Ceramah Math Upsr
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Transcript of Ceramah Math Upsr
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MATHEMATICS TEACHER
FED UP
DISLIKE
HATE
SCARED
BORING
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CANDIDATES WEAKNESSES
UPSR Candidates Face :
1. Weak of the 4 basic operations
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IMPORTANT KEY WORDS
ADDITIONS
Plus
TotalSum
More than
AmountAltogether
After
Bigger
Jumlah
Hasil TambahLebih banyak
Kesemuanya
Selepas
Lebih besar
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IMPORTANT KEY WORDS
SUBTRACTION
Balance
BeforeTake away
Remaining
Less than
SmallerLeft
The rest
Reduce
Difference
Baki
SebelumDikeluarkan
Baki
Kurang daripada
Lebih kecil
Yang tinggal/baki
Selebihnya/baki
KurangkanBeza
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IMPORTANT KEY WORDS
MULTIPLICATIONTambah berulang
Multiply
TimesProduct
Total
(give one/each theanswer is more than
one)
Darab
KaliHasil darab
Jumlah
(Diberi satuTetapi jwp
Lebih drp satu)
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IMPORTANT KEY WORDS
DIVISION
Tolak berulang
DivideQuotient
Remainder
Share equally
distribution(Give more but
The answer
Each)
BahagiHasil bahagi
Baki dari proses bahagi
Kongsi bersama
diagihkan(Beri lebih ttp jwp untuk
Satu)
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Basic Operations1 9 + 7 =2 5 X 6 =3 18 9 =4 4 X 5 =5 24 6 =6 0 X 8 =7 13 9 =8 16 4 =9 8 + 5 =10 9 5 =
16309
204044
134
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Basic Operations11 30 6 =12 6 X 0 =13 32
8 =
14 0 + 9 =15 16 9 =16 7 X 8 =17 49 7 =18 9 + 7 =19 8 X 9 =20 17 8 =
5049756716729
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Basic Operations21 56 7 =22 8 X 5 =23 16 4 =24 9 + 4 =25 12 7 =26 7 X 6 =27 36 6 =28 8 + 3 =29 9 X 3 =30 17 9 =
8404
13542611278
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Basic Operations31 5 + 4 =32 4 X 6 =33 10 7 =34 4 X 9 =35 30 6 =36 3 X 8 =37 14 9 =38 45 9 =39 3 + 8 =40 11 6 =
9243
3654
55
115
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CANDIDATES WEAKNESSESUPSR Candidates Face :
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CANDIDATES WEAKNESSESUPSR Candidates Face :
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CANDIDATES WEAKNESSESUPSR Candidates Face :
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1 marks-5 questions
- + , - , x ,
- mental
calculation- accurate
answer
2 marks- 10 question
- working.
- accurated
questions- complete
calculation
3 marks
- 5 questions
- working
- more than 2
operations
- marks forevery step.
- accurate
answer
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NUMBERs Write number
Digit value
Place value Round off
Write number in word
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Nyatakan nilai digit bagi 5 dalam
nombor 45 306 ?
4 5 3 0 6othThTTh
50001 mark
State the digit value of5 in 45 306?2
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Tuliskan dalam perkataan bagi nombor :
30 580
thousands
Thirty Five hundred and eighty
Thirty thousands five hundred
and eighty
Write 30 580 in words.3
f 49 012
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Bundarkan 495 012 kepadapuluh ribuyang
terdekat
hth tth th h t o4 9 5 0 1 25 0 0 0 0 0
+1
1 mark
Round of 495 012 to the nearestten thousand.4
5
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5 Write seventy-three thousand andfifty in numerals.
