GIOX)
+ COMB5: TT + 0.9 ( HT - GIOY)
+ COMB6: MAXMIN (COMB1, COMB2, COMB3, COMB5).
Yu cu :
- To s hnh hc, gn tit din, chia nh sn v dm nh hnh v, kt cu ngm ti t
- To Group KT3 bao gm cc phn t dm v ct trc 3. ( 0.5 im).
- Khai bo sn tuyt i cng
- Xut kt qu ni lc khung trc 3 ra exce ldm ti 4 tit din v ct ti 2 tit din, tm cc gi tr ni lc ln nht i vi dm v ct ( c th s dng filter trong excel tm)
- Tm 3 tn s dao ng u tin ca cng trnh.
1.2.10. Tnh kt cu vm, ct
S liu :
Tnh khung khng gian b tng ct - dm lin kt cng vi v cu (mi). Cu trc kt cu
c 8 ct trn (ct trn c c tit din thay i u) v dm bao quanh cc nh ct phi chia thnh 24 phn t.
- Vt liu : B tng c E= 2.6 E06 T / m2; W= 2.5 T/m3; m = 0.25 T/m3;
H s poisson =0.2
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ng dng Tin hc trong Thit k cng trnh
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- Cc kch thc:
+ a , b : cc kch thc hnh hc ca kt cu
+ n , m : s ct ca kt cu v s dm phi chia theo vnh ai trn trn nh ct
+ D1,D2 : ng knh chn v nh ct
+ Dm c tit din hnh vung chiu di mt cnh = ng knh nh ct (D2)
+ t : chiu dy ca v cu b tng.
- Ti trng :
+ Cc lc tp trung ti nt (T) : P1 t trn nh mi, P2 t ti u mt ct bt k theo phng ngang.
+ Ti trng phn b u trn mi theo phng - Z : q1 (T/m2 ).
+ Ti trng gi phn b hnh thang trn mt ct v tc dng ln mt na s ct ca kt cu, c hng theo phng ngang, c gi tr l q2, q3 (T/m) tng ng ti chn ct v nh ct.
- Lin kt : ngm ti cc chn ct .
- Bng d liu
n m a
(cm)
b
(cm)
D1
(cm)
D2
(cm)
t
(cm)
P1
(T)
P2
(T)
q1
(T-m)
q2
(T-m)
q3
(T-m)
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Phn II- Phn mm SAP2000
291
8 24 7 4.5 40 30 15 0.8 1 0.5 0.3 0.6
Yu cu :
- To lp s kt cu khung - v theo d liu cho ( 5.5 im ) .
- To 3 nhm ( group ) cho loi kt cu ct , dm , v mi ( 1.0 im )
- Khai bo 3 trng hp ti trng ( 1 im ); Gn cc ti trng cho cc trng hp ( 2 im )
+ Trng hp 1 : Ch chu ti trng bn thn h s 1.1
+ Trng hp 2 : Ch chu ti trng tp trung P1 , P2 v q1
+ Trng hp 3 : Ch chu ti trng gi q2, q3
- Khai bo 2 t hp ( 0.5 im )
+ T hp 1 : TH1 + 0.9 TH2
+ T hp 2 : 0.8 TH1 + 0.8 TH2 + 0.7 TH3
2. bi tp kt cu v
2.1.1. Tnh tm trn:
S liu :
- Dng hnh hc : Tm trn c ng knh 4m . (chia th v sau dng Mesh shell chia nh hn thnh 72 phn t ). Tm dy : 0.1 m c k n trng lng bn thn.
- Vt liu : b tng E=2.6E6 T/m2 , h s poisson 0.2 , W= 2.5 T/ m3
- Lin kt : tnh cho hai trng hp : ngm v khp xung quanh tm .
- Ti trng : phn b u trn c tm q=-1.5 T/m2 ; lc t ti tm tm Pz = -2.5 T
Yu cu : Tnh chuyn v v ni lc ca tm trong hai trng hp lin kt khc nhau.
2.1.2. Tnh v hm:
S liu :
- Vt liu b tng c E= 2.5 E6 T/ m2 ; H s Poisson =0.2 ; W = 2.5T/m3
- Kch thc : - Chiu cao vm 4 m Chiu rng vm: 7m
Chiu di ca c vm ng 10 m ; Bn knh vm : r = 4 m ;
Gc chn hai cung c hai vm 60o
Chiu dy ca c thnh v sn v t =20 cm
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ng dng Tin hc trong Thit k cng trnh
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Ti trng : ti trng phn b u ln c v l 1500 kgF/m2
Lin kt ngm chn thnh v
Yu cu : tnh cho hai trng hp ti trng :
+ Trng hp 1 : ch chu ti trng bn thn , h s 1.1
+ Trng hp 2 : Chu ti trng phn b u trn v
+ Tnh mt t hp cho c hai trng hp
3. Tnh dm, cc trn nn n hi
3.1.1. Tnh dm trn nn n hi.
S liu :
- Vt liu E= 1.0 E7 kN/m2 H s nn 60 000 kN/m3
- Cc c trng hnh hc : b rng dm 1m ; A= 1m;
I =0.0426 m4
- Dm coi nh ch chu cc l xo c phn lc theo phng thng ng ( c 1 thnh phn cng .
