13-1662 Acadian Contractors - PV-14923A - 09-17-2013
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Transcript of 13-1662 Acadian Contractors - PV-14923A - 09-17-2013
SRC ENGINEERS, INC.
P.O. BOX 81903 LAFAYETTE, LA 70598-1903 (337) 837-3810 Fax (337) 837-5710
100 CARDINAL DRIVE LAFAYETTE, LA 70508-4449 srcengineers.com
Report Date:
CUSTOMER
ACADIAN CONTRACTORSAbbeville, Louisiana
VESSEL DESCRIPTION
Enterprise - Neptune Plant
Air Eliminator - PV-14923A
24" OD x 6'-0" S/S x 275 PSIG x 100°F
Drawing Number:
ASME Code Stamped: Yes
Vessel designed per the ASME Boiler & Pressure Vessel Code,
Section VIII, Division I, 2010 Edition, A11 Addenda
SRC JOB NUMBER
13-1662
NAMEPLATE INFORMATION
MAWP: PSI @ °F Serial Number:
MDMT: °F @ PSI National Board Number:
Year built: 2013 Postweld heat treatment:
Radiography: RT-1 Lethal Service:
Engineer: Date:
Q.C. Manager: Date:
275 100 13-150
-20 275
N/A
Non-Lethal
9/17/2013
09/17/13
111-825
Dennis Kohl P.E.
Acadian Contractors, Inc
17102 West LA HWY 330
Abbeville, LA 70510
ASME Calculations (275psig@100F)
Item: Air EliminatorVessel No: PV-14923ACustomer: Enterprise - Neptune PlantDesigner: Brett Hebert
Date: Monday, August 05, 2013
Revision History
No. Date Operator Notes
0 8/ 1/2013 bretth New vessel created ASME Section VIII Division 1 [COMPRESS Build 7110]
1 8/ 5/2013 bretth
Converted from ASME Section VIII Division 1, 2010 Edition to ASME Section VIIIDivision 1, 2010 Edition, A11 Addenda. Default Forging Material Changed to A 105.During the conversion, changes may have been made to your vessel (some maybe listed above). Please check your vessel carefully.
1/103
Table Of ContentsRevision History1.
Settings Summary2.
Deficiencies Summary3.
Pressure Summary4.
Thickness Summary5.
Weight Summary6.
Hydrostatic Test7.
Liquid Level bounded by Ellipsoidal Head #18.
Long Seam Summary9.
Wind Code10.
Seismic Code11.
Cylinder #112.
Ellipsoidal Head #113.
Straight Flange on Ellipsoidal Head #114.
Ellipsoidal Head #215.
Straight Flange on Ellipsoidal Head #216.
Nozzle Schedule17.
Nozzle Summary18.
N1 - 3" 300# RFLWN - Liquid Outlet (N1)19.
N2 - 3" 300# RFLWN - Vapor In (N2)20.
N3 - 1 1/2" 300# RFLWN - Level Gauge (N3)21.
N4 - 1 1/2" 300# RFLWN - Level Gauge (N4)22.
N5 - 2" 300# RFWN Drain (N5)23.
N6 - 3" 300# RFWN Flare Outlet (N6)24.
Support Skirt #125.
Skirt Opening (SO)26.
Skirt Base Ring #127.
2/103
Settings Summary
COMPRESS 2013 Build 7320
Units: U.S. Customary
Datum Line Location: 0.00" from bottom seam
Design
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
Design or Rating: Get Thickness from PressureMinimum thickness: 0.0625" per UG-16(b)Design for cold shut down only: NoDesign for lethal service (full radiography required): NoDesign nozzles for: Design P, find nozzle MAWP and MAPCorrosion weight loss: 100% of theoretical lossUG-23 Stress Increase: 1.20Skirt/legs stress increase: 1.0Minimum nozzle projection: 6"Juncture calculations for α > 30 only: YesPreheat P-No 1 Materials > 1.25" and <= 1.50" thick: NoUG-37(a) shell tr calculation considers longitudinal stress: NoButt welds are tapered per Figure UCS-66.3(a).
Hydro/Pneumatic Test
Shop Hydrotest Pressure: 1.3 times vesselMAWP
Test liquid specific gravity: 1.00Maximum stress during test: 90% of yield
Required Marking - UG-116
UG-116(e) Radiography: RT1UG-116(f) Postweld heat treatment: None
Code Cases\Interpretations
Use Code Case 2547: NoApply interpretation VIII-1-83-66: YesApply interpretation VIII-1-86-175: YesApply interpretation VIII-1-01-37: YesNo UCS-66.1 MDMT reduction: NoNo UCS-68(c) MDMT reduction: NoDisallow UG-20(f) exemptions: No
UG-22 Loadings
UG-22(a) Internal or External Design Pressure : YesUG-22(b) Weight of the vessel and normal contents under operating or test conditions: Yes
3/103
UG-22(c) Superimposed static reactions from weight of attached equipment (external loads): NoUG-22(d)(2) Vessel supports such as lugs, rings, skirts, saddles and legs: YesUG-22(f) Wind reactions: YesUG-22(f) Seismic reactions: YesUG-22(j) Test pressure and coincident static head acting during the test: NoNote: UG-22(b),(c) and (f) loads only considered when supports are present.
4/103
Deficiencies Summary
No deficiencies found.
5/103
Pressure Summary
Pressure Summary for Chamber bounded by Ellipsoidal Head #1 and Ellipsoidal Head #2
IdentifierP
Design( psi)
T
Design( °F)
MAWP( psi)
MAP( psi)
MDMT( °F)
MDMTExemption
ImpactTested
Ellipsoidal Head #2 275 100 275.32 275.32 -54.3 Note 1 No
Straight Flange on Ellipsoidal Head #2 275 100 420.17 420.17 -54.3 Note 2 No
Cylinder #1 275 100 418.56 420.17 -54 Note 3 No
Straight Flange on Ellipsoidal Head #1 275 100 418.51 420.17 -53.9 Note 5 No
Ellipsoidal Head #1 275 100 275.1 276.91 -53.9 Note 4 No
N1 - 3" 300# RFLWN - Liquid Outlet (N1) 275 100 418.7 420.17 -54 Note 6 No
N2 - 3" 300# RFLWN - Vapor In (N2) 275 100 419.17 420.17 -54.1 Note 7 No
N3 - 1 1/2" 300# RFLWN - Level Gauge (N3) 275 100 420.17 420.17 -54.3 Note 8 No
N4 - 1 1/2" 300# RFLWN - Level Gauge (N4) 275 100 418.7 420.17 -54 Note 6 No
N5 - 2" 300# RFWN Drain (N5) 275 100 303.71 305.75 -55 Note 9 No
N6 - 3" 300# RFWN Flare Outlet (N6) 275 100 303.99 303.99 -29.5 Note 10 No
Chamber design MDMT is -20 °FChamber rated MDMT is -29.5 °F @ 275.1 psi
Chamber MAWP hot & corroded is 275.1 psi @ 100 °F
Chamber MAP cold & new is 275.32 psi @ 70 °F
This pressure chamber is not designed for external pressure.
6/103
Notes for MDMT Rating:
Note # Exemption Details
1. Straight Flange governs MDMT
2. Material impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34.3 °F, (coincident ratio = 0.6566) UCS-66 governing thickness = 0.25 in
3. Material impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34 °F, (coincident ratio = 0.6604) UCS-66 governing thickness = 0.25 in
4. Straight Flange governs MDMT
5. Material impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 33.9 °F, (coincident ratio = 0.6606) UCS-66 governing thickness = 0.25 in
6. Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34 °F, (coincident ratio = 0.6601) UCS-66 governing thickness = 0.25 in.
7. Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34.1 °F, (coincident ratio = 0.659) UCS-66 governing thickness = 0.25 in.
8. Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34.3 °F, (coincident ratio = 0.6566) UCS-66 governing thickness = 0.25 in.
9. Flange rating governs: UCS-66(b)(1)(b)
10. Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 9.5 °F, (coincident ratio = 0.9055) UCS-66 governing thickness = 0.1632 in.
Design notes are available on the Settings Summary page.
7/103
Thickness Summary
ComponentIdentifier
Material Diameter(in)
Length(in)
Nominal t(in)
Design t(in)
Total Corrosion(in)
JointE
Load
Ellipsoidal Head #2 SA-516 70 24 OD 6.0816 0.1632* 0.163 0 1.00 Internal
Straight Flange on Ellipsoidal Head #2 SA-516 70 24 OD 2 0.25 0.1641 0 1.00 Internal
Cylinder #1 SA-516 70 24 OD 72 0.25 0.1651 0 1.00 Internal
Straight Flange on Ellipsoidal Head #1 SA-516 70 24 OD 2 0.25 0.1651 0 1.00 Internal
Ellipsoidal Head #1 SA-516 70 24 OD 6.0821 0.1641* 0.1641 0 1.00 Internal
Support Skirt #1 SA-516 70 24 OD 26.625 0.1875 0.004 0 0.55 Wind
Nominal t: Vessel wall nominal thickness
Design t: Required vessel thickness due to governing loading + corrosion
Joint E: Longitudinal seam joint efficiency
* Head minimum thickness after forming
Load
internal: Circumferential stress due to internal pressure governs
external: External pressure governs
Wind: Combined longitudinal stress of pressure + weight + wind governs
Seismic: Combined longitudinal stress of pressure + weight + seismic governs
8/103
Weight Summary
ComponentWeight ( lb) Contributed by Vessel Elements Surface
Areaft2Metal
New*Metal
Corroded* Insulation InsulationSupports Lining Piping
+ Liquid
Operating Liquid Test Liquid
New Corroded New Corroded
Ellipsoidal Head #2 40.1 40.1 0 0 0 0 0 0 95.8 95.8 6
Cylinder #1 376.9 376.9 0 0 0 0 699.3 699.3 1,130.4 1,130.4 37
Ellipsoidal Head #1 40.9 40.9 0 0 0 0 66.3 66.3 94.7 94.7 6
Support Skirt #1 103.7 103.7 0 0 0 0 0 0 0 0 28
Skirt Base Ring #1 66 66 0 0 0 0 0 0 0 0 7
TOTAL: 627.5 627.5 0 0 0 0 765.5 765.5 1,320.9 1,320.9 84
* Shells with attached nozzles have weight reduced by material cut out for opening.
Component
Weight ( lb) Contributed by Attachments SurfaceAreaft2Body Flanges Nozzles &
Flanges PackedBeds
Ladders &Platforms
Trays TraySupports
Rings &Clips
VerticalLoads
New Corroded New Corroded
Ellipsoidal Head #2 0 0 35.1 35.1 0 0 0 0 0 0 1
Cylinder #1 0 0 90.3 90.3 0 0 0 0 0 0 3
Ellipsoidal Head #1 0 0 11.7 11.7 0 0 0 0 0 0 1
Support Skirt #1 0 0 2.8 2.8 0 0 0 0 0 0 0
TOTAL: 0 0 139.9 139.9 0 0 0 0 0 0 4
Vessel operating weight, Corroded: 1,533 lbVessel operating weight, New: 1,533 lbVessel empty weight, Corroded: 767 lbVessel empty weight, New: 767 lbVessel test weight, New: 2,088 lbVessel test weight, Corroded: 2,088 lbVessel surface area: 88 ft2
Vessel center of gravity location - from datum - lift condition
Vessel Lift Weight, New: 767 lbCenter of Gravity: 22.8244"
Vessel Capacity
Vessel Capacity** (New): 158 US galVessel Capacity** (Corroded): 158 US gal**The vessel capacity does not include volume of nozzle, piping or other attachments.
9/103
Hydrostatic Test
Shop test pressure determination for Chamber bounded by Ellipsoidal Head #1 and Ellipsoidal Head #2 basedon MAWP per UG-99(b)
Shop hydrostatic test gauge pressure is 357.63 psi at 70 °F (the chamber MAWP = 275.1 psi)
The shop test is performed with the vessel in the vertical position.
IdentifierLocal testpressure
psi
Test liquidstatic head
psi
UG-99(b)stressratio
UG-99(b)pressure
factorEllipsoidal Head #2 (1) 358.217 0.587 1 1.30
Straight Flange on Ellipsoidal Head #2 358.217 0.587 1 1.30
Cylinder #1 360.816 3.186 1 1.30
Straight Flange on Ellipsoidal Head #1 360.888 3.258 1 1.30
Ellipsoidal Head #1 361.102 3.471 1 1.30
N1 - 3" 300# RFLWN - Liquid Outlet (N1) 360.626 2.996 1 1.30
N2 - 3" 300# RFLWN - Vapor In (N2) 359.947 2.317 1 1.30
N3 - 1 1/2" 300# RFLWN - Level Gauge (N3) 358.461 0.83 1 1.30
N4 - 1 1/2" 300# RFLWN - Level Gauge (N4) 360.626 2.996 1 1.30
N5 - 2" 300# RFWN Drain (N5) 361.434 3.804 1 1.30
N6 - 3" 300# RFWN Flare Outlet (N6) 357.925 0.295 1 1.30
Notes:(1) Ellipsoidal Head #2 limits the UG-99(b) stress ratio.
The field test condition has not been investigated for the Chamber bounded by Ellipsoidal Head #1 and EllipsoidalHead #2.
The test temperature of 70 °F is warmer than the minimum recommended temperature of 0.5 °F so the brittle fractureprovision of UG-99(h) has been met.
10/103
Liquid Level bounded by Ellipsoidal Head #1
Location from datum 63.625"
Operating Liquid Specific Gravity 0.7
11/103
Long Seam Summary
Shell Long Seam Angles
Component Seam 1
Cylinder #1 0°
Support Skirt #1 90°
Shell Plate Lengths
Component StartingAngle Plate 1
Cylinder #1 0° 74.6128"
Support Skirt #1 90° 74.8092"
*North is located at 0°*Plate Lengths use the circumference of the vessel based on the mid diameter of the components
12/103
Shell Rollout
13/103
Wind Code
Building Code: ASCE 7-10Elevation of base above grade: 0.0000 ftIncrease effective outer diameter by: 0.0000 ft Wind Force Coefficient Cf: 0.5600 Risk Category (Table 1.5-1): II
Basic Wind Speed:, V: 150.0000mph
Exposure category: DWind Directionality Factor, Kd: 0.9500Topographic Factor, Kzt: 1.0000Enforce min. loading of 16 psf: Yes
Vessel Characteristics
Vessel height, h: 9.1478 ftVessel Minimum Diameter, b
Operating, Corroded: 2.0000 ftEmpty, Corroded: 2.0000 ft
Fundamental Frequency, n1
Operating, Corroded: 45.4480 HzEmpty, Corroded: 61.6511 Hz
Damping coefficient, βOperating, Corroded: 0.0250
Empty, Corroded: 0.0200
Vortex Shedding CalculationsTable Lookup Values
2.4.1 Basic Load Combinations for Allowable Stress DesignThe following load combinations are considered in accordance with ASCE section 2.4.1:
5. D + P + Ps + 0.6W7. 0.6D + P + Ps + 0.6WWhereD = Dead loadP = Internal or external pressure loadPs = Static head loadW = Wind load
Wind Deflection Reports:
Operating, CorrodedEmpty, CorrodedWind Pressure Calculations
14/103
Wind Deflection Report: Operating, Corroded
ComponentElevation of
bottom abovebase (in)
Effective OD(ft)
Elastic modulusE (106 psi)
InertiaI (ft4)
Platformwind shear atBottom (lbf)
Total windshear at
Bottom (lbf)
bendingmoment at
Bottom (lbf-ft)
Deflectionat top (in)
Ellipsoidal Head #2 101.6915 2.00 29.3 * 0 20 6 0.0017
Cylinder #1 29.6915 2.00 29.3 0.06343 0 227 823 0.0016
Ellipsoidal Head #1 (top) 26.625 2.00 29.3 * 0 236 882 0.0002
Support Skirt #1 0 2.00 29.3 0.04795 0 312 1,490 0.0002
*Moment of Inertia I varies over the length of the componentWind Deflection Report: Empty, Corroded
ComponentElevation of
bottom abovebase (in)
Effective OD(ft)
Elastic modulusE (106 psi)
InertiaI (ft4)
Platformwind shear atBottom (lbf)
Total windshear at
Bottom (lbf)
bendingmoment at
Bottom (lbf-ft)
Deflectionat top (in)
Ellipsoidal Head #2 101.6915 2.00 29.4 * 0 20 6 0.0017
Cylinder #1 29.6915 2.00 29.4 0.06343 0 227 823 0.0016
Ellipsoidal Head #1 (top) 26.625 2.00 29.4 * 0 236 882 0.0002
Support Skirt #1 0 2.00 29.4 0.04795 0 312 1,490 0.0002
*Moment of Inertia I varies over the length of the component
Wind Pressure (WP) Calculations
Gust Factor (G¯) Calculations
Kz = 2.01 * (Z/Zg)2/α
= 2.01 * (Z/700.0000)0.1739
qz = 0.00256 * Kz * Kzt * Kd * V2
= 0.00256 * Kz * 1.0000 * 0.9500 * 150.00002
= 54.7200 * KzWP = 0.6 * qz * G * Cf (Minimum 16 lb/ft2)
= 0.6 * qz * G * 0.5600 (Minimum 16 lb/ft2)
Design Wind Pressures
Height Z(') Kz qz
(psf)WP: Operating
(psf)WP: Empty
(psf)
WP: HydrotestNew(psf)
WP: HydrotestCorroded
(psf)
WP:Vacuum
(psf)
15.0 1.0302 56.37 17.28 17.28 N.A. N.A. N.A.Design Wind Force determined from: F = Pressure * Af , where Af is the projected area.
Vortex Shedding Calculations
Vortex shedding calculations are based on NBC 1995 building code, Structural Commentaries (Part 4).