Tulis angka bagi tujuh puluh tiga ribulima puluh.
oththtth
05037
1 mark
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BASIC OPERATIONS Addition
Multiply
Subtract Divide
1
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700 thousands + 65 hundreds + 85 tens=
700 000
6 500085+
707 350
1 mark
1
2
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108 x 40 =
108X 40
000
1 mark
432
4320
2
3
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5068 + 547 + 1542 =5068
5475615
+
3
5615+ 1542
7157
4
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6003 x 23 =
6003X 23
18009
1 mark
12006
138069
4
5
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5
83 407
1 mark
945 1 826=
83 407 945
82 462 =82 4621 826
80 636
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MIXED operation
Subtract and divide
Add and Subtract
Divide and multiply
( Add ) and divide Add and multiply
48 96 12
1
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48 + 96 12 =
9612 968
0096
48
+ 856
1 mark1 mark
1
2
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321 + 64 x 12 =
64
12x128
64768
321
768+1089
1 mark
1 mark
2
J=1098
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1 735 689 + 974
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1 735689 + 97 =
1 mark
4
1 735
689
2 1
6
61
401
1 046
+ 973
1
411
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FRACTIONS
Write in words
Multiply
Subtract
fractions
Fractions to
decimal number
Fractions line Addition
fractions
Equivalentfractions Fractions to
percentage
Diagram and
write in
simplest form
2 41
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12
5
4
5
=
7
5
4
5
=3
5
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1
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15
3
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Tukarkan kepada nombor bercampur15
7
1572
141 2
1
7
1 mark
Convert to a mixed number15
7
3
3
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15- 7
8- 7
1
= 2
1
7
3
4
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1
3
4
+
4
9 =
1 x 3
3 x 3 +
4
9 =
3
9 +
4
9 =
7
9
1 mark
1 mark
5
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5What is the fraction of the shaded region of the figure?
Berapakah pecahan kawasan berlorek daripada seluruh rajah ?
5
25=
1
5
1 mark 1 mark
6
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6
Write in word
3
8 =
Three over eight
Tiga per lapan
@1mark
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DECIMAL Subtract
Divide
Addition
Multiply
Decimal to % Decimal tofraction Mixed numberto decimal
1
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Tukarkan 0.057 kepada pecahan.
3 tempat perpuluhan
57
10001 mark
State 0.057 to fraction.1
2
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Tukarkan 0.04 kepada peratus.
2 tempat perpuluhan
1 mark
x 1004
100
= 4 %
Express 0.04 to percentage.2
3
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178 8273 =
1 7 8
- 8 2 7 3
0 07 9 10
725
10
9
1 mark1 mark
3
4
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4
0.427 7 =
04277
006
42
7
1
7000
1 mark
1 mark
6
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614
1
x 208802
41238
802
x+
2192
96 374 + 852 =7
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96374 + 852 =
1 mark
7
9 6
3 7 40
5 1
6
8 1
85
685
+ 58 2 060
1
1
1
9
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MONEY Money table
Diagram ofmoney and
problem solving
Addition Price listtable
Problemsolving andshopping list
1
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Money RM50 RM10 RM5 RM1 10 sen
Quantity 3 5 3 4 7
Total RM150 RM50 RM15 RM4 RM0.70
1 mark
atau
RM 219.70
RM 150.00RM 50.00RM 15.00RM 4.00
RM 0.70+1 mark
1
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3
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RM45.90
RM299
Berapakahperbezaanharga di antara dua
barangan di atas ?
RM 299.00- RM 45.90
RM 253 10
1 mark
1 mark
What is the difference in theprice of the two items ?
3
4
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RM855 sen + RM3.95 =
RM 8.00RM 0.55
RM 7.45
RM 7.45RM 3.95+
RM 11.40
1 markah 1 markah
4
5
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5Item Watch Hat
Price per unit RM59.60
Fuad bought a watch and 4
hats at the cost of RM93. What
is the cost of one hat?Fuad membeli seutas jam tangan dan
4 buah topi dengan jumlah harga RM93.
Berapakah harga bagi sebuah topi ?( RM 93.00 RM 59.60 ) 4 =
5
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( RM 93.00 RM 59.60 ) 4 =RM 93.00
RM 59.60RM 33.40
RM 33.40RM 8
32.
