Ch 5 Quantum Theory

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    1

    Quantum Theory and theElectronic Structure of Atoms

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    Atom interact through their outer parts, their

    electrons.

    The arrangement of electrons in atoms are

    referred to as their electronic structure.

    Electron structure relates to:

    Number of electrons an atom possess.

    Where they are located.

    What energies they possess.

    Electronic Structure

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    Properties of Waves

    Wavelength(l) is the distance between identical

    points on successive waves.

    Ampl i tudeis the vertical distance from themidline of a wave to the peak or trough.

    Frequency(n) is the number of waves that pass

    through a particular point in 1 second (Hz = 1cycle/s).

    The speed (u) of the wave = l x n

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    Identifying l and n

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    The Electromagnetic Spectrum

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    l

    n

    7

    l x n = cl = c/nl = 3.00 x 108 m/s/ 6.0 x 104 Hz

    l = 5.0 x 103 m

    A photon has a frequency

    of 6.0 x 104 Hz. Convertthis frequency into

    wavelength (nm). Does

    this frequency fall in the

    visible region?

    l = 5.0 x 1012 nm

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    The yellow light given off by a sodium vapor

    lamp used for public lighting has a wavelength of

    589 nm. What is the frequency of this radiation?

    Class Guided Practice Problem

    ln=c A laser used to weld detached retinas produces

    radiation with a frequency of 4.69 x 1014 s-1.What is the wavelength of this radiation?

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    Planck: energy can only be absorbed or

    released from atoms in certain amounts chunks

    called quanta.

    The relationship between energy and frequency

    is

    where his Plancks constant (6.626 10-34 J.s).

    .

    Quantized Energy and Photons

    nhE=

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    Plancks theory revolutionized experimental

    observations.

    Einstein:

    Used plancks theory to explain the photoelectric

    effect.

    Assumed that light traveled in energy packets

    called photons. The energy of one photon:

    The Photoelectric Effect

    nhE=

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    Light has both:

    1. wave nature

    2. particle nature

    hn = KE + W

    Mystery #2, Photoelectric Effect

    Solved by Einstein in 1905

    Photonis a particle of light

    KE = hn - W

    hn

    KE e-

    where Wis the work function and

    depends how strongly electrons

    are held in the metal

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    E= h x n

    E= 6.63 x 10-34 (Js) x 3.00 x 10 8 (m/s) / 0.154 x 10-9 (m)

    E= 1.29 x 10 -15 J

    E= h x c / l

    When copper is bombarded with high-energy

    electrons, X rays are emitted. Calculate the energy(in joules) associated with the photons if the

    wavelength of the X rays is 0.154 nm.

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    Calculate the energy of a photon of yellow light

    whose wavelength is 589 nm.

    Class Guided Practice Problem

    nhE= (a)Calculate the smallest increment of energy (a

    quantum) that can be emitted or absorbed at a

    wavelength of 803 nm. (b) Calculate the energyof a photon of frequency 7.9 x 1014 s-1. (c) What

    frequency of radiation has photons of energy

    1.88 x 10-18 J? Now calculate the wavelength.

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    Line Spectra Radiation composed of only one wavelength is

    called monochromatic.

    Most common radiation sources that produce

    radiation containing many different wavelengths

    components, a spectrum.

    This rainbow of colors, containing light of all

    wavelengths, is called a continuous spectrum. Note that there are no dark spots on the

    continuous spectrum that would correspond to

    different lines.

    Line Spectra and the Bohr Model

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    Line Emission Spectrum of Hydrogen Atoms

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    Specific Wavelength Line Spectra

    When gases are placed under reduced pressure in a tube and

    a high voltage is applied, radiation at different wavelengths

    (colors) will be emitted.

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    Rutherford assumed the electrons orbited thenucleus analogous to planets around the sun.

    However, a charged particle moving in a circular

    path should lose energy.

    This means that the atom should be unstable

    according to Rutherfords theory.

    Bohr noted the line spectra of certain elements

    and assumed the electrons were confined to

    specific energy states. These were called orbits.