Average diameter of vessel (upper third): D = 1.9269 ftAspect ratio: Ar = 4.7474Weight per foot of vessel, Operating, Corroded, (upper third): M = 149.7553 lb/ftStrouhal number, Operating, Corroded: S = 0.2000Weight per foot of vessel, Empty, Corroded, (upper third): M = 78.8956 lb/ft
15/103
Strouhal number, Empty, Corroded: S = 0.2000
Critical wind speed at top of vessel, Vh = (n*D/S)*(3600/5280) mph
Operating, Corroded: Vh = (45.4480*1.9269/0.2000)*(3600/5280) = 298.5440 mph (480.4600 km/h)Empty, Corroded: Vh = (61.6511*1.9269/0.2000)*(3600/5280) = 404.9804 mph (651.7528 km/h)Reference wind speed corresponding to critical wind speed, V Ref
Operating, Corroded: VRef = 333.7801 mph (537.1670 km/h)Empty, Corroded: VRef = 452.7788 mph (728.6769 km/h)Corresponding reference wind speed, VRef
Operating, Corroded: VRef = 150.0000 mph (241.4016 km/h)Empty, Corroded: VRef = 150.0000 mph (241.4016 km/h)
Speed for operating, corroded condition which produces vortex shedding is greater than reference speed. No furthervortex shedding computations were done for this condition.Speed for empty, corroded condition which produces vortex shedding is greater than reference speed. No furthervortex shedding computations were done for this condition.
Gust Factor Calculations
Operating, CorrodedEmpty, Corroded
Gust Factor Calculations: Operating, Corroded
Vessel is considered a rigid structure as n1 = 45.4480 Hz ≥ 1 Hz.
z¯ = max ( 0.60 * h , zmin )= max ( 0.60 * 9.1478 , 7.0000 )= 7.0000
Iz¯ = c * (33 / z¯)1/6
= 0.1500 * (33 / 7.0000)1/6
= 0.1942Lz¯ = l * (z¯ / 33)ep
= 650.0000 * (7.0000 / 33)0.1250
= 535.4715Q = Sqr(1 / (1 + 0.63 * ((b + h) / Lz¯)0.63))
= Sqr(1 / (1 + 0.63 * ((2.0000 + 9.1478) / 535.4715)0.63))= 0.9736
G = 0.925 * (1 + 1.7 * gQ * Iz¯ * Q) / (1 + 1.7 * gv * Iz¯)= 0.925 * (1 + 1.7 * 3.40* 0.1942 * 0.9736) / (1 + 1.7 * 3.40 * 0.1942)= 0.9121
Gust Factor Calculations: Empty, Corroded
Vessel is considered a rigid structure as n1 = 61.6511 Hz ≥ 1 Hz.
z¯ = max ( 0.60 * h , zmin )
16/103
= max ( 0.60 * 9.1478 , 7.0000 )= 7.0000
Iz¯ = c * (33 / z¯)1/6
= 0.1500 * (33 / 7.0000)1/6
= 0.1942Lz¯ = l * (z¯ / 33)ep
= 650.0000 * (7.0000 / 33)0.1250
= 535.4715Q = Sqr(1 / (1 + 0.63 * ((b + h) / Lz¯)0.63))
= Sqr(1 / (1 + 0.63 * ((2.0000 + 9.1478) / 535.4715)0.63))= 0.9736
G = 0.925 * (1 + 1.7 * gQ * Iz¯ * Q) / (1 + 1.7 * gv * Iz¯)= 0.925 * (1 + 1.7 * 3.40* 0.1942 * 0.9736) / (1 + 1.7 * 3.40 * 0.1942)= 0.9121
Table Lookup Values
α = 11.5000, zg = 700.0000 ft [Table 26.9-1, page 256]c = 0.1500, l = 650.0000, ep = 0.1250 [Table 26.9-1, page 256]a¯ = 0.1111, b¯ = 0.8000 [Table 26.9-1, page 256]zmin = 7.0000 ft [Table 26.9-1, page 256]gQ = 3.40 [26.9.4 page 254]gv = 3.40 [26.9.4 page 254]
17/103
Seismic Code
Method of seismic analysis: ASCE 7-10 groundsupported
Site Class CImportance Factor: Ie = 1.0000Spectral Response Acceleration at short period (% g) Ss = 10.00%Spectral Response Acceleration at period of 1 sec (% g) S1 = 4.00%Response Modification Coeficient from Table 15.4-2 R = 3.0000Acceleration based site co-efficient: Fa = 1.2000Velocity based site co-efficient: Fv = 1.7000Long-period transition period: TL = 12.0000Redundancy factor: ρ = 1.0000User Defined Vertical Accelerations Considered: No
2.4 Combining Nominal Loads Using Allowable Stress DesignThe following load combinations are considered in accordance with ASCE section 2.4.1:
5. D + P + Ps + 0.7E8. 0.6D + P + Ps + 0.7EWhereD = Dead loadP = Internal or external pressure loadPs = Static head loadE = Seismic load
Vessel Characteristics
Vessel height: 9.1478 ftVessel Weight:
Operating, Corroded: 1,533 lbEmpty, Corroded: 767 lb
Period of Vibration Calculation
Fundamental Period, T:Operating, Corroded: 0.022 sec (f = 45.4 Hz)
Empty, Corroded: 0.016 sec (f = 61.7 Hz)
The fundamental period of vibration T (above) is calculated using the Rayleigh method of approximation:
T = 2 * PI * Sqr( {Sum(Wi * yi2 )} / {g * Sum(Wi * yi )} ), where
Wi is the weight of the ith lumped mass, andyi is its deflection when the system is treated as a cantilever beam.
18/103
Seismic Shear Reports:
Operating, CorrodedEmpty, CorrodedBase Shear Calculations
Seismic Shear Report: Operating, Corroded
Component Elevation of bottomabove base (in)
Elastic modulus E(106 psi)
Inertia I(ft4)
Seismic shear atBottom (lbf)
Bending Moment atBottom (lbf-ft)
Ellipsoidal Head #2 101.6915 29.3 * 1 1
Cylinder #1 29.6915 29.3 0.0634 10 114
Ellipsoidal Head #1 (top) 26.625 29.3 * 10 117
Support Skirt #1 0 29.3 0.04795 11 143
*Moment of Inertia I varies over the length of the componentSeismic Shear Report: Empty, Corroded
Component Elevation of bottomabove base (in)
Elastic modulus E(106 psi)
Inertia I(ft4)
Seismic shear atBottom (lbf)
Bending Moment atBottom (lbf-ft)
Ellipsoidal Head #2 101.6915 29.4 * 1 1
Cylinder #1 29.6915 29.4 0.0634 5 99
Ellipsoidal Head #1 (top) 26.625 29.4 * 5 100
Support Skirt #1 0 29.4 0.04795 5 114
*Moment of Inertia I varies over the length of the component
11.4.3: Maximum considered earthquake spectral response acceleration
The maximum considered earthquake spectral response acceleration at short period, SMSSMS = Fa * Ss = 1.2000 * 10.00 / 100 = 0.1200The maximum considered earthquake spectral response acceleration at 1 s period, SM1SM1 = Fv * S1 = 1.7000 * 4.00 / 100 = 0.0680
11.4.4: Design spectral response acceleration parameters
Design earthquake spectral response acceleration at short period, SDSSDS = 2 / 3 * SMS = 2 / 3 * 0.1200 = 0.0800Design earthquake spectral response acceleration at 1 s period, SD1SD1 = 2 / 3 * SM1 = 2 / 3 * 0.0680 = 0.0453
Note: This vessel is assigned to Seismic Design Category A, and seismic design is per Section 11.7. The VAccel Termis not applicable.
Base Shear Calculations
Operating, CorrodedEmpty, Corroded
Base Shear Calculations: Operating, Corroded
Per Section 11.7, this vessel is assigned to Seismic Design Category A, as (SD1 = 0.0453) < 0.067, and (SDs =0.0800) < 0.167.
19/103
Seismic load is determined with Equation 1.4-1.
V = 0.01 * W * 0.7 (Only 70% of seismic load considered as per Section 2.4.1)= 0.01 * 1,532.9884 * 0.7= 10.73 lb
Base Shear Calculations: Empty, Corroded
Per Section 11.7, this vessel is assigned to Seismic Design Category A, as (SD1 = 0.0453) < 0.067, and (SDs =0.0800) < 0.167.Seismic load is determined with Equation 1.4-1.
V = 0.01 * W * 0.7 (Only 70% of seismic load considered as per Section 2.4.1)= 0.01 * 767.4460 * 0.7= 5.37 lb
20/103
Cylinder #1
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
Component: CylinderMaterial specification: SA-516 70 (II-D p. 18, ln. 19)Material impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34 °F, (coincident ratio = 0.6604)UCS-66 governing thickness = 0.25 in
Internal design pressure: P = 275 psi @ 100 °F
Static liquid head:
Ps = 1.61 psi (SG = 0.7, Hs =63.625",Operating head)
Ptv = 3.19 psi (SG = 1, Hs = 88.25",Vertical test head)
Corrosion allowance Inner C = 0" Outer C = 0"
Design MDMT = -20 °F No impact test performedRated MDMT = -54 °F Material is not normalized
Material is not produced to Fine Grain PracticePWHT is not performed
Radiography: Longitudinal joint - Full UW-11(a) Type 1Top circumferential joint - Full UW-11(a) Type 1Bottom circumferential joint - Full UW-11(a) Type 1
Estimated weight New = 376.9 lb corr = 376.9 lbCapacity New = 135.19 US gal corr = 135.19 US gal
OD = 24"LengthLc
= 72"
t = 0.25"
Design thickness, (at 100 °F) Appendix 1-1
t = P*Ro / (S*E + 0.40*P) + Corrosion= 276.61*12 / (20,000*1.00 + 0.40*276.61) + 0= 0.1651"
Maximum allowable working pressure, (at 100 °F) Appendix 1-1
P = S*E*t / (Ro - 0.40*t) - Ps= 20,000*1.00*0.25 / (12 - 0.40*0.25) - 1.61= 418.56 psi
Maximum allowable pressure, (at 70 °F) Appendix 1-1
P = S*E*t / (Ro - 0.40*t)= 20,000*1.00*0.25 / (12 - 0.40*0.25)= 420.17 psi
21/103
% Extreme fiber elongation - UCS-79(d)
EFE = (50*t / Rf)*(1 - Rf / Ro)= (50*0.25 / 11.875)*(1 - 11.875 / ∞)= 1.0526%
The extreme fiber elongation does not exceed 5%.
Design thickness = 0.1651"
The governing condition is due to internal pressure.
The cylinder thickness of 0.25" is adequate.
Thickness Required Due to Pressure + External Loads
Condition Pressure P (psi)
AllowableStress BeforeUG-23 StressIncrease ( psi)
Temperature (°F)
Corrosion C(in) Load Req'd Thk Due to
Tension (in)Req'd Thk Due toCompression (in)
St Sc
Operating, Hot & Corroded 275 20,000 15,771 100 0 Wind 0.0679 0.0659
Seismic 0.0671 0.0667
Operating, Hot & New 275 20,000 15,771 100 0 Wind 0.0679 0.0659
Seismic 0.0671 0.0667
Hot Shut Down, Corroded 0 20,000 15,771 100 0 Wind 0.0007 0.0016
Seismic 0.0001 0.0006
Hot Shut Down, New 0 20,000 15,771 100 0 Wind 0.0007 0.0016
Seismic 0.0001 0.0006
Empty, Corroded 0 20,000 15,771 70 0 Wind 0.0007 0.0016
Seismic 0.0001 0.0005
Empty, New 0 20,000 15,771 70 0 Wind 0.0007 0.0016
Seismic 0.0001 0.0005
Hot Shut Down, Corroded, Weight& Eccentric Moments Only 0 20,000 15,771 100 0 Weight 0.0003 0.0006
Allowable Compressive Stress, Hot and Corroded- ScHC, (table CS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScHC = min(B, S) = 15,771 psi
Allowable Compressive Stress, Hot and New- ScHN
ScHN = ScHC
= 15,771 psi
22/103
Allowable Compressive Stress, Cold and New- ScCN, (table CS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScCN = min(B, S) = 15,771 psi
Allowable Compressive Stress, Cold and Corroded- ScCC
ScCC = ScCN
= 15,771 psi
Allowable Compressive Stress, Vacuum and Corroded- ScVC, (tableCS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScVC = min(B, S) = 15,771 psi
Operating, Hot & Corroded, Wind, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 9,876 / (π*11.8752*20,000*1.20*1.00)= 0.0009"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0.0009 - (0.0002)= 0.0679"
twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0003"
tc = |tmc + twc - tpc|(total, nettensile)
= |0.0009 + (0.0003) - (0.0672)|= 0.0659"
23/103
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0.0009 + (0.0002)) / (11.75 - 0.40*(0.25 - 0.0009 + (0.0002)))= 1,026.94 psi
Operating, Hot & New, Wind, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 9,876 / (π*11.8752*20,000*1.20*1.00)= 0.0009"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0.0009 - (0.0002)= 0.0679"
twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0003"
tc = |tmc + twc - tpc|(total, nettensile)
= |0.0009 + (0.0003) - (0.0672)|= 0.0659"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0.0009 + (0.0002)) / (11.75 - 0.40*(0.25 - 0.0009 + (0.0002)))= 1,026.94 psi
Hot Shut Down, Corroded, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*St*Ks*Ec) (bending)= 9,876 / (π*11.8752*20,000*1.20*1.00)= 0.0009"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw (total required, tensile)= 0 + 0.0009 - (0.0002)= 0.0007"
tmc = M / (π*Rm2*Sc*Ks) (bending)
24/103
= 9,876 / (π*11.8752*15,770.69*1.20)= 0.0012"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 542.4 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0012 + (0.0004) - (0)= 0.0016"
Hot Shut Down, New, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*St*Ks*Ec) (bending)= 9,876 / (π*11.8752*20,000*1.20*1.00)= 0.0009"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw (total required, tensile)= 0 + 0.0009 - (0.0002)= 0.0007"
tmc = M / (π*Rm2*Sc*Ks) (bending)
= 9,876 / (π*11.8752*15,770.69*1.20)= 0.0012"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 542.4 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0012 + (0.0004) - (0)= 0.0016"
Empty, Corroded, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*St*Ks*Ec) (bending)= 9,876 / (π*11.8752*20,000*1.20*1.00)= 0.0009"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw (total required, tensile)= 0 + 0.0009 - (0.0002)= 0.0007"
tmc = M / (π*Rm2*Sc*Ks) (bending)
= 9,876 / (π*11.8752*15,770.69*1.20)= 0.0012"
25/103
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 542.4 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0012 + (0.0004) - (0)= 0.0016"
Empty, New, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*St*Ks*Ec) (bending)= 9,876 / (π*11.8752*20,000*1.20*1.00)= 0.0009"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw (total required, tensile)= 0 + 0.0009 - (0.0002)= 0.0007"
tmc = M / (π*Rm2*Sc*Ks) (bending)
= 9,876 / (π*11.8752*15,770.69*1.20)= 0.0012"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 542.4 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0012 + (0.0004) - (0)= 0.0016"
Hot Shut Down, Corroded, Weight & Eccentric Moments Only, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 940 / (π*11.8752*15,770.69*1.00)= 0.0001"
tw = W / (2*π*Rm*Sc*Ks) (Weight)= 542.4 / (2*π*11.875*15,770.69*1.00)= 0.0005"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0001 - (0.0005)|= 0.0003"
tc = tmc + twc - tpc (total required, compressive)= 0.0001 + (0.0005) - (0)= 0.0006"
26/103
Operating, Hot & Corroded, Seismic, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 1,371 / (π*11.8752*20,000*1.20*1.00)= 0.0001"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.59*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0.0001 - (0.0002)= 0.0671"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1.01*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0003"
tc = |tmc + twc - tpc|(total, nettensile)
= |0.0001 + (0.0003) - (0.0672)|= 0.0667"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0.0001 + (0.0002)) / (11.75 - 0.40*(0.25 - 0.0001 + (0.0002)))= 1,030.25 psi
Operating, Hot & New, Seismic, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 1,371 / (π*11.8752*20,000*1.20*1.00)= 0.0001"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.59*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0.0001 - (0.0002)= 0.0671"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1.01*542.4 / (2*π*11.875*20,000*1.20*1.00)= 0.0003"
27/103
tc = |tmc + twc - tpc|(total, nettensile)
= |0.0001 + (0.0003) - (0.0672)|= 0.0667"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0.0001 + (0.0002)) / (11.75 - 0.40*(0.25 - 0.0001 + (0.0002)))= 1,030.25 psi
Hot Shut Down, Corroded, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 1,371 / (π*11.8752*15,770.69*1.20)= 0.0002"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*542.4 / (2*π*11.875*15,770.69*1.20)= 0.0002"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0002 - (0.0002)|= 0.0001"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*542.4 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0002 + (0.0004) - (0)= 0.0006"
Hot Shut Down, New, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 1,371 / (π*11.8752*15,770.69*1.20)= 0.0002"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*542.4 / (2*π*11.875*15,770.69*1.20)= 0.0002"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0002 - (0.0002)|= 0.0001"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*542.4 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0002 + (0.0004) - (0)
28/103
= 0.0006"
Empty, Corroded, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 1,182 / (π*11.8752*15,770.69*1.20)= 0.0001"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*542.4 / (2*π*11.875*15,770.69*1.20)= 0.0002"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0001 - (0.0002)|= 0.0001"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*542.4 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0001 + (0.0004) - (0)= 0.0005"
Empty, New, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 1,182 / (π*11.8752*15,770.69*1.20)= 0.0001"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*542.4 / (2*π*11.875*15,770.69*1.20)= 0.0002"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0001 - (0.0002)|= 0.0001"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*542.4 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0001 + (0.0004) - (0)= 0.0005"
29/103
Ellipsoidal Head #1
ASME Section VIII, Division 1, 2010 Edition, A11 Addenda
Component: Ellipsoidal HeadMaterial Specification: SA-516 70 (II-D p.18, ln. 19)Straight Flange governs MDMT
Internal design pressure: P = 275 psi @ 100 °F
Static liquid head:
Ps= 1.81 psi (SG=0.7, Hs=71.543" Operating head)Ptv= 3.47 psi (SG=1, Hs=96.168" Vertical test head)
Corrosion allowance: Inner C = 0" Outer C = 0"
Design MDMT = -20°F No impact test performedRated MDMT = -53.9°F Material is not normalized
Material is not produced to fine grain practicePWHT is not performedDo not Optimize MDMT / Find MAWP
Radiography: Category A joints - Seamless No RT Head to shell seam - Full UW-11(a) Type 1
Estimated weight*: new = 40.9 lb corr = 40.9 lbCapacity*: new = 11.3 US gal corr = 11.3 US gal* includes straight flange
Outer diameter = 24"Minimum head thickness = 0.1641"Head ratio D/2h = 2 (new)Head ratio D/2h = 2 (corroded)Straight flange length Lsf = 2"Nominal straight flange thickness tsf = 0.25"Results Summary
The governing condition is internal pressure.Minimum thickness per UG-16 = 0.0625" + 0" = 0.0625"Design thickness due to internal pressure (t) = 0.1641"Maximum allowable working pressure (MAWP) = 275.1 psiMaximum allowable pressure (MAP) = 276.91 psi
K (Corroded)
K=(1/6)*[2 + (D / (2*h))2]=(1/6)*[2 + (23.6718 / (2*5.918))2]=1
K (New)
K=(1/6)*[2 + (D / (2*h))2]=(1/6)*[2 + (23.6718 / (2*5.918))2]=1
30/103
Design thickness for internal pressure, (Corroded at 100 °F) Appendix 1-4(c)
t = P*Do*K / (2*S*E + 2*P*(K - 0.1)) + Corrosion= 276.81*24*1 / (2*20,000*1 + 2*276.81*(1 - 0.1)) + 0= 0.164"
The head internal pressure design thickness is 0.1641".