4
35
1
201 22 0
5
6
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6
RM50
1 mark
265 sen
RM50.00RM 2.65
549 9 0
3M4
7 Johan has RM84. Ahmads
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Johan has RM84. Ahmad s
money is of Johan money.4Calculate the total amount oftheir money.Johan ada RM84. Wang Ahmad adalah
daripada wang Johan.3
4Kirakan jumlah wang mereka.
7 Johan money RM84
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Johan money = RM84
Ahmad money
=
RM84
3
4Johan money
=3
4x
21
1
= RM63
TotalRM 84
+ RM 63RM147
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PERCENTAGE Value of percentage
Percentage to decimal Table and problem solving
Calculate percentage
1
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30% of 150 =30
100
150 = 45
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2
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Rajah terdir i daripada beberapa petak segi empat sama
yang sama besar. Berapakah bilangan petak yang
mewaki l i 40% dar ipada seluruh rajah itu ?
The diagram consits of squares of equalsize. How many of the squares represents40% of the whole diagram ?
2
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40 % = ?
40
100
X 15 =
5
2 3
1
6square
1 mark
1 mark
Shadedregion
Number of3
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village Perdana CarsX 6Y 14Z 5
Berapa peratuskah bilangan kereta perdana diKampung X, berbanding semua kereta perdana
di tiga kampung itu?
What is the percentage of the Perdanacars in the village X compared to all thePerdana cars in three villages ?
3
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6 x 100
6 + 14 + 5
=600
25 = 24%
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5 Diagram 9 consists of several
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squares of equal size .Rajah 9 terdir i daripada beberapa segiempat
sama yang sama besar.Calculate the percentage of
the coloured region of the
whole diagram.
Hitung peratusan kawasan
berwarna daripada seluruhrajah itu.
5 Percentage coloured region.
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g g
6 x 10015= 600151
0= 40%
6 Diagram 16 shows the volume of a
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barrel petrol.
Rajah 16 menunjukkan isipadu setong petrol.
Chin Seng menjual 70%
daripada petrol itu.Berapakah isipadu, dalam ,
petrol yang masih ada?
45l
Chin Seng sells 70% of
the petrol.
How much of the volume,in l, of petrol is left?
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AVERAGE Divide by 3 Total Volume of
liquid & divide 4
Find the valueof X , averagegiven
1
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HostelsNo. of
residents
P 50
Q 40
R
Bilangan penghuniasrama R adalah sama
dengan bilangan
penghuni asrama P danQ. H itungkan purata
bilangan penghuni
sebuah asrama.
The number of resident for hostel R is
the same as P and Q. Calculate theaverage number of residents for each
hostel.
Averagenumber of hostels residents
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Puratabil penghuni asrama
Hostel No. ofresidents
P 50
Q 40
R
Total P + Q= 90
90
50
40+ 90
180
180 3 = 60
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1 mark
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Number of bird in all the zoos =
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43 x 4 = 172 ekorNumber of bird X in Zoo P+Q+S =
7+93+13= 113
Number of bird X in zoo R =
172
113
59
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4
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Days Mondays Tuesday Wednesday
Numberof egg 78 125 91
Average
=78 + 125 + 91
3=
294
3
= 98
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35 i t3 hours
1
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30 minutes
4 hours 5 minutes
1 mark
3 hours
35 minutes3 hours
1 mark+
65 minutes
-60 minutes+ 1 hours
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4
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Convert 2235 hours tothe 12-hour system.Tukarkan Jam 2235 kepada
sistem 12 jam.
2235 1200
= 10.35 p.m.@
10 35 at nigh= 5
1
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Calculate 5 hours 15 minutes + hour.Write your answer in hours and minutes.
1
4
H itungkan 5 jam 15 minit + jam.
Ber ikan jawapan, dalam jam dan mini t.
1
4
1
4
hour
= 15 minutes
5 hours 15 minutes
+ 15 minutes30 minutes5 hours
3 Diagram 2 shows the time on aclock face in a morning.
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clock face in a morning.
Rajah 3 menunjukkan waktu pada sebuah muka jam
pada suatu pagi.
State the time shown on the clock face.
