1 Newton Kanunlari
Transcript of 1 Newton Kanunlari
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Rotational movement
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DGDG22
Mekanik
Akışkanlar Rijit Cisimler
Şekil değiştiren Katılar
Statik F = 0
Dinamik F 0
Kinematik Kinetik
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DİNAMİK
• Cisme etki eden kuvvetler ile cismin eylemsizliği arasındaki bağıntıları inceler.
• Bütün doğa olayları fizik kanunlarının öngördüğü şekilde meydana gelmektedir.Newton kanunları gibi kanunlar belli koşullar altında ne olacağına dair ayrıntılı öngörülenin çerçevesini çizmektedir.
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KUVVET VE HAREKETİN BULUŞMASI
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NEWTON KANUNLARI
HAREKET KANUNLARI ( DİNAMİK )
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NEWTON’UN HAREKET KANUNLARININ NEWTON’UN HAREKET KANUNLARININ GÜNLÜK HAYATTA UYGULAMA ALANLARIGÜNLÜK HAYATTA UYGULAMA ALANLARI
Paraşüt yapımında
Kışın arabaların kaymaması için arabalara zincir takılmasında
Örneğin arabayla yolda giderken şöför frene bastığı zaman biz öne doğru gideriz bu da Newton’un eylemsizlik prensibiyle ilgilidir.
Uçakların kanatlarının yapımında
Araba tamponlarının yumuşak maddelerden yapılmasında
Hava yastığı yapımında Newton’un hareket kanunlarından faydalanılır.
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Newton 1687 yılında hareket ile ilgili 3 temel kanun belirledi.
Bu kanunlar:1) Eylemsizlik kanunu2) Dinamiğin temel ilkesi (F=m.a)3) Etki-tepki kanunu dur.
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Newton’un Birinci Hareket Kanunu
Eylemsizlik Kanunu
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I.Kanun (Eylemsizlik Kanunu)
Bir cismin üzerine etki eden kuvvetlerin bileşkesi sıfır ise cisim hareket durumunu korur. Yani duruyorsa durmaya devam eder, hareket halindeyse düzgün doğrusal hareket yaparak hareketini sürdürür. Ama asla yavaşlamaz veya hızlanmaz veya hareket yönünü değiştirmez.
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İvme sıfır olduğunda;
• Cisim Mekanik Dengedir.
• Cisim üzerindeki net kuvvet sıfırdır.
• Statik Denge için hız sıfırdır.
• Dinamik Denge için hız sabittir.
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Dynamic EquilibriumVelocity is nonzero and constantExamples:Driving at constant velocity
Force from road
Weight down
Friction
Normal up
Weight downAir resistance
Terminal velocity in parachuting
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Eylemsizlik ve KütleEylemsizlik ve Kütle
Üzerine etkiyen kuvvetlerin sıfır olduğu cisimler durumlarınıkoruma isteklerine eylemsizlik denir.
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Eylemsizlik prensibine, adamın hareket eğilimini koruma isteğini örnek verebiliriz
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Şekilde görülen kamyonun üzerindeki merdiven hareketine devam etme eğilimindedir.Bunu da
eylemsizlik prensibine örnek verebiliriz.
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Bu cisme hiçbir kuvvet etki etmediğinden,Cisim durma eğilimini korumaktadır.
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The Accelerometer
a
i i
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Hava sürtünmesi
Net kuvvet =0Newtonun 1.kanunu
Sabit hızlı
İleri itici kuvvet
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Hava direnci
İleri itici kuvvet
Net kuvvet
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İleri itici kuvvet
Net kuvvet
Hava sürtünmesi
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Newton’un İkinci Hareket Kanunu
Dinamiğin temel ilkesi
F= m.a
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• Bir cisme dengelenmemiş (bileşkesi sıfır değilse) bir kuvvet uygulandığında cisim kuvvet yönünde bir ivme kazanır.Kuvvetin ivmeye oranı sabittir.Bu sabit cismin kütlesini verir.
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F am
F am
m
F a
m
m
m F aM
ma
1
F aM
F aM
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F maF ma
1 N 1kgm
s2
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m=10kg F=100N
m=25kgF=250N
simülasyon
simülasyon
a = ?
a = ?
F ma
a Fm
m F
a
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m=10kg F=?
m=25kgF=?
simülasyon
simülasyon
a = 10 m / s2
a = 10 m / s2
F ma
a Fm
m F
a
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m=? F=100 N
m=?F=250 N
simülasyon
simülasyon
a = 10 m / s2
a = 10 m / s2
F ma
a Fm
m F
a
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Top üzerinde dengelenmemiş kuvvet olduğundan,top hızlanır. (
ivmelenir)
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Büyük kütlelere sahip cisimleri hareket ettirmek için büyük kuvvetlere ihtiyaç vardır.
(The more mass an object has, the more force is needed to move it)
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Examples of Newton's 3rd Law
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ÖRNEK:
5 10 15 200
1
2
3
a=m/s²)
t(s)
8 kg kütleli bir cismin ivme-zaman grafiği şekildeki gibidir.
Cisme 20 saniye içinde etki eden ortalama kuvvet kaç Newton’dur?
A)8 B)14 C)18 D)22 E)24
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ÇÖZÜM:
Bir cisme etki eden ortalama kuvveti Newton’un 2. hareket kanunundan yazabiliriz.