Maximum allowable working pressure, (Corroded at 100 °F) Appendix 1-4(c)
P = 2*S*E*t / (K*Do - 2*t*(K - 0.1)) - Ps= 2*20,000*1*0.1641 / (1*24 - 2*0.1641*(1 - 0.1)) - 1.81= 275.1 psi
The maximum allowable working pressure (MAWP) is 275.1 psi.
Maximum allowable pressure, (New at 70 °F) Appendix 1-4(c)
P = 2*S*E*t / (K*Do - 2*t*(K - 0.1)) - Ps= 2*20,000*1*0.1641 / (1*24 - 2*0.1641*(1 - 0.1)) - 0= 276.91 psi
The maximum allowable pressure (MAP) is 276.91 psi.
% Extreme fiber elongation - UCS-79(d)
EFE = (75*t / Rf)*(1 - Rf / Ro)= (75*0.25 / 4.1492)*(1 - 4.1492 / ∞)= 4.5189%
The extreme fiber elongation does not exceed 5%.
31/103
Straight Flange on Ellipsoidal Head #1
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
Component: Straight FlangeMaterial specification: SA-516 70 (II-D p. 18, ln. 19)Material impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 33.9 °F, (coincident ratio = 0.6606)UCS-66 governing thickness = 0.25 in
Internal design pressure: P = 275 psi @ 100 °F
Static liquid head:
Ps = 1.66 psi (SG = 0.7, Hs =65.625",Operating head)
Ptv = 3.26 psi (SG = 1, Hs = 90.25",Vertical test head)
Corrosion allowance Inner C = 0" Outer C = 0"
Design MDMT = -20 °F No impact test performedRated MDMT = -53.9 °F Material is not normalized
Material is not produced to Fine Grain PracticePWHT is not performed
Radiography: Longitudinal joint - Seamless No RTCircumferential joint - Full UW-11(a) Type 1
Estimated weight New = 10.6 lb corr = 10.6 lbCapacity New = 3.76 US gal corr = 3.76 US gal
OD = 24"LengthLc
= 2"
t = 0.25"
Design thickness, (at 100 °F) Appendix 1-1
t = P*Ro / (S*E + 0.40*P) + Corrosion= 276.66*12 / (20,000*1.00 + 0.40*276.66) + 0= 0.1651"
Maximum allowable working pressure, (at 100 °F) Appendix 1-1
P = S*E*t / (Ro - 0.40*t) - Ps= 20,000*1.00*0.25 / (12 - 0.40*0.25) - 1.66= 418.51 psi
Maximum allowable pressure, (at 70 °F) Appendix 1-1
P = S*E*t / (Ro - 0.40*t)= 20,000*1.00*0.25 / (12 - 0.40*0.25)= 420.17 psi
32/103
% Extreme fiber elongation - UCS-79(d)
EFE = (50*t / Rf)*(1 - Rf / Ro)= (50*0.25 / 11.875)*(1 - 11.875 / ∞)= 1.0526%
The extreme fiber elongation does not exceed 5%.
Design thickness = 0.1651"
The governing condition is due to internal pressure.
The cylinder thickness of 0.25" is adequate.
Thickness Required Due to Pressure + External Loads
Condition Pressure P (psi)
AllowableStress BeforeUG-23 StressIncrease ( psi)
Temperature (°F)
Corrosion C(in) Load Req'd Thk Due to
Tension (in)Req'd Thk Due toCompression (in)
St Sc
Operating, Hot & Corroded 275 20,000 15,771 100 0 Wind 0.068 0.0659
Seismic 0.0671 0.0667
Operating, Hot & New 275 20,000 15,771 100 0 Wind 0.068 0.0659
Seismic 0.0671 0.0667
Hot Shut Down, Corroded 0 20,000 15,771 100 0 Wind 0.0008 0.0016
Seismic 0.0001 0.0006
Hot Shut Down, New 0 20,000 15,771 100 0 Wind 0.0008 0.0016
Seismic 0.0001 0.0006
Empty, Corroded 0 20,000 15,771 70 0 Wind 0.0008 0.0016
Seismic 0.0001 0.0005
Empty, New 0 20,000 15,771 70 0 Wind 0.0008 0.0016
Seismic 0.0001 0.0005
Hot Shut Down, Corroded, Weight& Eccentric Moments Only 0 20,000 15,771 100 0 Weight 0.0003 0.0006
Allowable Compressive Stress, Hot and Corroded- ScHC, (table CS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScHC = min(B, S) = 15,771 psi
Allowable Compressive Stress, Hot and New- ScHN
ScHN = ScHC
= 15,771 psi
33/103
Allowable Compressive Stress, Cold and New- ScCN, (table CS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScCN = min(B, S) = 15,771 psi
Allowable Compressive Stress, Cold and Corroded- ScCC
ScCC = ScCN
= 15,771 psi
Allowable Compressive Stress, Vacuum and Corroded- ScVC, (tableCS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScVC = min(B, S) = 15,771 psi
Operating, Hot & Corroded, Wind, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 10,341 / (π*11.8752*20,000*1.20*1.00)= 0.001"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0.001 - (0.0002)= 0.068"
twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 553 / (2*π*11.875*20,000*1.20*1.00)= 0.0003"
tc = |tmc + twc - tpc|(total, nettensile)
= |0.001 + (0.0003) - (0.0672)|= 0.0659"
34/103
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0.001 + (0.0002)) / (11.75 - 0.40*(0.25 - 0.001 + (0.0002)))= 1,026.77 psi
Operating, Hot & New, Wind, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 10,341 / (π*11.8752*20,000*1.20*1.00)= 0.001"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0.001 - (0.0002)= 0.068"
twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 553 / (2*π*11.875*20,000*1.20*1.00)= 0.0003"
tc = |tmc + twc - tpc|(total, nettensile)
= |0.001 + (0.0003) - (0.0672)|= 0.0659"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0.001 + (0.0002)) / (11.75 - 0.40*(0.25 - 0.001 + (0.0002)))= 1,026.77 psi
Hot Shut Down, Corroded, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*St*Ks*Ec) (bending)= 10,341 / (π*11.8752*20,000*1.20*1.00)= 0.001"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw (total required, tensile)= 0 + 0.001 - (0.0002)= 0.0008"
tmc = M / (π*Rm2*Sc*Ks) (bending)
35/103
= 10,341 / (π*11.8752*15,770.69*1.20)= 0.0012"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 553 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0012 + (0.0004) - (0)= 0.0016"
Hot Shut Down, New, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*St*Ks*Ec) (bending)= 10,341 / (π*11.8752*20,000*1.20*1.00)= 0.001"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw (total required, tensile)= 0 + 0.001 - (0.0002)= 0.0008"
tmc = M / (π*Rm2*Sc*Ks) (bending)
= 10,341 / (π*11.8752*15,770.69*1.20)= 0.0012"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 553 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0012 + (0.0004) - (0)= 0.0016"
Empty, Corroded, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*St*Ks*Ec) (bending)= 10,341 / (π*11.8752*20,000*1.20*1.00)= 0.001"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw (total required, tensile)= 0 + 0.001 - (0.0002)= 0.0008"
tmc = M / (π*Rm2*Sc*Ks) (bending)
= 10,341 / (π*11.8752*15,770.69*1.20)= 0.0012"
36/103
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 553 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0012 + (0.0004) - (0)= 0.0016"
Empty, New, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*St*Ks*Ec) (bending)= 10,341 / (π*11.8752*20,000*1.20*1.00)= 0.001"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw (total required, tensile)= 0 + 0.001 - (0.0002)= 0.0008"
tmc = M / (π*Rm2*Sc*Ks) (bending)
= 10,341 / (π*11.8752*15,770.69*1.20)= 0.0012"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 553 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0012 + (0.0004) - (0)= 0.0016"
Hot Shut Down, Corroded, Weight & Eccentric Moments Only, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 940 / (π*11.8752*15,770.69*1.00)= 0.0001"
tw = W / (2*π*Rm*Sc*Ks) (Weight)= 553 / (2*π*11.875*15,770.69*1.00)= 0.0005"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0001 - (0.0005)|= 0.0003"
tc = tmc + twc - tpc (total required, compressive)= 0.0001 + (0.0005) - (0)= 0.0006"
37/103
Operating, Hot & Corroded, Seismic, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 1,392 / (π*11.8752*20,000*1.20*1.00)= 0.0001"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.59*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0.0001 - (0.0002)= 0.0671"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1.01*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0003"
tc = |tmc + twc - tpc|(total, nettensile)
= |0.0001 + (0.0003) - (0.0672)|= 0.0667"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0.0001 + (0.0002)) / (11.75 - 0.40*(0.25 - 0.0001 + (0.0002)))= 1,030.25 psi
Operating, Hot & New, Seismic, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 1,392 / (π*11.8752*20,000*1.20*1.00)= 0.0001"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.59*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0002"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0.0001 - (0.0002)= 0.0671"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1.01*553 / (2*π*11.875*20,000*1.20*1.00)= 0.0003"
38/103
tc = |tmc + twc - tpc|(total, nettensile)
= |0.0001 + (0.0003) - (0.0672)|= 0.0667"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0.0001 + (0.0002)) / (11.75 - 0.40*(0.25 - 0.0001 + (0.0002)))= 1,030.25 psi
Hot Shut Down, Corroded, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 1,392 / (π*11.8752*15,770.69*1.20)= 0.0002"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*553 / (2*π*11.875*15,770.69*1.20)= 0.0002"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0002 - (0.0002)|= 0.0001"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*553 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0002 + (0.0004) - (0)= 0.0006"
Hot Shut Down, New, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 1,392 / (π*11.8752*15,770.69*1.20)= 0.0002"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*553 / (2*π*11.875*15,770.69*1.20)= 0.0002"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0002 - (0.0002)|= 0.0001"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*553 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0002 + (0.0004) - (0)
39/103
= 0.0006"
Empty, Corroded, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 1,193 / (π*11.8752*15,770.69*1.20)= 0.0001"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*553 / (2*π*11.875*15,770.69*1.20)= 0.0002"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0001 - (0.0002)|= 0.0001"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*553 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0001 + (0.0004) - (0)= 0.0005"
Empty, New, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 1,193 / (π*11.8752*15,770.69*1.20)= 0.0001"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*553 / (2*π*11.875*15,770.69*1.20)= 0.0002"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0.0001 - (0.0002)|= 0.0001"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*553 / (2*π*11.875*15,770.69*1.20)= 0.0004"
tc = tmc + twc - tpc (total required, compressive)= 0.0001 + (0.0004) - (0)= 0.0005"
40/103
Ellipsoidal Head #2
ASME Section VIII, Division 1, 2010 Edition, A11 Addenda
Component: Ellipsoidal HeadMaterial Specification: SA-516 70 (II-D p.18, ln. 19)Straight Flange governs MDMT
Internal design pressure: P = 275 psi @ 100 °F
Static liquid head:
Ps= 0 psi (SG=0.7, Hs=0" Operating head)Ptv= 0.51 psi (SG=1, Hs=14.25" Vertical test head)
Corrosion allowance: Inner C = 0" Outer C = 0"
Design MDMT = -20°F No impact test performedRated MDMT = -54.3°F Material is not normalized
Material is not produced to fine grain practicePWHT is not performedDo not Optimize MDMT / Find MAWP
Radiography: Category A joints - Seamless No RT Head to shell seam - Full UW-11(a) Type 1
Estimated weight*: new = 40.1 lb corr = 40.1 lbCapacity*: new = 11.3 US gal corr = 11.3 US gal* includes straight flange
Outer diameter = 24"Minimum head thickness = 0.1632"Head ratio D/2h = 2 (new)Head ratio D/2h = 2 (corroded)Straight flange length Lsf = 2"Nominal straight flange thickness tsf = 0.25"Results Summary
The governing condition is internal pressure.Minimum thickness per UG-16 = 0.0625" + 0" = 0.0625"Design thickness due to internal pressure (t) = 0.163"Maximum allowable working pressure (MAWP) = 275.32 psiMaximum allowable pressure (MAP) = 275.32 psi
K (Corroded)
K=(1/6)*[2 + (D / (2*h))2]=(1/6)*[2 + (23.6737 / (2*5.9184))2]=1
K (New)
K=(1/6)*[2 + (D / (2*h))2]=(1/6)*[2 + (23.6737 / (2*5.9184))2]=1
41/103
Design thickness for internal pressure, (Corroded at 100 °F) Appendix 1-4(c)
t = P*Do*K / (2*S*E + 2*P*(K - 0.1)) + Corrosion= 275*24*1 / (2*20,000*1 + 2*275*(1 - 0.1)) + 0= 0.163"
The head internal pressure design thickness is 0.163".
Maximum allowable working pressure, (Corroded at 100 °F) Appendix 1-4(c)
P = 2*S*E*t / (K*Do - 2*t*(K - 0.1)) - Ps= 2*20,000*1*0.1632 / (1*24 - 2*0.1632*(1 - 0.1)) - 0= 275.32 psi
The maximum allowable working pressure (MAWP) is 275.32 psi.
Maximum allowable pressure, (New at 70 °F) Appendix 1-4(c)
P = 2*S*E*t / (K*Do - 2*t*(K - 0.1)) - Ps= 2*20,000*1*0.1632 / (1*24 - 2*0.1632*(1 - 0.1)) - 0= 275.32 psi
The maximum allowable pressure (MAP) is 275.32 psi.
% Extreme fiber elongation - UCS-79(d)
EFE = (75*t / Rf)*(1 - Rf / Ro)= (75*0.25 / 4.1495)*(1 - 4.1495 / ∞)= 4.5186%
The extreme fiber elongation does not exceed 5%.
42/103
Straight Flange on Ellipsoidal Head #2
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
Component: Straight FlangeMaterial specification: SA-516 70 (II-D p. 18, ln. 19)Material impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34.3 °F, (coincident ratio = 0.6566)UCS-66 governing thickness = 0.25 in
Internal design pressure: P = 275 psi @ 100 °F
Static liquid head:
Ps = 0 psi (SG = 0.7, Hs = 0",Operating head)
Ptv = 0.59 psi (SG = 1, Hs = 16.25", Vertical testhead)
Corrosion allowance Inner C = 0" Outer C = 0"
Design MDMT = -20 °F No impact test performedRated MDMT = -54.3 °F Material is not normalized
Material is not produced to Fine Grain PracticePWHT is not performed
Radiography: Longitudinal joint - Seamless No RTCircumferential joint - Full UW-11(a) Type 1
Estimated weight New = 10.6 lb corr = 10.6 lbCapacity New = 3.76 US gal corr = 3.76 US gal
OD = 24"LengthLc
= 2"
t = 0.25"
Design thickness, (at 100 °F) Appendix 1-1
t = P*Ro / (S*E + 0.40*P) + Corrosion= 275*12 / (20,000*1.00 + 0.40*275) + 0= 0.1641"
Maximum allowable working pressure, (at 100 °F) Appendix 1-1
P = S*E*t / (Ro - 0.40*t) - Ps= 20,000*1.00*0.25 / (12 - 0.40*0.25) - 0= 420.17 psi
Maximum allowable pressure, (at 70 °F) Appendix 1-1
P = S*E*t / (Ro - 0.40*t)= 20,000*1.00*0.25 / (12 - 0.40*0.25)= 420.17 psi
43/103
% Extreme fiber elongation - UCS-79(d)
EFE = (50*t / Rf)*(1 - Rf / Ro)= (50*0.25 / 11.875)*(1 - 11.875 / ∞)= 1.0526%
The extreme fiber elongation does not exceed 5%.
Design thickness = 0.1641"
The governing condition is due to internal pressure.
The cylinder thickness of 0.25" is adequate.