Nyatakan waktu yang ditunjukkan pada muka jam itu.
6
12
39
6.30 a.m.
@
0630 hours
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1812
Time training starts
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6
12
39
4.25 p.m.
Training takes90 minutes
Time training endhours minutes
4 25
+ 901154
- 60+ 1
555
5.55 p.m.
@
1755 hours
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1812
Time training starts
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6
12
39
4.25 p.m.
Training takes90 minutes
Time training endhours minutes
4 25
+ 901154
- 60+ 1
555
5.55 p.m.
@
1755 hours
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LENGTH Ruler (High of pupils)
Subtract(km m) Ruler(length of object)
Problem solving Addition
(km + m)
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of a piece of rope measur ing32
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dar ipada seutas tal i
yang panjangnya 20 meter
telah dipotong. Kirakan
panjang tali selepas dipotong.
3
5
ofa piece of rope measur ing
20 meter was cut. Calculate the length
of the rope after it was cut.
5
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24.6 km3
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P
Q
34
daripada PQ telah diturap.
Cari panjang jalan yangbelum diturap
dalam m ?
3
4
Of PQ had been paved.
Calculate the length, in m, of the
road that had not been paved
24.6 km = 24600 m
3
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24.6 km =24600 m
Unpaved =
x 24600m
1
6 1 5 0
= 6150 m
14
1
4
1 mark
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5 Calculate 2 m 7 cm 9 .
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72
3
7
Give the answer, in cm .Hitung 2 m 7 cm 9.
Ber ikan jawapan, dalam cm.
2 m= 200 cm
7 cm7 cm+
207 cm
207 cm92
182
00
cm
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MASS Weighing machine ( kg & g )
Subtract Problem solving Multiplication
Addition / Divide Diagram 1 shows the mass of a1
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Rajah 1 menunjukkan berat sebij i mangga.
Berapakah berat, dalam kg, mangga itu ?
mango. What is the mass, in kg, ofthe mango ?
Reading
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mass250 g
5=50 g
50 g
50 g 250 g50 g
+ 50 g350 g=0.350 kg
2
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H itungkan 305 kg500 g.
Nyatakan jawapan, dalam g.
Calculate 305 kg 500 g.State your answer, ing.
3.05 kg 500 g = ? g
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3050 g
500 g2550 g
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1
2
3
456
7
8
9 0
kg 1
23
4
0
kg
What is the difference of themass, in g, of the two fruits?Berapakah perbezaan berat, dalam g,
kedua-dua buah-buahan tersebut ?
3
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Mass of watermelon= 6.5 kg = 6 500 g
Mass of pineapple= 1.5 kg = 1 500 g
The difference6 500 g 1 500 g5 000 g
1 mark
1 mark
1 mark
4 Vijaya has 3.75 kg of flour.
Sh d 4 2 k f fl t
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She needs 4.2 kg of flour to
bake cakes.
Vijaya ada 3.75 kg tepung. Dia
memerlukan 4.2 kg tepung untuk
membuat kek.
How much more flour, in g,
does she need ?
Berapakah jisim tepung, dalam g, yang
diper lukan lagi?
4 Need flour = 4.2 kg
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Has flour= 3.75 kg
g
Need more flour in g4200 g
3750 g450 g @
4.2 kg 3.75 kg0
0.45 kg=450 g
VOLUME OF LIQUID
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Beaker problemsolving (ml)
Beaker ml / l Addition / Subtract Divide ml
Volume of water in a bottle is2
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Isipadu air dalam botol ialah 1.5 l.
daripadanya tumpah.
Berapakah baki isipadu air, dalam ml,dalam botol itu ?
2
5
1.5 l. of it split.
What is the volume, im ml, of
water left in the bottle ?
2
5
1
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1.5 ( l ) liter
1
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1.5 ( l ) liter
split = mlleft ?25
1500ml3
5
1500mlx
300= 900 ml
1 mark
1 mark
1 mark
8.4 lof water is poured2
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8 4 air dituang sama banyak ke
dalam 5 buah botol. Berapa isipaduair dalam , bagi setiap botol itu ?
equally into 5 bottles.
