Professor Dionisio Sá

Professor Dionisio Sá

1

1

– 1

– 1

seno

cosseno O

P

B

C

tg

Professor Dionisio Sá

1

1

– 1

– 1

seno

cosseno O

P

B

C

x

s𝑒𝑛 (𝜋 − 𝑥) = 𝑠𝑒𝑛 𝑥

𝑐𝑜𝑠(𝜋 − 𝑥) = −𝑐𝑜𝑠𝑥

𝑡𝑔 𝜋 − 𝑥 = −𝑡𝑔 𝑥

tg

x

Professor Dionisio Sá

1

1

– 1

– 1

seno

cosseno O

P

B

C

x

s𝑒𝑛 (𝜋 + 𝑥) = −𝑠𝑒𝑛𝑥 𝑐𝑜𝑠 (𝜋 + 𝑥) = − cos 𝑥

𝑡𝑔 𝜋 + 𝑥 = 𝑡𝑔 𝑥

tg

x

Professor Dionisio Sá

1

1

– 1

– 1

seno

cosseno O

P

B

C

x

s𝑒𝑛 (2𝜋 − 𝑥) = −𝑠𝑒𝑛𝑥

𝑐𝑜𝑠 (2𝜋 − 𝑥) = 𝑐𝑜𝑠𝑥

𝑡𝑔 2𝜋 − 𝑥 = −𝑡𝑔𝑥

tg

x

Professor Dionisio Sá

s𝒆𝒄 𝒙 =𝟏

𝐜𝐨𝐬 𝒙

𝒄𝒐𝒔𝒆𝒄 𝒙 =𝟏

𝒔𝒆𝒏 𝒙

𝒄𝒐𝒕𝒈 𝒙 =𝟏

𝒕𝒈 𝒙

Professor Dionisio Sá

𝐷𝑒𝑡𝑒𝑟𝑚𝑖𝑛𝑒 𝑜 𝑣𝑎𝑙𝑜𝑟 𝑛𝑢𝑚é𝑟𝑖𝑐𝑜 𝑑𝑒

𝐴 =𝑠𝑒𝑛 2820° ∙ 𝑐𝑜𝑠1830°

𝑡𝑔1665°

Professor Dionisio Sá

𝐷𝑒𝑡𝑒𝑟𝑚𝑖𝑛𝑒 𝑜 𝑣𝑎𝑙𝑜𝑟 𝑑𝑒

𝐴 =cos 2𝑥 − 𝑠𝑒𝑛

94

𝑥

𝑠𝑒𝑛𝑥2

− 𝑐𝑜𝑠94

𝑥

𝑐𝑜𝑚 𝑥 =𝜋

3𝑟𝑎𝑑

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