Thickness Required Due to Pressure + External Loads
Condition Pressure P (psi)
AllowableStress BeforeUG-23 StressIncrease ( psi)
Temperature (°F)
Corrosion C(in) Load Req'd Thk Due to
Tension (in)Req'd Thk Due toCompression (in)
St Sc
Operating, Hot & Corroded 275 20,000 15,771 100 0 Wind 0.0671 0.0671
Seismic 0.0671 0.0671
Operating, Hot & New 275 20,000 15,771 100 0 Wind 0.0671 0.0671
Seismic 0.0671 0.0671
Hot Shut Down, Corroded 0 20,000 15,771 100 0 Wind 0 0.0001
Seismic 0 0.0001
Hot Shut Down, New 0 20,000 15,771 100 0 Wind 0 0.0001
Seismic 0 0.0001
Empty, Corroded 0 20,000 15,771 70 0 Wind 0 0.0001
Seismic 0 0.0001
Empty, New 0 20,000 15,771 70 0 Wind 0 0.0001
Seismic 0 0.0001
Hot Shut Down, Corroded, Weight& Eccentric Moments Only 0 20,000 15,771 100 0 Weight 0.0001 0.0001
Allowable Compressive Stress, Hot and Corroded- ScHC, (table CS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScHC = min(B, S) = 15,771 psi
Allowable Compressive Stress, Hot and New- ScHN
ScHN = ScHC
= 15,771 psi
44/103
Allowable Compressive Stress, Cold and New- ScCN, (table CS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScCN = min(B, S) = 15,771 psi
Allowable Compressive Stress, Cold and Corroded- ScCC
ScCC = ScCN
= 15,771 psi
Allowable Compressive Stress, Vacuum and Corroded- ScVC, (tableCS-2)A = 0.125 / (Ro / t)
= 0.125 / (12 / 0.25)= 0.002604
B = 15,771 psi
S = 20,000 / 1.00 = 20,000 psi
ScVC = min(B, S) = 15,771 psi
Operating, Hot & Corroded, Wind, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 69 / (π*11.8752*20,000*1.20*1.00)= 0"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*75.2 / (2*π*11.875*20,000*1.20*1.00)= 0"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0 - (0)= 0.0671"
twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 75.2 / (2*π*11.875*20,000*1.20*1.00)= 0"
tc = |tmc + twc - tpc|(total, nettensile)
= |0 + (0) - (0.0672)|= 0.0671"
45/103
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0 + (0)) / (11.75 - 0.40*(0.25 - 0 + (0)))= 1,030.12 psi
Operating, Hot & New, Wind, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 69 / (π*11.8752*20,000*1.20*1.00)= 0"
tw = 0.6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.60*75.2 / (2*π*11.875*20,000*1.20*1.00)= 0"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0 - (0)= 0.0671"
twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 75.2 / (2*π*11.875*20,000*1.20*1.00)= 0"
tc = |tmc + twc - tpc|(total, nettensile)
= |0 + (0) - (0.0672)|= 0.0671"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0 + (0)) / (11.75 - 0.40*(0.25 - 0 + (0)))= 1,030.12 psi
Hot Shut Down, Corroded, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 69 / (π*11.8752*15,770.69*1.20)= 0"
tw = 0.6*W / (2*π*Rm*Sc*Ks) (Weight)= 0.60*75.2 / (2*π*11.875*15,770.69*1.20)= 0"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0)|= 0"
twc = W / (2*π*Rm*Sc*Ks) (Weight)
46/103
= 75.2 / (2*π*11.875*15,770.69*1.20)= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
Hot Shut Down, New, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 69 / (π*11.8752*15,770.69*1.20)= 0"
tw = 0.6*W / (2*π*Rm*Sc*Ks) (Weight)= 0.60*75.2 / (2*π*11.875*15,770.69*1.20)= 0"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0)|= 0"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 75.2 / (2*π*11.875*15,770.69*1.20)= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
Empty, Corroded, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 69 / (π*11.8752*15,770.69*1.20)= 0"
tw = 0.6*W / (2*π*Rm*Sc*Ks) (Weight)= 0.60*75.2 / (2*π*11.875*15,770.69*1.20)= 0"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0)|= 0"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 75.2 / (2*π*11.875*15,770.69*1.20)= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
47/103
Empty, New, Wind, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 69 / (π*11.8752*15,770.69*1.20)= 0"
tw = 0.6*W / (2*π*Rm*Sc*Ks) (Weight)= 0.60*75.2 / (2*π*11.875*15,770.69*1.20)= 0"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0)|= 0"
twc = W / (2*π*Rm*Sc*Ks) (Weight)= 75.2 / (2*π*11.875*15,770.69*1.20)= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
Hot Shut Down, Corroded, Weight & Eccentric Moments Only, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 0 / (π*11.8752*15,770.69*1.00)= 0"
tw = W / (2*π*Rm*Sc*Ks) (Weight)= 75.2 / (2*π*11.875*15,770.69*1.00)= 0.0001"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0.0001)|= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
Operating, Hot & Corroded, Seismic, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 6 / (π*11.8752*20,000*1.20*1.00)= 0"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.59*75.2 / (2*π*11.875*20,000*1.20*1.00)= 0"
tt = tp + tm - tw
48/103
(total required,tensile)
= 0.0672 + 0 - (0)= 0.0671"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1.01*75.2 / (2*π*11.875*20,000*1.20*1.00)= 0"
tc = |tmc + twc - tpc|(total, nettensile)
= |0 + (0) - (0.0672)|= 0.0671"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0 + (0)) / (11.75 - 0.40*(0.25 - 0 + (0)))= 1,030.14 psi
Operating, Hot & New, Seismic, Bottom Seam
tp = P*R / (2*St*Ks*Ec + 0.40*|P|) (Pressure)= 275*11.75 / (2*20,000*1.20*1.00 + 0.40*|275|)= 0.0672"
tm = M / (π*Rm2*St*Ks*Ec) (bending)
= 6 / (π*11.8752*20,000*1.20*1.00)= 0"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0.59*75.2 / (2*π*11.875*20,000*1.20*1.00)= 0"
tt = tp + tm - tw(total required,tensile)
= 0.0672 + 0 - (0)= 0.0671"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1.01*75.2 / (2*π*11.875*20,000*1.20*1.00)= 0"
tc = |tmc + twc - tpc|(total, nettensile)
= |0 + (0) - (0.0672)|= 0.0671"
Maximum allowable working pressure, Longitudinal Stress
P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0.40*(t - tm + tw))= 2*20,000*1.20*1.00*(0.25 - 0 + (0)) / (11.75 - 0.40*(0.25 - 0 + (0)))= 1,030.14 psi
49/103
Hot Shut Down, Corroded, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 6 / (π*11.8752*15,770.69*1.20)= 0"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*75.2 / (2*π*11.875*15,770.69*1.20)= 0"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0)|= 0"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*75.2 / (2*π*11.875*15,770.69*1.20)= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
Hot Shut Down, New, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 6 / (π*11.8752*15,770.69*1.20)= 0"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*75.2 / (2*π*11.875*15,770.69*1.20)= 0"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0)|= 0"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*75.2 / (2*π*11.875*15,770.69*1.20)= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
Empty, Corroded, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 6 / (π*11.8752*15,770.69*1.20)= 0"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*75.2 / (2*π*11.875*15,770.69*1.20)= 0"
50/103
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0)|= 0"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*75.2 / (2*π*11.875*15,770.69*1.20)= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
Empty, New, Seismic, Bottom Seam
tp = 0" (Pressure)tm = M / (π*Rm
2*Sc*Ks) (bending)= 6 / (π*11.8752*15,770.69*1.20)= 0"
tw = (0.6 - 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0.59*75.2 / (2*π*11.875*15,770.69*1.20)= 0"
tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0)|= 0"
twc = (1 + 0.14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1.01*75.2 / (2*π*11.875*15,770.69*1.20)= 0.0001"
tc = tmc + twc - tpc (total required, compressive)= 0 + (0.0001) - (0)= 0.0001"
51/103
Nozzle Schedule
Nozzlemark Service Size Materials Impact
Tested Normalized FineGrain Flange Blind
N1 N1 - 3" 300# RFLWN - Liquid Outlet 4.62 OD x 0.81 Nozzle SA-105 No No No NPS 3 Class 300LWN A105 No
N2 N2 - 3" 300# RFLWN - Vapor In 4.62 OD x 0.81 Nozzle SA-105 No No No NPS 3 Class 300LWN A105 No
N3 N3 - 1 1/2" 300# RFLWN - LevelGauge 2.75 OD x 0.625 Nozzle SA-105 No No No
NPS 1 1/2 Class300LWN A105
No
N4 N4 - 1 1/2" 300# RFLWN - LevelGauge 2.75 OD x 0.625 Nozzle SA-105 No No No
NPS 1 1/2 Class300LWN A105
No
N5 N5 - 2" 300# RFWN Drain NPS 2 Sch 80(XS) Nozzle SA-106 B Smls
pipe No No No NPS 2 Class 300WN A105 No
N6 N6 - 3" 300# RFWN Flare Outlet 4.62 OD x 0.81 Nozzle SA-105 No No No NPS 3 Class 300LWN A105 No
52/103
Nozzle Summary
Nozzlemark
OD(in)
tn
(in)Req t
n(in)
A1? A2?Shell Reinforcement
Pad Corr(in)
Aa/A
r(%)
Nom t(in)
Design t(in)
User t(in)
Width(in)
tpad(in)
N1 4.62 0.81 0.2258 Yes Yes 0.25 N/A N/A N/A 0 Exempt
N2 4.62 0.81 0.2258 Yes Yes 0.25 N/A N/A N/A 0 Exempt
N3 2.75 0.625 0.1776 Yes Yes 0.25 N/A N/A N/A 0 Exempt
N4 2.75 0.625 0.1776 Yes Yes 0.25 N/A N/A N/A 0 Exempt
N5 2.375 0.218 0.154 Yes Yes 0.1641* N/A N/A N/A 0 Exempt
N6 4.62 0.81 0.1799 Yes Yes 0.1632* N/A N/A N/A 0 Exempt
tn: Nozzle thicknessReq tn: Nozzle thickness required per UG-45/UG-16Nom t: Vessel wall thicknessDesign t: Required vessel wall thickness due to pressure + corrosion allowance per UG-37User t: Local vessel wall thickness (near opening)Aa: Area available per UG-37, governing conditionAr: Area required per UG-37, governing conditionCorr: Corrosion allowance on nozzle wall* Head minimum thickness after forming
53/103
N1 - 3" 300# RFLWN - Liquid Outlet (N1)
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
tw(lower) = 0.25 inLeg41 = 0.25 inLeg43 = 0.25 inhnew = 0.5 in
Note: round inside edges per UG-76(c)
Location and OrientationLocated on: Cylinder #1Orientation: 180°Nozzle center line offset to datum line: 6.75 inEnd of nozzle to shell center: 18 inPasses through a Category A joint: No
NozzleAccess opening: NoMaterial specification: SA-105 (II-D p. 18, ln. 5)Inside diameter, new: 3 inNominal wall thickness: 0.81 inCorrosion allowance: 0 inProjection available outside vessel, Lpr: 4.88 inInternal projection, hnew: 0.5 inProjection available outside vessel to flange face, Lf: 6 inLocal vessel minimum thickness: 0.25 inLiquid static head included: 1.475 psiLongitudinal joint efficiency: 1
ASME B16.5-2009 FlangeDescription: NPS 3 Class 300 LWN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Blind included: NoRated MDMT: -55°F per UCS-66(b)(1)(b)Liquid static head: 1.4371 psiMAWP rating: 740 psi @ 100°FMAP rating: 740 psi @ 70°FHydrotest rating: 1,125 psi @ 70°FPWHT performed: No
54/103
Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 420.17 psi @ 100 °F
UG-45Nozzle WallThicknessSummary
(in)The nozzle
passes UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.2258 0.81
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.175 0.175 weld size is adequate
Calculations for internal pressure 420.17 psi @ 100 °F
Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34 °F, (coincident ratio = 0.6601).
Nozzle UCS-66 governing thk: 0.25 inNozzle rated MDMT: -54 °FParallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(3, 1.5 + (0.81 - 0) + (0.25 - 0))= 3 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.25 - 0), 2.5*(0.81 - 0) + 0)= 0.625 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(2.5*(t - C), 2.5*(ti - Cn - C))= MIN(2.5*(0.25 - 0), 2.5*(0.81 - 0 - 0))= 0.625 in
55/103
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 420.1738*1.5 / (20,000*1 - 0.6*420.1738)= 0.0319 in
Required thickness tr from UG-37(a)
tr = P*Ro / (S*E + 0.4*P)= 420.1738*12 / (20,000*1 + 0.4*420.1738)= 0.25 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.25 intc(min) = lesser of 0.25 or 0.7*tmin = 0.175 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 420.1738*1.5 / (20,000*1 - 0.6*420.1738) + 0= 0.0319 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.0319 , 0 ]= 0.0319 in
tb1 = P*Ro / (S*E + 0.4*P) + Corrosion= 420.1738*12 / (20,000*1 + 0.4*420.1738) + 0= 0.25 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.25 , 0.0625 ]= 0.25 in
tb = min[ tb3 , tb1 ]= min[ 0.2258 , 0.25 ]= 0.2258 in
tUG-45 = max[ ta , tb ]
56/103
= max[ 0.0319 , 0.2258 ]= 0.2258 in
Available nozzle wall thickness new, tn = 0.81 in
The nozzle neck thickness is adequate.
57/103
Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 420.17 psi @ 70 °F
UG-45Nozzle WallThicknessSummary
(in)The nozzle
passes UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.2258 0.81
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.175 0.175 weld size is adequate
Calculations for internal pressure 420.17 psi @ 70 °F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(3, 1.5 + (0.81 - 0) + (0.25 - 0))= 3 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.25 - 0), 2.5*(0.81 - 0) + 0)= 0.625 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(2.5*(t - C), 2.5*(ti - Cn - C))= MIN(2.5*(0.25 - 0), 2.5*(0.81 - 0 - 0))= 0.625 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 420.1735*1.5 / (20,000*1 - 0.6*420.1735)= 0.0319 in
58/103
Required thickness tr from UG-37(a)
tr = P*Ro / (S*E + 0.4*P)= 420.1735*12 / (20,000*1 + 0.4*420.1735)= 0.25 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.25 intc(min) = lesser of 0.25 or 0.7*tmin = 0.175 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 420.1735*1.5 / (20,000*1 - 0.6*420.1735) + 0= 0.0319 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.0319 , 0 ]= 0.0319 in
tb1 = P*Ro / (S*E + 0.4*P) + Corrosion= 420.1735*12 / (20,000*1 + 0.4*420.1735) + 0= 0.25 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.25 , 0.0625 ]= 0.25 in
tb = min[ tb3 , tb1 ]= min[ 0.2258 , 0.25 ]= 0.2258 in
tUG-45 = max[ ta , tb ]= max[ 0.0319 , 0.2258 ]= 0.2258 in
Available nozzle wall thickness new, tn = 0.81 in
The nozzle neck thickness is adequate.
59/103
N2 - 3" 300# RFLWN - Vapor In (N2)
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
tw(lower) = 0.25 inLeg41 = 0.25 inLeg43 = 0.25 inhnew = 0.5 in
Note: round inside edges per UG-76(c)
Location and OrientationLocated on: Cylinder #1Orientation: 270°Nozzle center line offset to datum line: 25.5625 inEnd of nozzle to shell center: 18 inPasses through a Category A joint: No
NozzleAccess opening: NoMaterial specification: SA-105 (II-D p. 18, ln. 5)Inside diameter, new: 3 inNominal wall thickness: 0.81 inCorrosion allowance: 0 inProjection available outside vessel, Lpr: 4.88 inInternal projection, hnew: 0.5 inProjection available outside vessel to flange face, Lf: 6 inLocal vessel minimum thickness: 0.25 inLiquid static head included: 0.9997 psiLongitudinal joint efficiency: 1
ASME B16.5-2009 FlangeDescription: NPS 3 Class 300 LWN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Blind included: NoRated MDMT: -55°F per UCS-66(b)(1)(b)Liquid static head: 0.9618 psiMAWP rating: 740 psi @ 100°FMAP rating: 740 psi @ 70°FHydrotest rating: 1,125 psi @ 70°FPWHT performed: No
60/103
Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 420.17 psi @ 100 °F
UG-45Nozzle WallThicknessSummary
(in)The nozzle
passes UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.2258 0.81
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.175 0.175 weld size is adequate
Calculations for internal pressure 420.17 psi @ 100 °F
Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34.1 °F, (coincident ratio = 0.659).
Nozzle UCS-66 governing thk: 0.25 inNozzle rated MDMT: -54.1 °FParallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(3, 1.5 + (0.81 - 0) + (0.25 - 0))= 3 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.25 - 0), 2.5*(0.81 - 0) + 0)= 0.625 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(2.5*(t - C), 2.5*(ti - Cn - C))= MIN(2.5*(0.25 - 0), 2.5*(0.81 - 0 - 0))= 0.625 in
61/103
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 420.1715*1.5 / (20,000*1 - 0.6*420.1715)= 0.0319 in
Required thickness tr from UG-37(a)
tr = P*Ro / (S*E + 0.4*P)= 420.1715*12 / (20,000*1 + 0.4*420.1715)= 0.25 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.25 intc(min) = lesser of 0.25 or 0.7*tmin = 0.175 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 420.1715*1.5 / (20,000*1 - 0.6*420.1715) + 0= 0.0319 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.0319 , 0 ]= 0.0319 in
tb1 = P*Ro / (S*E + 0.4*P) + Corrosion= 420.1715*12 / (20,000*1 + 0.4*420.1715) + 0= 0.25 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.25 , 0.0625 ]= 0.25 in
tb = min[ tb3 , tb1 ]= min[ 0.2258 , 0.25 ]= 0.2258 in
tUG-45 = max[ ta , tb ]
62/103
= max[ 0.0319 , 0.2258 ]= 0.2258 in
Available nozzle wall thickness new, tn = 0.81 in
The nozzle neck thickness is adequate.
63/103
Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 420.17 psi @ 70 °F
UG-45Nozzle WallThicknessSummary
(in)The nozzle
passes UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.2258 0.81
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.175 0.175 weld size is adequate
Calculations for internal pressure 420.17 psi @ 70 °F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(3, 1.5 + (0.81 - 0) + (0.25 - 0))= 3 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.25 - 0), 2.5*(0.81 - 0) + 0)= 0.625 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(2.5*(t - C), 2.5*(ti - Cn - C))= MIN(2.5*(0.25 - 0), 2.5*(0.81 - 0 - 0))= 0.625 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 420.1735*1.5 / (20,000*1 - 0.6*420.1735)= 0.0319 in
64/103
Required thickness tr from UG-37(a)
tr = P*Ro / (S*E + 0.4*P)= 420.1735*12 / (20,000*1 + 0.4*420.1735)= 0.25 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.25 intc(min) = lesser of 0.25 or 0.7*tmin = 0.175 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 420.1735*1.5 / (20,000*1 - 0.6*420.1735) + 0= 0.0319 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.0319 , 0 ]= 0.0319 in
tb1 = P*Ro / (S*E + 0.4*P) + Corrosion= 420.1735*12 / (20,000*1 + 0.4*420.1735) + 0= 0.25 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.25 , 0.0625 ]= 0.25 in
tb = min[ tb3 , tb1 ]= min[ 0.2258 , 0.25 ]= 0.2258 in
tUG-45 = max[ ta , tb ]= max[ 0.0319 , 0.2258 ]= 0.2258 in
Available nozzle wall thickness new, tn = 0.81 in
The nozzle neck thickness is adequate.