What is the volume, in l, of
a water in each bottle ?
2
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8.4 l51
53
.
4
6
3 0
4
0
0
8
40
l 1 mark
1 mark
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3
4
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4
5
x 1.85 l
= 1 850 ml
4
5
x 1 850 ml
=
370
1480 ml1
4 2 l
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1 l
The water in the beaker is poured
equally into 4 beakers.What is the volume of water, in ml, in
each beaker ?
Air di dalam bekas itu dituang samabanyak ke dalam 4 buah bekas lain.
Berapakah isi padu, dalam ml, setiap bekasitu ?
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SHAPE AND SPACE Draw
Naming
Characteristics of cuboid- number of vertices
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b)a)Namakan setiap bentuk berikut :
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b)a)
Piramid bertapak segiempat samaSegitiga bersudut tegak
1 markah1 markah
Right angled triangleSquarebased pyramid
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10 cm10 cm
10 cmEquilateral triangle
Segitiga sama sisi
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7 cm
squareSegiempat sama
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7 cm
rectangleSegiempat tepat
5 cm
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Berdasarkan gambarajah, namakan bahagian-
Base on the diagram, name the parts shown.
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Berdasarkan gambarajah, namakan bahagian
bahagian yang ditunjukkan.
Bulatan /Circle
Pusat Bulatan /Centerpoin t
Jejari /Radius
Diameter
PERIMETER
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Diagram Diagram
(composite shape)triangle and rectangle
P U
T
6 cm1
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Q R
T
S
5 cm
Dalam rajah 2, PQRU ialah segi empat sama. UTR
dan QRS ialah garislurus.Hitungkan perimeter
rajah itu ?
PQRU is a square. RST is an isosceles
triangle with sides, 3 cm. The perimeter of
the region is
P U6 cm
3 cm6 cm3 cm
1
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6 cm
Q R
T
S
3 cm
5 cm
3 cm
5 cm9 cm6 cm+
29 cm
1 mark1 mark
6 cm
3 cm
3 cm
P Q12 cmV
1
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9 cm
RS3 cm
TU
PQRS ialah segiempat tepat.
TUV segitiga sama sisi bersisi 8 cm.
Perimeter kawasan berwarna ialah
PQRS is a rectangle.
TUV is an equilateral triangle with sides 8 cm
The perimeter of the shaded region is ..
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3 Diagram 14 shows a combonition of atriangle PQU and a rectangle URST. PUTand UQR are straight line. PU = UT .
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Rajah 14 menunjukkan gabungan sebuah segitiga
PQU dan sebuah segiempat tepat URST. PUT dan
UQR ialah garis lurus. PU = UT.P
Q R
ST
5 cm3 cm
4 cm
U
10 cm
What is perimeter, in cm,of the whole diagram?
Berapakah
perimeter, dalam
cm, seluruh
rajah itu?
3 PU = TU
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P
Q R
ST
5 cm3 cm
4 cm
U
10 cm
3 cm 3 cm
6 cm
Perimeter =
3 cm3 cm
10 cm
3 cm6 cm5 cm+
30 cm
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A B10 cm1
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D7 cm
ABCE =(rectangle) Segiempat tepat
ADE =(right triangle) Segitiga bersuduttegak
Luas kawasan ber lorek ?
4 cm
CE
4 cm
Area of shaded region ?