F=m.a FORT=m.∆V/∆ta=∆V/∆t
Burada ∆V cismin hızındaki değişme olup ivme – zaman grafiğinin altındaki alana eşittir.∆V= S1+S2= (3+1/2).10+(2+1/2).10=20+15= ∆V=35 m/s
M=8 kg, ∆t=20 sn
Fort=m. ∆V/ ∆t =8.35/20 = 2.35/5 =2.7Fort=14 Newton olur CEVAP “B”
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ÖRNEK:
Sürtünmesiz yatay düzlemde duran m kütleli cisme 5 N’luk sabit yatay bir kuvvet a ivmesini kazandırıyor.Aynı cisme yatay 15 N’luk kuvvet kaç “a” ivmesini kazandırır?
A)1 B)3/2 C)2/3 D)3 E)4
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ÇÖZÜM:
Newton’un 2. hareket kanununa göre; F=m.a
a= F/m ‘ dir.
Öyleyse; a= F1/m=5/m
a2=F2/m=15/m = 3.5/m = a2 = 3.a olur
CEVAP “D”
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ÖRNEK:
530
m=2 kg
F=50 N
Yatay düzlemde şekildeki cisim 4 s de kaç metre yol olur?
(sin53=0,8 , cos 53=0,6)0 0
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ÇÖZÜM:
530
Fs=24N
G=m.g
FX=24N
Cismin hareketini F kuvvetinin yatay bileşeni ile sürtünme kuvveti etkiler.
Burada;Fx=F.cos53 =50.0,6=30N dur.F kuvvetinin y bileşeni cismi yüzeye doğru ittiği içinYüzeyin cisme tepkisi N=G+Fy olur.Burada sürtünme kuvveti;
Fs=k.N=k(G+Fy)=0,4(mg+Fy)Fs=0,4.(2.10+50.0,8)=0,4.60=24N olur.Cismin ivmesi:a=Fnet/m=Fs-fs/m=30-24/2=3m/s²‘dir.X=1/2a.t²=1/2.3.4²=24 metre yol alır.
0
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ÖRNEK:
m
FSürtünmeli yatay düzlemde yatay F kuvveti ile çekilen cisim kaç tane kuvvetin etkisindedir?
A)1 B)2 C)3 D)4 E)5
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●
ÇÖZÜM:
N
F
G=m.g
Fs
Şekildede görüldüğü gibi cisme;dört kuvvet etki etmektedir.Bunlar;
1)Yerçekimi
2)Yerin cisme gönderdiği tepki(N)
3)Cisme uygulanan yatay kuvvet(F)
4)Sürtünme kuvveti’dir.
CEVAP “D”
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ÖRNEK:
m=8 kg
F1=20NFS=4NYatay ve sürtünmesiz yüzeyde şekildeki cisim 25 metrelik yolu kaç saniyede alır?
A)3 B)4 C)5 D)6 E)7
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ÇÖZÜM:
Cisme etki eden bileşke kuvvet;
Fnet=F1-Fs=20-4= Fnet=16 N olur.
Cisim bu kuvvet etkisinde a=Fnet/m
a=16/8=2 m/s² lik ivme kazanarak düzgün hızlanan hareket yapar.Hareket denklemi:
x=1/2a.t² x=25m a=2m/s²
Yerlerine konulursa; 25=1/2.2.t² = t²=25 ise
t==5 saniyede alır.CEVAP “C”
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Newton’un Üçüncü Hareket Kanunu
Etki – Tepki Prensibi
Fab = - Fba
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Newton’s Third Law
• Single isolated force cannot exist• For every action there is an equal and
opposite reaction
Force on “1” due to “2”
F12
rF21
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Newton’s Third Law cont.
• F12 is action force F21 is reaction force• You can switch
action <-> reaction
• Action & reaction forces act on different objects
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Action-Reaction Pairs
n
rn
Fg Fg'
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Define the OBJECT (free body)
• Newton’s Law uses the forces acting ON object
• n and Fg act on object
• n’ and Fg’ act on other objects
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Her etki kuvvetine karşılık eşit ve zıt yönde tepki kuvveti vardır.
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Her etki kuvvetine karşılık eşit ve zıt yönde tepki kuvveti vardır.
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etki
tepki
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Normal kuvvet yüzeye diktir !!!
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Niçin yerçekimi kutuyu aşağıya düşüremiyor?
Dünya kutuya kuvvet uygular ( Ağırlık)
Zemin kutuya kuvvet uygular ( Normal kuvvet)
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Normal kuvvet yüzeye diktir !!!
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Example 4.10You are calibrating an accelerometer so that you can measure the steady horizontal acceleration of a car by measuring the angle a ball swings backwards.If M = 2.5 kg and the acceleration, a = 3.0 m/s2:a) At what angle does the ball swing backwards?b) What is the tension in the string?
=17 degT= 25.6 N
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).(1067.6; 112
21 SIGr
mmGF
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Her etki kuvvetine karşılık eşit ve zıt yönde tepki kuvveti vardır.
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4.8 The Normal Force
The normal force FN is one component of the force that a
surface exerts on an object with which it is in contact, namely, the component that is perpendicular to the surface.
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Normal Force Is Not Always Equal to the Weight
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Apparent Weight
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Apparent Weight