65/103
N3 - 1 1/2" 300# RFLWN - Level Gauge (N3)
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
tw(lower) = 0.25 inLeg41 = 0.25 inLeg43 = 0.25 inhnew = 0.5 in
Note: round inside edges per UG-76(c)
Location and OrientationLocated on: Cylinder #1Orientation: 315°Nozzle center line offset to datum line: 66 inEnd of nozzle to shell center: 18 inPasses through a Category A joint: No
NozzleAccess opening: NoMaterial specification: SA-105 (II-D p. 18, ln. 5)Inside diameter, new: 1.5 inNominal wall thickness: 0.625 inCorrosion allowance: 0 inProjection available outside vessel, Lpr: 5.19 inInternal projection, hnew: 0.5 inProjection available outside vessel to flange face, Lf: 6 inLocal vessel minimum thickness: 0.25 inLiquid static head included: 0 psiLongitudinal joint efficiency: 1
ASME B16.5-2009 FlangeDescription: NPS 1.5 Class 300 LWN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Blind included: NoRated MDMT: -55°F per UCS-66(b)(1)(b)Liquid static head: 0 psiMAWP rating: 740 psi @ 100°FMAP rating: 740 psi @ 70°FHydrotest rating: 1,125 psi @ 70°FPWHT performed: No
66/103
Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 420.17 psi @ 100 °F
UG-45 NozzleWall
ThicknessSummary (in)The nozzle passes
UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.1776 0.625
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.175 0.175 weld size is adequate
Calculations for internal pressure 420.17 psi @ 100 °F
Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34.3 °F, (coincident ratio = 0.6566).
Nozzle UCS-66 governing thk: 0.25 inNozzle rated MDMT: -54.3 °FParallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(1.5, 0.75 + (0.625 - 0) + (0.25 - 0))= 1.625 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.25 - 0), 2.5*(0.625 - 0) + 0)= 0.625 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(2.5*(t - C), 2.5*(ti - Cn - C))= MIN(2.5*(0.25 - 0), 2.5*(0.625 - 0 - 0))= 0.625 in
67/103
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 420.1735*0.75 / (20,000*1 - 0.6*420.1735)= 0.016 in
Required thickness tr from UG-37(a)
tr = P*Ro / (S*E + 0.4*P)= 420.1735*12 / (20,000*1 + 0.4*420.1735)= 0.25 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.25 intc(min) = lesser of 0.25 or 0.7*tmin = 0.175 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 420.1735*0.75 / (20,000*1 - 0.6*420.1735) + 0= 0.016 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.016 , 0 ]= 0.016 in
tb1 = P*Ro / (S*E + 0.4*P) + Corrosion= 420.1735*12 / (20,000*1 + 0.4*420.1735) + 0= 0.25 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.25 , 0.0625 ]= 0.25 in
tb = min[ tb3 , tb1 ]= min[ 0.1776 , 0.25 ]= 0.1776 in
tUG-45 = max[ ta , tb ]
68/103
= max[ 0.016 , 0.1776 ]= 0.1776 in
Available nozzle wall thickness new, tn = 0.625 in
The nozzle neck thickness is adequate.
69/103
Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 420.17 psi @ 70 °F
UG-45 NozzleWall
ThicknessSummary (in)The nozzle passes
UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.1776 0.625
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.175 0.175 weld size is adequate
Calculations for internal pressure 420.17 psi @ 70 °F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(1.5, 0.75 + (0.625 - 0) + (0.25 - 0))= 1.625 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.25 - 0), 2.5*(0.625 - 0) + 0)= 0.625 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(2.5*(t - C), 2.5*(ti - Cn - C))= MIN(2.5*(0.25 - 0), 2.5*(0.625 - 0 - 0))= 0.625 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 420.1735*0.75 / (20,000*1 - 0.6*420.1735)= 0.016 in
70/103
Required thickness tr from UG-37(a)
tr = P*Ro / (S*E + 0.4*P)= 420.1735*12 / (20,000*1 + 0.4*420.1735)= 0.25 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.25 intc(min) = lesser of 0.25 or 0.7*tmin = 0.175 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 420.1735*0.75 / (20,000*1 - 0.6*420.1735) + 0= 0.016 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.016 , 0 ]= 0.016 in
tb1 = P*Ro / (S*E + 0.4*P) + Corrosion= 420.1735*12 / (20,000*1 + 0.4*420.1735) + 0= 0.25 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.25 , 0.0625 ]= 0.25 in
tb = min[ tb3 , tb1 ]= min[ 0.1776 , 0.25 ]= 0.1776 in
tUG-45 = max[ ta , tb ]= max[ 0.016 , 0.1776 ]= 0.1776 in
Available nozzle wall thickness new, tn = 0.625 in
The nozzle neck thickness is adequate.
71/103
N4 - 1 1/2" 300# RFLWN - Level Gauge (N4)
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
tw(lower) = 0.25 inLeg41 = 0.25 inLeg43 = 0.25 inhnew = 0.5 in
Note: round inside edges per UG-76(c)
Location and OrientationLocated on: Cylinder #1Orientation: 315°Nozzle center line offset to datum line: 6 inEnd of nozzle to shell center: 18 inPasses through a Category A joint: No
NozzleAccess opening: NoMaterial specification: SA-105 (II-D p. 18, ln. 5)Inside diameter, new: 1.5 inNominal wall thickness: 0.625 inCorrosion allowance: 0 inProjection available outside vessel, Lpr: 5.19 inInternal projection, hnew: 0.5 inProjection available outside vessel to flange face, Lf: 6 inLocal vessel minimum thickness: 0.25 inLiquid static head included: 1.475 psiLongitudinal joint efficiency: 1
ASME B16.5-2009 FlangeDescription: NPS 1.5 Class 300 LWN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Blind included: NoRated MDMT: -55°F per UCS-66(b)(1)(b)Liquid static head: 1.4561 psiMAWP rating: 740 psi @ 100°FMAP rating: 740 psi @ 70°FHydrotest rating: 1,125 psi @ 70°FPWHT performed: No
72/103
Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 420.17 psi @ 100 °F
UG-45 NozzleWall
ThicknessSummary (in)The nozzle passes
UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.1776 0.625
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.175 0.175 weld size is adequate
Calculations for internal pressure 420.17 psi @ 100 °F
Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 34 °F, (coincident ratio = 0.6601).
Nozzle UCS-66 governing thk: 0.25 inNozzle rated MDMT: -54 °FParallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(1.5, 0.75 + (0.625 - 0) + (0.25 - 0))= 1.625 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.25 - 0), 2.5*(0.625 - 0) + 0)= 0.625 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(2.5*(t - C), 2.5*(ti - Cn - C))= MIN(2.5*(0.25 - 0), 2.5*(0.625 - 0 - 0))= 0.625 in
73/103
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 420.1738*0.75 / (20,000*1 - 0.6*420.1738)= 0.016 in
Required thickness tr from UG-37(a)
tr = P*Ro / (S*E + 0.4*P)= 420.1738*12 / (20,000*1 + 0.4*420.1738)= 0.25 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.25 intc(min) = lesser of 0.25 or 0.7*tmin = 0.175 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 420.1738*0.75 / (20,000*1 - 0.6*420.1738) + 0= 0.016 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.016 , 0 ]= 0.016 in
tb1 = P*Ro / (S*E + 0.4*P) + Corrosion= 420.1738*12 / (20,000*1 + 0.4*420.1738) + 0= 0.25 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.25 , 0.0625 ]= 0.25 in
tb = min[ tb3 , tb1 ]= min[ 0.1776 , 0.25 ]= 0.1776 in
tUG-45 = max[ ta , tb ]
74/103
= max[ 0.016 , 0.1776 ]= 0.1776 in
Available nozzle wall thickness new, tn = 0.625 in
The nozzle neck thickness is adequate.
75/103
Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 420.17 psi @ 70 °F
UG-45 NozzleWall
ThicknessSummary (in)The nozzle passes
UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.1776 0.625
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.175 0.175 weld size is adequate
Calculations for internal pressure 420.17 psi @ 70 °F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(1.5, 0.75 + (0.625 - 0) + (0.25 - 0))= 1.625 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.25 - 0), 2.5*(0.625 - 0) + 0)= 0.625 in
Inner Normal Limit of reinforcement per UG-40
LI = MIN(2.5*(t - C), 2.5*(ti - Cn - C))= MIN(2.5*(0.25 - 0), 2.5*(0.625 - 0 - 0))= 0.625 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 420.1735*0.75 / (20,000*1 - 0.6*420.1735)= 0.016 in
76/103
Required thickness tr from UG-37(a)
tr = P*Ro / (S*E + 0.4*P)= 420.1735*12 / (20,000*1 + 0.4*420.1735)= 0.25 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.25 intc(min) = lesser of 0.25 or 0.7*tmin = 0.175 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 420.1735*0.75 / (20,000*1 - 0.6*420.1735) + 0= 0.016 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.016 , 0 ]= 0.016 in
tb1 = P*Ro / (S*E + 0.4*P) + Corrosion= 420.1735*12 / (20,000*1 + 0.4*420.1735) + 0= 0.25 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.25 , 0.0625 ]= 0.25 in
tb = min[ tb3 , tb1 ]= min[ 0.1776 , 0.25 ]= 0.1776 in
tUG-45 = max[ ta , tb ]= max[ 0.016 , 0.1776 ]= 0.1776 in
Available nozzle wall thickness new, tn = 0.625 in
The nozzle neck thickness is adequate.
77/103
N5 - 2" 300# RFWN Drain (N5)
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
tw(lower) = 0.1641 inLeg41 = 0.25 in
Note: round inside edges per UG-76(c)
Location and OrientationLocated on: Ellipsoidal Head #1Orientation: 0°End of nozzle to datum line: -17.125 inCalculated as hillside: NoDistance to head center, R: 0 inPasses through a Category A joint: No
NozzleAccess opening: NoMaterial specification: SA-106 B Smls pipe (II-D p. 10, ln. 40)Description: NPS 2 Sch 80 (XS)Inside diameter, new: 1.939 inNominal wall thickness: 0.218 inCorrosion allowance: 0 inProjection available outside vessel, Lpr: 6.3228 inProjection available outside vessel to flange face, Lf: 9.0728 inLocal vessel minimum thickness: 0.1641 inLiquid static head included: 2.0362 psiLongitudinal joint efficiency: 1
ASME B16.5-2009 FlangeDescription: NPS 2 Class 300 WN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Blind included: NoRated MDMT: -55°F per UCS-66(b)(1)(b)Liquid static head: 2.0404 psiMAWP rating: 740 psi @ 100°FMAP rating: 740 psi @ 70°FHydrotest rating: 1,125 psi @ 70°F
78/103
PWHT performed: NoCircumferential joint radiography: Full UW-11(a) Type 1
79/103
Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 305.75 psi @ 100 °F
UG-45 NozzleWall
ThicknessSummary (in)The nozzle passes
UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.1348 0.1908
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.1149 0.175 weld size is adequate
Calculations for internal pressure 305.75 psi @ 100 °F
Fig UCS-66.2 general note (1) applies.
Nozzle is impact test exempt per UCS-66(d) (NPS 4 or smaller pipe).
Nozzle UCS-66 governing thk: 0.1641 inNozzle rated MDMT: -155 °FParallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(1.939, 0.9695 + (0.218 - 0) + (0.1641 - 0))= 1.939 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.1641 - 0), 2.5*(0.218 - 0) + 0)= 0.4103 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 305.75*0.9695 / (17,100*1 - 0.6*305.75)= 0.0175 in
80/103
Required thickness tr from UG-37(a)(c)
tr = P*K1*Do / (2*S*E + 0.8*P)= 305.75*0.9*24 / (2*20,000*1 + 0.8*305.75)= 0.1641 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.1641 intc(min) = lesser of 0.25 or 0.7*tmin = 0.1149 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
Interpretation VIII-1-83-66 has been applied.
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 305.7542*0.9695 / (17,100*1 - 0.6*305.7542) + 0= 0.0175 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.0175 , 0 ]= 0.0175 in
tb1 = 0.181 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.181 , 0.0625 ]= 0.181 in
tb = min[ tb3 , tb1 ]= min[ 0.1348 , 0.181 ]= 0.1348 in
tUG-45 = max[ ta , tb ]= max[ 0.0175 , 0.1348 ]= 0.1348 in
Available nozzle wall thickness new, tn = 0.875*0.218 = 0.1908 in
The nozzle neck thickness is adequate.
81/103
Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 305.75 psi @ 70 °F
UG-45 NozzleWall
ThicknessSummary (in)The nozzle passes
UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.1348 0.1908
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.1149 0.175 weld size is adequate
Calculations for internal pressure 305.75 psi @ 70 °F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(1.939, 0.9695 + (0.218 - 0) + (0.1641 - 0))= 1.939 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.1641 - 0), 2.5*(0.218 - 0) + 0)= 0.4103 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 305.7542*0.9695 / (17,100*1 - 0.6*305.7542)= 0.0175 in
Required thickness tr from UG-37(a)(c)
tr = P*K1*Do / (2*S*E + 0.8*P)= 305.7542*0.9*24 / (2*20,000*1 + 0.8*305.7542)= 0.1641 in
This opening does not require reinforcement per UG-36(c)(3)(a)
82/103
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.1641 intc(min) = lesser of 0.25 or 0.7*tmin = 0.1149 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
Interpretation VIII-1-83-66 has been applied.
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 305.7542*0.9695 / (17,100*1 - 0.6*305.7542) + 0= 0.0175 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.0175 , 0 ]= 0.0175 in
tb1 = 0.181 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.181 , 0.0625 ]= 0.181 in
tb = min[ tb3 , tb1 ]= min[ 0.1348 , 0.181 ]= 0.1348 in
tUG-45 = max[ ta , tb ]= max[ 0.0175 , 0.1348 ]= 0.1348 in
Available nozzle wall thickness new, tn = 0.875*0.218 = 0.1908 in
The nozzle neck thickness is adequate.
83/103
N6 - 3" 300# RFWN Flare Outlet (N6)
ASME Section VIII Division 1, 2010 Edition, A11 Addenda
tw(lower) = 0.1632 inLeg41 = 0.25 in
Note: round inside edges per UG-76(c)
Location and OrientationLocated on: Ellipsoidal Head #2Orientation: 0°End of nozzle to datum line: 88.25 inCalculated as hillside: NoDistance to head center, R: 0 inPasses through a Category A joint: No
NozzleAccess opening: NoMaterial specification: SA-105 (II-D p. 18, ln. 5)Inside diameter, new: 3 inNominal wall thickness: 0.81 inCorrosion allowance: 0 inProjection available outside vessel, Lpr: 7.1622 inProjection available outside vessel to flange face, Lf: 8.2822 inLocal vessel minimum thickness: 0.1632 inLiquid static head included: 0 psiLongitudinal joint efficiency: 1
ASME B16.5-2009 FlangeDescription: NPS 3 Class 300 LWN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Blind included: NoRated MDMT: -55°F per UCS-66(b)(1)(b)Liquid static head: 0 psiMAWP rating: 740 psi @ 100°FMAP rating: 740 psi @ 70°FHydrotest rating: 1,125 psi @ 70°FPWHT performed: No
84/103
Reinforcement Calculations for MAWP
The vessel wall thickness governs the MAWP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 303.99 psi @ 100 °F
UG-45Nozzle WallThicknessSummary
(in)The nozzle
passes UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.1799 0.81
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.1142 0.175 weld size is adequate
Calculations for internal pressure 303.99 psi @ 100 °F
Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -20 °FFig UCS-66.1 MDMT reduction = 9.5 °F, (coincident ratio = 0.9055).
Nozzle UCS-66 governing thk: 0.1632 inNozzle rated MDMT: -29.5 °FParallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(3, 1.5 + (0.81 - 0) + (0.1632 - 0))= 3 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.1632 - 0), 2.5*(0.81 - 0) + 0)= 0.4079 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 303.992*1.5 / (20,000*1 - 0.6*303.992)= 0.023 in
85/103
Required thickness tr from UG-37(a)(c)
tr = P*K1*Do / (2*S*E + 0.8*P)= 303.992*0.9*24 / (2*20,000*1 + 0.8*303.992)= 0.1632 in
This opening does not require reinforcement per UG-36(c)(3)(a)
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.1632 intc(min) = lesser of 0.25 or 0.7*tmin = 0.1142 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
Interpretation VIII-1-83-66 has been applied.
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 303.992*1.5 / (20,000*1 - 0.6*303.992) + 0= 0.023 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.023 , 0 ]= 0.023 in
tb1 = 0.1799 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.1799 , 0.0625 ]= 0.1799 in
tb = min[ tb3 , tb1 ]= min[ 0.2258 , 0.1799 ]= 0.1799 in
tUG-45 = max[ ta , tb ]= max[ 0.023 , 0.1799 ]= 0.1799 in
Available nozzle wall thickness new, tn = 0.81 in
The nozzle neck thickness is adequate.
86/103
Reinforcement Calculations for MAP
The vessel wall thickness governs the MAP of this nozzle.
UG-37 Area Calculation Summary(in2)
For P = 303.99 psi @ 70 °F
UG-45Nozzle WallThicknessSummary
(in)The nozzle
passes UG-45
Arequired
Aavailable A1 A2 A3 A5
Awelds treq tmin
This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0.1799 0.81
UG-41 Weld Failure Path Analysis Summary
The nozzle is exempt from weld strength calculationsper UW-15(b)(2)
UW-16 Weld Sizing Summary
Weld description Required weldthroat size (in)
Actual weldthroat size (in) Status
Nozzle to shell fillet (Leg41) 0.1142 0.175 weld size is adequate
Calculations for internal pressure 303.99 psi @ 70 °F
Parallel Limit of reinforcement per UG-40
LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(3, 1.5 + (0.81 - 0) + (0.1632 - 0))= 3 in
Outer Normal Limit of reinforcement per UG-40
LH = MIN(2.5*(t - C), 2.5*(tn - Cn) + te)= MIN(2.5*(0.1632 - 0), 2.5*(0.81 - 0) + 0)= 0.4079 in
Nozzle required thickness per UG-27(c)(1)
trn = P*Rn / (Sn*E - 0.6*P)= 303.992*1.5 / (20,000*1 - 0.6*303.992)= 0.023 in
Required thickness tr from UG-37(a)(c)
tr = P*K1*Do / (2*S*E + 0.8*P)= 303.992*0.9*24 / (2*20,000*1 + 0.8*303.992)= 0.1632 in
This opening does not require reinforcement per UG-36(c)(3)(a)
87/103
UW-16(c) Weld Check
Fillet weld: tmin = lesser of 0.75 or tn or t = 0.1632 intc(min) = lesser of 0.25 or 0.7*tmin = 0.1142 intc(actual) = 0.7*Leg = 0.7*0.25 = 0.175 in
The fillet weld size is satisfactory.
Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).
UG-45 Nozzle Neck Thickness Check
Interpretation VIII-1-83-66 has been applied.
ta UG-27 = P*R / (S*E - 0.6*P) + Corrosion= 303.992*1.5 / (20,000*1 - 0.6*303.992) + 0= 0.023 in
ta = max[ ta UG-27 , ta UG-22 ]= max[ 0.023 , 0 ]= 0.023 in
tb1 = 0.1799 in
tb1 = max[ tb1 , tb UG16 ]= max[ 0.1799 , 0.0625 ]= 0.1799 in
tb = min[ tb3 , tb1 ]= min[ 0.2258 , 0.1799 ]= 0.1799 in
tUG-45 = max[ ta , tb ]= max[ 0.023 , 0.1799 ]= 0.1799 in
Available nozzle wall thickness new, tn = 0.81 in
The nozzle neck thickness is adequate.
88/103
Support Skirt #1
Material: SA-516 70 (II-D p. 18, ln. 19)Design temperature, operating: 100 °FInner diameter at top, new: 23.625inInner diameter at bottom, new: 23.625inOverall length (includes base ring thickness): 26.625inCorrosion allowance inside: 0 inCorrosion allowance outside: 0 inWeld joint efficiency top: 0.55Weld joint efficiency bottom: 0.8Nominal thickness, new: 0.1875inSkirt is attached to: Ellipsoidal Head #1Skirt attachment offset: 3.0665in down from the top seam
Skirt design thickness, largest of the following + corrosion = 0.004 in
The governing condition is due to wind, compressive stress at the base, operating & corroded.
The skirt thickness of 0.1875 in is adequate.
LoadingVessel
Condition(Stress)
GoverningSkirt
Location
Temperature(°F)
AllowableStress(psi)
CalculatedStress/E
(psi)
Requiredthickness
(in)
Wind operating, corroded (+) bottom 100 20,000 189.22 0.0018
Wind operating, corroded (-) bottom 100 14,898.49 318.71 0.004
Wind empty, corroded (+) bottom 70 20,000 230.15 0.0022
Wind empty, corroded (-) bottom 70 14,898.49 264.13 0.0033
Wind test, new (+) bottom 70 14,898.49 -75.28 0.0009
Wind test, new (-) bottom 70 14,898.49 155.48 0.002
Seismic operating, corroded (+) bottom 100 14,898.49 -40.99 0.0005
Seismic operating, corroded (-) bottom 100 14,898.49 126.35 0.0016
Seismic empty, corroded (+) bottom 70 14,898.49 -13.01 0.0002
Seismic empty, corroded (-) bottom 70 14,898.49 67 0.0008
Loading due to wind, operating & corroded
Windward side (tensile)
Required thickness, tensile stress at base:
t = -0.6*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -0.6*1,466.99 / (π*23.8125*20,000*0.8) + 48*1,490 / (π*23.81252*20,000*0.8)= 0.0018 in
Required thickness, tensile stress at the top:
t = -0.6*Wt / (π*Dt*St*E) + 48*Mt / (π*Dt2*St*E)
= -0.6*1,360.52 / (π*23.8125*20,000*0.55) + 48*882.1 / (π*23.81252*20,000*0.55)= 0.0012 in
89/103
Leeward side (compressive)
Required thickness, compressive stress at base:
t = W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= 1,466.99 / (π*23.8125*14,898*1) + 48*1,490 / (π*23.81252*14,898*1)= 0.004 in
Required thickness, compressive stress at the top:
t = Wt / (π*Dt*Sc*Ec) + 48*Mt / (π*Dt2*Sc*Ec)
= 1,360.52 / (π*23.8125*14,898*1) + 48*882.1 / (π*23.81252*14,898*1)= 0.0028 in
Loading due to wind, empty & corroded
Windward side (tensile)
Required thickness, tensile stress at base:
t = -0.6*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -0.6*701.45 / (π*23.8125*20,000*0.8) + 48*1,490 / (π*23.81252*20,000*0.8)= 0.0022 in
Required thickness, tensile stress at the top:
t = -0.6*Wt / (π*Dt*St*E) + 48*Mt / (π*Dt2*St*E)
= -0.6*594.98 / (π*23.8125*20,000*0.55) + 48*882.1 / (π*23.81252*20,000*0.55)= 0.0017 in
Leeward side (compressive)
Required thickness, compressive stress at base:
t = W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= 701.45 / (π*23.8125*14,898*1) + 48*1,490 / (π*23.81252*14,898*1)= 0.0033 in
Required thickness, compressive stress at the top:
t = Wt / (π*Dt*Sc*Ec) + 48*Mt / (π*Dt2*Sc*Ec)
= 594.98 / (π*23.8125*14,898*1) + 48*882.1 / (π*23.81252*14,898*1)= 0.0021 in
Loading due to wind, test & new
90/103
Windward side (tensile)
Required thickness, tensile stress at base:
t = -0.6*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -0.6*2,023.01 / (π*23.8125*14,898*1) + 48*78.3 / (π*23.81252*14,898*1)= 0.0009 in
Required thickness, tensile stress at the top:
t = -0.6*Wt / (π*Dt*St*E) + 48*Mt / (π*Dt2*St*E)
= -0.6*1,916.54 / (π*23.8125*14,898*1) + 48*78.3 / (π*23.81252*14,898*1)= 0.0009 in
Leeward side (compressive)
Required thickness, compressive stress at base:
t = W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= 2,023.01 / (π*23.8125*14,898*1) + 48*78.3 / (π*23.81252*14,898*1)= 0.002 in
Required thickness, compressive stress at the top:
t = Wt / (π*Dt*Sc*Ec) + 48*Mt / (π*Dt2*Sc*Ec)
= 1,916.54 / (π*23.8125*14,898*1) + 48*78.3 / (π*23.81252*14,898*1)= 0.0019 in
Loading due to earthquake, operating & corroded
Tensile side
Required thickness, tensile stress at base:
t = -(0.6 - 0.14*SDS)*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -(0.6 - 0.14*0.08)*1,466.99 / (π*23.8125*14,898*1) + 48*143.3 / (π*23.81252*14,898*1)= 0.0005 in
Required thickness, tensile stress at the top:
t = -(0.6 - 0.14*SDS)*Wt / (π*Dt*St*E) + 48*Mt / (π*Dt2*St*E)
= -(0.6 - 0.14*0.08)*1,360.52 / (π*23.8125*14,898*1) + 48*116.8 / (π*23.81252*14,898*1)= 0.0005 in
Compressive side
91/103
Required thickness, compressive stress at base:
t = (1 + 0.14*SDS)*W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= (1 + 0.14*0.08)*1,466.99 / (π*23.8125*14,898*1) + 48*143.3 / (π*23.81252*14,898*1)= 0.0016 in
Required thickness, compressive stress at the top:
t = (1 + 0.14*SDS)*Wt / (π*Dt*Sc*Ec) + 48*Mt / (π*Dt2*Sc*Ec)
= (1 + 0.14*0.08)*1,360.52 / (π*23.8125*14,898*1) + 48*116.8 / (π*23.81252*14,898*1)= 0.0014 in
Loading due to earthquake, empty & corroded
Tensile side
Required thickness, tensile stress at base:
t = -(0.6 - 0.14*SDS)*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -(0.6 - 0.14*0.08)*701.45 / (π*23.8125*14,898*1) + 48*114.4 / (π*23.81252*14,898*1)= 0.0002 in
Required thickness, tensile stress at the top:
t = -(0.6 - 0.14*SDS)*Wt / (π*Dt*St*E) + 48*Mt / (π*Dt2*St*E)
= -(0.6 - 0.14*0.08)*594.98 / (π*23.8125*14,898*1) + 48*99.8 / (π*23.81252*14,898*1)= 0.0001 in
Compressive side
Required thickness, compressive stress at base:
t = (1 + 0.14*SDS)*W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= (1 + 0.14*0.08)*701.45 / (π*23.8125*14,898*1) + 48*114.4 / (π*23.81252*14,898*1)= 0.0008 in
Required thickness, compressive stress at the top:
t = (1 + 0.14*SDS)*Wt / (π*Dt*Sc*Ec) + 48*Mt / (π*Dt2*Sc*Ec)
= (1 + 0.14*0.08)*594.98 / (π*23.8125*14,898*1) + 48*99.8 / (π*23.81252*14,898*1)= 0.0007 in
92/103
Skirt Opening (SO)
ASME Section VIII, Division 2, 2010 Edition, A11 Addenda
Component Skirt Opening
Description Skirt Opening
Drawing Mark SO
Opening forNozzle N5 - 2" 300# RFWN Drain (N5)
Sleeve Material SA-106 B Smls pipe (II-D p. 10, ln. 40)
Location and Orientation
Attached to Support Skirt #1
Orientation radial
Offset, L 17.125"
Angle, θ 0°
Distance, r 12.5"
Through aCategory B Joint No
Dimensions
Pipe NPS andSchedule NPS 6 Sch 80 (XS)
Inside Diameter 5.761"
Nominal WallThickness 0.432"
Skirt Thickness 0.1875"
Leg41 0.25"
ExternalProjection
Available, Lpr1
0.5"
Corrosion Inner 0"
Outer 0"
93/103
Skirt Opening Reinforcement Summary
RequiredThickness
tr(in)
AT(in2)
Ar(in2) Ratio Status
Operating Hot & CorrodedWind Tensile 0.0009 1.116 0.0054 206.1583 OK
Compressive 0.0032 0.6151 0.0187 32.9219 OK
Seismic Tensile 0 0.6221 0 N/A OK
Compressive 0.0015 0.6189 0.0086 71.7272 OK
Empty Cold & CorrodedWind Tensile 0.0012 1.1148 0.0072 154.4035 OK
Compressive 0.0026 0.6166 0.0147 41.8703 OK
Seismic Tensile 0 0.6221 0 N/A OK
Compressive 0.0008 0.6205 0.0044 140.8571 OK
Shop Test New Wind Tensile 0 0.6221 0 N/A OK
Compressive 0.0019 0.618 0.0109 56.5854 OKNote: Skirt required thickness of zero on tensile side indicates load is compressive.
Openings Subject to Axial Tension
LR = min[ (Reff*t)0.5, 2*Rn] (4.5.4)
LH1 = min[ 1.5*t , te] + (Rn*tn)0.5 (4.5.11)
LH2 = Lpr1 (4.5.12)
LH3 = 8*(t + te) (4.5.13)
LH = min[ LH1, LH2, LH3] + t (4.5.14)
fr1 = min[ Sn / S , 1 ]
fr2 = min[ Sn / S , 1 ]
A1 = 2*LR*(E1*t - tr)
A2 = 2*(LH - tr)*tn*fr2
A41 = L412*fr2
AT = A1 + A2 + A41
Ar = d*tr + 2*tn*tr*(1 - fr1)
Corroded
LR = min[ (11.8125*0.1875)0.5, 2*2.8805] = 1.4882"
LH1 = min[ 1.5*0.1875 , 0] + (2.8805*0.432)0.5 = 1.1155"
LH2 = 0.5 = 0.5"
LH3 = 8*(0.1875 + 0) = 1.5"
LH = min[ 1.1155, 0.5, 1.5] + 0.1875 = 0.6875"
Operating Hot & Corroded Wind Tensile
94/103
fr1 = min[ 17,100 / 20,000 , 1 ] = 0.855
fr2 = min[ 17,100 / 20,000 , 1 ] = 0.855
A1 = 2*1.4882*(1*0.1875 - 0.0009) = 0.5554 in2
A2 = 2*(0.6875 - 0.0009)*0.432*0.855 = 0.5072 in2
A41 = 0.252*0.855 = 0.0534 in2
AT = 0.5554 + 0.5072 + 0.0534 = 1.116 in2
Ar = 5.761*0.0009 + 2*0.432*0.0009*(1 - 0.855) = 0.0054 in2
AT = 1.116 in2 ≥ Ar = 0.0054 in2
Empty Cold & Corroded Wind Tensile
fr1 = min[ 17,100 / 20,000 , 1 ] = 0.855
fr2 = min[ 17,100 / 20,000 , 1 ] = 0.855
A1 = 2*1.4882*(1*0.1875 - 0.0012) = 0.5544 in2
A2 = 2*(0.6875 - 0.0012)*0.432*0.855 = 0.507 in2
A41 = 0.252*0.855 = 0.0534 in2
AT = 0.5544 + 0.507 + 0.0534 = 1.1148 in2
Ar = 5.761*0.0012 + 2*0.432*0.0012*(1 - 0.855) = 0.0072 in2
AT = 1.1148 in2 ≥ Ar = 0.0072 in2
Division 2 4.5.17.3 Openings Subject to Axial Compression
γn = d / {2*(R*t)0.5} (4.5.212)
γn > {(R / t) / 291 + 0.22}2
tn,eff = min[ tn , t]
LR = 0.75*(R*t)0.5
LH = min[0.5*{(d / 2)*tn}0.5 , 2.5*tn , Lpr1 ]
fr1 = min[ Sn / S , 1 ]
fr2 = min[ Sn / S , 1 ]
A1 = 2*LR*(t - tr) - 2*tn,eff*(t - tr)*(1 - fr1)
A2 = 2*LH*tn,eff*fr2
A41 = L412*fr2
AT = A1 + A2 + A41
Ar = d*tr (4.5.211)
New
γn = 5.761 / {2*(11.8125*0.1875)0.5} = 1.9355
γn > {(11.8125 / 0.1875) / 291 + 0.22}2 = 0.1905
95/103
Area required factor for compressive side = 1
LR = 0.75*(11.8125*0.1875)0.5 = 1.1162"
LH = min[0.5*{(5.761 / 2)*0.432}0.5 , 2.5*0.432 , 0.5 ] = 0.5"
tn,eff = min[ 0.432 , 0.1875] = 0.1875"
Corroded
γn = 5.761 / {2*(11.8125*0.1875)0.5} = 1.9355
γn > {(11.8125 / 0.1875) / 291 + 0.22}2 = 0.1905
Area required factor for compressive side = 1
LR = 0.75*(11.8125*0.1875)0.5 = 1.1162"
LH = min[0.5*{(5.761 / 2)*0.432}0.5 , 2.5*0.432 , 0.5 ] = 0.5"
tn,eff = min[ 0.432 , 0.1875] = 0.1875"
Operating Hot & Corroded Wind Compressive
fr1 = min[ 17,100 / 20,000 , 1 ] = 0.855
fr2 = min[ 17,100 / 20,000 , 1 ] = 0.855
A1 = 2*1.1162*(0.1875 - 0.0032) - 2*0.1875*(0.1875 - 0.0032)*(1 - 0.855) = 0.4013 in2
A2 = 2*0.5*0.1875*0.855 = 0.1603 in2
A41 = 0.252*0.855 = 0.0534 in2
AT = 0.4013 + 0.1603 + 0.0534 = 0.6151 in2
Ar = 5.761*0.0032 = 0.0187 in2
AT = 0.6151 in2 ≥ Ar = 0.0187 in2
Empty Cold & Corroded Wind Compressive
fr1 = min[ 17,100 / 20,000 , 1 ] = 0.855
fr2 = min[ 17,100 / 20,000 , 1 ] = 0.855
A1 = 2*1.1162*(0.1875 - 0.0026) - 2*0.1875*(0.1875 - 0.0026)*(1 - 0.855) = 0.4028 in2
A2 = 2*0.5*0.1875*0.855 = 0.1603 in2
A41 = 0.252*0.855 = 0.0534 in2
AT = 0.4028 + 0.1603 + 0.0534 = 0.6166 in2
Ar = 5.761*0.0026 = 0.0147 in2
AT = 0.6166 in2 ≥ Ar = 0.0147 in2
Shop Test New Wind Compressive
fr1 = min[ 17,100 / 20,000 , 1 ] = 0.855
fr2 = min[ 17,100 / 20,000 , 1 ] = 0.855
A1 = 2*1.1162*(0.1875 - 0.0019) - 2*0.1875*(0.1875 - 0.0019)*(1 - 0.855) = 0.4042 in2
A2 = 2*0.5*0.1875*0.855 = 0.1603 in2
A41 = 0.252*0.855 = 0.0534 in2
96/103
AT = 0.4042 + 0.1603 + 0.0534 = 0.618 in2
Ar = 5.761*0.0019 = 0.0109 in2
AT = 0.618 in2 ≥ Ar = 0.0109 in2
Operating Hot & Corroded Seismic Compressive
fr1 = min[ 17,100 / 20,000 , 1 ] = 0.855
fr2 = min[ 17,100 / 20,000 , 1 ] = 0.855
A1 = 2*1.1162*(0.1875 - 0.0015) - 2*0.1875*(0.1875 - 0.0015)*(1 - 0.855) = 0.4051 in2
A2 = 2*0.5*0.1875*0.855 = 0.1603 in2
A41 = 0.252*0.855 = 0.0534 in2
AT = 0.4051 + 0.1603 + 0.0534 = 0.6189 in2
Ar = 5.761*0.0015 = 0.0086 in2
AT = 0.6189 in2 ≥ Ar = 0.0086 in2
Empty Cold & Corroded Seismic Compressive
fr1 = min[ 17,100 / 20,000 , 1 ] = 0.855
fr2 = min[ 17,100 / 20,000 , 1 ] = 0.855
A1 = 2*1.1162*(0.1875 - 0.0008) - 2*0.1875*(0.1875 - 0.0008)*(1 - 0.855) = 0.4067 in2
A2 = 2*0.5*0.1875*0.855 = 0.1603 in2
A41 = 0.252*0.855 = 0.0534 in2
AT = 0.4067 + 0.1603 + 0.0534 = 0.6205 in2
Ar = 5.761*0.0008 = 0.0044 in2
AT = 0.6205 in2 ≥ Ar = 0.0044 in2
97/103
Skirt Base Ring #1
Base configuration: single base plate without gussetsFoundation compressive strength: 20,000 psiAnchor bolt material:Anchor bolt allowable stress, Sb: 20,000 psiBolt circle, BC: 28.125 inAnchor bolt corrosion allowance (applied to root radius): 0 inAnchor bolt clearance: 0.375 inBase plate material: 516-70Base plate allowable stress, Sp: 20,000 psiBase plate inner diameter, Di: 19 inBase plate outer diameter, Do: 31 inBase plate thickness, tb: 0.5 inInitial bolt preload: 0 % (0 psi)Number of bolts, N: 8Bolt size and type: 0.75 inch series 8 threadedBolt root area (corroded), Ab: 0.302 in2
Diameter of anchor bolt holes, db: 1.125 in
Load Vesselcondition
Base M(lbf-ft)
W(lb)
Requiredbolt area
(in2)
trBase(in)
Foundationbearingstress(psi)
Wind operating, corroded 1,490 1,533 0.0101 0.1384 10.43
Wind operating, new 1,490 1,533 0.0101 0.1384 10.43
Wind empty, corroded 1,490 767.4 0.013 0.127 8.77
Wind empty, new 1,490 767.4 0.013 0.127 8.77
Wind test, new 78.3 2,089 0 0.0947 4.88
Seismic operating, corroded 143.3 1,533 0 0.0861 4.03
Seismic operating, new 143.3 1,533 0 0.0861 4.03
Seismic empty, corroded 114.4 767.4 0 0.0639 2.22
Seismic empty, new 114.4 767.4 0 0.0639 2.22
Anchor bolt load (operating, corroded + Wind)
P = -0.6*W / N + 48 * M / (N*BC)= -0.6*1,532.99 / 8 + 48 * 1,490 / (8*28.125)= 202.89 lbf
Required area per bolt = P / Sb = 0.0101 in2
The area provided (0.302 in2) by the specified anchor bolt is adequate.