Area of shadedregion = Area ABCD Area ADE
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= 10cmx 4 cm= 40 cm2Area ABCD
Area ADE=
7 cm x 4 cm
2 =
28 cm
2
= 14 cm2
Area ofshededregion
= 40 cm2 14 cm2
= 26 cm2
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MATEMATIK KERTAS 1
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MATEMATIK KERTAS 1
40 questions Time 1 hour (60 minutes) 90 second for 1question Questions are in English & Bahasa Melayu Objektive Answer options given A , B , C , D Covers all topics About 75% of the items are Creative andCritical Thinking Skills based
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IMPORTANT TOPICS
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2 & 3 Dimension Money Time & Duration Fractions Percentage Decimal An average 4questions for
every topic
1 50% = (in decimal)
21
5=X 60
0.512
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5
3 0.7 + 3 =4 0.25 kg = (in gram)
5 RM1.60 = (in sen)
6 4.30 p.m. = (24-hour system)
71
5= (in minutes)
8 0.6 l + 4 l =
9 1.4 x 10 =
10 180% =(pecahan
bercampur)
jam
3.7250160Jam 1630124.6 l @ 4600 ml141 80100@ 1
45
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Have targets and goals
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Be confident and proud
of yourself WHOLE NUMBERS
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Converting fraction or decimalsnumbers to whole numbers4operation
Problem solving / estimateNumber line
1. 305 million =3 05 j t
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305 juta =A 30 500
B 305 000C 3 050 000
D 30 500 000
Million7 digit
Answer 2 1.005 mil = 1 005 000
3
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A 3 465 000
B 3 355 000
C 2 785 000
D 2 676 000
3
4mil = 750 000
0.21 mil = 210 000
12
mil1 = 1 500 000 +
5 0006
A
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Nearest hundred thounsands7 400 000
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7 400 000
A 7 459 271
00 000
+ 1
7 5
X B 7 452 70400 000
+ 1
7 5
X
C 7 354 301
00 000
+ 1
7 4 C
6. From the followingmultiplication, which one
i th l b t
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gives the value between
50 000 and 55 000 ?
A 680 x 80B 700 x 70C 760 x 60D 800 x 50
680X 800
654A
7. 12
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6090380A 11280Remainder 8B 11280Remainder 38C 12180Remainder 8D 12180
50109100 xxD
8 + 705.38 = 1 02510
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A 319.62B 320.38C 324.62D 1 730.38
1025.00
705.38
x
4 9 10
2x 6.
10
9
Answer A
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MIXED OPERATION
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1. Mains skills
BODMAS RULE
a. If there is a ( ), solve the numbers inthe bracket first
b. ( + followed - @ - followed +, solve fromleft to right )
c. ( + followed x @ + followed , solve xorfirst )
d. ( - followed x @ - followed , solve xor first )
2. Problem solving follow the sentencesgiven
10 5 000 107 x 23 =
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A 2 539B 3 461C 112 539D 117 461
107
X 232114
5000
2461
- 2461XX 9
FRACTION
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Proper fractions Equivalent fractions and
state in simplest form
Find a commondenominator ( for + & -operations )
Convert to decimal orpercentage
Fraction with quantity
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12. 7 2 4 1 =7 4 4 7
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7 2
2 31421114
3 314311
14 14=3 414 714 =21814 714xx
=21114B
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Always bealert and thenwait. Perhaps
what you'relooking for,
will find you...
131
22
1
y
14
15
16 2 2
22
3
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12
3
21
6
2
1
6A
213
B
2
1
2C
223
D
14
6
15
6
16
6
2 22
6
23
6
236
= 212
C
14. 4180X Y 4210
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35 of the total ofXandYisY(4210 4180) 2= 30 2 = 15
= 4180 + 15= 4195
X
4180 (15 x 4 )=4180 60= 4120A 4120 C 4989x
1315
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Diagram 2 consists of several equailateral triangles ofequal size.Cikgu Azlan ask Maziana to shade of the wholediagram.
How many more equailateral triangles should she shade ?
A 7B 8C 9D 10
3
4
57
15
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Shade =34 x 16 = 12
Have shade = 512
57 A
DECIMALS
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Converting fractions or
percentage to decimal.
Place value in decimals.
Operations with decimals
numbers
Number up to 3 decimals
place.