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- Dm chu cc ti trng nh trn hnh v .
Yu cu : Tnh chuyn v v ni lc ca dm .
3.1.2. Tnh cc
S liu :
- Cc c chiu di 38 m , chn trong t 25 m ;
- t nn:h s nn ca t : Ks = 32000 ( kN/m3 ) . Ti trng t ngang cc H
- Cc t trng hnh hc :E= 2.e7 kN/m2; I= 0.1m4 ; D=1.2 m ; A= 1.13m2
Yu cu : Tnh ni lc v chuyn v ca
dm 25
m13
m
H = 200 kN H = 200 kN
D
4. bi tp tng hp - S kt cu nh b tng khung sn vch hn hp 6 tng
4.1. S kt cu nh b tng khung sn vch hn hp 6 tng
- Mt bng mt tng ca kt cu :
6 m
1
.5m
3.5m
4m 4m 1m 4m 4m
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ng dng Tin hc trong Thit k cng trnh
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- Hnh dng khng gian ca nh 6 tng:
4.2. Cc s liu c th:
- Kt cu b tng ct thp c E=2.5E5 kGF/cm2 W= 2.4E-3 kG/cm3 M= 2.4E- 6 kGs/ cm2
- Kch thc hnh hc nh cho trn hnh v: chiu cao tng 1= 4m ; cc tng khc =3.6m
+ Dm : Dm D1 ti cc trc A,B, D D1 = 50x30 cm
Dm D2 ti cc trc C,1,6 D2 = 45x30 cm
Dm D3 ti cc trc 2,3,4,5 D3 = 40x30 cm
+ Ct: Ct ch nht C1 ti cc v tr nh trong mt bng C1 = 50x30 cm
Ct vung C2 ti cc v tr nh trong mt bng C2 = 45x45 cm
- Sn b tng c chiu dy 15cm : (mi tm sn phi chia t nht thnh 4 phn t)
- Vch dy 10cm : cng phi chia thnh 4 tm ( cc dm ,ct phi chia tng ng )
- Trng hp Ti trng : 5 trng hp
+ Trng hp 1 : chu ti trng bn thn + ti trng tng qui i thnh phn b u trn cc dm: cc dm D1 v D2 l 500kGF/m ; dm D3 l 300 kGF/m
+ Trng hp 2 : Hot ti sn - phn b u trn din tch mi sn = 600 kGF/ m2
4
3.
6
3.6
3.
6
3.6
3
.6
1m
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+ Trng hp 3 : Hot ti sn - phn b trn mt s sn bn phi = 1000kGF/ m2 ( tu chn )
+ Trng hp 4 : Ti trng gi phn b theo phng X trn mt phng YZ tri ( ch tc dng ln cc ct ) vi gi tr =300kGF/m ( tng 1+2) ; 400 kGF/m ( tng 3+4) v 500kGF/m(tng 5+6)
+ Trng hp 5 : Ti trng tp trung ti 2 nt trn nh vch P=1200kGF
- T hp ti trng: 3 t hp :
+ T hp 1 : trng hp 1 +0.9 trng hp 3
+ T hp 2 : trng hp 1 + 0.85 trng hp 2 + 0.9gi( TH4)
+ T hp 3 : trng hp 1 + trng hp 5
- Lin kt ngm ti cc chn ct
4.3. Yu cu tnh ton:
- Thit lp s kt cu vi cc d liu cho
- Tnh ni lc v chuyn v cho 3 t hp ( ct cho kt qu ti 2 im, dm tnh KQ ti 3 im)
- Tnh dao ng ring ca kt cu, tm dng c tn s thp nht ( khi lng do SAP t qui i)
- Xem cc kt qu trn ho v tp vn bn
- T chc mt file bo co xut ra Microsoft Word bao gm cc phn sau : ( d liu xut l d liu vo& kt qu ca cc phn t thanh trong Khung XZ -trc D, phn t v
trong sn tng1)
Cc dng tiu : BAI TAP KHUNG - SAN - VACH
M t cc thng s c nhn ca ngi thc hin : Tn - Lp- M s sinh vin - Kha .