    Bohr Model

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    18

    1. e- can only have

    specific (quantized)

    energy values

    2. light is emitted as e-

    moves from one energy

    level to a lower energylevel

    Bohrs Model of the

    Atom (1913)

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    Colors from excited gases arise because electrons

    move between energy states in the atom.

    Line Spectra (Colors)

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    Since the energy states are quantized, the light

    emitted from excited atoms must be quantized

    and appear as line spectra.

    After lots of math, Bohr showed that

    where n is the principal quantum number (i.e., n =

    1, 2, 3, and nothing else).

    Line Spectra (Energy)

    =

    2

    18 1J1018.2

    n

    E

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    De Broglie (1924) reasoned

    that e- is both particle andwave.

    u = velocity of e-

    m = mass of e-

    2pr= nl l = hmu

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    Chemistry in Action: Electron Microscopy

    STM image of iron atoms

    on copper surface

    le = 0.004 nm

    Electron micrograph of a normal

    red blood cell and a sickled red

    blood cell from the same person

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    Schrdingerproposed an equation that contains

    both wave and particle terms.

    Solving the equation leads to wave functions.

    The wave function gives the shape of the

    electronic orbital.

    The square of the wave function, gives the

    probability of finding the electron, that is, gives

    the electron density for the atom.

    Quantum Mechanics and

    Atomic Orbitals

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    Electron Density Distribution

    Probability of finding an electron in a hydrogen

    atom in its ground state.

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    1. Principal Quantum Number, n

    the same as Bohrs n. As n becomeslarger, the atom becomes larger and

    the electron is further from the nucleus.

    (n= 1, 2, 3)

    Schrdingers Three Quantum

    Numbers

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    2. Azimuthal Quantum Number, l

    quantum number depends on the

    value of n. values oflbegin at 0 and increase to

    (n - 1). We usually use letters forl(s,

    p, dand fforl= 0, 1, 2, and 3).

    Usually we refer to the s,p, dand f-

    orbitals. (l= 0, 1, 2n-1).

    defines the shape of the orbitals.

    Schrdingers Three Quantum

    Numbers

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    3. Magnetic Quantum Number, ml

    quantum number depends on l.

    magnetic quantum number has integral

    values between -land +l.

    Magnetic quantum numbers give the3D orientation of each orbital in

    space. (m = -l0+1)

    Schrdingers Three Quantum

    Numbers

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    Orbitals and Quantum Numbers

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    Class Guided Practice Problem

    (a) For n = 4, what are the possible values ofl?

    (b) Forl= 2. What are the possible values of

    ml

    ? What are the representative orbital for the

    value oflin (a)?

    (c) How many possible values forland mlarethere when (d) n = 3; (b) n = 5?

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    All s-orbitals are spherical.

    As n increases, the s-orbitals get larger.

    As n increases, the number of nodes increase.

    A node is a region in space where the probability

    of finding an electron is zero.

    At a node, 2 = 0

    For an s-orbital, the number of nodes is (n - 1).

    Representations of Orbitals

    The s-Orbitals

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    The s-Orbitals

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    There are threep-orbitalspx,py, andpz.

    The threep-orbitals lie along thex-, y- and z-

    axes of a Cartesian system.

    The letters correspond to allowed values ofmlof

    -1, 0, and +1.

    The orbitals are dumbbell shaped.

    As n increases, thep-orbitals get larger.

    Allp-orbitals have a node at the nucleus.

    The p-Orbitals

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    The p-Orbitals

    Electron-distribution of a 2p

    orbital.

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    There are five dand seven f-orbitals.

    Three of the d-orbitals lie in a plane bisecting

    thex-, y- and z-axes.

    Two of the d-orbitals lie in a plane aligned along

    thex-, y- and z-axes.

    Four of the d-orbitals have four lobes each.

    One d-orbital has two lobes and a collar.

    The d and f-Orbitals

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    Orbitals can be ranked in terms of energy to

    yield an Aufbau diagram.