Ex : 2.08 + 14 - 7.495 =
16
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11.200+ 17.075A 27.071B 23.415C 23.135
28.27528.275
5.1405xx
3
C
17 617
1000
4
1004 =
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1000 100
A 2.13
B 2.013C 1.977
D 1.617
6.0174.040X
7
X5 9 10
7
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2010
14
5.024 + 115
1000
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A 6.354
B 6 376
C 6.249
D 6.241
10.250
- 5.0245.226
5.226
+ 1.0151
D
21 903 %
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A 9.3B 9.03C 0.93D 0.903903100 = 9.03
B
TIME & DURATION
1. 24 hour system :
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- before ( - )- after ( + )2. Conversion of unit of time- hour minute second
( x 60 @ 60 )3. Calendar / age- Month week day- Year month4. Diagram analog clock5. Problem solving
22 hours + 3 hours 50 minutes =910
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jam + 3 jam 50 minit =910
A 3 jam 59 minit
B 4 jam 4 minit
C 4 jam 40 minitD 4 jam 44 minit
22 jam + 3 jam 50 minit =910
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A 3 jam 59 minitB 4 jam 4 minit
C 4 jam 40 minitD 4 jam 44 minit
j m
3 50
54+1043
x60 -+ 1
44
23. Diagram 3 shows the timeEncik Halim returned from
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the night market.
1 hour 25 minutes later,he watched television.
State the time, in the 24-
hour system, he started towatch television.
23. Returned from the night market.11.15 pm = 2315 hrs
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1 hour 25 minuteslater
watch tvhours minutes
23 15
+ 1 25 +4024
A 0040 hrsB 0950 hrsC 1240 hrsD 2150 hrs 24 00
00 40
A-
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Don't letthe situation
confuse you...
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25 4 l 75 ml1
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+ 195 ml
A 4270 mlB 4345 mlC 4750 mlD 6700 ml
4000 ml +
x0x 7
A
26 7 l 70 ml + 4 l140 ml =
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A 11.084 lB 11.11 lC 11.21 lD 11.84 l
7.070 l+ 4.140 l0
x1
x
1
2
25 ml +027l + 4l15ml +755ml= .... l27
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0.025 l0.270 l4.015 l0.755 l5.065 l C
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293
0.750 l=
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0.750 l3
8 750ml
Left
83
8
=5
8
3
8= 750ml
1
8= 250ml
= 250x5 = 1250ml
DA 1.25B 2.5
C 125
D 125O
XX
MASS
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Main Skills :
- Conversion of units ( multiply ÷ )
kg g = x 1000
g kg = 1000
- Involving four operation
- Very good at reading graduation( senggat ) & weighing machine
30 Convert 6kg 25g to kg.6 kg = 6000 g
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6 kg
+ 25 g
= 6000 g
6000 g
6025 g
A 62.5
B 6.25
C 6.025
D 0.625
6025 g
= 6.025 kg
Cx
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Always look at where you'regoing...
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31. Which of the following is theheaviest ?Antara ber ikut, yang manakah paling
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Antara ber ikut, yang manakah paling
berat ?
A 5
1
2 kg
B 5
1
4 kg
C 5
3
5 kg
D 5
3
10kg
A 51
2kg = 5 500 g
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B 5 14
kg
C 5 35
kg
D 5 310
kg
= 5 250 g= 5 600 g
= 5 300 g Answer
321325 g = 1.325 kg
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0000
0.120
1.325+ 1.445
1.44520x
A 28.9
B 26.74
C 26.62
D 26.592
28900
28.900
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33. Mr. Rajesh sold 24 papayas toPuan Rohaya. The mass ofone papaya is between 340 g
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to 650 g.Estimate in kg, the mass of allthe papayas bought by PuanRohaya.
Encik Rajesh menjual 24 bij i buah betik kepada Puan
Rohaya. Berat sebij i buah betik adalah di antara 340 ghingga 650 g.
Anggarkan berat, dalam kg, semua buah betik yang dibeli
oleh Puan Rohaya.
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34 35 m 8 cm 4
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A 8.77 cmB 87.7 cmC 877 cmD 8770 cm
3500 35088323xx C
35. Ironrod Lenght Lengthcm
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K 3700 mmL 360 cmM 3.8 mN 3.09 mK B L
C M D N
Which rod is theshortest ?
