冷凍空調技師:駱昀昊 - hd-hvac. · PDF file冷凍循環原理: 冷凝器 3 2...

34
冷凍空調概論 冷凍空調概論 冷凍空調概論 冷凍空調概論 冷凍空調技師 駱昀昊 冷凍空調技師駱昀昊

Transcript of 冷凍空調技師:駱昀昊 - hd-hvac. · PDF file冷凍循環原理: 冷凝器 3 2...

  • 2000(Crete)

    (Minoan)

    755755 (Lebanon)(Mecca)

    1040 (S i )1040(Syria)

    -

  • 231.

    2

    2.

    3.

    4.

    14

    Ps:

    -

  • -

  • ()

    -

  • ()()

    Q m* (h1 h4)Q=m* (h1-h4)

    [m: h:]

    -

  • ()()(

    ))

    -

  • R-

    22R-407R410R134a22 R 407 R410 R134a

    -

  • (R(R--12)12)()

    23

    14

    ()

    -()

  • (R(R--22)22)

    -

  • (R(R--134a)134a)

    -

  • SI

    -

  • CMM (m3/min) , CFM (ft3/min), CMH (m3/hr)

    [ 1CMM=60CMH , 1CMM=35.3CFM , 1CFM=1.7CMH ]

    GPM (gal/min) , LPM (L/min)

    [ 1GPM=3.785LPM ] [ 1gal=3.785Liter ]

    USRT(RT) , Kcal/hr , Btu/hr , MBH , Kw

    [ 1RT=3024Kcal/hr =12000Btu/hr =12MBH =3.517Kw ]

    -

  • mmAq , inch(WG) , Pa

    [ 1inch(WG)=25mmAq , 1mmAq=10Pa ]

    [ 1K / 2 10 WG ][ 1Kg/cm2=10mWG ]

    M/S , FPM (ft/min)

    [ 1M/S=196.8FPM ]

    M2 , Ft2 ,

    -

    [ 1=3.3M2 , 1M2=10.76Ft2 ] [ 1M3=35.3Ft3 ]

  • Q=60*LPM* T

    [ Q: Kcal/hr LPM: l/min T:(T2-T1) T2:() T1:() ]

    1RT 1RT5

    Ans:Ans:

    -

  • Q=500*GPM* T

    [ Q: Btu/hr GPM: Gal/min T:(T2-T1) T2:() T1:() ]

    1RT 2 4GPM 1RT2.4GPM

    Ans:Ans:

    -

  • ()

    -

  • A.

    Qr=U*A*(CLTD)

    Qw=U*A*(CLTD)( )

    Qgc=U*A*(CLTD) Qgr=A*(SC)*(SCL)Qgc U A (CLTD) Qgr A (SC) (SCL)

    ** U: SC: A:

    CLTD: Cooling Load Temperature Differential

    -

    g p

    SCL: Solar Cooling Load

  • B.

    Qi=U*A*T

    Qigc=U*A*Tg

    ** U: A:

    T :

    -

  • C.

    Qps=N*SHG*CLF

    Qpl=N*LHG

    Qe=(Kw)*CLF*F1

    Qm=(Kw)*CLF*F2

    -

  • C.** N: SHG: LHG:

    CLF:(Cooling Load Factor)

    1:CLF1.0

    (1)24(1)24

    (2)24

    (3)(3)

    2:F1F2

    -

  • D. Qsh=1.12*m*(To-Ti)

    Qlh=2.78*m*(Wo-Wi)

    Q Q h Qlh 1 10* *(H Hi)Qt=Qsh+Qlh=1.10*m*(Ho-Hi)

    ** m:(Lps) To Ti: () Wo Wi: (g/kg)** m:(Lps) To,Ti:() Wo,Wi:(g/kg)

    Ho,Hi:(kj/kg) Q (w)

    1: 1.1235 DB/55%RH0.9m3/kg2.7835DB/

    55%RH

    -

  • U

    -

  • U

    -

  • USC

    -

  • U

    -

  • ()

    (1)34DB,60%RH (2)34DB,70%RH

    (3)35DB,60%RH (4)35DB,70%RH

    (5)36DB 60%RH (6)36DB 70%RH(5)36DB,60%RH (6)36DB,70%RH

    ( DB, %RH)

    -

  • E.E.R.C.O.P. E.E.R. (Energy Efficiency Ratio)

    C li H i Eff i B /hColing or Heating Effect in Btu/hr

    E.E.R.=

    Power Supplied in WattsPower Supplied in Watts

    -

  • E.E.R.C.O.P. C.O.P. (Coefficient Of Performance)

    C.O.P.E.E.R.

    Qin ()

    C O P =C.O.P.

    Win ()

    -

  • E.E.R.C.O.P.

    -

  • [79]

    1 20 20 15 1.202015

    Ans:

    Q=60*LPM* T

    20RT*3024Kcal/RT=60*LPM*(20-15)

    =201.6LPM

    -

  • 2.

    A 20m*10m*4mH A.20m*10m*4mH(U2.4w/m2/k)10

    B.10120w/85w/CLF0.8

    C.25w/m210150wCLF0.75

    D.8Lps/35/55%RH25/65%RH

    To=35,Ti=25,Wo=19.5g/kg,Wi=13g/kg

    -

  • 2.

    Ans: A. Qw=U*A*(CLTD)Qw1=(20m*4mH)*2*2.4w/m2/k*10 =3840W

    Qw2=(10m*4mH)*2*2.4w/m2/k*10 =1920W

    B Qps=N*SHG*CLF Qpl=N*LHGB. Qps N SHG CLF Qpl N LHG

    Qps=10*120w/*0.8=960W

    Qpl= 10*85w/=850W

    C. Qe=(Kw)*CLF*F1 Qm=(Kw)*CLF*F2Qe=(20m*10m)*25w/m2*0.75=3750W

    Qm=(10*150w/)*0.75=1125W( )

    D. Qsh=1.12*m*(To-Ti) Qlh=2.78*m*(Wo-Wi)

    Qsh=1.12*(10*8Lps/)*(35-25) =896W

    Qlh 2 78*(10*8L /)*(19 5 13) /k 1446W

    -

    Qlh=2.78*(10*8Lps/)*(19.5-13)g/kg=1446W

    Qtotal=Qw1+Qw2+Qps+Qpl+Qe+Qm+Qsh+Qlh=14787W/3517=4.2RT

  • THANK YOU !!THANK YOU !!

    -