. .
Tiu : DU LIEU VAO
Mt s bng d liu vo : To nt , Phn t thanh ,ti trng ca trng hp 3
Hnh v s kt cu
Tiu : KET QUA
Mt s bng kt qu : Chuyn v, Ni lc thanh
Hnh v biu mmen ca t hp1 ; biu ng sut S11 ca t hp 2.
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ng dng Tin hc trong Thit k cng trnh
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4.4. Hng dn cc bc lm qua cc hnh v minh ha:
- Dng h ta d cc to ra mt h li c cc phng X,Y nh s mt bng hnh 6.1, c 1 khong li theo phng Z vi cao l 3.6m.
Hnh 6.1
- Trn h li to, v khung mt tng nh hnh 6.2, ch dc hnh lang gia khng c dm ngang. gn phn t sn khp vi dm, ti sn ln nht v mt dm 4m,
v mt dm 1m.
Hnh 6.2
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- V cc ct ca khung trong mt phng XZ v YZ da theo hnh 6.3.
- Theo cc s liu cho gn tit din cho cc dm v ct.
Hnh 6.3
- Da theo s khung, v cc phn t sn trong tng , sau dng Mesh Shell chia cc sn thnh 4 hoc 2 phn t sao cho cc im nt l lin tc gia sn v dm (hnh 6.4) . Ti cu thang my khng c sn (thng).
- Chuyn v cc mt phng YZ v cc vch cu thang, ch phn ca khng c vch ( trng) dng Mesh Shell chia nh. Hai vch to chia thnh 4 phn t, cn vch nh pha sau chia thnh 2 phn t.
- Chia i cc dm ti nhng ni tm c chia nh dm v sn lm vic ng thi.
- Gn tit din cho sn v vch.
Hnh 6.4
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ng dng Tin hc trong Thit k cng trnh
298
- Sau khi hon chnh khung sn mt tng (v kch thc, tit din) dng lnh Replicate Linear sao chp tng ny thnh khung 6 tng nh hnh 6.5 .
- Dng chc nng Edit Grid di chuyn dng li ti Z=0m thnh -0.4m ( tng mt tr thnh cao 4m, cc tng khc vn gi nguyn 3.6m) .
- nh du cc nt lin kt ni t, gn lin kt ngm.
Hnh 6.5
- kim tra li m hnh kt cu 3D dng chc nng hin 3D (Extrude) nh hnh 6.6 (tri) v di chuyn li theo mt phng YZ ti v tr X=0.75m hin hnh 6.6 (phi).
Hnh 6.6
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Phn II- Phn mm SAP2000
299
- Gn ti trng phn b u cho cc phn t thanh dm D1, D2, D3 cho trng hp 1 nh u bi yu cu (hnh 6.7 tri), v ti trng gi cho trng hp 4( hnh 6.7 phi).
Hnh 6.7
- Gn ti trng cho cc sn trng hp 2 v 3 nh hnh 6.8 ( cng gi tr c th hin qua cc mu )
Hnh 6.8
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ng dng Tin hc trong Thit k cng trnh
300
- Gn ti trng ti nt hai u cu thang my ca tng 6 nh hnh 6.9
Hnh 6.9
- Hon chnh vic khai bo cc trng hp ti trng (4) v t hp ti trng(3), ch ct d liu qua tng giai on.
- Khai bo 6 dng dao ng.
- Vo Analysis thc hin phn tch ( RUN )
- Trn hnh 6.10 l chuyn v ca kt cu cho trng hp 1 ( tnh ti DEAD) v trng hp 4 (gi WIND). Biu hin c dng kt cu khi cha bin dng v chuyn v do
ti trng.
Hnh 6.10
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Phn II- Phn mm SAP2000
301
- Trn hnh 6.11 tri l biu M33 phn t thanh ca t hp 2 v biu M11 ca phn t Shell cho trng hp2 hnh 6.11 phi.
Hnh 6.11
- Tng ng trn hnh 6.12 l biu ng sut S11 cho t hp 2 v biu hp lc F11cho t hp 3 ca phn t Shell, c dng ng ng sut theo di mu.
Hnh 6.12
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ng dng Tin hc trong Thit k cng trnh
302
- S dng cc chc nng hin nh hin mt phng XY, dng Limit chn ring c cu thang my, hin cc biu ng sut nh hnh 6.13.
Hnh 6.13
- lm bo co vo chc nng File Report nhp tiu , a vo cc d liu ca bng, cc biu ( tham kho chng 3 phn cu trc bng ca SAP2000 ).
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