Foundation bearing stress (operating, corroded + Wind)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64
98/103
= 38,936.11 in4
fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + 1,532.99 / 463.2867 + 6*1,490*31 / 38,936.11= 10 psi
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (operating, corroded + Wind)
tr = (3*fc*L2 / Sp)0.5
= (3*10*3.52 / 20,000)0.5
= 0.1384 in
The base plate thickness is satisfactory.
Anchor bolt load (operating, new + Wind)
P = -0.6*W / N + 48 * M / (N*BC)= -0.6*1,532.99 / 8 + 48 * 1,490 / (8*28.125)= 202.89 lbf
Required area per bolt = P / Sb = 0.0101 in2
The area provided (0.302 in2) by the specified anchor bolt is adequate.
Foundation bearing stress (operating, new + Wind)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64= 38,936.11 in4
fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + 1,532.99 / 463.2867 + 6*1,490*31 / 38,936.11= 10 psi
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (operating, new + Wind)
tr = (3*fc*L2 / Sp)0.5
= (3*10*3.52 / 20,000)0.5
= 0.1384 in
The base plate thickness is satisfactory.
Anchor bolt load (empty, corroded + Wind)
P = -0.6*W / N + 48 * M / (N*BC)= -0.6*767.45 / 8 + 48 * 1,490 / (8*28.125)= 260.31 lbf
Required area per bolt = P / Sb = 0.013 in2
99/103
The area provided (0.302 in2) by the specified anchor bolt is adequate.
Foundation bearing stress (empty, corroded + Wind)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64= 38,936.11 in4
fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + 767.45 / 463.2867 + 6*1,490*31 / 38,936.11= 9 psi
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (empty, corroded + Wind)
tr = (3*fc*L2 / Sp)0.5
= (3*9*3.52 / 20,000)0.5
= 0.127 in
The base plate thickness is satisfactory.
Anchor bolt load (empty, new + Wind)
P = -0.6*W / N + 48 * M / (N*BC)= -0.6*767.45 / 8 + 48 * 1,490 / (8*28.125)= 260.31 lbf
Required area per bolt = P / Sb = 0.013 in2
The area provided (0.302 in2) by the specified anchor bolt is adequate.
Foundation bearing stress (empty, new + Wind)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64= 38,936.11 in4
fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + 767.45 / 463.2867 + 6*1,490*31 / 38,936.11= 9 psi
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (empty, new + Wind)
tr = (3*fc*L2 / Sp)0.5
= (3*9*3.52 / 20,000)0.5
100/103
= 0.127 in
The base plate thickness is satisfactory.
Anchor bolt load (test, new + Wind)
P = -0.6*W / N + 48 * M / (N*BC)= -0.6*2,089.01 / 8 + 48 * 78.3 / (8*28.125)= -139.97 lbf
The anchor bolts are satisfactory (no net uplift on anchor bolt)
Foundation bearing stress (test, new + Wind)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64= 38,936.11 in4
fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + 2,089.01 / 463.2867 + 6*78.3*31 / 38,936.11= 5 psi
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (test, new + Wind)
tr = (3*fc*L2 / Sp)0.5
= (3*5*3.52 / 20,000)0.5
= 0.0947 in
The base plate thickness is satisfactory.
Anchor bolt load (operating, corroded + Seismic)
P = -(0.6 - 0.14*SDS)*W / N + 48 * M / (N*BC)= -(0.6 - 0.14*0.08)*1,532.99 / 8 + 48 * 143.3 / (8*28.125)= -82.26 lbf
The anchor bolts are satisfactory (no net uplift on anchor bolt)
Foundation bearing stress (operating, corroded + Seismic)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64= 38,936.11 in4
fc = N*Ab*Preload / Ac + (1 + 0.14*SDS)*W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + (1 + 0.14*0.08)*1,532.99 / 463.2867 + 6*143.3*31 / 38,936.11= 4 psi
101/103
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (operating, corroded + Seismic)
tr = (3*fc*L2 / Sp)0.5
= (3*4*3.52 / 20,000)0.5
= 0.0861 in
The base plate thickness is satisfactory.
Anchor bolt load (operating, new + Seismic)
P = -(0.6 - 0.14*SDS)*W / N + 48 * M / (N*BC)= -(0.6 - 0.14*0.08)*1,532.99 / 8 + 48 * 143.3 / (8*28.125)= -82.26 lbf
The anchor bolts are satisfactory (no net uplift on anchor bolt)
Foundation bearing stress (operating, new + Seismic)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64= 38,936.11 in4
fc = N*Ab*Preload / Ac + (1 + 0.14*SDS)*W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + (1 + 0.14*0.08)*1,532.99 / 463.2867 + 6*143.3*31 / 38,936.11= 4 psi
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (operating, new + Seismic)
tr = (3*fc*L2 / Sp)0.5
= (3*4*3.52 / 20,000)0.5
= 0.0861 in
The base plate thickness is satisfactory.
Anchor bolt load (empty, corroded + Seismic)
P = -(0.6 - 0.14*SDS)*W / N + 48 * M / (N*BC)= -(0.6 - 0.14*0.08)*767.45 / 8 + 48 * 114.4 / (8*28.125)= -32.09 lbf
The anchor bolts are satisfactory (no net uplift on anchor bolt)
Foundation bearing stress (empty, corroded + Seismic)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
102/103
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64= 38,936.11 in4
fc = N*Ab*Preload / Ac + (1 + 0.14*SDS)*W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + (1 + 0.14*0.08)*767.45 / 463.2867 + 6*114.4*31 / 38,936.11= 2 psi
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (empty, corroded + Seismic)
tr = (3*fc*L2 / Sp)0.5
= (3*2*3.52 / 20,000)0.5
= 0.0639 in
The base plate thickness is satisfactory.
Anchor bolt load (empty, new + Seismic)
P = -(0.6 - 0.14*SDS)*W / N + 48 * M / (N*BC)= -(0.6 - 0.14*0.08)*767.45 / 8 + 48 * 114.4 / (8*28.125)= -32.09 lbf
The anchor bolts are satisfactory (no net uplift on anchor bolt)
Foundation bearing stress (empty, new + Seismic)
Ac = pi*(Do2 - Di
2) / 4 - N*pi*db2 / 4
= π*(312 - 192) / 4 - 8*π*1.1252 / 4= 463.2867 in2
Ic = π*(Do4 - Di
4) / 64= π*(314 - 194) / 64= 38,936.11 in4
fc = N*Ab*Preload / Ac + (1 + 0.14*SDS)*W / Ac + 6*M*Do / Ic= 8*0.302*0 / 463.2867 + (1 + 0.14*0.08)*767.45 / 463.2867 + 6*114.4*31 / 38,936.11= 2 psi
As fc <= 20,000 psi the base plate width is satisfactory.
Base plate required thickness (empty, new + Seismic)
tr = (3*fc*L2 / Sp)0.5
= (3*2*3.52 / 20,000)0.5
= 0.0639 in
The base plate thickness is satisfactory.
103/103
LIFTING EYE DESIGN
MGW 1000 lbf Max gross weight of equipment
DLF 2.00 Dynamic Load Factor
θ 60 deg Sling angle with respect to horizontal axis
N 2 Number of slings in lifting system
t 0.5 in Lug plate thickness
tc 0.1875 in Cheek plate thickness
ro 1.50 in Lift eye finish radius (minimum distance from center of hole to radius)
dh 0.8125 in Pin hole diameter (Hole diameter should not exceed 10% of the shackle pin diameter)
d 3.0 in Lifting Eye width at attachment (weld)
h1 3.0 in Distance from center of hole to fixed edge attachment (weld)
γ 0 deg Angle between vertical sling plane and plane of pad eye
dc 2.5 in Cheek plate diameter
Fy 38 ksi Yield strength of the pad eye material
Fu 70 ksi Ultimate tensile strength of the pad eye material
T 1 Select Type of Sling Load Calculation: T = 1 for GOM - No Shackle Fit (load on all slings) = 2 for GOM - Shackle Fit (load on N-1 slings)
= 3 for slings per DNV 2.7-1 (load on N-1 slings)
PDirection 1 Select Direction of Sling with respect to weld: PDirection = 1 for Toward weld
= 2 for Away from weld
h2 0 in Vertical distance from the center of pin holeto the centroid to the pad eye geometry:
BRIGHT 6 x 19 Class STEEL CORE (IWRC)
Diameter Breaking(in.) Strength in
(Tons)
1/4 3.4
5/16 5.3
3/8 7.6
7/16 10.2
1/2 13.3
9/16 16.8
5/8 20.6
3/4 29.4
7/8 39.8
1 51.7
1 1/8 65.0
1 1/4 79.9
1 3/8 96.0
1 1/2 114.0
1 5/8 132.0
1 3/4 153.0
2 198.0
2 1/4 247.0
2 3/8 274.0
2 1/2 302.0
Diameter Breaking(in.) Strength in
(Tons)
1/4 2.7
5/16 4.1
3/8 5.9
7/16 8.0
1/2 10.3
9/16 13.0
5/8 16.1
3/4 23.0
7/8 31.1
1 40.4
1 1/8 50.8
1 1/4 62.5
1 3/8 75.1
1 1/2 89.0
1 5/8 103.0
1 3/4 120.0
1 7/8 137.0
2 155.0
2 1/8 173.0
2 1/4 193.0
GALVANIZED6 x 19 Class
STEEL CORE (IWRC)Nominal Size Working Load Dimensions (in.)
Limit (Tons) A B C
3/16 1/3 0.38 0.25 0.88
0.25 1/2 0.47 0.31 1.13
0.31 3/4 0.53 0.38 1.22
0.38 1 0.66 0.44 1.44
0.44 1 1/2 0.75 0.50 1.69
0.50 2 0.81 0.64 1.88
0.63 3 1/4 1.06 0.77 2.38
0.75 4 3/4 1.25 0.89 2.81
0.88 6 1/2 1.44 1.02 3.31
1.00 8 1/2 1.69 1.15 3.75
1.13 9 1/2 1.81 1.25 4.25
1.25 12 2.03 1.40 4.69
1.38 13 1/2 2.25 1.53 5.25
1.50 17 2.38 1.66 5.75
1.75 25 2.88 2.04 7.00
2.00 35 3.25 2.30 7.75
2.50 55 4.13 2.80 10.50Maximum Proof Load is 2.0 times the Working Load Limit. Minimun Ultimate Strength is 6 times the Working Load Limit.
Crosby Forged Shackles G-2130
For G-2140 Crosby Alloy Bolt Type Shackles andG-2130CT / G-2140CT Crosby COLD TUFF Shackles SeeCrosby Catalog Latest Edition
**Rule of thumb: Size the cable first then choose a shackle one diameter larger than the sling.
SHACKLE & CABLE DATA:
SS 0.63 in Shackle Size
SSWLL 3.25 tonf Shackle Safe Working Load
Shackle Dimensions:
A 1.06 in B 0.77 in C 2.38 in
Cselect 1 Select Cable Type:Cselect = 1 for Normal
= 2 for Galvanized
CS 0.5 in Cable Size
CBS 13.3 tonf Cable Min BS
Check shackle clearance around pad eye geometry (Note 0.375" is included for thimble thickness):
Cactual ro
dh
2
CS 0.375 in
Cactual 1.969 in C 2.38 in
Clearance "Satisfactory" Cactual Cif
"NOTSatisfactory" otherwise
"Satisfactory"
Ferule efficiency for mechanical splice - Wire Rope Sling Manual - 3rd Ed., Page 13 - Table 4 (IWRC / EIPS)
KT 0.95 0.25 in CS 1 inif
0.925 1 in CS 2 inif
0.90 CS 2 inif
KT 0.95
Calculate the cable WLL for a single sling (to be compared to the calculated resultant sling force):
Note: The cable WLL is calculated using a design factor of 5.0(to account for variations in load, wear, abrasion, and damage).Wire Rope Sling Manual - 3rd Ed., Page 5Additionally, the working load limit is multiplied by the feruleefficiency (mechanical splice).
CWLL
CBS KT
52.527 tonf
MASTER LINK ASSEMBLY - USE CROSBY A-345:
1/2 7,000 14,000 2.50 5.005/8 9,000 18,000 3.00 6.003/4 12,300 24,600 2.75 5.507/8 14,000 28,400 3.75 6.38
1 24,360 48,700 3.50 7.001 1/4 36,200 72,400 4.38 8.751 1/2 54,300 113,200 5.25 10.501 3/4 84,900 169,800 6.00 12.002 102,600 205,200 7.00 14.002 1/4 143,100 289,200 8.00 16.002 1/2 160,000 320,000 8.00 16.002 3/4 216,900 433,800 9.50 16.003 228,000 456,000 9.00 18.003 1/4 262,200 524,400 10.00 20.003 1/2 279,000 558,000 12.00 24.003 3/4 336,000 672,000 10.00 20.004 373,000 746,000 10.00 20.004 1/4 354,000 708,000 12.00 24.004 1/2 360,000 720,000 14.00 28.004 3/4 389,000 778,000 14.00 28.005 395,000 790,000 15.00 30.00
** Proof test load equals or exceeds the requirement of ASTM A957(8.1) and ASME B30.9-1.4 for the chain size and number of legs
C
A-342 Alloy Master Links
* Minimum Ultimate Load is 5 times the Working Load Limit. Based single leg sling (in-line load), or resultant load on multiple legs with an included angle less than or equal to 120 degrees.
Working Load Limit (lbs)*
Size "A" (in.)
Proof Load (lbs)**
B
Note: As a Minimum the Master LinkAssembly Size Should be 2 Times theSelected Cable Size
Link 1.0 in Link = Master Link Assembly Size (From Crosby Catalog)
LinkWLL 24360 lbf Link WLL = Master Link Assembly Safe Working Load (With 5:1 Factor of Safety)
Note: If the sling assembly has three or more legs and the sling has a WLL greater than 25,000 lbs thena master link with sub links should be used.
1. Calculate the resultant sling loads (without DLF) and compare with the available working load limits (WLL) ofthe lifting set components:
n N 1( ) N 4 T 2= T 3=( )if
N otherwise
2 Number of lugs used for slings load calculations.
Resultant sling force (no factor of safetyincluded)Note: If T (type) = 3, DNV EnhancementFactor, "EF" is multiplied times the RSF.
RSFMGW
n sin θ( )T 1= T 2=if
EF MGW
n sin θ( )T 3=if
EF 1
Check Shackle:
SSWLL 3.25 tonfShackle "Satisfactory" SSWLL RSFif
"NOTSatisfactory" otherwise
"Satisfactory"
RSF 0.289 tonf
Check Slings:
BSreq5.0 RSF
KT1.52 tonf
Slings "Satisfactory" CWLL RSFif
"NOTSatisfactory" otherwise
"Satisfactory"
CWLL 2.527 tonf
RSF 0.289 tonf
Check Master Link:
LinkWLL 12.18 tonfMasterLink "Satisfactory" LinkWLL MGW T 2if
"Satisfactory" LinkWLL EF MGW T 3=if
"NOTSatisfactory" otherwise
"Satisfactory"
MGW 0.5 tonf
MGW EF 0.5 tonf
2. Calculate sling load components (with DLF) to determine lift eye stress:
FOS 5 N 1=if
DLF otherwise
2 Factor of safety (DLF of 5 is used for single point lifts (n= 1)
PFOS MGW
n sin θ( )T 1= T 2=if
FOS MGW
n sin θ( )T 3=if
Resultant sling force (DLF included)
Pv P sin θ( ) 1000 lbf Vertical sling load component (DLF included)
Ph P cos θ( ) 577 lbf Horizontal sling load component (DLF included)
Pside P sin γ( )( ) θ 90deg=if
P sin γ( ) cos θ( )( ) otherwise
0 lbf Out of plane component of sling loadnormal to the plane of the pad eye (DLFincluded)
3. Calculate the tensile stress at the pin hole (section A-A) as per AISC:
Allowable tensile stress on the net area ofthe pin hole for pin-connected membersAISC D3.1 and D3.2
Ft1 0.45 Fy 17.1 ksi
Tensile area at section A-AAt1 2 ro dh t dc dh 2 tc 1.727 in
2
Tensile stressat section A-A ft1
Ph
At10.33 ksi
TensionAtHole "Satisfactory" ft1 Ft1if
"NOTSatisfactory" otherwise
"Satisfactory"
4. Calculate the tensile stress at the attachment as per AISC:
Allowable tensile stress at attachmentas per AISC D1, Page 5-40Ft2 min 0.60 Fy 0.50 Fu 22.8 ksi
At2 d t 1.5 in2
Cross sectional area (tensile)of lift eye plate at theattachment
Tensile stress at the attachmentft2
Ph
At20.385 ksi
TensionAtAttachment "Satisfactory" ft2 Ft2if
"NOTSatisfactory" otherwise
"Satisfactory"
5. Check pin shear tear out stress (section B-B) as per AISC:
Allowable shear stress as per AISC J-4 Page 5-77, F.4 Page 5-49Fto min 0.40 Fy 0.30Fu 15.2 ksi
Ato 2 ro
dh
2
t 4dc
2
dh
2
tc 1.727 in2
Shear tear out area (double shear)
ftoP
Ato0.67 ksi Shear tear out stress
ShearTearOut "Satisfactory" fto Ftoif
"NOTSatisfactory" otherwise
"Satisfactory"
6. Check bearing stress at the hole as per AISC:
Fp 0.90 Fy 34.2 ksi Allowable bearing stress as per AISC J8 - Page 5-79
Ap t tc B 0.53 in2
Bearing area at hole
fpP
Ap2.181 ksi Bearing stress at hole
Bearing "Satisfactory" fp Fpif
"NOTSatisfactory" otherwise
"Satisfactory"
7. Check bending stress at the lug attachment as per AISC:
Allowable bending stress as per AISC(about strong axis)Fb 0.60 Fy 22.8 ksi
Strong axis section modulus of the lifteye plate at the attachmentSs
t d2
60.75 in
3
Weak axis section modulus of the lifteye plate at the attachmentSw
d t2
60.125 in
3
Mo Pv h1 Ph h2 PDirection 1=if
Pv h1 Ph h2 PDirection 2=if
Summation of the moments acting about the strong axis of lift lug.
