實驗八 . 過氧化氫的分解速率

實實實 . 實實實實實實實實實實實：實實實 49912009 實實實實實實實實實、實實實 49912014 實實實實實實實實實、、

Upload
sef
Category

Documents
view
122
download
4

Embed Size (px):

description

實驗八 . 過氧化氫的分解速率. 分工：王依宸 49912009 目的、原理與公式推導臧遇卿 49912014 儀器、藥品、實驗步驟. 實驗目的. 了解在中性及酸性溶液中， H 2 O 2 的分解反應催化劑種類、濃度對反應速率的影響學習操作實驗儀器. 實驗原理 — 催化反應. 由加入催化劑，而改變反應速率反應分為勻相、非勻相勻相：反應物與催化劑在同相中進行 Ex ： H 2 O 2 ( 液相 )+Br 2 ( 催化劑；液相 ) 非勻相：反應物與催化劑在不同相進行 - PowerPoint PPT Presentation

Transcript of 實驗八 . 過氧化氫的分解速率

. 49912009 49912014 H2O2 Ex H2O2()+Br2() Ex H2O2()+KI()

r aA + bB cC + dD

R = k [] n k n

H2O2

( n=1 )O2H2O2

O2100ml510ml(100ml)250ml100mlH2O2KI35

0.05N & 0.1N KI10ml0.05N0.083g 10ml0.1N0.166g 10ml(166.01g/mol)3%5ml0.86ml 35% H2O2 10ml

3. !4.5.5ml 3% H2O26.10ml 0.05N KI7.(0.05N KI)30O2(15~30min)8. 45 O2V 9. 0.1N KI step4.-8.10. O2H2O2

t =k ()

t =

0.05M KIV(ml)93Vt(ml)7.514.023.430.035.541.046.051.055.560.5V- Vt (ml)85.579.069.663.057.552.047.042.037.532.5t (s)306090120150180210240270300Log(V- Vt)1.9311.8971.8431.7991.7601.7161.6721.6231.5741.5120.1M KIV(ml)55Vt(ml)8.415.120.226.130.534.037.441.543.545.0V- Vt (ml)46.639.934.828.924.521.017.613.511.510.0t (s)306090120150180210240270300Log(V- Vt)1.691.601.541.461.391.321.251.141.061.00= -0.0015 = -k/2.303k = 0.0015*2.303 = 0.0035= -0.0026 = -k/2.303k = 0.0026*2.303 = 0.0060 http://case.ntu.edu.tw/hs/wordpress/wp-content/uploads/2010/12/form110.jpghttp://blog.ncue.edu.tw/yangsp/doc/29402