    As n increases, note that the spacing between

    energy levels becomes smaller.

    Orbitals of the same energy are said to bedegenerate.

    Orbitals and Quantum Numbers

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    Orbitals and Their Energies

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    Line spectra of many electron atoms show each

    line as a closely spaced pair of lines.

    Stern and Gerlach designed an experiment to

    determine why. A beam of atoms was passed through a slit and

    into a magnetic field and the atoms were then

    detected.

    Two spots were found: one with the electrons

    spinning in one direction and one with the

    electrons spinning in the opposite direction.

    Electron Spin and the Pauli

    Exclusion Principle

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    Electron Spin and the Pauli

    Exclusion Principle

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    Paramagneticunpaired electrons

    2p

    Diamagneticall electrons paired

    2p

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    Since electron spin is quantized, we define ms=

    spin quantum number = .

    Paulis Exclusions Principle: no two electrons

    can have the same set of 4 quantum numbers.

    Therefore, two electrons in the same orbitalmust have opposite spins.

    Electron Spin and the Pauli

    Exclusion Principle

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    Electron configurations tells us in which

    orbitals the electrons for an element are located.

    Three rules:

    electrons fill orbitals starting with lowest nand

    moving upwards;

    no two electrons can fill one orbital with the same

    spin (Pauli);

    for degenerate orbitals, electrons fill each orbital

    singly before any orbital gets a second electron

    (Hunds rule).

    Electron Configurations: Hunds Rule

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    Electron con f igurat ionis how

    the electrons are distributed

    among the various atomic orbitalsin an atom.

    1s1

    principal quantum

    numbern

    angular momentum

    quantum numberl

    number of electrons

    in the orbital or subshell

    Orbital diagram

    H

    1s1

    Order of orbitals (filling) in multi-electron atom

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    Order of orbitals (filling) in multi-electron atom

    1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s

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    What is the electron configuration of Mg?

    Mg 12 electrons

    1s < 2s < 2p < 3s < 3p < 4s

    1s22s22p63s2 2 + 2 + 6 + 2 = 12 electrons

    Abbreviated as [Ne]3s

    2

    [Ne] 1s

    2

    2s

    2

    2p

    6

    What are the possible quantum numbers for the last

    (outermost) electron in Cl?

    Cl 17 electrons 1s < 2s < 2p < 3s < 3p < 4s

    1s22s22p63s23p5 2 + 2 + 6 + 2 + 5 = 17 electrons

    Last electron added to 3p orbital

    n = 3 l= 1 ml= -1, 0, or +1 ms = or -

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    The periodic table can be used as a guide for

    electron configurations.

    The period number is the value ofn. Groups 1A and 2A (1 & 2) have the s-orbital

    filled.

    Groups 3A - 8A (13 - 18) have thep-orbital filled. Groups 3B - 2B (3 - 12) have the d-orbital filled.

    The lanthanides and actinides have the f-orbital

    filled.

    Electron Configurations and the

    Periodic Table

    Outermost subshell being filled with electrons

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    Outermost subshell being filled with electrons

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    Class Guided Practice Problem

    Write the electron configurations for the

    following atoms: (a) Cs and (b) Ni

    Write the electron configurations for the

    following atoms: (a) Se and (b) Pb

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    After Ar the dorbitals begin to fill.

    After the 3dorbitals are full, the 4p

    orbitals begins to fill. Transition metals: elements in

    which the delectrons are the

    valence electrons.

    Transition Metals

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    From Cs onwards the 4forbitals begin to fill.

    Note: La: [Xe]6s25d14f0

    Elements Ce - Lu have the 4forbitals filled and are

    called lanthanides orrare earth elements. Elements Th - Lr have the 5forbitals filled and are

    called actinides.

    Most actinides are not found in nature.

    Lanthanides and Actinides

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    Class Practice

    53

    Make condensed electronic configuration

    for all Representative elements

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    Paramagnetic

    unpaired electrons

    2p

    Diamagnetic

    all electrons paired

    2p