Strong Axis Bending Stress at attachment(Due to horizontal component load)fbx
Mo
Ss4 ksi
Weak Axis Bending Stress atattachment(due to out of plane load)fbz1
Pside h1
Sw0 ksi
API RP 2A - due to 5% API side loadrequirement(5% of total sling load with DLFincluded)
PAPI 0.05 P 58 lbf
Weak Axis Bending Stress atattachment(due to out of plane load)
fbz2
PAPI h1
Sw1.386 ksi
fb fbx fbz1 fbz2 5.386 ksi Max bending stress at attachment
Bending "Satisfactory" fb Fbif
"NOTSatisfactory" otherwise
"Satisfactory"
8. Check transverse (direct) shear stress at the lug attachment as per AISC:
Fv 0.40 Fy 15.2 ksi Allowable shear stress as per AISC F4 - Page 5-49
Av d t 1.5 in2
Shear area at attachment
fv
Pv
Av0.67 ksi Shear stress at attachment due to
horizontal load
ShearAtAttachment "Satisfactory" fv Fvif
"NOTSatisfactory" otherwise
"Satisfactory"
9. Check combined stress (axial tension, bending, and shear) at attachment as per AISC:
ft2 0.385 ksi Tensile stress at the attachment
fb 5.386 ksi Max bending stress at attachment
fv 0.667 ksi Shear stress at attachment due to horizontal load
Unity code check for combined axial tension, bending, and shear at the attachment as per Article: "A SystematicApproach to Lifting Eye Design" - Ocean ResourcesEngineering - 1977. Also similar in approach to AISC H1 -Page 5-54 but more conservative.
Uft2 fb
0.60 Fy
fv
0.60 Fy
2
0.254
CombinedStress "Satisfactory" U 1.0if
"NOTSatisfactory" otherwise
"Satisfactory"
10. Shackle pin versus lug hole dimensional check:
B 0.77 in Selected shackle pin diameter
Dhmax B 1.10 0.847 in Maximum permitted pin hole diameter (should not be more than 110% of the pin diameter)
Dhmin B 1.04 0.801 in Minimum permitted pin hole diameter (should not be less than 104% of the pin diameter)
dh 0.813 in Specified pin hole diameter
11. Shackle jaw gap versus lug thickness dimensional check:
A 1.06 in Selected Shackle (inside) width
tmin A 0.75 0.795 in Minimum permitted plate thickness(should not be less than 75% of inside shackle jaw gap)
tmax A 0.063 in 0.997 in Maximum permitted plate thickness (should not be more than 1/16" less than inside of shackle jaw gap)
tactual t 2 tc 0.875 in Specified plate thickness (including cheek plate)
VERIFICATION OF RESULTS:
ShackleClearance "Satisfactory" Cactual Cif
"NOTSatisfactory" otherwise
"Satisfactory"
ShacklePinFit "Satisfactory" dh Dhmax dh Dhminif
"NOTSatisfactory" otherwise
"Not Applicable" T 1=if
"Not Applicable"
ShackleJawFit "Satisfactory" tactual tmin tactual tmaxif
"NOTSatisfactory" otherwise
"Not Applicable" T 1=if
"Not Applicable"
ShackleWLL "Satisfactory" SSWLL RSFif
"NOTSatisfactory" otherwise
"Satisfactory"
SlingsWLL "Satisfactory" CWLL RSFif
"NOTSatisfactory" otherwise
"Satisfactory"
MasterLinkWLL "Satisfactory" LinkWLL MGWif
"NOTSatisfactory" otherwise
"Satisfactory"
TensionAtHole "Satisfactory" ft1 Ft1if
"NOTSatisfactory" otherwise
"Satisfactory"
TensionAtAttachment "Satisfactory" ft2 Ft2if
"NOTSatisfactory" otherwise
"Satisfactory"
ShearTearOut "Satisfactory" fto Ftoif
"NOTSatisfactory" otherwise
"Satisfactory"
Bearing "Satisfactory" fp Fpif
"NOTSatisfactory" otherwise
"Satisfactory"
Bending "Satisfactory" fb Fbif
"NOTSatisfactory" otherwise
"Satisfactory"
ShearAtAttachment "Satisfactory" fv Fvif
"NOTSatisfactory" otherwise
"Satisfactory"
CombinedStress "Satisfactory" U 1.0if
"NOTSatisfactory" otherwise
"Satisfactory"
SUMMARY OF FACTORS OF SAFETY:
Shear Tear Out FS
Factor of safety for shear tear out stress with respect to the shear yield strength (0.58*Fy):
FSTO
0.58Fy
fto
FOS
65.91 FSreqdTO 3.0
TearOutFS "Satisfactory" FSTO FSreqdTOif
"Not Satisfactory" FSreqdTO FSTOif
"Satisfactory"
Contact/Bearing Stress FS
Factor of safety for bearing stress with respect to the yield strength:
FSCS
Fy
fp
FOS
34.842 FSreqdCS 2.22
ContactFS "Satisfactory" FSCS FSreqdCSif
"Not Satisfactory" FSreqdCS FSCSif
"Satisfactory"
Pad Eye Combined Stress FS
Factor of safety for combined stress (axial tension and bending) with respect to the yield strength:
FSPS
Fy
ft2 fb
FOS
13.17 FSreqdPS 3.03
PadEyeFS "Satisfactory" FSPS FSreqdPSif
"Not Satisfactory" FSreqdPS FSPSif
"Satisfactory"
Cable FS
Factor of safety for slings with respect to the working load limit:
FSC
CWLL
RSF8.754 DFc 1.0
CableFS "Satisfactory" FSC DFcif
"Not Satisfactory" otherwise
"Satisfactory"
Shackle FS
Factor of safety for shackles with respect to the working load limit:
FSS
SSWLL
RSF11.258 DFs 1.0
ShackleFS "Satisfactory" FSS DFsif
"Not Satisfactory" otherwise
"Satisfactory"
Master Link FS
Factor of safety for master link with respect to the working load limit:
FSML
LinkWLL
MGW24.36 DFml 1.0
MasterLinkFS "Satisfactory" FSML DFmlif
"Not Satisfactory" otherwise
"Satisfactory"
XI
B
XII
A
B
I
FP60
SHELL FP30
II
HEAD
SHELL
IXA
B
C
X
A
B
VII
GRIND FLUSH
G
B
VIII
B
V
B
FLUSH
VI
BA
1/8"
AB
III IV
FP70
PLA
TFO
RM
NO
RTH
N
78 "
7"
38 "
78 "
38 "
18 "
34 "
14 "
1116 "
112 "
1116 "
214 " 1
12 "
7"
2"
114 "
14 "
334 "
516 "
2,081WEIGHT
0.810
SERVICE
RF LWN
100
275
24" O.D. x 6'-0" S/S
SA516-70/0.25
SA516-70/0.25
RT-1
PY - 14923ATAG NO. 0
760
A
358
WEIGHT
13-150
2013
6.0
FULL
SA 105VAPOR IN
275
WPS-PC-103
-
NOTES:
3" 300
MAT'L/THKN
N1 LIQUID OUT1
-
3" 300
°FPSI
PSI
1. ALL TEXT TO BE 1/8" ARIAL UNLESS NOTES OTHERWISE
W
AIR ELIMINATOR
AT
LENGTH
SHELL
HEAD
MAT'L/THKN
-20
HYDRO
YEAR
BUILT
TEST AT
DRY
DIA (ID) x
ALLOW
CORR
MFG SRL
-
NUMBER
-
IN
NECK
ACADIAN CONTRACTORS
1
NAMEPLATE DETAIL
17102 Louisiana 330 Abbeville, LA 70510E
LBS
-WPS-PC-103
CERTIFIED BY
PSI
0.5 X 0.250 0.250
RF LWN 3.0 0.810 SA 105 - - - 6.0 0.5 X 0.250 0.250 -
MARKWELD SIZE
No.WIDE & THK. MAT'L O.S. I.S. WELD
DETAIL
AT
B C
LBS
SHELL
B
REINFORCING PAD
B
SERVICE SIZE RATING TYPE BOREWALL MAT'L LENGTH
MDMT
MAWP
ASME CODE
NAT'L BD. NO.
(337) 893-6397
°F
N2
PROJECTION
B
3.0
ORIENTATION
ASM
N6 1 FLARE OUTLET 3" 300 RF LWN 3.0 0.810 SA 105 - - - NOTED 0.0 V - 0.250 -
N5 1 DRAIN 2" 300 RF WN S/80 0.218 SA 106B - - - NOTED 0.0 V,IV - 0.250 -
N4 1 LEVEL GAUGE 1½" 300 RF LWN 1.5 0.625 SA 105 - - - 6.0 0.5 X 0.250 0.250 -
N3 1 LEVEL GAUGE 1½" 300 RF LWN 1.5 0.625 SA 105 - - - 6.0 0.5 X 0.250 0.250
REF. SIZE QTY. DESCRIPTION
1 24" O.D. 6'-0"SHELL: ROLLED PLATE, 0.25" NOMINAL THICKNESS (0.1651" CALCULATED MINIMUM) SA 516-70
2 24" O.D. 2HEADS: ASME 2:1 ELLIPSOIDAL, 2" S.F., (0.1641" CALCULATED MINIMUM) SA 516-70
3 24" O.D. 2'-2" SKIRT: ROLLED PLATE: 0.1875" NOMINAL THICKNESS, SA 516-70
4 3" 3 FLANGES: ANSI 300, RF LWN, 3" BORE, SA 105
5 1½" 2 FLANGES: ANSI 300, RF LWN, 1½" BORE, SA 105
6 2" 1 FLANGES: ANSI 300, RF WN, SCH. 80 BORE, SA 105
7 2" 1'-7" PIPE: SMLS., SCH. 80, SA 106B
8 2" 1 ELBOW: 90 L.R., WELD, SCH. 80, SA 234 WPB
9 ½" 6.7 SQFT PLATE: SA 516-70
10 - 1 ASME/ACADIAN CONTRACTORS NAME PLATE
11 ½ 0.25 SQFT PLATE: SA 516-70
12 6" 3" PIPE: SMLS., SCH. 80, SA 106B
13 3/16" 0.1 SQFT PLATE: SA 36
REVISIONS
REV. DESCRIPTION DATE BY APPROVED
A ISSUED FOR APPROVAL 08-20-2013 RJF SRC
B LIFT LUG THICKNESS, N2 EXT. EXT. 09-17-2013 RJF SRC
REPRODUCTION IN PART OR AS A WHOLE
D
C
B
AA
B
C
D
12345678
8 7 6 5
5. INSIDE CORNERS R. .032,
SHARP CORNERS.
PV: 14923A
6. MACHINE FINISH
ACADIAN CONTRACTORS. ANY
ASME Y14.5M=1994
.030
ACADIAN CONTRACTORS IS PROHIBITED.
PROPRIETARY AND CONFIDENTIAL
DRAWN
CHECKED
ENG APPR.
MFG APPR.
Q.A.
COMMENTS:
DATE NAME
SRC ENGINEERS, INC.
SIZE
BDWG. NO. REV
-
WEIGHT:SCALE: 1:32
UNLESS OTHERWISE SPECIFIED:
SHEET 1 OF 1
Lafayette, LA (337)837-3810
111-825B
ACADIAN CONTRACTORS
ENTERPRISE - NEPTUNE PLANTABBEVILLE, LOUISIANA
JOB NO. 13-1662
08/13
__ __
__ __
0
MACHINE
14
4. REMOVE ALL BURRS AND
ASME SECT. VIII DIV. 1, 2010 ED., A11 ADD.
RT-1
FRACTIONS= .X =
3
THE INFORMATION CONTAINED IN THIS
358
FABRICATION
DRAWING IS THE SOLE PROPERTY OF
275
1/16" .XX =
__
.XXX =
__
1. DO NOT SCALE DRAWING.
3° .XXXX =
-
3. INTERPRET DIM. TOL. PER
INT. SURFACE TREATMENT:
OUTSIDE CORNERS R. .020
N/A
2
.015
-
F MIN/MAX
-
-
JML
0.50°
FLG. STUD SPEC.:
.0010
AIR ELIMINATOR - PV - 14923A
CONSTRUCTION CODE:
ANGLES
YEAR BUILT:
-
SERIAL No.: 13-150
BW FIT MATL. SPEC.:
DESIGN PRESSURE EXTERNAL:
INSULATION DESC.:
__ __
2013
WITHOUT THE WRITTEN PERMISSION OF
24"O.D. x 6'-0" S/S x 275 PSIG
SPECIFICATIONSTAG/ MODEL No.:
2. DIMENSIONS ARE IN INCHES.
HYDRO PRESSURE INTERNAL:
.005
J.E. ROUND SEAMS: CORROSION ALLOWANCE:
FULL LIQUID WEIGHT.:
PSIG @ TEMP
DESIGN PRESSURE INTERNAL: PSIG @ TEMP
F MIN/MAX
ANGLES
FLANGE RATING: ANSI 300
J.E. LONG SEAMS:
100%
NATIONAL BD. No.: -
STRESS RELIEF: NONE
COUPLING RATING: N/A
HEAD MATL. SPEC.: SA 516-70
CPLG. MATL. SPEC.: N/A
SHELL MATL. SPEC.: SA 516-70
RADIOGRAPHY:
SA 105
-20/100
FLANGE MATL. SPEC.:
SA 106B
SA 515-70 REPAD MATL. SPEC.:
-
100%
N/A RJ GSK. MATL. SPEC.:
LBS 760
FLEXITALLIC GASKET STYLE "CG"
PIPE MATL. SPEC.:
RF GSK. DESC.:
SA 234 WPB
SA 36
RF GSK. MATL. SPEC.:
STRUC. MATL. SPEC.:
SA 193-B7
SA 194-2H
EMPTY WEIGHT:
FLG. NUT SPEC.:
2,081 LBS
RJ GSK. DESC.: N/A
WELD PROCEDURE:
INSPECTED BY:
EXT. SURFACE TREATMENT:
TOLERANCES:
N O T E S:1. FLANGE BOLT HOLES TO STRADDLE VESSEL CENTERLINES UNLESS OTHERWISE NOTED.2. DRILL & TAP 1/4" TELLTALE HOLE IN REINFORCING PAD.3. OUTSIDE PROJECTION SHOWN IN THE NOZZLE SCHEDULE IS FROM THE VESSEL O.D. UNLESS OTHERWISE NOTED4. INSIDE PROJECTION SHOWN IN THE NOZZLE SCHEDULE IS MINIMUM ONLY.5. ALL TAIL DIMINSIONS ARE FROM THE REFERENCE LINE.6. ALL NOZZLES SHALL BE ADEQUATELY PROTECTED AND COVERED FOR SHIPMENT7. UNLESS OTHERWISE NOTED 1/4" DIMENSIONAL, OR 1/2" ANGULAR TOLERANCES.8. CHIP ALL WELDS TO SOUND METAL, UNLESS OTHERWISE NOTED9. NOZZLE INTERNAL PROJECTIONS SHALL HAVE 1/8" RADIUS ROUNDED EDGES.10. VESSEL SHALL MEET THE REQUIREMENTS OF THE ASME BOILER & PRESSURE VESSEL CODE SECTION VIII, DIV. 1, AND STAMPED ACCORDINGLY.
N2
N4
N5
N3
N1
SKIRT
0
270
180
90
I
CLLUG
WELD
WELDI
N6ASME NAMEPLATE & LIFT
2
45.0°
45.0°
90.0°
N4
N2
N3
N1
N6
N5
5
4
5 4
12
SIDE ELEVATION
AS POSSIBLE
1
2
2
3
7
76
9
8
4
(4) 1" DIA. VENT HOLES,LOCATED AS HIGH
11
A
6"
6"
6" "8 171
31"
LIFT LUG DETAILSCALE 1:4
11
13 BOTH SIDES
(2 REQUIRED)
TO SHELL
13
1 1 "
"
3"
R1
"
2
3"
16
1
2
212 "
3/16
12
DETAIL A SCALE 1 : 16
3
FLUSH
3/16INSIDE
3/16
12 " N2
N4
N6
N1
N3
2
4
7
4
4
FRONT ELEVATION
6
IIWELD
LOCATION
WELDII
1
5
2 3
5
9
ASME NAMEPLATE
11
"
"4
24" O.D.
43
"7
"
1
72"
16 46
SEAM TO SEAM
16
6
2914
4"