370360380309
D
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37AX BX
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0.12 kg
= 120 g
2l24ml
= 2.024l
C
2000 cm
= 20m = 0.02km
C
38
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760 m = 0.760 km+ 4.990 km
A 5 650
B 5 750
C 5.65
D 5.75
x
50 km7D
47kmPerpustakaan
Rumah En. Mail39
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850m
195km3km 250 m
Hospital
Pejabat Pos
1.95 km3.25 km0.85 km4.70 km
10.75 kmB
MONEY
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Mains Skills- Value of RM and sen, andconversion of units- Involving quantity, number ofobjects and total- The four operations & quantity- Calculation involving fractions &percentage- Selling & buying concept & profitand loss
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Kuantiti Alat Tulis Harga
seunit RM
Harga
RM
10 biji Pemadam 12.00.2041
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Kuantiti Alat Tulis Hargaseunit RM
HargaRM
4 btg Pen 1.60
3 kotak Warna Air
5 kotak Pensil 3.00 15.00
Jumlah 46.90
10 kotak PensilWarna
Jumlah 97.00
6.4025.50.50
8.50 85.00
AX
X
2 & 3 DIMENSIONAL SHAPE
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Main Skills- Characteristics 2-D and 3-D.
- Able to use formula of area,perimeter & volume
- Calculation of area, perimeter &volume from diagram
- Conversion of units andmeasurements
42
B D
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A C
Diagram 1 is drawn on
squares of equal size.
Among triangles A, B, C, and D,which one has the same base ?
43Vertex /Bucu 5
Flat surface / Permukaan rata 5
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Flat surface /Permukaan rata 5
A Pyramid
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44 Perimeter shadedregion = 28 cm1 side 28= = 4 cm
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A 72B 68
C 64D 60
7Perimeterunshaded region= 4 cm x 18
= 72 cmA
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45. X 180 Y 255 175
Total X + Y
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A 610B 465 C 310D 155
= 215 x 5= 1075
= 1075 (180+255+175)= 1075 610 = 465
xx
Y = 2X Y = 465 3= 155
D
46.Ain 84
Ilyani
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Zuidayana
849
= 75
75 + 15= 90Average84 + 75 + 90
3= 83 B
47 Sabrie = 900Haziq = 900150 = 750
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q 750
3 = 800 x 3 = 2400
Average = 900+750+24005
= 40505
= 810 A
48 TAJ = 524
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TS = 524 48 = 476Total
524
+ 4761000
10000
x 2020000
C
DATA HANDLING
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Main Skills- Skilful reading information &
pictograph
- Skilful with the four operations- Skilful at making comparison
and adding
- Skilful at finding informationand average
49 Malay English Science
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Mathematics Represents 15 minutes
The school holiday was1 week.How much time did Mohamad Azim
spend to study during the holidays?
49
Malay 15 x 5 = 75m
A 40h 15mB 38h 15m C 28h 45mD 27h 25m A
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English Science
Math Represents 15 minutes
75m
15 x 7 =105m
15 x 5 = 75m
15 x 6 = 90m
345m
+Total
One week= 7 days
Total345 X 7= 60 =
241560
= 40 hrs
50 One pipe = 5.5mTotal pipes
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P = 16Q = 20
R = 10S = 22
To = 68
x
5.5m
680
4400
33000
374.00 =
0.374 km
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CITA-CITA ANDA
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14A!
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10 A!
17A!
18A!
18A!17A!
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10A! 17A!
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17A!
18A!
17A!
18A!
14A!
,2007
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NewS
traitsTimesTue
sday,March13
,
18A!
15A!
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MURID YANG ..
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Dreamwhat you want to dream;
Go where you want to go;
Be what you want to be,
Because you have only one lifeand one chance to do all the things
you want to do.
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49 61
50 63
51 64
57 71
58 73
59 74
65 81
66 83
67 84
73 91
74 93
75 94
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51 64
52 65
53 6654 68
55 69
59 74
60 75
61 7662 78
63 79
67 84
68 85
69 8670 88
71 89
75 94
76 95
77 9678 98
79 99